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  • Missing return statement when using .charAt [migrated]

    - by Timothy Butters
    I need to write a code that returns the number of vowels in a word, I keep getting an error in my code asking for a missing return statement. Any solutions please? :3 import java.util.*; public class vowels { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("Please type your name."); String name = input.nextLine(); System.out.println("Congratulations, your name has "+ countVowels(name) +" vowels."); } public static int countVowels(String str) { int count = 0; for (int i=0; i < str.length(); i++) { // char c = str.charAt(i); if (str.charAt(i) == 'a' || str.charAt(i) == 'e' || str.charAt(i) == 'o' || str.charAt(i) == 'i' || str.charAt(i) == 'u') count = count + 1; } } }

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  • Java: charAt convert to int?

    - by sling
    Hi, I would like to key in my nirc number eg.S1234567I and then put 1234567 individualy as a integer as indiv1 as charAt(1), indiv2 as charAt(2), indiv as charAt(3), etc. However, when I do as the codes below, I cant seem to get even the first the number out? Any idea? Scanner console = new Scanner(System.in); System.out.println("Enter your NRIC number: "); String nric = console.nextLine(); int indiv1 = nric.charAt(1); System.out.println(indiv1);

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  • alert(line) alerts 'ac' and typeof(line) is 'string', but charAt is not a function

    - by Delirium tremens
    alert(line) alerts 'ac' typeof(line) is 'string' When I run line.charAt(0), charAt is not a function. When line is 'http://www.google.com/', it works, I think it's the UTF-8 encoding of the file that I opened... How to make charAt work with UTF-8? UPDATED: http://mxr.mozilla.org/mozilla-central/source/netwerk/dns/src/effective_tld_names.dat?raw=1 is in my extension's chrome folder as effective_tld_names.dat To run the code: authority = 'orkut.com.br'; lines = sc_geteffectivetldnames(); lines = sc_preparetouse(lines); domainname = sc_extractdomainname(authority, lines); The code: function sc_geteffectivetldnames () { var MY_ID = "[email protected]"; var em = Components.classes["@mozilla.org/extensions/manager;1"]. getService(Components.interfaces.nsIExtensionManager); var file = em.getInstallLocation(MY_ID).getItemFile(MY_ID, "chrome/effective_tld_names.dat"); var istream = Components.classes["@mozilla.org/network/file-input-stream;1"]. createInstance(Components.interfaces.nsIFileInputStream); istream.init(file, 0x01, 0444, 0); istream.QueryInterface(Components.interfaces.nsILineInputStream); var line = {}, lines = [], hasmore; do { hasmore = istream.readLine(line); lines.push(line.value); } while(hasmore); istream.close(); return lines; } function sc_preparetouse(lines) { lines = sc_notcomment(lines); lines = sc_notempty(lines); return lines; } function sc_notcomment(lines) { var line; var commentre; var matchedcomment; var replacedlines; replacedlines = new Array(); var i = 0; while (i < lines.length) { line = lines[i]; commentre = new RegExp("^//", 'i'); matchedcomment = line.match(commentre); if(matchedcomment) { lines.splice(i, 1); } else { i++; } } return lines; } function sc_notempty(lines) { var line; var emptyre; var matchedempty; var replacedlines; replacedlines = new Array(); var i = 0; while (i < lines.length) { line = lines[i]; emptyre = new RegExp("^$", 'i'); matchedempty = line.match(emptyre); if(matchedempty) { lines.splice(i, 1); } else { i++; } } return lines; } function sc_extractdomainname(authority, lines) { for (var i = 0; i < lines.length; i++) { line = lines[i]; alert(line); alert(typeof(line)); if (line.chatAt(0) == '*') { alert('test1'); continue; } if (line.chatAt(0) == '!') { alert('test2'); line.chatAt(0) = ''; } alert('test3'); checkline = sc_checknotasteriskline(authority, line); if (checkline) { domainname = checkline; } } if (!domainname) { for (var i = 0; i < lines.length; i++) { line = lines[i]; alert(line); if (line.chatAt(0) != '*') { continue; alert('test4'); } if (line.chatAt(0) == '!') { line.chatAt(0) = ''; alert('test5'); } alert('test6'); checkline = sc_checkasteriskline(authority, line); if (checkline) { domainname = checkline; } } } return domainname; } It alerts 'ac', then 'string', then nothing.

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  • alert(line) alerts 'ac' and typeof(line) is 'string', but charAt is not a function

