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  • Method binding to base method in external library can't handle new virtual methods "between"

    - by Berg
    Lets say I have a library, version 1.0.0, with the following contents: public class Class1 { public virtual void Test() { Console.WriteLine( "Library:Class1 - Test" ); Console.WriteLine( "" ); } } public class Class2 : Class1 { } and I reference this library in a console application with the following contents: class Program { static void Main( string[] args ) { var c3 = new Class3(); c3.Test(); Console.ReadKey(); } } public class Class3 : ClassLibrary1.Class2 { public override void Test() { Console.WriteLine("Console:Class3 - Test"); base.Test(); } } Running the program will output the following: Console:Class3 - Test Library:Class1 - Test If I build a new version of the library, version 2.0.0, looking like this: public class Class1 { public virtual void Test() { Console.WriteLine( "Library:Class1 - Test V2" ); Console.WriteLine( "" ); } } public class Class2 : Class1 { public override void Test() { Console.WriteLine("Library:Class2 - Test V2"); base.Test(); } } and copy this version to the bin folder containing my console program and run it, the results are: Console:Class3 - Test Library:Class1 - Test V2 I.e, the Class2.Test method is never executed, the base.Test call in Class3.Test seems to be bound to Class1.Test since Class2.Test didn't exist when the console program was compiled. This was very surprising to me and could be a big problem in situations where you deploy new versions of a library without recompiling applications. Does anyone else have experience with this? Are there any good solutions? This makes it tempting to add empty overrides that just calls base in case I need to add some code at that level in the future...

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  • I want to find the span tag beween the LI tag and its attributes but no luck.

    - by Mahesh
    I want to find the span tag beween the LI tag and its attributes. Trying with beautful soap but no luck. Details of my code. Is any one point me right methodlogy In this this code, my getId function should return me id = "0_False-2" Any one know right method? from BeautifulSoup import BeautifulSoup as bs import re html = '<ul>\ <li class="line">&nbsp;</li>\ <li class="folder-open-last" id="0">\ <img style="float: left;" class="trigger" src="/media/images/spacer.gif" border="0">\ <span class="text" id="0_False">NOC</span><ul style="display: block;"><li class="line">&nbsp;</li><li class="doc" id="1"><span class="active text" id="0_False-1">PNQAIPMS1</span></li><li class="line">&nbsp;</li><li class="doc-last" id="2"><span class="text" id="0_False-2">PNQAIPMS2</span></li><li class="line-last"></li></ul></li><li class="line-last"></li>\ </ul>' def getId(html, txt): soup = bs(html) soup.findAll('ul',recursive=False) head = soup.contents[0] temp = head elements = {} while True: # It temp is None that means no HTML tags are available if temp == None: break #print temp if re.search('li', str( temp)) != None: attr = str(temp.attrs).encode('ascii','ignore') attr = attr.replace(' ', '') attr = attr.replace('[', '') attr = attr.replace(']', '') attr = attr.replace(')', '') attr = attr.replace('(', '') attr = attr.replace('u\'', '') attr = attr.replace('\'', '') attr = attr.split(',') span = str(temp.text) if span == txt: return attr[3] temp = temp.next else: temp = temp.next id = getId(html,"PNQAIPMS2") print "ID = " + id

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  • How to prevent Hibernate from nullifying relationship column during entity removal

    - by Grzegorz
    I have two entities, A and B. I need to easily retrieve entities A, joined with entities B on the condition of equal values of some column (some column from A equal to some column in B). Those columns are not primary or foreign keys, they contain same business data. I just need to have access from each instance of A to the collection of B's with the same value of this column. So I model it like this: class A { @OneToMany @JoinColumn(name="column_in_B", referencedColumnName="column_in_A") Collection<B> bs; This way, I can run queries like "select A join fetch a.bs b where b...." (Actually, the real relationship here is many-to-many. But when I use @ManyToMany, Hibernate forces me to use join table, which doesnt exist here. So I have to use @OneToMany as workaround). So far so good. The main problem is: whenever I delete an instance of A, hibernate calls "Update B set column_in_B = null", becuase it thinks the column_in_B is foreign key pointing at primary key in A (and because row in A is deleted, it tries to clean the foreign key in B). BUT the column_in_B IS NOT a foreign key, and can't be modified, because it causes data lost (and this column is NOT NULL anyway in my case, causing data integerity exception to be thrown). Plese help me with this. How to model such relationships with Hibernate? (I would call it "virtual relationships", or "secondary relationships" or so: as they are not based on foreign keys, they are just some shortcuts which allows for retrieving related objects and quering for them with HQL)

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  • Read a variable from a variable cookie jquerycookie.

    - by Ozaki
    TLDR How could I tell "page.html" which one of 3 or so cookies to look at when the cookie is set on the previous page? Currently: When a link is clicked save text of link to cookie When "page.html" is loaded get the value of the cookie Loads the getjson call as per value of the cookie. E.g: <a href="page.html">link1</a> -c1 <a href="page.html">link2</a> -c2 <a href="page.html">link3</a> -c3 See previous discussion here Now that is all good and well apart from the fact if I were to say open them in multiple tabs. It changes the cookie and correctly loads the right data. But if I were to refresh one of these tabs it will load the most recently open data rather than what it should be. So if I were to save a cookie as c1 with a value of link1 c2 with a value of link2 c3 with a value of link3 How could I tell "page.html" which cookie it should be looking at, therefore not breaking the back/forward/refresh buttons on the browser when multiple tabs are open?

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  • GCC/X86, Problems with relative jumps

    - by Ian Kelly
    I'm trying to do a relative jump in x86 assembly, however I can not get it to work. It seems that for some reason my jump keeps getting rewritten as an absolute jump or something. A simple example program for what I'm trying to do is this: .global main main: jmp 0x4 ret Since the jmp instruction is 4 bytes long and a relative jump is offset from the address of the jump + 1, this should be a fancy no-op. However, compiling and running this code will cause a segmentation fault. The real puzzler for me is that compiling it to the object level and then disassembling the object file shows that it looks like the assembler is correctly doing a relative jump, but after the file gets compiled the linker is changing it into another type of jump. For example if the above code was in a file called asmtest.s: $gcc -c asmtest.s $objdump -D asmtest.o ... Some info from objdump 00000000 <main>: 0: e9 00 00 00 00 jmp 5 <main+0x5> 5: c3 ret This looks like the assembler correctly made a relative jump, although it's suspicious that the jmp instruction is filled with 0s. I then used gcc to link it then disassembled it and got this: $gcc -o asmtest asmtest.o $objdump -d asmtest ...Extra info and other disassembled functions 08048394 <main>: 8048394: e9 6b 7c fb f7 jmp 4 <_init-0x8048274> 8048399: c3 ret This to me looks like the linker rewrote the jmp statement, or substituted the 5 in for another address. So my question comes down to, what am I doing wrong? Am I specifying the offset incorrectly? Am I misunderstanding how relative jumps work? Is gcc trying to make sure I don't do dangerous things in my code?

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  • How does loop address alignment affect the speed on Intel x86_64?

