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Published on 2010-06-17T22:01:10Z
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I have this code.
xmlhttp.open("GET","getuser.php?q="+str,true);
where q="+str
I want to pass a second var how do I do this?
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Hello,
I was expecting the below scenario common, but couldn't find much help online. I have a form loaded through Ajax (say, create entity form). It is loaded through a button click (load) event
$("#bt-create").click(function(){
$ ('#pid').load('/controller/vehicleModel/create3');
…
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I’m excited to announce the September 2013 release of the Ajax Control Toolkit, which now supports building new Ajax Control Toolkit controls with jQuery.
You can download the latest release of the Ajax Control Toolkit from http://AjaxControlToolkit.CodePlex.com or you can install the Ajax Control…
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Visual Studio 2010 Beta 2 was released this week and one of the first things that I hope you notice is that it no longer contains the latest version of ASP.NET AJAX. What happened? Where did AJAX go?
Just like Sting and The Police, just like Phil Collins and Genesis, just like Greg Page and the Wiggles…
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Olá pessoal,
A Microsoft publicou 14 vídeos que cedi a eles a respeito do ASP.NET AJAX. Todos os vídeos são gratuitos, e caso você ainda use o AJAX estas lições podem ajudá-lo bastante. Tenha um excelente estudo.
Instalação do AJAX Control Tookit
ASP.NET AJAX: Controle calendário
ASP.NET…
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I’m super excited to announce the July 2013 release of the Ajax Control Toolkit. You can download the new version of the Ajax Control Toolkit from CodePlex (http://ajaxControlToolkit.CodePlex.com) or install the Ajax Control Toolkit from NuGet:
With this release, we have completely rewritten the…
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I have set an array in my config file that I use global in my functions.
This works fine, but now I want to pass the name of this array as a @param in my function.
// in config file:
$album_type_arr = array("appartamento", "villa");
global $album_type_arr; // pull in from db_config
echo $album_type_arr[0];
function…
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I have a tricky one.
By means of a <cfoutput query="…"> I list some records in the page from a SQL Server database.
By the end of each line viewing I try to add this in to a record in a MySQL database.
As you see is simple, because I can use the exact variables from the output query in to…
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One of the very tricky question asked in an interview...
we need to swap the values of two variables like a=10 and b=15
Generaly to swap two variables values, we need 3rd variable like..
temp=a
a=b
b=temp
Now the requirement is, swaping value of two variable values without using 3rd variable…
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Hey guys...
$bookA = "123";
$crack = "A";
I want to do something similar to this:
echo $book$crack;
Such that the output is 123.
What is the correct syntax for the echo command?
Thanks.
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is it possible to copy a variable like this this?
class Colours {
var $var = "one";
var $var2 = array('something', $var);
}
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