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  • Merge sort versus quick sort performance

    - by Giorgio
    I have implemented merge sort and quick sort using C (GCC 4.4.3 on Ubuntu 10.04 running on a 4 GB RAM laptop with an Intel DUO CPU at 2GHz) and I wanted to compare the performance of the two algorithms. The prototypes of the sorting functions are: void merge_sort(const char **lines, int start, int end); void quick_sort(const char **lines, int start, int end); i.e. both take an array of pointers to strings and sort the elements with index i : start <= i <= end. I have produced some files containing random strings with length on average 4.5 characters. The test files range from 100 lines to 10000000 lines. I was a bit surprised by the results because, even though I know that merge sort has complexity O(n log(n)) while quick sort is O(n^2), I have often read that on average quick sort should be as fast as merge sort. However, my results are the following. Up to 10000 strings, both algorithms perform equally well. For 10000 strings, both require about 0.007 seconds. For 100000 strings, merge sort is slightly faster with 0.095 s against 0.121 s. For 1000000 strings merge sort takes 1.287 s against 5.233 s of quick sort. For 5000000 strings merge sort takes 7.582 s against 118.240 s of quick sort. For 10000000 strings merge sort takes 16.305 s against 1202.918 s of quick sort. So my question is: are my results as expected, meaning that quick sort is comparable in speed to merge sort for small inputs but, as the size of the input data grows, the fact that its complexity is quadratic will become evident? Here is a sketch of what I did. In the merge sort implementation, the partitioning consists in calling merge sort recursively, i.e. merge_sort(lines, start, (start + end) / 2); merge_sort(lines, 1 + (start + end) / 2, end); Merging of the two sorted sub-array is performed by reading the data from the array lines and writing it to a global temporary array of pointers (this global array is allocate only once). After each merge the pointers are copied back to the original array. So the strings are stored once but I need twice as much memory for the pointers. For quick sort, the partition function chooses the last element of the array to sort as the pivot and scans the previous elements in one loop. After it has produced a partition of the type start ... {elements <= pivot} ... pivotIndex ... {elements > pivot} ... end it calls itself recursively: quick_sort(lines, start, pivotIndex - 1); quick_sort(lines, pivotIndex + 1, end); Note that this quick sort implementation sorts the array in-place and does not require additional memory, therefore it is more memory efficient than the merge sort implementation. So my question is: is there a better way to implement quick sort that is worthwhile trying out? If I improve the quick sort implementation and perform more tests on different data sets (computing the average of the running times on different data sets) can I expect a better performance of quick sort wrt merge sort? EDIT Thank you for your answers. My implementation is in-place and is based on the pseudo-code I have found on wikipedia in Section In-place version: function partition(array, 'left', 'right', 'pivotIndex') where I choose the last element in the range to be sorted as a pivot, i.e. pivotIndex := right. I have checked the code over and over again and it seems correct to me. In order to rule out the case that I am using the wrong implementation I have uploaded the source code on github (in case you would like to take a look at it). Your answers seem to suggest that I am using the wrong test data. I will look into it and try out different test data sets. I will report as soon as I have some results.

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  • How is counting sort a stable sort?

    - by eSKay
    Suppose my input is (a,b and c to distinguish between equal keys) 1 6a 8 3 6b 0 6c 4 My counting sort will save as (discarding the a,b and c info!!) 0(1) 1(1) 3(1) 4(1) 6(3) 8(1) which will give me the result 0 1 3 4 6 6 6 8 So, how is this stable sort? I am not sure how it is "maintaining the relative order of records with equal keys." Please explain.

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  • To (monkey)patch or not to (monkey)patch, that is the question

    - by gsakkis
    I was talking to a colleague about one rather unexpected/undesired behavior of some package we use. Although there is an easy fix (or at least workaround) on our end without any apparent side effect, he strongly suggested extending the relevant code by hard patching it and posting the patch upstream, hopefully to be accepted at some point in the future. In fact we maintain patches against specific versions of several packages that are applied automatically on each new build. The main argument is that this is the right thing to do, as opposed to an "ugly" workaround or a fragile monkey patch. On the other hand, I favor practicality over purity and my general rule of thumb is that "no patch" "monkey patch" "hard patch", at least for anything other than a (critical) bug fix. So I'm wondering if there is a consensus on when it's better to (hard) patch, monkey patch or just try to work around a third party package that doesn't do exactly what one would like. Does it have mainly to do with the reason for the patch (e.g. fixing a bug, modifying behavior, adding missing feature), the given package (size, complexity, maturity, developer responsiveness), something else or there are no general rules and one should decide on a case-by-case basis ?