    - by Alexander Gololobov
    I'm seeing 15% performance degradation of the same C++ code compiled to exactly same machine instructions but located on differently aligned addresses. When my tiny main loop starts at 0x415220 it's faster then when it is at 0x415250. I'm running this on Intel Core2 Duo. I use gcc 4.4.5 on x86_64 Ubuntu. Can anybody explain the cause of slowdown and how I can force gcc to optimally align the loop? Here is the disassembly for both cases with profiler annotation: 415220 576 12.56% |XXXXXXXXXXXXXX 48 c1 eb 08 shr $0x8,%rbx 415224 110 2.40% |XX 0f b6 c3 movzbl %bl,%eax 415227 0.00% | 41 0f b6 04 00 movzbl (%r8,%rax,1),%eax 41522c 40 0.87% | 48 8b 04 c1 mov (%rcx,%rax,8),%rax 415230 806 17.58% |XXXXXXXXXXXXXXXXXXX 4c 63 f8 movslq %eax,%r15 415233 186 4.06% |XXXX 48 c1 e8 20 shr $0x20,%rax 415237 102 2.22% |XX 4c 01 f9 add %r15,%rcx 41523a 414 9.03% |XXXXXXXXXX a8 0f test $0xf,%al 41523c 680 14.83% |XXXXXXXXXXXXXXXX 74 45 je 415283 ::Run(char const*, char const*)+0x4b3 41523e 0.00% | 41 89 c7 mov %eax,%r15d 415241 0.00% | 41 83 e7 01 and $0x1,%r15d 415245 0.00% | 41 83 ff 01 cmp $0x1,%r15d 415249 0.00% | 41 89 c7 mov %eax,%r15d 415250 679 13.05% |XXXXXXXXXXXXXXXX 48 c1 eb 08 shr $0x8,%rbx 415254 124 2.38% |XX 0f b6 c3 movzbl %bl,%eax 415257 0.00% | 41 0f b6 04 00 movzbl (%r8,%rax,1),%eax 41525c 43 0.83% |X 48 8b 04 c1 mov (%rcx,%rax,8),%rax 415260 828 15.91% |XXXXXXXXXXXXXXXXXXX 4c 63 f8 movslq %eax,%r15 415263 388 7.46% |XXXXXXXXX 48 c1 e8 20 shr $0x20,%rax 415267 141 2.71% |XXX 4c 01 f9 add %r15,%rcx 41526a 634 12.18% |XXXXXXXXXXXXXXX a8 0f test $0xf,%al 41526c 749 14.39% |XXXXXXXXXXXXXXXXXX 74 45 je 4152b3 ::Run(char const*, char const*)+0x4c3 41526e 0.00% | 41 89 c7 mov %eax,%r15d 415271 0.00% | 41 83 e7 01 and $0x1,%r15d 415275 0.00% | 41 83 ff 01 cmp $0x1,%r15d 415279 0.00% | 41 89 c7 mov %eax,%r15d

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  • Have any software engineers gotten math degrees later in their careers?

    - by vin
    I have a bachelors in computer science and worked the last 12 years as a software engineer. I'm bored with doing general development work, so I want to specialize. I'm thinking about getting a master's degree in math so I can build math models and write algorithms to implement them. I'm unsure what type of work I'd do (financial, gaming, graphics, science, research, etc) but I'm open minded. I would need to refresh my undergrad math skills (which are old and faded), but I loved algebra and calculus. I've been working with couple statisticians so I've been finding myself more interested in statistics. Since I'm a parent supporting a household, I would have to continue working while studying. Have any software engineers taken this route? (Specifically, going from BS in comp sci to MS in math.) If so, what advice do you have for coursework, financing, and getting a job that combines programming with advanced math? How abundant are these kinds of jobs? I'm not sure where one starts. Also, how do you hop from a BS to an MS in a different subject?

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  • C# WebBrowser Invoke issue

    - by James Jeffrey
    I am logging into facebook using a web browser. Everything works, but the problem is when I invoke the button click I need to check if the password is correct but, the check seems to happen before the button is invoked which makes no sense at all because the checking code is after the invoke. private void Facebook_Login(String username, String password) { webBrowser1.Url = new Uri("http://m.facebook.com"); while (webBrowser1.ReadyState != WebBrowserReadyState.Complete) Application.DoEvents(); HtmlElementCollection inputs = webBrowser1.Document.GetElementsByTagName("input"); foreach(HtmlElement input in inputs) { if (input.GetAttribute("name") == "email") { input.SetAttribute("value", "[email protected]"); } if (input.GetAttribute("name") == "pass") { input.SetAttribute("value", "kelaroostj"); // dont worry that pass wont work lol. } if (input.GetAttribute("name") == "login") { input.InvokeMember("click"); } } while (webBrowser1.ReadyState != WebBrowserReadyState.Complete) Application.DoEvents(); HtmlElementCollection bs = webBrowser1.Document.GetElementsByTagName("b"); foreach(HtmlElement b in bs) { MessageBox.Show(b.InnerHtml); } Log_Message("Logged into Facebook with: [email protected]"); }

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  • Doubts in executable and relocatable object file

    - by bala1486
    Hello, I have written a simple Hello World program. #include <stdio.h> int main() { printf("Hello World"); return 0; } I wanted to understand how the relocatable object file and executable file look like. The object file corresponding to the main function is 0000000000000000 <main>: 0: 55 push %rbp 1: 48 89 e5 mov %rsp,%rbp 4: bf 00 00 00 00 mov $0x0,%edi 9: b8 00 00 00 00 mov $0x0,%eax e: e8 00 00 00 00 callq 13 <main+0x13> 13: b8 00 00 00 00 mov $0x0,%eax 18: c9 leaveq 19: c3 retq Here the function call for printf is callq 13. One thing i don't understand is why is it 13. That means call the function at adresss 13, right??. 13 has the next instruction, right?? Please explain me what does this mean?? The executable code corresponding to main is 00000000004004cc <main>: 4004cc: 55 push %rbp 4004cd: 48 89 e5 mov %rsp,%rbp 4004d0: bf dc 05 40 00 mov $0x4005dc,%edi 4004d5: b8 00 00 00 00 mov $0x0,%eax 4004da: e8 e1 fe ff ff callq 4003c0 <printf@plt> 4004df: b8 00 00 00 00 mov $0x0,%eax 4004e4: c9 leaveq 4004e5: c3 retq Here it is callq 4003c0. But the binary instruction is e8 e1 fe ff ff. There is nothing that corresponds to 4003c0. What is that i am getting wrong? Thanks. Bala

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  • How do I get Spotlight attributes to display in the get info window?

    - by Alexander Rauchfuss
    I have created a spotlight importer for comic files. The attributes are successfully imported and searchable. The one thing that remains is getting the attributes to display in a file's get info window. It seems that this should be a simple matter of editing the schema.xml file so the attributes are nested inside displayattrs tags. Unfortunately this does not seem to be working. I simplified the plugin for testing. The following are all of the important files. schema.xml <types> <type name="cx.c3.cbz-archive"> <allattrs> kMDItemTitle kMDItemAuthors </allattrs> <displayattrs> kMDItemTitle kMDItemAuthors </displayattrs> </type> <type name="cx.c3.cbr-archive"> <allattrs> kMDItemTitle kMDItemAuthors </allattrs> <displayattrs> kMDItemTitle kMDItemAuthors </displayattrs> </type> GetMetadataForFile.m Boolean GetMetadataForFile(void* thisInterface, CFMutableDictionaryRef attributes, CFStringRef contentTypeUTI, CFStringRef pathToFile) { NSAutoreleasePool * pool = [NSAutoreleasePool new]; NSString * file = (NSString *)pathToFile; NSArray * authors = [[UKXattrMetadataStore stringForKey: @"com_opencomics_authors" atPath: file traverseLink: NO] componentsSeparatedByString: @","]; [(NSMutableDictionary *)attributes setObject: authors forKey: (id)kMDItemAuthors]; NSString * title = [UKXattrMetadataStore stringForKey: @"com_opencomics_title" atPath: file traverseLink: NO]; [(NSMutableDictionary *)attributes setObject: title forKey: (id)kMDItemTitle]; [pool release]; return true; }

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  • When is factory method better than simple factory and vice versa?

