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  • Presenting Beginning PowerShell at SQL Saturday 149 MN

    - by merrillaldrich
    I am happy to be presenting a session on beginning PowerShell for DBAs at my new home town’s SQL Saturday! (I moved from Seattle to Saint Paul, MN a short time ago.) I will be sharpening this presentation up to make sure anyone who comes will not go away empty handed. BTW, WOW, the schedule is up and I must admit I did not expect nine tracks of awesome. This looks amazing. My session is geared toward helping those DBAs who have not seen PowerShell, or perhaps may find PowerShell syntax opaque or...(read more)

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  • SQL Server 2008 need just like crosstab query on XML column?

    - by user1332896
    <abc id="abc1"> <def id="def1"> <ghi att='ghi1'> <mn id="0742d2ea" name="RF" dt="0" df="3" ty="0" /> <mn id="64d9a11b" name="CJ" dt="0" df="3" ty="0" /> <mn id="db72d154" name="FJ" dt="2" df="4" ty="0" /> <mn id="39af9fa1" name="BS" dt="0" df="2" ty="0" /> </ghi> <jkl att='jkl1'> <mn id="0742d2ea" name="RF" dt="1" gl="19" /> <mn id="64d9a11b" name="CJ" dt="0" gl="6" /> <mn id="db72d154" name="FJ" dt="0" gl="0" /> <mn id="39af9fa1" name="BS" dt="0" gl="12" /> <mn id="ac4f566f" name="DJ" dt="0" gl="9" /> <mn id="4bf3ba2f" name="RP" dt="0" gl="16" /> <mn id="db1af021" name="SC" dt="1" gl="10" /> <mn id="c4c93a2d" name="DN" dt="1" gl="15" /> </jkl> </def> </abc> I need this output. Is this possible in SQL Server 2008? id name ghiDT ghiDF ghiTY jklDT jklGL 0742d2ea RF 0 3 0 1 19 64d9a11b CJ 0 3 0 0 6 db72d154 FJ 2 4 0 0 0 39af9fa1 BS 0 2 0 0 12 ac4f566f DJ 0 0 0 0 9 4bf3ba2f RP 0 0 0 0 16 db1af021 SC 0 0 0 1 10 c4c93a2d DN 0 0 0 1 15

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  • mysql query to dynamically convert row data to columns

    - by Anirudh Goel
    I am working on a pivot table query. The schema is as follows Sno, Name, District The same name may appear in many districts eg take the sample data for example 1 Mike CA 2 Mike CA 3 Proctor JB 4 Luke MN 5 Luke MN 6 Mike CA 7 Mike LP 8 Proctor MN 9 Proctor JB 10 Proctor MN 11 Luke MN As you see i have a set of 4 distinct districts (CA, JB, MN, LP). Now i wanted to get the pivot table generated for it by mapping the name against districts Name CA JB MN LP Mike 3 0 0 1 Proctor 0 2 2 0 Luke 0 0 3 0 i wrote the following query for this select name,sum(if(District="CA",1,0)) as "CA",sum(if(District="JB",1,0)) as "JB",sum(if(District="MN",1,0)) as "MN",sum(if(District="LP",1,0)) as "LP" from district_details group by name However there is a possibility that the districts may increase, in that case i will have to manually edit the query again and add the new district to it. I want to know if there is a query which can dynamically take the names of distinct districts and run the above query. I know i can do it with a procedure and generating the script on the fly, is there any other method too? I ask so because the output of the query "select distinct(districts) from district_details" will return me a single column having district name on each row, which i will like to be transposed to the column.

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  • Using a map with set_intersection

    - by Robin Welch
    Not used set_intersection before, but I believe it will work with maps. I wrote the following example code but it doesn't give me what I'd expect: #include <map> #include <string> #include <iostream> #include <algorithm> using namespace std; struct Money { double amount; string currency; bool operator< ( const Money& rhs ) const { if ( amount != rhs.amount ) return ( amount < rhs.amount ); return ( currency < rhs.currency ); } }; int main( int argc, char* argv[] ) { Money mn[] = { { 2.32, "USD" }, { 2.76, "USD" }, { 4.30, "GBP" }, { 1.21, "GBP" }, { 1.37, "GBP" }, { 6.74, "GBP" }, { 2.55, "EUR" } }; typedef pair< int, Money > MoneyPair; typedef map< int, Money > MoneyMap; MoneyMap map1; map1.insert( MoneyPair( 1, mn[1] ) ); map1.insert( MoneyPair( 2, mn[2] ) ); map1.insert( MoneyPair( 3, mn[3] ) ); // (3) map1.insert( MoneyPair( 4, mn[4] ) ); // (4) MoneyMap map2; map1.insert( MoneyPair( 3, mn[3] ) ); // (3) map1.insert( MoneyPair( 4, mn[4] ) ); // (4) map1.insert( MoneyPair( 5, mn[5] ) ); map1.insert( MoneyPair( 6, mn[6] ) ); map1.insert( MoneyPair( 7, mn[7] ) ); MoneyMap out; MoneyMap::iterator out_itr( out.begin() ); set_intersection( map1.begin(), map1.end(), map2.begin(), map2.end(), inserter( out, out_itr ) ); cout << "intersection has " << out.size() << " elements." << endl; return 0; } Since the pair labelled (3) and (4) appear in both maps, I was expecting that I'd get 2 elements in the intersection, but no, I get: intersection has 0 elements. I'm sure this is something to do with the comparitor on the map / pair but can't figure it out.

