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• django: failing tests from django.contrib.auth

  - by gruszczy

  When I run my django test I get following errors, that are outside of my test suite: ====================================================================== ERROR: test_known_user (django.contrib.auth.tests.remote_user.RemoteUserCustomTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 160, in test_known_user super(RemoteUserCustomTest, self).test_known_user() File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 67, in test_known_user self.assertEqual(response.context['user'].username, 'knownuser') TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_last_login (django.contrib.auth.tests.remote_user.RemoteUserCustomTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 87, in test_last_login self.assertNotEqual(default_login, response.context['user'].last_login) TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_no_remote_user (django.contrib.auth.tests.remote_user.RemoteUserCustomTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 33, in test_no_remote_user self.assert_(isinstance(response.context['user'], AnonymousUser)) TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_unknown_user (django.contrib.auth.tests.remote_user.RemoteUserCustomTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 168, in test_unknown_user super(RemoteUserCustomTest, self).test_unknown_user() File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 51, in test_unknown_user self.assertEqual(response.context['user'].username, 'newuser') TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_known_user (django.contrib.auth.tests.remote_user.RemoteUserNoCreateTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 67, in test_known_user self.assertEqual(response.context['user'].username, 'knownuser') TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_last_login (django.contrib.auth.tests.remote_user.RemoteUserNoCreateTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 87, in test_last_login self.assertNotEqual(default_login, response.context['user'].last_login) TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_no_remote_user (django.contrib.auth.tests.remote_user.RemoteUserNoCreateTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 33, in test_no_remote_user self.assert_(isinstance(response.context['user'], AnonymousUser)) TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_unknown_user (django.contrib.auth.tests.remote_user.RemoteUserNoCreateTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 118, in test_unknown_user self.assert_(isinstance(response.context['user'], AnonymousUser)) TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_known_user (django.contrib.auth.tests.remote_user.RemoteUserTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 67, in test_known_user self.assertEqual(response.context['user'].username, 'knownuser') TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_last_login (django.contrib.auth.tests.remote_user.RemoteUserTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 87, in test_last_login self.assertNotEqual(default_login, response.context['user'].last_login) TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_no_remote_user (django.contrib.auth.tests.remote_user.RemoteUserTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 33, in test_no_remote_user self.assert_(isinstance(response.context['user'], AnonymousUser)) TypeError: 'NoneType' object is unsubscriptable ====================================================================== ERROR: test_unknown_user (django.contrib.auth.tests.remote_user.RemoteUserTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/remote_user.py", line 51, in test_unknown_user self.assertEqual(response.context['user'].username, 'newuser') TypeError: 'NoneType' object is unsubscriptable ====================================================================== FAIL: test_current_site_in_context_after_login (django.contrib.auth.tests.views.LoginTest) ---------------------------------------------------------------------- Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/contrib/auth/tests/views.py", line 190, in test_current_site_in_context_after_login self.assertEquals(response.status_code, 200) AssertionError: 302 != 200 Could anyone explain me, what am I doing wrong or what I should set to get those tests pass?

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• Change user email in Django without using django-profiles

  - by mridang

  Hi guys, In my Django application I would like the user to be able to change the email address. I've seen solution of StackOverflow pointing people to django-profiles. Unfortunately I don't want to use a full fledged profile module to accomplish a tiny feat of changing the users email. Has anyone seen this implemented anywhere. The email address verification procedure by sending a confirmation email is a requisite in this scenario. I've spent a great a deal of time trying to a find a solution that works but to no avail. Cheers.

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• Django CMS - not able to upload images through cmsplugin_filer_image

  - by Luke

  i have a problem with a local installation on django cms 2.3.3: i've installed it trough pip, in a separated virtualenv. next i followed the tutorial for settings.py configuration, i started the server. Then in the admin i created an page (home), and i've tried to add an image in the placeholder through the cmsplugin_filer_image, but the upload seems that doesn't work. here's my settings.py: # Django settings for cms1 project. # -*- coding: utf-8 -*- import os gettext = lambda s: s PROJECT_PATH = os.path.abspath(os.path.dirname(__file__)) DEBUG = True TEMPLATE_DEBUG = DEBUG ADMINS = ( # ('Your Name', '[email protected]'), ) MANAGERS = ADMINS DATABASES = { 'default': { 'ENGINE': 'django.db.backends.postgresql_psycopg2', # Add 'postgresql_psycopg2', 'mysql', 'sqlite3' or 'oracle'. 'NAME': 'cms1', # Or path to database file if using sqlite3. 'USER': 'cms', # Not used with sqlite3. 'PASSWORD': 'cms', # Not used with sqlite3. 'HOST': '', # Set to empty string for localhost. Not used with sqlite3. 'PORT': '', # Set to empty string for default. Not used with sqlite3. } } # Local time zone for this installation. Choices can be found here: # http://en.wikipedia.org/wiki/List_of_tz_zones_by_name # although not all choices may be available on all operating systems. # In a Windows environment this must be set to your system time zone. TIME_ZONE = 'Europe/Rome' # Language code for this installation. All choices can be found here: # http://www.i18nguy.com/unicode/language-identifiers.html LANGUAGE_CODE = 'it-it' SITE_ID = 1 # If you set this to False, Django will make some optimizations so as not # to load the internationalization machinery. USE_I18N = True # If you set this to False, Django will not format dates, numbers and # calendars according to the current locale. USE_L10N = True # If you set this to False, Django will not use timezone-aware datetimes. USE_TZ = True # Absolute filesystem path to the directory that will hold user-uploaded files. # Example: "/home/media/media.lawrence.com/media/" MEDIA_ROOT = os.path.join(PROJECT_PATH, "media") # URL that handles the media served from MEDIA_ROOT. Make sure to use a # trailing slash. # Examples: "http://media.lawrence.com/media/", "http://example.com/media/" MEDIA_URL = '/media/' # Absolute path to the directory static files should be collected to. # Don't put anything in this directory yourself; store your static files # in apps' "static/" subdirectories and in STATICFILES_DIRS. # Example: "/home/media/media.lawrence.com/static/" STATIC_ROOT = os.path.join(PROJECT_PATH, "static") STATIC_URL = "/static/" # Additional locations of static files STATICFILES_DIRS = ( os.path.join(PROJECT_PATH, "static_auto"), # Put strings here, like "/home/html/static" or "C:/www/django/static". # Always use forward slashes, even on Windows. # Don't forget to use absolute paths, not relative paths. ) # List of finder classes that know how to find static files in # various locations. STATICFILES_FINDERS = ( 'django.contrib.staticfiles.finders.FileSystemFinder', 'django.contrib.staticfiles.finders.AppDirectoriesFinder', # 'django.contrib.staticfiles.finders.DefaultStorageFinder', ) # Make this unique, and don't share it with anybody. SECRET_KEY = '^c2q3d8w)f#gk%5i)(#i*lwt%lm-!2=(*1d!1cf+rg&-hqi_9u' # List of callables that know how to import templates from various sources. TEMPLATE_LOADERS = ( 'django.template.loaders.filesystem.Loader', 'django.template.loaders.app_directories.Loader', # 'django.template.loaders.eggs.Loader', ) MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', 'cms.middleware.multilingual.MultilingualURLMiddleware', 'cms.middleware.page.CurrentPageMiddleware', 'cms.middleware.user.CurrentUserMiddleware', 'cms.middleware.toolbar.ToolbarMiddleware', # Uncomment the next line for simple clickjacking protection: # 'django.middleware.clickjacking.XFrameOptionsMiddleware', ) ROOT_URLCONF = 'cms1.urls' # Python dotted path to the WSGI application used by Django's runserver. WSGI_APPLICATION = 'cms1.wsgi.application' TEMPLATE_DIRS = ( os.path.join(PROJECT_PATH, "templates"), # Put strings here, like "/home/html/django_templates" or "C:/www/django/templates". # Always use forward slashes, even on Windows. # Don't forget to use absolute paths, not relative paths. ) CMS_TEMPLATES = ( ('template_1.html', 'Template One'), ('template_2.html', 'Template Two'), ) TEMPLATE_CONTEXT_PROCESSORS = ( 'django.contrib.auth.context_processors.auth', 'django.core.context_processors.i18n', 'django.core.context_processors.request', 'django.core.context_processors.media', 'django.core.context_processors.static', 'cms.context_processors.media', 'sekizai.context_processors.sekizai', ) LANGUAGES = [ ('it', 'Italiano'), ('en', 'English'), ] INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.staticfiles', 'cms', #django CMS itself 'mptt', #utilities for implementing a modified pre-order traversal tree 'menus', #helper for model independent hierarchical website navigation 'south', #intelligent schema and data migrations 'sekizai', #for javascript and css management #'cms.plugins.file', 'cms.plugins.flash', 'cms.plugins.googlemap', 'cms.plugins.link', #'cms.plugins.picture', 'cms.plugins.snippet', 'cms.plugins.teaser', 'cms.plugins.text', #'cms.plugins.video', 'cms.plugins.twitter', 'filer', 'cmsplugin_filer_file', 'cmsplugin_filer_folder', 'cmsplugin_filer_image', 'cmsplugin_filer_teaser', 'cmsplugin_filer_video', 'easy_thumbnails', 'PIL', # Uncomment the next line to enable the admin: 'django.contrib.admin', # Uncomment the next line to enable admin documentation: # 'django.contrib.admindocs', ) # A sample logging configuration. The only tangible logging # performed by this configuration is to send an email to # the site admins on every HTTP 500 error when DEBUG=False. # See http://docs.djangoproject.com/en/dev/topics/logging for # more details on how to customize your logging configuration. LOGGING = { 'version': 1, 'disable_existing_loggers': False, 'filters': { 'require_debug_false': { '()': 'django.utils.log.RequireDebugFalse' } }, 'handlers': { 'mail_admins': { 'level': 'ERROR', 'filters': ['require_debug_false'], 'class': 'django.utils.log.AdminEmailHandler' } }, 'loggers': { 'django.request': { 'handlers': ['mail_admins'], 'level': 'ERROR', 'propagate': True, }, } } when i try to upload an image, in the clipboard section i don't have the thumbnail, but just an 'undefined' message: and this is the runserver console while trying to upload: [20/Oct/2012 15:15:56] "POST /admin/filer/clipboard/operations/upload/?qqfile=29708_1306856312320_7706073_n.jpg HTTP/1.1" 500 248133 [20/Oct/2012 15:15:56] "GET /it/admin/filer/folder/unfiled_images/undefined HTTP/1.1" 301 0 [20/Oct/2012 15:15:56] "GET /it/admin/filer/folder/unfiled_images/undefined/ HTTP/1.1" 404 1739 Also, this is project filesystem: cms1 +-- cms1 ¦   +-- __init__.py ¦   +-- __init__.pyc ¦   +-- media ¦   ¦   +-- filer_public ¦   ¦   +-- 2012 ¦   ¦   +-- 10 ¦   ¦   +-- 20 ¦   ¦   +-- 29708_1306856312320_7706073_n_1.jpg ¦   ¦   +-- 29708_1306856312320_7706073_n_2.jpg ¦   ¦   +-- 29708_1306856312320_7706073_n_3.jpg ¦   ¦   +-- 29708_1306856312320_7706073_n_4.jpg ¦   ¦   +-- 29708_1306856312320_7706073_n_5.jpg ¦   ¦   +-- 29708_1306856312320_7706073_n_6.jpg ¦   ¦   +-- 29708_1306856312320_7706073_n_7.jpg ¦   ¦   +-- 29708_1306856312320_7706073_n.jpg ¦   ¦   +-- torrent-client-macosx.jpg ¦   +-- settings.py ¦   +-- settings.pyc ¦   +-- static ¦   +-- static_auto ¦   +-- static_manual ¦   +-- templates ¦   ¦   +-- base.html ¦   ¦   +-- template_1.html ¦   ¦   +-- template_2.html ¦   +-- urls.py ¦   +-- urls.pyc ¦   +-- wsgi.py ¦   +-- wsgi.pyc +-- manage.py So files are uploaded, but they are not accessible to cms. there's a similar question here, but doens't help me so much. It would be very helpful any help on this issue to me. Thanks, luke

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• Where is meta.local_fields set in django.db.models.base.py ?

  - by BryanWheelock

  I'm getting the error: Exception Value: (1110, "Column 'about' specified twice") As I was reviewing the Django error page, I noticed that the customizations the model User, seem to be appended to the List twice. This seems to be happening here in django/db/model/base.py in base_save(): values = [(f, f.get_db_prep_save(raw and getattr(self, f.attname) or f.pre_save(self, True))) for f in meta.local_fields] this is what Django error page shows values to be: values = [(<django.db.models.fields.CharField object at 0xa78996c>, u'kallie'), (<django.db.models.fields.CharField object at 0xa7899cc>, ''), (<django.db.models.fields.CharField object at 0xa789a2c>, ''), (<django.db.models.fields.EmailField object at 0xa789a8c>, u'[email protected]'), (<django.db.models.fields.CharField object at 0xa789b2c>, 'sha1$d4a80$0e5xxxxxxxxxxxxxxxxxxxxddadfb07'), (<django.db.models.fields.BooleanField object at 0xa789bcc>, False), (<django.db.models.fields.BooleanField object at 0xa789c6c>, True), (<django.db.models.fields.BooleanField object at 0xa789d2c>, False), (<django.db.models.fields.DateTimeField object at 0xa789dcc>, u'2010-02-03 14:54:35'), (<django.db.models.fields.DateTimeField object at 0xa789e2c>, u'2010-02-03 14:54:35'), # this is where the values from the User model customizations show up (<django.db.models.fields.BooleanField object at 0xa8c69ac>, False), (<django.db.models.fields.CharField object at 0xa8c688c>, None), (<django.db.models.fields.PositiveIntegerField object at 0xa8c69cc>, 1), (<django.db.models.fields.CharField object at 0xa8c69ec>, 'b5ab1603b2308xxxxxxxxxxx75bca1'), (<django.db.models.fields.SmallIntegerField object at 0xa8c6dac>, 0), (<django.db.models.fields.SmallIntegerField object at 0xa8c6e4c>, 0), (<django.db.models.fields.SmallIntegerField object at 0xa8c6e8c>, 0), (<django.db.models.fields.SmallIntegerField object at 0xa8c6ecc>, 10), (<django.db.models.fields.DateTimeField object at 0xa8c6eec>, u'2010-02-03 14:54:35'), (<django.db.models.fields.CharField object at 0xa8c6f2c>, ''), (<django.db.models.fields.URLField object at 0xa8c6f6c>, ''), (<django.db.models.fields.CharField object at 0xa8c6fac>, ''), (<django.db.models.fields.DateField object at 0xa8c6fec>, None), (<django.db.models.fields.TextField object at 0xa8cb04c>, ''), # at this point User model customizations repeats itself (<django.db.models.fields.BooleanField object at 0xa663b0c>, False), (<django.db.models.fields.CharField object at 0xaa1e94c>, None), (<django.db.models.fields.PositiveIntegerField object at 0xaa1e34c>, 1), (<django.db.models.fields.CharField object at 0xaa1e40c>, 'b5ab1603b2308050ebd62f49ca75bca1'), (<django.db.models.fields.SmallIntegerField object at 0xa8c6d8c>, 0), (<django.db.models.fields.SmallIntegerField object at 0xaa2378c>, 0), (<django.db.models.fields.SmallIntegerField object at 0xaa237ac>, 0), (<django.db.models.fields.SmallIntegerField object at 0xaa237ec>, 10), (<django.db.models.fields.DateTimeField object at 0xaa2380c>, u'2010-02-03 14:54:35'), (<django.db.models.fields.CharField object at 0xaa2384c>, ''), (<django.db.models.fields.URLField object at 0xaa2388c>, ''), (<django.db.models.fields.CharField object at 0xaa238cc>, ''), (<django.db.models.fields.DateField object at 0xaa2390c>, None), (<django.db.models.fields.TextField object at 0xaa2394c>, '')] Since this app is in Production, I can't figure out how to use pdb.set_trace() to see what's going on inside of save_base. The customizations to User are: User.add_to_class('email_isvalid', models.BooleanField(default=False)) User.add_to_class('email_key', models.CharField(max_length=16, null=True)) User.add_to_class('reputation', models.PositiveIntegerField(default=1)) User.add_to_class('gravatar', models.CharField(max_length=32)) User.add_to_class('email_feeds', generic.GenericRelation(EmailFeed)) User.add_to_class('favorite_questions', models.ManyToManyField(Question, through=FavoriteQuestion, related_name='favorited_by')) User.add_to_class('badges', models.ManyToManyField(Badge, through=Award, related_name='awarded_to')) User.add_to_class('gold', models.SmallIntegerField(default=0)) User.add_to_class('silver', models.SmallIntegerField(default=0)) User.add_to_class('bronze', models.SmallIntegerField(default=0)) User.add_to_class('questions_per_page', models.SmallIntegerField(choices=QUESTIONS_PER_PAGE_CHOICES, default=10)) User.add_to_class('last_seen', models.DateTimeField(default=datetime.datetime.now)) User.add_to_class('real_name', models.CharField(max_length=100, blank=True)) User.add_to_class('website', models.URLField(max_length=200, blank=True)) User.add_to_class('location', models.CharField(max_length=100, blank=True)) User.add_to_class('date_of_birth', models.DateField(null=True, blank=True)) User.add_to_class('about', models.TextField(blank=True)) Django1.1.1 Python 2.5