    - by Bruce
    Hi all Working my way through the Head First Design Patterns book. I believe I understand the simple factory and the factory method, but I'm having trouble seeing what advantages factory method brings over simple factory. If an object A uses a simple factory to create its B objects, then clients can create it like this: A a = new A(new BFactory()); whereas if an object uses a factory method, a client can create it like this: A a = new ConcreteA(); // ConcreteA contains a method for instantiating the same Bs that the BFactory above creates, with the method hardwired into the subclass of A, ConcreteA. So in the case of the simple factory, clients compose A with a B factory, whereas with the factory method, the client chooses the appropriate subclass for the types of B it wants. There really doesn't seem to be much to choose between them. Either you have to choose which BFactory you want to compose A with, or you have to choose the right subclass of A to give you the Bs. Under what circumstances is one better than the other? Thanks all!

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  • How to display panels with component in frame

    - by terence6
    Why my JFrame 'frame' is diplaying empty window, when it should give me 3 menu buttons and my own painted JComponent below ? What am I missing here ? import java.awt.*; import javax.swing.*; public class Eyes extends JFrame { public static void main(String[] args) { final JFrame frame = new JFrame("Eyes"); frame.setPreferredSize(new Dimension(450, 300)); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JPanel players = new JPanel(new GridLayout(1, 3)); players.add(new JButton("Eyes color")); players.add(new JButton("Eye pupil")); players.add(new JButton("Background color")); JPanel eyes = new JPanel(); eyes.add(new MyComponent()); JPanel content = new JPanel(); content.setLayout(new BoxLayout(content, BoxLayout.Y_AXIS)); content.add(players); content.add(eyes); frame.getContentPane(); frame.pack(); frame.setVisible(true); } } class MyComponent extends JComponent { public MyComponent(){ } @Override public void paint(Graphics g) { int height = 120; int width = 120; Graphics2D g2d = (Graphics2D) g; g2d.setRenderingHint(RenderingHints.KEY_ANTIALIASING,RenderingHints.VALUE_ANTIALIAS_ON); BasicStroke bs = new BasicStroke(3.0f); g2d.setStroke(bs); g2d.setColor(Color.yellow); g2d.fillOval(200, 200, height, width); g2d.setColor(Color.black); g2d.drawOval(60, 60, height, width); } }

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  • Makefile; mirroring a growing tree through a process

    - by Martineau
    I would like to periodically mirror a growing tree, say, from $in to $out, doing a process in between (saving the only file header). As; #!/bin/bash in=./segd out=./db for f in `find $in -name "*.segd"`;do # Deduct output (dir + name) d=`dirname $f|perl -pe 's!'$in'!'$out'!'` n=`basename $f|perl -pe 's!$!_hdr!'` if [ ! -e $d/$n ]; then [ ! -d $d ] && mkdir -p $d; printf "From %s now build %s\n" $f "$d/$n" # Do something, whathever. For example e.g; dd if=$f bs=32 count=1 conv=swab 2>/dev/null|od -x > $d/$n fi done That is about fair. However; to be more robust, for a better synchronization (say if a source file did change or whatever), I would like to use a Makefile, as in; HDR := $(patsubst ./segd/%.segd,./db/%.segd_hdr,$(wildcard ./segd/*.segd)) all: ${HDR} db/%.segd_hdr: ./segd/%.segd echo "Doing" dd if=$< bs=32 count=1 conv=swab 2>/dev/null|od -x > $@ My problem; I cannot code this Makefile to "dive" more deeply within the source ./segd tree. How can we do it and is there a way ? Many thanks for your kind recommendations. PS: The idea will be to later rsync the (smaller) destination tree over a sat connection.

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  • Most readable way to write simple conditional check

    - by JRL
    What would be the most readable/best way to write a multiple conditional check such as shown below? Two possibilities that I could think of (this is Java but the language really doesn't matter here): Option 1: boolean c1 = passwordField.getPassword().length > 0; boolean c2 = !stationIDTextField.getText().trim().isEmpty(); boolean c3 = !userNameTextField.getText().trim().isEmpty(); if (c1 && c2 && c3) { okButton.setEnabled(true); } Option 2: if (passwordField.getPassword().length > 0 && !stationIDTextField.getText().trim().isEmpty() && !userNameTextField.getText().trim().isEmpty() { okButton.setEnabled(true); } What I don't like about option 2 is that the line wraps and then indentation becomes a pain. What I don't like about option 1 is that it creates variables for nothing and requires looking at two places. So what do you think? Any other options?

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  • C++ Macro Arithmetric

    - by anon
    I have to do with Macros (it's macros calling macros; so templates are out of the question). Here's what I want: foo(3, a, b1, c1) --> foo1(a, b1, c1); foo(5, a, b1, c1, b2, c2) -> foo2(a, b1, c1, b2, c2); foo(7, a, b1, c1, b2, c2, b3, c3) -> foo3(a, b1, c1, b2, c2, b3, c3); So basically, what I want is to be able to execute the "function" n - (n-1)/2 at macro expansion time. Is this possible? Thanks! [PS, if you dislike my questions; I support your right to downvote; my worst question so far is only -17, so maybe we can break that record; however, please let me know why my question is technically invalid.] Thanks EDIT: Foo takes a variable # of arguments, of the form: foo(N, a1, b1, a2, b2, ... a_N, b_N) -> foo##N(a1, b1, a2, b2, ... a_N, b_N);

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  • Upload Certificate and Key to RUEI in order to decrypt SSL traffic

