Search Results

Search found 5 results on 1 pages for 'aparna'.

Page 1/1 | 1 

  • Problem in searching String array [on hold]

    - by user2573607
    I'm working on a bank interface project, where I have to search an array of string when the user types in his username. The array has 10 strings, but only the first string is recognized as a valid username...I'm positive that the syntax of the search technique(Linear Search) is correct, but I cannot seem to find the problem. The code however compiles properly. Any answer will be appreciated, TIA! Aparna

    Read the article

  • Prevent Navigation to CreateUserWizardStep in the Postback event of nextbutton

    - by Aparna
    I am working with CreateUserWizard tool for creating a registration page. This is the first time and I am encountering problem with the following: I defined two steps in WizardSteps in the page: <WizardSteps> <asp:WizardStep ID="CreateUserWizardStep0" runat="server" Title="Sign Up for your new Account !!"> <asp:TextBox ID="Email" runat="server"> In the first wizard step, the user provides email, and we need to check if this email meets certain criteria (if he exists in our internal database, country is US etc) and if he/she is eligible navigate to CreateUserWizardStep1. I have a StartNextButton in the Start Navigation template for the WizardStep0. <StartNavigationTemplate> <br /> <asp:Button ID="StartNextButton" runat="server" CommandName="MoveNext" OnClick="StartNextButton_Click" Text="Check My Eligibility" /> </StartNavigationTemplate> I do all the logic of checking eligibility in the post-back event OnClick="StartNextButton_Click . If he is not eligible, I should display the error message in the step0 textbox and prevent navigation to CreateUserWizardStep1. I tried the following: if(noteligible) { lblError1.Visible = true; lblError1.Text = this.hfUserAlreadyRegistered.Value.ToString(); this.CreateUserWizard1.ActiveStepIndex = this.CreateUserWizard1.WizardSteps.IndexOf(this.CreateUserWizardStep0); this.CreateUserWizard1.Controls.Remove(CreateUserWizardStep1); this.CreateUserWizard1.ActiveStepIndex = 0; break; } But this is not working. I am taken out of step0 and step1 is coming irrespective of this. How can I just remain in Step0 and display the error message when the user is not eligible and navigate to Step1 only when he is eligible to register ? Thank you very much.

    Read the article

  • cross domain access in iframe from parent to child

    - by Aparna
    Hi, Could someone please help me with this- I've 2 applications AAA and BBB. The homepage of AAA contains an iFrame which displays the application BBB. When I login to AAA, the same login details should be used to login to BBB(single signon) and on pageload of the homepage of AAA, homepage of BBB should also be loaded in the iFrame. I tried to use javascript to access the form elements of login page of BBB to enter the login data and submit. But the browser gives me a 'Access is denied' error. I did a little reading and came to know that cross- domain communication is not allowed by the browser. Could someone tell me how i can go about achieving this?

    Read the article

  • Compilation Error related

    - by aparna
    Given: 11. public static void test(String str) { 12. int check = 4; 13. if (check = str.length()) { 14. System.out.print(str.charAt(check -= 1) +", "); 15. } else { 16. System.out.print(str.charAt(0) + ", "); 17. } 18. } and the invocation: 21. test("four"); 22. test("tee"); 23. test("to"); What is the result? A. r, t, t, B. r, e, o, C. Compilation fails. D. An exception is thrown at runtime. Answer: C Can you explain why the compilation fails please?

    Read the article

  • how to create a linked list in java without using util package? [closed]

    - by aparna
    I do not want to use any of the elements of the UTIL package. I tried but I am not able to get to the next node. Can anyone please help me out? Thanks in advance. I have put up this much. public class Element { private String s; private Element next; } public Element(String s) { this.s = s; this.next = null; } public void setNext(Element e) { this.next = e; } public String getString() { return this.s; } public Element getNext() { return this.next; } public String toString() { return "[" + s + "] => "; } public void add(String s) { int index = 0; System.out.println("Adding at index: " + index); Element curr = new Element(s); Element e = this.data[index]; if (e == null) { this.data[index] = curr; return; } while(e.getNext() != null) { e = e.getNext(); } e.setNext(curr); } }

    Read the article

1