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• Will I need a dedicated static IP or a unique IP is enough to SSL enable my website?

  - by Devner

  Hi, This is the first time I am dealing with SSL and Dedicated Static IP /Unique IP. Now this webhost says that they will provide Unique IP (not shared with other customers) but do NOT guarantee that it will be static. Now I plan to make my website SSL enabled and install a SSL certificate. So in order to SSL enable my website, will I really need a Dedicated Static IP or will this Unique IP (without the guarantee that it will be static) be enough? What problems will I need to face if the IP is not static? I have already bought hosting from them. And they showed me that option while adding optional services to the account (after I placed my order), so I did not even have a clue about this. Thank you all in advance.

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• Web Hosting: Any web host that supports files more than 50,000 in number?

  - by Devner

  Hi all, For my PHP & mySQL based application, I am trying to buy website hosting from a host who does not have a limit on the number of files I carry in my hosting account. Almost all the websites have a common limit of 50,000 files (some websites call it 50,000 nodes). The rest(to the extent of my search) are not even close. I have gone through the various websites, Googled lot of information, have spoken with the customer service of the hosting companies and they said that they have a limit of 50,000 files and that's why they call it the LIMIT. Now I have my application, which is a kind of social networking website, where people can upload various files of varying file size. So say if 50,000 users were to join the website and upload 1 file each, the limit of 50,000 will be reached very easily and my 50,001 customer will start facing file upload problems (& so will my account). So I would like to know if there's any website hosting services that do NOT levy such restrictions. In summary, I need the following options: No maximum file limit (more than 50,000 files in account). No maximum file upload limit in server setting (10MB, 12MB, 15MB, 20MB, etc.). Ability to upload files of various types (zip, flv, jg, png, etc.). Ability to stream Audio and Video (live audio & video not necessary). Access to .htaccess Access to php.ini, my.cnf or my.ini (this would be a plus) Supports SSL. Provides dedicated hosting(& IP) as well. Monthly payments without contracts are a plus. If you know of any such website hosting services, please post a reply ( a link to the same will be appreciated ). Thank you.

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• Should I go along with my choice of web hosting company or still search?

  - by Devner

  Hi all, I have been searching for a good website hosting company that can offer me all the services that I need for hosting my PHP & MySQL based website. Now this is a community based website and users will be able to upload pictures, etc. The hosting company that I have in mind, currently lets me do everything... let me use mail(), supports CRON jobs, etc. Of course they are charging about $6/month. Now the only problem with this company is that they have a limit of 50,000 files that can exist within the hosting account at any time. This kind of contradicts their frontpage ad of "UNLIMITED SPACE" on their website. Apart from this, I know of no other reason why I should not go with this hosting company. But my issue is that 50,000 file limit is what I cannot live with, once the users increase in significant number and the files they upload, exceed 50,000 in number. Now since this is a dynamic website and also includes sensitive issues like payments, etc. I am not sure if I should go ahead with this company as I am just starting out and then later switch over to a better hosting company which does not limit me with 50,000 files. If I need to switch over once I host with this company, I will need to take backups of all the files located in my account (jpg, zip, etc.), then upload them to the new host. I am not aware of any tools that can help me in this process. Can you please mention if you know any? I can go ahead with the other companies right now, but their cost is double/triple of the current price and they all sport less features than my current choice. If I pay more, then they are ready to accommodate my higher demands. Unfortunately, the company that I am willing to go with now, does NOT have any other higher/better plans that I can switch to. So that's the really really bad part. So my question(s): Since I am starting out with my website and since the scope of users initially is going to be less/small, should I go ahead with the current choice and then once the demand increases, switch over to a better provider? If yes, how can I transfer my database, especially the jpg files, etc. to the new provider? I don't even know the tools required to backup and restore to another host. (I don't like this idea but still..) Should I go ahead and pay more right now and go with better providers (without knowing if the website is going to do really that well) just for saving myself the trouble of having to take a backup of the 50,000 files and upload to a new host from an old host and just start paying double/triple the price without even knowing if I would receive back the returns as I expected? Backup and Restore in such a bulky numbers is something that I have never done before and hence I am stuck here trying to decide what to do. The price per month is also a considerable factor in my decision. All these web hosting companies say one common thing: It is customers responsibility to backup and restore data and they are not liable for any loss. So no matter what hosting company that I would like to go with, they ask me to take backup via FTP so that I can restore them whenever I want (& it seems to be safer to have the files locally with me). Some are providing tools for backup and some are not and I am not sure how much their backup tools can be trusted considering the disclaimers they have. I have never backed-up and restored 50,000 files from one web host to another, so please, all you experienced people out there, leave your comments and let me know your suggestions so that I can decide. I have spent 2 days fighting with myself trying to decide what to do and finally concluded that this is a double-edged sword and I can't arrive at a satisfactory final decision without involving others suggestions. I believe that someone must be out there who may have had such troublesome decision to make. So all your suggestions to help me make my decision are appreciated. Thank you all.

