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  • Checking if an array contains all elements of another array

    - by mozcelikors
    I'm designing an electrical engineering application. However, i'm stuck on this: I have the following array <?php // Static Array $GroupOfEight = array ( array(0,1,3,2,4,5,7,6), array(4,5,6,7,16,12,13,14), array(12,13,15,14,8,9,11,10), array(2,6,14,10,3,7,15,11), array(1,3,5,7,13,15,9,11), array(0,4,12,8,1,5,13,9), array(0,1,3,2,8,9,11,10) ); ?> And I have another array, but this one is one dimensional. <?php $myStack = array(0,1,3,2,4,5,7,6); //Dynamic, gets value by POST method. ?> What I want to do is to check if $myStack is equal to any sub array of $GroupOfEight array. ( Number ordering is not important. The script should just check if every elements contained. It's not important if their order is same or not. ) Here is what I've done to solve the issue so far: <?php //Check if stackArray contains 8group for($i=0; $i<count($GroupOfEight);$i++) for($j=0; $j<count($GroupOfEight[$i]); $j++){ //$containsSearch = count(array_intersect($search_this,$all)) == count($search_this); $containsSearch = count(array_intersect($stackArray,$GroupOfEight[$j])) == count($stackArray); echo $containsSearch; } ?> Please help me correct my code or introduce me the solution of this issue, Thanks.

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