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  • Can I return JSON from an .asmx Web Service if the ContentType is not JSON?

    - by Click Ahead
    I would like to post a form using ajax and jquery to a .asmx webservice and return the value from the webservice as JSON. I'm using ASP.NET 4.0. I know that in order to return JSON from a webservice the following needs to be set (1) dataType: "json" (2) contentType: "application/json; charset=utf-8", (3) type: "POST" (4) set the Data to something. I have tested this and it works fine (i.e. my webservice returns the data as JSON) if all *four are set*. But, lets say in my case I want to do a standard form post i.e. test1=value1&test2=value2 so the contentType is not JSON but I want back JSON {test1:value1}. This doesn't seem to work because the contentType is "application/x-www-form-urlencoded" not "application/json; charset=utf-8". Can anyone tell me why I can't do this? It seems crazy to me that you have to explicitly send JSON to get JSON back, yet if you don't use JSON (i.e. post urlencoded contenttype) then the webservice will return XML. Any insights are greatly appreciated :)

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  • ContentType Issue -- Human is an idiot - Can't figure out how to tie the original model to a Content

    - by bmelton
    Originally started here: http://stackoverflow.com/questions/2650181/django-in-query-as-a-string-result-invalid-literal-for-int-with-base-10 I have a number of apps within my site, currently working with a simple "Blog" app. I have developed a 'Favorite' app, easily enough, that leverages the ContentType framework in Django to allow me to have a 'favorite' of any type... trying to go the other way, however, I don't know what I'm doing, and can't find any examples for. I'll start off with the favorite model: favorite/models.py from django.db import models from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic from django.contrib.auth.models import User class Favorite(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() user = models.ForeignKey(User) content_object = generic.GenericForeignKey() class Admin: list_display = ('key', 'id', 'user') class Meta: unique_together = ("content_type", "object_id", "user") Now, that allows me to loop through the favorites (on a user's "favorites" page, for example) and get the associated blog objects via {{ favorite.content_object.title }}. What I want now, and can't figure out, is what I need to do to the blog model to allow me to have some tether to the favorite (so when it is displayed in a list it can be highlighted, for example). Here is the blog model: blog/models.py from django.db import models from django.db.models import permalink from django.template.defaultfilters import slugify from category.models import Category from section.models import Section from favorite.models import Favorite from django.contrib.auth.models import User from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic class Blog(models.Model): title = models.CharField(max_length=200, unique=True) slug = models.SlugField(max_length=140, editable=False) author = models.ForeignKey(User) homepage = models.URLField() feed = models.URLField() description = models.TextField() page_views = models.IntegerField(null=True, blank=True, default=0 ) created_on = models.DateTimeField(auto_now_add = True) updated_on = models.DateTimeField(auto_now = True) def __unicode__(self): return self.title @models.permalink def get_absolute_url(self): return ('blog.views.show', [str(self.slug)]) def save(self, *args, **kwargs): if not self.slug: slug = slugify(self.title) duplicate_count = Blog.objects.filter(slug__startswith = slug).count() if duplicate_count: slug = slug + str(duplicate_count) self.slug = slug super(Blog, self).save(*args, **kwargs) class Entry(models.Model): blog = models.ForeignKey('Blog') title = models.CharField(max_length=200) slug = models.SlugField(max_length=140, editable=False) description = models.TextField() url = models.URLField(unique=True) image = models.URLField(blank=True, null=True) created_on = models.DateTimeField(auto_now_add = True) def __unicode__(self): return self.title def save(self, *args, **kwargs): if not self.slug: slug = slugify(self.title) duplicate_count = Entry.objects.filter(slug__startswith = slug).count() if duplicate_count: slug = slug + str(duplicate_count) self.slug = slug super(Entry, self).save(*args, **kwargs) class Meta: verbose_name = "Entry" verbose_name_plural = "Entries" Any guidance?

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  • Jquery JQGrid breaks when contentType=application/json?

    - by JK
    I've had to use $.ajaxSetup() to globally change the contentType to application/json $.ajaxSetup({ contentType: "application/json; charset=utf-8" }); (See this question for why I had to use application/json http://stackoverflow.com/questions/2792603/aspnet-mvc-why-is-modelstate-isvalid-false-the-x-field-is-required-when-that) But this breaks the jquery jqrid with this error: Invalid JSON primitive: _search The POST data it is trying to send is: _search=false&nd=1274042681880&rows=20&page=1&sidx=&sord=asc Which of is not in json format, so of course it fails. Is there anyway to tell jqrid what contenttype to use? I have searched on the jqrid wiki, but doesn't have much documentation about anything really. http://www.trirand.com/jqgridwiki/doku.php?do=search&id=contenttype&fulltext=Search

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  • ContentType DocumentTemplate not found in a List