    - by Delirium tremens
    alert(line) alerts 'ac' typeof(line) is 'string' When I run line.charAt(0), charAt is not a function. When line is 'http://www.google.com/', it works, I think it's the UTF-8 encoding of the file that I opened... How to make charAt work with UTF-8? UPDATED: http://mxr.mozilla.org/mozilla-central/source/netwerk/dns/src/effective_tld_names.dat?raw=1 is in my extension's chrome folder as effective_tld_names.dat To run the code: authority = 'orkut.com.br'; lines = sc_geteffectivetldnames(); lines = sc_preparetouse(lines); domainname = sc_extractdomainname(authority, lines); The code: function sc_geteffectivetldnames () { var MY_ID = "[email protected]"; var em = Components.classes["@mozilla.org/extensions/manager;1"]. getService(Components.interfaces.nsIExtensionManager); var file = em.getInstallLocation(MY_ID).getItemFile(MY_ID, "chrome/effective_tld_names.dat"); var istream = Components.classes["@mozilla.org/network/file-input-stream;1"]. createInstance(Components.interfaces.nsIFileInputStream); istream.init(file, 0x01, 0444, 0); istream.QueryInterface(Components.interfaces.nsILineInputStream); var line = {}, lines = [], hasmore; do { hasmore = istream.readLine(line); lines.push(line.value); } while(hasmore); istream.close(); return lines; } function sc_preparetouse(lines) { lines = sc_notcomment(lines); lines = sc_notempty(lines); return lines; } function sc_notcomment(lines) { var line; var commentre; var matchedcomment; var replacedlines; replacedlines = new Array(); var i = 0; while (i < lines.length) { line = lines[i]; commentre = new RegExp("^//", 'i'); matchedcomment = line.match(commentre); if(matchedcomment) { lines.splice(i, 1); } else { i++; } } return lines; } function sc_notempty(lines) { var line; var emptyre; var matchedempty; var replacedlines; replacedlines = new Array(); var i = 0; while (i < lines.length) { line = lines[i]; emptyre = new RegExp("^$", 'i'); matchedempty = line.match(emptyre); if(matchedempty) { lines.splice(i, 1); } else { i++; } } return lines; } function sc_extractdomainname(authority, lines) { for (var i = 0; i < lines.length; i++) { line = lines[i]; alert(line); alert(typeof(line)); if (line.chatAt(0) == '*') { alert('test1'); continue; } if (line.chatAt(0) == '!') { alert('test2'); line.chatAt(0) = ''; } alert('test3'); checkline = sc_checknotasteriskline(authority, line); if (checkline) { domainname = checkline; } } if (!domainname) { for (var i = 0; i < lines.length; i++) { line = lines[i]; alert(line); if (line.chatAt(0) != '*') { alert('test4'); continue; } if (line.chatAt(0) == '!') { alert('test5'); line.chatAt(0) = ''; } alert('test6'); checkline = sc_checkasteriskline(authority, line); if (checkline) { domainname = checkline; } } } return domainname; } It alerts 'ac', then 'string', then nothing.

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  • StringIndexOutOfBoundsException error in main method

    - by Ro Siv
    I am obtaining a StringIndexOutOfBoundsError when running my main method. Here is the output of my program in the command line. "Please enter the shift, 1 for day, 2 for night" 1 "you entered a number for the shift" "Please enter the hourly pay Rate" 2 "you entered a number for the pay Rate" "Please enter the employees name" brenda "cat6b" "your value you entered is correct 0-9 or a - z" "Please enter the employee number" 100e "cat41" "your value you entered is correct 0-9 or a - z" "Please enter current date in XXYYZZZZ format, X is day, Y is month, Z is year" 10203933 "cat81 " "your value you entered is correct 0-9 or a - z" 90 1 valye of array is 1 81 0 value of array is 0 82 2 value of array is 2 83 0 value of array is 0 84 3 value of array is 3 85 9 value of array is 9 86 3 value of array is 3 87 3 value of array is 3 "Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 8 at java.lang.String.charAt(String.java:658) at ProductionWorker<init>(ProductionWorker.java:66) at labBookFiftyFour.main(labBookFiftyFour.java:58)" "Press any key to continue . . ." Ignore the cat parts in the code, i was using a println statement to test the code. Ignore the value of array output as well, as i wanted to use an array in the program later on. Here is my main method. import java.math.*; import java.text.DecimalFormat; import java.io.*; import java.util.*; public class labBookFiftyFour { public static void main(String[] args) { Scanner myInput = new Scanner(System.in); int shift = -1; double pRate = -2; String name = " "; String number = " "; String date = " "; while(shift < 0 || pRate < 0 ) { System.out.println("Please enter the shift, 1 for day, 2 for night"); if(myInput.hasNextInt()){ System.out.println("you entered a number for the shift"); shift = myInput.nextInt(); } System.out.println("Please enter the hourly pay Rate"); if(myInput.hasNextDouble()){ System.out.println("you entered a number for the pay Rate"); pRate = myInput.nextDouble(); } else if (myInput.hasNext()) { System.out.println("Please enter a proper value"); myInput.next(); } else { System.err.println("No more input"); System.exit(1); } } myInput.nextLine(); //consume newLine System.out.println("Please enter the employees name"); name = myInput.nextLine(); //use your isValid method if(isValid(name)) { System.out.println("your value you entered is correct 0-9 or a - z "); } System.out.println("Please enter the employee number"); number = myInput.nextLine(); //use your isValid method if(isValid(number)) { System.out.println("your value you entered is correct 0-9 or a - z "); } System.out.println("Please enter current date in XXYYZZZZ format, X is day, Y is month, Z is year"); date = myInput.nextLine(); //use your isValid method if(isValid(date)) { System.out.println("your value you entered is correct 0-9 or a - z "); } ProductionWorker myWorker = new ProductionWorker(shift, pRate, name, number, date); //int day and night , double payRate System.out.println("THis is the shift " + myWorker.getShift() + " This is the pay Rate " + myWorker.getPRate() + " " + myWorker.getName() + " " + myWorker.getNumber() + " " + myWorker.getDate()); } //Made this method for testing String input for 0-9 or a - z values , put AFTER main method, but before end of class public static boolean isValid(String stringName) //This method has to be static, for some reason? { System.out.println("cat" + stringName.length() + stringName.charAt(0)); boolean flag = true; int index = 0; while(index < stringName.length()) { if(Character.isLetterOrDigit(stringName.charAt(index))) { flag = true; } else { flag = false; } ++index; } return flag; } } Here is my employeeOne. java Superclass public class employeeOne { private String name; private String number; private String date; public employeeOne(String name, String number, String date) { this.name = name; this.number = number; this.date = date; } public String getName() { return name; } public String getNumber() { return number; } public String getDate() { return date; } } Here is my ProductionWorker.java subclass, which extends employeeOne public class ProductionWorker extends employeeOne { private int shift; //shift represents day or night, day = 1, night = 2 private double pRate; //hourly pay rate public ProductionWorker(int shift, double pRate, String name, String number, String date) { super(name, number, date); this.shift = shift; if(this.shift >= 3 || this.shift <= 0) { System.out.println("You entered an out of bounds shift date, enter 1 for day or 2 for night, else shift will be day"); this.shift = 1; } this.pRate = pRate; boolean goodSoFar = true; int indexNum = 0; int indexDate = 0; if(name.length() <= 10 && number.length() <= 4 && date.length() < 9 ) { goodSoFar = true; } else { goodSoFar = false; } while(goodSoFar && indexNum < 3) //XXXL XXX digits 1-9, L is a letter A -M { if(Character.isDigit(number.charAt(indexNum))) { goodSoFar = true; } else { goodSoFar = false; } ++indexNum; } while(goodSoFar && indexNum < 4) { if(Character.isLetter(number.charAt(indexNum))) { goodSoFar = true; } else if(Character.isDigit(number.charAt(indexNum))) { goodSoFar = false; } else if(Character.isDigit(number.charAt(indexNum)) == false && Character.isLetter(number.charAt(indexNum)) == false) { goodSoFar = false; } ++indexNum; } int[] dateValues = new int[date.length()]; while(goodSoFar && indexDate <= date.length()) //XXYYZZZZ { System.out.println("" + date.length() + indexDate + " " + date.charAt(indexDate)); if(Character.isDigit(date.charAt(indexDate))) { dateValues[indexDate] = Character.getNumericValue(date.charAt(indexDate)); System.out.println("value of array is " + dateValues[indexDate]); ++indexDate; } else { goodSoFar = false; } } if(goodSoFar) { System.out.println("your input is good so far"); } else { System.out.println("your input is wrong for name or number or date"); } } public int getShift() { return shift; } public double getPRate() { return pRate; } }

