The intention of following (simplified) code fragment is to return one random row. Unfortunatly, when we run this fragment in the query analyzer, it returns between zero and three results.

As our input table consists of exactly 5 rows with unique ID's and as we perform a select on this table where ID equals a random number, we are stumped that there would ever be more than one row returned.

Note: among other things, we already tried casting the checksum result to an integer with no avail.

DECLARE @Table TABLE (
  ID INTEGER IDENTITY (1, 1)
  , FK1 INTEGER
)

INSERT INTO @Table
SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5

SELECT  *
FROM    @Table 
WHERE   ID = ABS(CHECKSUM(NEWID())) % 5 + 1