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• Recover RAID 5 data after created new array instead of re-using

  - by Brigadieren

  Folks please help - I am a newb with a major headache at hand (perfect storm situation). I have a 3 1tb hdd on my ubuntu 11.04 configured as software raid 5. The data had been copied weekly onto another separate off the computer hard drive until that completely failed and was thrown away. A few days back we had a power outage and after rebooting my box wouldn't mount the raid. In my infinite wisdom I entered mdadm --create -f... command instead of mdadm --assemble and didn't notice the travesty that I had done until after. It started the array degraded and proceeded with building and syncing it which took ~10 hours. After I was back I saw that that the array is successfully up and running but the raid is not I mean the individual drives are partitioned (partition type f8 ) but the md0 device is not. Realizing in horror what I have done I am trying to find some solutions. I just pray that --create didn't overwrite entire content of the hard driver. Could someone PLEASE help me out with this - the data that's on the drive is very important and unique ~10 years of photos, docs, etc. Is it possible that by specifying the participating hard drives in wrong order can make mdadm overwrite them? when I do mdadm --examine --scan I get something like ARRAY /dev/md/0 metadata=1.2 UUID=f1b4084a:720b5712:6d03b9e9:43afe51b name=<hostname>:0 Interestingly enough name used to be 'raid' and not the host hame with :0 appended. Here is the 'sanitized' config entries: DEVICE /dev/sdf1 /dev/sde1 /dev/sdd1 CREATE owner=root group=disk mode=0660 auto=yes HOMEHOST <system> MAILADDR root ARRAY /dev/md0 metadata=1.2 name=tanserv:0 UUID=f1b4084a:720b5712:6d03b9e9:43afe51b Here is the output from mdstat cat /proc/mdstat Personalities : [linear] [multipath] [raid0] [raid1] [raid6] [raid5] [raid4] [raid10] md0 : active raid5 sdd1[0] sdf1[3] sde1[1] 1953517568 blocks super 1.2 level 5, 512k chunk, algorithm 2 [3/3] [UUU] unused devices: <none> fdisk shows the following: fdisk -l Disk /dev/sda: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000bf62e Device Boot Start End Blocks Id System /dev/sda1 * 1 9443 75846656 83 Linux /dev/sda2 9443 9730 2301953 5 Extended /dev/sda5 9443 9730 2301952 82 Linux swap / Solaris Disk /dev/sdb: 750.2 GB, 750156374016 bytes 255 heads, 63 sectors/track, 91201 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000de8dd Device Boot Start End Blocks Id System /dev/sdb1 1 91201 732572001 8e Linux LVM Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00056a17 Device Boot Start End Blocks Id System /dev/sdc1 1 60801 488384001 8e Linux LVM Disk /dev/sdd: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000ca948 Device Boot Start End Blocks Id System /dev/sdd1 1 121601 976760001 fd Linux raid autodetect Disk /dev/dm-0: 1250.3 GB, 1250254913536 bytes 255 heads, 63 sectors/track, 152001 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-0 doesn't contain a valid partition table Disk /dev/sde: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x93a66687 Device Boot Start End Blocks Id System /dev/sde1 1 121601 976760001 fd Linux raid autodetect Disk /dev/sdf: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xe6edc059 Device Boot Start End Blocks Id System /dev/sdf1 1 121601 976760001 fd Linux raid autodetect Disk /dev/md0: 2000.4 GB, 2000401989632 bytes 2 heads, 4 sectors/track, 488379392 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 524288 bytes / 1048576 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Per suggestions I did clean up the superblocks and re-created the array with --assume-clean option but with no luck at all. Is there any tool that will help me to revive at least some of the data? Can someone tell me what and how the mdadm --create does when syncs to destroy the data so I can write a tool to un-do whatever was done? After the re-creating of the raid I run fsck.ext4 /dev/md0 and here is the output root@tanserv:/etc/mdadm# fsck.ext4 /dev/md0 e2fsck 1.41.14 (22-Dec-2010) fsck.ext4: Superblock invalid, trying backup blocks... fsck.ext4: Bad magic number in super-block while trying to open /dev/md0 The superblock could not be read or does not describe a correct ext2 filesystem. If the device is valid and it really contains an ext2 filesystem (and not swap or ufs or something else), then the superblock is corrupt, and you might try running e2fsck with an alternate superblock: e2fsck -b 8193 Per Shanes' suggestion I tried root@tanserv:/home/mushegh# mkfs.ext4 -n /dev/md0 mke2fs 1.41.14 (22-Dec-2010) Filesystem label= OS type: Linux Block size=4096 (log=2) Fragment size=4096 (log=2) Stride=128 blocks, Stripe width=256 blocks 122101760 inodes, 488379392 blocks 24418969 blocks (5.00%) reserved for the super user First data block=0 Maximum filesystem blocks=0 14905 block groups 32768 blocks per group, 32768 fragments per group 8192 inodes per group Superblock backups stored on blocks: 32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208, 4096000, 7962624, 11239424, 20480000, 23887872, 71663616, 78675968, 102400000, 214990848 and run fsck.ext4 with every backup block but all returned the following: root@tanserv:/home/mushegh# fsck.ext4 -b 214990848 /dev/md0 e2fsck 1.41.14 (22-Dec-2010) fsck.ext4: Invalid argument while trying to open /dev/md0 The superblock could not be read or does not describe a correct ext2 filesystem. If the device is valid and it really contains an ext2 filesystem (and not swap or ufs or something else), then the superblock is corrupt, and you might try running e2fsck with an alternate superblock: e2fsck -b 8193 <device> Any suggestions? Regards!

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• Sql 2005 problem in set up

  - by kareemsaad

  When I setup sql2005 this problem appear Minimum Hardware Requirement (Warning) Messages Minimum Hardware Requirement The current system does not meet the minimum hardware requirements for this SQL Server release. For detailed hardware and software requirements, see the readme file or SQL Server Books Online. and I continued setup but I couldnot found sql management studio tools in start menue

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• Openvz: What exactly does it mean when tcpsndbuf failcnt increases? Why must there be a minimum difference between limit and barrier?

  - by Antonis Christofides

  When the failcnt of tcpsndbuf increases, what does this mean? Does it mean the system had to go past the barrier, or past the limit? Or, maybe, that the system failed to provide enough buffers, either because it needed to go past the limit, or because it needed to go past the barrier but couldn't because other VMs were using too many resources? I understand the difference between barrier and limit only for disk space, where you can specify a grace period for which the system can exceed the barrier but not the limit. But in resources like tcpsndbuf, which have no such thing as a grace period, what is the meaning of barrier vs. limit? Why does the difference between barrier and limit in tcpsndbuf be at least 2.5KB times tcpnumsock? I could understand it if, e.g., tcpsndbuf should be at least 2.5KB times tcpnumsock (either the barrier or the limit), but why should I care about the difference between the barrier and the limit?

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• swapon --all --verbose : 'read swap header failed: Invalid argument'

  - by user66088

  Recently ran through EnableHibernateWithEncryptedSwap and ran the following command: swapon --all --verbose and received: 'read swap header failed: Invalid argument' How do I fix this? Here's some more pertinent output... Output of sudo fdisk -l: Disk /dev/sda: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders, total 156301488 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00006d20 Device Boot Start End Blocks Id System /dev/sda1 * 2048 499711 248832 83 Linux /dev/sda2 501758 156301311 77899777 5 Extended /dev/sda5 501760 156301311 77899776 8e Linux LVM Disk /dev/mapper/ubuntu--t10194-root: 75.5 GB, 75539415040 bytes 255 heads, 63 sectors/track, 9183 cylinders, total 147537920 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/ubuntu--t10194-root doesn't contain a valid partition table Disk /dev/mapper/ubuntu--t10194-swap_1: 4227 MB, 4227858432 bytes 255 heads, 63 sectors/track, 514 cylinders, total 8257536 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x08040000 Disk /dev/mapper/ubuntu--t10194-swap_1 doesn't contain a valid partition table Disk /dev/mapper/cryptswap1: 4225 MB, 4225761280 bytes 255 heads, 63 sectors/track, 513 cylinders, total 8253440 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xd2236983 Disk /dev/mapper/cryptswap1 doesn't contain a valid partition table Thanks for any and ALL help!

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• mount another drive to the same directory

  - by Ken Autotron

  I recently purchased a server that was advertised as 2TB (2 1TB drives) in size, when I use it it reports only one of the drives, I would like to be able to use both as if one drive. here is the specs... sudo lshw -C disk *-disk description: ATA Disk product: TOSHIBA DT01ACA1 vendor: Toshiba physical id: 0.0.0 bus info: scsi@1:0.0.0 logical name: /dev/sda version: MS2O serial: 13EJ81XPS size: 931GiB (1TB) capabilities: partitioned partitioned:dos configuration: ansiversion=5 signature=0005b3dd *-disk description: ATA Disk product: TOSHIBA DT01ACA1 vendor: Toshiba physical id: 0.0.0 bus info: scsi@4:0.0.0 logical name: /dev/sdb version: MS2O serial: 13OX3TKPS size: 931GiB (1TB) capabilities: partitioned partitioned:dos configuration: ansiversion=5 signature=00030e86 and fdisk -l Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00030e86 Device Boot Start End Blocks Id System /dev/sdb1 * 4096 41947135 20971520 fd Linux raid autodetect /dev/sdb2 41947136 1952468991 955260928 fd Linux raid autodetect /dev/sdb3 1952468992 1953519615 525312 82 Linux swap / Solaris Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x0005b3dd Device Boot Start End Blocks Id System /dev/sda1 * 4096 41947135 20971520 fd Linux raid autodetect /dev/sda2 41947136 1952468991 955260928 fd Linux raid autodetect /dev/sda3 1952468992 1953519615 525312 82 Linux swap / Solaris Disk /dev/md2: 978.2 GB, 978187124736 bytes 2 heads, 4 sectors/track, 238815216 cylinders, total 1910521728 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Disk /dev/md2 doesn't contain a valid partition table Disk /dev/md1: 21.5 GB, 21474770944 bytes 2 heads, 4 sectors/track, 5242864 cylinders, total 41942912 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Disk /dev/md1 doesn't contain a valid partition table is it possible to mount both drives to say /Home/ so I would have 2TB of usable space?

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• format/build raid 5 with one 4k drive, three 512b

  - by skidawgz

  I have 4 WD 1TB drives which I want to 4x1TB Raid5. I am not sure what course of action to take next. How do I configure my 4th drive (sde) to align with the rest? Will this affect performance? I rcv this msg (which brings me here to ask these question): The device presents a logical sector size that is smaller than the physical sector size. Aligning to a physical sector (or optimal I/O) size boundary is recommended, or performance may be impacted. fdisk -l shows: Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 81 heads, 63 sectors/track, 382818 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xf324ba09 Device Boot Start End Blocks Id System /dev/sdb1 2048 1953525167 976761560 fd Linux raid autodetect Disk /dev/sdc: 1000.2 GB, 1000204886016 bytes 81 heads, 63 sectors/track, 382818 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x38bcc1f0 Device Boot Start End Blocks Id System /dev/sdc1 2048 1953525167 976761560 fd Linux raid autodetect Disk /dev/sdd: 1000.2 GB, 1000204886016 bytes 81 heads, 63 sectors/track, 382818 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x570f77e7 Device Boot Start End Blocks Id System /dev/sdd1 2048 1953525167 976761560 fd Linux raid autodetect Disk /dev/sde: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0xeb665e7b Device Boot Start End Blocks Id System

