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How to handle subclasses in JasperReports?

- by gotch4

I've two classes (A and B) that extend a base class BASE. I need to make a report that takes an array of such classes and the prints the fields of A or B. I tought of using conditional expressions, then casting to one or another (depending on a field value). But I can't cast, because I don't know how to refere to the current bean. To do this I am using a JRBeanCollectionDataSource filled with a List<BASE>. How do I cast every bean to A or B in a report (or subreport)? I tried: ((A)this) but it says basically that this contains the report instance, not the current bean and gives error.

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File.mkdir is not working and I can't understand why

- by gotch4

Hello, I've this brief snippet: String target = baseFolder.toString() + entryName; target = target.substring(0, target.length() - 1); File targetdir = new File(target); if (!targetdir.mkdirs()) { throw new Exception("Errore nell'estrazione del file zip"); } doesn't mattere if I leave the last char (that is usually a slash). It's done this way to work on both unix and windows. The path is actually obtained from the URI of the base folder. As you can see from baseFolder.toString() (baseFolder is of type URI and is correct). The base folder actually exists. I can't debug this because all I get is true or false from mkdir, no other explanations.The weird thing is that baseFolder is created as well with mkdir and in that case it works. Now I'm under windows. the value of target just before the creation of targetdir is "file:/C:/Users/dario/jCommesse/jCommesseDB" if I cut and paste it (without the last entry) in windows explore it works...

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Java generics why this won't work

- by gotch4

I was writing something using generics and to my surprise I found that this doesn't work: class foo<T>{ T innerT = new T(); } So can't I instantiate the genericized type? Aren't there any ways to do this?

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How to get cheap version control?

- by gotch4

Hello, I'm a programmer, contractor, self experimenter and so on. I'd need to have cheap version control. I've been working with Subversion and recently with Mercurial. I've seen around many cheap hosting but, even if they are great (like BitBucket), many of them don't allow many private projects (1 or 2). Much of the code I need to keep on VC is not open, maybe because it is stuff I'm working on for clients, or maybe because it's code I usually need for my development, but it is not intended and usable as a open source project. Now, I've a cheap web hosting, with unlimited space and free mysql. I CAN'T install Mercurial or SVN on those machinese, but I was asking myself if is it there a way to use a common CVS with it, with "common" I mean something that has its good IDE plugins (Eclipse or Netbeans) that may avoid me to write commands by hand. Thank you

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Spring can't find a lib and webapp doesn't start up in tomcat 6

- by gotch4

I've this problem using STS: I'm building a simple Spring app, just to try out features like MVC and persistence. Now I've created something very simple, out of a bunch of tutorials for Spring 3, that I'm using. The application fails with this, during server startup: Code: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping#0': Initialization of bean failed; nested exception is org.springframework.beans.factory.CannotLoadBeanClassException: Cannot find class [org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean] for bean with name 'mySessionFactory' defined in ServletContext resource [/WEB-INF/spring/appServlet/servlet-context.xml]; nested exception is java.lang.ClassNotFoundException: org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean but I've org.springframework.orm in web-inf/classes folder (I even tried putting it in web-inf/lib). As I copied these libs there, the came out in Web App Libraries folder. Building this project in STS works fine as this dependency is set up in build path throught project properties, but how do I transfer the libs to the web app? (I'm using Tomcat 6 as it is the server I'm going to use sometime in the future for production). Is this a config problem of my XML? Or am I just missing the right way to put this lib? (I encountered the same problem before, but adding the needed lib in classes worked it out). More than this I that if I browse inside my workspace to the folder where the working folder of tomcat should be, I can't find any work directory and any commo

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I can't use Spring filters in servlet-context XML

- by gotch4

For some reason both Eclipse and Spring can't find the filter tag (there is even a red mark)... What's wrong? <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> <bean class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor"></bean> <bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="com.mysql.jdbc.Driver" /> <property name="url" value="jdbc:mysql://localhost/jacciseweb" /> <property name="username" value="root" /> <property name="password" value="siussi" /> </bean> <bean id="mySessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="dataSource" ref="myDataSource" /> <property name="annotatedClasses"> <list> <value>it.jsoftware.jacciseweb.beans.Utente </value> <value>it.jsoftware.jacciseweb.beans.Ordine </value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect"> org.hibernate.dialect.MySQLDialect </prop> <prop key="hibernate.show_sql"> true </prop> <prop key="hibernate.hbm2ddl.auto"> update </prop> <prop key="hibernate.cache.provider_class">org.hibernate.cache.NoCacheProvider</prop> </props> </property> </bean> <filter> <filter-name>hibernateFilter</filter-name> <filter-class> org.springframework.orm.hibernate3.support.OpenSessionInViewFilter </filter-class> <init-param> <param-name>singleSession</param-name> <param-value>true</param-value> </init-param> <init-param> <param-name>sessionFactoryBeanName</param-name> <param-value>mySessionFactory</param-value> </init-param> </filter>      <bean id="acciseHibernateDao" class="it.jsoftware.jacciseweb.model.JAcciseWebManagementDaoHibernate"> <property name="sessionFactory" ref="mySessionFactory" /> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="mySessionFactory" /> </bean> <tx:annotation-driven /> <bean id="acciseService" class="it.jsoftware.jacciseweb.model.JAcciseWebManagementServiceImpl"> <property name="dao" ref="acciseHibernateDao" /> </bean> <context:component-scan base-package="it.jsoftware.jacciseweb.controllers"></context:component-scan> <mvc:annotation-driven /> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" p:synchronizeOnSession="true" /> <bean class="org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping" /> <mvc:resources mapping="/resources/**" location="/resources/" />   </beans> in particular it says "filter" is invalid content

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How to implement a network protocol?

- by gotch4

Here is a generic question. I'm not in search of the best answer, I'd just like you to express your favourite practices. I want to implement a network protocol in Java (but this is a rather general question, I faced the same issues in C++), this is not the first time, as I have done this before. But I think I am missing a good way to implement it. In fact usually it's all about exchanging text messages and some byte buffers between hosts, storing the status and wait until the next message comes. The problem is that I usually end up with a bunch of switch and more or less complex if statements that react to different statuses / messages. The whole thing usually gets complicated and hard to mantain. Not to mention that sometimes what comes out has some "blind spot", I mean statuses of the protocol that have not been covered and that behave in a unpredictable way. I tried to write down some state machine classes, that take care of checking start and end statuses for each action in more or less smart ways. This makes programming the protocol very complicated as I have to write lines and lines of code to cover every possible situation. What I'd like is something like a good pattern, or a best practice that is used in programming complex protocols, easy to mantain and to extend and very readable. What are your suggestions?

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