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  • Can't access a map member from a pointer

    - by fjfnaranjo
    Hi. That's my first question :) I'm storing the configuration of my program in a Group->Key->Value form, like the old INIs. I'm storing the information in a pair of structures. First one, I'm using a std::map with string+ptr for the groups info (the group name in the string key). The second std::map value is a pointer to the sencond structure, a std::list of std::maps, with the finish Key->Value pairs. The Key-Value pairs structure is created dynamically, so the config structure is: std::map< std::string , std::list< std::map<std::string,std::string> >* > lv1; Well, I'm trying to implement two methods to check the existence of data in the internal config. The first one, check the existence of a group in the structure: bool isConfigLv1(std::string); bool ConfigManager::isConfigLv1(std::string s) { return !(lv1.find(s)==lv1.end()); } The second method, is making me crazy... It check the existence for a key inside a group. bool isConfigLv2(std::string,std::string); bool ConfigManager::isConfigLv2(std::string s,std::string d) { if(!isConfigLv1(s)) return false; std::map< std::string , std::list< std::map<std::string,std::string> >* >::iterator it; std::list< std::map<std::string,std::string> >* keyValue; std::list< std::map<std::string,std::string> >::iterator keyValueIt; it = lv1.find(s); keyValue = (*it).second; for ( keyValueIt = keyValue->begin() ; keyValueIt != keyValue->end() ; keyValueIt++ ) if(!((*keyValueIt).second.find(d)==(*keyValueIt).second.end())) return true; return false; } I don't understand what is wrong. The compiler says: ConfigManager.cpp||In member function ‘bool ConfigManager::isConfigLv2(std::string, std::string)’:| ConfigManager.cpp|(line over return true)|error: ‘class std::map<std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::less<std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, std::allocator<std::pair<const std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> > > > >’ has no member named ‘second’| But it has to have the second member, because it's a map iterator... Any suggestion about what's happening? Sorry for my English :P, and consider I'm doing it as a exercise, I know there are a lot of cool configuration managers.

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  • Why is this Python class copying another class contents?

    - by fjfnaranjo
    Hello guys. I'm trying to understand an estrange behavior in Python. I have the next python code: class IntContainer: listOfInts = [] def __init__(self, initListOfInts): for i in initListOfInts: self.listOfInts.append(i) def printInts(self): print self.listOfInts if __name__ == "__main__": intsGroup1 = [1,2,3,4] intsGroup2 = [4,5,6,7] intsGroups = [intsGroup1,intsGroup2] intsContainers = [] for ig in intsGroups: newIntContainer = IntContainer(ig) intsContainers.append(newIntContainer) for ic in intsContainers: print ic.listOfInts I expect to get something like: [1, 2, 3, 4] [4, 5, 6, 7] But i get: [1, 2, 3, 4, 4, 5, 6, 7] [1, 2, 3, 4, 4, 5, 6, 7] I have check the next question: http://stackoverflow.com/questions/1876905/why-is-python-reusing-a-class-instance-inside-in-function And a lot of Python reference, but I can not understand what is happening. I think is related with the newIntContainer identifier reutilization, but I do not understand it deeply. Why Python appears to reused the last reference for the new object, even if I have added it to a permanent list? What can I do to resolve this behavior? Thanks ;)

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