Array loading with doubles in C

Posted by user2892120 on Stack Overflow See other posts from Stack Overflow or by user2892120
Published on 2013-10-17T21:36:29Z Indexed on 2013/10/17 21:53 UTC
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I am trying to load a 3x8 array of doubles but my code keeps outputting 0.00 for all of the values. The code should be outputting the array (same as the input) under the Read#1 Read#2 Read#3 lines, with the average under average.

Here is my code:

#include <stdio.h>

double getAvg(double num1, double num2, double num3);

int main()
{
        int numJ,month,day,year,i,j;
        double arr[3][8];

        scanf("%d %d %d %d",&numJ,&month,&day,&year);

        for (i = 0; i < 8; i++)
        {
              scanf("%f %f %f",&arr[i][0], &arr[i][1], &arr[i][2]);
        }

        printf("\nJob %d Date: %d/%d/%d",numJ,month,day,year);
        printf("\n\nLocation Read#1 Read#2 Read#3 Average");
        for (j = 0; j < 8; j++)
        {
              printf("\n       %d   %.2f   %.2f   %.2f   %.2f",j+1,arr[j][0],arr[j]  [1],arr[j][2],getAvg(arr[j][0],arr[j][1],arr[j][2]));            
        }

        return 0;
}

double getAvg(double num1, double num2, double num3)
{
        double avg = (num1 + num2 + num3) / 3;
        return avg;
}

Input example:

157932   09 01 2013
0.00 0.00 0.00
0.36 0.27 0.23
0.18 0.16 0.26
0.27 0.00 0.34
0.24 0.00 0.31
0.16 0.33 0.36
0.29 0.36 0.00
0.21 0.36 0.00

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