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• Product Search SEO

  - by dana

  I am a wondering if there is a recommended "best practice" for a product search SEO. I know to create a dynamic sitemap file that lists links to all products in the site. However, I want to implement a a bookmark-able "advanced search". Should I let search engines index any of the results? Take the following parameters for a search on a make believe used car website: minprice (minimum price in dollars) maxprice (maximum price in dollars) make (honda, audi, volvo) model (accord, A4, S40) minyear (minimum model year) maxyear (maximum model year) minmileage (minimum mileage) maxmileage (maximum mileage) Given these parameters, there could be an infinite number of search combinations: Price Between $10,000 and $20,000 /search?minprice=10000&maxprice&20000 Audis with less than 50k miles /search?model=audi&maxmileage=50000 More than 100,000 miles and less than $5,000 /search?minmileage=100000&maxprice=5000 etc. Over time, there may be inbound links to a variety of these types of searches, yet they are all slices of the same data. Should I allow for all of these searches to be indexed?

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• SEO for a list of products with filters

  - by dana

  I am a wondering if there is a recommended "best practice" for a product search SEO. I know to create a dynamic sitemap file that lists links to all products in the site. However, I want to implement a a bookmark-able "advanced search". Should I let search engines index any of the results? Take the following parameters for a search on a make believe used car website: minprice (minimum price in dollars) maxprice (maximum price in dollars) make (honda, audi, volvo) model (accord, A4, S40) minyear (minimum model year) maxyear (maximum model year) minmileage (minimum mileage) maxmileage (maximum mileage) Given these parameters, there could be an infinite number of search combinations: Price Between $10,000 and $20,000 /search?minprice=10000&maxprice&20000 Audis with less than 50k miles /search?model=audi&maxmileage=50000 More than 100,000 miles and less than $5,000 /search?minmileage=100000&maxprice=5000 etc. Over time, there may be inbound links to a variety of these types of searches, yet they are all slices of the same data. Should I allow for all of these searches to be indexed?

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• SQL SERVER – A Puzzle Part 4 – Fun with SEQUENCE in SQL Server 2012 – Guess the Next Value

  - by pinaldave

  It seems like every weekend I get a new puzzle in my mind. Before continuing I suggest you read my previous posts here where I have shared earlier puzzles. A Puzzle – Fun with SEQUENCE in SQL Server 2012 – Guess the Next Value  A Puzzle Part 2 – Fun with SEQUENCE in SQL Server 2012 – Guess the Next Value A Puzzle Part 3 – Fun with SEQUENCE in SQL Server 2012 – Guess the Next Value After reading above three posts, I am very confident that you all will be ready for the next set of puzzles now. First execute the script which I have written here. Now guess what will be the next value as requested in the query. USE TempDB GO -- Create sequence CREATE SEQUENCE dbo.SequenceID AS DECIMAL(3,0) START WITH 1 INCREMENT BY -1 MINVALUE 1 MAXVALUE 3 CYCLE NO CACHE; GO SELECT next value FOR dbo.SequenceID; -- Guess the number SELECT next value FOR dbo.SequenceID; -- Clean up DROP SEQUENCE dbo.SequenceID; GO Please note that Starting value is 1, Increment value is the negative value of -1 and Minimum value is 3. Now let us first assume how this will work out. In our example of the sequence starting value is equal to 1 and decrement value is -1, this means the value should decrement from 1 to 0. However, the minimum value is 1. This means the value cannot further decrement at all. What will happen here? The natural assumption is that it should throw an error. How many of you are assuming about query will throw an ERROR? Well, you are WRONG! Do not blame yourself, it is my fault as I have told you only half of the story. Now if you have voted for error, let us continue running above code in SQL Server Management Studio. The above script will give the following output: Isn’t it interesting that instead of error out it is giving us result value 3. To understand the answer about the same, carefully observe the original syntax of creating SEQUENCE – there is a keyword CYCLE. This keyword cycles the values between the minimum and maximum value and when one of the range is exhausted it cycles the values from the other end of the cycle. As we have negative incremental value when query reaches to the minimum value or lower end it will cycle it from the maximum value. Here the maximum value is 3 so the next logical value is 3. If your business requirement is such that if sequence reaches the maximum or minimum value, it should throw an error, you should not use the keyword cycle, and it will behave as discussed. I hope, you are enjoying the puzzles as much as I am enjoying it. If you have any interesting puzzle to share, please do share with me and I will share this on blog with due credit to you. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

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• Extending Python’s int type to accept only values within a given range

  - by igor

  I would like to create a custom data type which basically behaves like an ordinary int, but with the value restricted to be within a given range. I guess I need some kind of factory function, but I cannot figure out how to do it. myType = MyCustomInt(minimum=7, maximum=49, default=10) i = myType(16) # OK i = myType(52) # raises ValueError i = myType() # i == 10 positiveInt = MyCustomInt(minimum=1) # no maximum restriction negativeInt = MyCustomInt(maximum=-1) # no minimum restriction nonsensicalInt = MyCustomInt() # well, the same as an ordinary int Any hint is appreciated. Thanks!

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• a question on common lisp

  - by kostas

  Hello people, I'm getting crazy with a small problem here, I keep getting an error and I cant seem to figure out why, the code is supposed to change the range of a list, so if we give it a list with values (1 2 3 4) and we want to change the range in 11 to fourteen the result would be (11 12 13 14) the problem is that the last function called scale-list will give back an error saying: Debugger entered--Lisp error: (wrong-type-argument number-or-marker-p nil) anybody has a clue why? I use aquamacs as an editor thanks in advance ;;finds minimum in a list (defun minimum(list) (car (sort list #'<))) ;;finds maximum in a list (defun maximum(list) (car (sort list #'>))) ;;calculates the range of a list (defun range(list) (- (maximum list) (minimum list))) ;;this codes scales a value from a list (defun scale-value(list low high n) (+ (/ (* (- (nth (- n 1) list) (minimum list)) (- high low)) (range list)) low)) ;and this code is supposed to scale the whole list (defun scale-list(list low high n) (unless (= n 0) (cons (scale-value list low high n) (scale-list list low high (- n 1))))) (scale-list '(0.1 0.3 0.5 0.9) 20 30 4)

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• Deletion procedure for a Binary Search Tree

  - by Metz

  Consider the deletion procedure on a BST, when the node to delete has two children. Let's say i always replace it with the node holding the minimum key in its right subtree. The question is: is this procedure commutative? That is, deleting x and then y has the same result than deleting first y and then x? I think the answer is no, but i can't find a counterexample, nor figure out any valid reasoning. EDIT: Maybe i've got to be clearer. Consider the transplant(node x, node y) procedure: it replace x with y (and its subtree). So, if i want to delete a node (say x) which has two children i replace it with the node holding the minimum key in its right subtree: y = minimum(x.right) transplant(y, y.right) // extracts the minimum (it doesn't have left child) y.right = x.right y.left = x.left transplant(x,y) The question was how to prove the procedure above is not commutative.

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• & ' " < > blah & ' " < > blah & ' " < > blah

  - by cfaweflj

  testr question couldn't be submitted because: * body must be at least 15 characters; you entered 4 * title too short; minimum length 15 r question couldn't be submitted because: * body must be at least 15 characters; you entered 4 * title too short; minimum length 15 r question couldn't be submitted because: * body must be at least 15 characters; you entered 4 * title too short; minimum length 15

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• Find subset with K elements that are closest to eachother

