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  • jquery closest dl element

    - by Sebastiaan
    HTML: <dl id="feature-list"> <dt id="basic" class="category-name"> <dd id="basic-toggle" class="category-recepient"> <div class="feature"> <div class="feature-content"> <input id="checkbox1" type="checkbox"> </div> </div> </dd> <dt id="options" class="category-name"> <dd id="options-toggle" class="category-recepient"> <div class="feature"> <div class="feature-content"> <input id="checkbox2" type="checkbox"> </div> </div> </dd> </dl> JQUERY $('input').change(function () { var value = $(this).closest("dt"); //do something with value.id }); $(this).closest("dt") returns the checkbox instead of <dt id="(category)" class="category-name"> I tried $(this).closest(.category-name), $(this).closest("dt").find(.category-name)

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  • Mysql Algorithm for Determining Closest Colour Match

    - by buggedcom
    I'm attempting to create a true mosaic application. At the moment I have one mosaic image, ie the one the mosaic is based on and about 4000 images from my iPhoto library that act as the image library. I have already done my research and analysed the mosaic image. I've converted it into 64x64 slices each of 8 pixels. I've calculated the average colour for each slice and assertain the r, g, b and brightness (Luminance (perceived option 1) = (0.299*R + 0.587*G + 0.114*B)) value. I have done the same for each of the image library photos. The mosaic slices table looks like so. slice_id, slice_image_id, slice_slice_id, slice_image_column, slice_image_row, slice_colour_hex, slice_rgb_red, slice_rgb_blue, slice_rgb_green, slice_rgb_brightness The image library table looks like so. upload_id, upload_file, upload_colour_hex, upload_rgb_red, upload_rgb_green, upload_rgb_blue, upload_rgb_brightness So basically I'm reading the image slices from the slices table into PHP and then pulling out the appropriate images from the library table based on the colour hexs. My trouble is that I've been on this too long and probably had too many energy drinks so am not concentrating properly, I can't figure out the way to pick out the nearest colour neighbor if the appropriate hex code doesn't exist. Any ideas on the perfect query? NB: I know pulling out the slices one by one is not ideal however the mosaic is only rebuilt periodically so a sudden burst in the mysql load doesn't really bother me, however if there us a way to pull the images out all at once that would also be a massive bonus.

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  • Tweaking AStar to find closest location to unreachable destination

    - by Shivan Dragon
    I've implemented AStar in Java and it works ok for an area with obstacles where the chosen destination is reachable. However, when the destination is unreachable, the calculated "path" is in no way to the closest location (to the unreachable location) but is instead some random path. Is there a feasible way to tweak AStar into finding the path to the closest location to an unreachable destination?

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  • Finding closest object to a location within a specific perpendicular distance to direction vector

    - by Sniper
    I have a location and a direction vector indicating facing, I want to find the closest object to that location that is within some tolerance distance (perpendicular distance) to the ray formed by the location and direction vector. Basically I want to get the object that is being aimed at. I have thought about finding all objects within a box and then finding the closest object to my vector from them results, but I am sure that there is a more efficient way. The Z axis is optional, the objects are most likely within a few meters of the search vector.

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  • Points on lines where the two lines are the closest together

    - by James Bedford
    Hey guys, I'm trying to find the points on two lines where the two lines are the closest. I've implemented the following method (Points and Vectors are as you'd expect, and a Line consists of a Point on the line and a non-normalized direction Vector from that point): void CDClosestPointsOnTwoLines(Line line1, Line line2, Point* closestPoints) { closestPoints[0] = line1.pointOnLine; closestPoints[1] = line2.pointOnLine; Vector d1 = line1.direction; Vector d2 = line2.direction; float a = d1.dot(d1); float b = d1.dot(d2); float e = d2.dot(d2); float d = a*e - b*b; if (d != 0) // If the two lines are not parallel. { Vector r = Vector(line1.pointOnLine) - Vector(line2.pointOnLine); float c = d1.dot(r); float f = d2.dot(r); float s = (b*f - c*e) / d; float t = (a*f - b*c) / d; closestPoints[0] = line1.positionOnLine(s); closestPoints[1] = line2.positionOnLine(t); } else { printf("Lines were parallel.\n"); } } I'm using OpenGL to draw three lines that move around the world, the third of which should be the line that most closely connects the other two lines, the two end points of which are calculated using this function. The problem is that the first point of closestPoints after this function is called will lie on line1, but the second point won't lie on line2, let alone at the closest point on line2! I've checked over the function many times but I can't see where the mistake in my implementation is. I've checked my dot product function, scalar multiplication, subtraction, positionOnLine() etc. etc. So my assumption is that the problem is within this method implementation. If it helps to find the answer, this is function supposed to be an implementation of section 5.1.8 from 'Real-Time Collision Detection' by Christer Ericson. Many thanks for any help!