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  • org-sort multi: date/time (?d ?t) | priority (?p) | title (?a)

    - by lawlist
    Is anyone aware of an org-sort function / modification that can refile / organize a group of TODO so that it sorts them by three (3) criteria: first sort by due date, second sort by priority, and third sort by by title of the task? EDIT: I believe that org-sort by deadline (?d) has a bug that cannot properly handle undated tasks. I am working on a workaround (i.e., moving the undated todo to a different heading before the deadline (?d) sort occurs), but perhaps the best thing to do would be to try and fix the original sorting function. Development of the workaround can be found in this thread (i.e., moving the undated tasks to a different heading in one fell swoop): How to automate org-refile for multiple todo EDIT: Apparently, the following code (ancient history) that I found on the internet was eventually modified and included as a part of org-sort-entries. Unfortunately, undated todo are not properly sorted when sorting by deadline -- i.e., they are mixed in with the dated todo. ;; multiple sort (defun org-sort-multi (&rest sort-types) "Multiple sorts on a certain level of an outline tree, or plain list items. SORT-TYPES is a list where each entry is either a character or a cons pair (BOOL . CHAR), where BOOL is whether or not to sort case-sensitively, and CHAR is one of the characters defined in `org-sort-entries-or-items'. Entries are applied in back to front order. Example: To sort first by TODO status, then by priority, then by date, then alphabetically (case-sensitive) use the following call: (org-sort-multi '(?d ?p ?t (t . ?a)))" (interactive) (dolist (x (nreverse sort-types)) (when (char-valid-p x) (setq x (cons nil x))) (condition-case nil (org-sort-entries (car x) (cdr x)) (error nil)))) ;; sort current level (defun lawlist-sort (&rest sort-types) "Sort the current org level. SORT-TYPES is a list where each entry is either a character or a cons pair (BOOL . CHAR), where BOOL is whether or not to sort case-sensitively, and CHAR is one of the characters defined in `org-sort-entries-or-items'. Entries are applied in back to front order. Defaults to \"?o ?p\" which is sorted by TODO status, then by priority" (interactive) (when (equal mode-name "Org") (let ((sort-types (or sort-types (if (or (org-entry-get nil "TODO") (org-entry-get nil "PRIORITY")) '(?d ?t ?p) ;; date, time, priority '((nil . ?a)))))) (save-excursion (outline-up-heading 1) (let ((start (point)) end) (while (and (not (bobp)) (not (eobp)) (<= (point) start)) (condition-case nil (outline-forward-same-level 1) (error (outline-up-heading 1)))) (unless (> (point) start) (goto-char (point-max))) (setq end (point)) (goto-char start) (apply 'org-sort-multi sort-types) (goto-char end) (when (eobp) (forward-line -1)) (when (looking-at "^\\s-*$") ;; (delete-line) ) (goto-char start) ;; (dotimes (x ) (org-cycle)) ))))) EDIT: Here is a more modern version of multi-sort, which is likely based upon further development of the above-code: (defun org-sort-all () (interactive) (save-excursion (goto-char (point-min)) (while (re-search-forward "^\* " nil t) (goto-char (match-beginning 0)) (condition-case err (progn (org-sort-entries t ?a) (org-sort-entries t ?p) (org-sort-entries t ?o) (forward-line)) (error nil))) (goto-char (point-min)) (while (re-search-forward "\* PROJECT " nil t) (goto-char (line-beginning-position)) (ignore-errors (org-sort-entries t ?a) (org-sort-entries t ?p) (org-sort-entries t ?o)) (forward-line)))) EDIT: The best option will be to fix sorting of deadlines (?d) so that undated todo are moved to the bottom of the outline, instead of mixed in with the dated todo. Here is an excerpt from the current org.el included within Emacs Trunk (as of July 1, 2013): (defun org-sort (with-case) "Call `org-sort-entries', `org-table-sort-lines' or `org-sort-list'. Optional argument WITH-CASE means sort case-sensitively." (interactive "P") (cond ((org-at-table-p) (org-call-with-arg 'org-table-sort-lines with-case)) ((org-at-item-p) (org-call-with-arg 'org-sort-list with-case)) (t (org-call-with-arg 'org-sort-entries with-case)))) (defun org-sort-remove-invisible (s) (remove-text-properties 0 (length s) org-rm-props s) (while (string-match org-bracket-link-regexp s) (setq s (replace-match (if (match-end 2) (match-string 3 s) (match-string 1 s)) t t s))) s) (defvar org-priority-regexp) ; defined later in the file (defvar org-after-sorting-entries-or-items-hook nil "Hook that is run after a bunch of entries or items have been sorted. When children are sorted, the cursor is in the parent line when this hook gets called. When a region or a plain list is sorted, the cursor will be in the first entry of the sorted region/list.") (defun org-sort-entries (&optional with-case sorting-type getkey-func compare-func property) "Sort entries on a certain level of an outline tree. If there is an active region, the entries in the region are sorted. Else, if the cursor is before the first entry, sort the top-level items. Else, the children of the entry at point are sorted. Sorting can be alphabetically, numerically, by date/time as given by a time stamp, by a property or by priority. The command prompts for the sorting type unless it has been given to the function through the SORTING-TYPE argument, which needs to be a character, \(?n ?N ?a ?A ?t ?T ?s ?S ?d ?D ?p ?P ?o ?O ?r ?R ?f ?F). Here is the precise meaning of each character: n Numerically, by converting the beginning of the entry/item to a number. a Alphabetically, ignoring the TODO keyword and the priority, if any. o By order of TODO keywords. t By date/time, either the first active time stamp in the entry, or, if none exist, by the first inactive one. s By the scheduled date/time. d By deadline date/time. c By creation time, which is assumed to be the first inactive time stamp at the beginning of a line. p By priority according to the cookie. r By the value of a property. Capital letters will reverse the sort order. If the SORTING-TYPE is ?f or ?F, then GETKEY-FUNC specifies a function to be called with point at the beginning of the record. It must return either a string or a number that should serve as the sorting key for that record. Comparing entries ignores case by default. However, with an optional argument WITH-CASE, the sorting considers case as well." (interactive "P") (let ((case-func (if with-case 'identity 'downcase)) (cmstr ;; The clock marker is lost when using `sort-subr', let's ;; store the clocking string. (when (equal (marker-buffer org-clock-marker) (current-buffer)) (save-excursion (goto-char org-clock-marker) (looking-back "^.*") (match-string-no-properties 0)))) start beg end stars re re2 txt what tmp) ;; Find beginning and end of region to sort (cond ((org-region-active-p) ;; we will sort the region (setq end (region-end) what "region") (goto-char (region-beginning)) (if (not (org-at-heading-p)) (outline-next-heading)) (setq start (point))) ((or (org-at-heading-p) (condition-case nil (progn (org-back-to-heading) t) (error nil))) ;; we will sort the children of the current headline (org-back-to-heading) (setq start (point) end (progn (org-end-of-subtree t t) (or (bolp) (insert "\n")) (org-back-over-empty-lines) (point)) what "children") (goto-char start) (show-subtree) (outline-next-heading)) (t ;; we will sort the top-level entries in this file (goto-char (point-min)) (or (org-at-heading-p) (outline-next-heading)) (setq start (point)) (goto-char (point-max)) (beginning-of-line 1) (when (looking-at ".*?\\S-") ;; File ends in a non-white line (end-of-line 1) (insert "\n")) (setq end (point-max)) (setq what "top-level") (goto-char start) (show-all))) (setq beg (point)) (if (>= beg end) (error "Nothing to sort")) (looking-at "\\(\\*+\\)") (setq stars (match-string 1) re (concat "^" (regexp-quote stars) " +") re2 (concat "^" (regexp-quote (substring stars 0 -1)) "[ \t\n]") txt (buffer-substring beg end)) (if (not (equal (substring txt -1) "\n")) (setq txt (concat txt "\n"))) (if (and (not (equal stars "*")) (string-match re2 txt)) (error "Region to sort contains a level above the first entry")) (unless sorting-type (message "Sort %s: [a]lpha [n]umeric [p]riority p[r]operty todo[o]rder [f]unc [t]ime [s]cheduled [d]eadline [c]reated A/N/P/R/O/F/T/S/D/C means reversed:" what) (setq sorting-type (read-char-exclusive)) (and (= (downcase sorting-type) ?f) (setq getkey-func (org-icompleting-read "Sort using function: " obarray 'fboundp t nil nil)) (setq getkey-func (intern getkey-func))) (and (= (downcase sorting-type) ?r) (setq property (org-icompleting-read "Property: " (mapcar 'list (org-buffer-property-keys t)) nil t)))) (message "Sorting entries...") (save-restriction (narrow-to-region start end) (let ((dcst (downcase sorting-type)) (case-fold-search nil) (now (current-time))) (sort-subr (/= dcst sorting-type) ;; This function moves to the beginning character of the "record" to ;; be sorted. (lambda nil (if (re-search-forward re nil t) (goto-char (match-beginning 0)) (goto-char (point-max)))) ;; This function moves to the last character of the "record" being ;; sorted. (lambda nil (save-match-data (condition-case nil (outline-forward-same-level 1) (error (goto-char (point-max)))))) ;; This function returns the value that gets sorted against. (lambda nil (cond ((= dcst ?n) (if (looking-at org-complex-heading-regexp) (string-to-number (match-string 4)) nil)) ((= dcst ?a) (if (looking-at org-complex-heading-regexp) (funcall case-func (match-string 4)) nil)) ((= dcst ?t) (let ((end (save-excursion (outline-next-heading) (point)))) (if (or (re-search-forward org-ts-regexp end t) (re-search-forward org-ts-regexp-both end t)) (org-time-string-to-seconds (match-string 0)) (org-float-time now)))) ((= dcst ?c) (let ((end (save-excursion (outline-next-heading) (point)))) (if (re-search-forward (concat "^[ \t]*\\[" org-ts-regexp1 "\\]") end t) (org-time-string-to-seconds (match-string 0)) (org-float-time now)))) ((= dcst ?s) (let ((end (save-excursion (outline-next-heading) (point)))) (if (re-search-forward org-scheduled-time-regexp end t) (org-time-string-to-seconds (match-string 1)) (org-float-time now)))) ((= dcst ?d) (let ((end (save-excursion (outline-next-heading) (point)))) (if (re-search-forward org-deadline-time-regexp end t) (org-time-string-to-seconds (match-string 1)) (org-float-time now)))) ((= dcst ?p) (if (re-search-forward org-priority-regexp (point-at-eol) t) (string-to-char (match-string 2)) org-default-priority)) ((= dcst ?r) (or (org-entry-get nil property) "")) ((= dcst ?o) (if (looking-at org-complex-heading-regexp) (- 9999 (length (member (match-string 2) org-todo-keywords-1))))) ((= dcst ?f) (if getkey-func (progn (setq tmp (funcall getkey-func)) (if (stringp tmp) (setq tmp (funcall case-func tmp))) tmp) (error "Invalid key function `%s'" getkey-func))) (t (error "Invalid sorting type `%c'" sorting-type)))) nil (cond ((= dcst ?a) 'string<) ((= dcst ?f) compare-func) ((member dcst '(?p ?t ?s ?d ?c)) '<))))) (run-hooks 'org-after-sorting-entries-or-items-hook) ;; Reset the clock marker if needed (when cmstr (save-excursion (goto-char start) (search-forward cmstr nil t) (move-marker org-clock-marker (point)))) (message "Sorting entries...done"))) (defun org-do-sort (table what &optional with-case sorting-type) "Sort TABLE of WHAT according to SORTING-TYPE. The user will be prompted for the SORTING-TYPE if the call to this function does not specify it. WHAT is only for the prompt, to indicate what is being sorted. The sorting key will be extracted from the car of the elements of the table. If WITH-CASE is non-nil, the sorting will be case-sensitive." (unless sorting-type (message "Sort %s: [a]lphabetic, [n]umeric, [t]ime. A/N/T means reversed:" what) (setq sorting-type (read-char-exclusive))) (let ((dcst (downcase sorting-type)) extractfun comparefun) ;; Define the appropriate functions (cond ((= dcst ?n) (setq extractfun 'string-to-number comparefun (if (= dcst sorting-type) '< '>))) ((= dcst ?a) (setq extractfun (if with-case (lambda(x) (org-sort-remove-invisible x)) (lambda(x) (downcase (org-sort-remove-invisible x)))) comparefun (if (= dcst sorting-type) 'string< (lambda (a b) (and (not (string< a b)) (not (string= a b))))))) ((= dcst ?t) (setq extractfun (lambda (x) (if (or (string-match org-ts-regexp x) (string-match org-ts-regexp-both x)) (org-float-time (org-time-string-to-time (match-string 0 x))) 0)) comparefun (if (= dcst sorting-type) '< '>))) (t (error "Invalid sorting type `%c'" sorting-type))) (sort (mapcar (lambda (x) (cons (funcall extractfun (car x)) (cdr x))) table) (lambda (a b) (funcall comparefun (car a) (car b))))))