    - by stefan.thieme(at)oracle.com
    So you want to monitor encrypted traffic with your RUEI collector ?Actually this is an easy thing if you follow the lines below...I will start out with creating a pair of snakeoil (so called self-signed) certificate and key with the make-ssl-cert tool which comes pre-packaged with apache only for the purpose of this example.$ sudo make-ssl-cert generate-default-snakeoil$ sudo ls -l /etc/ssl/certs/ssl-cert-snakeoil.pem /etc/ssl/private/ssl-cert-snakeoil.key-rw-r--r-- 1 root root     615 2010-06-07 10:03 /etc/ssl/certs/ssl-cert-snakeoil.pem-rw-r----- 1 root ssl-cert 891 2010-06-07 10:03 /etc/ssl/private/ssl-cert-snakeoil.keyRUEI Configuration of Security SSL Keys You will most likely get these two files from your Certificate Authority (CA) and/or your system administrators should be able to extract this from your WebServer or LoadBalancer handling SSL encryption for your infrastructure.Now let's look at the content of these two files, the certificate (apache assumes this is in PEM format) is called a public key and the private key is used by the apache server to encrypt traffic for a client using the certificate to initiate the SSL connection with the server.In case you already know that these two match, you simply have to paste them in one text file and upload this text file to your RUEI instance.$ sudo cat /etc/ssl/certs/ssl-cert-snakeoil.pem /etc/ssl/private/ssl-cert-snakeoil.key > /tmp/ruei.cert_and_key$ sudo cat /tmp/ruei.cert_and_key -----BEGIN CERTIFICATE----- MIIBmTCCAQICCQD7O3XXwVilWzANBgkqhkiG9w0BAQUFADARMQ8wDQYDVQQDEwZ1 YnVudHUwHhcNMTAwNjA3MDgwMzUzWhcNMjAwNjA0MDgwMzUzWjARMQ8wDQYDVQQD EwZ1YnVudHUwgZ8wDQYJKoZIhvcNAQEBBQADgY0AMIGJAoGBALbs+JnI+p+K7Iqa SQZdnYBxOpdRH0/9jt1QKvmH68v81h9+f1Z2rVR7Zrd/l+ruE3H9VvuzxMlKuMH7 qBX/gmjDZTlj9WJM+zc0tSk+e2udy9he20lGzTxv0vaykJkuKcvSWNk4WE9NuAdg IHZvjKgoTSVmvM1ApMCg69nyOy97AgMBAAEwDQYJKoZIhvcNAQEFBQADgYEAk2rv VEkxR1qPSpJiudDuGUHtWKBKWiWbmSwI3REZT+0vG+YDG5a55NdxgRk3zhQntqF7 gNYjKxblBByBpY7W0ci00kf7kFgvXWMeU96NSQJdnid/YxzQYn0dGL2rSh1dwdPN NPQlNSfnEQ1yxFevR7aRdCqTbTXU3mxi8YaSscE= -----END CERTIFICATE----- -----BEGIN RSA PRIVATE KEY----- MIICXgIBAAKBgQC27PiZyPqfiuyKmkkGXZ2AcTqXUR9P/Y7dUCr5h+vL/NYffn9W dq1Ue2a3f5fq7hNx/Vb7s8TJSrjB+6gV/4Jow2U5Y/ViTPs3NLUpPntrncvYXttJ Rs08b9L2spCZLinL0ljZOFhPTbgHYCB2b4yoKE0lZrzNQKTAoOvZ8jsvewIDAQAB AoGBAJ7LCWeeUwnKNFqBYmD3RTFpmX4furnal3lBDX0945BZtJr0WZ/6N679zIYA aiVTdGfgjvDC9lHy3n3uctRd0Jqdh2QoSSxNBhq5elIApNIIYzu7w/XI/VhGcDlA b6uadURQEC2q+M8YYjw3mwR2omhCWlHIViOHe/9T8jfP/8pxAkEA7k39WRcQildH DFKcj7gurqlkElHysacMTFWf0ZDTEUS6bdkmNXwK6mH63BlmGLrYAP5AMgKgeDf8 D+WRfv8YKQJBAMSCQ7UGDN3ysyfIIrdc1RBEAk4BOrKHKtD5Ux0z5lcQkaCYrK8J DuSldreN2yOhS99/S4CRWmGkTj04wRSnjwMCQQCaR5mW3QzTU4/m1XEQxsBKSdZE 2hMSmsCmhuSyK13Kl0FPLr/C7qyuc4KSjksABa8kbXaoKfUz/6LLs+ePXZ2JAkAv +mIPk5+WnQgS4XFgdYDrzL8HTpOHPSs+BHG/goltnnT/0ebvgXWqa5+1pyPm6h29 PrYveM2pY1Va6z1xDowDAkEAttfzAwAHz+FUhWQCmOBpvBuW/KhYWKZTMpvxFMSY YD5PH6NNyLfBx0J4nGPN5n/f6il0s9pzt3ko++/eUtWSnQ== -----END RSA PRIVATE KEY----- Simply click on the add new key and browse for the cert_and_key file on your desktop which you concatenated earlier using any text editor. You may need to add a passphrase in order to decrypt the RSA key in some cases (it should tell you BEGIN ENCRYPTED PRIVATE KEY in the header line). I will show you the success screen after uploading the certificate to RUEI. You may want to restart your collector once you have uploaded all the certificate/key pairs you want to use in order to make sure they get picked up asap.You should be able to see the number of SSL Connections rising in the Collector statistics screen below. The figures for decrypt errors should slowly go down and the usage figures for your encryption algortihm on the subsequent SSL Encryption screen should go up. You should be 100% sure everything works fine by now, otherwise see below to distinguish the remaining 1% from your 99% certainty.Verify Certificate and Key are matchingYou can compare the modulus of private key and public certificate and they should match in order for the key to fit the lock. You only want to make sure they both fit each other.We are actually interested only in the following details of the two files, which can be determined by using the -subject, -dates and -modulus command line switches instead of the complete -text output of the x509 certificate/rsa key contents.$ sudo openssl x509 -noout -subject -in /etc/ssl/certs/ssl-cert-snakeoil.pemsubject= /CN=ubuntu$ sudo openssl x509 -noout -dates -in /etc/ssl/certs/ssl-cert-snakeoil.pemnotBefore=Jun  7 08:03:53 2010 GMTnotAfter=Jun  4 08:03:53 2020 GMT$ sudo openssl x509 -noout -modulus -in /etc/ssl/certs/ssl-cert-snakeoil.pem Modulus=B6ECF899C8FA9F8AEC8A9A49065D9D80713A97511F4FFD8EDD502AF987EBCBFCD61F7E7F5676AD547B66B77F97EAEE1371FD56FBB3C4C94AB8C1FBA815FF8268C3653963F5624CFB3734B5293E7B6B9DCBD85EDB4946CD3C6FD2F6B290992E29CBD258D938584F4DB8076020766F8CA8284D2566BCCD40A4C0A0EBD9F23B2F7B $ sudo openssl rsa -noout -modulus -in /etc/ssl/private/ssl-cert-snakeoil.keyModulus=B6ECF899C8FA9F8AEC8A9A49065D9D80713A97511F4FFD8EDD502AF987EBCBFCD61F7E7F5676AD547B66B77F97EAEE1371FD56FBB3C4C94AB8C1FBA815FF8268C3653963F5624CFB3734B5293E7B6B9DCBD85EDB4946CD3C6FD2F6B290992E29CBD258D938584F4DB8076020766F8CA8284D2566BCCD40A4C0A0EBD9F23B2F7BAs you can see the modulus matches exactly and we have the proof that the certificate has been created using the private key. OpenSSL Certificate and Key DetailsAs I already told you, you do not need all the greedy details, but in case you want to know it in depth what is actually in those hex-blocks can be made visible with the following commands which show you the actual content in a human readable format.Note: You may not want to post all the details of your private key =^) I told you I have been using a self-signed certificate only for showing you these details.$ sudo openssl rsa -noout -text -in /etc/ssl/private/ssl-cert-snakeoil.keyPrivate-Key: (1024 bit)modulus:    00:b6:ec:f8:99:c8:fa:9f:8a:ec:8a:9a:49:06:5d:    9d:80:71:3a:97:51:1f:4f:fd:8e:dd:50:2a:f9:87:    eb:cb:fc:d6:1f:7e:7f:56:76:ad:54:7b:66:b7:7f:    97:ea:ee:13:71:fd:56:fb:b3:c4:c9:4a:b8:c1:fb:    a8:15:ff:82:68:c3:65:39:63:f5:62:4c:fb:37:34:    b5:29:3e:7b:6b:9d:cb:d8:5e:db:49:46:cd:3c:6f:    d2:f6:b2:90:99:2e:29:cb:d2:58:d9:38:58:4f:4d:    b8:07:60:20:76:6f:8c:a8:28:4d:25:66:bc:cd:40:    a4:c0:a0:eb:d9:f2:3b:2f:7bpublicExponent: 65537 (0x10001)privateExponent:    00:9e:cb:09:67:9e:53:09:ca:34:5a:81:62:60:f7:    45:31:69:99:7e:1f:ba:b9:da:97:79:41:0d:7d:3d:    e3:90:59:b4:9a:f4:59:9f:fa:37:ae:fd:cc:86:00:    6a:25:53:74:67:e0:8e:f0:c2:f6:51:f2:de:7d:ee:    72:d4:5d:d0:9a:9d:87:64:28:49:2c:4d:06:1a:b9:    7a:52:00:a4:d2:08:63:3b:bb:c3:f5:c8:fd:58:46:    70:39:40:6f:ab:9a:75:44:50:10:2d:aa:f8:cf:18:    62:3c:37:9b:04:76:a2:68:42:5a:51:c8:56:23:87:    7b:ff:53:f2:37:cf:ff:ca:71prime1:    00:ee:4d:fd:59:17:10:8a:57:47:0c:52:9c:8f:b8:    2e:ae:a9:64:12:51:f2:b1:a7:0c:4c:55:9f:d1:90:    d3:11:44:ba:6d:d9:26:35:7c:0a:ea:61:fa:dc:19:    66:18:ba:d8:00:fe:40:32:02:a0:78:37:fc:0f:e5:    91:7e:ff:18:29prime2:    00:c4:82:43:b5:06:0c:dd:f2:b3:27:c8:22:b7:5c:    d5:10:44:02:4e:01:3a:b2:87:2a:d0:f9:53:1d:33:    e6:57:10:91:a0:98:ac:af:09:0e:e4:a5:76:b7:8d:    db:23:a1:4b:df:7f:4b:80:91:5a:61:a4:4e:3d:38:    c1:14:a7:8f:03exponent1:    00:9a:47:99:96:dd:0c:d3:53:8f:e6:d5:71:10:c6:    c0:4a:49:d6:44:da:13:12:9a:c0:a6:86:e4:b2:2b:    5d:ca:97:41:4f:2e:bf:c2:ee:ac:ae:73:82:92:8e:    4b:00:05:af:24:6d:76:a8:29:f5:33:ff:a2:cb:b3:    e7:8f:5d:9d:89exponent2:    2f:fa:62:0f:93:9f:96:9d:08:12:e1:71:60:75:80:    eb:cc:bf:07:4e:93:87:3d:2b:3e:04:71:bf:82:89:    6d:9e:74:ff:d1:e6:ef:81:75:aa:6b:9f:b5:a7:23:    e6:ea:1d:bd:3e:b6:2f:78:cd:a9:63:55:5a:eb:3d:    71:0e:8c:03coefficient:    00:b6:d7:f3:03:00:07:cf:e1:54:85:64:02:98:e0:    69:bc:1b:96:fc:a8:58:58:a6:53:32:9b:f1:14:c4:    98:60:3e:4f:1f:a3:4d:c8:b7:c1:c7:42:78:9c:63:    cd:e6:7f:df:ea:29:74:b3:da:73:b7:79:28:fb:ef:    de:52:d5:92:9d$ sudo openssl x509 -noout -text -in /etc/ssl/certs/ssl-cert-snakeoil.pemCertificate:    Data:        Version: 1 (0x0)        Serial Number:            fb:3b:75:d7:c1:58:a5:5b        Signature Algorithm: sha1WithRSAEncryption        Issuer: CN=ubuntu        Validity            Not Before: Jun  7 08:03:53 2010 GMT            Not After : Jun  4 08:03:53 2020 GMT        Subject: CN=ubuntu        Subject Public Key Info:            Public Key Algorithm: rsaEncryption            RSA Public Key: (1024 bit)                Modulus (1024 bit):                    00:b6:ec:f8:99:c8:fa:9f:8a:ec:8a:9a:49:06:5d:                    9d:80:71:3a:97:51:1f:4f:fd:8e:dd:50:2a:f9:87:                    eb:cb:fc:d6:1f:7e:7f:56:76:ad:54:7b:66:b7:7f:                    97:ea:ee:13:71:fd:56:fb:b3:c4:c9:4a:b8:c1:fb:                    a8:15:ff:82:68:c3:65:39:63:f5:62:4c:fb:37:34:                    b5:29:3e:7b:6b:9d:cb:d8:5e:db:49:46:cd:3c:6f:                    d2:f6:b2:90:99:2e:29:cb:d2:58:d9:38:58:4f:4d:                    b8:07:60:20:76:6f:8c:a8:28:4d:25:66:bc:cd:40:                    a4:c0:a0:eb:d9:f2:3b:2f:7b                Exponent: 65537 (0x10001)    Signature Algorithm: sha1WithRSAEncryption        93:6a:ef:54:49:31:47:5a:8f:4a:92:62:b9:d0:ee:19:41:ed:        58:a0:4a:5a:25:9b:99:2c:08:dd:11:19:4f:ed:2f:1b:e6:03:        1b:96:b9:e4:d7:71:81:19:37:ce:14:27:b6:a1:7b:80:d6:23:        2b:16:e5:04:1c:81:a5:8e:d6:d1:c8:b4:d2:47:fb:90:58:2f:        5d:63:1e:53:de:8d:49:02:5d:9e:27:7f:63:1c:d0:62:7d:1d:        18:bd:ab:4a:1d:5d:c1:d3:cd:34:f4:25:35:27:e7:11:0d:72:        c4:57:af:47:b6:91:74:2a:93:6d:35:d4:de:6c:62:f1:86:92:        b1:c1The above output can also be seen if you direct your browser client to your website and check the certificate sent by the server to your browser. You will be able to lookup all the details including the validity dates, subject common name and the public key modulus.Capture an SSL connection using WiresharkAnd as you would have expected, looking at the low-level tcp data that has been exchanged between the client and server with a tcp-diagnostics tool (i.e. wireshark/tcpdump) you can also see the modulus in there.These were the settings I used to capture all traffic on the local loopback interface, matching the filter expression: tcp and ip and host 127.0.0.1 and port 443. This tells Wireshark to leave out any other information, I may not have been interested in showing you.

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  • Oracle BI Server Modeling, Part 1- Designing a Query Factory

    - by bob.ertl(at)oracle.com
      Welcome to Oracle BI Development's BI Foundation blog, focused on helping you get the most value from your Oracle Business Intelligence Enterprise Edition (BI EE) platform deployments.  In my first series of posts, I plan to show developers the concepts and best practices for modeling in the Common Enterprise Information Model (CEIM), the semantic layer of Oracle BI EE.  In this segment, I will lay the groundwork for the modeling concepts.  First, I will cover the big picture of how the BI Server fits into the system, and how the CEIM controls the query processing. Oracle BI EE Query Cycle The purpose of the Oracle BI Server is to bridge the gap between the presentation services and the data sources.  There are typically a variety of data sources in a variety of technologies: relational, normalized transaction systems; relational star-schema data warehouses and marts; multidimensional analytic cubes and financial applications; flat files, Excel files, XML files, and so on. Business datasets can reside in a single type of source, or, most of the time, are spread across various types of sources. Presentation services users are generally business people who need to be able to query that set of sources without any knowledge of technologies, schemas, or how sources are organized in their company. They think of business analysis in terms of measures with specific calculations, hierarchical dimensions for breaking those measures down, and detailed reports of the business transactions themselves.  Most of them create queries without knowing it, by picking a dashboard page and some filters.  Others create their own analysis by selecting metrics and dimensional attributes, and possibly creating additional calculations. The BI Server bridges that gap from simple business terms to technical physical queries by exposing just the business focused measures and dimensional attributes that business people can use in their analyses and dashboards.   After they make their selections and start the analysis, the BI Server plans the best way to query the data sources, writes the optimized sequence of physical queries to those sources, post-processes the results, and presents them to the client as a single result set suitable for tables, pivots and charts. The CEIM is a model that controls the processing of the BI Server.  It provides the subject areas that presentation services exposes for business users to select simplified metrics and dimensional attributes for their analysis.  It models the mappings to the physical data access, the calculations and logical transformations, and the data access security rules.  The CEIM consists of metadata stored in the repository, authored by developers using the Administration Tool client.     Presentation services and other query clients create their queries in BI EE's SQL-92 language, called Logical SQL or LSQL.  The API simply uses ODBC or JDBC to pass the query to the BI Server.  Presentation services writes the LSQL query in terms of the simplified objects presented to the users.  The BI Server creates a query plan, and rewrites the LSQL into fully-detailed SQL or other languages suitable for querying the physical sources.  For example, the LSQL on the left below was rewritten into the physical SQL for an Oracle 11g database on the right. Logical SQL   Physical SQL SELECT "D0 Time"."T02 Per Name Month" saw_0, "D4 Product"."P01  Product" saw_1, "F2 Units"."2-01  Billed Qty  (Sum All)" saw_2 FROM "Sample Sales" ORDER BY saw_0, saw_1       WITH SAWITH0 AS ( select T986.Per_Name_Month as c1, T879.Prod_Dsc as c2,      sum(T835.Units) as c3, T879.Prod_Key as c4 from      Product T879 /* A05 Product */ ,      Time_Mth T986 /* A08 Time Mth */ ,      FactsRev T835 /* A11 Revenue (Billed Time Join) */ where ( T835.Prod_Key = T879.Prod_Key and T835.Bill_Mth = T986.Row_Wid) group by T879.Prod_Dsc, T879.Prod_Key, T986.Per_Name_Month ) select SAWITH0.c1 as c1, SAWITH0.c2 as c2, SAWITH0.c3 as c3 from SAWITH0 order by c1, c2   Probably everybody reading this blog can write SQL or MDX.  However, the trick in designing the CEIM is that you are modeling a query-generation factory.  Rather than hand-crafting individual queries, you model behavior and relationships, thus configuring the BI Server machinery to manufacture millions of different queries in response to random user requests.  This mass production requires a different mindset and approach than when you are designing individual SQL statements in tools such as Oracle SQL Developer, Oracle Hyperion Interactive Reporting (formerly Brio), or Oracle BI Publisher.   The Structure of the Common Enterprise Information Model (CEIM) The CEIM has a unique structure specifically for modeling the relationships and behaviors that fill the gap from logical user requests to physical data source queries and back to the result.  The model divides the functionality into three specialized layers, called Presentation, Business Model and Mapping, and Physical, as shown below. Presentation services clients can generally only see the presentation layer, and the objects in the presentation layer are normally the only ones used in the LSQL request.  When a request comes into the BI Server from presentation services or another client, the relationships and objects in the model allow the BI Server to select the appropriate data sources, create a query plan, and generate the physical queries.  That's the left to right flow in the diagram below.  When the results come back from the data source queries, the right to left relationships in the model show how to transform the results and perform any final calculations and functions that could not be pushed down to the databases.   Business Model Think of the business model as the heart of the CEIM you are designing.  This is where you define the analytic behavior seen by the users, and the superset library of metric and dimension objects available to the user community as a whole.  It also provides the baseline business-friendly names and user-readable dictionary.  For these reasons, it is often called the "logical" model--it is a virtual database schema that persists no data, but can be queried as if it is a database. The business model always has a dimensional shape (more on this in future posts), and its simple shape and terminology hides the complexity of the source data models. Besides hiding complexity and normalizing terminology, this layer adds most of the analytic value, as well.  This is where you define the rich, dimensional behavior of the metrics and complex business calculations, as well as the conformed dimensions and hierarchies.  It contributes to the ease of use for business users, since the dimensional metric definitions apply in any context of filters and drill-downs, and the conformed dimensions enable dashboard-wide filters and guided analysis links that bring context along from one page to the next.  The conformed dimensions also provide a key to hiding the complexity of many sources, including federation of different databases, behind the simple business model. Note that the expression language in this layer is LSQL, so that any expression can be rewritten into any data source's query language at run time.  This is important for federation, where a given logical object can map to several different physical objects in different databases.  It is also important to portability of the CEIM to different database brands, which is a key requirement for Oracle's BI Applications products. Your requirements process with your user community will mostly affect the business model.  This is where you will define most of the things they specifically ask for, such as metric definitions.  For this reason, many of the best-practice methodologies of our consulting partners start with the high-level definition of this layer. Physical Model The physical model connects the business model that meets your users' requirements to the reality of the data sources you have available. In the query factory analogy, think of the physical layer as the bill of materials for generating physical queries.  Every schema, table, column, join, cube, hierarchy, etc., that will appear in any physical query manufactured at run time must be modeled here at design time. Each physical data source will have its own physical model, or "database" object in the CEIM.  The shape of each physical model matches the shape of its physical source.  In other words, if the source is normalized relational, the physical model will mimic that normalized shape.  If it is a hypercube, the physical model will have a hypercube shape.  If it is a flat file, it will have a denormalized tabular shape. To aid in query optimization, the physical layer also tracks the specifics of the database brand and release.  This allows the BI Server to make the most of each physical source's distinct capabilities, writing queries in its syntax, and using its specific functions. This allows the BI Server to push processing work as deep as possible into the physical source, which minimizes data movement and takes full advantage of the database's own optimizer.  For most data sources, native APIs are used to further optimize performance and functionality. The value of having a distinct separation between the logical (business) and physical models is encapsulation of the physical characteristics.  This encapsulation is another enabler of packaged BI applications and federation.  It is also key to hiding the complex shapes and relationships in the physical sources from the end users.  Consider a routine drill-down in the business model: physically, it can require a drill-through where the first query is MDX to a multidimensional cube, followed by the drill-down query in SQL to a normalized relational database.  The only difference from the user's point of view is that the 2nd query added a more detailed dimension level column - everything else was the same. Mappings Within the Business Model and Mapping Layer, the mappings provide the binding from each logical column and join in the dimensional business model, to each of the objects that can provide its data in the physical layer.  When there is more than one option for a physical source, rules in the mappings are applied to the query context to determine which of the data sources should be hit, and how to combine their results if more than one is used.  These rules specify aggregate navigation, vertical partitioning (fragmentation), and horizontal partitioning, any of which can be federated across multiple, heterogeneous sources.  These mappings are usually the most sophisticated part of the CEIM. Presentation You might think of the presentation layer as a set of very simple relational-like views into the business model.  Over ODBC/JDBC, they present a relational catalog consisting of databases, tables and columns.  For business users, presentation services interprets these as subject areas, folders and columns, respectively.  (Note that in 10g, subject areas were called presentation catalogs in the CEIM.  In this blog, I will stick to 11g terminology.)  Generally speaking, presentation services and other clients can query only these objects (there are exceptions for certain clients such as BI Publisher and Essbase Studio). The purpose of the presentation layer is to specialize the business model for different categories of users.  Based on a user's role, they will be restricted to specific subject areas, tables and columns for security.  The breakdown of the model into multiple subject areas organizes the content for users, and subjects superfluous to a particular business role can be hidden from that set of users.  Customized names and descriptions can be used to override the business model names for a specific audience.  Variables in the object names can be used for localization. For these reasons, you are better off thinking of the tables in the presentation layer as folders than as strict relational tables.  The real semantics of tables and how they function is in the business model, and any grouping of columns can be included in any table in the presentation layer.  In 11g, an LSQL query can also span multiple presentation subject areas, as long as they map to the same business model. Other Model Objects There are some objects that apply to multiple layers.  These include security-related objects, such as application roles, users, data filters, and query limits (governors).  There are also variables you can use in parameters and expressions, and initialization blocks for loading their initial values on a static or user session basis.  Finally, there are Multi-User Development (MUD) projects for developers to check out units of work, and objects for the marketing feature used by our packaged customer relationship management (CRM) software.   The Query Factory At this point, you should have a grasp on the query factory concept.  When developing the CEIM model, you are configuring the BI Server to automatically manufacture millions of queries in response to random user requests. You do this by defining the analytic behavior in the business model, mapping that to the physical data sources, and exposing it through the presentation layer's role-based subject areas. While configuring mass production requires a different mindset than when you hand-craft individual SQL or MDX statements, it builds on the modeling and query concepts you already understand. The following posts in this series will walk through the CEIM modeling concepts and best practices in detail.  We will initially review dimensional concepts so you can understand the business model, and then present a pattern-based approach to learning the mappings from a variety of physical schema shapes and deployments to the dimensional model.  Along the way, we will also present the dimensional calculation template, and learn how to configure the many additivity patterns.

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  • problem when view the super block in ext3 file system

    - by xuczhang
    I tried to view the superblock by command "dd" in ext3 file system. dd if=/dev/sda3 bs=4096 skip=1 count=1 of=superblock But the result in superblock file is not correct(I compare the value of Inodes count I got from dumpe2fs). The device file /dev/sda3 is started at the boot block and then the superblock of the group0? And another question is the boot block and superblock's size are both BLOCKSIZE(here is 4096)? The disk format of ext2/ext3(I think they are the same) are shown below:

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  • Disable "longhaul" kernel module with a GRUB command?

    - by Julian Schweigert
    I've got a problem with a VIA C3 (1GHz)-system: the system freezes immediately when the CPU frequency goes under 731MHz because of an incompatibility with the (not completely implemented) i686 commands and a powersave feature of the kernel. There is a workaround: deactivate the "longhaul" kernelmodule via alias longhaul off in /etc/modprobe.d/aliases. But the system freezes before I can install any Linux distribution - even Clonezilla freezes. Is there a possibility to deactivate the module with a GRUB boot parameter before the kernel is loaded?

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  • Linux buffer cache effect on IO writes?

    - by Patrick LeBoutillier
    I'm copying large files (3 x 30G) between 2 filesystems on a Linux server (kernel 2.6.37, 16 cores, 32G RAM) and I'm getting poor performance. I suspect that the usage of the buffer cache is killing the I/O performance. To try and narrow down the problem I used fio directly on the SAS disk to monitor the performance. Here is the output of 2 fio runs (the first with direct=1, the second one direct=0): Config: [test] rw=write blocksize=32k size=20G filename=/dev/sda # direct=1 Run 1: test: (g=0): rw=write, bs=32K-32K/32K-32K, ioengine=sync, iodepth=1 Starting 1 process Jobs: 1 (f=1): [W] [100.0% done] [0K/205M /s] [0/6K iops] [eta 00m:00s] test: (groupid=0, jobs=1): err= 0: pid=4667 write: io=20,480MB, bw=199MB/s, iops=6,381, runt=102698msec clat (usec): min=104, max=13,388, avg=152.06, stdev=72.43 bw (KB/s) : min=192448, max=213824, per=100.01%, avg=204232.82, stdev=4084.67 cpu : usr=3.37%, sys=16.55%, ctx=655410, majf=0, minf=29 IO depths : 1=100.0%, 2=0.0%, 4=0.0%, 8=0.0%, 16=0.0%, 32=0.0%, >=64=0.0% submit : 0=0.0%, 4=100.0%, 8=0.0%, 16=0.0%, 32=0.0%, 64=0.0%, >=64=0.0% complete : 0=0.0%, 4=100.0%, 8=0.0%, 16=0.0%, 32=0.0%, 64=0.0%, >=64=0.0% issued r/w: total=0/655360, short=0/0 lat (usec): 250=99.50%, 500=0.45%, 750=0.01%, 1000=0.01% lat (msec): 2=0.01%, 4=0.02%, 10=0.01%, 20=0.01% Run status group 0 (all jobs): WRITE: io=20,480MB, aggrb=199MB/s, minb=204MB/s, maxb=204MB/s, mint=102698msec, maxt=102698msec Disk stats (read/write): sda: ios=0/655238, merge=0/0, ticks=0/79552, in_queue=78640, util=76.55% Run 2: test: (g=0): rw=write, bs=32K-32K/32K-32K, ioengine=sync, iodepth=1 Starting 1 process Jobs: 1 (f=1): [W] [100.0% done] [0K/0K /s] [0/0 iops] [eta 00m:00s] test: (groupid=0, jobs=1): err= 0: pid=4733 write: io=20,480MB, bw=91,265KB/s, iops=2,852, runt=229786msec clat (usec): min=16, max=127K, avg=349.53, stdev=4694.98 bw (KB/s) : min=56013, max=1390016, per=101.47%, avg=92607.31, stdev=167453.17 cpu : usr=0.41%, sys=6.93%, ctx=21128, majf=0, minf=33 IO depths : 1=100.0%, 2=0.0%, 4=0.0%, 8=0.0%, 16=0.0%, 32=0.0%, >=64=0.0% submit : 0=0.0%, 4=100.0%, 8=0.0%, 16=0.0%, 32=0.0%, 64=0.0%, >=64=0.0% complete : 0=0.0%, 4=100.0%, 8=0.0%, 16=0.0%, 32=0.0%, 64=0.0%, >=64=0.0% issued r/w: total=0/655360, short=0/0 lat (usec): 20=5.53%, 50=93.89%, 100=0.02%, 250=0.01%, 500=0.01% lat (msec): 2=0.01%, 4=0.01%, 10=0.01%, 20=0.01%, 50=0.12% lat (msec): 100=0.38%, 250=0.04% Run status group 0 (all jobs): WRITE: io=20,480MB, aggrb=91,265KB/s, minb=93,455KB/s, maxb=93,455KB/s, mint=229786msec, maxt=229786msec Disk stats (read/write): sda: ios=8/79811, merge=7/7721388, ticks=9/32418456, in_queue=32471983, util=98.98% I'm not knowledgeable enough with fio to interpret the results, but I don't expect the overall performance using the buffer cache to be 50% less than with O_DIRECT. Can someone help me interpret the fio output? Are there any kernel tunings that could fix/minimize the problem? Thanks a lot,

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  • Linux buffer cache effect on IO writes?

    - by Patrick LeBoutillier
    Hi, I'm copying large files (3 x 30G) between 2 filesystems on a Linux server (kernel 2.6.37, 16 cores, 32G RAM) and I'm getting poor performance. I suspect that the usage of the buffer cache is killing the I/O performance. To try and narrow down the problem I used fio directly on the SAS disk to monitor the performance. Here is the output of 2 fio runs (the first with direct=1, the second one direct=0): Config: [test] rw=write blocksize=32k size=20G filename=/dev/sda # direct=1 Run 1: test: (g=0): rw=write, bs=32K-32K/32K-32K, ioengine=sync, iodepth=1 Starting 1 process Jobs: 1 (f=1): [W] [100.0% done] [0K/205M /s] [0/6K iops] [eta 00m:00s] test: (groupid=0, jobs=1): err= 0: pid=4667 write: io=20,480MB, bw=199MB/s, iops=6,381, runt=102698msec clat (usec): min=104, max=13,388, avg=152.06, stdev=72.43 bw (KB/s) : min=192448, max=213824, per=100.01%, avg=204232.82, stdev=4084.67 cpu : usr=3.37%, sys=16.55%, ctx=655410, majf=0, minf=29 IO depths : 1=100.0%, 2=0.0%, 4=0.0%, 8=0.0%, 16=0.0%, 32=0.0%, >=64=0.0% submit : 0=0.0%, 4=100.0%, 8=0.0%, 16=0.0%, 32=0.0%, 64=0.0%, >=64=0.0% complete : 0=0.0%, 4=100.0%, 8=0.0%, 16=0.0%, 32=0.0%, 64=0.0%, >=64=0.0% issued r/w: total=0/655360, short=0/0 lat (usec): 250=99.50%, 500=0.45%, 750=0.01%, 1000=0.01% lat (msec): 2=0.01%, 4=0.02%, 10=0.01%, 20=0.01% Run status group 0 (all jobs): WRITE: io=20,480MB, aggrb=199MB/s, minb=204MB/s, maxb=204MB/s, mint=102698msec, maxt=102698msec Disk stats (read/write): sda: ios=0/655238, merge=0/0, ticks=0/79552, in_queue=78640, util=76.55% Run 2: test: (g=0): rw=write, bs=32K-32K/32K-32K, ioengine=sync, iodepth=1 Starting 1 process Jobs: 1 (f=1): [W] [100.0% done] [0K/0K /s] [0/0 iops] [eta 00m:00s] test: (groupid=0, jobs=1): err= 0: pid=4733 write: io=20,480MB, bw=91,265KB/s, iops=2,852, runt=229786msec clat (usec): min=16, max=127K, avg=349.53, stdev=4694.98 bw (KB/s) : min=56013, max=1390016, per=101.47%, avg=92607.31, stdev=167453.17 cpu : usr=0.41%, sys=6.93%, ctx=21128, majf=0, minf=33 IO depths : 1=100.0%, 2=0.0%, 4=0.0%, 8=0.0%, 16=0.0%, 32=0.0%, >=64=0.0% submit : 0=0.0%, 4=100.0%, 8=0.0%, 16=0.0%, 32=0.0%, 64=0.0%, >=64=0.0% complete : 0=0.0%, 4=100.0%, 8=0.0%, 16=0.0%, 32=0.0%, 64=0.0%, >=64=0.0% issued r/w: total=0/655360, short=0/0 lat (usec): 20=5.53%, 50=93.89%, 100=0.02%, 250=0.01%, 500=0.01% lat (msec): 2=0.01%, 4=0.01%, 10=0.01%, 20=0.01%, 50=0.12% lat (msec): 100=0.38%, 250=0.04% Run status group 0 (all jobs): WRITE: io=20,480MB, aggrb=91,265KB/s, minb=93,455KB/s, maxb=93,455KB/s, mint=229786msec, maxt=229786msec Disk stats (read/write): sda: ios=8/79811, merge=7/7721388, ticks=9/32418456, in_queue=32471983, util=98.98% I'm not knowledgeable enough with fio to interpret the results, but I don't expect the overall performance using the buffer cache to be 50% less than with O_DIRECT. Can someone help me interpret the fio output? Are there any kernel tunings that could fix/minimize the problem? Thanks a lot,

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  • RAID 50 24Port Fast Writes Slow Reads - Ubuntu

    - by James
    What is going on here?! I am baffled. serveradmin@FILESERVER:/Volumes/MercuryInternal/test$ sudo dd if=/dev/zero of=/Volumes/MercuryInternal/test/test.fs bs=4096k count=10000 10000+0 records in 10000+0 records out 41943040000 bytes (42 GB) copied, 57.0948 s, 735 MB/s serveradmin@FILESERVER:/Volumes/MercuryInternal/test$ sudo dd if=/Volumes/MercuryInternal/test/test.fs of=/dev/null bs=4096k count=10000 10000+0 records in 10000+0 records out 41943040000 bytes (42 GB) copied, 116.189 s, 361 MB/s OF NOTE: My RAID50 is 3 sets of 8 disks. - This might not be the best config for SPEED. OS: Ubuntu 12.04.1 x64 Hardware Raid: RocketRaid 2782 - 24 Port Controller HardDriveType: Seagate Barracuda ES.2 1TB Drivers: v1.1 Open Source Linux Drivers. So 24 x 1TB drives, partitioned using parted. Filesystem is ext4. I/O scheduler WAS noop but have changed it to deadline with no seemingly performance benefit/cost. serveradmin@FILESERVER:/Volumes/MercuryInternal/test$ sudo gdisk -l /dev/sdb GPT fdisk (gdisk) version 0.8.1 Partition table scan: MBR: protective BSD: not present APM: not present GPT: present Found valid GPT with protective MBR; using GPT. Disk /dev/sdb: 41020686336 sectors, 19.1 TiB Logical sector size: 512 bytes Disk identifier (GUID): 95045EC6-6EAF-4072-9969-AC46A32E38C8 Partition table holds up to 128 entries First usable sector is 34, last usable sector is 41020686302 Partitions will be aligned on 2048-sector boundaries Total free space is 5062589 sectors (2.4 GiB) Number Start (sector) End (sector) Size Code Name 1 2048 41015625727 19.1 TiB 0700 primary To me this should be working fine. I can't think of anything that would be causing this other then fundamental driver errors? I can't seem to get much/if any higher then the 361MB a second, is this hitting the "SATA2" link speed, which it shouldn't given it is a PCIe2.0 card. Or maybe some cacheing quirk - I do have Write Back enabled. Does anyone have any suggestions? Tests for me to perform? Or if you require more information, I am happy to provide it! This is a video fileserver for editing machines, so we have a preference for FAST reads over writes. I was just expected more from RAID 50 and 24 drives together... EDIT: (hdparm results) serveradmin@FILESERVER:/Volumes/MercuryInternal$ sudo hdparm -Tt /dev/sdb /dev/sdb: Timing cached reads: 17458 MB in 2.00 seconds = 8735.50 MB/sec Timing buffered disk reads: 884 MB in 3.00 seconds = 294.32 MB/sec EDIT2: (config details) Also, I am using a RAID block size of 256K. I was told a larger block size is better for larger (in my case large video) files. EDIT3: (Bonnie++ Results. Would love some guidance with this!)

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  • Firefox appending .xls extension to .xlsx files

    - by Chris Lively
    We are serving files with the .xlsx (excel 2007/2010) extension. IE, Chrome, Safari all download the file and open excel just fine. Firefox is being stupid. For some reason it's appending .xls to the extension. I found this: https://support.mozilla.com/bs/questions/758363 However, the instructions weren't very specific and completely unclear to me. How can I tell Firefox not to screw with the file extension? Thanks,

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  • Using dd command and running out of space while cloning drive to img

    - by Alan Kuras
    I have a problem with drive cloning. Im using dd on damaged disk with bad sectors trying to make an image from it. Im booting computer with Live Linux CD . Damaged disk: sda 146GB (NTFS) External drive: sdb 300GB (NTFS) After running the command below im running out of space on disk sdb. dd if=/dev/sda of=/dev/sdb/hdd.img bs=4096 conv=noerror,sync The question is why im running out of space on disk sdb ?

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