How to upload Image on Android?

Posted by Mattiah85 on Stack Overflow See other posts from Stack Overflow or by Mattiah85
Published on 2014-06-04T06:55:13Z Indexed on 2014/06/04 9:25 UTC
Read the original article Hit count: 217

Filed under:
|
|

I havve to upload image from my SD card to PHP server. I have read a lot of articles and topics but I have some problems...

First I have use that code:

HttpURLConnection connection = null;
    DataOutputStream outputStream = null;
    //DataInputStream inputStream = null;
    String urlServer = hostName+"Upload";
    String lineEnd = "\r\n";
    String twoHyphens = "--";
    String boundary =  "*****";
    String serverResponseMessage;
    //int serverResponseCode;

    int bytesRead, bytesAvailable, bufferSize;
    byte[] buffer;
    int maxBufferSize = 1*1024*1024;

    try
    {

        showLog("uploading file: " + file);

        FileInputStream fileInputStream = new FileInputStream(new File(pictureFileDir+"/"+file) );

        URL url = new URL(urlServer);
        connection = (HttpURLConnection) url.openConnection();

        // Allow Inputs & Outputs.
        connection.setDoInput(true);
        connection.setDoOutput(true);
        connection.setUseCaches(false);

        // Set HTTP method to POST.
        connection.setRequestMethod("POST");

        connection.setRequestProperty("Connection", "Keep-Alive");
        connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);

        outputStream = new DataOutputStream( connection.getOutputStream() );
        outputStream.writeBytes(twoHyphens + boundary + lineEnd);
        outputStream.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\"" + file +"\"" + lineEnd);
        outputStream.writeBytes(lineEnd);

        bytesAvailable = fileInputStream.available();
        bufferSize = Math.min(bytesAvailable, maxBufferSize);
        buffer = new byte[bufferSize];

        // Read file
        bytesRead = fileInputStream.read(buffer, 0, bufferSize);

        while (bytesRead > 0)
        {
            outputStream.write(buffer, 0, bufferSize);
            bytesAvailable = fileInputStream.available();
            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        }

        outputStream.writeBytes(lineEnd);
        outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

        // Responses from the server (code and message)
        //serverResponseCode = connection.getResponseCode();
        serverResponseMessage = connection.getResponseMessage();

        showLog("server response: " + serverResponseMessage);

        fileInputStream.close();
        outputStream.flush();
        outputStream.close();
    }
    catch (Exception ex)
    {
        ex.printStackTrace();
    }

but server response 200/OK and no file was on destination server...

After i have read about Multipart:

try {
        HttpParams params = new BasicHttpParams();
        params.setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);
        DefaultHttpClient mHttpClient = new DefaultHttpClient(params); 
        File image = new File(pictureFileDir + "/" + filename);
        HttpPost httppost = new HttpPost(hostName+"Upload");

        MultipartEntity multipartEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);  
        multipartEntity.addPart("Image", new FileBody(image));
        httppost.setEntity(multipartEntity);

        mHttpClient.execute(httppost, new PhotoUploadResponseHandler());

    } catch (Exception e) {
       e.printStackTrace();
    }

but then a i have such LOG in LogCat and nothing else...

06-04 06:50:52.277: D/dalvikvm(1584): DexOpt: couldn't find static field Lorg/apache/http/message/BasicHeaderValueParser;.INSTANCE 06-04 06:50:52.277: W/dalvikvm(1584): VFY: unable to resolve static field 6688 (INSTANCE) in Lorg/apache/http/message/BasicHeaderValueParser; 06-04 06:50:52.277: D/dalvikvm(1584): VFY: replacing opcode 0x62 at 0x001b

ServerSide Script:

$target_path  = "uploads";
$target_path = $target_path . basename( $_FILES['Image']);
if(move_uploaded_file($_FILES['tmp_name'], $file_path)) {
    echo "success";
} else{
    echo "fail";
}

why? What is the simplest way to upload image?

© Stack Overflow or respective owner

Related posts about android

Related posts about image