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  • PyQt signal between QObjects

    - by geho
    I'm trying to make a view and controller in PyQt where the view is emitting a custom signal when a button is clicked, and the controller has one of its methods connected to the emitted signal. It does not work, however. The respond method is not called when I click the button. Any idea what I did wrong ? import sys from PyQt4.QtCore import * from PyQt4.QtGui import QPushButton, QVBoxLayout, QDialog, QApplication class TestView(QDialog): def __init__(self, parent=None): super(TestView, self).__init__(parent) self.button = QPushButton('Click') layout = QVBoxLayout() layout.addWidget(self.button) self.setLayout(layout) self.connect(self.button, SIGNAL('clicked()'), self.buttonClicked) def buttonClicked(self): self.emit(SIGNAL('request')) class TestController(QObject): def __init__(self, view): self.view = view self.connect(self.view, SIGNAL('request'), self.respond) def respond(self): print 'respond' app = QApplication(sys.argv) dialog = TestView() controller = TestController(dialog) dialog.show() app.exec_()

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