  - by Nima

  Given an array of integers size N, how can you efficiently find a subset of size K with elements that are closest to each other? Let the closeness for a subset (x1,x2,x3,..xk) be defined as: 2 <= N <= 10^5 2 <= K <= N constraints: Array may contain duplicates and is not guaranteed to be sorted. My brute force solution is very slow for large N, and it doesn't check if there's more than 1 solution: N = input() K = input() assert 2 <= N <= 10**5 assert 2 <= K <= N a = [] for i in xrange(0, N): a.append(input()) a.sort() minimum = sys.maxint startindex = 0 for i in xrange(0,N-K+1): last = i + K tmp = 0 for j in xrange(i, last): for l in xrange(j+1, last): tmp += abs(a[j]-a[l]) if(tmp > minimum): break if(tmp < minimum): minimum = tmp startindex = i #end index = startindex + K? Examples: N = 7 K = 3 array = [10,100,300,200,1000,20,30] result = [10,20,30] N = 10 K = 4 array = [1,2,3,4,10,20,30,40,100,200] result = [1,2,3,4]

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• What are Android different screens dimensions in dp for different screens (e.g. xlarge = 960dp x 720dp)?

  - by Zizo

  in this link: Range of screens supported, Android team mentioned that: As you design your UI for different screen sizes, you'll discover that each design requires a minimum amount of space. So, each generalized screen size above has an associated minimum resolution that's defined by the system. These minimum sizes are in "dp" units—the same units you should use when defining your layouts—which allows the system to avoid worrying about changes in screen density. xlarge screens are at least 960dp x 720dp large screens are at least 640dp x 480dp normal screens are at least 470dp x 320dp small screens are at least 426dp x 320dp So, If I want to support all Android screens, can I create images, for full screen view, in those dimensions and that will be sufficient condition to support all available screens? or they are just the minimum sizes, and I need other dimensions? If other dimensions are needed, Please list them as in the list above. Thanks in Advance.

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• [BST] Deletion procedure

  - by Metz

  Hi all. Consider the deletion procedure on a BST, when the node to delete has two children. Let's say i always replace it with the node holding the minimum key in its right subtree. The question is: is this procedure commutative? That is, deleting x and then y has the same result than deleting first y and then x? I think the answer is no, but i can't find a counterexample, nor figure out any valid reasoning. Thank you. EDIT: Maybe i've got to be clearer. Consider the transplant(node x, node y) procedure: it replace x with y (and its subtree). So, if i want to delete a node (say x) which has two children i replace it with the node holding the minimum key in its right subtree: y = minimum(x.right) transplant(y, y.right) // extracts the minimum (it doesn't have left child) y.right = x.right y.left = x.left transplant(x,y) The question was how to prove the procedure above is not commutative.

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• Regular Expression - Password Validation is not working

  - by Kesavan

  Hi, I have to validate the password using regex. The password rule is like at least 1 uppercase and at least 2 numeric. It works fine except if the character comes at the end of the string. The regular expression which i am using is "^(?=.*\d.{2})(?=.*[A-Z].{1})(?=.*[@#$%^&+=].{2}).{8,12}$" Rules: minimum length = 8 minimum uppercase = 1 minimum numeric = 2 minimum special character = 1 It works for Test123$$, Test$123, TEST123$s, Test123$1, Test12$3 but it fails if the character specified comes at the end of the string like Test123$, Test$a12, Test12aa@, 123aa@@T. Please let me know if there is any fix for this.

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• Sql2005 Setup Problem

  - by KareemSaad

  When I setup sql2005 this problem appear Minimum Hardware Requirement (Warning) Messages Minimum Hardware Requirement The current system does not meet the minimum hardware requirements for this SQL Server release. For detailed hardware and software requirements, see the readme file or SQL Server Books Online. and I continued setup but I couldnot found sql management studio tools in start menue

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• Adding Extra Hard Drives Debian Fdisk