    - by Rich Bennema
    I have the following Feature: <?xml version="1.0" encoding="utf-8"?> <Feature Id="9A3C5D02-A2EB-4725-97F7-CDA6DE319F1B" Title="My Custom Types" Scope="Site" DefaultResourceFile="core" Hidden="TRUE" xmlns="http://schemas.microsoft.com/sharepoint/"> <ElementManifests> <ElementManifest Location="Elements.xml" /> <ElementFile Location="templates/MeetingMinutes.docx" /> </ElementManifests> </Feature> Which contains the following Elements.xml: <?xml version="1.0" encoding="utf-8"?> <Elements xmlns="http://schemas.microsoft.com/sharepoint/"> <Module Name="Templates" Url="_cts/Meeting Minutes" Path="templates" RootWebOnly="TRUE"> <File Url="MeetingMinutes.docx" Type="Ghostable" /> </Module> <ContentType ID="0x01010066DD088A6B8B46BCA775CCD119FBB3E8" Name="Meeting Minutes" Group="Custom Content Types" Version="0"> <FieldRefs /> <DocumentTemplate TargetName="MeetingMinutes.docx"/> </ContentType> </Elements> I then use this ContentType within a custom List Template. I deploy the solution, activate the feature, and create an instance of the List Template. I go into the library and select Settings Document Library Settings Content Types: Meeting Minutes Parent: Meeting Minutes Advanced settings. I'm now in the Advance Settings of the Site Content Type. The URL of the existing document template is MeetingMinutes.docx and there is an (Edit Template) link which points to http://myserver/sites/testsite/_cts/Meeting%20Minutes/MeetingMinutes.docx. Everything's shiny. But, I hit the back button two times so I'm back in the settings of the List Content Type. This time when I click Advance settings, the URL of the existing document template is still MeetingMinutes.docx, but there is no (Edit Template) link. Troubling. Pressing on, I go back to AllItems.aspx and click New Meeting Minutes. As Word is loading, I see a little Opening dialog which says, Opening: http://myserver/sites/testsite/Shared%20Documents/Forms/Document/MeetingMinutes.docx, to which Word responds: "Word was unable to read this document. It may be corrupt." So the Document Template works correctly in the Site Content Type (where it does me no good), but is not working in the List Content Type (where I really need it). Now, I know I could put this in _layouts, but from what I've read, _cts is the way to do it. What am I doing wrong?

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  • SharePoint SPListItem.ContentType.Name - "Message" vs "Discussion" ?

    - by Christopher
    I am writing a C# code to find all of our SharePoint Sites that have emails contained in the Email List page. It appears that some of our email messages are SPListItem.ContentType.Name = "Message" and some of our email messages are SPListItem.ContentType.Name = "Discussion" Aside from the confusion, this is forcing my to cycle through mylist.Folders and mylist.Items in two separate loops, so that I don't miss any of the emails. Is this normal? Any idea why this could be happening? There are threads that contains messages of both types.

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  • Image URL has the contentType "text/html"

    - by user1503025
    I want to implement a method to download Image from website to laptop. public static void DownloadRemoteImageFile(string uri, string fileName) { HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri); HttpWebResponse response = (HttpWebResponse)request.GetResponse(); if ((response.StatusCode == HttpStatusCode.OK || response.StatusCode == HttpStatusCode.Moved || response.StatusCode == HttpStatusCode.Redirect) && response.ContentType.StartsWith("image", StringComparison.OrdinalIgnoreCase)) { //if the remote file was found, download it using (Stream inputStream = response.GetResponseStream()) using (Stream outputStream = File.OpenWrite(fileName)) { byte[] buffer = new byte[4096]; int bytesRead; do { bytesRead = inputStream.Read(buffer, 0, buffer.Length); outputStream.Write(buffer, 0, bytesRead); } while (bytesRead != 0); } } } But the ContentType of request or response is not "image/jpg" or "image/png". They're always "text/html". I think that's why after I save them to local, they has incorrect content and I cannot view them. Can anyone has a solution here? Thanks

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  • Help deciphering exception details from WebRequestCreator when setting ContentType to "application/json"