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  • Using charAt in java

    - by ThuL?nå F?rñ?nDö
    This is my assignment: Write a program where the user enters a string, and the program echoes it to the monitor with one character per line: C:\>java LinePerChar Enter a string: Octopus O c t o p u s I have tried, but I'm getting some compilation errors. Here's my code: import java.util.*; class CharactorEcho{ public static void main(String args []){ Scanner sc = new Scanner(System.in); System.out.println("Enter a string :"); try { String inputString = sc.nextLine(); for(int i=0; i < sc.length(); i++) { char c = inputString.charAt(i); System.out.println("" + c); } } catch(IOException e) { } } }

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  • traverse a string char by char javascript

    - by mikeandike
    function SimpleSymbols(str) { var letter =['a','b','c','d','e','f','g','h','i','j', 'k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']; var newstr = ""; for (var i = 0; i<str.length; i++){ if (str.charAt(i).toLowerCase() in letter){ newstr += "M"; } else{ newstr += "X"; } } return newstr; } If str is "Argument goes here" it returns XXXXXXXXX. WHy doesn't it return MMMMMMMMMM?

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  • Java Scanner class reading strings

    - by Max
    I've created a scanner class to read through the text file and get the value what I'm after. Let's assume that I have a text file contains 1 : Fnjiei : ID 7868860 : Age 18 2 : Oipuiieerb : ID 334134 : Age 39 3 : Enekaree : ID 6106274 : Age 31 I'm trying to get a name and id number and age, but everytime I try to run my code it gives me an exception. Here's my code. Any suggestion from java gurus?:) public void readFile(String fileName)throws IOException{ Scanner input = null; input = new Scanner(new BufferedReader(new FileReader(fileName))); try { while (input.hasNextLine()){ int howMany = 3; System.out.println(howMany); String userInput = input.nextLine(); String name = ""; String idS = ""; String ageS = ""; int id; int age; int count=0; for (int j = 0; j <= howMany; j++){ for (int i=0; i < userInput.length(); i++){ if(count < 2){ // for name if(Character.isLetter(userInput.charAt(i))){ name+=userInput.charAt(i); // store the name }else if(userInput.charAt(i)==':'){ count++; i++; } }else if(count == 2){ // for id if(Character.isDigit(userInput.charAt(i))){ idS+=userInput.charAt(i); // store the id } else if(userInput.charAt(i)==':'){ count++; i++; } }else if(count == 3){ // for age if(Character.isDigit(userInput.charAt(i))){ ageS+=userInput.charAt(i); // store the age } } id = Integer.parseInt(idS); // convert id to integer age = Integer.parseInt(ageS); // convert age to integer Fighters newFighters = new Fighters(id, name, age); fighterList.add(newFighters); } userInput = input.nextLine(); } } }finally{ if (input != null){ input.close(); } } } My appology if my mere code begs to be changed.