  - by Belgin Fish

  well I just got a new server and it's a little different than what I'm use to, when I run cfdisk I get WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 3000.6 GB, 3000592982016 bytes 255 heads, 63 sectors/track, 364801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sda1 1 267350 2147483647+ ee GPT Partition 1 does not start on physical sector boundary. WARNING: GPT (GUID Partition Table) detected on '/dev/sdb'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sdb: 3000.6 GB, 3000592982016 bytes 255 heads, 63 sectors/track, 364801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sdb1 1 267350 2147483647+ ee GPT Partition 1 does not start on physical sector boundary. WARNING: GPT (GUID Partition Table) detected on '/dev/sdc'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sdc: 3000.6 GB, 3000592982016 bytes 255 heads, 63 sectors/track, 364801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sdc1 1 267350 2147483647+ ee GPT Partition 1 does not start on physical sector boundary. WARNING: GPT (GUID Partition Table) detected on '/dev/sdd'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sdd: 3000.6 GB, 3000592982016 bytes 255 heads, 63 sectors/track, 364801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sdd1 1 267350 2147483647+ ee GPT Partition 1 does not start on physical sector boundary. WARNING: GPT (GUID Partition Table) detected on '/dev/sdf'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sdf: 3000.6 GB, 3000592982016 bytes 255 heads, 63 sectors/track, 364801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sdf1 1 267350 2147483647+ ee GPT Partition 1 does not start on physical sector boundary. WARNING: GPT (GUID Partition Table) detected on '/dev/sde'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sde: 3000.6 GB, 3000592982016 bytes 255 heads, 63 sectors/track, 364801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sde1 1 267350 2147483647+ ee GPT Partition 1 does not start on physical sector boundary. Usually it tells me which ones arn't partitioned and stuff, and I only have 6 drives in my server and there's 6 showing up here so I'm only assuming the first ones already mounted and formatted correctly? I'm not really sure if anyone would help me out here. Basically I just want to format and mount these drives :)

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• Random Position between ranges.

  - by blakey87

  Does anyone have a good algorithm for generating a random y position for spawning a block, which takes into account a minimum and maximum height, allowing player to to jump on the block. Blocks will continually be spawned, so the player must always be able to jump onto the next block, bearing in mind the minimum position which would be the ground, and the maximum which would the players jump height bearing in mind the ceiling

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• Creating Windows 8.1 system image error

  - by Random

  I'm experiencing "not enough space" error when trying to create system image to a USB hard drive: Detailed error: ERROR - A Volume Shadow Copy Service operation error has occurred: (0x8004231f) Insufficient storage available to create either the shadow copy storage file or other shadow copy data. Blah, blah... There is not enough disk space to create the volume shadow copy on the storage location. Make sure that, for all volumes to be backup up, the minimum required disk space for shadow copy creation is available. This applies to both the backup storage destination and volumes included in the backup. Minimum requirement: For volumes less than 500 megabytes, the minimum is 50 megabytes of free space. For volumes more than 500 megabytes, the minimum is 320 megabytes of free space. Recommended: At least 1 gigabyte of free disk space on each volume if volume size is more than 1 gigabyte. ERROR - A Volume Shadow Copy Service operation error has occurred: (0x8004231f) Insufficient storage available to create either the shadow copy storage file or other shadow copy data. I'd tried both - PowerShell wbAdmin start backup -backupTarget:E: -include:C: -allCritical -quiet and via Control Panel - File History button Clearly both EFI and Windows Recovery Environment partitions don't meet requirements coming from System Image tool (pic below) On top of that all system partitions are now shown as 100% free in Disk Management, it's disturbing but far from the actual state. My question is - hot to create System Image in Windows 8.1?

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• Finding a shared HDD attached to the network from my F-13 machine

  - by Ramy

  Sorry for the slew of n00bie questions, but here is one more. I recently partitioned my 1.5TB harddrive according to this question I then bought this to attach the harddrive to my network. The problem is, how do I navigate to the hard drive to move files over the network to the HDD. should this be moved to serverfault? update: the disk isn't even showing up when i call "fdisk -l" (as root). How can I mount it if I can't even find it? [root@Moonface ~]# /sbin/fdisk -l Disk /dev/sda: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00018598 Device Boot Start End Blocks Id System /dev/sda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/sda2 64 19458 155777024 8e Linux LVM Disk /dev/dm-0: 53.7 GB, 53687091200 bytes 255 heads, 63 sectors/track, 6527 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-0 doesn't contain a valid partition table Disk /dev/dm-1: 4764 MB, 4764729344 bytes 255 heads, 63 sectors/track, 579 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-1 doesn't contain a valid partition table Disk /dev/dm-2: 101.0 GB, 101032394752 bytes 255 heads, 63 sectors/track, 12283 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-2 doesn't contain a valid partition table

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• disk partition centos

  - by FlourishDNA

  I am setting up server for hosting two WordPress which has size of around 70GB. I have already installed CentOS as OS and I would like to partition the Disk. Is there any tool which can help me or can someone guide me though the process as I am not expert is SSH commands. Here are some output that might help. OS: CentOS release 6.3 fdisk -l Disk /dev/xvdb: 214.7 GB, 214748364800 bytes 255 heads, 63 sectors/track, 26108 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000b91e0 Device Boot Start End Blocks Id System Disk /dev/xvda: 21.5 GB, 21474836480 bytes 255 heads, 63 sectors/track, 2610 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000e542c Device Boot Start End Blocks Id System /dev/xvda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/xvda2 64 2611 20458496 8e Linux LVM Disk /dev/mapper/vg_flourish-lv_root: 16.7 GB, 16718495744 bytes 255 heads, 63 sectors/track, 2032 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/vg_flourish-lv_swap: 4227 MB, 4227858432 bytes 255 heads, 63 sectors/track, 514 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 df Filesystem 1K-blocks Used Available Use% Mounted on /dev/mapper/vg_flourish-lv_root 16070076 758184 14495560 5% / tmpfs 958500 0 958500 0% /dev/shm /dev/xvda1 495844 31926 438318 7% /boot df -h Filesystem Size Used Avail Use% Mounted on /dev/mapper/vg_flourish-lv_root 16G 741M 14G 5% / tmpfs 937M 0 937M 0% /dev/shm /dev/xvda1 485M 32M 429M 7% /boot Thanks

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• How can I shrink the Address toolbar in the Task Bar?

  - by Iszi

  I like being able to run commands straight from my Task Bar. So, I've enabled the Address toolbar on my new Windows 7 system - just like I had on my old XP system. However, the bar seems to have a mandatory minimum length that's a bit longer than I'd prefer. It's about twice as long, if memory serves, as the minimum size allowed in XP. Is there any way I can adjust this minimum length, through a Registry key or some other means? (Note: I've also got a related question, about removing the Refresh button at the end of the bar.) EDIT: For clarity, I'm adding a screenshot. The toolbar I want to shorten is the one circled below, with an empty text-entry field that has a drop-down and "Refresh" button. I currently have it positioned between a Quick Launch toolbar and the Taskbar. On the far side of the Taskbar, before the System Tray, is a Desktop toolbar.

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• Cheapest server to run Windows 2008 R2?

  - by chopps

  Hey Everyone, I want to build a really cheap server to use for testing etc but don't want to spend alot of dough. Any recomendations on what kind of home pc/server would work for these requirements? Any place to get refurbs at a good price? Component Requirement Processor Minimum: 1.4 GHz (x64 processor) Note: An Intel Itanium 2 processor is required for Windows Server 2008 for Itanium-Based Systems Memory Minimum: 512 MB RAM Maximum: 8 GB (Foundation) or 32 GB (Standard) or 2 TB (Enterprise, Datacenter, and Itanium-Based Systems) Disk Space Requirements Minimum: 32 GB or greater Foundation: 10 GB or greater Note: Computers with more than 16 GB of RAM will require more disk space for paging, hibernation, and dump files Display Super VGA (800 × 600) or higher resolution monitor Other DVD Drive, Keyboard and Microsoft Mouse (or compatible pointing device), Internet access (fees may apply)

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