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  • Monkey Hunter algorithm - Interview question [closed]

    - by Estefany Velez
    Question asked in an Interview: You are a hunter in the forest. A monkey is in the trees, but you don't know where and you can't see it. You can shoot at the trees, you have unlimited ammunition. Immediately after you shoot at a tree, if the monkey was in the tree, he falls and you win. If the monkey was not in the tree, he jumps (randomly) to an adjacent tree (he has to). Find an algorithm to get the monkey in the fewest shots possible. SOLUTION: The correct answer according to me was in the comments, credit to @rtperson: You could eliminate this possibility by shooting each tree twice as you sweep left, giving you a worst case of O(2n). EDIT: ...that is, a worst case of O(2n-1). You don't need to shoot the last tree twice.

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  • Java Alphabetize Algorithm Insertion sort vs Bubble Sort

    - by Chris Okyen
    I am supposed to "Develop a program that alphabetizes three strings. The program should allow the user to enter the three strings, and then display the strings in alphabetical order." It's instructed that I need to use the String library compareTo()/charAt()/toLowerCase() to make all the characters lowercase so the Lexicon comparison is also a alphabetical comparison. Input Pseudo Code: String input[3]; Scanner keyboard = new Scanner(System.in); System.out.println("Enter three strings: "); for(byte i = 0; i < 3; i++) input[i] = keyboard.next() The sorting would be Insertion Sort: 321 2 3 1 2 31 231 1 23 1 2 3 1 23 1 23 123 Bubble Sort 321 231 213 123 Which would be more efficient in this case? The bubble sort seems to be more efficient though they seem to have equal stats for worst best and avg case, but I read the Insertion Sort is quicker for small amounts of data like my case.

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  • Sort list using stl sort function

    - by Vlad
    I'm trying to sort a list (part of a class) in descending containg items of a struct but it doesn't compile(error: no match for 'operator-' in '__last - __first'): sort(Result.poly.begin(), Result.poly.end(), SortDescending()); And here's SortDescending: struct SortDescending { bool operator()(const term& t1, const term& t2) { return t2.pow < t1.pow; } }; Can anyone tell me what's wrong? Thanks!

