how openjpa2.0 enhances entities at runtime?

Posted by Digambar Daund on Stack Overflow See other posts from Stack Overflow or by Digambar Daund
Published on 2010-06-09T11:22:22Z Indexed on 2010/06/09 13:22 UTC
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Below is my test code:

package jee.jpa2;

import java.util.List;

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.EntityTransaction;
import javax.persistence.Persistence;
import javax.persistence.Query;

import org.testng.annotations.BeforeClass;
import org.testng.annotations.Test;
@Test
public class Tester {
    EntityManager em;
    EntityTransaction tx;
    EntityManagerFactory emf;

    @BeforeClass
    public void setup() {
        emf = Persistence.createEntityManagerFactory("basicPU", System.getProperties());
    }

    @Test
    public void insert() {
        Item item = new Item();
        for (int i = 0; i < 1000; ++i) {
            em = emf.createEntityManager();
            tx = em.getTransaction();
            tx.begin();
            item.setId(null);
            em.persist(item);
            tx.commit();
            em.clear();
            em.close();
            tx=null;
            em=null;
        }
    }

    @Test
    public void read() {
        em = emf.createEntityManager();
        tx = em.getTransaction();
        tx.begin();
        Query findAll = em.createNamedQuery("findAll");
        List<Item> all = findAll.getResultList();
        for (Item item : all) {
            System.out.println(item);
        }
        tx.commit();
    }
}

And here is the entity:

package jee.jpa2;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.NamedQuery;

@Entity
@NamedQuery(name="findAll", query="SELECT i FROM Item i")
public class Item {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID", nullable = false, updatable= false)
    protected Long id;
    protected String name;

    public Item() {
        name = "Digambar";
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @Override
    public String toString() {
        return String.format("Item [id=%s, name=%s]", id, name);
    }

}

After executing test I get Error:

Item [id=1, name=Digambar]
Item [id=2, name=Digambar]
PASSED: read
FAILED: insert
<openjpa-2.0.0-r422266:935683 nonfatal store error> org.apache.openjpa.persistence.EntityExistsException: Attempt to persist detached object "jee.jpa2.Item-2".  If this is a new instance, make sure any version and/or auto-generated primary key fields are null/default when persisting.
FailedObject: jee.jpa2.Item-2
    at org.apache.openjpa.kernel.BrokerImpl.persist(BrokerImpl.java:2563)
    at org.apache.openjpa.kernel.BrokerImpl.persist(BrokerImpl.java:2423)
    at org.apache.openjpa.kernel.DelegatingBroker.persist(DelegatingBroker.java:1069)
    at org.apache.openjpa.persistence.EntityManagerImpl.persist(EntityManagerImpl.java:705)
    at jee.jpa2.Tester.insert(Tester.java:33)

Please Explain whats happening here?

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