Search Results

Search found 6392 results on 256 pages for 'bash history'.

Page 10/256 | < Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >

• Prevent URLs from specific domains from being saved in Firefox history

  - by noam

  I want to prevent or block URLs of specific domains from being saved or shown in my history. I want to be able to go to these certain websites normally, just not have them saved and not have to use private or incognito mode. For instance, I don't want any of Google's search result pages to be saved in my history since then when I use the awesomebar I get a lot of Google's search results, which are of no use to me. Of course I can keep on deleting them, but I would like a way to specify that any URL starting with www.google.com shouldn't be saved.

  Read the article

• remotely running find -exec options

  - by Michael Merchant

  I'm trying to setup a bash process for deploying my django project onto a linux server. Through cygwin, I'm running a script that is calling scp to copy my files over. Is there a similar command to delete *.pyc files. As of now, I've only been able to accomplish this locally after using ssh with: find . -name "*.pyc" -exec rm -rf {} \; I'm looking for some kind of command to call remotely that would be equivalent.

  Read the article

• How to prevent code/option injection in a bash script

  - by asmaier

  I have written a small bash script called "isinFile.sh" for checking if the first term given to the script can be found in the file "file.txt": #!/bin/bash FILE="file.txt" if [ `grep -w "$1" $FILE` ]; then echo "true" else echo "false" fi However, running the script like > ./isinFile.sh -x breaks the script, since -x is interpreted by grep as an option. So I improved my script #!/bin/bash FILE="file.txt" if [ `grep -w -- "$1" $FILE` ]; then echo "true" else echo "false" fi using -- as an argument to grep. Now running > ./isinFile.sh -x false works. But is using -- the correct and only way to prevent code/option injection in bash scripts? I have not seen it in the wild, only found it mentioned in ABASH: Finding Bugs in Bash Scripts.

  Read the article

• Editing history in bash

  - by nameanyone

  In bash, when I go back in history, edit some command and run it, this edited command is appended to history and the original one is left intact. But every once in a while I somehow manage to affect the original command, i.e. my edit replaces the original command back in history. I can't put my finger on how this happens. Can someone explain? My goal is to avoid this, so any edit to a previous command always gets appended to history and never replaces the original.

  Read the article

• Wrapper around bash, control STDIN and STDOUT

  - by blinry

  I would like to talk to a interactive bash process. Here is an example, so you know what I want to archieve: Program starts a new bash process. User types "ls" into my program. Program sends this command to the bash process. Program reads all available output of the bash (including the prompt) and displays it back to the user. GOTO 1 As you can guess, there is much room for nifty manipulations here and there... ;-) It would be wonderful if this also worked for subprocesses (started by the bash process) and curses-based programs. I would like to implement this functionality in Ruby, and already have experimented with IO.popen, but strange things happen. You are also welcome to do this in other languages.

  Read the article

• How to get bash to insert ' in the output

  - by ~danieljamesthomas

  Hi everybody, I'm rather new to bash, and somehow just haven't found out what I'm doing wrong here: (this is a small bash script calling my generator) if [ -n $folder ]; then $zorbalocation -q $generator -f -e files=\"$lFiles\" -e folder=\"lFolder\" else $zorbalocation -q $generator -f -e files=\"$lFiles\" -e folder=\".\" fi Now, obviously I want bash to execute these commands, depending on the content of folder. But, for some reason, bash insists on putting apostrophes ( ' ) around files=... and folder =... So, it tries to execute ../../../zorba/build/bin/zorba -q generator.xq -f -e 'files="test.xqlib"' -e 'folder="."' instead of ../../../zorba/build/bin/zorba -q generator.xq -f -e files="test.xqlib" -e folder="." Does anybody know why bash insists on inserting the apostrophes there? A nice day to everyone Danny