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• Need to capture and store receiver's details via IPN by using Paypal Mass Pay API

  - by Devner

  Hi all, This is a question about Paypal Mass Pay IPN. My platform is PHP & mySQL. All over the Paypal support website, I have found IPN for only payments made. I need an IPN on similar lines for Mass Pay but could not find it. Also tried experimenting with already existing Mass Pay NVP code, but that did not work either. What I am trying to do is that for all the recipients to whom the payment has been successfully sent via Mass Pay, I want to record their email, amount and unique_id in my own database table. If possible, I want to capture the payment status as well, whether it has been a success of failure and based upon the same, I need to do some in house processing. The existing code Mass pay code is below: <?php $environment = 'sandbox'; // or 'beta-sandbox' or 'live' /** * Send HTTP POST Request * * @param string The API method name * @param string The POST Message fields in &name=value pair format * @return array Parsed HTTP Response body */ function PPHttpPost($methodName_, $nvpStr_) { global $environment; // Set up your API credentials, PayPal end point, and API version. $API_UserName = urlencode('my_api_username'); $API_Password = urlencode('my_api_password'); $API_Signature = urlencode('my_api_signature'); $API_Endpoint = "https://api-3t.paypal.com/nvp"; if("sandbox" === $environment || "beta-sandbox" === $environment) { $API_Endpoint = "https://api-3t.$environment.paypal.com/nvp"; } $version = urlencode('51.0'); // Set the curl parameters. $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $API_Endpoint); curl_setopt($ch, CURLOPT_VERBOSE, 1); // Turn off the server and peer verification (TrustManager Concept). curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_POST, 1); // Set the API operation, version, and API signature in the request. $nvpreq = "METHOD=$methodName_&VERSION=$version&PWD=$API_Password&USER=$API_UserName&SIGNATURE=$API_Signature$nvpStr_"; // Set the request as a POST FIELD for curl. curl_setopt($ch, CURLOPT_POSTFIELDS, $nvpreq); // Get response from the server. $httpResponse = curl_exec($ch); if(!$httpResponse) { exit("$methodName_ failed: ".curl_error($ch).'('.curl_errno($ch).')'); } // Extract the response details. $httpResponseAr = explode("&", $httpResponse); $httpParsedResponseAr = array(); foreach ($httpResponseAr as $i => $value) { $tmpAr = explode("=", $value); if(sizeof($tmpAr) > 1) { $httpParsedResponseAr[$tmpAr[0]] = $tmpAr[1]; } } if((0 == sizeof($httpParsedResponseAr)) || !array_key_exists('ACK', $httpParsedResponseAr)) { exit("Invalid HTTP Response for POST request($nvpreq) to $API_Endpoint."); } return $httpParsedResponseAr; } // Set request-specific fields. $emailSubject =urlencode('example_email_subject'); $receiverType = urlencode('EmailAddress'); $currency = urlencode('USD'); // or other currency ('GBP', 'EUR', 'JPY', 'CAD', 'AUD') // Add request-specific fields to the request string. $nvpStr="&EMAILSUBJECT=$emailSubject&RECEIVERTYPE=$receiverType&CURRENCYCODE=$currency"; $receiversArray = array(); for($i = 0; $i < 3; $i++) { $receiverData = array( 'receiverEmail' => "[email protected]", 'amount' => "example_amount", 'uniqueID' => "example_unique_id", 'note' => "example_note"); $receiversArray[$i] = $receiverData; } foreach($receiversArray as $i => $receiverData) { $receiverEmail = urlencode($receiverData['receiverEmail']); $amount = urlencode($receiverData['amount']); $uniqueID = urlencode($receiverData['uniqueID']); $note = urlencode($receiverData['note']); $nvpStr .= "&L_EMAIL$i=$receiverEmail&L_Amt$i=$amount&L_UNIQUEID$i=$uniqueID&L_NOTE$i=$note"; } // Execute the API operation; see the PPHttpPost function above. $httpParsedResponseAr = PPHttpPost('MassPay', $nvpStr); if("SUCCESS" == strtoupper($httpParsedResponseAr["ACK"]) || "SUCCESSWITHWARNING" == strtoupper($httpParsedResponseAr["ACK"])) { exit('MassPay Completed Successfully: '.print_r($httpParsedResponseAr, true)); } else { exit('MassPay failed: ' . print_r($httpParsedResponseAr, true)); } ?> In the code above, how and where do I add code to capture the fields that I requested above? Any code indicating the solution is highly appreciated. Thank you very much.