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• Django one form for two models

  - by martinthenext

  Hello! I have a ForeignKey relationship between TextPage and Paragraph and my goal is to make front-end TextPage creating/editing form as if it was in ModelAdmin with 'inlines': several field for the TextPage and then a couple of Paragraph instances stacked inline. The problem is that i have no idea about how to validate and save that: @login_required def textpage_add(request): profile = request.user.profile_set.all()[0] if not (profile.is_admin() or profile.is_editor()): raise Http404 PageFormSet = inlineformset_factory(TextPage, Paragraph, extra=5) if request.POST: try: textpageform = TextPageForm(request.POST) # formset = PageFormSet(request.POST) except forms.ValidationError as error: textpageform = TextPageForm() formset = PageFormSet() return render_to_response('textpages/manage.html', { 'formset' : formset, 'textpageform' : textpageform, 'error' : str(error), }, context_instance=RequestContext(request)) # Saving data if textpageform.is_valid() and formset.is_valid(): textpageform.save() formset.save() return HttpResponseRedirect(reverse(consults)) else: textpageform = TextPageForm() formset = PageFormSet() return render_to_response('textpages/manage.html', { 'formset' : formset, 'textpageform' : textpageform, }, context_instance=RequestContext(request)) I know I't a kind of code-monkey style to post code that you don't even expect to work but I wanted to show what I'm trying to accomplish. Here is the relevant part of models.py: class TextPage(models.Model): title = models.CharField(max_length=100) page_sub_category = models.ForeignKey(PageSubCategory, blank=True, null=True) def __unicode__(self): return self.title class Paragraph(models.Model): article = models.ForeignKey(TextPage) title = models.CharField(max_length=100, blank=True, null=True) text = models.TextField(blank=True, null=True) def __unicode__(self): return self.title Any help would be appreciated. Thanks!

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• Overriding the save() method of a model that uses django-mptt