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  • OpenLDAP replication fails, "syncrepl_entry: rid=666 be_modify failed (20)"

    - by Pavel
    I've configured a second host to replicate the main LDAP server via syncrepl in the slapd.conf: syncrepl rid=666 provider=ldaps://my-main-server.com type=refreshAndPersist searchBase="dc=Staff,dc=my-main-server,dc=com" filter="(objectClass=*)" scope=sub schemachecking=off bindmethod=simple binddn="cn=repadmin,dc=my-main-server,dc=com" credentials=mypassword When I restart slapd, it writes to /var/log/debug Jun 11 15:48:33 cluster-mn-04 slapd[29441]: @(#) $OpenLDAP: slapd 2.4.9 (Mar 31 2009 07:18:37) $ ^Ibuildd@yellow:/build/buildd/openldap2.3-2.4.9/debian/build/servers/slapd Jun 11 15:48:34 cluster-mn-04 slapd[29442]: slapd starting Jun 11 15:48:34 cluster-mn-04 slapd[29442]: null_callback : error code 0x14 Jun 11 15:48:34 cluster-mn-04 slapd[29442]: syncrepl_entry: rid=666 be_modify failed (20) Jun 11 15:48:34 cluster-mn-04 slapd[29442]: do_syncrepl: rid=666 quitting I've looked into the sources for the return code and found only #define LDAP_TYPE_OR_VALUE_EXISTS 0x14 in include/ldap.h. Anyway, I don't quite get what the error message means. Can you help me debugging this problem and figure out why the LDAP replication doesn't work? I've managed to put a "manual" copy via slapcat and slapadd into the database, but I'd like to sync automatically. UPDATE: "Solved" by removing /var/lib/ldap/* and re-importing the database with slapadd.

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  • Elegant way for a recursive C++ template to do something different with the leaf class?

    - by Costas
    I have a C++ class template that makes an Array of pointers. This also gets typedefed to make Arrays of Arrays and so on: typedef Array<Elem> ElemArray; typedef Array<ElemArray> ElemArrayArray; typedef Array<ElemArrayArray> ElemArrayArrayArray; I would like to be able to set one leaf node from another by copying the pointer so they both refer to the same Elem. But I also want to be able to set one Array (or Array of Arrays etc) from another. In this case I don't want to copy the pointers, I want to keep the arrays seperate and descend into each one until I get to the leaf node, at where I finally copy the pointers. I have code that does this (below). When you set something in an Array it calls a CopyIn method to do the copying. But because this is templated it also has to call the CopyIn method on the leaf class, which means I have to add a dummy method to every leaf class that just returns false. I have also tried adding a flag to the template to tell it whether it contains Arrays or not, and so whether to call the CopyIn method. This works fine - the CopyIn method of the leaf nodes never gets called, but it still has to be there for the compile to work! Is there a better way to do this? #include <stdio.h> class Elem { public: Elem(int v) : mI(v) {} void Print() { printf("%d\n",mI); } bool CopyIn(Elem *v) { return false; } int mI; }; template < typename T > class Array { public: Array(int size) : mB(0), mN(size) { mB = new T* [size]; for (int i=0; i<mN; i++) mB[i] = new T(mN); } ~Array() { for (int i=0; i<mN; i++) delete mB[i]; delete [] mB; } T* Get(int i) { return mB[i]; } void Set(int i, T* v) { if (! mB[i]->CopyIn(v) ) { // its not an array, so copy the pointer mB[i] = v; } } bool CopyIn(Array<T>* v) { for (int i=0; i<mN; i++) { if (v && i < v->mN ) { if ( ! mB[i]->CopyIn( v->mB[i] )) { // its not an array, so copy the pointer mB[i] = v->mB[i]; } } else { mB[i] = 0; } } return true; // we did the copy, no need to copy pointer } void Print() { for (int i=0; i<mN; i++) { printf("[%d] ",i); mB[i]->Print(); } } private: T **mB; int mN; }; typedef Array<Elem> ElemArray; typedef Array<ElemArray> ElemArrayArray; typedef Array<ElemArrayArray> ElemArrayArrayArray; int main () { ElemArrayArrayArray* a = new ElemArrayArrayArray(2); ElemArrayArrayArray* b = new ElemArrayArrayArray(3); // In this case I need to copy the pointer to the Elem into the ElemArrayArray a->Get(0)->Get(0)->Set(0, b->Get(0)->Get(0)->Get(0)); // in this case I need go down through a and b until I get the to Elems // so I can copy the pointers a->Set(1,b->Get(2)); b->Get(0)->Get(0)->Get(0)->mI = 42; // this will also set a[0,0,0] b->Get(2)->Get(1)->Get(1)->mI = 96; // this will also set a[1,1,1] // should be 42,2, 2,2, 3,3, 3,96 a->Print(); }

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  • Mean of Sampleset and powered Sampleset

    - by Milla Well
    I am working on an ICA implementation wich is based on the assumption, that all source signals are independent. So I checked on the basic concepts of Dependence vs. Correlation and tried to show this example on sample data from numpy import * from numpy.random import * k = 1000 s = 10000 mn = 0 mnPow = 0 for i in arange(1,k): a = randn(s) a = a-mean(a) mn = mn + mean(a) mnPow = mnPow + mean(a**3) print "Mean X: ", mn/k print "Mean X^3: ", mnPow/k But I couldn't produce the last step of this example E(X^3) = 0: >> Mean X: -1.11174580826e-18 >> Mean X^3: -0.00125229267144 First value I would consider to be zero, but second value is too large, isn't it? Since I subtract the mean of a, I expected the mean of a^3 to be zero as well. Does the problem lie in the random number generator, the precision of the numerical values in my misunderstanding of the concepts of mean and expected value?

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  • I need a js function that can sort state from Dropbox and gave me a phone number to call [on hold]

    - by User584
    AL West AR West CT EAST DC EAST Il West MN East player one groupe A player tow Groupe B player zero Groupe D if the Group is A and the State is AL then Phone = 0762154852 if the Group is B and the State is AR then phone = 2145632541 if the group is D and the state is MN then phone = 2589632541 if i player from a dropbox and then i select State from a dropbox I want the Field phone Show the right number

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  • Which version management design methodology to be used in a Dependent System nodes?

    - by actiononmail
    This is my first question so please indicate if my question is too vague and not understandable. My question is more related to High Level Design. We have a system (specifically an ATCA Chassis) configured in a Star Topology, having Master Node (MN) and other sub-ordinate nodes(SN). All nodes are connected via Ethernet and shall run on Linux OS with other proprietary applications. I have to build a recovery Framework Design so that any software entity, whether its Linux, Ramdisk or application can be rollback to previous good versions if something bad happens. Thus I think of maintaining a State Version Matrix over MN, where each State(1,2....n) represents Good Kernel, Ramdisk and application versions for each SN. It may happen that one SN version can dependent on other SN's version. Please see following diagram:- So I am in dilemma whether to use Package Management Methodology used by Debian Distributions (Like Ubuntu) or GIT repository methodology; in order to do a Rollback to previous good versions on either one SN or on all the dependent SNs. The method should also be easier for upgrading SNs along with MNs. Some of the features which I am trying to achieve:- 1) Upgrade of even single software entity is achievable without hindering others. 2) Dependency checks must be done before applying rollback or upgrade on each of the SN 3) User Prompt should be given in case dependency fails.If User still go for rollback, all the SNs should get notification to rollback there own releases (if required). 4) The binaries should be distributed on SNs accordingly so that recovery process is faster; rather fetching every time from MN. 5) Release Patches from developer for bug fixes, feature enhancement can be applied on running system. 6) Each version can be easily tracked and distinguishable. Thanks

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  • Constructor ambiguous quesiton

