Search Results

Search found 14 results on 1 pages for 'kknight'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 1/1 | 1 

  • Confused about home screen widget size in normal screen and larget screen

    - by kknight
    I am designing a home screen widget. The widget layout file is like below. <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/widget" android:layout_width="240dip" android:layout_height="200dip" android:background="@drawable/base_all" /> I ran this widget on a HTC Hero device, which has a screen of 320 pixels * 480 pixels with mdpi. It ran perfect on HTC Hero. The widget takes 3 cells * 2 cells space, i.e. 240 pixels * 200 pixels. Then I ran this widget on a Nexus One device, which has a screen of 480 pixels * 800 pixels, mdpi. Since Nexus One also is mdpi, so I though 240dip is equivalent to 240 pixels on Nexus One and 200dip is equivalent to 200 pixels on Nexus One, so the widget will not take 3 cells * 2 cells space on Nexus One device. To my surprise, when running on Nexus One device, the widget take exact 3 cells * 2 cells, about 360 pixels * 300 pixels, on Nexus One device. I am confused. The layout xml above specifies 240dip in width and 200dip in height for the widget, but why did it take 360 pixels * 300 pixels on Nexus One Device? What am I missing? Thanks.

    Read the article

  • Unexpected behavior of IntentService

    - by kknight
    I used IntentService in my code instead of Service because IntentService creates a thread for me in onHandleIntent(Intent intent), so I don't have to create a Thead myself in the code of my service. I expected that two intents to the same IntentSerivce will execute in parallel because a thread is generated in IntentService for each invent. But my code turned out that the two intents executed in sequential way. This is my IntentService code: public class UpdateService extends IntentService { public static final String TAG = "HelloTestIntentService"; public UpdateService() { super("News UpdateService"); } protected void onHandleIntent(Intent intent) { String userAction = intent .getStringExtra("userAction"); Log.v(TAG, "" + new Date() + ", In onHandleIntent for userAction = " + userAction + ", thread id = " + Thread.currentThread().getId()); if ("1".equals(userAction)) { try { Thread.sleep(20 * 1000); } catch (InterruptedException e) { Log.e(TAG, "error", e); } Log.v(TAG, "" + new Date() + ", This thread is waked up."); } } } And the code call the service is below: public class HelloTest extends Activity { //@Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Intent selectIntent = new Intent(this, UpdateService.class); selectIntent.putExtra("userAction", "1"); this.startService(selectIntent); selectIntent = new Intent(this, UpdateService.class); selectIntent.putExtra("userAction", "2"); this.startService(selectIntent); } } I saw this log message in the log: V/HelloTestIntentService( 848): Wed May 05 14:59:37 PDT 2010, In onHandleIntent for userAction = 1, thread id = 8 D/dalvikvm( 609): GC freed 941 objects / 55672 bytes in 99ms V/HelloTestIntentService( 848): Wed May 05 15:00:00 PDT 2010, This thread is waked up. V/HelloTestIntentService( 848): Wed May 05 15:00:00 PDT 2010, In onHandleIntent for userAction = 2, thread id = 8 I/ActivityManager( 568): Stopping service: com.example.android/.UpdateService The log shows that the second intent waited the first intent to finish and they are in the same thread. It there anything I misunderstood of IntentService. To make two service intents execute in parallel, do I have to replace IntentService with service and start a thread myself in the service code? Thanks.

    Read the article

  • Home screen widget size for large screen or hdpi?

    - by kknight
    From Android widget screen guidelines, http://developer.android.com/guide/practices/ui_guidelines/widget_design.html, we know that, home screen has 4*4 cells, and in portrait orientation, each cell is 80 pixels wide by 100 pixels tall. I think these are for baseline HVGA screen. How about for large screens and hdpi screens, do they still have 4*4 cells for widget and each cell in portrait orientation is still 80 pixels * 100 pixels? Thanks.

    Read the article

  • How to detect orientation change in home screen widget?

    - by kknight
    I am writing a home screen widget and want to update the home screen widget when the device orientation changes from portrait to landscape or the other way. How can I make it? Currently, I tried to reigster to CONFIGURATION_CHANGED action like the code below, but the Android didn't allow me to do that by saying "IntentReceiver components are not allowed to register to receive intents". Can someone help me? Thanks. public class MyWidget extends AppWidgetProvider { @Override public void onEnabled(Context context) { super.onEnabled(context); this.registerReceiver(this, new IntentFilter(Intent.ACTION_CONFIGURATION_CHANGED)); }

    Read the article

  • How to make a shape with left-top round rounded corner and left-bottom rounded corner?

    - by kknight
    I want to make a shape with with left-top rounded corner and left-bottom rounded corner: <?xml version="1.0" encoding="UTF-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android"> <solid android:color="#555555"/> <stroke android:width="3dp" android:color="#555555" /> <padding android:left="1dp" android:top="1dp" android:right="1dp" android:bottom="1dp" /> <corners android:bottomRightRadius="0dp" android:bottomLeftRadius="2dp" android:topLeftRadius="2dp" android:topRightRadius="0dp"/> </shape> But the shape above didn't give me what I want. It gives me a rectangle without any rounded corners. Can anyone help? Thanks.

    Read the article

  • Weird onclick behavior of images on home screen widget

    - by kknight
    I wrote a home screen widget with one image on it. When the image is clicked, browser will be opened for a url link. Generally, it is working. But a weird thing is that, when I click background, then click the picture, the browser will not be open. Until I click the second time on the picture, the browser opens. The steps to reproduce is below: Click on the home screen widget background. Click on the image on the home screen. The browser is not opened. Click on the image again. The browser is opened. If I didn't click on the background, the image will react to click very well, i.e. browser will be open when the image is clicked the first time. The widget XML file is as below: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/widget" android:layout_width="320dip" android:layout_height="200dip" android:background="@drawable/prt_base" > <ImageView android:id="@+id/picture1" android:layout_width="134dip" android:layout_height="102dip" android:layout_marginLeft="62dip" android:layout_marginTop="6dip" android:scaleType="center" android:src="@drawable/picture1" /> </RelativeLayout> The code to set OnClick on the picture1 ImageView is as below: defineIntent = new Intent(Intent.ACTION_VIEW, Uri .parse("http://www.google.com")); pendingIntent = PendingIntent .getActivity(context, 0 /* no requestCode */, defineIntent, 0 /* no flags */); updateViews.setOnClickPendingIntent( picId, pendingIntent); Anyone knows what's wrong? Thanks.

    Read the article

  • Werid onclick behavior of images on home screen widget

    - by kknight
    I wrote a home screen widget with one image on it. When the image is clicked, browser will be opened for a url link. Generally, it is working. But a weird thing is that, when I click background, then click the picture, the browser will not be open. Until I click the second time on the picture, the browser opens. The steps to reproduce is below: Click on the home screen widget background. Click on the image on the home screen. The browser is not opened. Click on the image again. The browser is opened. If I didn't click on the background, the image will react to click very well, i.e. browser will be open when the image is clicked the first time. The widget XML file is as below: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/widget" android:layout_width="320dip" android:layout_height="200dip" android:background="@drawable/prt_base" > <ImageView android:id="@+id/picture1" android:layout_width="134dip" android:layout_height="102dip" android:layout_marginLeft="62dip" android:layout_marginTop="6dip" android:scaleType="center" android:src="@drawable/picture1" /> </RelativeLayout> The code to set OnClick on the picture1 ImageView is as below: defineIntent = new Intent(Intent.ACTION_VIEW, Uri .parse("http://www.google.com")); pendingIntent = PendingIntent .getActivity(context, 0 /* no requestCode */, defineIntent, 0 /* no flags */); updateViews.setOnClickPendingIntent( picId, pendingIntent); Anyone knows what's wrong? Thanks.

    Read the article

  • What's the default ScaleType of ImageView?

    - by kknight
    What's the default ScaleType of ImageView?If I put an image which is 400 pixels x 400 pixels on a normal screen (320x480) without specifying ScaleType, how will the image be scaled? Thanks. <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent"> <ImageView android:layout_width="fill_parent" android:layout_height="fill_parent" android:src="@drawable/big_image" /> </RelativeLayout>

    Read the article

  • Can I update an image in the drawable directory from code?

    - by kknight
    I have a picture in res/drawable directory: res/drawable/picture.jpeg. Can I dynamically update this picture.jpeg from code? i.e. I want to use another picture to replace this picture in the drawable directory dynamically. If I can, what path should I use to access the picture? Should I use "res/drawable/picture.jpeg"? Thanks.

    Read the article

  • Is it a good practice to create a reference to application context and use it anywhere?

    - by kknight
    I have to use context in many places of my code such as database operations, preference operations, etc. I don't want to pass in context for every method. Is it a good practice to create a reference to application context at the main Activity and use it anywhere such as database operations? So, I don't need some many context in method parameters, and the code can avoid position memory leak due to use of Activity Context. public class MainActivity extends Activity { public static Context s_appContext; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); s_appContext = this.getApplicationContext();

    Read the article

  • Weird parsing date string error in Android 2.0 emulator

    - by kknight
    I have a simple test code for testing SimpleDateFormat. This code works well on Eclipse and Android 1.5 emulator, but it failed at Android 2.0 emulator. Does anyone know why? Thanks. public class TemplateActivity extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); TextView tv = new TextView(this); tv.setText(R.string.hello); setContentView(tv); SimpleDateFormat format = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss zzz"); String dateStr = "Mon, 17 May 2010 01:45:41 GMT"; try { Date parsed = format.parse(dateStr); Log.v("Test", parsed.toString()); } catch (ParseException pe) { Log.v("Test", "ERROR: Cannot parse \"" + dateStr + "\""); } } } Log message: V/Test( 400): ERROR: Cannot parse "Mon, 17 May 2010 01:45:41 GMT"

    Read the article

  • comma in regex in String.replaceAll() method?

    - by kknight
    My code tries to replace "," with "/" in a string. Should I escape "," in the regex string? Both of the two code snippets generated the same results, so I am confused. Code snippet 1: String test = "a,bc,def"; System.out.println(test.replaceAll("\\,", "/")); Code snippet 2: String test = "a,bc,def"; System.out.println(test.replaceAll(",", "/")); Should I use "," or "\,"? Which is safer? Thanks.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

1