  Read the article

• Using bash shell from within PHP

  - by Dan

  Hi everyone, In my terminal window (using Max OS X) my shell is bash. However when I run a command in PHP via shell_exec or backtick operators I see that PHP is using the Bourne Shell (sh). Here's an example of what I'm seeing: From within my terminal window: $ echo $0 - bash Also if I call php as follows: $ php -r "echo shell_exec('echo $0');" -bash However, if I create a script called test.php with the following: <?php echo shell_exec('echo $0'); ?> And then run test php I get the following: $ php test.php sh I'm wanting to use the bash shell when calling shell_exec - why is it choosing the Bourne shell and can I force it to use bash? Thanks! Dan

  Read the article

• A command before every bash command

  - by jthoenes

  Does anyone know a mean of putting a 'time' command before every command in a bash session?

  Read the article

• A command before every bash command

  - by jthoenes

  Does anyone know a mean of putting a 'time' command before every command in a bash session?

  Read the article

• Bash on Snow Leopard doesn't obey terminal colours

  - by karbassi

  With the new version of Snow Leopard, OSX upgraded the bash version to GNU bash, version 3.2.48(1)-release (x86_64-apple-darwin10.0). Now, my .bashrc sets the following settings: # Colors export TERM=xterm-color export GREP_OPTIONS='--color=auto' GREP_COLOR='1;32' export CLICOLOR=1 export LSCOLORS=ExGxFxDxCxHxHxCbCeEbEb # Setup some colors to use later in interactive shell or scripts export COLOR_NC='\e[0m' # No Color export COLOR_WHITE='\e[1;37m' export COLOR_BLACK='\e[0;30m' export COLOR_BLUE='\e[0;34m' export COLOR_LIGHT_BLUE='\e[1;34m' export COLOR_GREEN='\e[0;32m' export COLOR_LIGHT_GREEN='\e[1;32m' export COLOR_CYAN='\e[0;36m' export COLOR_LIGHT_CYAN='\e[1;36m' export COLOR_RED='\e[0;31m' export COLOR_LIGHT_RED='\e[1;31m' export COLOR_PURPLE='\e[0;35m' export COLOR_LIGHT_PURPLE='\e[1;35m' export COLOR_BROWN='\e[0;33m' export COLOR_YELLOW='\e[1;33m' export COLOR_GRAY='\e[1;30m' export COLOR_LIGHT_GRAY='\e[0;37m' The colours are used later on for output. This used to work in previous version of OSX but not my output is as such: Some ideas that have not worked. Switching Terminal.app from 64-bit to 32-bit.

  Read the article

• Linux Bash Script, Single Command But Multiple Lines?

  - by Jay LaCroix

  I have the following script I wrote by searching Google, and it backs up my Linux system to an archive: #!/bin/bash # init DATE=$(date +20%y%m%d) tar -cvpzf /share/Recovery/Snapshots/$HOSTNAME_$DATE.tar.gz --exclude=/proc --exclude=/lost+found --exclude=/sys --exclude=/mnt --exclude=/media --exclude=/dev --exclude=/share/Archive / This works, but I am wondering if I can format the script to show the command over multiple lines, something like this, so it is easy to edit later: tar -cvpzf /share/Recovery/Snapshots/$HOSTNAME_$DATE.tar.gz --exclude=/proc --exclude=/lost+found --exclude=/sys --exclude=/mnt --exclude=/media --exclude=/dev --exclude=/share/Archive / That way it is easier to read and edit later. Is it possible to format a Bash script this way?

  Read the article

• Variable parsing with Bash and wget

  - by Bill Westrup

  I'm attempting to use wget in a simple bash script to grab a jpeg image from an Axis camera. This script outputs a file named JPEGOUT, instead of the desired output, which should be a timestamp jpeg (ex: 201209292040.jpg) . Changing the variable in the wget statement from JPEGOUT to $JPEGOUT makes wget fail with "wget: missing URL" error. The weird thing is wget parses the $IP vairable correctly. No luck on the output file name. I've tried single quotes, double quotes, parenthesis: all to no luck. Here's the script !/bin/bash IP=$1 JPEGOUT= date +%Y%m%d%H%M.jpg wget -O JPEGOUT http://$IP/axis-cgi/jpg/image.cgi?resolution=640x480&compression=25 Any ideas on how to get the output file name to parse correctly?

  Read the article

• bash completion with aliases

  - by dstarh

  I have a bunch of bash completion scripts set up (mostly using bash-it and some manually setup). I also have a bunch of aliases setup for common tasks like gco for git checkout. Right now I can type git checkout d tab and develop is completed for me but when I type gco d tab it does not complete. I'm assuming this is because the completion script is completing on git and it fails to see gco. Is there a way to generically/programmatically get all of my completion scripts to work with my aliases? Not being able to complete when using the alias kind of defeats the purpose of the alias.

  Read the article

• Why does bash invocation differ on AIX when using telnet vs ssh

  - by Philbert

  I am using an AIX 5.3 server with a .bashrc file set up to echo "Executing bashrc." When I log in to the server using ssh and run: bash -c ls I get: Executing bashrc . .. etc.... However, when I log in with telnet as the same user and run the same command I get: . .. etc.... Clearly in the telnet case, the .bashrc was not invoked. As near as I can tell this is the correct behaviour given that the shell is non-interactive in both cases (it is invoked with -c). However, the ssh case seems to be invoking the shell as interactive. It does not appear to be invoking the .profile, so it is not creating a login shell. I cannot see anything obviously different between the environments in the two cases. What could be causing the difference in bash behaviour?

  Read the article

• Bash Script Exits su or ssh Session Rather than Script

  - by Russ

  I am using CentOS 5.4. I created a bash script that does some checking before running any commands. If the check fails, it will simply exit 0. The problem I am having is that on our server, the script will exit the su or ssh session when the exit 0 is called. #!/bin/bash # check if directory has contents and exit if none if [ -z "`ls /ebs_raid/import/*.txt 2>/dev/null`" ]; then echo "ok" exit 0 fi here is the output: [root@ip-10-251-86-31 ebs_raid]# . test.sh ok [russ@ip-10-251-86-31 ebs_raid]$ as you can see, I was removed from my sudo session, if I wasn't in the sudo session, it would have logged me out of my ssh session. I am not sure what I am doing wrong here or where to start.

  Read the article

• Running SQL*Plus with bash causes wrong encoding

  - by Petr Mensik

  I have a problem with running SQL*Plus in the bash. Here is my code #!/bin/bash #curl http://192.168.168.165:8080/api_test/xsql/f_exp_order_1016.xsql > script.sql wget -O script.sql 192.168.168.165:8080/api_test/xsql/f_exp_order_1016.xsql set NLS_LANG=_.UTF8 sqlplus /nolog << ENDL connect login/password set sqlblanklines on start script.sql exit <<endl I download the insert statements from our intranet, put it into sql file and run it through SQL*Plus. This is working fine. My problem is that when I save the file script.sql my encoding goes wrong. All special characters(like íášc) are broken and that's causing inserting wrong characters into my DB. Encoding of that file is UTF-8, also UTF-8 is set on the XSQL page on our intranet. So I really don't know where could be a problem. And also any advices regarding to my script are welcomed, I am total newbie in Linux scripting:-)