    - by Crystal
    I'm trying to create a simple date class, but I get an error on my main file that says, "call of overloaded Date() is ambiguous." I'm not sure why since I thought as long as I had different parameters for my constructor, I was ok. Here is my code: header file: #ifndef DATE_H #define DATE_H using std::string; class Date { public: static const int monthsPerYear = 12; // num of months in a yr Date(int = 1, int = 1, int = 1900); // default constructor Date(); // uses system time to create object void print() const; // print date in month/day/year format ~Date(); // provided to confirm destruction order string getMonth(int month) const; // gets month in text format private: int month; // 1 - 12 int day; // 1 - 31 int year; // any year int checkDay(int) const; }; #endif .cpp file #include <iostream> #include <iomanip> #include <string> #include <ctime> #include "Date.h" using namespace std; Date::Date() { time_t seconds = time(NULL); struct tm* t = localtime(&seconds); month = t->tm_mon; day = t->tm_mday; year = t->tm_year; } Date::Date(int mn, int dy, int yr) { if (mn > 0 && mn <= monthsPerYear) month = mn; else { month = 1; // invalid month set to 1 cout << "Invalid month (" << mn << ") set to 1.\n"; } year = yr; // could validate yr day = checkDay(dy); // validate the day // output Date object to show when its constructor is called cout << "Date object constructor for date "; print(); cout << endl; } void Date::print() const { string str; cout << month << '/' << day << '/' << year << '\n'; // new code for HW2 cout << setfill('0') << setw(3) << day; // prints in ddd cout << " " << year << '\n'; // yyyy format str = getMonth(month); // prints in month (full word), day, year cout << str << " " << day << ", " << year << '\n'; } and my main.cpp #include <iostream> #include "Date.h" using std::cout; int main() { Date date1(4, 30, 1980); date1.print(); cout << '\n'; Date date2; date2.print(); }

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  • Ambiguous constructor call

    - by Crystal
    I'm trying to create a simple date class, but I get an error on my main file that says, "call of overloaded Date() is ambiguous." I'm not sure why since I thought as long as I had different parameters for my constructor, I was ok. Here is my code: header file: #ifndef DATE_H #define DATE_H using std::string; class Date { public: static const int monthsPerYear = 12; // num of months in a yr Date(int = 1, int = 1, int = 1900); // default constructor Date(); // uses system time to create object void print() const; // print date in month/day/year format ~Date(); // provided to confirm destruction order string getMonth(int month) const; // gets month in text format private: int month; // 1 - 12 int day; // 1 - 31 int year; // any year int checkDay(int) const; }; #endif .cpp file #include <iostream> #include <iomanip> #include <string> #include <ctime> #include "Date.h" using namespace std; Date::Date() { time_t seconds = time(NULL); struct tm* t = localtime(&seconds); month = t->tm_mon; day = t->tm_mday; year = t->tm_year; } Date::Date(int mn, int dy, int yr) { if (mn > 0 && mn <= monthsPerYear) month = mn; else { month = 1; // invalid month set to 1 cout << "Invalid month (" << mn << ") set to 1.\n"; } year = yr; // could validate yr day = checkDay(dy); // validate the day // output Date object to show when its constructor is called cout << "Date object constructor for date "; print(); cout << endl; } void Date::print() const { string str; cout << month << '/' << day << '/' << year << '\n'; // new code for HW2 cout << setfill('0') << setw(3) << day; // prints in ddd cout << " " << year << '\n'; // yyyy format str = getMonth(month); // prints in month (full word), day, year cout << str << " " << day << ", " << year << '\n'; } and my main.cpp #include <iostream> #include "Date.h" using std::cout; int main() { Date date1(4, 30, 1980); date1.print(); cout << '\n'; Date date2; date2.print(); }

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  • Set up Windows SBS dns server and vpn clients from brench office

    - by mn
    I have got some clients from bench office which connects vpn to main office. The Router from bench office assigned addresses from DHCP 192.168.1.0/255.255.255.0 and remote gateway assigned vpn ip addresses 10.10.20.0/255.255.255.0. There is a DNS server (Active Directory Win SBS 2000) and vpn client are registered with vpn address (10.10.20.0/255.255.255.0 and domain company.com.pl). I would like to register also primary bench subnet 192.168.1.0/255.255.255.0 with domain for example company.vpn.local I want to access vpn hosts for example: dev3.copmany.pkb.local and dev3.company.com using my Win SBS 2000 DNS server.

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  • HP E200i Controlller RAID Configuration fon Win2008 Ent, Sql Server, IIS Apps etc need opinion

    - by mn
    Hello, Actually I run RAID 5 (4 x SAS drives) with Win 2008 Ent(1x host) Win 2008 End(3x guest) Sql Server 2005 Std (on guest) 3 x asp.net applications (on guest) I bought 3 x drives to create additional array (on same controller E200i, I am waiting now for confirmation is it possible to have 3 raids in same controller) I am planning to have 2 x RAID5 (if it is possible) first RAID 5 with all vhd files, systems etc second RAID 5 all data files and transaction logs I am looking for opinion how to optimize data layer (seven drives, one controller).

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  • storing passed arguments in separate variables -shell scripting

    - by Nathan Pk
    In my script "script.sh" , I want to store 1st and 2nd argument to some variable and rest to another separate variable. What command I must use to implement this task? Number of arguments that is passed to a script is random) When I run the command in console ./script.sh abc def ghi jkl mn o p qrs xxx #It can have any number of arguments In this case, I want my script to store "abc" and "def" in one variable. "ghi jkl mn o p qrs xxx" should be stored in another variable.

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  • SimplePie not parsing flickr feed

    - by mn
    I am trying to use SimplePie to pull a group pool flickr feed: $feed = new SimplePie(); $feed->set_feed_url('http://api.flickr.com/services/feeds/groups_pool.gne?id=25938750@N00&lang=en-us&format=rss_200'); $feed->init(); $feed->handle_content_type(); Then I use typical SimplePie php calls to loop through the feed items. However, nothing is returned. The HTML is there, but the feed elements aren't inserted. When I try to use a flickr feed of tags, like: $feed->set_feed_url('http://api.flickr.com/services/feeds/photos_public.gne?tags=architecture,building&lang=en-us&format=rss_200'); I get back a list of photos from the public photo feed, but the tags aren't taken into account. Any ideas? The only thing I can think of is I need an API key, but there is nothing on the flickr website that indicates a key is needed for feed calls. Plus, I can open both types of feeds in my browser and get the feed I am looking for.

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  • NSString within a link

    - by MN
    Hi, I have a UIWebView that loads a link, http://www.google.com/a/datacommsales.net. But I want to have the datacommsales.net part interchangable. What I would like it to be is http://www.google.com/a/stringOne, stringOne being the NSString, so I can set the value of the string and change the link without editing the code. But the link is inside quotes, @"http://www.google.com/a/datacommsales.net", so it doesn't recognize the string. How could I include the string's value as part of the link? Any help is appreciated.

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  • Two '==' equality operators in same 'if' condition are not working as intended.

    - by Manav MN
    I am trying to establish equality of three equal variables, but the following code is not printing the obvious true answer which it should print. Can someone explain, how the compiler is parsing the given if condition internally? #include<stdio.h> int main() { int i = 123, j = 123, k = 123; if ( i == j == k) printf("Equal\n"); else printf("NOT Equal\n"); return 0; } Output: manav@workstation:~$ gcc -Wall -pedantic calc.c calc.c: In function ‘main’: calc.c:5: warning: suggest parentheses around comparison in operand of ‘==’ manav@workstation:~$ ./a.out NOT Equal manav@workstation:~$ EDIT: Going by the answers given below, is the following statement okay to check above equality? if ( (i==j) == (j==k))

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  • Using (void)awakeFromNib

    - by MN
    I am trying to run an action when the application starts. The action checkAtStart is supposed to display an alert if there is no text in field1 and hide startView if there is text in field1. checkAtStart works fine if assigned to a button, but when I try to run it using (void)awakeFromNib, the alert will display no matter what and startView will never hide. Its probably something really simple that I'm forgetting. Any help is appreciated! Here is my code: - (void)awakeFromNib { [self checkAtStart:self]; } - (IBAction)checkAtStart:(id)sender { if (field1.text == nil || [field1.text isEqualToString:@""]) { NSString *msg = nil; msg = nil; UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Test Message" message:@"Test Message" delegate:self cancelButtonTitle:@"Close" otherButtonTitles: nil]; [alert show]; [alert release]; [msg release]; } else { startView.hidden = YES; } }

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  • iPhone application not running with Distribution Certificate

    - by MN
    I have a problem regarding running my application with a Distribution certificate. The application will work fine with a Development certificate on my iPod Touch. Once I change the Code Signing Identity to a Distribution certificate and specify an Entitlements file, the application crashes on launch. Is there anything I can do to correct this? Thanks in advance!

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  • Object not declared in scope

    - by jay
    I'm using Xcode for C++ on my computer while using Visual Studio at school. The following code worked just fine in Visual Studio, but I'm having this problem when using Xcode. clock c1(2, 3, 30); Everything works just fine, but it keeps giving me this error that says "Expected ';' before 'c1'" Fine, I put the ';' .. but then, it gives me this error: "'c1' was not declared in this scope" Here's the whole header code: #include <iostream> using namespace std; class clock { private: int h; int m; int s; public: clock(int hr, int mn, int sec); }; clock::clock(int hr, int mn, int sec) { h = hr; m = mn; s = sec; } Here's the whole .cpp code: #include "clock.h" int main() { clock c1(2, 3, 30); return 0; } I stripped everything down to where I had the problem. Everything else, as far as I know, is irrelevant since the problem remains the same with just the mentioned above. Thanks in advance!

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  • new Date() In javascript :: need Help

    - by gskoli
    Dear all, i am creating a digital clock using images & javascript but i want to pass a server time that time ... How to do that ... I am getting time from server and passing it to Date Following i have given snippet . var time_str = document.clock_form.time_str.value ; //alert (time_str); function dotime(){ theTime=setTimeout('dotime();',1000); //d = new Date(Date.parse(time_str)); d= new Date(time_str); hr= d.getHours()+100; mn= d.getMinutes()+100; se= d.getSeconds()+100; var time_str = document.clock_form.time_str.value ; //alert (time_str); alert(' TIME ---> '+hr+' :: '+mn+' :: '+ se); if(hr==100){ hr=112;am_pm='am'; } else if(hr<112){ am_pm='am'; } else if(hr==112){ am_pm='pm'; } else if(hr>112){ am_pm='pm';hr=(hr-12); } tot=''+hr+mn+se; document.hr1.src = '/flash_files/digits/dg'+tot.substring(1,2)+'.gif'; document.hr2.src = '/flash_files/digits/dg'+tot.substring(2,3)+'.gif'; document.mn1.src = '/flash_files/digits/dg'+tot.substring(4,5)+'.gif'; document.mn2.src = '/flash_files/digits/dg'+tot.substring(5,6)+'.gif'; document.se1.src = '/flash_files/digits/dg'+tot.substring(7,8)+'.gif'; document.se2.src = '/flash_files/digits/dg'+tot.substring(8,9)+'.gif'; document.ampm.src= '/flash_files/digits/dg'+am_pm+'.gif'; } dotime(); But it is not working Help me out Thanks in advance.

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  • Passing time from server to client

    - by gskoli
    Dear all, i am creating a digital clock using images & javascript but i want to pass a server time that time ... How to do that ... I am getting time from server and passing it to Date Following i have given snippet . var time_str = document.clock_form.time_str.value ; //alert (time_str); function dotime(){ theTime=setTimeout('dotime();',1000); //d = new Date(Date.parse(time_str)); d= new Date(time_str); hr= d.getHours()+100; mn= d.getMinutes()+100; se= d.getSeconds()+100; var time_str = document.clock_form.time_str.value ; //alert (time_str); alert(' TIME ---> '+hr+' :: '+mn+' :: '+ se); if(hr==100){ hr=112;am_pm='am'; } else if(hr<112){ am_pm='am'; } else if(hr==112){ am_pm='pm'; } else if(hr>112){ am_pm='pm';hr=(hr-12); } tot=''+hr+mn+se; document.hr1.src = '/flash_files/digits/dg'+tot.substring(1,2)+'.gif'; document.hr2.src = '/flash_files/digits/dg'+tot.substring(2,3)+'.gif'; document.mn1.src = '/flash_files/digits/dg'+tot.substring(4,5)+'.gif'; document.mn2.src = '/flash_files/digits/dg'+tot.substring(5,6)+'.gif'; document.se1.src = '/flash_files/digits/dg'+tot.substring(7,8)+'.gif'; document.se2.src = '/flash_files/digits/dg'+tot.substring(8,9)+'.gif'; document.ampm.src= '/flash_files/digits/dg'+am_pm+'.gif'; } dotime(); But it is not working Help me out Thanks in advance.

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  • Three Steps to Becoming an Expert Oracle Linux System Administrator

    - by Antoinette O'Sullivan
    Oracle provides a complete system administration curriculum to take you from your initial experience of Unix to being an expert Oracle Linux system administrator. You can take these live instructor-led courses from your own desk through live-virtual events or by traveling to an education center through in-class events. Step 1: Unix and Linux Essentials This 3-day course is designed for users and administrators who are new to Oracle Linux. It will help you develop the basic UNIX skills needed to interact comfortably and confidently with the operating system. Below is a sample of the in-class events already on the schedule.  Location  Date  Delivery Language  Vivoorde, Belgium  28 October 2013  English  Berlin, Germany  15 July 2013  German  Utrecht, Netherlands  19 August 2013  Dutch  Bucarest, Romania  12 August 2013  Romanian  Ankara, Turkey  6 January 2013  Turkish  Nairobi, Kenya  5 August 2013  English  Kaduna, Nigeria  15 July 2013  English   Woodmead, South Africa  15 July 2013  English   Jakarta, Indonesia  23 September 2013  English  Petaling Jaya, Malaysia  22 July 2013  English  Makati City, Philippines  3 July 2013  English  Bangkok, Thailand  20 November 2013  English  Auckland, New Zealand  5 August 2013  English  Melbourne, Australia  12 August 2013  English  Ottawa, Montreal, Toronto, Canada  3 September 2013  English  San Francisco and San Jose, CA, United States  15 July 2013  English  Reston, VA, United States  7 August 2013  English  Edison, NJ, and King of Prussia, PA, United States  3 September 2013  English  Denver, CO, United States  25 September 2013  English  Cambridge, MA, and Roseville MN, United States  6 November 2013  English  Phoenix, AZ, and Sacramento, CA, United States  25 November 2013  English Step 2: Oracle Linux System Administration Through this 5-day course, become a knowledgeable Oracle Linux system administrator, learning how to install Oracle Linux and the benefits of Oracle's Unbreakable Enterprise Kernel and Ksplice. Below is a sample of in-class events already on the schedule.  Location  Date  Delivery Language  Vienna, Austria  1 July 2013  German  Vivoorde, Belgium  18 November 2013  English  Zagreb, Croatia  16 September 2013  Croatian  London, England  3 September 2013  English  Manchester, England  9 September 2013  English  Paris, France  29 July 2013  French  Budapest, Hungary  8 July 2013  Hungarian  Utrecht, Netherland  2 September 2013  Dutch  Warsaw, Poland  15 July 2013  Polish  Bucharest, Romania  2 December 2013  Romanian  Ankara, Turkey  7 October 2013  Turkish  Istanbul, Turkey  9 September 2013  Turkish  Nairobi, Kenya  12 August 2013  English  Petaling Jaya, Malaysia  29 July 2013  English  Kuala Lumpur, Malaysia  21 October 2013  English  Makati City, Philippines  8 July 2013  English  Singapore  24 July 2013  English  Bangkok, Thailand  26 July 2013  English  Canberra, Australia  19 August 2013  English  Melbourne, Australia  16 September 2013  English   Sydney, Australia 19 August 2013   English   Mississauga, Canada  26 August 2013  English  Ottawa, Canada  4 November 2013  English  Phoenix, AZ, United States  7 October 2013  English  Belmont, CA, United States  23 September 2013  English  Irvine, CA, United States  18 November 2013  English  Sacramento, CA, United States  19 August 2013  English  San Francisco, CA, United States  15 July 2013  English  Denver, CO, United States  19 August 2013  English  Schaumburg, IL, United States  26 August 2013  English  Indianapolis, IN, United States  14 October 2013  English  Columbia, MD, United States  30 September 2013  English  Roseville, MN, United States  19 August 2013  English  St Louis, MO, United States  7 October 2013  English  Edison, NJ, United States  28 October 2013  English  Beaverton, OR, United States  12 August 2013  English  Pittsburg, PA, United States 9 December 2013   English  Reston, VA, United States 12 August 2013   English  Brookfield, WI, United States 30 September 2013   English  Sao Paolo, Brazil 15 July 2013   Brazilian Portugese Step 3: Oracle Linux Advanced System Administration This new 3-day course is ideal for administrators who want to learn about managing resources and file systems while developing troubleshooting and advanced storage administration skills. You will learn about Linux Containers, Cgroups, btrfs, DTrace and more. Below is a sample of in-class events already on the schedule.  Location  Date  Delivery Language  Melbourne, Australia  9 October 2013  English  Roseville, MN, United States  3 September 2013  English To register for or learn more about these courses, go to http://oracle.com/education/linux. Watch this video to learn more about Oracle's operating system training.

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  • BlackBerry/J2ME - SAX parse collection of objects with attributes