    - by Stephen Patten
    Hello, This one is real simple, run this Silverlight4 example with the ContentType property commented out and you'll get back a response from from my service in xml. Now uncomment the property and run it and you'll get an exception similar to this one. System.Net.ProtocolViolationException occurred Message=A request with this method cannot have a request body. StackTrace: at System.Net.Browser.AsyncHelper.BeginOnUI(SendOrPostCallback beginMethod, Object state) at System.Net.Browser.ClientHttpWebRequest.EndGetResponse(IAsyncResult asyncResult) at com.patten.silverlight.ViewModels.WebRequestLiteViewModel.<MakeCall>b__0(IAsyncResult cb) InnerException: What I am trying to accomplish is just pulling down some JSON formatted data from my wcf endpoint. Can this really be this hard, or is it another classic example of just overlooking something simple. Edit: While perusing SO, I noticed similar posts, like this one Why am I getting ProtocolViolationException when trying to use HttpWebRequest? Thank you, Stephen try { Address = "http://stephenpattenconsulting.com/Services/GetFoodDescriptionsLookup(2100)"; // Get the URI Uri httpSite = new Uri(Address); // Create the request object using the Browsers networking stack // HttpWebRequest wreq = (HttpWebRequest)WebRequest.Create(httpSite); // Create the request using the operating system's networking stack HttpWebRequest wreq = (HttpWebRequest)WebRequestCreator.ClientHttp.Create(httpSite); // http://stackoverflow.com/questions/239725/c-webrequest-class-and-headers // These headers have been set, so use the property that has been exposed to change them // wreq.Headers[HttpRequestHeader.ContentType] = "application/json"; //wreq.ContentType = "application/json"; // Issue the async request. // http://timheuer.com/blog/archive/2010/04/23/silverlight-authorization-header-access.aspx wreq.BeginGetResponse((cb) => { HttpWebRequest rq = cb.AsyncState as HttpWebRequest; HttpWebResponse resp = rq.EndGetResponse(cb) as HttpWebResponse; StreamReader rdr = new StreamReader(resp.GetResponseStream()); string result = rdr.ReadToEnd(); Jounce.Framework.JounceHelper.ExecuteOnUI(() => { Result = result; }); rdr.Close(); }, wreq); } catch (WebException ex) { Jounce.Framework.JounceHelper.ExecuteOnUI(() => { Error = ex.Message; }); } catch (Exception ex) { Jounce.Framework.JounceHelper.ExecuteOnUI(() => { Error = ex.Message; }); } EDIT: This is how the WCF 4 end point is configured, primarily 'adapted' from this link http://geekswithblogs.net/michelotti/archive/2010/08/21/restful-wcf-services-with-no-svc-file-and-no-config.aspx [ServiceContract] public interface IRDA { [OperationContract] IList<FoodDescriptionLookup> GetFoodDescriptionsLookup(String id); [OperationContract] FOOD_DES GetFoodDescription(String id); [OperationContract] FOOD_DES InsertFoodDescription(FOOD_DES foodDescription); [OperationContract] FOOD_DES UpdateFoodDescription(String id, FOOD_DES foodDescription); [OperationContract] void DeleteFoodDescription(String id); } // RESTfull service [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] public class RDAService : IRDA { [WebGet(UriTemplate = "FoodDescription({id})")] public FOOD_DES GetFoodDescription(String id) { ... } [AspNetCacheProfile("GetFoodDescriptionsLookup")] [WebGet(UriTemplate = "GetFoodDescriptionsLookup({id})")] public IList<FoodDescriptionLookup> GetFoodDescriptionsLookup(String id) { return rda.GetFoodDescriptionsLookup(id); ; } [WebInvoke(UriTemplate = "FoodDescription", Method = "POST")] public FOOD_DES InsertFoodDescription(FOOD_DES foodDescription) { ... } [WebInvoke(UriTemplate = "FoodDescription({id})", Method = "PUT")] public FOOD_DES UpdateFoodDescription(String id, FOOD_DES foodDescription) { ... } [WebInvoke(UriTemplate = "FoodDescription({id})", Method = "DELETE")] public void DeleteFoodDescription(String id) { ... } } And the portion of my web.config that pertains to WCF <system.serviceModel> <serviceHostingEnvironment aspNetCompatibilityEnabled="true" multipleSiteBindingsEnabled="true" /> <standardEndpoints> <webHttpEndpoint> <standardEndpoint name="" helpEnabled="true" automaticFormatSelectionEnabled="true" /> </webHttpEndpoint> </standardEndpoints> </system.serviceModel>

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  • Java (JSP): repeating the contentType header in a "sub-jsp"

    - by Webinator
    What happens when headers are repeated in a .jsp you include in another .jsp? For example if example.jsp starts with this: <?xml version="1.0" encoding="UTF-8"?> <jsp:root version="2.0" xmlns:jsp="http://java.sun.com/JSP/Page"> <jsp:directive.page contentType="text/html; charset=UTF-8" /> <div class="content"> <jsp:include page="support-header.jsp"/> ... (it includes support-header.jsp) And then support-header.jsp starts also with this: <?xml version="1.0" encoding="UTF-8"?> <jsp:root version="2.0" xmlns:jsp="http://java.sun.com/JSP/Page"> <jsp:directive.page contentType="text/html; charset=UTF-8" /> ... Is that a problem? Is it bad practice? What does concretely happen when you repeat several times a header that only corresponds to one header in the resulting .html page?

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  • How do I use HttpWebRequest GET method w/ ContentType="application/json"

    - by Stephen Patten
    Hello, This one is real simple, run this Silverlight4 example with the ContentType property commented out and you'll get back a response from from my service in xml. Now uncomment the property and run it and you'll get an ProtocolViolationException, what should happen is the service returns JSON formatted data. HttpWebRequest wreq = (HttpWebRequest)WebRequestCreator.ClientHttp.Create(new Uri("http://stephenpattenconsulting.com/Services/GetFoodDescriptionsLookup(2100)")); //wreq.ContentType = "application/json"; wreq.BeginGetResponse((cb) => { HttpWebRequest rq = cb.AsyncState as HttpWebRequest; HttpWebResponse resp = rq.EndGetResponse(cb) as HttpWebResponse; // Exception StreamReader rdr = new StreamReader(resp.GetResponseStream()); string result = rdr.ReadToEnd(); rdr.Close(); }, wreq); EDIT: While perusing SO, I noticed similar posts, like this one Why am I getting ProtocolViolationException when trying to use HttpWebRequest? and this one How do I use HttpWebRequest with GET method EDIT: The WCF 4 end point is 'adapted' from this link http://geekswithblogs.net/michelotti/archive/2010/08/21/restful-wcf-services-with-no-svc-file-and-no-config.aspx. I can use Fiddler's request builder to to construct the proper requests and changing the content type does yield the correct results.

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  • Create Excel document from a ContentType in SharePoint

    - by Saab
    Is it possible to create an Excel document using VSTO, using a SharePoint contenttype? Creating a document in VSTO based on a template is easy. Workbook newWorkbook = this.Application.Workbooks.Add(@"C:\temp\TestTemplate.xltx"); But the "template" that's assigned to a content type in SharePoint has xlsx as an extension.

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  • [grails] setting cookies when render type is "contentType: text/json"

    - by Robin Jamieson
    Is it possible to set cookies on response when the return render type is set as json? I can set cookies on the response object when returning with a standard render type and later on, I'm able to get it back on the subsequent request. However, if I were to set the cookies while rendering the return values as json, I can't seem to get back the cookie on the next request object. What's happening here? These two actions work as expected with 'basicForm' performing a regular form post to the action, 'withRegularSubmit', when the user clicks submit. // first action set the cookie and second action yields the originally set cookie def regularAction = { // using cookie plugin response.setCookie("username-regular", "regularCookieUser123",604800); return render(view: "basicForm"); } // called by form post def withRegularSubmit = { def myCookie = request.getCookie("username-regular"); // returns the value 'regularCookieUser123' return render(view: "resultView"); } When I switch to setting the cookie just before returning from the response with json, I don't get the cookie back with the post. The request starts by getting an html document that contains a form and when doc load event is fired, the following request is invoked via javascript with jQuery like this: var someUrl = "http://localhost/jsonAction"; $.get(someUrl, function(jsonData) { // do some work with javascript} The controller work: // this action is called initially and returns an html doc with a form. def loadJsonForm = { return render(view: "jsonForm"); } // called via javascript when the document load event is fired def jsonAction = { response.setCookie("username-json", "jsonCookieUser456",604800); // using cookie plugin return render(contentType:'text/json') { 'pair'('myKey': "someValue") }; } // called by form post def withJsonSubmit = { def myCookie = request.getCookie("username-json"); // got null value, expecting: jsonCookieUser456 return render(view: "resultView"); } The data is returned to the server as a result of the user pressing the 'submit' button and not through a script. Prior to the submit of both 'withRegularSubmit' and 'withJsonSubmit', I see the cookies stored in the browser (Firefox) so I know they reached the client.

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  • Jquery - How to make $.post() use contentType=application/json?

    - by JK.
    I've noticed that when using $.post() in jquery that the default contentType is application/x-www-form-urlencoded - when my asp.net mvc code needs to have contentType=application/json (See this question for why I must use application/json: http://stackoverflow.com/questions/2792603/aspnet-mvc-why-is-modelstate-isvalid-false-the-x-field-is-required-when-that) How can I make $.post() send contentType=application/json? I already have a large number of $.post() functions, so I don't want to change to $.ajax() because it would take too much time If I try $.post(url, data, function(), "json") It still has contentType=application/x-www-form-urlencoded. So what exactly does the "json" param do if it does not change the contenttype to json? If I try $.ajaxSetup({ contentType: "application/json; charset=utf-8" }); That works but affects every single $.get and $.post that I have and causes some to break. So is there some way that I can change the behavior of $.post() to send contentType=application/json?

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  • Jquery - How to make $.post() use contentType=application/json?

    - by JK
    I've noticed that when using $.post() in jquery that the default contentType is application/x-www-form-urlencoded - when my asp.net mvc code needs to have contentType=application/json (See this question for why I must use application/json: http://stackoverflow.com/questions/2792603/aspnet-mvc-why-is-modelstate-isvalid-false-the-x-field-is-required-when-that) How can I make $.post() send contentType=application/json? I already have a large number of $.post() functions, so I don't want to change to $.ajax() because it would take too much time If I try $.post(url, data, function(), "json") It still has contentType=application/x-www-form-urlencoded. So what exactly does the "json" param do if it does not change the contenttype to json? If I try $.ajaxSetup({ contentType: "application/json; charset=utf-8" }); That works but affects every single $.get and $.post that I have and causes some to break. So is there some way that I can change the behavior of $.post() to send contentType=application/json?

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  • Limit of 88 bytes on response.write?

    - by Chris
    I am trying to serve a csv file from a wcf service, as a string response. It looks like this: HttpContext.Current.Response.AddHeader("Content-disposition", "attachment; filename=ImportErrors.csv"); HttpContext.Current.Response.ContentType = "text/csv"; HttpContext.Current.Response.Write(myCsvContent); The response StatusCode is set to (int)HttpStatusCode.OK (200) It works, but I am only getting 88 bytes of my csv and the rest is cut off (not shown). Any suggestions on where to look? I don't see any custom entries in my web.config that are setting a limit.

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  • When and How is an image cached for an ASPX with ContentType = image/jpeg ?

    - by Aamir Hasan
     In asp.net you can cache your page. You can vary the output cache by the followingThe query string in an initial request (HTTP GET).Control values passed on postback (HTTP POST values).The HTTP headers passed with a request.The major version number of the browser making the request.      A custom string in the page. In that case, you create custom code in the Global.asax file to specify the page's caching behavior.Link: http://msdn2.microsoft.com/en-us/library/xadzbzd6(VS.80).aspxyou can set the output caching for your GetImage.aspx, so that you dont have to requery the database every image request ,but you must use varybyParam , so that you have a cached version for every parameters arrangement:set the output cache for your page like this :At top of ASPX page: <%@ OutputCache Duration="600" VaryByParam="ID,Height,Width" %>VaryByParam  attribute allows you to vary the cached output depending on the query string.Adding this will make your images cached for 600 seconds, so that if the image request within this period ,the cahed version will be returned

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  • How to add event receiver to SharePoint2010 content type programmatically

    - by ybbest
    Today , I’d like to show how to add event receiver to How to add event receiver to SharePoint2010 content type programmatically. 1. Create empty SharePoint Project and add a class called ItemContentTypeEventReceiver and make it inherit from SPItemEventReceiver and implement your logic as below public class ItemContentTypeEventReceiver : SPItemEventReceiver { private bool eventFiringEnabledStatus; public override void ItemAdded(SPItemEventProperties properties) { base.ItemAdded(properties); UpdateTitle(properties); } private void UpdateTitle(SPItemEventProperties properties) { SPListItem addedItem = properties.ListItem; string enteredTitle = addedItem["Title"] as string; addedItem["Title"] = enteredTitle + " Updated"; DisableItemEventsScope(); addedItem.Update(); EnableItemEventsScope(); } public override void ItemUpdated(SPItemEventProperties properties) { base.ItemUpdated(properties); UpdateTitle(properties); } private void DisableItemEventsScope() { eventFiringEnabledStatus = EventFiringEnabled; EventFiringEnabled = false; } private void EnableItemEventsScope() { eventFiringEnabledStatus = EventFiringEnabled; EventFiringEnabled = true; } } 2.Create a Site or Web(depending or your requirements) scoped feature and implement your feature event handler as below: public override void FeatureActivated(SPFeatureReceiverProperties properties) { SPWeb web = GetFeatureWeb(properties); //http://karinebosch.wordpress.com/walkthroughs/event-receivers-theory/ string assemblyName =  System.Reflection.Assembly.GetExecutingAssembly().FullName; const string className = "YBBEST.AddEventReceiverToContentType.ItemContentTypeEventReceiver"; SPContentType contentType= web.ContentTypes["Item"]; AddEventReceiverToContentType(className, contentType, assemblyName, SPEventReceiverType.ItemAdded, SPEventReceiverSynchronization.Asynchronous); AddEventReceiverToContentType(className, contentType, assemblyName, SPEventReceiverType.ItemUpdated, SPEventReceiverSynchronization.Asynchronous); contentType.Update(); } protected static void AddEventReceiverToContentType(string className, SPContentType contentType, string assemblyName, SPEventReceiverType eventReceiverType, SPEventReceiverSynchronization eventReceiverSynchronization) { if (className == null) throw new ArgumentNullException("className"); if (contentType == null) throw new ArgumentNullException("contentType"); if (assemblyName == null) throw new ArgumentNullException("assemblyName"); SPEventReceiverDefinition eventReceiver = contentType.EventReceivers.Add(); eventReceiver.Synchronization = eventReceiverSynchronization; eventReceiver.Type = eventReceiverType; eventReceiver.Assembly = assemblyName; eventReceiver.Class = className; eventReceiver.Update(); } 3.Deploy your solution and now you have a event receiver that attached to the Item contentType. You can download the complete source code here.You can also check how to add event receiver to a list using SharePoint event receiver item in Visual Studio2010 in my previous blog.

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  • Is it possible to set ContentType for a WCF WebGet method?

    - by James Cadd
    I'm working with a WCF restful/http method that returns a stream of image data. I want to make sure that the content type is marked as "image/png". The method is defined as: [ServiceContract] [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] [ServiceBehavior(InstanceContextMode = InstanceContextMode.PerCall)] public class TileImageService { [WebGet(UriTemplate = "{id}")] public Stream GetTileImage(string id) { Bitmap bmp = new Bitmap(173, 173); Graphics g = Graphics.FromImage(bmp); g.Clear(Color.Blue); g.DrawString(DateTime.Now.ToLongTimeString(), new Font("Chiller", 20), Brushes.White, new PointF(10, 10)); g.Flush(); MemoryStream ms = new MemoryStream(); bmp.Save(ms, ImageFormat.Png); ms.Seek(0, SeekOrigin.Begin); return ms; } } In Firefox it looks like the content type is marked as application/octet stream. Is there a way to change the content type?

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    I'm new to ofbiz so try to keep your answer as simple as possibly. If you can give examples that would be kind. My problem is I created a project inside the ofbiz/hot-deploy folder namely productionmgntSystem. Inside the folder ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem I created a file app_details_1.ftl. The following are the code of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server. The file is get from user " tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1". But the file is not uploaded. Give me a good solution for uploading a file to the server.

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  • How do you save images to a Blackberry device via HttpConnection?

    - by Kai
    My script fetches xml via httpConnection and saves to persistent store. No problems there. Then I loop through the saved data to compose a list of image url's to fetch via queue. Each of these requests calls the httpConnection thread as so ... public synchronized void run() { HttpConnection connection = (HttpConnection)Connector.open("http://www.somedomain.com/image1.jpg"); connection.setRequestMethod("GET"); String contentType = connection.getHeaderField("Content-type"); InputStream responseData = connection.openInputStream(); connection.close(); outputFinal(responseData, contentType); } public synchronized void outputFinal(InputStream result, String contentType) throws SAXException, ParserConfigurationException, IOException { if(contentType.startsWith("text/")) { // bunch of xml save code that works fine } else if(contentType.equals("image/png") || contentType.equals("image/jpeg") || contentType.equals("image/gif")) { // how to save images here? } else { //default } } What I can't find any good documentation on is how one would take the response data and save it to an image stored on the device. Maybe I just overlooked something very obvious. Any help is very appreciated. Thanks

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  • Image Preview in ASP.NET MVC

    - by imran_ku07
      Introduction :         Previewing an image is a great way to improve the UI of your site. Also it is always best to check the file type, size and see a preview before submitting the whole form. There are some ways to do this using simple JavaScript but not work in all browsers (like FF3).In this Article I will show you how do this using ASP.NET MVC application. You also see how this will work in case of nested form.   Description :          Create a new ASP.NET MVC project and then add a file upload and image control into your View. <form id="form1" method="post" action="NerdDinner/ImagePreview/AjaxSubmit">            <table>                <tr>                    <td>                        <input type="file" name="imageLoad1" id="imageLoad1"  onchange="ChangeImage(this,'#imgThumbnail')" />                    </td>                </tr>                <tr>                    <td align="center">                        <img src="images/TempImage.gif" id="imgThumbnail" height="200px" width="200px">                     </td>                </tr>            </table>        </form>           Note that here NerdDinner is refers to the virtual directory name, ImagePreview is the Controller and ImageLoad is the action name which you will see shortly          I will use the most popular jQuery form plug-in, that turns a form into an AJAX form with very little code. Therefore you must get these from Jquery site and then add these files into your page.          <script src="NerdDinner/Scripts/jquery-1.3.2.js" type="text/javascript"></script>        <script src="NerdDinner/Scripts/jquery.form.js" type="text/javascript"></script>            Then add the javascript function. <script type="text/javascript">function ChangeImage(fileId,imageId){ $("#form1").ajaxSubmit({success: function(responseText){ var d=new Date(); $(imageId)[0].src="NerdDinner/ImagePreview/ImageLoad?a="+d.getTime(); } });}</script>             This function simply submit the form named form1 asynchronously to ImagePreviewController's method AjaxSubmit and after successfully receiving the response, it will set the image src property to the action method ImageLoad. Here I am also adding querystring, preventing the browser to serve the cached image.           Now I will create a new Controller named ImagePreviewController. public class ImagePreviewController : Controller { [AcceptVerbs(HttpVerbs.Post)] public ActionResult AjaxSubmit(int? id) { Session["ContentLength"] = Request.Files[0].ContentLength; Session["ContentType"] = Request.Files[0].ContentType; byte[] b = new byte[Request.Files[0].ContentLength]; Request.Files[0].InputStream.Read(b, 0, Request.Files[0].ContentLength); Session["ContentStream"] = b; return Content( Request.Files[0].ContentType+";"+ Request.Files[0].ContentLength ); } public ActionResult ImageLoad(int? id) { byte[] b = (byte[])Session["ContentStream"]; int length = (int)Session["ContentLength"]; string type = (string)Session["ContentType"]; Response.Buffer = true; Response.Charset = ""; Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.ContentType = type; Response.BinaryWrite(b); Response.Flush(); Session["ContentLength"] = null; Session["ContentType"] = null; Session["ContentStream"] = null; Response.End(); return Content(""); } }             The AjaxSubmit action method will save the image in Session and return content type and content length in response. ImageLoad action method will return the contents of image in response.Then clear these Sessions.           Just run your application and see the effect.   Checking Size and Content Type of File:          You may notice that AjaxSubmit action method is returning both content type and content length. You can check both properties before submitting your complete form.     $(myform).ajaxSubmit({success: function(responseText)            {                                var contentType=responseText.substring(0,responseText.indexOf(';'));                var contentLength=responseText.substring(responseText.indexOf(';')+1);                // Here you can do your validation                var d=new Date();                $(imageId)[0].src="http://weblogs.asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime();            }        });  Handling Nested Form Case:          The above code will work if you have only one form. But this is not the case always.You may have a form control which wraps all the controls and you do not want to submit the whole form, just for getting a preview effect.           In this case you need to create a dynamic form control using JavaScript, and then add file upload control to this form and submit the form asynchronously  function ChangeImage(fileId,imageId)         {            var myform=document.createElement("form");                    myform.action="NerdDinner/ImagePreview/AjaxSubmit";            myform.enctype="multipart/form-data";            myform.method="post";            var imageLoad=document.getElementById(fileId).cloneNode(true);            myform.appendChild(imageLoad);            document.body.appendChild(myform);            $(myform).ajaxSubmit({success: function(responseText)                {                                    var contentType=responseText.substring(0,responseText.indexOf(';'));                    var contentLength=responseText.substring(responseText.indexOf(';')+1);                    var d=new Date();                    $(imageId)[0].src="http://weblogs.asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime();                    document.body.removeChild(myform);                }            });        }            You also need append the child in order to send request and remove them after receiving response.

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  • How to deploy Document Set using CAML in SharePoint2010 solution package

    - by ybbest
    In my last post, I showed you how to use Document Set using SharePoint UI in the browser. In this post, I’d like to show you how to create the same Document Set using CAML and SharePoint solution package. You can download the complete solution here. 1. Create the Application Number site column using the SharePoint empty element item template in VS2010 <?xml version="1.0" encoding="utf-8"?> <Elements xmlns="http://schemas.microsoft.com/sharepoint/"> <Field Type="Text" DisplayName="ApplicationNumber" Required="FALSE" EnforceUniqueValues="FALSE" Indexed="FALSE" MaxLength="255" Group="YBBEST" ID="{916bf3af-5ec1-4441-acd8-88ff62ab1b7e}" Name="ApplicationNumber" ></Field> </Elements> 2. Create the Loan Application Form and Loan Contract Form content types. <?xml version="1.0" encoding="utf-8"?> <Elements xmlns="http://schemas.microsoft.com/sharepoint/"> <!-- Parent ContentType: Document (0x0101) --> <ContentType ID="0x0101005dfbf820ce3c49f69c73a00e0e0e53f6" Name="Loan Contract Form" Group="YBBEST" Description="Loan Contract Form" Inherits="TRUE" Version="0"> <FieldRefs> <FieldRef ID="916bf3af-5ec1-4441-acd8-88ff62ab1b7e" Name="ApplicationNumber" DisplayName="ApplicationNumber" /> </FieldRefs> </ContentType> <!-- Parent ContentType: Document (0x0101) --> <ContentType ID="0x010100f3016e3d03454b93bc4d6ab63941c0d2" Name="Loan Application Form" Group="YBBEST" Description="Loan Application Form" Inherits="TRUE" Version="0"> <FieldRefs> <FieldRef ID="916bf3af-5ec1-4441-acd8-88ff62ab1b7e" Name="ApplicationNumber" DisplayName="ApplicationNumber" /> </FieldRefs> </ContentType> </Elements> 3. Create the Loan Application Document Set. 4. Create the Document Set Welcome Page using the SharePoint Module item template. Notes: 1.When creating document set content type , you need to set the  Inherits=”FALSE”  or remove the  Inherits=”TRUE” from the content type definition (default is  Inherits=”FALSE”) . This is the Document Set limitation in the current version of SharePoint2010. Because of this , you also need to manually  attach the event receiver and  Document Set welcome page to your custom Document Set Content Type. 2. Shared Fields are push down only: 3. Not available in SharePoint foundation (only SharePoint Server 2010). 4. You can’t have folders within document sets (you can place document sets in folders though). For a complete limitation and considerations , you can see the references for details. References: Document Set Limitations and Considerations in SharePoint 2010 1 Document Set Limitations and Considerations in SharePoint 2010 2 Document Sets planning (SharePoint Server 2010) Import Document Sets Issue http://msdn.microsoft.com/en-us/library/gg581064.aspx http://channel9.msdn.com/Events/TechEd/NorthAmerica/2010/OSP305 DocumentSet Class

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  • How to deploy Document Set using CAML in SharePoint2010 solution package

    - by ybbest
    In my last post, I showed you how to use Document Set using SharePoint UI in the browser. In this post, I’d like to show you how to create the same Document Set using CAML and SharePoint solution package. You can download the complete solution here. 1. Create the Application Number site column using the SharePoint empty element item template in VS2010 <?xml version="1.0" encoding="utf-8"?> <Elements xmlns="http://schemas.microsoft.com/sharepoint/"> <Field Type="Text" DisplayName="ApplicationNumber" Required="FALSE" EnforceUniqueValues="FALSE" Indexed="FALSE" MaxLength="255" Group="YBBEST" ID="{916bf3af-5ec1-4441-acd8-88ff62ab1b7e}" Name="ApplicationNumber" ></Field> </Elements> 2. Create the Loan Application Form and Loan Contract Form content types. <?xml version="1.0" encoding="utf-8"?> <Elements xmlns="http://schemas.microsoft.com/sharepoint/"> <!-- Parent ContentType: Document (0x0101) --> <ContentType ID="0x0101005dfbf820ce3c49f69c73a00e0e0e53f6" Name="Loan Contract Form" Group="YBBEST" Description="Loan Contract Form" Inherits="TRUE" Version="0"> <FieldRefs> <FieldRef ID="916bf3af-5ec1-4441-acd8-88ff62ab1b7e" Name="ApplicationNumber" DisplayName="ApplicationNumber" /> </FieldRefs> </ContentType> <!-- Parent ContentType: Document (0x0101) --> <ContentType ID="0x010100f3016e3d03454b93bc4d6ab63941c0d2" Name="Loan Application Form" Group="YBBEST" Description="Loan Application Form" Inherits="TRUE" Version="0"> <FieldRefs> <FieldRef ID="916bf3af-5ec1-4441-acd8-88ff62ab1b7e" Name="ApplicationNumber" DisplayName="ApplicationNumber" /> </FieldRefs> </ContentType> </Elements> 3. Create the Loan Application Document Set. 4. Create the Document Set Welcome Page using the SharePoint Module item template. Notes: 1.When creating document set content type , you need to set the  Inherits=”FALSE”  or remove the  Inherits=”TRUE” from the content type definition (default is  Inherits=”FALSE”) . This is the Document Set limitation in the current version of SharePoint2010. Because of this , you also need to manually  attach the event receiver and  Document Set welcome page to your custom Document Set Content Type. 2. Shared Fields are push down only: 3. Not available in SharePoint foundation (only SharePoint Server 2010). 4. You can’t have folders within document sets (you can place document sets in folders though). For a complete limitation and considerations , you can see the references for details. References: Document Set Limitations and Considerations in SharePoint 2010 1 Document Set Limitations and Considerations in SharePoint 2010 2 Document Sets planning (SharePoint Server 2010) Import Document Sets Issue http://msdn.microsoft.com/en-us/library/gg581064.aspx http://channel9.msdn.com/Events/TechEd/NorthAmerica/2010/OSP305 DocumentSet Class

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    Hi all, Im new to ofbiz.So is my question is have any mistake forgive me for my mistakes.Im new to ofbiz so i did not know some terminologies in ofbiz.Sometimes my question is not clear because of lack of knowledge in ofbiz.So try to understand my question and give me a good solution with respect to my level.Because some solutions are in very high level cannot able to understand for me.So please give the solution with good examples. My problem is i created a project inside the ofbiz/hot-deploy folder namely "productionmgntSystem".Inside the folder "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem" i created a .ftl file namely "app_details_1.ftl" .The following are the coding of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml" ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file "ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java" package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server.The file is get from user "<input type="file"..> tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1".But the file is not uploaded. Give me a good solution for uploading a file to the server. Thanks & Regards, Sivakumar.J

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