why is optional chaining required in an if let statement
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b-ryan ca
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Published on 2014-06-06T03:20:15Z
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2014/06/06
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swift-language
Why would the Swift compiler expect me to write
if let addressNumber = paul.residence?.address?.buildingNumber?.toInt() { }
instead of just writing:
if let addressNumber = paul.residence.address.buildingNumber.toInt() { }
The compiler clearly has the static type information to handle the conditional statement for the first dereference of the optional value and each following value. Why would it not continue to do so for the following statements?
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