  - by saturdayplace

  I've been using django-mptt in my project for a while now, it's fabulous. Recently, I've found a need to override a model's save() method that uses mptt, and I'm getting an error when I try to save a new instance of that model: Exception Type: ValueError at /admin/scrivener/page/add/ Exception Value: Cannot use None as a query value I'm assuming that this is a result of the fact that the instance hasn't been stuck into a tree yet, but I'm not sure how to go about fixing this. I added a comment about it onto a similar issue on the project's tracker, but I was hoping that someone here might be able to put me on the right track faster. Here's the traceback. Environment: Request Method: POST Request URL: http://localhost:8000/admin/scrivener/page/add/ Django Version: 1.2 rc 1 SVN-13117 Python Version: 2.6.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'django.contrib.sitemaps', 'mptt', 'filebrowser', 'south', 'haystack', 'django_static', 'etc', 'scrivener', 'gregor', 'annunciator'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware') Traceback: File "B:\django-apps\3rd Party Source\django\core\handlers\base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "B:\django-apps\3rd Party Source\django\contrib\admin\options.py" in wrapper 239. return self.admin_site.admin_view(view)(*args, **kwargs) File "B:\django-apps\3rd Party Source\django\utils\decorators.py" in _wrapped_view 74. response = view_func(request, *args, **kwargs) File "B:\django-apps\3rd Party Source\django\views\decorators\cache.py" in _wrapped_view_func 69. response = view_func(request, *args, **kwargs) File "B:\django-apps\3rd Party Source\django\contrib\admin\sites.py" in inner 190. return view(request, *args, **kwargs) File "B:\django-apps\3rd Party Source\django\utils\decorators.py" in _wrapper 21. return decorator(bound_func)(*args, **kwargs) File "B:\django-apps\3rd Party Source\django\utils\decorators.py" in _wrapped_view 74. response = view_func(request, *args, **kwargs) File "B:\django-apps\3rd Party Source\django\utils\decorators.py" in bound_func 17. return func(self, *args2, **kwargs2) File "B:\django-apps\3rd Party Source\django\db\transaction.py" in _commit_on_success 299. res = func(*args, **kw) File "B:\django-apps\3rd Party Source\django\contrib\admin\options.py" in add_view 795. self.save_model(request, new_object, form, change=False) File "B:\django-apps\3rd Party Source\django\contrib\admin\options.py" in save_model 597. obj.save() File "B:\django-apps\scrivener\models.py" in save 205. self.url = self.get_absolute_url() File "B:\django-apps\3rd Party Source\django\utils\functional.py" in _curried 55. return _curried_func(*(args+moreargs), **dict(kwargs, **morekwargs)) File "B:\django-apps\3rd Party Source\django\db\models\base.py" in get_absolute_url 940. return settings.ABSOLUTE_URL_OVERRIDES.get('%s.%s' % (opts.app_label, opts.module_name), func)(self, *args, **kwargs) File "B:\django-apps\3rd Party Source\django\db\models\__init__.py" in inner 31. bits = func(*args, **kwargs) File "B:\django-apps\scrivener\models.py" in get_absolute_url 194. for ancestor in self.get_ancestors(): File "B:\django-apps\3rd Party Source\mptt\models.py" in get_ancestors 23. opts.tree_id_attr: getattr(self, opts.tree_id_attr), File "B:\django-apps\3rd Party Source\django\db\models\manager.py" in filter 141. return self.get_query_set().filter(*args, **kwargs) File "B:\django-apps\3rd Party Source\django\db\models\query.py" in filter 550. return self._filter_or_exclude(False, *args, **kwargs) File "B:\django-apps\3rd Party Source\django\db\models\query.py" in _filter_or_exclude 568. clone.query.add_q(Q(*args, **kwargs)) File "B:\django-apps\3rd Party Source\django\db\models\sql\query.py" in add_q 1131. can_reuse=used_aliases) File "B:\django-apps\3rd Party Source\django\db\models\sql\query.py" in add_filter 1000. raise ValueError("Cannot use None as a query value") Exception Type: ValueError at /admin/scrivener/page/add/ Exception Value: Cannot use None as a query value

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• Show models.ManyToManyField as inline, with the same form as models.ForeignKey inline

  - by Kristian

  I have a model similar to the following (simplified): models.py class Sample(models.Model): name=models.CharField(max_length=200) class Action(models.Model): samples=models.ManyToManyField(Sample) title=models.CharField(max_length=200) description=models.TextField() Now, if Action.samples would have been a ForeignKey instead of a ManyToManyField, when I display Action as a TabularInline in Sample in the Django Admin, I would get a number of rows, each containing a nice form to edit or add another Action. However; when I display the above as an inline using the following: class ActionInline(admin.TabularInline): model=Action.samples.through I get a select box listing all available actions, and not a nifty form to create a new Action. My question is really: How do I display the ManyToMany relation as an inline with a form to input information as described? In principle it should be possible since, from the Sample's point of view, the situation is identical in both cases; Each Sample has a list of Actions regardless if the relation is a ForeignKey or a ManyToManyRelation. Also; Through the Sample admin page, I never want to choose from existing Actions, only create new or edit old ones.

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• Django admin site populated combo box based on imput

  - by user292652

  hi i have to following model class Match(models.Model): Team_one = models.ForeignKey('Team', related_name='Team_one') Team_two = models.ForeignKey('Team', related_name='Team_two') Stadium = models.CharField(max_length=255, blank=True) Start_time = models.DateTimeField(auto_now_add=False, auto_now=False, blank=True, null=True) Rafree = models.CharField(max_length=255, blank=True) Judge = models.CharField(max_length=255, blank=True) Winner = models.ForeignKey('Team', related_name='winner', blank=True) updated = models.DateTimeField('update date', auto_now=True ) created = models.DateTimeField('creation date', auto_now_add=True ) def save(self, force_insert=False, force_update=False): pass @models.permalink def get_absolute_url(self): return ('view_or_url_name') class MatchAdmin(admin.ModelAdmin): list_display = ('Team_one','Team_two', 'Winner') search_fields = ['Team_one','Team_tow'] admin.site.register(Match, MatchAdmin) i was wondering is their a way to populated the winner combo box once the team one and team two is selected in admin site ?

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• Django admin site auto populate combo box based on input

  - by user292652

  hi i have to following model class Match(models.Model): Team_one = models.ForeignKey('Team', related_name='Team_one') Team_two = models.ForeignKey('Team', related_name='Team_two') Stadium = models.CharField(max_length=255, blank=True) Start_time = models.DateTimeField(auto_now_add=False, auto_now=False, blank=True, null=True) Rafree = models.CharField(max_length=255, blank=True) Judge = models.CharField(max_length=255, blank=True) Winner = models.ForeignKey('Team', related_name='winner', blank=True) updated = models.DateTimeField('update date', auto_now=True ) created = models.DateTimeField('creation date', auto_now_add=True ) def save(self, force_insert=False, force_update=False): pass @models.permalink def get_absolute_url(self): return ('view_or_url_name') class MatchAdmin(admin.ModelAdmin): list_display = ('Team_one','Team_two', 'Winner') search_fields = ['Team_one','Team_tow'] admin.site.register(Match, MatchAdmin) i was wondering is their a way to populated the winner combo box once the team one and team two is selected in admin site ?