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  • Using selection sort in java to sort floats

    - by user334046
    Hey, I need to sort an array list of class house by a float field in a certain range. This is my code for the selection sort: public ArrayList<House> sortPrice(ArrayList<House> x,float y, float z){ ArrayList<House> xcopy = new ArrayList<House>(); for(int i = 0; i<x.size(); i++){ if(x.get(i).myPriceIsLessThanOrEqualTo(z) && x.get(i).myPriceIsGreaterThanOrEqualTo(y)){ xcopy.add(x.get(i)); } } ArrayList<House> price= new ArrayList<House>(); while(xcopy.size()>0){ House min = xcopy.get(0); for(int i = 1; i < xcopy.size();i++){ House current = xcopy.get(i); if (current.myPriceIsGreaterThanOrEqualTo(min.getPrice())){ min = current; } } price.add(min); xcopy.remove(min); } return price; } Here is what the house class looks like: public class House { private int numBedRs; private int sqft; private float numBathRs; private float price; private static int idNumOfMostRecentHouse = 0; private int id; public House(int bed,int ft, float bath, float price){ sqft = ft; numBathRs = bath; numBedRs = bed; this.price = price; idNumOfMostRecentHouse++; id = idNumOfMostRecentHouse; } public boolean myPriceIsLessThanOrEqualTo(float y){ if(Math.abs(price - y)<0.000001){ return true; } return false; } public boolean myPriceIsGreaterThanOrEqualTo(float b){ if(Math.abs(b-price)>0.0000001){ return true; } return false; } When i call looking for houses in range 260000.50 to 300000 I only get houses that are at the top of the range even though I have a lower value at 270000. Can someone help?

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  • Media Monkey music management alternative?

    - by DeoxNa
    Media Monkey has some great and simple music management tools, like batch renaming, moving, fetching metadata, etc. I use Picard for some music organization, but it doesn't have as many options, namely that it will only automatically rename music it finds in its database and I have a lot of classical music which isn't in any data base or is already named how I want it (in their filenames) and I want to write the correct metadata and organize these files into folders. So is there other music management applications in linux other than Picard with a similar feature set to Media Monkey?

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  • New .NET Library for Accessing the Survey Monkey API

    - by Ben Emmett
    I’ve used Survey Monkey’s API for a while, and though it’s pretty powerful, there’s a lot of boilerplate each time it’s used in a new project, and the json it returns needs a bunch of processing to be able to use the raw information. So I’ve finally got around to releasing a .NET library you can use to consume the API more easily. The main advantages are: Only ever deal with strongly-typed .NET objects, making everything much more robust and a lot faster to get going Automatically handles things like rate-limiting and paging through results Uses combinations of endpoints to get all relevant data for you, and processes raw response data to map responses to questions To start, either install it using NuGet with PM> Install-Package SurveyMonkeyApi (easier option), or grab the source from https://github.com/bcemmett/SurveyMonkeyApi if you prefer to build it yourself. You’ll also need to have signed up for a developer account with Survey Monkey, and have both your API key and an OAuth token. A simple usage would be something like: string apiKey = "KEY"; string token = "TOKEN"; var sm = new SurveyMonkeyApi(apiKey, token); List<Survey> surveys = sm.GetSurveyList(); The surveys object is now a list of surveys with all the information available from the /surveys/get_survey_list API endpoint, including the title, id, date it was created and last modified, language, number of questions / responses, and relevant urls. If there are more than 1000 surveys in your account, the library pages through the results for you, making multiple requests to get a complete list of surveys. All the filtering available in the API can be controlled using .NET objects. For example you might only want surveys created in the last year and containing “pineapple” in the title: var settings = new GetSurveyListSettings { Title = "pineapple", StartDate = DateTime.Now.AddYears(-1) }; List<Survey> surveys = sm.GetSurveyList(settings); By default, whenever optional fields can be requested with a response, they will all be fetched for you. You can change this behaviour if for some reason you explicitly don’t want the information, using var settings = new GetSurveyListSettings { OptionalData = new GetSurveyListSettingsOptionalData { DateCreated = false, AnalysisUrl = false } }; Survey Monkey’s 7 read-only endpoints are supported, and the other 4 which make modifications to data might be supported in the future. The endpoints are: Endpoint Method Object returned /surveys/get_survey_list GetSurveyList() List<Survey> /surveys/get_survey_details GetSurveyDetails() Survey /surveys/get_collector_list GetCollectorList() List<Collector> /surveys/get_respondent_list GetRespondentList() List<Respondent> /surveys/get_responses GetResponses() List<Response> /surveys/get_response_counts GetResponseCounts() Collector /user/get_user_details GetUserDetails() UserDetails /batch/create_flow Not supported Not supported /batch/send_flow Not supported Not supported /templates/get_template_list Not supported Not supported /collectors/create_collector Not supported Not supported The hierarchy of objects the library can return is Survey List<Page> List<Question> QuestionType List<Answer> List<Item> List<Collector> List<Response> Respondent List<ResponseQuestion> List<ResponseAnswer> Each of these classes has properties which map directly to the names of properties returned by the API itself (though using PascalCasing which is more natural for .NET, rather than the snake_casing used by SurveyMonkey). For most users, Survey Monkey imposes a rate limit of 2 requests per second, so by default the library leaves at least 500ms between requests. You can request higher limits from them, so if you want to change the delay between requests just use a different constructor: var sm = new SurveyMonkeyApi(apiKey, token, 200); //200ms delay = 5 reqs per sec There’s a separate cap of 1000 requests per day for each API key, which the library doesn’t currently enforce, so if you think you’ll be in danger of exceeding that you’ll need to handle it yourself for now.  To help, you can see how many requests the current instance of the SurveyMonkeyApi object has made by reading its RequestsMade property. If the library encounters any errors, including communicating with the API, it will throw a SurveyMonkeyException, so be sure to handle that sensibly any time you use it to make calls. Finally, if you have a survey (or list of surveys) obtained using GetSurveyList(), the library can automatically fill in all available information using sm.FillMissingSurveyInformation(surveys); For each survey in the list, it uses the other endpoints to fill in the missing information about the survey’s question structure, respondents, and responses. This results in at least 5 API calls being made per survey, so be careful before passing it a large list. It also joins up the raw response information to the survey’s question structure, so that for each question in a respondent’s set of replies, you can access a ProcessedAnswer object. For example, a response to a dropdown question (from the /surveys/get_responses endpoint) might be represented in json as { "answers": [ { "row": "9384627365", } ], "question_id": "615487516" } Separately, the question’s structure (from the /surveys/get_survey_details endpoint) might have several possible answers, one of which might look like { "text": "Fourth item in dropdown list", "visible": true, "position": 4, "type": "row", "answer_id": "9384627365" } The library understands how this mapping works, and uses that to give you the following ProcessedAnswer object, which first describes the family and type of question, and secondly gives you the respondent’s answers as they relate to the question. Survey Monkey has many different question types, with 11 distinct data structures, each of which are supported by the library. If you have suggestions or spot any bugs, let me know in the comments, or even better submit a pull request .