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• PHP, MySQL: Receive email, auto search in DB & send email based on the results

  - by Devner

  Hi all, Visitors can contact staff by means of contact form (visitor needs to submit email as well). This will be stored in DB. Now considering that staff responds to this message, the reply from the staff would be sent to the visitors email directly. Say if the user wants to follow up on the message sent by the staff, I would like the visitor to just hit the reply button in his email service & send me his questions on the same topic, but just retain the ID in the Subject line. So when the visitor send this email, I would like to receive the email & at the same time, try to search in my DB if the ID that is present in the email subject, actually exists in the system. If yes, that would be sent back to the same staff member who handled the response previously or it would be assigned to a new staff member. That being said, I was thinking of how to do this. The part where I am really held up is when the staff receives the actual email from the visitors email, how can I check the DB? Say I am/staff is receiving emails at [email protected]. When visitor sends reply email, then it would be sent to [email protected]. How can I check to see if the ID in the subject line of the email that I received at [email protected], actually exists in my DB in my website? This is where I am really stuck. Looking forward for your replies. Thank you.

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• php & mySQL: Storing doc, xls, zip, etc. with limited access and archiving

  - by Devner

  Hi all, In my application, I have a provision for users to upload files like doc, xls, zip, etc. I would like to know how to store these files on my website and have only restricted people access it. I may have a group of people and let only these group access those uploaded files. I know that some may try to just copy the link to the document or the file and pass it to another (non-permitted) user and they can download it. So how can I prevent it? How can I check if the request to download the file was made by a legitimate user who has access to the file? The usernames of the group members are stored in the database along with the document name and location in the database so they can access it. But how do I prevent non-permitted users from being able to access that confidential data in all ways? With the above in mind, how do I store these documents? Do I store the documents in a blob column in the Database or just just let user upload to a folder and merely store the path to the file in the database? The security of the documents is of utmost importance. So any procedure that could facilitate this feature would definitely help. I am not into Object Oriented programming so if you have a simpler code that you would like to share with me, I would greatly appreciate it. Also how do I archive documents that are old? Like say there are documents that are 1 year old and I want to conserve my website space by archiving them but still make them available to the user when they need it. How do I go about this? Thank you.

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• (PHP) Validation, Security and Speed - Does my app have these?

  - by Devner

  Hi all, I am currently working on a building community website in PHP. This contains forms that a user can fill right from registration to lot of other functionality. I am not an Object-oriented guy, so I am using functions most of the time to handle my application. I know I have to learn OOPS, but currently need to develop this website and get it running soon. Anyway, here's a sample of what I let my app. do: Consider a page (register.php) that has a form where a user has 3 fields to fill up, say: First Name, Last Name and Email. Upon submission of this form, I want to validate the form and show the corresponding errors to the users: <form id="form1" name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <label for="name">Name:</label> <input type="text" name="name" id="name" /><br /> <label for="lname">Last Name:</label> <input type="text" name="lname" id="lname" /><br /> <label for="email">Email:</label> <input type="text" name="email" id="email" /><br /> <input type="submit" name="submit" id="submit" value="Submit" /> </form> This form will POST the info to the same page. So here's the code that will process the POST'ed info: <?php require("functions.php"); if( isset($_POST['submit']) ) { $errors = fn_register(); if( count($errors) ) { //Show error messages } else { //Send welcome mail to the user or do database stuff... } } ?> <?php //functions.php page: function sql_quote( $value ) { if( get_magic_quotes_gpc() ) { $value = stripslashes( $value ); } else { $value = addslashes( $value ); } if( function_exists( "mysql_real_escape_string" ) ) { $value = mysql_real_escape_string( $value ); } return $value; } function clean($str) { $str = strip_tags($str, '<br>,<br />'); $str = trim($str); $str = sql_quote($str); return $str; } foreach ($_POST as &$value) { if (!is_array($value)) { $value = clean($value); } else { clean($value); } } foreach ($_GET as &$value) { if (!is_array($value)) { $value = clean($value); } else { clean($value); } } function validate_name( $fld, $min, $max, $rule, $label ) { if( $rule == 'required' ) { if ( trim($fld) == '' ) { $str = "$label: Cannot be left blank."; return $str; } } if ( isset($fld) && trim($fld) != '' ) { if ( isset($fld) && $fld != '' && !preg_match("/^[a-zA-Z\ ]+$/", $fld)) { $str = "$label: Invalid characters used! Only Lowercase, Uppercase alphabets and Spaces are allowed"; } else if ( strlen($fld) < $min or strlen($fld) > $max ) { $curr_char = strlen($fld); $str = "$label: Must be atleast $min character &amp; less than $max char. Entered characters: $curr_char"; } else { $str = 0; } } else { $str = 0; } return $str; } function validate_email( $fld, $min, $max, $rule, $label ) { if( $rule == 'required' ) { if ( trim($fld) == '' ) { $str = "$label: Cannot be left blank."; return $str; } } if ( isset($fld) && trim($fld) != '' ) { if ( !eregi('^[a-zA-Z0-9._-]+@[a-zA-Z0-9._-]+\.([a-zA-Z]{2,4})$', $fld) ) { $str = "$label: Invalid format. Please check."; } else if ( strlen($fld) < $min or strlen($fld) > $max ) { $curr_char = strlen($fld); $str = "$label: Must be atleast $min character &amp; less than $max char. Entered characters: $curr_char"; } else { $str = 0; } } else { $str = 0; } return $str; } function val_rules( $str, $val_type, $rule='required' ){ switch ($val_type) { case 'name': $val = validate_name( $str, 3, 20, $rule, 'First Name'); break; case 'lname': $val = validate_name( $str, 10, 20, $rule, 'Last Name'); break; case 'email': $val = validate_email( $str, 10, 60, $rule, 'Email'); break; } return $val; } function fn_register() { $errors = array(); $val_name = val_rules( $_POST['name'], 'name' ); $val_lname = val_rules( $_POST['lname'], 'lname', 'optional' ); $val_email = val_rules( $_POST['email'], 'email' ); if ( $val_name != '0' ) { $errors['name'] = $val_name; } if ( $val_lname != '0' ) { $errors['lname'] = $val_lname; } if ( $val_email != '0' ) { $errors['email'] = $val_email; } return $errors; } //END of functions.php page ?> OK, now it might look like there's a lot, but lemme break it down target wise: 1. I wanted the foreach ($_POST as &$value) and foreach ($_GET as &$value) loops to loop through the received info from the user submission and strip/remove all malicious input. I am calling a function called clean on the input first to achieve the objective as stated above. This function will process each of the input, whether individual field values or even arrays and allow only tags and remove everything else. The rest of it is obvious. Once this happens, the new/cleaned values will be processed by the fn_register() function and based on the values returned after the validation, we get the corresponding errors or NULL values (as applicable). So here's my questions: 1. This pretty much makes me feel secure as I am forcing the user to correct malicious data and won't process the final data unless the errors are corrected. Am I correct? Does the method that I follow guarantee the speed (as I am using lots of functions and their corresponding calls)? The fields of a form differ and the minimum number of fields I may have at any given point of time in any form may be 3 and can go upto as high as 100 (or even more, I am not sure as the website is still being developed). Will having 100's of fields and their validation in the above way, reduce the speed of application (say upto half a million users are accessing the website at the same time?). What can I do to improve the speed and reduce function calls (if possible)? 3, Can I do something to improve the current ways of validation? I am holding off object oriented approach and using FILTERS in PHP for the later. So please, I request you all to suggest me way to improve/tweak the current ways and suggest me if the script is vulnerable or safe enough to be used in a Live production environment. If not, what I can do to be able to use it live? Thank you all in advance.

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• PHP, MySQL: mysql substitute for php in_array function

  - by Devner

  Hi all, Say if I have an array and I want to check if an element is a part of that array, I can go ahead and use in_array( needle, haystack ) to determine the results. I am trying to see the PHP equivalent of this for my purpose. Now you might have an instant answer for me and you might be tempted to say "Use IN". Yes, I can use IN, but that's not fetching the desired results. Let me explain with an example: I have a column called "pets" in DB table. For a record, it has a value: Cat, dog, Camel (Yes, the column data is a comma separated value). Consider that this row has an id of 1. Now I have a form where I can enter the value in the form input and use that value check against the value in the DB. So say I enter the following comma separated value in the form input: CAT, camel (yes, CAT is uppercase & intentional as some users tend to enter it that way). Now when I enter the above info in the form input and submit, I can collect the POST'ed info and use the following query: $search = $_POST['pets']; $sql = "SELECT id FROM table WHERE pets IN ('$search') "; The above query is not fetching me the row that already exists in the DB (remember the record which has Cat, dog, Camel as the value for the pets column?). I am trying to get the records to act as a superset and the values from the form input as subsets. So in this case I am expecting the id value to show up as the values exist in the column, but this is not happending. Now say if I enter just CAT as the form input and perform the search, it should show me the ID 1 row. Now say if I enter just camel, cAT as the form input and perform the search, it should show me the ID 1 row. How can I achieve the above? Thank you.

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• php, mySQL & AJAX: Unable to use sessions across the scripts in the same domain

  - by Devner

  Hi all, I have the following pages: page1.php, page2.php and page3.php. Code in each of them is as below CODE: page1.php <script type="text/javascript"> $(function(){ $('#imgID').upload({ submit_to_url: "page2.php", file_name: 'myfile1', description : "Image", limit : 1, file_types : "*.jpg", }) }); </script> <body> <form action="page3.php" method="post" enctype="multipart/form-data" name="frm1" id="frm1"> //Some other text fields <input type="submit" name="submit" id="submit" value="Submit" /> </form> </body> page2.php <?php session_start(); $a = $_SESSION['a']; $b = $_SESSION['b']; $c = $_SESSION['c']; $res = mysql_query("SELECT col FROM table WHERE col1 = $a AND col2 = $b AND col3 = $c LIMIT 1"); $num_rows = mysql_num_rows($res); echo $num_rows; //echos 0 when in fact it should have been 1 because the data in the Session exists. //Ok let's proceed further //... Do some stuff... //Store some more values and create new session variables (and assume that page1.php is going to be able to use it) $_SESSION['d'] = 'd'; $_SESSION['e'] = 'e'; $_SESSION['f'] = 'f'; if (move_uploaded_file($_FILES['file']['tmp_name'], $file)) { echo "success"; } else { echo "error ".$_FILES['file']['error']; } ?> page3.php <?php session_start(); if( isset($_POST['submit']) ) { //These sessions are non-existent although the AJAX request //to page2.php may have created them when called via AJAX from within page1.php echo $_SESSION['d'].$_SESSION['e'].$_SESSION['f']; ?> } ?> As the code says it I am posting some info via AJAX call from page1.php to page2.php. page2.php is supposed to be able to use the session values from page1.php i.e. $_SESSION['a'], $_SESSION['b'] and $_SESSION['c'] but it does not. Why? How can I fix this? page2.php is creating some more sessions after some processing is done and a response is sent back to page1.php. The submit button of the form on page1.php is hit and the page gets POST'ed to page3.php. But when the SESSION info that gets created in page2.php is echoed, it's blank signifying that SESSIONS from page2.php are not used. How can I fix this? I looked over a lot of information and have spent about 50 hours trying to do different things with my scripts before arriving at the above conclusions. My app. is custom made using function (not OOPS) and does not use any PHP frameworks & I am not even about to use any as my knowledge of OOP concepts is limited any many frameworks are object oriented. I came across race conditions, but the solutions provided don't help too much. One more solution of using DB to hold sessions and seek and retrieve from DB is the last thing on my mind and I really want to avoid creating table, coding and maintaining code for a task as simple as just keeping sessions across pages in the same domain. So my request is: Is there a way that I can solve the above problem(s) via simple coding in present conditions? Any help is appreciated. Thank you.

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• PHP, MySQL, jQuery, AJAX: json data returns correct response but frontend returns error

  - by Devner

  Hi all, I have a user registration form. I am doing server side validation on the fly via AJAX. The quick summary of my problem is that upon validating 2 fields, I get error for the second field validation. If I comment first field, then the 2nd field does not show any error. It has this weird behavior. More details below: The HTML, JS and Php code are below: HTML FORM: <form id="SignupForm" action=""> <fieldset> <legend>Free Signup</legend> <label for="username">Username</label> <input name="username" type="text" id="username" /><span id="status_username"></span><br /> <label for="email">Email</label> <input name="email" type="text" id="email" /><span id="status_email"></span><br /> <label for="confirm_email">Confirm Email</label> <input name="confirm_email" type="text" id="confirm_email" /><span id="status_confirm_email"></span><br /> </fieldset> <p> <input id="sbt" type="button" value="Submit form" /> </p> </form> JS: <script type="text/javascript"> $(document).ready(function() { $("#email").blur(function() { var email = $("#email").val(); var msgbox2 = $("#status_email"); if(email.length > 3) { $.ajax({ type: 'POST', url: 'check_ajax2.php', data: "email="+ email, dataType: 'json', cache: false, success: function(data) { if(data.success == 'y') { alert('Available'); } else { alert('Not Available'); } } }); } return false; }); $("#confirm_email").blur(function() { var confirm_email = $("#confirm_email").val(); var email = $("#email").val(); var msgbox3 = $("#status_confirm_email"); if(confirm_email.length > 3) { $.ajax({ type: 'POST', url: 'check_ajax2.php', data: 'confirm_email='+ confirm_email + '&email=' + email, dataType: 'json', cache: false, success: function(data) { if(data.success == 'y') { alert('Available'); } else { alert('Not Available'); } } , error: function (data) { alert('Some error'); } }); } return false; }); }); </script> PHP code: <?php //check_ajax2.php if(isset($_POST['email'])) { $email = $_POST['email']; $res = mysql_query("SELECT uid FROM members WHERE email = '$email' "); $i_exists = mysql_num_rows($res); if( 0 == $i_exists ) { $success = 'y'; $msg_email = 'Email available'; } else { $success = 'n'; $msg_email = 'Email is already in use.</font>'; } print json_encode(array('success' => $success, 'msg_email' => $msg_email)); } if(isset($_POST['confirm_email'])) { $confirm_email = $_POST['confirm_email']; $email = ( isset($_POST['email']) && trim($_POST['email']) != '' ? $_POST['email'] : '' ); $res = mysql_query("SELECT uid FROM members WHERE email = '$confirm_email' "); $i_exists = mysql_num_rows($res); if( 0 == $i_exists ) { if( isset($email) && isset($confirm_email) && $email == $confirm_email ) { $success = 'y'; $msg_confirm_email = 'Email available and match'; } else { $success = 'n'; $msg_confirm_email = 'Email and Confirm Email do NOT match.'; } } else { $success = 'n'; $msg_confirm_email = 'Email already exists.'; } print json_encode(array('success' => $success, 'msg_confirm_email' => $msg_confirm_email)); } ?> THE PROBLEM: As long as I am validating the $_POST['email'] as well as $_POST['confirm_email'] in the check_ajax2.php file, the validation for confirm_email field always returns an error. With my limited knowledge of Firebug, however, I did find out that the following were the responses when I entered email and confirm_email in the fields: RESPONSE 1: {"success":"y","msg_email":"Email available"} RESPONSE 2: {"success":"y","msg_email":"Email available"}{"success":"n","msg_confirm_email":"Email and Confirm Email do NOT match."} Although the RESPONSE 2 shows that we are receiving the correct message via msg_confirm_email, in the front end, the alert 'Some error' is popping up (I have enabled the alert for debugging). I have spent 48 hours trying to change every part of the code wherever possible, but with only little success. What is weird about this is that if I comment the validation for $_POST['email'] field completely, then the validation for $_POST['confirm_email'] field is displaying correctly without any errors. If I enable it back, it is validating email field correctly, but when it reaches the point of validating confirm_email field, it is again showing me the error. I have also tried renaming success variable in check_ajax2.php page to other different names for both $_POST['email'] and $_POST['confirm_email'] but no success. I will be adding more fields in the form and validating within the check_ajax2.php page. So I am not planning on using different ajax pages for validating each of those fields (and I don't think it's smart to do it that way). I am not a jquery or AJAX guru, so all help in resolving this issue is highly appreciated. Thank you in advance.

