Search Results

Search found 12645 results on 506 pages for 'group policy'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 10/506 | < Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >

  • SCHA API for resource group failover / switchover history

    - by krishna.k.murthy
    The Oracle Solaris Cluster framework keeps an internal log of cluster events, including switchover and failover of resource groups. These logs can be useful to Oracle support engineers for diagnosing cluster behavior. However, till now, there was no external interface to access the event history. Oracle Solaris Cluster 4.2 provides a new API option for viewing the recent history of resource group switchovers in a program-parsable format. Oracle Solaris Cluster 4.2 provides a new option tag argument RG_FAILOVER_LOG for the existing API command scha_cluster_get which can be used to list recent failover / switchover events for resource groups. The command usage is as shown below: # scha_cluster_get -O RG_FAILOVER_LOG number_of_days number_of_days : the number of days to be considered for scanning the historical logs. The command returns a list of events in the following format. Each field is separated by a semi-colon [;]: resource_group_name;source_nodes;target_nodes;time_stamp source_nodes: node_names from which resource group is failed over or was switched manually. target_nodes: node_names to which the resource group failed over or was switched manually. There is a corresponding enhancement in the C API function scha_cluster_get() which uses the SCHA_RG_FAILOVER_LOG query tag. In the example below geo-infrastructure (failover resource group), geo-clusterstate (scalable resource group), oracle-rg (failover resource group), asm-dg-rg (scalable resource group) and asm-inst-rg (scalable resource group) are part of Geographic Edition setup. # /usr/cluster/bin/scha_cluster_get -O RG_FAILOVER_LOG 3 geo-infrastructure;schost1c;;Mon Jul 21 15:51:51 2014 geo-clusterstate;schost2c,schost1c;schost2c;Mon Jul 21 15:52:26 2014 oracle-rg;schost1c;;Mon Jul 21 15:54:31 2014 asm-dg-rg;schost2c,schost1c;schost2c;Mon Jul 21 15:54:58 2014 asm-inst-rg;schost2c,schost1c;schost2c;Mon Jul 21 15:56:11 2014 oracle-rg;;schost2c;Mon Jul 21 15:58:51 2014 geo-infrastructure;;schost2c;Mon Jul 21 15:59:19 2014 geo-clusterstate;schost2c;schost2c,schost1c;Mon Jul 21 16:01:51 2014 asm-inst-rg;schost2c;schost2c,schost1c;Mon Jul 21 16:01:10 2014 asm-dg-rg;schost2c;schost2c,schost1c;Mon Jul 21 16:02:10 2014 oracle-rg;schost2c;;Tue Jul 22 16:58:02 2014 oracle-rg;;schost1c;Tue Jul 22 16:59:05 2014 oracle-rg;schost1c;schost1c;Tue Jul 22 17:05:33 2014 Note that in the output some of the entries might have an empty string in the source_nodes. Such entries correspond to events in which the resource group is switched online manually or during a cluster boot-up. Similarly, an empty destination_nodes list indicates an event in which the resource group went offline. - Arpit Gupta, Harish Mallya

    Read the article

  • Percentage function for a group based on another group.

    - by Jeff O
    I have two grouping levels in a report. Group A can have a Percentage() of the entire report and so can Group B, but I would like to know the Percentage() of Group A of Group B. Even if I code it, it seems like once the inner and outer groups have created their footers, I can't go back to to the inner group and set it's value. Example: Group A Total 50 Group A percentage of Report Total = 33% Group A Percentage of Group B Total = 33% but I want 50% Group B Total 100 Group B Percentage of Report Total = 66% Report Total 150

    Read the article

  • Oracle Announces Oracle Insurance Policy Administration for Life and Annuity 9.4

    - by helen.pitts(at)oracle.com
    Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin;} Today's global insurers require the ability to provide higher levels of service and quickly bring to market life insurance and annuity products that not only help them stand out from the competition, but also stay current with local legislation. To succeed, they require agile and flexible core systems that enable them to meet the unique localization requirements of the markets in which they operate, whether in North America, Asia Pacific or the Pan-European Region. The release of Oracle Insurance Policy Administration for Life and Annuity 9.4, announced today, helps insurers meet this need with expanded international market capabilities that enable them to reduce risk and profitably compete wherever their business takes them. It offers expanded multi-language along with unit-linked product and fund processing capabilities that enable regional and global insurers to rapidly configure and deliver localized products – along with providing better service for end users through a single policy admin solution. Key enhancements include: Kanji/Kana language support, pre-defined content, and imperial date processing for the Japanese market New localization flexibility for configuring and managing international mailing addresses along with regional variations for client information Enhanced capability to calculate unit-linked pricing and valuation, in addition to market-based processing and pre-configured unit linked content Expanded role-based security and masking capability to further protect sensitive customer data Enhanced capability to restrict processing specified activities based on time of day and user role, reducing exposure to market timing risks Further capability to eliminate duplicate client records, helping to reduce underwriting risks and enhance servicing through a single view of the client "The ability to leverage a single, rules-driven policy administration system for multiple global operation centers can help insurers realize significant improvements in speed to market, customer service, compliance with regional regulations, and consolidation efforts,” noted Celent's Craig Weber, senior vice president, Insurance. “We believe such initiatives are necessary to help the industry address service and distribution imperatives." Helping our customers meet these mission-critical business imperatives is a key objective for Oracle Insurance. Active, ongoing dialogue with our customers is an important part of the process to help understand how our solutions are and can continue to help them achieve success in the marketplace. I had the opportunity to meet with several of our insurance customers at the Oracle Insurance Policy Administration Client Advisory Board meeting last week in Philadelphia, Penn. (View photos on the Oracle Insurance Facebook page.)   It was a great forum for Oracle Insurance and our clients. Discussion centered on the latest business and IT trends, with opportunities to learn more about the latest release of Oracle Insurance Policy Administration for Life and Annuity and other Oracle Insurance solutions such as data warehousing / business intelligence, while exchanging best practices for product innovation and servicing customers and sales channels. Helen Pitts is senior product marketing manager for Oracle Insurance's life and annuities solutions.

    Read the article

  • Select number of rows for each group where two column values makes one group

    - by Fábio Antunes
    I have a two select statements joined by UNION ALL. In the first statement a where clause gathers only rows that have been shown previously to the user. The second statement gathers all rows that haven't been shown to the user, therefore I end up with the viewed results first and non-viewed results after. Of course this could simply be achieved with the same select statement using a simple ORDER BY, however the reason for two separate selects is simple after you realize what I hope to accomplish. Consider the following structure and data. +----+------+-----+--------+------+ | id | from | to | viewed | data | +----+------+-----+--------+------+ | 1 | 1 | 10 | true | .... | | 2 | 10 | 1 | true | .... | | 3 | 1 | 10 | true | .... | | 4 | 6 | 8 | true | .... | | 5 | 1 | 10 | true | .... | | 6 | 10 | 1 | true | .... | | 7 | 8 | 6 | true | .... | | 8 | 10 | 1 | true | .... | | 9 | 6 | 8 | true | .... | | 10 | 2 | 3 | true | .... | | 11 | 1 | 10 | true | .... | | 12 | 8 | 6 | true | .... | | 13 | 10 | 1 | false | .... | | 14 | 1 | 10 | false | .... | | 15 | 6 | 8 | false | .... | | 16 | 10 | 1 | false | .... | | 17 | 8 | 6 | false | .... | | 18 | 3 | 2 | false | .... | +----+------+-----+--------+------+ Basically I wish all non viewed rows to be selected by the statement, that is accomplished by checking weather the viewed column is true or false, pretty simple and straightforward, nothing to worry here. However when it comes to the rows already viewed, meaning the column viewed is TRUE, for those records I only want 3 rows to be returned for each group. The appropriate result in this instance should be the 3 most recent rows of each group. +----+------+-----+--------+------+ | id | from | to | viewed | data | +----+------+-----+--------+------+ | 6 | 10 | 1 | true | .... | | 7 | 8 | 6 | true | .... | | 8 | 10 | 1 | true | .... | | 9 | 6 | 8 | true | .... | | 10 | 2 | 3 | true | .... | | 11 | 1 | 10 | true | .... | | 12 | 8 | 6 | true | .... | +----+------+-----+--------+------+ As you see from the ideal result set we have three groups. Therefore the desired query for the viewed results should show a maximum of 3 rows for each grouping it finds. In this case these groupings were 10 with 1 and 8 with 6, both which had three rows to be shown, while the other group 2 with 3 only had one row to be shown. Please note that where from = x and to = y, makes the same grouping as if it was from = y and to = x. Therefore considering the first grouping (10 with 1), from = 10 and to = 1 is the same group if it was from = 1 and to = 10. However there are plenty of groups in the whole table that I only wish the 3 most recent of each to be returned in the select statement, and thats my problem, I not sure how that can be accomplished in the most efficient way possible considering the table will have hundreds if not thousands of records at some point. Thanks for your help. Note: The columns id, from, to and viewed are indexed, that should help with performance. PS: I'm unsure on how to name this question exactly, if you have a better idea, be my guest and edit the title.

    Read the article

  • SQL Query - group by more than one column, but distinct

    - by Ranhiru
    I have a bidding table, as follows: SellID INT FOREIGN KEY REFERENCES SellItem(SellID), CusID INT FOREIGN KEY REFERENCES Customer(CusID), Amount FLOAT NOT NULL, BidTime DATETIME DEFAULT getdate() Now in my website I need to show the user the current bids; only the highest bid but without repeating the same user. SELECT CusID, Max(Amount) FROM Bid WHERE SellID = 10 GROUP BY CusID ORDER BY Max(Amount) DESC This is the best I have achieved so far. This gives the CusID of each user with the maximum bid and it is ordered ascending. But I need to get the BidTime for each result as well. When I try to put the BidTime in to the query: SELECT CusID, Max(Amount), BidTime FROM Bid WHERE SellID = 10 GROUP BY CusID ORDER BY Max(Amount) DESC I am told that "Column 'Bid.BidTime' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause." Thus I tried: SELECT CusID, Max(Amount), BidTime FROM Bid WHERE SellID = 10 GROUP BY CusID, BidTime ORDER BY Max(Amount) DESC But this returns all the rows. No distinction. Any suggestions on solving this issue?

    Read the article

  • sql query - how to apply limit within group by

    - by Raj
    hey guys assuming i have a table named t1 with following fields: ROWID, CID, PID, Score, SortKey it has the following data: 1, C1, P1, 10, 1 2, C1, P2, 20, 2 3, C1, P3, 30, 3 4, C2, P4, 20, 3 5, C2, P5, 30, 2 6, C3, P6, 10, 1 7, C3, P7, 20, 2 what query do i write so that it applies group by on CID, but instead of returning me 1 single result per group, it returns me a max of 2 results per group. also where condition is score = 20 and i want the results ordered by CID and SortKey. If I had to run my query on above data, i would expect the following result: RESULTS FOR C1 - note: ROWID 1 is not considered as its score < 20 C1, P2, 20, 2 C1, P3, 30, 3 RESULTS FOR C2 - note: ROWID 5 appears before ROWID 4 as ROWID 5 has lesser value SortKey C2, P5, 30, 2 C2, P4, 20, 3 RESULTS FOR C3 - note: ROWID 6 does not appear as its score is less than 20 so only 1 record returned here C3, P7, 20, 2 IN SHORT, I WANT A LIMIT WITHIN A GROUP BY. I want the simplest solution and want to avoid temp tables. sub queries are fine. also note i am using sqlite for this

    Read the article

  • Monitor SQL Server Agent Jobs with Policy Based Management

    I need to monitor all the SQL Agents to find out if a job failed in the last 24 hours. Could this be done with policy based management? If so, can you show me how to create the policy? Join SQL Backup’s 35,000+ customers to compress and strengthen your backups "SQL Backup will be a REAL boost to any DBA lucky enough to use it." Jonathan Allen. Download a free trial now.

    Read the article

  • Add a custom Ribbon group to an existing custom Ribbon group in word 2007

    - by SwiftLion
    Hi How can I add a new group to an existing (3rd party) custom ribbon tab add-in? I know that I can add to out of box ribbons by specifying the Tabs idMSo value but how do I do that for a custom ribbon tab. I have already tried the ID value of the custom ribbon, but it juts duplicates the ribbon? have also tried idMso and idQ attributes passing in the required custom tab Id but no success. I can add it to out of box tab group by specifying the idMso value but not to custom tab regards

    Read the article

  • C# LINQ: Join and Group

    - by Soo
    I have two tables TableA aId aValue TableB bId aId bValue I want to join these two tables via aId, and from there, group them by bValue var result = from a in db.TableA join b in db.TableB on a.aId equals b.aId group b by b.bValue into x select new {x}; My code doesn't recognize the join after the group. In other words, the grouping works, but the join doesn't (or at least I can't figure out how to access all of the data after the join). Any help would be appreciated. I'm a n00b.

    Read the article

  • Why do I need to explicitly specify all columns in a SQL "GROUP BY" clause - why not "GROUP BY *"?

    - by rwmnau
    This has always bothered me - why does the GROUP BY clause in a SQL statement require that I include all non-aggregate columns? These columns should be included by default - a kind of "GROUP BY *" - since I can't even run the query unless they're all included. Every column has to either be an aggregate or be specified in the "GROUP BY", but it seems like anything not aggregated should be automatically grouped. Maybe it's part of the ANSI-SQL standard, but even so, I don't understand why. Can somebody help me understand the need for this convention?

    Read the article

  • The use of GROUP BY in MySQL

    - by Gustav Bertram
    I'm fishing for a comprehensive and canonical answer for the typical "mysql group by?" question. Here is some sample data: TABLE A +------+------+----------+-----+ | id | foo | bar | baz | +------+------+----------+-----+ | 1 | 1 | hello | 42 | | 2 | 0 | apple | 96 | | 3 | 20 | boot | 11 | | 4 | 31 | unicorn | 99 | | 5 | 19 | pumpkin | 11 | | 6 | 88 | orange | 13 | +------+------+----------+-----+ TABLE B +------+------+ | id | moo | +------+------+ | 1 | 1 | | 2 | 99 | | 3 | 11 | +------+------+ Demonstrate and explain the correct use of the GROUP BY clause in MySQL. Touch upon the following points: The use of MIN, MAX, SUM, AVG The use of HAVING Grouping by date, and ranges of dates Grouping with an ORDER BY Grouping with a JOIN Grouping on multiple columns Bonus points for references to other great answers, the MySQL online manual, and online tutorials on GROUP BY.

    Read the article

  • Specify sorting order for a GROUP BY query to retrieve oldest or newest record for each group

    - by Beau Simensen
    I need to get the most recent record for each device from an upgrade request log table. A device is unique based on a combination of its hardware ID and its MAC address. I have been attempting to do this with GROUP BY but I am not convinced this is safe since it looks like it may be simply returning the "top record" (whatever SQLite or MySQL thinks that is). I had hoped that this "top record" could be hinted at by way of ORDER BY but that does not seem to be having any impact as both of the following queries returns the same records for each device, just in opposite order: SELECT extHwId, mac, created FROM upgradeRequest GROUP BY extHwId, mac ORDER BY created DESC SELECT extHwId, mac, created FROM upgradeRequest GROUP BY extHwId, mac ORDER BY created ASC Is there another way to accomplish this? I've seen several somewhat related posts that have all involved sub selects. If possible, I would like to do this without subselects as I would like to learn how to do this without that.

    Read the article

  • How do I prevent or override a group policy on Windows 7?

    - by Kevin
    A few months ago my company was purchased by a large corporation. We recently switched our network over to the large corporate network which has more restrictions requirements. One of these is the requirement to use a proxy server for Internet traffic. However, some of our internal servers are not recognized by the corporate DNS, so we need to provide the fully qualified domain name. For W7, we make changes to the Internet Properties for IE8 and Chrome to include our domain name as an exception to the proxy server (e.g., *.foobar.com). The problem is that a group policy that does not include our domain name is continually pushed out to my systems throughout the day. This requires me to make the appropriate changes to the Internet Properties several times a day in order to access our internal servers. Is there a way that I can prevent the group policy from being pushed to my systems or detect when the group policy is pushed and override it? I am an administrator on all of my systems. I do have Firefox installed which is not subject to the same group policy push, but I need to have IE8 and Chrome working.

    Read the article

  • How do I prevent or override a group policy on Windows 7?

    - by Kevin
    A few months ago my company was purchased by a large corporation. We recently switched our network over to the large corporate network which has more restrictions requirements. One of these is the requirement to use a proxy server for Internet traffic. However, some of our internal servers are not recognized by the corporate DNS, so we need to provide the fully qualified domain name. For W7, we make changes to the Internet Properties for IE8 and Chrome to include our domain name as an exception to the proxy server (e.g., *.foobar.com). The problem is that a group policy that does not include our domain name is continually pushed out to my systems throughout the day. This requires me to make the appropriate changes to the Internet Properties several times a day in order to access our internal servers. Is there a way that I can prevent the group policy from being pushed to my systems or detect when the group policy is pushed and override it? I am an administrator on all of my systems. I do have Firefox installed which is not subject to the same group policy push, but I need to have IE8 and Chrome working.

    Read the article

  • I deployed Flash Player via a Software Installation policy. How to upgrade?

    - by eleven81
    I have a Windows Server 2008 machine as my DC. Earlier this year I created a Software Installation GPO to deploy Adobe Flash Player plugin MSI. I assigned the policy to the computers, about half run Windows XP x86 and the other half Windows 7 x64. That all works like clockwork. When I created the Software Installation Policy, I disabled the Flash Player plugin's automatic update feature by editing the MSI in Orca. I did this because I wanted all of my machines to run the exact same version of the plugin. Now, some time has passed and a newer version of the Flash Player plugin has been released. It is time for me to push out the updated version of the plugin. I already have the new MSI, but I am lost on what to do next. I see the upgrades tab in the Software Installation GPO, but everything there reads like that would be used for add-ons to a larger master program and not for updates that are released over time. I have read that it is best to create a new Software Installation policy with the new MSI, revoke the old GPO, and assign the new GPO. I feel as though, over time, I will wind up with more revoked policies than active ones. I have also read that some people have had success by replacing the old MSI with the new MSI and simply telling the GPO to redeploy. This seems like a backdoor method that will only get me in to trouble. In short, what is the correct, best-practice, or preferred way to roll out the new version via Group Policy?

    Read the article

  • Allow sudo on specific file from active directory group

    - by tubaguy50035
    I have an Ubuntu Server 12.04 box that has active directory integration running on it. I want to allow a certain active directory group access to execute a script as sudo. I want to do something like this: %programmers ALL=NOPASSWD: /usr/local/bin/createSambaShare.php When I log in with my active directory user and issue groups I do not see the group programmers, but I am a part of the programmers group within active directory. I've set up the group under the Unix attributes tab and given it an id of 1000 and added my user to it. My first thought was that I needed to add the group to the Ubuntu box. When I tried to do that, it told me that the programmers group already existed. What am I missing here?

    Read the article

  • The Unintended Consequences of Sound Security Policy

    - by Tanu Sood
    v\:* {behavior:url(#default#VML);} o\:* {behavior:url(#default#VML);} w\:* {behavior:url(#default#VML);} .shape {behavior:url(#default#VML);} Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Calibri","sans-serif"; mso-bidi-font-family:"Times New Roman";} Author: Kevin Moulton, CISSP, CISM Meet the Author: Kevin Moulton, Senior Sales Consulting Manager, Oracle Kevin Moulton, CISSP, CISM, has been in the security space for more than 25 years, and with Oracle for 7 years. He manages the East Enterprise Security Sales Consulting Team. He is also a Distinguished Toastmaster. Follow Kevin on Twitter at twitter.com/kevin_moulton, where he sometimes tweets about security, but might also tweet about running, beer, food, baseball, football, good books, or whatever else grabs his attention. Kevin will be a regular contributor to this blog so stay tuned for more posts from him. When I speak to a room of IT administrators, I like to begin by asking them if they have implemented a complex password policy. Generally, they all nod their heads enthusiastically. I ask them if that password policy requires long passwords. More nodding. I ask if that policy requires upper and lower case letters – faster nodding – numbers – even faster – special characters – enthusiastic nodding all around! I then ask them if their policy also includes a requirement for users to regularly change their passwords. Now we have smiles with the nodding! I ask them if the users have different IDs and passwords on the many systems that they have access to. Of course! I then ask them if, when they walk around the building, they see something like this: Thanks to Jake Ludington for the nice example. Can these administrators be faulted for their policies? Probably not but, in the end, end-users will find a way to get their job done efficiently. Post-It Notes to the rescue! I was visiting a business in New York City one day which was a perfect example of this problem. First I walked up to the security desk and told them where I was headed. They asked me if they should call upstairs to have someone escort me. Is that my call? Is that policy? I said that I knew where I was going, so they let me go. Having the conference room number handy, I wandered around the place in a search of my destination. As I walked around, unescorted, I noticed the post-it note problem in abundance. Had I been so inclined, I could have logged in on almost any machine and into any number of systems. When I reached my intended conference room, I mentioned my post-it note observation to the two gentlemen with whom I was meeting. One of them said, “You mean like this,” and he produced a post it note full of login IDs and passwords from his breast pocket! I gave him kudos for not hanging the list on his monitor. We then talked for the rest of the meeting about the difficulties faced by the employees due to the security policies. These policies, although well-intended, made life very difficult for the end-users. Most users had access to 8 to 12 systems, and the passwords for each expired at a different times. The post-it note solution was understandable. Who could remember even half of them? What could this customer have done differently? I am a fan of using a provisioning system, such as Oracle Identity Manager, to manage all of the target systems. With OIM, and email could be automatically sent to all users when it was time to change their password. The end-users would follow a link to change their password on a web page, and then OIM would propagate that password out to all of the systems that the user had access to, even if the login IDs were different. Another option would be an Enterprise Single-Sign On Solution. With Oracle eSSO, all of a user’s credentials would be stored in a central, encrypted credential store. The end-user would only have to login to their machine each morning and then, as they moved to each new system, Oracle eSSO would supply the credentials. Good-bye post-it notes! 3M may be disappointed, but your end users will thank you. I hear people say that this post-it note problem is not a big deal, because the only people who would see the passwords are fellow employees. Do you really know who is walking around your building? What are the password policies in your business? How do the end-users respond?

    Read the article

  • SQL Group By Modulo of Row Count

    - by Alex Czarto
    I have the following sample data: Id Name Quantity 1 Red 1 2 Red 3 3 Blue 1 4 Red 1 5 Yellow 3 So for this example, there are a total of 5 Red, 1 Blue, and 3 Yellow. I am looking for a way to group them by Color, but with a maximum of 2 items per group (sorting is not important). Like so: Name QuantityInPackage Red 2 Red 2 Red 1 Blue 1 Yellow 2 Yellow 1 Any suggestions on how to accomplish this using T-SQL on MS-SQL 2005?

    Read the article

  • SQL Server Update Group by

    - by Gerardo Abdo
    I'm trying to execute this on MS-SQL but returns me an error just at the Group by line update #temp Set Dos=Count(1) From Temp_Table2010 s where Id=s.Total and s.total in (Select Id from #temp) group by s.Total Do anyone knows how can I solve this problem having good performance.

    Read the article

  • How to do a case sensitive GROUP BY?

    - by Abe Miessler
    If I execute the code below: with temp as ( select 'Test' as name UNION ALL select 'TEST' UNION ALL select 'test' UNION ALL select 'tester' UNION ALL select 'tester' ) SELECT name, COUNT(name) FROM temp group by name It returns the results: TEST 3 tester 2 Is there a way to have the group by be case sensitive so that the results would be: Test 1 TEST 1 test 1 tester 2

    Read the article

  • Is it possible to have a local group for an LDAP user

    - by fakedrake
    I have an LDAP server to which i do not have full privileges and an ubuntu system with LDAP authentication to which i am root. Is it possible to add an LDAP user to a local group? (i dont know if i phrase this correctly but all i want is to have a user in LDAP in a group without edititing the actual database)

    Read the article

  • How Can I prevent a specific application from being run on a specific machine using Group Policy?

    - by Mike
    I know this is possible to do and I am working on it with limited success. I believe the Group Policy I want is "Do Not Run Specified Windows Applications" - I can enable this and add the .exe I want to the list of programs not to be run. I have tried this on my local machine by running gpedit.msc going to User Config Admin Templates System and then choosing that policy and editing and enabling it. Doing it this way verifies that it works as I could then not run the specified .exe (XenAppWeb.exe) So this is great. I have created a GPO to do the same thing in GP Management on my domain controller where we centralize this, enforced it, applied it to an OU, and put one of our machines into this OU to test it. I have let it sit there for 3 days, run gpupdate /force, and when I try to run XenAppWeb.exe on this machine, it still lets me run it fine. What can I look at to troubleshoot this? I should note that I am trying to enact this policy on Windows XP machines (Virtual Machines) Thanks, Mike

    Read the article

  • Windows AD: Is loopback processing absolutely necessary in order to apply a user policy to users logging into computers in the OU?

    - by Brett
    I've had our AD setup running on server 2008r2 and now 2012, and I swear, a user policy applied to an OU containing only computers actually does apply to users logging into those computers, without loopback processing enabled. Everything I read seems to say that is not how it should work, but it does. Is this normal behavior? Just tested again - created a policy with a drive map (which is a user policy), applied it to an OU containing my terminal server, forced a gpupdate, logged out/in, and sure enough, the drive is mapped. I did NOT turn on loopback processing.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >