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  • Best way to handle multiple tables to replace one big table in Rails? (e.g. 'Books1', 'Books2', etc.

    - by mikep
    Hello, I've decided to use multiple tables for an entity (e.g. Books1, Books2, Books3, etc.), instead of just one main table which could end up having a lot of rows (e.g. just Books). I'm doing this to try and to avoid a potential future performance drop that could come with having too many rows in one table. With that, I'm looking for a good way to handle this in Rails, mainly by trying to avoid loading a bunch of unused associations. (I know that I could use a partition for this, but, for now, I've decided to go the 'multiple tables' route.) Each user has their books placed into a specific table. The actual book table is chosen when the user is created, and all of their books go into the same table. I'm going to split the adds across the tables. The goal is to try and keep each table pretty much even -- but that's a different issue. One thing I don't particularly want to have is a bunch of unused associations in the User class. Right now, it looks like I'd have to do the following: class User < ActiveRecord::Base has_many :books1, :books2, :books3, :books4, :books5 end class Books1 < ActiveRecord::Base belongs_to :user end class Books2 < ActiveRecord::Base belongs_to :user end class Books3 < ActiveRecord::Base belongs_to :user end I'm assuming that the main performance hit would come in terms of memory and possibly some method call overhead for each User object, since it has to load all of those associations, which in turn creates all of those nice, dynamic model accessor methods like User.find_by_. But for each specific user, only one of the book tables would be usable/applicable, since all of a user's books are stored in the same table. So, only one of the associations would be in use at any time and any other has_many :bookX association that was loaded would be a waste. For example, with a user.id of 2, I'd only need books3.find_by_author('Author'), but the way I'm thinking of setting this up, I'd still have access to Books1..n. I don't really know Ruby/Rails does internally with all of those has_many associations though, so maybe it's not so bad. But right now I'm thinking that it's really wasteful, and that there may just be a better, more efficient way of doing this. So, a few questions: 1) Is there's some sort of special Ruby/Rails methodology that could be applied to this 'multiple tables to represent one entity' scheme? Are there any 'best practices' for this? 2) Is it really bad to have so many unused has_many associations for each object? Is there a better way to do this? 3) Does anyone have any advice on how to abstract the fact that there's multiple book tables behind a single books model/class? For example, so I can call books.find_by_author('Author') instead of books3.find_by_author('Author'). Thank you!

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  • Change Stylesheet via If in php

    - by mikep
    Hey i have a question. At the moment i'm trying to use a stylesheet which i get through a if. but it doesn't do anything. here is my code at the moment. the variable $stylesheet will be variable but while testing i've setted it to normal <?php $stylesheet = 'normal' if($stylesheet = 'small') { $style = './sitestyle/stylesheetsmall.css'; } if($stylesheet = 'big') { $style = './sitestyle/stylesheetbig.css'; } else { $style = './sitestyle/stylesheet.css'; } echo '<link rel="stylesheet" type="text/css" href="$style">'; ?> Thanks for your answers.

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  • Debugging JSR 168 Portlet with spring, eclipse & pluto.

    - by mikep
    I am trying to set up a development environment to test Spring Portlet MVC for development of JSR 168 conforming portlets. I have the latest STS installed, which included Spring 2.5 and Eclipse (Catalina). This has been my environment to develop with Spring MVC, and that works fine using Apache as a local server for debugging. I found some instructions on the Pluto portal site on using Pluto as a remote debugging host for portlets. I have implemented those instructions. I am sending Eclipse into debug mode by right clicking on one of the JSPs and going into "debug as". My problem is that when I log into Pluto, it is not sending me into debug mode. I am seeing the default Pluto page as opposed to my portlet. My portlet has not been installed onto Pluto, and the instructions do not seem to require the portlet to be installed. To help, I have a screen shot at http://www.ceruleaninc.ca/pluto%5Fproblem.jpg, showing the following: Eclipse showing the remote debugging to localhost:8000 Tomcat showing the "Listening for transport dt_socket at address: 8000 The Catalina.bat jpda start command The Pluto Portal screen after log in Thanks much! I would welcome any advice on approaches to debugging portlets. I am not tied to pluto. There does seem to be a lack of detailed instructions on this topic.

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  • Compilation error on a user control

    - by MikeP
    I'm stumped! We have a user control for managing account information. We use this particular control on two pages. On one page, everything works perfectly and meets our expectation. On the second page however we receive compilation errors stating that: "C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\Temporary ASP.NET Files\lrpcentral\0e987bea\6719c8b6\App_Web_PageThatFails.aspx.f3d462c1.oi52bvii.0.cs(172): error CS0433: The type 'xxxx_ascx' exists in both 'c:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\Temporary ASP.NET Files\APPLICATIONNAME\0e987bea\6719c8b6\App_Web_xxxx.ascx.cdcab7d2.xbnvt2za.dll' and 'c:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\Temporary ASP.NET Files\APPLICATIONNAME\0e987bea\6719c8b6\App_Web_eix7xllr.dll' My problem is similar to Cyril's but the "delete everything from Temp" is not an option for me, and Cyril's solution does not apply since the only variable we have is contained in the designer file, which is not deployed to our production environment (we pre-compile). After reading David's answer (here) I examined my directories for circular dependency and was unable to find any. Structure: Top Level Page that works Control Directory A Page that causes the error

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  • How to avoid multiple, unused has_many associations when using multiple models for the same entity (

    - by mikep
    Hello, I'm looking for a nice, Ruby/Rails-esque solution for something. I'm trying to split up some data using multiple tables, rather than just using one gigantic table. My reasoning is pretty much to try and avoid the performance drop that would come with having a big table. So, rather than have one table called books, I have multiple tables: books1, books2, books3, etc. (I know that I could use a partition, but, for now, I've decided to go the 'multiple tables' route.) Each user has their books placed into a specific table. The actual book table is chosen when the user is created, and all of their books go into the same table. The goal is to try and keep each table pretty much even -- but that's a different issue. One thing I don't particularly want to have is a bunch of unused associations in the User class. Right now, it looks like I'd have to do the following: class User < ActiveRecord::Base has_many :books1, :books2, :books3, :books4, :books5 end class Books1 < ActiveRecord::Base belongs_to :user end class Books2 < ActiveRecord::Base belongs_to :user end First off, for each specific user, only one of the book tables would be usable/applicable, since all of a user's books are stored in the same table. So, only one of the associations would be in use at any time and any other has_many :bookX association that was loaded would be a waste. I don't really know Ruby/Rails does internally with all of those has_many associations though, so maybe it's not so bad. But right now I'm thinking that it's really wasteful, and that there may just be a better, more efficient way of doing this. Is there's some sort of special Ruby/Rails methodology that could be applied here to avoid having to have all of those has_many associations? Also, does anyone have any advice on how to abstract the fact that there's multiple book tables behind a single books model/class?

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  • Animate an Image after hovering an item a second

    - by mikep
    Hey, after some tries to get this to work, i ask you, if you know where my mistake is. This is my code until now: $(".menu a").hover( function () { $(this).data('timeout', setTimeout( function () { $(this).hover(function() { $(this).next("em").animate({opacity: "show", top: "-65"}, "slow"); }, function() { $(this).next("em").animate({opacity: "hide", top: "-75"}, "fast"); }); }, 1000)); }, function () { clearTimeout($(this).data('timeout')); }); i would be happy about some help.

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  • Why i get everytime the error-message that i've already sent the headers

    - by mikep
    Hey, i've another question about web-programming. I programmed a login script, but everytime when i try to login it says that i've send the header informations already. Here are the 2 files: <?php if($_GET['logout'] == 1) { setcookie('authorized', 1, time()-3600); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Login - photoAdminSite</title> </head> <style type="text/css"> body { text-align: center; font-family: helvetica; } #loginForm { padding: 1em; background: #e3e3e3; width: 260px; margin: 3em auto 0; text-align: left; } </style> <body> <div id="loginForm"> <form method="post" action="confirm_login_credentials.php"> <h2>LOGIN</h2> <p>Username: <input type="text" name="username" /></p> <p>Password: <input type="password" name="password" /></p> <p><input type="submit" value="Login" name="submit" /></p> </form> </div> </body> </html> <?php $username = $_POST['username']; $password = $_POST['password']; require 'database.php'; $q = "SELECT id FROM users_photoadminsite WHERE user_name = '$username' AND password = '$password'"; $result = $mysqli->query($q) or die(mysqli_error()); if (mysqli_num_rows($result) == 1) { setcookie('authorized', 1, 0); header("Location: index.php"); } else { header("Location: login.php"); } ?> i would be really happy about some helpful answers.

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