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  • Oracle Social Network and the Flying Monkey Smart Target

    - by kellsey.ruppel
    Originally posted by Jake Kuramoto on The Apps Lab blog. I teased this before OpenWorld, and for those of you who didn’t make it to the show or didn’t come by the Office Hours to take the Oracle Social Network Technical Tour Noel (@noelportugal) ran, I give you the Flying Monkey Smart Target. In brief, Noel built a target, about two feet tall, which when struck, played monkey sounds and posted a comment to an Oracle Social Network Conversation, all controlled by a Raspberry Pi. He also connected a Dropcam to record the winner just prior to the strike. I’m not sure how it all works, but maybe Noel can post the technical specifics. Here’s Noel describing the Challenge, the Target and a few other tidbit in an interview with Friend of the ‘Lab, Bob Rhubart (@brhubart). The monkey target bits are 2:12-2:54 if you’re into brevity, but watch the whole thing. Here are some screen grabs from the Oracle Social Network Conversation, including the Conversation itself, where you can see all the strikes documented, the picture captured, and the annotation capabilities: #gallery-1 { margin: auto;? } #gallery-1 .gallery-item { float: left; margin-top: 10px; text-align: center; width: 33%; } #gallery-1 img { border: 2px solid #cfcfcf; } #gallery-1 .gallery-caption { margin-left: 0; }    That’s Diego in one shot, looking very focused, and Ernst in the other, who kindly annotated himself, two of the development team members. You might have seen them in the Oracle Social Network Hands-On Lab during the show. There’s a trend here. Not by accident, fun stuff like this has becoming our calling card, e.g. the Kscope 12 WebCenter Rock ‘em Sock ‘em Robots. Not only are these entertaining demonstrations, but they showcase what’s possible with RESTful APIs and get developers noodling on how easy it is to connect real objects to cloud services to fix pain points. I spoke to some great folks from the City of Atlanta about extending the concepts of the flying monkey target to physical asset monitoring. Just take an internet-connected camera with REST APIs like the Dropcam, wire it up to Oracle Social Netwok, and you can hack together a monitoring device for a datacenter or a warehouse. Sure, it’s easier said than done, but we’re a lot closer to that reality than we were even two years ago. Another noteworthy bit from Noel’s interview, beginning at 2:55, is the evolution of social developer. Speaking of, make sure to check out the Oracle Social Developer Community. Look for more on the social developer in the coming months. Noel has become quite the Raspberry Pi evangelist, and why not, it’s a great tool, a low-power Linux machine, cheap ($35!) and highly extensible, perfect for makers and students alike. He attended a meetup on Saturday before OpenWorld, and during the show, I heard him evangelizing the Pi and its capabilities to many people. There is some fantastic innovation forming in that ecosystem, much of it with Java. The OTN gang raffled off five Pis, and I expect to see lots of great stuff in the very near future. Stay tuned this week for posts on all our Challenge entrants. There’s some great innovation you won’t want to miss. Find the comments. Update: I forgot to mention that Noel used Twilio, one of his favorite services, during the show to send out Challenge updates and information to all the contestants.

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  • unexpected result from gnu sort

    - by funkycat
    when I try to sort the following text file 'input': test1 3 test3 2 test 4 with the command sort input the output is exactly the input. Here is the output of od -bc input : 0000000 164 145 163 164 061 011 063 012 164 145 163 164 063 011 062 012 t e s t 1 \t 3 \n t e s t 3 \t 2 \n 0000020 164 145 163 164 011 064 012 t e s t \t 4 \n 0000027 It's just a tab separated file with two columns. When I do sort -k 2 The output changes to test3 2 test1 3 test 4 which is what I would expect. But if I do sort -k 1 nothing changes with respect to the input, whereas I would expect 'test' to sort before 'test1'. Finally, if I do cat input | cut -f 1 | sort I get test test1 test3 as expected. Is there a logical explanation for this? What exactly is sort supposed to do by default, something like: sort -k 1 ? My version of sort: sort (GNU coreutils) 7.4

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  • How to UNIX sort by one column only?

    - by ssn
    I know that the -k option for the Unix sort allow us to sort by a specific column and all of the following. For instance, given the input file: 2 3 2 2 1 2 2 1 1 1 Using sort -n -k 1, I get an output sorted by the 1st column and then by the 2nd: 1 1 1 2 2 1 2 2 2 3 However, I want to keep the 2nd column ordering, like this: 1 2 1 1 2 3 2 2 2 1 Is this possible with the sort command?

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  • function to org-sort by three (3) criteria: due date / priority / title

    - by lawlist
    Is anyone aware of an org-sort function / modification that can refile / organize a group of TODO so that it sorts them by three (3) criteria: first sort by due date, second sort by priority, and third sort by by title of the task? EDIT: If anyone can please help me to modify this so that undated TODO are sorted last, that would be greatly appreciated -- at the present time, undated TODO are not being sorted: ;; multiple sort (defun org-sort-multi (&rest sort-types) "Multiple sorts on a certain level of an outline tree, or plain list items. SORT-TYPES is a list where each entry is either a character or a cons pair (BOOL . CHAR), where BOOL is whether or not to sort case-sensitively, and CHAR is one of the characters defined in `org-sort-entries-or-items'. Entries are applied in back to front order. Example: To sort first by TODO status, then by priority, then by date, then alphabetically (case-sensitive) use the following call: (org-sort-multi '(?d ?p ?t (t . ?a)))" (interactive) (dolist (x (nreverse sort-types)) (when (char-valid-p x) (setq x (cons nil x))) (condition-case nil (org-sort-entries (car x) (cdr x)) (error nil)))) ;; sort current level (defun lawlist-sort (&rest sort-types) "Sort the current org level. SORT-TYPES is a list where each entry is either a character or a cons pair (BOOL . CHAR), where BOOL is whether or not to sort case-sensitively, and CHAR is one of the characters defined in `org-sort-entries-or-items'. Entries are applied in back to front order. Defaults to \"?o ?p\" which is sorted by TODO status, then by priority" (interactive) (when (equal mode-name "Org") (let ((sort-types (or sort-types (if (or (org-entry-get nil "TODO") (org-entry-get nil "PRIORITY")) '(?d ?t ?p) ;; date, time, priority '((nil . ?a)))))) (save-excursion (outline-up-heading 1) (let ((start (point)) end) (while (and (not (bobp)) (not (eobp)) (<= (point) start)) (condition-case nil (outline-forward-same-level 1) (error (outline-up-heading 1)))) (unless (> (point) start) (goto-char (point-max))) (setq end (point)) (goto-char start) (apply 'org-sort-multi sort-types) (goto-char end) (when (eobp) (forward-line -1)) (when (looking-at "^\\s-*$") ;; (delete-line) ) (goto-char start) ;; (dotimes (x ) (org-cycle)) )))))

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  • New Web Comic: Code Monkey Kung Fu

    - by Dane Morgridge
    It’s been something I’ve wanted to do for quite some time and decided it was finally time. Yesterday, I launched a new web comic “Code Monkey Kung Fu”. After being a programer for more than ten years, I’ve come across quite a few hilarious situations and will be drawing on them for inspiration. I also have a four kids, so they will probably produce a lot as well. My plan is to release on Tuesdays with additional comics mixed in on occasion. I hope you enjoy! http://www.codemonkeykungfu.com

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  • Sort files in folders by size (Mac OS X)

    - by Željko Filipin
    I have a folder full of folders and files. I want to sort files by size (so I could remove the largest files). I know how to do that in Windows Explorer, but I can not find a way to do it in Mac OS X Finder. Windows 2003: open folder in Windows Explorer click button Search leave Search for files or folders named and Containing text text fields empty click button Search Now sort by size Is there a way to do something like this in Finder on Mac OS X?

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  • Are there any worse sorting algorithms than Bogosort (a.k.a Monkey Sort)?

    - by womp
    My co-workers took me back in time to my University days with a discussion of sorting algorithms this morning. We reminisced about our favorites like StupidSort, and one of us was sure we had seen a sort algorithm that was O(n!). That got me started looking around for the "worst" sorting algorithms I could find. We postulated that a completely random sort would be pretty bad (i.e. randomize the elements - is it in order? no? randomize again), and I looked around and found out that it's apparently called BogoSort, or Monkey Sort, or sometimes just Random Sort. Monkey Sort appears to have a worst case performance of O(∞), a best case performance of O(n), and an average performance of O(n * n!). Are there any named algorithms that have worse average performance than O(n * n!)? Or are just sillier than Monkey Sort in general?

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  • Merging and sorting multiple files with "sort"

    - by NewbiZ
    Hello, I have a bunch of text logfiles in the following format: ID (17 characters) Timestamp (14 characters YYYYmmddHHMMSS e.g. "20060210100040" -> 2006/02/10 10:00:40) Random data (? characters) end of line The files are already sorted by timestamp. I need to get 1 log file with all the logs from multiple logs files, sorted by timestamp. Note that the log files are really huge, around 3-4G each (and there are dozens of them) I tried the following command: sort -s -m -t '|' -k1n,1n +17 -o data_sort.txt *.TXT Here is how I ended up with this command: -s : don't bother with tie results -m : merge all logs files -t '|' : there is no | in my logs, so the whole line should be field 1 -k1n,1n: sort on the first field as a numeric value +17 : the timestamp starts at index 17 -o : output file Actually... it fails miserably. The output file data_sort.txt is just the concatenation of all files, not sorted at all :( I would greatly appreciate if anyone could provide any help on this problem! Thanks

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  • List.Sort in C#: comparer being called with null object

    - by cbp
    I am getting strange behaviour using the built-in C# List.Sort function with a custom comparer. For some reason it sometimes calls the comparer class's Compare method with a null object as one of the parameters. But if I check the list with the debugger there are no null objects in the collection. My comparer class looks like this: public class DelegateToComparer<T> : IComparer<T> { private readonly Func<T,T,int> _comparer; public int Compare(T x, T y) { return _comparer(x, y); } public DelegateToComparer(Func<T, T, int> comparer) { _comparer = comparer; } } This allows a delegate to be passed to the List.Sort method, like this: mylist.Sort(new DelegateToComparer<MyClass>( (x, y) => { return x.SomeProp.CompareTo(y.SomeProp); }); So the above delegate will throw a null reference exception for the x parameter, even though no elements of mylist are null. UPDATE: Yes I am absolutely sure that it is parameter x throwing the null reference exception! UPDATE: Instead of using the framework's List.Sort method, I tried a custom sort method (i.e. new BubbleSort().Sort(mylist)) and the problem went away. As I suspected, the List.Sort method passes null to the comparer for some reason.

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  • Template Sort In C++

    - by wdow88
    Hey all, I'm trying to write a sort function but am having trouble figuring out how to initialize a value, and making this function work as a generic template. The sort works by: Find a pair =(ii,jj)= with a minimum value = ii+jj = such at A[ii]A[jj] If such a pair exists, then swap A[ii] and A[jj] else break; The function I have written is as follows: template <typename T> void sort(T *A, int size) { T min =453; T temp=0; bool swapper = true; while(swapper) { swapper = false; int index1 = 0, index2 = 0; for (int ii = 0; ii < size-1; ii++){ for (int jj = ii + 1; jj < size; jj++){ if((min >= (A[ii]+A[jj])) && (A[ii] > A[jj])){ min = (A[ii]+A[jj]); index1 = ii; index2 = jj; swapper = true; } } } if (!swapper) return; else { temp = A[index1]; A[index1] = A[index2]; A[index2] = temp; sort(A,size); } } } This function will successfully sort an array of integers, but not an array of chars. I do not know how to properly initialize the min value for the start of the comparison. I tried initializing the value by simply adding the first two elements of the array together (min = A[0] + A[1]), but it looks to me like for this algorithm it will fail. I know this is sort of a strange type of sort, but it is practice for a test, so thanks for any input.

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  • How do I force folder view sort order to not ignore special characters?

    - by Jason Hartley
    I have many folders in my home directory that have names that begin with special characters such as _OLD_500GB_HD or !FolderIWantToSeeAtTheTop, but for some reason these folders are sorted according to their first alphanumeric character rather than the leading special character. So how can I force the folder to not ignore the special character, or how else can I make the sort view organize certain folders at the top or bottom of the sort? Thanks.

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  • How do I sort by human readable sizes numerically?

    - by UAdapter
    for example I have command that shows how much space folder takes du folder | sort -n it works great, however I would like to have human readable form du -h folder however if I do that than I cannot sort it as numeric. How to join du folder and du -h folder to see output sorted as du folder, but with first column from du -h folder P.S. this is just an example. this technique might be very useful for me (if its possible)

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