    - by Changqi Guo
    I have a problem with using the SAX parser to parse a XML file. It is a complex XML file, it is like the following. <Objects> <Object no="1"> <field name="PID">ilives:87877</field> <field name="dc.coverage">Charlottetown</field> <field name="fgs.ownerId">fedoraAdmin</field> </Object> <Object no="2">...... I am confused how to get the names in each field, and how to store the information of each object. import java.util.Enumeration; import java.util.Hashtable; public class XMLObject { private Hashtable mFields = new Hashtable(); private int mN = -1; public int getN() { return mN; } public void setN(int n) { mN = n; } public String getStringField(String key) { return (String) mFields.get(key); } public void setStringField(String key, String value) { mFields.put(key, value); } public String getPID() { return getStringField("PID"); } public void setPID(String pid) { setStringField("PID", pid); } public String getDcCoverage() { return getStringField("dc.coverage"); } public void setDcCoverage(String dcCoverage) { setStringField("dc.coverage", dcCoverage); } public String getFgsOwnerId() { return getStringField("fgs.ownerId"); } public void setFgsOwnerId(String fgsOwnerId) { setStringField("fgs.ownerId", fgsOwnerId); } public String dccreator() { return getStringField("dc.creator"); } public void dccreator(String dccreator) { setStringField("dc.creator", dccreator); } public String getdcformat() { return getStringField("dc.format"); } public void setdcformat(String dcformat) { setStringField("dc.format", dcformat); } public String getdcidentifier() { return getStringField("dc.identifier"); } public void setdcidentifier(String dcidentifier) { setStringField("dc.identifier", dcidentifier); } public String getdclanguage() { return getStringField("dc.language"); } public void setdclanguage(String dclanguage) { setStringField("dc.language", dclanguage); } public String getdcpublisher() { return getStringField("dc.publisher"); } public void setdcpublisher(String dcpublisher) { setStringField("dc.publisher",dcpublisher); } public String getdcsubject() { return getStringField("dc.subject"); } public void setdcsubject(String dcsubject) { setStringField("dc.subject",dcsubject); } public String getdctitle() { return getStringField("dc.title"); } public void setdctitle(String dctitle) { setStringField("dc.title",dctitle); } public String getdctype() { return getStringField("dc.type"); } public void setdctype(String dctype) { setStringField("dc.type",dctype); } public String toString() { StringBuffer sb = new StringBuffer(); sb.append("N:"+mN+";"); Enumeration keys = mFields.keys(); while (keys.hasMoreElements()) { String key = (String) keys.nextElement(); sb.append(key+":"+mFields.get(key)+";"); } return sb.toString(); } } i used the same handler class you provided import java.io.*; import net.rim.device.api.system.Bitmap; import javax.xml.parsers.ParserConfigurationException; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import java.io.InputStream; import net.rim.device.api.ui.component.*; import net.rim.device.api.ui.container.MainScreen; import net.rim.device.api.xml.parsers.*; import org.w3c.dom.*; import org.xml.sax.*; import org.xml.sax.helpers.DefaultHandler; public class xmlparsermainscreen extends MainScreen{ private static String xmlres = "/xml/xml1.xml"; private RichTextField textOutputField; public xmlparsermainscreen() throws ParserConfigurationException, net.rim.device.api.xml.parsers.ParserConfigurationException, IOException { InputStream inputStream = getClass().getResourceAsStream(xmlres); ByteArrayOutputStream baos = new ByteArrayOutputStream(); byte[] buffer = new byte[10000]; int bytesRead = inputStream.read(buffer); while (bytesRead > 0) { baos.write(buffer, 0, bytesRead); bytesRead = inputStream.read(buffer); } baos.close(); String result=baos.toString(); ByteArrayInputStream bais = new ByteArrayInputStream(result.getBytes()); XMLObject[] xmlObjects = getXMLObjects(bais); for (int i = 0; i < xmlObjects.length; i++) { XMLObject o = xmlObjects[i]; textOutputField = new RichTextField(); add(textOutputField); textOutputField.setText(o.toString()); // add(new LabelField(o.toString())); } LabelField resultdis=new LabelField("resultdisplay"); add(resultdis); //textOutputField = new RichTextField(); //add(textOutputField); //textOutputField.setText(result); } static XMLObject[] getXMLObjects(InputStream is) throws ParserConfigurationException { XMLObjectHandler xmlObjectHandler = new XMLObjectHandler(); try { SAXParser parser = SAXParserFactory.newInstance() .newSAXParser(); parser.parse(is, xmlObjectHandler); } catch (ParserConfigurationException e) { e.printStackTrace(); } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xmlObjectHandler.getXMLObjects(); } } import java.io.IOException; import javax.xml.parsers.ParserConfigurationException; import net.rim.device.api.ui.UiApplication; public class xmlparser extends UiApplication { private xmlparser() throws ParserConfigurationException, net.rim.device.api.xml.parsers.ParserConfigurationException, IOException { pushScreen( new xmlparsermainscreen() ); } public static void main( String[] args ) throws ParserConfigurationException, net.rim.device.api.xml.parsers.ParserConfigurationException, IOException { new xmlparser().enterEventDispatcher(); } }

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