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• Phonegap Screenshot plugin in Cordova 2.0.0

  - by ObjectiveJ

  I have set up the screenshot plugin from github, located here: https://github.com/phonegap/phonegap-plugins/tree/master/Android/Screenshot I set it up as instructed and with 1.8.1 of cordova. It worked and the screenshot was saved to the phone. However it fails with cordova 2.0.0. Screenshot.java code: https://github.com/phonegap/phonegap-plugins/blob/master/Android/Screenshot/src/org/apache/cordova/Screenshot.java Screenshot.js code: https://github.com/phonegap/phonegap-plugins/blob/master/Android/Screenshot/www/Screenshot.js Due to the advice of a very clever man called Simon MacDonald, I removed line 31 and 38 from the JS file shown above. However when I try to use the screenshot plugin with cordova 2.0.0 I receive these errors: ERROR: org.json.JSONException: Value undefined of type java.lang.String cannot be converted to JSONArray. Error: Status=8 Message=JSON error file:///android_asset/www/cordova-2.0.0.js: Line 938 : Error: Status=8 Message=JSON error Error: Status=8 Message=JSON error at file:///android_asset_/www/cordova-2.0.0.js:938 line 938 of the cordova.js is: // If error, then display error else { console.log("Error: Status="+v.status+" Message="+v.message); but im almost certain this is a compatibility error. Does anyone know a fix for this, or even a reason. Im abit lost. Any help is appreciated. I call the screenshot.js with this code: function takeScreenShot() { cordovaRef.exec("Screenshot.saveScreenshot"); } Any help massively appreciated.

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• Wordpress main website and mobile website duplicate content.

  - by ObjectiveJ

  Basically a client has asked for his WordPress website to be turned into a mobile website as well. I have never attempted this and know nothing about SEO. However the issue has arisen that this may cause duplicate content issues with Google, and therefore both sites may be dropped in the rankings. I was looking at turning the website into a mobile site via one of the available WordPress mobile website plugins. My question is if duplicate content will be an issue? Has anyone ever tried this? After doing some reading I kind of think it may be possible to tell Google not to index the mobile website, although as I understand it It would be the same set of files. So I am unsure that if I tell it not to index one of them, that it will drop the other one as well. Can anyone with WordPress and SEO knowledge clear this up for me?

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• Passing variables from PHP to Javascript back to PHP using Ajax.

  - by ObjectiveJ

  I hope this makes sesne, please bare with me. So I have a PHP page that contains variables, I have some radial boxes, and on click of them, it calculates a price for the item you have clicked on. I do this by activating a js function that I have passed some variables to. Like so. PHP: <?php $result = mssql_query("SELECT * FROM Segments ORDER BY 'Squares'"); if (!$result) { echo 'query failed'; exit; } while ($row = mssql_fetch_array($result)) { ?> <span><?php echo $row["Squares"]; ?></span><input name="squares" type="radio" onclick="ajaxCases('<?php echo $row["Squares"]; ?>', '<?php echo $row["StartCaseID"]; ?>', '<?php echo $row["StartMatrixPrice"]; ?>')" value="<?php echo $row["Squares"]; ?>"<?php if ($row["Squares"] == "1") { ?> checked="checked" <?php }else{ ?> checked="" <?php } ?>/> <?php } ?> As you can see onclick it goes to a function called ajaxcases, this function looks like this. function ajaxCases(squares,start,price){ $('#step1').html('<p style="margin:100px 0px 0px 100px"><img src="images/ajax-loader-bigindic.gif" width="32" height="32" alt="" /></p>'); $('#step1').load("ajax-styles.php?squares="+squares); prevId1 = ""; document.varsForm.caseid.value=start; $('#step1price').html('<span style="margin:0px 0px 0px 30px"><img src="images/ajax-loader-price.gif" width="24" height="24" alt="" /></span>'); $('#step1price').load("ajax-step1-price.php?Squares="+Squares); return true; } This then goes to a php page called ajax-step1-price.php and I try to recall the variable Squares. However it doesn't work, I thought it was a GET however that returns undefined. In Summary: I would like to know how to pass a variable from PHP to JS then back to PHP, or if someone could just tell me where I am going wrong that would be greatly appreciated.

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