  Read the article

• Bash Script to Back Up Backs Up Itself

  - by Jay LaCroix

  I have the following bash script that creates a tar.gz of my filesystem on a Kubuntu PC. The problem is, that it also tries to backup the tar.gz backup file, even though I am storing the backup in /tmp and omitting /tmp from the backup. I am wondering why it's backing up the file in /tmp even though I told it not to. #!/bin/bash # init DATE=$(date +20%y%m%d) sudo tar -cvpzf /tmp/`hostname`_$DATE.tar.gz \ --exclude=/proc \ --exclude=/lost+found \ --exclude=/sys \ --exclude=/mnt \ --exclude=/media \ --exclude=/dev \ --exclude=/tmp \ --exclude=/home/jlacroix/Desktop \ --exclude=/home/jlacroix/Documents \ --exclude=/home/jlacroix/Music \ --exclude=/home/jlacroix/Pictures \ --exclude=/home/jlacroix/Projects \ --exclude=/home/jlacroix/Roms \ --exclude=/home/jlacroix/Videos \ --exclude=/home/jlacroix/.VirtualBox\ VMs \ --exclude=/home/jlacroix/.SpiderOak \ / scp /tmp/`hostname`_$DATE.tar.gz jlacroix@Pluto:/share/Recovery/Snapshots sudo rm /tmp/`hostname`_$DATE.tar.gz

  Read the article

• bash completion processing gone bad, how to debug?

  - by msw

  It all started with a simple alias gv='gvim --remote-quiet' and now gv Space Tab gives nothing where it normally should give filenames. Oddly, alias gvi='gvim --remote-quiet' works as expected. I clearly have a workaround, but I'd like to know what is catching my gv for special processing. compopt is no help as gv shares the same settings as ls which does filename completion correctly. $compopt gv compopt +o bashdefault +o default +o dirnames -o filenames +o nospace +o plusdirs gv $ compopt ls compopt +o bashdefault +o default +o dirnames -o filenames +o nospace +o plusdirs ls The complete command is slightly more helpful but it doesn't tell me why my two characters got singled out for alteration: $ complete -p gv complete -o filenames -F _filedir_xspec gv $ complete -p ls complete -o filenames -F _longopt ls $ complete -p echo bash: complete: echo: no completion specification $ alias gvi='gvim --remote-silent' msw@tallguy:~/.gnupg$ complete -p gvi bash: complete: gvi: no completion specification Where did complete -o filenames -F _filedir_xpec gv come from?

  Read the article

• Why does bash invocation differ on AIX when using telnet vs ssh

  - by Philbert

  I am using an AIX 5.3 server with a .bashrc file set up to echo "Executing bashrc." When I log in to the server using ssh and run: bash -c ls I get: Executing bashrc . .. etc.... However, when I log in with telnet as the same user and run the same command I get: . .. etc.... Clearly in the telnet case, the .bashrc was not invoked. As near as I can tell this is the correct behaviour given that the shell is non-interactive in both cases (it is invoked with -c). However, the ssh case seems to be invoking the shell as interactive. It does not appear to be invoking the .profile, so it is not creating a login shell. I cannot see anything obviously different between the environments in the two cases. What could be causing the difference in bash behaviour?

  Read the article

• How to programmatically query bash completion for given string

  - by Ryan McKay

  I want to ask bash how it would complete a string as if I had typed it in a shell and hit tab. For example, if I type ls /[TAB][TAB] I see the list of files and dirs in / that could possibly complete the ls command. How do I ask bash how it would complete 'ls /' without typing it and hitting tab? I want something like: query_complete 'partial command line string' I read the man page for complete and compgen, but couldn't figure out how to do it with them. Note: 'ls /' is not the actual command I'm interested in, just an example. I am looking for a general solution for any arbitrary string representing a partial command line.

  Read the article

• Bash preexecute

  - by Alex_Bender

  I'm trying to write bash command wrapper, which will be patch bash current command on the fly. But i'm faced with the problem. As i'm not a good Shell user, i can't write right expression of variable assignment in string. See bellow: I'm set trap to preexecute, through this: alex@bender:~$ trap "caller >/dev/null || xxx \"\${BASH_COMMAND}"\" DEBUG; I want change variable BASH_COMMAND, do something like BASH_COMMAND=xxx ${BASH_COMMAND} but i don't know, how i need escaping variables in this string NOTE: xxx -- my custom function, which must return some value, if in end of command situated word teststr function xxx(){ # find by grep, if teststr in the end `echo "$1" | grep "teststr$" >/dev/null`; # if true ==> do if [ "$?" == "0" ]; then # cut last 6 chars (len('teststr')==6) var=`echo "$1" | sed 's/......$//'`; echo "$var"; fi } How can i do this stuff?: alex@bender:~$ trap "caller >/dev/null || ${BASH_COMMAND}=`xxx $BASH_COMMAND`" DEBUG;

  Read the article

• Bash: Variable substitution in variable name with default value

  - by krissi

  i have the following variables: # config file MYVAR_DEFAULT=123 MYVAR_FOO=456 #MYVAR_BAR unset # program USER_INPUT=FOO TARGET_VAR=<need to be set> If the USER_INPUT is "foo", I want TARGET_VAR to be the value of MYVAR_FOO (TARGET_VAR=456). If USER_INPUT is "bar" I want TARGET_VAR to be set to MYVAR_DEFAULT (123), because MYVAR_BAR is unset. I prefer it to be sh-compatible and as a substitution string. But it might also be bash compatible and/or in a function. I got these snippets: # Default values for variable (sh-compatible) echo ${MYVAR_FOO-$MYVAR_DEFAULT} # Uppercase (bash compatible) echo ${USER_INPUT^^} I would need something like this: TARGET_VAR="${MYVAR_${USER_INPUT^^}-$MYVAR_DEFAULT}" # or somecommand -foo "${MYVAR_${USER_INPUT^^}-$MYVAR_DEFAULT}" This is to switch a bunch of variables between multiple "profiles". In the example, FOO and BAR are profiles. New profiles should be added easily, in this example there would be an implicit profile named BAZ, too, all variables to their default values. Unfortunately it is not that easy. Do you have an idea to solve this? Thanks in advance, krissi

  Read the article

• help with bash script using find and diff command

  - by su

  Helloe, i have a bash script that i need help with: #!/bin/bash if [ -f "/suid.old" ] then find / -perm -4000 -o -perm -2000 ls > suid.old else find / -perm 4000 -o -perm -2000 ls > suid.new diff suid.old suid.new > newchanges.list fi when i run it it gives me an error saying: diff: suid.old: No such file or directory. My script should say, if suid.old does not exist, then use the find command to create one, or else use find command to do whatever it needs to with the suid.new. after find any changes it made and redirect it to newchanges.list please help,

  Read the article

• script not run after reboot from /etc/rc3.d

  - by yael

  I create symbolic link to the file - /etc/rc3.d/platform.bash from /var/tmp/platform.bash ln -s /var/tmp/platform.bash /etc/rc3.d/platform.bash script exist under /var/tmp : -rwxr-xr-x 1 root root 58442 Aug 30 08:49 platform.bash view from /etc/rc3.d : lrwxrwxrwx 1 root root 31 Aug 30 06:33 S99platform.bash -> /var/tmp/platform.bash my target is to run platform.bash after reboot ( on solaris 10 OS ) from some reason the script platform.bash not run after reboot ? please advice what I need to check in order to verify the problem ? my script ( platform.bash ) #!/bin/bash echo test > /var/tmp/log.txt

  Read the article

• Going to directory using bash variables doesn't work when directory names have spaces

  - by gsingh2011

  Let's say I want to store the following command in a variable cd "/cygdrive/c/Program Files/" So I do this dir="cd \"/cygdrive/c/Program Files/\"" That should store the command to navigate to the Program Files directory, so when I type $dir it takes me to that directory. To check that the quotations have been properly escaped, I type echo $dir which gives me cd "/cygdrive/c/Program Files/" So everything should be working fine. However, when I type, $dir I get bash: cd: "/cygdrive/c/Program: No such file or directory What am I doing wrong? I'm using Cygwin, but I assume this problem applies to bash in general.

  Read the article

< Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >