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  • Get to Know a Candidate (9 of 25): Gary Johnson–Libertarian Party

    - by Brian Lanham
    DISCLAIMER: This is not a post about “Romney” or “Obama”. This is not a post for whom I am voting. Information sourced for Wikipedia. Johnson served as the 29th Governor of New Mexico from 1995 to 2003, as a member of the Republican Party, and is known for his low-tax libertarian views and his strong emphasis on personal health and fitness. While a student at the University of New Mexico in 1974, Johnson sustained himself financially by working as a door-to-door handyman. In 1976 he founded Big J Enterprises, which grew from this one-person venture to become one of New Mexico's largest construction companies. He entered politics for the first time by running for Governor of New Mexico in 1994 on a fiscally conservative, low-tax, anti-crime platform. Johnson won the Republican Party of New Mexico's gubernatorial nomination, and defeated incumbent Democratic governor Bruce King by 50% to 40%. He cut the 10% annual growth in the budget: in part, due to his use of the gubernatorial veto 200 times during his first six months in office, which gained him the nickname "Governor Veto". Johnson sought re-election in 1998, winning by 55% to 45%. In his second term, he concentrated on the issue of school voucher reforms, as well as campaigning for marijuana decriminalization and opposition to the War on Drugs. During his tenure as governor, Johnson adhered to a stringent anti-tax and anti-bureaucracy policy driven by a cost–benefit analysis rationale, setting state and national records for his use of veto powers: more than the other 49 contemporary governors put together. Term-limited, Johnson could not run for re-election at the end of his second term. As a fitness enthusiast, Johnson has taken part in several Ironman Triathlons, and he climbed Mount Everest in May 2003. After leaving office, Johnson founded the non-profit Our America Initiative in 2009, a political advocacy committee seeking to promote policies such as free enterprise, foreign non-interventionism, limited government and privatization. The Libertarian Party is the third largest political party in the United States. It is also identified by many as the fastest growing political party in the United States. The political platform of the Libertarian Party reflects the ideas of libertarianism, favoring minimally regulated markets, a less powerful state, strong civil liberties (including support for Same-sex marriage and other LGBT rights), cannabis legalization and regulation, separation of church and state, open immigration, non-interventionism and neutrality in diplomatic relations (i.e., avoiding foreign military or economic entanglements with other nations), freedom of trade and travel to all foreign countries, and a more responsive and direct democracy. Members of the Libertarian Party have also supported the repeal of NAFTA, CAFTA, and similar trade agreements, as well as the United States' exit from the United Nations, WTO, and NATO. Although there is not an officially labeled political position of the party, it is considered by many to be more right-wing than the Democratic Party but more left-wing than the Republican Party when comparing the parties' positions to each other, placing it at or above the center. In the 30 states where voters can register by party, there are over 282,000 voters registered as Libertarians. Hundreds of Libertarian candidates have been elected or appointed to public office, and thousands have run for office under the Libertarian banner. The Libertarian Party has many firsts in its credit, such as being the first party to get an electoral vote for a woman in a United States presidential election. Learn more about Gary Johnson and Libertarian Party on Wikipedia.

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  • Congratulations Nick Colebourn - Microsoft Certified Master

    - by Christian
    Congratulations to Nick Colebourn who was brave enough to take his MCM lab exam in Seattle during PASS last month (at very short notice!) and is now a Microsoft Certified Master in SQL Server! Nick’s momentous achievement is especially exciting for us as he’s now the 5th member of our team to achieve Microsoft’s highest technical qualification for SQL Server – Coeo now has more SQL Server MCM’s than any other Microsoft customer or partner in the WORLD! Thank you Nick, and congratulations; it’s well deserved and we’re all very proud of you!   Christian Bolton - MCA, MCM, MVP Technical Director http://coeo.com - SQL Server Consulting & Managed Services You can read more about the Certified Master program on Microsoft’s website here: http://bit.ly/aOFLxm

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  • Is Nick Clegg a man or a mouse?

    - by BizTalk Visionary
    Well we got the hung election so many of us wanted! I believe it really is time for electoral change. Why? Consider: the ConMen under Cameroon have polled 36% of the great British voting public – well those that got to vote!! That means 64% of us don’t want him as PM. So what gives him the right to govern? Well an ancient voting system ideal for two party politics. But for the last 30 years we’ve had multi-party politics and going forward we may see 4 or 5 parties stepping up. We have to set in place a system that makes this work! So what does that mean today: Nick has a golden chance to push forward the case and in fact the absolute right for the change. He needs to keep this in mind when he discusses coalition with both Labour and the ConMen. So the mouse approach: Decides it is only fair to side with the ‘biggest’ vote and team up with the ConMen. Chances of electoral change? Big fat zero. Chance of achieving any of his other targets. Big fat zero. Why? Simple (as the Meer Kat would say). Cameroon needs to become PM by hook or crook. Once PM he holds the whip hand. Labour will dump Brown and head off into Leadership race land, Clegg will be knocking on number 10, having meaningless meetings and seeing no reward. Finally while Labour is at 6‘s and 7’s  the ‘new’ PM will call a new election, gain the majority they need and dump luckless Nick!! So the man approach: Team up with Labour. As one of the conditions – Brown to go. Run referendum for PR. Get PR through then force Labour to have new election under PR. Nick now hero and should be in a much better place following a PR election!! The man bit is standing up to the media attack for supporting Labour. Come Nick – be a man for a better Britain!!

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  • Is Nick Clegg a man or a mouse?

    - by BizTalk Visionary
    Well we got the hung election so many of us wanted! I believe it really is time for electoral change. Why? Consider: the ConMen under Cameroon have polled 36% of the great British voting public – well those that got to vote!! That means 64% of us don’t want him as PM. So what gives him the right to govern? Well an ancient voting system ideal for two party politics. But for the last 30 years we’ve had multi-party politics and going forward we may see 4 or 5 parties stepping up. We have to set in place a system that makes this work! So what does that mean today: Nick has a golden chance to push forward the case and in fact the absolute right for the change. He needs to keep this in mind when he discusses coalition with both Labour and the ConMen. So the mouse approach: Decides it is only fair to side with the ‘biggest’ vote and team up with the ConMen. Chances of electoral change? Big fat zero. Chance of achieving any of his other targets. Big fat zero. Why? Simple (as the Meer Kat would say). Cameroon needs to become PM by hook or crook. Once PM he holds the whip hand. Labour will dump Brown and head off into Leadership race land, Glegg will be knocking on number 10, having meaningless meetings and seeing no reward. Finally while Labour is at 6‘s and 7’s  the ‘new’ PM will call a new election, gain the majority they need and dump luckless Nick!! So the man approach: Team up with Labour. As one of the conditions – Brown to go. Run referendum for PR. Get PR through then force Labour to have new election under PR. Nick now hero and should be in a much better place following a PR election!! The man bit is standing up to the media attack for supporting Labour. Come Nick – be a man for a better Britain!!

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  • 50 Years of LEDs: An Interview with Inventor Nick Holonyak [Video]

    - by Jason Fitzpatrick
    The man who powered on the first LED half a century ago is still around to talk about it; read on to watch an interview with LED inventor Nick Holonyak. The most fascinating thing about Holonyak’s journey to the invention of the LED was that he started off trying to build a laser and ended up inventing a super efficient light source: Holonyak got his PhD in 1954. In 1957, after a year at Bell Labs and a two year stint in the Army, he joined GE’s research lab in Syracuse, New York. GE was already exploring semiconductor applications and building the forerunners of modern diodes called thyristors and rectifiers. At a GE lab in Schenectady, the scientist Robert Hall was trying to build the first diode laser. Hall, Holonyak and others noticed that semiconductors emit radiation, including visible light, when electricity flows through them. Holonyak and Hall were trying to “turn them on,” and channel, focus and multiply the light. Hall was the first to succeed. He built the world’s first semiconductor laser. Without it, there would be no CD and DVD players today. “Nobody knew how to turn the semiconductor into the laser,” Holonyak says. “We arrived at the answer before anyone else.” But Hall’s laser emitted only invisible, infrared light. Holonyak spent more time in his lab, testing, cutting and polishing his hand-made semiconducting alloys. In the fall of 1962, he got first light. “People thought that alloys were rough and turgid and lumpy,” he says. “We knew damn well what happened and that we had a very powerful way of converting electrical current directly into light. We had the ultimate lamp.” How To Get a Better Wireless Signal and Reduce Wireless Network Interference How To Troubleshoot Internet Connection Problems 7 Ways To Free Up Hard Disk Space On Windows

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  • Why isn't this driver install working (sudo code)?

    - by Nick
    I have a soundcard that I'd like to use and I've been trying to install it and being a new Ubuntu user, I get about half way through this in the Terminal and it stops cooperating with me... See the link (soundcard hyperlink) but basically what I have here: I do the following and it works: sudo apt-get install subversion svn co https://line6linux.svn.sourceforge.net/svnroot/line6linux Change to the directory cd line6linux/driver/trunk Time to build from the source but first make sure you have the latest build and headers sudo apt-get install build-essential sudo apt-get install linux-headers Then after this point it says must specify file to install. Not sure how to do this or what it means. Then, running make gives the following output: ./set_revision.sh ./set_revision.sh: 9: test: https://line6linux.svn.sourceforge.net/svnroot/line6linux/driver/trunk: unexpected operator make -C /lib/modules/3.2.0-29-generic-pae/build CONFIG_LINE6_USB=m SUBDIRS=/home/nick/line6linux/driver/trunk modules make[1]: Entering directory /usr/src/linux-headers-3.2.0-29-generic-pae' CC [M] /home/nick/line6linux/driver/trunk/audio.o /home/nick/line6linux/driver/trunk/audio.c: In function ‘line6_init_audio’: /home/nick/line6linux/driver/trunk/audio.c:30:57: error: ‘THIS_MODULE’ undeclared (first use in this function) /home/nick/line6linux/driver/trunk/audio.c:30:57: note: each undeclared identifier is reported only once for each function it appears in make[2]: * [/home/nick/line6linux/driver/trunk/audio.o] Error 1 make[1]: * [module/home/nick/line6linux/driver/trunk] Error 2 make[1]: Leaving directory/usr/src/linux-headers-3.2.0-29-generic-pae' make: * [default] Error 2 This is in Ubuntu 12.04.1 LTS Another thing, semi related. Cut, copy, paste? Seems like it's different from program to program. I was in the terminal and hit Ctrl-C and then Ctrl-Shift-V in Firefox and it won't paste. But in terminal it will paste. I'm confused. Here is what it's giving me after I hit "Make": nick@NickUbuntu:~/line6linux/driver/trunk$ make ./set_revision.sh ./set_revision.sh: 9: test: https://line6linux.svn.sourceforge.net/svnroot/line6linux/driver/trunk: unexpected operator make -C /lib/modules/3.2.0-29-generic-pae/build CONFIG_LINE6_USB=m SUBDIRS=/home/nick/line6linux/driver/trunk modules make[1]: Entering directory /usr/src/linux-headers-3.2.0-29-generic-pae' CC [M] /home/nick/line6linux/driver/trunk/audio.o /home/nick/line6linux/driver/trunk/audio.c: In function ‘line6_init_audio’: /home/nick/line6linux/driver/trunk/audio.c:30:57: error: ‘THIS_MODULE’ undeclared (first use in this function) /home/nick/line6linux/driver/trunk/audio.c:30:57: note: each undeclared identifier is reported only once for each function it appears in make[2]: *** [/home/nick/line6linux/driver/trunk/audio.o] Error 1 make[1]: *** [_module_/home/nick/line6linux/driver/trunk] Error 2 make[1]: Leaving directory/usr/src/linux-headers-3.2.0-29-generic-pae' make: * [default] Error 2 Looks like these folks also had similar problems: http://ubuntuforums.org/showthread.php?t=1163608&page=3

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  • Accessing the same service more than twice in the nick of time

    - by PointedC
    I have an application that will access interface service A which is to run from windows startup. This service is used by program B and my application functions on B's presence after getting a pointer to A. The scenario is translated as follows, public interface A{} ///my program public class MyProgram { public MyProgram() { ProgramB.DoA(); } public A GetA(){} } public class ProgramB { void DoA(){} } The translated source is not true, but that seems to be what I am looking for. In order to eliminate the overhead of allocating and realocating dynamic accesses to the same service used by other processes, would you please provide an actual solution to the problem ?(I am all out of any idea now)

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  • help in the Donalds B. Johnson's algorithm, i cannot understand the pseudo code (PART II)

    - by Pitelk
    Hi all , i cannot understand a certain part of the paper published by Donald Johnson about finding cycles (Circuits) in a graph. More specific i cannot understand what is the matrix Ak which is mentioned in the following line of the pseudo code : Ak:=adjacency structure of strong component K with least vertex in subgraph of G induced by {s,s+1,....n}; to make things worse some lines after is mentins " for i in Vk do " without declaring what the Vk is... As far i have understand we have the following: 1) in general, a strong component is a sub-graph of a graph, in which for every node of this sub-graph there is a path to any node of the sub-graph (in other words you can access any node of the sub-graph from any other node of the sub-graph) 2) a sub-graph induced by a list of nodes is a graph containing all these nodes plus all the edges connecting these nodes. in paper the mathematical definition is " F is a subgraph of G induced by W if W is subset of V and F = (W,{u,y)|u,y in W and (u,y) in E)}) where u,y are edges , E is the set of all the edges in the graph, W is a set of nodes. 3)in the code implementation the nodes are named by integer numbers 1 ... n. 4) I suspect that the Vk is the set of nodes of the strong component K. now to the question. Lets say we have a graph G= (V,E) with V = {1,2,3,4,5,6,7,8,9} which it can be divided into 3 strong components the SC1 = {1,4,7,8} SC2= {2,3,9} SC3 = {5,6} (and their edges) Can anybody give me an example for s =1, s= 2, s= 5 what if going to be the Vk and Ak according to the code? The pseudo code is in my previous question in http://stackoverflow.com/questions/2908575/help-in-the-donalds-b-johnsons-algorithm-i-cannot-understand-the-pseudo-code and the paper can be found at http://stackoverflow.com/questions/2908575/help-in-the-donalds-b-johnsons-algorithm-i-cannot-understand-the-pseudo-code thank you in advance

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  • help in the Donalds B. Johnson's algorithm, i cannot understand the pseudo code

    - by Pitelk
    Hi , does anyone know the Donald B. Johnson's algorithm which enumarates all the elementary circuits (cycles) in a Directed graph? link text I have the paper he had published in 1975 but I cannot understand the pseudo-code. My goal is to implement this algorithm in java. Some questions i have is for example what is the matrix Ak it refers to. In the pseudo code mentions that Ak:=adjacency structure of strong component K with least vertex in subgraph of G induced by {s,s+1,....n}; Does that mean i have to implement another algorithm that finds the Ak matrix? Another question is what the following means? begin logical f; Does also the line "logical procedure CIRCUIT (integer value v);" means that the circuit procedure returns a logical variable. In the pseudo code also has the line "CIRCUIT := f;" . Does this mean? It would be great if someone could translate this 1970's pseudocode to a more modern type of pseudo code so i can understand it in case you are interested to help but you cannot find the paper please email me at [email protected] and i will send you the paper. Thanks in advance

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  • How to get the Jabber ID for a Multi User Chat nick

    - by Kutzi
    I'm trying to get the Jabber ID for a nick in a multi user chat, but the following code returns only null: class JabberMUCMessageListenerAdapter implements PacketListener { private final MultiUserChat muc; public JabberMUCMessageListenerAdapter(MultiUserChat muc) { this.muc = muc; } @Override public void processPacket(Packet p) { if (p instanceof Message) { final Message msg = (Message) p; String jid = muc.getOccupant(msg.getFrom()).getJid(); // returns null ... } } } Does anyone know, what I'm doing wrong?

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  • storing and retrieving socket

    - by Trevor Newhook
    From what I can understand, once I create a socket, I can then create an array to store it with userArray[socket.nickname]=socket; I can then send a message to it with: io.sockets.socket(userArray[data.to]).emit('private message', tstamp(), socket.nickname, message); The basic logic is to store a copy of each socket in an object, identified by nickname. When I want to send a message to that socket, I use the copy of the socket, and send the message via io.sockets.socket(id).emit(). The entire server code is below: io.sockets.on('connection', function (socket) { socket.on('user message', function (msg) { socket.broadcast.emit('user message', tstamp(), socket.nickname, msg); updateLog('user message', socket.nickname, msg); }); socket.on('private message', function(data) { socket.get(data.nickname, function (err, name) { console.log('Chat message by ', name); }); updateLog('private message', socket.nickname, data.message); message=data.message; io.sockets.socket(userArray[data.to]).emit('private message', tstamp(), socket.nickname, message); }); socket.on('get log', function () { updateLog(); // Ensure old entries are cleared out before sending it. io.sockets.emit('chat log', log); }); socket.on('nickname', function (nick, fn) { var i = 1; var orignick = nick; while (nicknames[nick]) { nick = orignick+i; i++; } fn(nick); nicknames[nick] = socket.nickname = nick; userArray[socket.nickname]=socket; socket.set('nickname', nick, function () { socket.emit('ready'); }); socket.broadcast.emit('announcement', nick + ' connected'); // io.sockets.socket(userArray[nick]).emit('newID', 'Your name is: ' + nick, '. Your ID is: '+ userArray[nick]); io.sockets.emit('nicknames', nicknames); });

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  • VBA/SQL recordsets

    - by intruesiive
    The project I'm asking about is for sending an email to teachers asking what books they're using for the classes they're teaching next semester, so that the books can be ordered. I have a query that compares the course number of this upcoming semester's classes to the course numbers of historical textbook orders, pulling out only those classes that are being taught this semester. That's where I get lost. I have a table that contains the following: -Professor -Course Number -Year -Book -Title The data looks like this: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 12 1111 Pride and Prejudice smith 11 1222 Infinite Jest smith 10 1333 The Bible smith 13 1333 The Bible smith 12 1222 The Alchemist smith 10 1111 Moby Dick johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 10 1333 Everything is Illuminated johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time johnson 10 1333 Great Expectations johnson 9 1222 Proust on the Shore Here's what I need the code to do "on paper": Group the records by professor. Determine every unique course number in that group, and group records by course number. For each unique course number, determine the highest year associated. Then spit out every record with that professor+course number+year combination. With the sample data, the results would be: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 13 1333 The Bible johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time I'm thinking I should make a record set for each teacher, and within that, another record set for each course number. Within the course number record set, I need the system to determine what the highest year number is - maybe store that in a variable? Then pull out every associated record so that if the teacher ordered 3 books the last time they taught that class (whether it was in 2013 or 2012 and so on) all three books display. I'm not sure I'm thinking of record sets in the right way, though. My SQL so far is basic and clearly doesn't work: SELECT [All].Professor, [All].Course, Max([All].Year) FROM [All] GROUP BY [All].Professor, [All].Course; Thanks for your help.

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  • Linux Unable to Write to Directory Despite Permissions

    - by Nick Q.
    I'm trying to give myself permissions to /var/www/ however for some reason I am unable to do so. Currently what I'm facing is this: nick@server1:/var$ ls -l drwxrwxr-x 5 root wwwusers 232 Mar 15 19:31 www nick@server1:/var$ groups nick wwwusers nick@server1:/var$ mkdir www/trying mkdir: cannot create directory `www/trying': Permission denied I am running Ubuntu 10.04 LTS on a VPS and am used to running unix on my own machine so I may be doing something absolutely stupid, but I would like to be able to have the group wwwusers be able to write to www.

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  • Linux Unable to Write to Directory Despite Permissions

    - by Nick Q.
    I'm trying to give myself permissions to /var/www/ however for some reason I am unable to do so. Currently what I'm facing is this: nick@server1:/var$ ls -l drwxrwxr-x 5 root wwwusers 232 Mar 15 19:31 www nick@server1:/var$ groups nick wwwusers nick@server1:/var$ mkdir www/trying mkdir: cannot create directory `www/trying': Permission denied I am running Ubuntu 10.04 LTS on a VPS and am used to running unix on my own machine so I may be doing something absolutely stupid, but I would like to be able to have the group wwwusers be able to write to www.

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  • Still confused about JavaScript's 'this'.

    - by Nick Lowman
    I've been reading through quite a few articles on the 'this' keyword when using JavaScript objects and I'm still somewhat confused. I'm quite happy writing object orientated Javascript and I get around the 'this' issue by referring the full object path but I don't like the fact I still find 'this' confusing. I found a good answer here which helped me but I'm still not 100% sure. So, onto the example. The following script is linked from test.html with <script src="js/test.js"></script> if (!nick) { var nick = {}; } nick.lowman = function(){ var helloA = 'Hello A'; console.log('1.',this, this.helloA); var init = function(){ var helloB = 'Hello B'; console.log('2.',this, this.helloB); } return { init: init } }(); nick.lowman.init(); What kind of expected to see was 1. Object {} nick.lowman, 'Hello A' 2. Object {} init, 'Hello B' But what I get is this? 1. Window test.html, undefined 2. Object {} init, undefined I think I understand some of what's happening there but I would mind if someone out there explains it to me. Also, I'm not entirely sure why the first 'console.log' is being called at all? If I remove the call to the init function //nick.lowman.init() firebug still outputs 1. Window test.html, undefined. Why is that? Why does nick.lowman() get called by the window object when the html page loads? Many thanks

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  • Can the public ssh key from my local machine be used to access two different users on a remote serve

    - by Nick
    I have an new ubuntu (hardy 8.04) server, it has two users, User1 and User2. User1 is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/user1/.ssh/authorized_keys, changed the permissions on user1/.ssh/ to 700 and user1/.ssh/authorized_keys to 600 and both file and folder are owned my User1. Then added I User1 to sshd_config (AllowUsers User1). This works and I can login into User1 debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from ..*.* I then copied the authorized_keys file remote_server/home/user1/.ssh/authorized_keys to remote_server/home/user2/.shh/authorized_keys and changed the permissions and ownership and added User2 to AllowUsers in sshd_config (AllowUsers User1 User2). Now when I try to login to User2 it will not authenticate the same public key. debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works? Thanks in advance, Nick

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  • Active directory integration not working properly with winbind and samba

    - by tubaguy50035
    I'm trying to get my linux box to use active directory authentication. I believe I have almost everything setup correctly. I'm able to issue wbinfo -g and wbinfo -u and see all the groups and users respectively. Brief intro to my setup: The username I use on my linux box to do admin things is nick. My active directory username is nwalke. They have two different passwords. I am able to log in to the box with nick and that user's password and I'm also able to login as nwalke with nwalke's password. The curious bit: Upon creating the active directory user's home directory, I run a script that requires root access. This is to setup some system wide things like a samba share for them. When I log in as nwalke, I enter my nwalke password and it succeeds. I'm then greeted with [sudo] password for nick:. If I enter my nwalke password here, it says Sorry, try again.. If I enter nick's password, it says Sorry, user nick is not allowed to execute scriptname as root. If I do groups as nwalke, I see that magically my user has been given the group nick. Now, I accidentally thought that nick had a UID of 100, not 1000. So originally in my smb.conf I had idmap uid 1000-10000. The only thing I can think of, is that I logged in with nwalke while that was still set and now I'm just being presented with a UID of 1000 forcing linux to think I'm nick. I'm not really sure where to go from here. Like I said, I'm fairly certain active directory is communicating with my server properly, but something must not be mapped right on the linux side. Any thoughts? Here is my smb.conf: [global] security = ads netbios name = hostname realm = COMPANY.COM password server = adshost.company.com workgroup = COMPANY idmap uid = 10000-90000 idmap gid = 10000-90000 winbind separator = + winbind enum users = no winbind enum groups = no winbind use default domain = yes template homedir = /home/%D/%U template shell = /bin/bash client use spnego = yes domain master = no load printers = no printing = bsd printcap name = /dev/null disable spoolss = yes Let me know if more information about something is required.

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  • It is possible to record a data that have a straight row in mysql based on date or sequence?

    - by user1987816
    I want to get the data that have a straight Sell more than 3 times, it is possible in mysql? If not, how to get it right? I'm need it on mysql or php. my database:- +----------+---------------------+--------+ | Username | Date | Action | +----------+---------------------+--------+ | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Buy | | Adam | 2014-08-20 22:30:20 | Buy | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Buy | +----------+---------------------+--------+ From the table above, I need to list out all data that have a straight sell more then 3 times. RESULT +----------+---------------------+--------+-------------+ | Username | Date | Action | Straight 3+ | +----------+---------------------+--------+-------------+ | Adam | 2014-08-20 22:30:20 | Sell | 3 | | Adam | 2014-08-20 22:30:20 | Sell | 4 | | Nick | 2014-08-20 22:30:20 | Sell | 4 | +----------+---------------------+--------+-------------+

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  • How properly perform passing operation result to View

    - by atomAltera
    I'm developing web site on self made MVC engine. I have actionController that handles operations like register, login, post submit and etc. actionController receives operation name and parameters. Of course it mast handle errors such user with same nick already exists or password is to short about which action handler have to notify user. The question is which is the best way to organize errors, such that View could easily get localized user notification message. I see two ways First one: define error constants like ERR_NICK_BUSY = '1' ERR_NICK_INVALID = '2' ... and localization map local[ERR_NICK_BUSY] = 'User with the same nick already registered' local[ERR_NICK_INVALID ] = 'Nick, you entered is invalid' ... And second one: define abstract constants like ERR_FIELD_BUSY = '1' ERR_FIELD_INVALID = '2' ... and pass them with field name. In this case localization looks like local['nick_'+ERR_FIELD_BUSY] = 'User with the same nick already registered' ... I don't like both this methods. Can you advise something else?

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  • Using the public ssh key from local machine to access two remote users [closed]

    - by Nick
    I have an new Ubuntu (Hardy 8.04) server; it has two users, Alice and Bob. Alice is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/Alice/.ssh/authorized_keys, changed the permissions on Alice/.ssh/ to 700 and Alice/.ssh/authorized_keys to 600, and both the file and folder are owned my Alice. Then added I Alice to sshd_config (AllowUsers Alice). This works and I can login into Alice: ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 123.456.789.00 I then copied the authorized_keys file remote_server/home/Alice/.ssh/authorized_keys to remote_server/home/Bob/.shh/authorized_keys and changed the permissions and ownership and added Bob to AllowUsers in sshd_config (AllowUsers Alice Bob). Now when I try to login to Bob it will not authenticate the same public key. ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works?

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  • Can the same ssh key be used to access two different users on the same server?

    - by Nick
    I have an new ubuntu (hardy 8.04) server, it has two users, User1 and User2. User1 is listed in sudoers. I appended my public ssh key to authorized_keys in /home/user1/.ssh/authorized_keys, changed the permissions on user1/.ssh/ to 700 and user1/.ssh/authorized_keys to 600 and both file and folder are owned my User1. Then added I User1 to sshd_config (AllowUsers User1). This works and I can login into User1 debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 86.141.61.197 I then copied the authorized_keys file to /home/user2/.shh/ and changed the permissions and ownership and added User2 to AllowUsers in sshd_config (AllowUsers User1 User2). Now when I try to login to User2 it will not authenticate the same public key. debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works? Thanks in advance, Nick

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  • Postfix rewrite sender: why doesn't this work

    - by Nick Coleman
    I have server A with an IP address only and a dummy FQDN (on the basis all machines should have a FQDN): pants.net.invalid. All mail is relayed through another server elsewhere, which works fine. On server A, Postfix rewrites the sender address with smtp_generic_maps = hash:/etc/postfix/generic. According to the Rewrite manual at http://www.postfix.org/ADDRESS_REWRITING_README.html#remote, this should rewrite all outgoing external mail's Sender address: $ cat /etc/postfix/generic @pants.net.invalid [email protected] but it does not. postmap -q [email protected] returns nothing. This works: [email protected] [email protected] It seems as though it is doing regex matching even though I specify type hash:. Clearly I am misunderstanding the manual. I don't want to use regex or pcre expressions because there are only a couple of users (root and two others) and I don't want the overhead. I can specify the users exactly and it works. But, I would like to know what I am misunderstanding for future reference. Thanks.

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