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  • Given an XML which contains a representation of a graph, how to apply it DFS algorithm? [on hold]

    - by winston smith
    Given the followin XML which is a directed graph: <?xml version="1.0" encoding="iso-8859-1" ?> <!DOCTYPE graph PUBLIC "-//FC//DTD red//EN" "../dtd/graph.dtd"> <graph direct="1"> <vertex label="V0"/> <vertex label="V1"/> <vertex label="V2"/> <vertex label="V3"/> <vertex label="V4"/> <vertex label="V5"/> <edge source="V0" target="V1" weight="1"/> <edge source="V0" target="V4" weight="1"/> <edge source="V5" target="V2" weight="1"/> <edge source="V5" target="V4" weight="1"/> <edge source="V1" target="V2" weight="1"/> <edge source="V1" target="V3" weight="1"/> <edge source="V1" target="V4" weight="1"/> <edge source="V2" target="V3" weight="1"/> </graph> With this classes i parsed the graph and give it an adjacency list representation: import java.io.IOException; import java.util.HashSet; import java.util.LinkedList; import java.util.Collection; import java.util.Iterator; import java.util.logging.Level; import java.util.logging.Logger; import practica3.util.Disc; public class ParsingXML { public static void main(String[] args) { try { // TODO code application logic here Collection<Vertex> sources = new HashSet<Vertex>(); LinkedList<String> lines = Disc.readFile("xml/directed.xml"); for (String lin : lines) { int i = Disc.find(lin, "source=\""); String data = ""; if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } Vertex v = new Vertex(); v.setName(data); v.setAdy(new HashSet<Vertex>()); sources.add(v); } } Iterator it = sources.iterator(); while (it.hasNext()) { Vertex ver = (Vertex) it.next(); Collection<Vertex> adyacencias = ver.getAdy(); LinkedList<String> ls = Disc.readFile("xml/graphs.xml"); for (String lin : ls) { int i = Disc.find(lin, "target=\""); String data = ""; if (lin.contains("source=\""+ver.getName())) { Vertex v = new Vertex(); if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } v.setName(data); } i = Disc.find(lin, "weight=\""); data = ""; if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } v.setWeight(Integer.parseInt(data)); } if (v.getName() != null) { adyacencias.add(v); } } } } for (Vertex vert : sources) { System.out.println(vert); System.out.println("adyacencias: " + vert.getAdy()); } } catch (IOException ex) { Logger.getLogger(ParsingXML.class.getName()).log(Level.SEVERE, null, ex); } } } This is another class: import java.util.Collection; import java.util.Objects; public class Vertex { private String name; private int weight; private Collection ady; public Collection getAdy() { return ady; } public void setAdy(Collection adyacencias) { this.ady = adyacencias; } public String getName() { return name; } public void setName(String nombre) { this.name = nombre; } public int getWeight() { return weight; } public void setWeight(int weight) { this.weight = weight; } @Override public int hashCode() { int hash = 7; hash = 43 * hash + Objects.hashCode(this.name); hash = 43 * hash + this.weight; return hash; } @Override public boolean equals(Object obj) { if (obj == null) { return false; } if (getClass() != obj.getClass()) { return false; } final Vertex other = (Vertex) obj; if (!Objects.equals(this.name, other.name)) { return false; } if (this.weight != other.weight) { return false; } return true; } @Override public String toString() { return "Vertice{" + "name=" + name + ", weight=" + weight + '}'; } } And finally: /** * * @author user */ /* -*-jde-*- */ /* <Disc.java> Contains the main argument*/ import java.io.*; import java.util.LinkedList; /** * Lectura y escritura de archivos en listas de cadenas * Ideal para el uso de las clases para gráficas. * * @author Peralta Santa Anna Victor Miguel * @since Julio 2011 */ public class Disc { /** * Metodo para lectura de un archivo * * @param fileName archivo que se va a leer * @return El archivo en representacion de lista de cadenas */ public static LinkedList<String> readFile(String fileName) throws IOException { BufferedReader file = new BufferedReader(new FileReader(fileName)); LinkedList<String> textlist = new LinkedList<String>(); while (file.ready()) { textlist.add(file.readLine().trim()); } file.close(); /* for(String linea:textlist){ if(linea.contains("source")){ //String generado = linea.replaceAll("<\\w+\\s+\"", ""); //System.out.println(generado); } }*/ return textlist; }//readFile public static int find(String linea,String palabra){ int i,j; boolean found = false; for(i=0,j=0;i<linea.length();i++){ if(linea.charAt(i)==palabra.charAt(j)){ j++; if(j==palabra.length()){ found = true; return i; } }else{ continue; } } if(!found){ i= -1; } return i; } /** * Metodo para la escritura de un archivo * * @param fileName archivo que se va a escribir * @param tofile la lista de cadenas que quedaran en el archivo * @param append el bit que dira si se anexa el contenido o se empieza de cero */ public static void writeFile(String fileName, LinkedList<String> tofile, boolean append) throws IOException { FileWriter file = new FileWriter(fileName, append); for (int i = 0; i < tofile.size(); i++) { file.write(tofile.get(i) + "\n"); } file.close(); }//writeFile /** * Metodo para escritura de un archivo * @param msg archivo que se va a escribir * @param tofile la cadena que quedaran en el archivo * @param append el bit que dira si se anexa el contenido o se empieza de cero */ public static void writeFile(String msg, String tofile, boolean append) throws IOException { FileWriter file = new FileWriter(msg, append); file.write(tofile); file.close(); }//writeFile }// I'm stuck on what can be the best way to given an adjacency list representation of the graph how to apply it Depth-first search algorithm. Any idea of how to aproach to complete the task?

