Calculations on the iteration count in for loop in Ruby 1.8.7

Posted by user1805035 on Stack Overflow See other posts from Stack Overflow or by user1805035
Published on 2012-11-07T04:58:22Z Indexed on 2012/11/07 4:59 UTC
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I was playing around with Ruby and Latex to create a color coding set. I'm more than a novice with C++, but haven't looked at Ruby until now. So, still learning a lot of coding.

I have the following block of code below. When attempting to run this, band1 = 1e+02.

I've tried band1 = (BigDecimal(i) * 100).to_f thinking maybe there was some odd floating point issue. This is just me trying anything though as an integer multiplied by an integer should create an integer, if I'm still thinking correctly. I've tried a variety of other things as well (things that I can do in C++, but this ain't C++), but to no avail.

(1..9).each do |i|       #Band 1
  (0..9).each do |j|     #Band 2
    (0..11).each do |k|  #Band 3
      #Band 3 Start
      #these are the colors of the resistor bands
      b1 = $c_band12[i]
      b2 = $c_band12[j]
      b3 = $c_band3[k]
      b4 = "Gold"

      oms = ((i*100) + (j*10)) * $mult[k]
      band1 = i*100
      band2 = j
      band3 = $mult[k]
    end
  end
end

Not sure what I'm missing. Should I be using .each_with_index through these iterations? I've tried this: (1..9).each_with_index {|i, indexi| #Band 1 (0..9).each_with_index {|j, indexj| #Band 2 (0..11).each_with_index {|k, indexk| #Band 3 #Band 3 Start #these are the colors of the resistor bands b1 = $c_band12[i] b2 = $c_band12[j] b3 = $c_band3[k] b4 = "Gold"

      oms = ((i*100) + (j*10)) * $mult[k]
      band1 = indexk * 100

and I get the same answer. I can't see why 1*100 should equate to such a large number?

Thank you, AT

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