Initializing a char array through passed pointer segfaults
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Bitgarden
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Published on 2012-06-10T22:30:24Z
Indexed on
2012/06/10
22:40 UTC
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Ie., why does the following work:
char* char_array(size_t size){
return new char[size];
}
int main(){
const char* foo = "foo";
size_t len = strlen(foo);
char* bar=char_array(len);
memset(bar, 0, len+1);
}
But the following segfaults:
void char_array(char* out, size_t size){
out= new char[size];
}
int main(){
const char* foo = "foo";
size_t len = strlen(foo);
char* bar;
char_array(bar, len);
memset(bar, 0, len+1);
}
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