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• (mySQL) Unable to query 2 tables properly for data

  - by Devner

  I have 2 tables. One is 'page_links' and the other is 'rpp'. Table page_links is the superset of table rpp. The following is the schema of my tables: -- Table structure for table `page_links` -- CREATE TABLE IF NOT EXISTS `page_links` ( `page` varchar(255) NOT NULL, `page_link` varchar(100) NOT NULL, `heading_id` tinyint(3) unsigned NOT NULL, PRIMARY KEY (`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `page_links` -- INSERT INTO `page_links` (`page`, `page_link`, `heading_id`) VALUES ('a1.php', 'A1', 8), ('b1.php', 'B1', 8), ('c1.php', 'C1', 5), ('d1.php', 'D1', 5), ('e1.php', 'E1', 8), ('f1.php', 'F1', 8), ('g1.php', 'G1', 8), ('h1.php', 'H1', 1), ('i1.php', 'I1', 1), ('j1.php', 'J1', 8), ('k1.php', 'K1', 8), ('l1.php', 'L1', 8), ('m1.php', 'M1', 8), ('n1.php', 'N1', 8), ('o1.php', 'O1', 8), ('p1.php', 'P1', 4), ('q1.php', 'Q1', 5), ('r1.php', 'R1', 4); -- Table structure for table `rpp` -- CREATE TABLE IF NOT EXISTS `rpp` ( `role_id` tinyint(3) unsigned NOT NULL, `page` varchar(255) NOT NULL, `is_allowed` tinyint(1) NOT NULL, PRIMARY KEY (`role_id`,`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `rpp` -- INSERT INTO `rpp` (`role_id`, `page`, `is_allowed`) VALUES (3, 'a1.php', 1), (3, 'b1.php', 1), (3, 'c1.php', 1), (3, 'd1.php', 1), (3, 'e1.php', 1), (3, 'f1.php', 1), (3, 'h1.php', 1), (3, 'i1.php', 1), (3, 'l1.php', 1), (3, 'm1.php', 1), (3, 'n1.php', 1), (4, 'a1.php', 1), (4, 'b1.php', 1), (4, 'q1.php', 1), (5, 'r1.php', 1); WHAT I AM TRYING TO DO: I am trying to query both the above tables (in a single query) in such a way that all the pages from page_links are displayed along with the is_allowed value from rpp for a particular role. For example, I want to get the is_allowed value of all the pages from rpp for role_id = 3 and at the same time, list all the available pages from page_links. A clear example of my expected result would be: page is_allowed role_id ---------------------------------------- a1.php 1 3 b1.php 1 3 c1.php 1 3 d1.php 1 3 e1.php 1 3 f1.php 1 3 g1.php NULL NULL h1.php 1 3 i1.php 1 3 j1.php NULL NULL k1.php NULL NULL l1.php 1 3 m1.php 1 3 n1.php 1 3 o1.php NULL NULL p1.php NULL NULL q1.php NULL NULL r1.php NULL NULL One more example of my desired result could be achieved by doing a LEFT JOIN rpp ON page_links.page = rpp.page but we need to omit using role_id = 3 (or any value) to be able to get that. But I do want to specify the role_id as well and get the results. I need the query to be able to get this result. I would appreciate any replies that could help me with this. If you can suggest me any changes as well to the table(s) design to be able to achieve the desired result, that's good as well. Thanks in advance.

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• Web Hosting: Any web host that supports files more than 50,000 in number?

  - by Devner

  Hi all, For my PHP & mySQL based application, I am trying to buy website hosting from a host who does not have a limit on the number of files I carry in my hosting account. Almost all the websites have a common limit of 50,000 files (some websites call it 50,000 nodes). The rest(to the extent of my search) are not even close. I have gone through the various websites, Googled lot of information, have spoken with the customer service of the hosting companies and they said that they have a limit of 50,000 files and that's why they call it the LIMIT. Now I have my application, which is a kind of social networking website, where people can upload various files of varying file size. So say if 50,000 users were to join the website and upload 1 file each, the limit of 50,000 will be reached very easily and my 50,001 customer will start facing file upload problems (& so will my account). So I would like to know if there's any website hosting services that do NOT levy such restrictions. In summary, I need the following options: No maximum file limit (more than 50,000 files in account). No maximum file upload limit in server setting (10MB, 12MB, 15MB, 20MB, etc.). Ability to upload files of various types (zip, flv, jg, png, etc.). Ability to stream Audio and Video (live audio & video not necessary). Access to .htaccess Access to php.ini, my.cnf or my.ini (this would be a plus) Supports SSL. Provides dedicated hosting(& IP) as well. Monthly payments without contracts are a plus. If you know of any such website hosting services, please post a reply ( a link to the same will be appreciated ). Thank you.

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• PHP, MySQL: Display only required parts of my website in sister website

  - by Devner

  Hi all, Now I have my website built on PHP & Mysql. Consider this like a forum. Now when a user posts a reply in my website 1 (ex. www.website1.com), I want to be able to show the starting thread and it's related replies in a sister website of mine. I want to do this in a way that it does not show the rest of the page & other page contents (like logo etc.). I don't think iframe would be a solution because an iframe would embed the whole page and the users visiting my sister website (totally different domain i.e. www.website2.com) would be able to see all the page contents, like logo etc. I want to avoid that. I want to make them see only limited information from website 1 and only the info. that I intend. I hope that makes sense. In a way, you could say that I am trying to replicate my 1 website, and show only a limited part of it. Users browsing 2nd website can post a reply in the 2nd website and it should automatically be posted & visible to the visitors of the website 1. Users of website 1 should not know that a user of website 2 has posted it. They would feel that some user from website 1 has posted it. Do I have to use 2 separate mysql DB or just 1? I think it would be problematic if I am trying to use different DB. I also feel I might have to face DB connectivity issues as I can connect to only 1 DB at a time. It's basically like users of website1.com should feel that they are replying to users of website1.com & users of website2.com should feel that they are replying to users of website2.com. (I need it this way to bridge the gap between them). At the same time I want to make the front end of the websites different so that they don't feel that they are replying to some other users outside the domain. These websites would be under my control and I will have access to the source code at any time. If I need to change the source code, these changes are welcome. Is this really possible? Thank you in advance.

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• PHP, MySQL: Security concern; Page loads in a weird way

  - by Devner

  Hi all, I am testing the security of my website. I am using the following URL to load a PHP page in my website, on localhost: http://localhost/domain/user/index.php/apple.php When I do this, the page is not loading normally; Instead the images, icons used in the page simply vanish/disappear from the page. Only text appears. And also on any link I click on this page, it brings me to this same page again without navigating to the required page. So if I have hyperlinks to other pages, such as "SEARCH", which points to search.php, instead of navigating to the search.php page, it refreshes the index.php page and just appends the page name of the destination page to the end of the URL. For example, say I used the link above. It then loads the index.php page minus the images at it's will. When I click on the "Search" link to navigate to the search page, I see the following in the URL: http://localhost/domain/user/index.php/search.php I have a redirection configured to a 404 error page in my .htaccess file, but the page does not redirect to the 404 error page. Notice the search.php towards the end of the URL above. Any other link that I click, reloads the index.php page and just appends the destination page name to the end of the URL like I have shown above. I was expecting to see a 404 Error but that does not happen. The URL should not even be able to load the page because I do NOT have a "index.php" folder in my website. What can I do to solve this? All help is appreciated. Thank you.

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