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  • Fastest way to find the closest point to a given point in 3D, in Python.

    - by Saebin
    So lets say I have 10,000 points in A and 10,000 points in B and want to find out the closest point in A for every B point. Currently, I simply loop through every point in B and A to find which one is closest in distance. ie. B = [(.5, 1, 1), (1, .1, 1), (1, 1, .2)] A = [(1, 1, .3), (1, 0, 1), (.4, 1, 1)] C = {} for bp in B: closestDist = -1 for ap in A: dist = sum(((bp[0]-ap[0])**2, (bp[1]-ap[1])**2, (bp[2]-ap[2])**2)) if(closestDist > dist or closestDist == -1): C[bp] = ap closestDist = dist print C However, I am sure there is a faster way to do this... any ideas?

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  • Closest location - Heapify or Build-heap

    - by Trevor Adams
    So lets say we have a set of gps data points and your current location. If asked to give the closest point to your current location we can utilize a heap with the distance being the key. Now if we update the current location, I suspect that only a few of the keys will change enough to violate the heap property. Would it be more efficient to rebuild the heap after recalculating the keys or to run heapify (assuming that only a few of the keys have changed enough). It is assumed that we don't jump around with the new location (new current location is close to the last current location).

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  • Closest to “Mathematica Graphics[]" drawing environment for Python

    - by 500
    Being only familiar with Mathematica and its Graphics, I have now to learn to draw Graphics using Python for a server. Mostly conditional combination of simple shape. What would be a package for Python that make drawing Graphics as close as possible as the Mathematica Graphics environment ? For Example, I would need to do such thing as in : http://mathematica.stackexchange.com/questions/1010/2d-gaussian-distribution-of-squares-coordinates#comment2475_1010

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  • snapping an angle to the closest cardinal direction

    - by Josh E
    I'm developing a 2D sprite-based game, and I'm finding that I'm having trouble with making the sprites rotate correctly. In a nutshell, I've got spritesheets for each of 5 directions (the other 3 come from just flipping the sprite horizontally), and I need to clamp the velocity/rotation of the sprite to one of those directions. My sprite class has a pre-computed list of radians corresponding to the cardinal directions like this: protected readonly List<float> CardinalDirections = new List<float> { MathHelper.PiOver4, MathHelper.PiOver2, MathHelper.PiOver2 + MathHelper.PiOver4, MathHelper.Pi, -MathHelper.PiOver4, -MathHelper.PiOver2, -MathHelper.PiOver2 + -MathHelper.PiOver4, -MathHelper.Pi, }; Here's the positional update code: if (velocity == Vector2.Zero) return; var rot = ((float)Math.Atan2(velocity.Y, velocity.X)); TurretRotation = SnapPositionToGrid(rot); var snappedX = (float)Math.Cos(TurretRotation); var snappedY = (float)Math.Sin(TurretRotation); var rotVector = new Vector2(snappedX, snappedY); velocity *= rotVector; //...snip private float SnapPositionToGrid(float rotationToSnap) { if (rotationToSnap == 0) return 0.0f; var targetRotation = CardinalDirections.First(x => (x - rotationToSnap >= -0.01 && x - rotationToSnap <= 0.01)); return (float)Math.Round(targetRotation, 3); } What am I doing wrong here? I know that the SnapPositionToGrid method is far from what it needs to be - the .First(..) call is on purpose so that it throws on no match, but I have no idea how I would go about accomplishing this, and unfortunately, Google hasn't helped too much either. Am I thinking about this the wrong way, or is the answer staring at me in the face?

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  • Finding distance to the closest point in a point cloud on an uniform grid

    - by erik
    I have a 3D grid of size AxBxC with equal distance, d, between the points in the grid. Given a number of points, what is the best way of finding the distance to the closest point for each grid point (Every grid point should contain the distance to the closest point in the point cloud) given the assumptions below? Assume that A, B and C are quite big in relation to d, giving a grid of maybe 500x500x500 and that there will be around 1 million points. Also assume that if the distance to the nearest point exceds a distance of D, we do not care about the nearest point distance, and it can safely be set to some large number (D is maybe 2 to 10 times d) Since there will be a great number of grid points and points to search from, a simple exhaustive: for each grid point: for each point: if distance between points < minDistance: minDistance = distance between points is not a good alternative. I was thinking of doing something along the lines of: create a container of size A*B*C where each element holds a container of points for each point: define indexX = round((point position x - grid min position x)/d) // same for y and z add the point to the correct index of the container for each grid point: search the container of that grid point and find the closest point if no points in container and D > 0.5d: search the 26 container indices nearest to the grid point for a closest point .. continue with next layer until a point is found or the distance to that layer is greater than D Basically: put the points in buckets and do a radial search outwards until a points is found for each grid point. Is this a good way of solving the problem, or are there better/faster ways? A solution which is good for parallelisation is preferred.

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  • Ubuntu vs Kubuntu: The closest Windows experience

    - by Leonardo
    For an experienced Windows user wanting to start experimenting with Linux, which distro provides the closest Windows experience? Assuming the use cases enumerated below: Web browsing Working with Office 2003/2007 documents File indexing (desktop search) Basic Sql Server 2005 database administration Media playback(MP3, M4P, WMV, WMA, dvds, etc) Windows Live instant messaging Skype calls/video calls Organizing millions of files FTP/SFTP, SSH, telnet automation

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  • Closest Approach question for math/physics heads

    - by Kyle
    I'm using a Segment to Segment closest approach method which will output the closest distance between two segments of length. These objects are moving at variable speed each, so even when it succeeds I'm currently using a 10-step method and calculating the distance between 2 spheres as they move along the two segments. So, basically the length of each segment is the object's traverse in the physics step, and the radius is the objects radius. By stepping, I can tell where they collide, and if they collide (Sort of; for the MOST part.).. I get the feeling that there could be something better. While I sort of believe that the first closest approach call is required, I think that the method immediately following it is a TAD weak. Can anyone help me out? I can illustrate this if needed. Thanks alot!

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  • Finding the closest grid coordinate to the mouse position with javascript/jQuery

    - by Acorn
    What I'm trying to do is make a grid of invisible coordinates on the page equally spaced. I then want a <div> to be placed at whatever grid coordinate is closest to the pointer when onclick is triggered. Here's the rough idea: I have the tracking of the mouse coordinates and the placing of the <div> worked out fine. What I'm stuck with is how to approach the problem of the grid of coordinates. First of all, should I have all my coordinates in an array which I then compare my onclick coordinate to? Or seeing as my grid coordinates follow a rule, could I do something like finding out which coordinate that is a multiple of whatever my spacing is is closest to the onclick coordinate? And then, where do I start with working out which grid point coordinate is closest? What's the best way of going about it? Thanks!

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  • Finding the closest grid coordinate to the mouse onclick with javascript/jQuery

    - by Acorn
    What I'm trying to do is make a grid of invisible coordinates on the page equally spaced. I then want a <div> to be placed at whatever grid coordinate is closest to the pointer when onclick is triggered. Here's the rough idea: I have the tracking of the mouse coordinates and the placing of the <div> worked out fine. What I'm stuck with is how to approach the problem of the grid of coordinates. First of all, should I have all my coordinates in an array which I then compare my onclick coordinate to? Or seeing as my grid coordinates follow a rule, could I do something like finding out which coordinate that is a multiple of whatever my spacing is is closest to the onclick coordinate? And then, where do I start with working out which grid point coordinate is closest? What's the best way of going about it? Thanks!

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  • jQuery.closest(); traversing down the DOM not up

    - by Alex
    Afternoon peoples. I am having a bit of a nightmare traversing a DOM tree properly. I have the following markup <div class="node" id="first-wh"> <div class="content-heading has-tools"> <div class="tool-menu" style="position: relative"> <span class="menu-open stepper-down"></span> <ul class="tool-menu-tools" style="display:none;"> <li><img src="/resources/includes/images/layout/tools-menu/edit22.png" /> Edit <input type="hidden" class="variables" value="edit,hobbies,text,/theurl" /></li> <li>Menu 2</li> <li>Menu 3</li> </ul> </div> <h3>Employment History</h3></div> <div class="content-body editable disabled"> <h3 class="dates">1st January 2010 - 10th June 2010</h3> <h3>Company</h3> <h4>Some Company</h4> <h3>Job Title</h3> <h4>IT Manager</h4> <h3>Job Description</h3> <p class="desc">I headed up the IT department for all things concerning IT and infrastructure</p> <h3>Roles &amp; Responsibilities</h3> <p class="desc">It is a long established fact that a reader will be distracted by the readable content of a page when looking at its layout. The point of using Lorem Ipsum is that it has a more-or-less normal distribution of letters, as opposed to using 'Content here, content here', making it look like readable English. Many desktop publishing packages and web page editors now use Lorem Ipsum as their default model text, and a search for 'lorem ipsum' will uncover many web sites still in their infancy. Various versions have evolved over the years, sometimes by accident, sometimes on purpose (injected humour and the like).</p> </div> <div class="content-body edit-node edit-node-hide"> <input class="variables" type="hidden" value="id,function-id" /> <h3 class="element-title">Employment Dates</h3> <span class="label">From:</span> <input class="edit-mode date date-from" type="text" value="date" /> <span class="label">To:</span> <input class="edit-mode date date-to" type="text" value="date" /> <h3 class="element-title">Company</h3> <input class="edit-mode" type="text" value="The company I worked for" /> <h3 class="element-title">Job Title</h3> <input class="edit-mode" type="text" value="My job title" /> <h3 class="element-title">Job Description</h3> <textarea class="edit-mode" type="text">The Job Title</textarea> <h3 class="element-title">Roles &amp; Responsibilities</h3> <textarea class="edit-mode" type="text">It is a long established fact that a reader will be distracted by the readable content of a page when looking at its layout. The point of using Lorem Ipsum is that it has a more-or-less normal distribution of letters, as opposed to using 'Content here, content here', making it look like readable English. Many desktop publishing packages and web page editors now use Lorem Ipsum as their default model text, and a search for 'lorem ipsum' will uncover many web sites still in their infancy. Various versions have evolved over the years, sometimes by accident, sometimes on purpose (injected humour and the like).</textarea> <div class="node-actions"> <input type="checkbox" class="checkdisable" value="This is a checkbox"/>This element is visible .<br /> <input type="submit" class="account-button save" value="Save" /> <input type="submit" class="account-button cancel" value="Cancel" /></div> </div></div> ... And I am trying to traverse from input.save at the bottom right the way up to div.node... This all works well with one copy of the markup but if I duplicate it (obvisouly changing the ID of the uppermost div.node and use jQuery.closest('div.node') for the upper of the div.node's it will return the element below it not the element above it (which is the right one). I've tried using parents() but that also has it's caveats. Is there some kind of contexyt that can be attached to closest to make it go up and not down? or is there a better way to do this. jQuery code below. $(".save").click(function(){ var element=$(this); var enodes=element.parents('.edit-node').find('input.variables'); var variables=enodes.val(); var onode=element.closest('div.node').find('.editable'); var enode=element.closest('div.node').find('.edit-node-hide'); var vnode=element.closest('div.node-actions').find('input.checkdisable'); var isvis=(vnode.is(":checked")) ? onode.removeClass('disabled') : onode.addClass('disabled'); onode.slideDown(200); enode.fadeOut(100); }); Thanks in advance. Alex P.S It seems that stackoverflow has done something weird to the markup! - I just triple checked it and it is fine but for some reason it's concate'd it below

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  • Finding the closest object in proxmity to the mouse Coordinates

    - by Cam
    Hey there, i've been working on a problem for a while now, which involves targeting the closest movieClip in relation to the x y coords of the mouse, I've attached a nice little acompanying graphic. Each mc added to the stage has it's own sub-class (HotSpots) which uses Pythag to measure distance from mouse. At this stage i can determine the closest value from my Main class but can't figure out how to reference it back to the movieclip... hope this makes sense. Below are the two Classes. My Main Class which attachs the mcs, and monitors mouse movement and traces closest value package { import flash.display.*; import flash.text.*; import flash.events.*; public class Main extends MovieClip { var pos:Number = 50; var nodeArray:Array; public function Main(){ nodeArray = []; for(var i:int = 0; i < 4; i++) { var hotSpot_mc:HotSpots = new HotSpots; hotSpot_mc.x += pos; hotSpot_mc.y += pos; addChild(hotSpot_mc); nodeArray.push(hotSpot_mc); // set some pos pos += 70; } stage.addEventListener(MouseEvent.MOUSE_MOVE,updateProxmity) } public function updateProxmity(e:MouseEvent):void { var tempArray:Array = new Array(); for(var i:int = 0; i < 4; i++) { this['tf'+[i]].text = String(nodeArray[i].dist); tempArray.push(nodeArray[i].dist); } tempArray.sort(Array.NUMERIC); var minValue:int = tempArray[0]; trace(minValue) } } } My HotSpots Class package { import flash.display.MovieClip; import flash.events.Event; import flash.text.TextField; public class HotSpots extends MovieClip { public var XSide:Number; public var YSide:Number; public var dist:Number = 0; public function HotSpots() { addEventListener(Event.ENTER_FRAME, textUp); } public function textUp(event:Event):void { XSide = this.x - MovieClip(root).mouseX; YSide = this.y - MovieClip(root).mouseY; dist = Math.round((Math.sqrt(XSide*XSide + YSide*YSide))); } } } thanks in advance

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  • Pulling application updates from closest server?

    - by Mike Morris
    Setup: 6 Major Sites with Server 2003/2008 DCs doing DHCP/AD Integrated DNS, each on their own subnet. All connect back to datacenter through a 3 mbps WAN ERP server running in the datacenter, accessed by clients at all sites Currently, when we update the software, I manually push a copy of the updated client/config files down to each DC. I have a script that we run on each PC to update the clients. It determines what subnet the PC is on, and pulls the software from that DC. It's messy, but it works. The client has an autoupdate feature, but it'll only pull from the application server (which is housed in the datacenter, over the 3 meg link). It takes forever, since the updates are not "patches" but a full version of the client, even for minor upgrades (bad design). After the most recent patch, you can configure the clients to pull from a different server. Unfortunately, it is the same for all clients. Is there some kind of DNS magic I can use to pull from the local server? For instance, if I tell the clients their update server is ERPUPDATE, can I have their local DNS server return a different IP for ERPUPDATE than the other sites? Example: Client 1 is at site A, client 2 is at site b. They each run the software and a version change is detected. As per the config files, the clients look to ERPUPDATE for their updated client. Client 1 queries DNS for the IP of ERPUPDATE at its current location (site A) DNS at site A returns 192.1.1.5 Client 1 pulls update from 192.1.1.5 Client 2 queries DNS for the IP of ERPUPDATE at its current location (site B) DNS at site B returns 192.1.2.5 Client 2 pulls update from 192.1.2.5 Excuse the poor explanation, I worked 61 hours over the weekend and haven't completely rebounded. I'll be happy to clarify if needed!

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  • Flash: Closest point to MovieClip

    - by LiraNuna
    I need to constrain a point inside a DisplayObject given to me by the artist. I got it working but only for the occations where the cursor is still inside bounds. The limited object is called limited. function onSqMouseMove(event:MouseEvent) { if(bounds.hitTestPoint(event.stageX, event.stageY, true)) { limited.x = event.stageX; limited.y = event.stageY; } else { /* Find closest point in the Sprite */ } } limited.addEventListener(MouseEvent.MOUSE_DOWN, function(event:MouseEvent) { stage.addEventListener(MouseEvent.MOUSE_MOVE, onSqMouseMove); }); limited.addEventListener(MouseEvent.MOUSE_UP, function(event:MouseEvent) { stage.removeEventListener(MouseEvent.MOUSE_MOVE, onSqMouseMove); }); How do I go about implementing the other half of the function? I am aware Sprite's startDrag accepts arguments, where the second one is the constraint rectangle, but in my case, bounds are an arbitrary shape. When the object is dragged outside the bounds, I want to calculate the closest point from the cursor to bounds' polygon. Just to note that bounds can have 'holes'.

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  • Closest Ruby representation of a 'private static final' and 'public static final' class variable in

    - by Hosh
    Given the Java code below, what's the closest you could represent these two static final variables in a Ruby class? And, is it possible in Ruby to distinguish between private static and public static variables as there is in Java? public class DeviceController { ... private static final Device myPrivateDevice = Device.getDevice("mydevice"); public static final Device myPublicDevice = Device.getDevice("mydevice"); ... public static void main(String args[]) { ... } }

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  • Convert Unicode char to closest (most similar) char in ASCII (.net)

    - by Andrey
    Hi all! Do you have any idea how to covert different Unicode characters to their closest ASCII equivalents? Like Ä - A. A googled but didn't find any suitable solution. Trick Encoding.ASCII.GetBytes("Ä")[0] didn't work. (Result was ?). I found that there is class Encoder that has Fallback property that is exactly for cases when char can't be converted, but implementations (EncoderReplacementFallback) are stupid and convert to ?. Any ideas? Thanks, Andrey

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  • using closest().find().text()

    - by erkan
    Hi guys i previously asked a question and got a good solution. here is the question: http://stackoverflow.com/questions/2536892/jquery-how-to-find-an-element-which-is-comming-2-elements-before-current-element when im using the solution which i got : paragrafheading.push($(this).closest(' h3').find(' h3').text()); im getting only [object Object] instead of the element text

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  • Find the closest locations to a given address

    - by xtine
    I have built an application in CakePHP that lists businesses. There are about 2000 entries, and the latitude and longitude coordinates for each business is in the DB. I now am trying to tackle the search function. There will be an input box where the user can put a street address, city, or zipcode, and then I would like it to return the 11 closest businesses as found from the database. How would I go about doing this?

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  • Find the closest vector

    - by Alexey Lebedev
    Hello! Recently I wrote the algorithm to quantize an RGB image. Every pixel is represented by an (R,G,B) vector, and quantization codebook is a couple of 3-dimensional vectors. Every pixel of the image needs to be mapped to (say, "replaced by") the codebook pixel closest in terms of euclidean distance (more exactly, squared euclidean). I did it as follows: class EuclideanMetric(DistanceMetric): def __call__(self, x, y): d = x - y return sqrt(sum(d * d, -1)) class Quantizer(object): def __init__(self, codebook, distanceMetric = EuclideanMetric()): self._codebook = codebook self._distMetric = distanceMetric def quantize(self, imageArray): quantizedRaster = zeros(imageArray.shape) X = quantizedRaster.shape[0] Y = quantizedRaster.shape[1] for i in xrange(0, X): print i for j in xrange(0, Y): dist = self._distMetric(imageArray[i,j], self._codebook) code = argmin(dist) quantizedRaster[i,j] = self._codebook[code] return quantizedRaster ...and it works awfully, almost 800 seconds on my Pentium Core Duo 2.2 GHz, 4 Gigs of memory and an image of 2600*2700 pixels:( Is there a way to somewhat optimize this? Maybe the other algorithm or some Python-specific optimizations.

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