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• Form for Profile models ?

  - by xRobot

  Is there a way to create a form from profile models ? For example... If I have this model as profile: class blogger(models.Model): user = models.ForeignKey(User, unique=True) born = models.DateTimeField('born') gender = models.CharField(max_length=1, choices=gender ) about = models.TextField(_('about'), null=True, blank=True) . I want this form: Name: Surname: Born: Gender: About: Is this possible ? If yes how ?

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• Django foreign key question

  - by Hulk

  All, i have the following model defined, class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() AND IN MY VIEWS I HAVE p= header(title=name,created_by=id) p.save() Now the data will be saved to header table .My question is that for this id generated in header table how will save the data to criteria and options table..Please let me know.. Thanks..

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• Django ForeignKey TemplateSyntaxError and ProgrammingError

  - by Daniel Garcia

  This is are my models i want to relate. i want for collection to appear in the form of occurrence. class Collection(models.Model): id = models.AutoField(primary_key=True, null=True) code = models.CharField(max_length=100, null=True, blank=True) address = models.CharField(max_length=100, null=True, blank=True) collection_name = models.CharField(max_length=100) def __unicode__(self): return self.collection_name class Meta: db_table = u'collection' ordering = ('collection_name',) class Occurrence(models.Model): id = models.AutoField(primary_key=True, null=True) reference = models.IntegerField(null=True, blank=True, editable=False) collection = models.ForeignKey(Collection, null=True, blank=True, unique=True), modified = models.DateTimeField(null=True, blank=True, auto_now=True) class Meta: db_table = u'occurrence' Every time i go to check the Occurrence object i get this error TemplateSyntaxError at /admin/hotiapp/occurrence/ Caught an exception while rendering: column occurrence.collection_id does not exist LINE 1: ...LECT "occurrence"."id", "occurrence"."reference", "occurrenc.. And every time i try to add a new occurrence object i get this error ProgrammingError at /admin/hotiapp/occurrence/add/ column occurrence.collection_id does not exist LINE 1: SELECT (1) AS "a" FROM "occurrence" WHERE "occurrence"."coll... What am i doing wrong? or how does ForeignKey works?

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• Django 1.2 + South 0.7 + django-annoying's AutoOneToOneField leads to TypeError: 'LegacyConnection'

  - by konrad

  I'm using Django 1.2 trunk with South 0.7 and an AutoOneToOneField copied from django-annoying. South complained that the field does not have rules defined and the new version of South no longer has an automatic field type parser. So I read the South documentation and wrote the following definition (basically an exact copy of the OneToOneField rules): rules = [ ( (AutoOneToOneField), [], { "to": ["rel.to", {}], "to_field": ["rel.field_name", {"default_attr": "rel.to._meta.pk.name"}], "related_name": ["rel.related_name", {"default": None}], "db_index": ["db_index", {"default": True}], }, ) ] from south.modelsinspector import add_introspection_rules add_introspection_rules(rules, ["^myapp"]) Now South raises the following error when I do a schemamigration. Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "django/core/management/base.py", line 223, in execute output = self.handle(*args, **options) File "South-0.7-py2.6.egg/south/management/commands/schemamigration.py", line 92, in handle (k, v) for k, v in freezer.freeze_apps([migrations.app_label()]).items() File "South-0.7-py2.6.egg/south/creator/freezer.py", line 33, in freeze_apps model_defs[model_key(model)] = prep_for_freeze(model) File "South-0.7-py2.6.egg/south/creator/freezer.py", line 65, in prep_for_freeze fields = modelsinspector.get_model_fields(model, m2m=True) File "South-0.7-py2.6.egg/south/modelsinspector.py", line 322, in get_model_fields args, kwargs = introspector(field) File "South-0.7-py2.6.egg/south/modelsinspector.py", line 271, in introspector arg_defs, kwarg_defs = matching_details(field) File "South-0.7-py2.6.egg/south/modelsinspector.py", line 187, in matching_details if any([isinstance(field, x) for x in classes]): TypeError: 'LegacyConnection' object is not iterable Is this related to a recent change in Django 1.2 trunk? How do I fix this? I use this field as follows: class Bar(models.Model): foo = AutoOneToOneField("foo.Foo", primary_key=True, related_name="bar") For reference the field code from django-tagging: class AutoSingleRelatedObjectDescriptor(SingleRelatedObjectDescriptor): def __get__(self, instance, instance_type=None): try: return super(AutoSingleRelatedObjectDescriptor, self).__get__(instance, instance_type) except self.related.model.DoesNotExist: obj = self.related.model(**{self.related.field.name: instance}) obj.save() return obj class AutoOneToOneField(OneToOneField): def contribute_to_related_class(self, cls, related): setattr(cls, related.get_accessor_name(), AutoSingleRelatedObjectDescriptor(related))

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• Django models avoid duplicates

  - by Hulk

  In models, class Getdata(models.Model): title = models.CharField(max_length=255) state = models.CharField(max_length=2, choices=STATE, default="0") name = models.ForeignKey(School) created_by = models.ForeignKey(profile) def __unicode__(self): return self.id() In templates <form> <input type="submit" save the data/> </form> If the user clicks on the save button and the above data is saved in the table how to avoid the duplicates,i.e, if the user again clicks on the same submit button there should not be another entry for the same values.Or is it some this that has to be handeled in views Thanks..

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• Django models avaoid duplicates

  - by Hulk

  In models, class Getdata(models.Model): title = models.CharField(max_length=255) state = models.CharField(max_length=2, choices=STATE, default="0") name = models.ForeignKey(School) created_by = models.ForeignKey(profile) def __unicode__(self): return self.id() In templates <form> <input type="submit" save the data/> </form> If the user clicks on the save button and the above data is saved in the table how to avoid the duplicates,i.e, if the user again clicks on the same submit button there should not be another entry for the same values.Or is it some this that has to be handeled in views Thanks..

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• Proper way to add record to many to many relationship in Django

  - by blcArmadillo

  First off, I'm planning on running my project on google app engine so I'm using djangoappengine which as far as I know doesn't support django's ManyToManyField type. Because of this I've setup my models like this: from django.db import models from django.contrib.auth.models import User class Group(models.Model): name = models.CharField(max_length=200) class UserGroup(models.Model): user = models.ForeignKey(User) group = models.ForeignKey(Group) On a page I have a form field where people can enter a group name. I want the results from this form field to create a UserGroup object for the user - group combination and if the group doesn't yet exist create a new Group object. At first I started putting this logic in the UserGroup class with a add_group method but quickly realized that it doesn't really make sense to put this in the UserGroup class. What would the proper way of doing this be? I saw some stuff about model managers. Is this what those are for?

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• How to convert this query to a "django model query" ?

  - by fabriciols

  Hello ! What i want is simple : models : class userLastTrophy(models.Model): user = models.ForeignKey(userInfo) platinum = models.IntegerField() gold = models.IntegerField() silver = models.IntegerField() bronze = models.IntegerField() level = models.IntegerField() rank = models.IntegerField() perc_level = models.IntegerField() date_update = models.DateTimeField(default=datetime.now, blank=True) total = models.IntegerField() points = models.IntegerField() class userTrophy(models.Model): user = models.ForeignKey(userInfo) platinum = models.IntegerField() gold = models.IntegerField() silver = models.IntegerField() bronze = models.IntegerField() total = models.IntegerField() level = models.IntegerField() perc_level = models.IntegerField() date_update = models.DateTimeField(default=datetime.now, blank=True) rank = models.IntegerField(default=0) total = models.IntegerField(default=0) points = models.IntegerField(default=0) last_trophy = models.ForeignKey(userLastTrophy, default=0) I have this query : select t2.user_id as id, t2.platinum - t1.platinum as plat, t2.gold - t1.gold as gold, t2.silver - t1.silver as silver, t2.bronze - t1.bronze as bronze, t2.points - t1.points as points from myps3t_usertrophy t2, myps3t_userlasttrophy t1 where t1.id = t2.last_trophy_id order by points; how to do this with django models ?

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• Default value for field in Django model

  - by Daniel Garcia

  Suppose I have a model: class SomeModel(models.Model): id = models.AutoField(primary_key=True) a = models.IntegerField(max_length=10) b = models.CharField(max_length=7) Currently I am using the default admin to create/edit objects of this type. How do I set the field 'a' to have the same number as id? (default=???) Other question Suppose I have a model: event_date = models.DateTimeField( null=True) year = models.IntegerField( null=True) month = models.CharField(max_length=50, null=True) day = models.IntegerField( null=True) How can i set the year, month and day fields by default to be the same as event_date field?

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• Django - How best to handle ValidationErrors after form.save(commit=False)

  - by orokusaki

  This is a fragment of my code from a view: if form.is_valid(): instance = form.save(commit=False) try: instance.account = request.account instance.full_clean() except ValidationError, e: # Do something with the errors here... I don't know what the best thing to do here is, but I certainly don't want to do it 180 times. This is an utter mess. Who would want to handle validation errors manually in every view. If you're not modifying the instance after save(commit=False), you don't have to worry about this, but what about in my case where every model has a foreign key to account which is set behind the scenes and hidden from the user? Any help is really appreciated.

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• Return template as string - Django

  - by Ninefingers

  Hi All, I'm still not sure this is the correct way to go about this, maybe not, but I'll ask anyway. I'd like to re-write wordpress (justification: because I can) albeit more simply myself in Django and I'm looking to be able to configure elements in different ways on the page. So for example I might have: Blog models A site update message model A latest comments model. Now, for each page on the site I want the user to be able to choose the order of and any items that go on it. In my thought process, this would work something like: class Page(models.Model) Slug = models.CharField(max_length=100) class PageItem(models.Model) Page = models.ForeignKey(Page) ItemType = models.CharField(max_length=100) InstanceNum = models.IntegerField() # all models have primary keys. Then, ideally, my template would loop through all the PageItems in a page which is easy enough to do. But what if my page item is a site update as opposed to a blog post? Basically, I am thinking I'd like to pull different item types back in different orders and display them using the appropriate templates. Now, I thought one way to do this would be to, in views.py, to loop through all of the objects and call the appropriate view function, return a bit of html as a string and then pipe that into the resultant template. My question is - is this the best way to go about doing things? If so, how do I do it? If not, which way should I be going? I'm pretty new to Django so I'm still learning what it can and can't do, so please bear with me. I've checked SO for dupes and don't think this has been asked before...

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• sort django queryset by latest instance of a subset of related model

  - by rsp

  I have an Order model and order_event model. Each order_event has a foreignkey to order. so from an order instance i can get: myorder.order_event_set. I want to get a list of all orders but i want them to be sorted by the date of the last event. A statement like this works to sort by the latest event date: queryset = Order.objects.all().annotate(latest_event_date=Max('order_event__event_datetime')).order_by('latest_event_date') However, what I really need is a list of all orders sorted by latest date of A SUBSET OF EVENTS. For example my events are categorized into "scheduling", "processing", etc. So I should be able to get a list of all orders sorted by the latest scheduling event. This django doc (https://docs.djangoproject.com/en/dev/topics/db/aggregation/#filter-and-exclude) shows how I can get the latest schedule event using a filter but this excludes orders without a scheduling event. I thought I could combine the filtered queryset with a queryset that includes back those orders that are missing a scheduling event...but I'm not quite sure how to do this. I saw answers related to using python list but it would be much more useful to have a proper django queryset (ie for a view with pagination, etc.)

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• Django tests failing on invalid keyword argument

  - by Darwin Tech

  I have a models.py like so: from django.db import models from django.contrib.auth.models import User from datetime import datetime class UserProfile(models.Model): user = models.OneToOneField(User) def __unicode__(self): return self.user.username class Project(models.Model): user = models.ForeignKey(UserProfile) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) product = models.ForeignKey('tool.product') module = models.ForeignKey('tool.module') model = models.ForeignKey('tool.model') zipcode = models.IntegerField(max_length=5) def __unicode__(self): return unicode(self.id) And my tests.py: from django.test import TestCase, Client # --- import app models from django.contrib.auth.models import User from tool.models import Module, Model, Product from user_profile.models import Project, UserProfile # --- unit tests --- # class UserProjectTests(TestCase): fixtures = ['admin_user.json'] def setUp(self): self.product1 = Product.objects.create( name='bar', ) self.module1 = Module.objects.create( name='foo', enable=True ) self.model1 = Model.objects.create( module=self.module1, name='baz', enable=True ) self.user1 = User.objects.get(pk=1) ... def test_can_create_project(self): self.project1 = Model.objects.create( user=self.user1, product=self.product1, module=self.module1, model=self.model1, zipcode=90210 ) self.assertEquals(self.project1.zipcode, 90210) But I get a TypeError: 'product' is an invalid keyword argument for this function error. I'm not sure what is failing but I'm guessing something to do with the FK relationships... Any help would be much appreciated.

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• Django models: Use multiple values as a key?

  - by Rosarch

  Here is a simple model: class TakingCourse(models.Model): course = models.ForeignKey(Course) term = models.ForeignKey(Term) Instead of Django creating a default primary key, I would like to use both course and term as the primary key - taken together, they uniquely identify a tuple. Is this allowed by Django? On a related note: I am trying to represent users taking courses in certain terms. Is there a better way to do this? class Course(models.Model): name = models.CharField(max_length=200) requiredFor = models.ManyToManyField(RequirementSubSet, blank=True) offeringSchool = models.ForeignKey(School) def __unicode__(self): return "%s at %s" % (self.name, self.offeringSchool) class MyUser(models.Model): user = models.ForeignKey(User, unique=True) takingReqSets = models.ManyToManyField(RequirementSet, blank=True) takingTerms = models.ManyToManyField(Term, blank=True) takingCourses = models.ManyToManyField(TakingCourse, blank=True) school = models.ForeignKey(School) class TakingCourse(models.Model): course = models.ForeignKey(Course) term = models.ForeignKey(Term) class Term(models.Model): school = models.ForeignKey(School) isPrimaryTerm = models.BooleanField()

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• Django many to many queries

  - by Hulk

  In the following, How to get designation when querying Emp sc=Emp.objects.filter(pk=profile.emp.id)[0] sc.desg //this gives an error class Emp(models.Model): name = models.CharField(max_length=255, unique=True) address1 = models.CharField(max_length=255) city = models.CharField(max_length=48) state = models.CharField(max_length=48) country = models.CharField(max_length=48) desg = models.ManyToManyField(Designation) class Designation(models.Model): description = models.TextField() title = models.TextField() def __unicode__(self): return self.board

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• Django-admin.py not working (-bash:django-admin.py: command not found)

  - by Diego

  I'm having trouble getting django-admin.py to work... it's in this first location: /Users/mycomp/bin/ but I think I need it in another location for the terminal to recognize it, no? Noob, Please help. Thanks!! my-computer:~/Django-1.1.1 mycomp$ sudo ln -s /Users/mycomp/bin/django-admin.py /Users/mycomp/django-1.1.1/django-admin.py Password: ln: /Users/mycomp/django-1.1.1/django-admin.py: File exists my-computer:~/Django-1.1.1 mycomp$ django-admin.py --version -bash: django-admin.py: command not found

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