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  • String Index Out Of Bound Exception error

    - by Fd Fehfhd
    Im not really sure why a am getting this error. But here is my code it is meant to test palindromes disregarding punctuation. So here is my code import java.util.Scanner; public class PalindromeTester { public static void main(String [] args) { Scanner kb = new Scanner(System.in); String txt = ""; int left; int right; int cntr = 0; do { System.out.println("Enter a word, phrase, or sentence (blank line to stop):"); txt = kb.nextLine(); txt = txt.toLowerCase(); char yP; String noP = ""; for (int i = 0; i < txt.length(); i++) { yP = txt.charAt(i); if (Character.isLetterOrDigit(txt.charAt(yP))) { noP += yP; } } txt = noP; left = 0; right = txt.length() -1; while (txt.charAt(left) == txt.charAt(right) && right > left) { left++; right--; } if (left > right) { System.out.println("Palindrome"); cntr++; } else { System.out.println("Not a palindrome"); } } while (!txt.equals("")); System.out.println("You found " + cntr + " palindromes. Thank you for using palindromeTester."); } } And if i test it and then i put enter so it will tell me how many palindromes you found the error i am getting is javav.lang.StringIndexOutOfBoundException : String index out of range 0 at PalindromeTester.main(PalindromeTester.java:38) and line 28 is while (txt.charAt(left) == txt.charAt(right) && right > left) Thanks for the help in advance

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  • Transposing and Untransposing a String in java

    - by Will
    I have been working on two methods that will Transpose and Untranspose a String respectively. The solutions that I have come up with both work to the best of my knowledge. I just want to know if I could have solved these problems in a simpler way. My code seems like it is too long for the task that is being performed. The first method, transpose(), will take a String as a parameter and transpose it. If "bridge" is entered, the output will be "bergid". Likewise, with the unTranspose() method, if the user enters "bergid", the output will be "bridge". public void transpose( String s ) { String t = ""; int end = s.length() - 1; for ( int i = 0; i < s.length() / 2; i++ ) { t += Character.toString( s.charAt( i ) ) + Character.toString( s.charAt( end ) ); end--; } // Lenth of String is odd if ( s.length() % 2 == 1 ) { // add character in middle of String to the end of the new String t+= Character.toString( s.charAt( s.length() / 2 ) ); } System.out.println( t ); } public void unTranspose( String s ) { String t = ""; // Length of String is odd if ( s.length() % 2 == 1 ) { for ( int i = 0; i < s.length(); i+=2 ) { t+= Character.toString( s.charAt( i ) ); } for ( int i = s.length() - 2; i > 0; i -= 2 ) { t += Character.toString( s.charAt( i ) ); } System.out.println( t ); } // Length of String is even else if ( s.length() % 2 == 0 ) { for ( int i = 0; i < s.length() - 1; i+=2 ) { t+= Character.toString( s.charAt( i ) ); } for ( int i = s.length() - 1; i > 0; i -= 2 ) { t+= Character.toString( s.charAt( i ) ); } System.out.println( t ); } } My code looks horrible. I'm still not used to formatting my code correctly. Please bear with me. Thanks for your time

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  • Common Substring of two strings

    - by Chander Shivdasani
    This particular interview-question stumped me: Given two Strings S1 and S2. Find the longest Substring which is a Prefix of S1 and suffix of S2. Through Google, I came across the following solution, but didnt quite understand what it was doing. public String findLongestSubstring(String s1, String s2) { List<Integer> occurs = new ArrayList<>(); for (int i = 0; i < s1.length(); i++) { if (s1.charAt(i) == s2.charAt(s2.length()-1)) { occurs.add(i); } } Collections.reverse(occurs); for(int index : occurs) { boolean equals = true; for(int i = index; i >= 0; i--) { if (s1.charAt(index-i) != s2.charAt(s2.length() - i - 1)) { equals = false; break; } } if(equals) { return s1.substring(0,index+1); } } return null; }

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  • Reducing Time Complexity in Java

    - by Koeneuze
    Right, this is from an older exam which i'm using to prepare my own exam in january. We are given the following method: public static void Oorspronkelijk() { String bs = "Dit is een boodschap aan de wereld"; int max = -1; char let = '*'; for (int i=0;i<bs.length();i++) { int tel = 1; for (int j=i+1;j<bs.length();j++) { if (bs.charAt(j) == bs.charAt(i)) tel++; } if (tel > max) { max = tel; let = bs.charAt(i); } } System.out.println(max + " keer " + let); } The questions are: what is the output? - Since the code is just an algorithm to determine the most occuring character, the output is "6 keer " (6 times space) What is the time complexity of this code? Fairly sure it's O(n²), unless someone thinks otherwise? Can you reduce the time complexity, and if so, how? Well, you can. I've received some help already and managed to get the following code: public static void Nieuw() { String bs = "Dit is een boodschap aan de wereld"; HashMap<Character, Integer> letters = new HashMap<Character, Integer>(); char max = bs.charAt(0); for (int i=0;i<bs.length();i++) { char let = bs.charAt(i); if(!letters.containsKey(let)) { letters.put(let,0); } int tel = letters.get(let)+1; letters.put(let,tel); if(letters.get(max)<tel) { max = let; } } System.out.println(letters.get(max) + " keer " + max); } However, I'm uncertain of the time complexity of this new code: Is it O(n) because you only use one for-loop, or does the fact we require the use of the HashMap's get methods make it O(n log n) ? And if someone knows an even better way of reducing the time complexity, please do tell! :)

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  • Decode base64 data as array in Python

    - by skerit
    I'm using this handy Javascript function to decode a base64 string and get an array in return. This is the string: base64_decode_array('6gAAAOsAAADsAAAACAEAAAkBAAAKAQAAJgEAACcBAAAoAQAA') This is what's returned: 234,0,0,0,235,0,0,0,236,0,0,0,8,1,0,0,9,1,0,0,10,1,0,0,38,1,0,0,39,1,0,0,40,1,0,0 The problem is I don't really understand the javascript function: var base64chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/'.split(""); var base64inv = {}; for (var i = 0; i < base64chars.length; i++) { base64inv[base64chars[i]] = i; } function base64_decode_array (s) { // remove/ignore any characters not in the base64 characters list // or the pad character -- particularly newlines s = s.replace(new RegExp('[^'+base64chars.join("")+'=]', 'g'), ""); // replace any incoming padding with a zero pad (the 'A' character is zero) var p = (s.charAt(s.length-1) == '=' ? (s.charAt(s.length-2) == '=' ? 'AA' : 'A') : ""); var r = []; s = s.substr(0, s.length - p.length) + p; // increment over the length of this encrypted string, four characters at a time for (var c = 0; c < s.length; c += 4) { // each of these four characters represents a 6-bit index in the base64 characters list // which, when concatenated, will give the 24-bit number for the original 3 characters var n = (base64inv[s.charAt(c)] << 18) + (base64inv[s.charAt(c+1)] << 12) + (base64inv[s.charAt(c+2)] << 6) + base64inv[s.charAt(c+3)]; // split the 24-bit number into the original three 8-bit (ASCII) characters r.push((n >>> 16) & 255); r.push((n >>> 8) & 255); r.push(n & 255); } // remove any zero pad that was added to make this a multiple of 24 bits return r; } What's the function of those "<<<" and "" characters. Or is there a function like this for Python?

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  • Time complexity O() of isPalindrome()

    - by Aran
    I have this method, isPalindrome(), and I am trying to find the time complexity of it, and also rewrite the code more efficiently. boolean isPalindrome(String s) { boolean bP = true; for(int i=0; i<s.length(); i++) { if(s.charAt(i) != s.charAt(s.length()-i-1)) { bP = false; } } return bP; } Now I know this code checks the string's characters to see whether it is the same as the one before it and if it is then it doesn't change bP. And I think I know that the operations are s.length(), s.charAt(i) and s.charAt(s.length()-i-!)). Making the time-complexity O(N + 3), I think? This correct, if not what is it and how is that figured out. Also to make this more efficient, would it be good to store the character in temporary strings?

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  • color letters in a div

    - by Growler
    I've created a palindrome checker. I want to take it one step further and show the letters being compared as it is being checked. HTML: <p id="typing"></p> <input type="text" id="textBox" onkeyup="pal(this.value);" value="" /> <div id="response"></div> <hr> <div id="palindromeRun"></div> JS: To do this, I run the recursive check... Then if it is a palindrome, I run colorLetters(), which I'm trying to highlight in green each letter as it is being checked. Right now it is just rewriting palindromeRun's HTML with the first letter. I know this is because of the way I'm resetting its HTML. I don't know how to just grab the first and last letter, change only those letters' css, then increment i and j on the next setTimeout loop. var timeout2 = null; function pal (input) { var str = input.replace(/\s/g, ''); var str2 = str.replace(/\W/, ''); if (checkPal(str2, 0, str2.length-1)) { $("#textBox").css({"color" : "green"}); $("#response").html(input + " is a palindrome"); $("#palindromeRun").html(input); colorLetters(str2, 0, str2.length-1); } else { $("#textBox").css({"color" : "red"}); $("#response").html(input + " is not a palindrome"); } if (input.length <= 0) { $("#response").html(""); $("#textBox").css({"color" : "black"}); } } function checkPal (input, i, j) { if (input.length <= 1) { return false; } if (i === j || ((j-i) == 1 && input.charAt(i) === input.charAt(j))) { return true; } else { if (input.charAt(i).toLowerCase() === input.charAt(j).toLowerCase()) { return checkPal(input, ++i, --j); } else { return false; } } } function colorLetters(myinput, i, j) { if (timeout2 == null) { timeout2 = setTimeout(function () { console.log("called"); var firstLetter = $("#palindromeRun").html(myinput.charAt(i)) var secondLetter = $("#palindromeRun").html(myinput.charAt(j)) $(firstLetter).css({"color" : "red"}); $(secondLetter).css({"color" : "green"}); i++; j++; timeout2=null; }, 1000); } } Secondary: If possible, I'd just like to have it colors the letters as the user is typing... I realize this will require a setTimeout on each keyup, but also am not sure how to write this.

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  • Extending jQuery Form Validation Script for new form fields

    - by user982124
    I have a simple HTML form that originally was a series of Questions (A1 to A5 and B1 to B3) with yes/no radio buttons like this: <tr> <td width="88%" valign="top" class="field_name_left">A1</td> <td width="12%" valign="top" class="field_data"> <input type="radio" name="CriteriaA1" value="Yes">Yes<input type="radio" name="CriteriaA1" value="No">No</td> </tr> The user could only answer either the A series of questions OR either the B series of questions, but not both. Also they must complete all questions in either the A or B series. I now have an additional series of questions - C1 to C6 - and need to extend my validation scripts to ensure the user enters either A, B or C and answers all questions within each series. My original script for just the A and B looks like this: $(function() { $("#editRecord").submit(function(){ // is anything checked? if(!checkEmpty()){ $("#error").html("Please check something before submitting"); //alert("nothing Checked"); return false; } // Only A _OR_ B if(isAorB()){ $("#error").html("Please complete A or B, not both"); //alert("please complete A or B, not both"); return false; }; // all A's or all B's if(allAorBChecked()){ $("#error").html("It appears you have not completed all questions"); //alert("missing data"); return false; }; if(haveNo()){ // we're going on, but sending "type = C" } //alert("all OK"); return true; }); }); function checkEmpty(){ var OK = false; $(":radio").each(function(){ if (this.checked){ OK = true; } }); return OK; } function isAorB(){ var OK = false; var Achecked = false; var Bchecked = false; $(":radio").each(function(){ var theChar=this.name.charAt(8); // if we have an A checked remember it if(theChar == "A" && this.checked && !Achecked){ Achecked = true; } if(Achecked && theChar == "B" && !Bchecked){ if(this.checked){ Bchecked = true; } } if (Achecked && Bchecked){ OK = true; } }); return OK; } function allAorBChecked(){ var notOK = false; var Achecked = false; $(":radio").each(function(){ // skip through to see if we're doing A's or B's var theChar=this.name.charAt(8); // check the A's if(theChar == "A" && this.checked && !Achecked){ Achecked = true; } }); if(Achecked){ // set the input to A $("#type").val("A"); // check _all_ a's are checked var thisName; var thisChecked = false; $(":radio").each(function(){ var theChar=this.name.charAt(8); var checked = this.checked; if (theChar == "A"){ if (this.name == thisName && !thisChecked){ // Yes wasn't checked - is No? if(!checked){ notOK = true; } } thisChecked = checked; thisName = this.name; } }); }else{ // set the input to B $("#type").val("B"); // check _all_ b's are checked var thisName; var thisChecked = false; $(":radio").each(function(){ var theChar=this.name.charAt(8); var checked = this.checked; if (theChar == "B"){ if (this.name == thisName && !thisChecked){ // A wasn't checked - is B? if(!checked){ notOK = true; } } thisChecked = checked; thisName = this.name; } }); } return notOK; } function haveNo(){ var thisName; var notOK = false; $(":radio").each(function(){ var checked = this.checked; if (this.name == thisName){ //Is this checked if(checked){ notOK = true; $("#type").val("C"); } } thisName = this.name; }); return notOK; } This worked well but I'm completely stuck at extending it to include the C series. I now have to check that the user hasn't answered any A and B, A and C and B and C questions. Everything I've tried fails to validate. Here's where I'm at right now with my new script: $(function() { $("#editRecord").submit(function(){ // is anything checked? if(!checkEmpty()){ $("#error").html("Please check something before submitting"); //alert("nothing Checked"); return false; } // Only A or B or C if(isAorBorC()){ $("#error").html("Please complete A or B or C, not both"); //alert("please complete A or B, not both"); return false; }; // all A's or all B's or all C's if(allAorBorCChecked()){ $("#error").html("It appears you have not completed all questions"); //alert("missing data"); return false; }; if(haveNo()){ // we're going on, but sending "type = C" } //alert("all OK"); return true; }); }); function checkEmpty(){ var OK = false; $(":radio").each(function(){ if (this.checked){ OK = true; } }); return OK; } function isAorBorC(){ var OK = false; var Achecked = false; var Bchecked = false; var Cchecked = false; $(":radio").each(function(){ var theChar=this.name.charAt(8); // if we have an A checked remember it if(theChar == "A" && this.checked && !Achecked){ Achecked = true; } if(theChar == "B" && this.checked && !Achecked){ Bchecked = true; } if(theChar == "C" && this.checked && !Achecked){ Cchecked = true; } if(Achecked && theChar == "B" && !Bchecked){ if(this.checked){ Bchecked = true; } } if(Achecked && theChar == "C" && !Cchecked){ if(this.checked){ Cchecked = true; } } if(Bchecked && theChar == "C" && !Cchecked){ if(this.checked){ Cchecked = true; } } if (Achecked && Bchecked){ OK = true; } if (Achecked && CBchecked){ OK = true; } if (Bchecked && Cchecked){ OK = true; } }); return OK; } function allAorBorCChecked(){ var notOK = false; var Achecked = false; $(":radio").each(function(){ // skip through to see if we're doing A's or B's var theChar=this.name.charAt(8); // check the A's if(theChar == "A" && this.checked && !Achecked){ Achecked = true; } }); if(Achecked){ // set the input to A $("#type").val("A"); // check _all_ a's are checked var thisName; var thisChecked = false; $(":radio").each(function(){ var theChar=this.name.charAt(8); var checked = this.checked; if (theChar == "A"){ if (this.name == thisName && !thisChecked){ // Yes wasn't checked - is No? if(!checked){ notOK = true; } } thisChecked = checked; thisName = this.name; } }); }elseif{ // set the input to B $("#type").val("B"); // check _all_ b's are checked var thisName; var thisChecked = false; $(":radio").each(function(){ var theChar=this.name.charAt(8); var checked = this.checked; if (theChar == "B"){ if (this.name == thisName && !thisChecked){ // A wasn't checked - is B? if(!checked){ notOK = true; } } thisChecked = checked; thisName = this.name; } }); } return notOK; } }else{ // set the input to C $("#type").val("C"); // check _all_ c's are checked var thisName; var thisChecked = false; $(":radio").each(function(){ var theChar=this.name.charAt(8); var checked = this.checked; if (theChar == "C"){ if (this.name == thisName && !thisChecked){ // A wasn't checked - is B? if(!checked){ notOK = true; } } thisChecked = checked; thisName = this.name; } }); } return notOK; } function haveNo(){ var thisName; var notOK = false; $(":radio").each(function(){ var checked = this.checked; if (this.name == thisName){ //Is this checked if(checked){ notOK = true; $("#type").val("C"); } } thisName = this.name; }); return notOK; } Anyone see what I'm doing wrong?

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  • StringIndexOutOfBoundsException: String index out of range 0

    - by Evan F
    I'm trying to write a program to take the first letter of the user input to generate a username. I'm trying to write it so that if the user leaves the input blank, then the letter that would otherwise be taken to generate the username defaults to the letter 'z'. Here is my full code: import java.util.Scanner; /** UsernameGenerator.java Generates a username based on the users inputs. @author: Evan Fravert */ public class UsernameGenerator { /** * Generates a username based on the users inputs. *@param args command line argument */ public static void main(String[] args) { // abcde String first; String middle; String last; String password1; String password2; int randomNum; randomNum = (int) (Math.random() * 1000) + 100; Scanner userInput = new Scanner(System.in); System.out.println("Please enter your first name:"); first = userInput.nextLine(); String firstLower = first.toLowerCase(); System.out.println("Please enter your middle name:"); middle = userInput.nextLine(); String middleLower = middle.toLowerCase(); System.out.println("Please enter your last name:"); last = userInput.nextLine(); int lastEnd = last.length()-1; String lastLower = last.toLowerCase(); System.out.println("Please enter your password:"); password1 = userInput.nextLine(); System.out.println("Please enter your password again:"); password2 = userInput.nextLine(); char firstLetter = firstLower.charAt(0); char middleLetter = middleLower.charAt(0); char lastLetter = lastLower.charAt(0); char lastLast = lastLower.charAt(lastEnd); if first.length() == 0) { firstLetter = 'z'; } else { firstLetter = firstLower.charAt(0); } System.out.println("Your username is " + firstLetter + "" + middleLetter + "" + lastLetter + "" + "" + lastLast + "" + randomNum); System.out.println("Your password is " + password1); System.out.println("Welcome " + first + " " + middle + " " + last + "!"); } }

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  • How to access a String Array location in android?

    - by Vamsi Challa
    Android 2.3.3 This is my code... String[] expression = {""}; //globally declared as empty somewhere in the code below, I am trying to assign a string to it. expression[0] = "Hi"; I keep getting the following error... 12-08 22:12:19.063: E/AndroidRuntime(405): java.lang.ArrayIndexOutOfBoundsException Can someone help me with this.. Can we access the index 0, directly as i am doing? Actual Code ::: static int x = 0; // global declaration String[] assembledArray = {""}; // global declaration assembleArray(strSubString, expression.charAt(i)); //Passing string to the method //Method Implementation private void assembleArray(String strSubString, char charAt) { // TODO Auto-generated method stub assembledArray[x] = strSubString; assembledArray[x+1] = String.valueOf(charAt); x = x+2; }

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  • What's the best way to replace the first letter of a string in Java?

    - by froadie
    I'm trying to convert the first letter of a string to lowercase. I know there's a capitalize method, but I want to accomplish the opposite. This is the code I used: value.substring(0,1).toLowerCase() + value.substring(1) Effective, but feels a bit manual. Are there any other ways to do it? Any better ways? Any Java string functions that do it for you? I was thinking of using something like a replace function, but Java's replace doesn't accept an index as a parameter. You have to pass the actual character/substring. Another way I can think of doing it is something like: value.replaceFirst(value.charAt(0), value.charAt(0).toLowerCase()) Except that replaceFirst expects 2 strings, so the value.charAt(0)s would probably need to be replaced with value.substring(0,1)s. Is this any better? Does it matter? Is there any standard way to do this?

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  • NOT replacing ? with letter guessed

    - by user3720541
    i need my code to replace the ? with the letter guessed. The ? needs to be replaced with a for only those to spots. The word in array is parameter. public static void replace(String[] wordOne, String blanks, char guess) { int i; blanks = wordOne[0]; for (i = 0; i < wordOne.length; i++) { for (int j = 0; j < wordOne[0].length(); j++) { blanks = blanks.replace(blanks.charAt(j), '?'); if (wordOne[0].charAt(i) == guess) { blanks = blanks.replace(blanks.charAt(i), guess); } } } System.out.println(blanks); } }

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  • How do I combine the two methods of cryptography, CBC cipher block and Vingenere Chiper [on hold]

    - by Bangpe
    Code Vingenere static String encrypt(String text, final String key) { String res = ""; text = text.toUpperCase(); for (int i = 0, j = 0; i < text.length(); i++) { char c = text.charAt(i); if (c < 'A' || c > 'Z') continue; res += (char)((c + key.charAt(j) - 2 * 'A') % 26 + 'A'); j = ++j % key.length(); } return res; } Code CBC Chiper public CbcBlockCipher( BlockCipher blockCipher ) { super( blockCipher.keySize(), blockCipher.blockSize() ); this.blockCipher = blockCipher; iv = new byte[blockSize()]; zeroBlock( iv ); temp = new byte[blockSize()]; }

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  • Multiple constructors in C

    - by meepz
    Hello, I am making a string class in C as a homework and I was wondering how I can make multiple constructors with the same name given the parameter. The commented out area is what I tried to do with results from a few searches but that gives me errors. Pretty much I have some cases where I want to create my new string without any parameter then in other cases create a string with a pointer to character. Here is mystring.h #include <stdio.h> #include <stdlib.h> typedef struct mystring { char * c; int length; int (*sLength)(void * s); char (*charAt)(void * s, int i); int (*compareTo)(void * s1, void * s2); struct mystring * (*concat)(void * s1, void * s2); struct mystring * (*subString)(void * s, int begin, int end); void (*printS)(void * s); } string_t; typedef string_t * String; String newString(char * c); String newString2(); int slength(void * s); char charat(void * S, int i); int compareto(void * s1, void * s2); String concat(void * s1, void * s2); String substring(void * S, int begin, int end); void printstring(void * s); And here is mystring.c #include "mystring.h" String newString(){ } String newString(char * input){ //String newString::newString(char * input) { String s; s = (string_t *) malloc(sizeof(string_t)); s->c = (char *) malloc(sizeof(char) * 20); int i = 0; if (input == NULL){ s->c[0] = '\0'; return s; } while (input[i] != '\0') { s->c[i] = input[i]; i++; } //functions s->sLength = slength; s->charAt = charat; s->compareTo = compareto; s->concat = concat; s->subString = substring; s->printS = printstring; return s; }

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