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  • Fastest method to define whether a number is a triangular number

    - by psihodelia
    A triangular number is the sum of the n natural numbers from 1 to n. What is the fastest method to find whether a given positive integer number is a triangular one? I suppose, there must be a hidden pattern in a binary representation of such numbers (like if you need to find whether a number is even/odd you check its least significant bit). Here is a cut of the first 1200th up to 1300th triangular numbers, you can easily see a bit-pattern here (if not, try to zoom out): (720600, '10101111111011011000') (721801, '10110000001110001001') (723003, '10110000100000111011') (724206, '10110000110011101110') (725410, '10110001000110100010') (726615, '10110001011001010111') (727821, '10110001101100001101') (729028, '10110001111111000100') (730236, '10110010010001111100') (731445, '10110010100100110101') (732655, '10110010110111101111') (733866, '10110011001010101010') (735078, '10110011011101100110') (736291, '10110011110000100011') (737505, '10110100000011100001') (738720, '10110100010110100000') (739936, '10110100101001100000') (741153, '10110100111100100001') (742371, '10110101001111100011') (743590, '10110101100010100110') (744810, '10110101110101101010') (746031, '10110110001000101111') (747253, '10110110011011110101') (748476, '10110110101110111100') (749700, '10110111000010000100') (750925, '10110111010101001101') (752151, '10110111101000010111') (753378, '10110111111011100010') (754606, '10111000001110101110') (755835, '10111000100001111011') (757065, '10111000110101001001') (758296, '10111001001000011000') (759528, '10111001011011101000') (760761, '10111001101110111001') (761995, '10111010000010001011') (763230, '10111010010101011110') (764466, '10111010101000110010') (765703, '10111010111100000111') (766941, '10111011001111011101') (768180, '10111011100010110100') (769420, '10111011110110001100') (770661, '10111100001001100101') (771903, '10111100011100111111') (773146, '10111100110000011010') (774390, '10111101000011110110') (775635, '10111101010111010011') (776881, '10111101101010110001') (778128, '10111101111110010000') (779376, '10111110010001110000') (780625, '10111110100101010001') (781875, '10111110111000110011') (783126, '10111111001100010110') (784378, '10111111011111111010') (785631, '10111111110011011111') (786885, '11000000000111000101') (788140, '11000000011010101100') (789396, '11000000101110010100') (790653, '11000001000001111101') (791911, '11000001010101100111') (793170, '11000001101001010010') (794430, '11000001111100111110') (795691, '11000010010000101011') (796953, '11000010100100011001') (798216, '11000010111000001000') (799480, '11000011001011111000') (800745, '11000011011111101001') (802011, '11000011110011011011') (803278, '11000100000111001110') (804546, '11000100011011000010') (805815, '11000100101110110111') (807085, '11000101000010101101') (808356, '11000101010110100100') (809628, '11000101101010011100') (810901, '11000101111110010101') (812175, '11000110010010001111') (813450, '11000110100110001010') (814726, '11000110111010000110') (816003, '11000111001110000011') (817281, '11000111100010000001') (818560, '11000111110110000000') (819840, '11001000001010000000') (821121, '11001000011110000001') (822403, '11001000110010000011') (823686, '11001001000110000110') (824970, '11001001011010001010') (826255, '11001001101110001111') (827541, '11001010000010010101') (828828, '11001010010110011100') (830116, '11001010101010100100') (831405, '11001010111110101101') (832695, '11001011010010110111') (833986, '11001011100111000010') (835278, '11001011111011001110') (836571, '11001100001111011011') (837865, '11001100100011101001') (839160, '11001100110111111000') (840456, '11001101001100001000') (841753, '11001101100000011001') (843051, '11001101110100101011') (844350, '11001110001000111110') For example, can you also see a rotated normal distribution curve, represented by zeros between 807085 and 831405?

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  • Lucene case sensitive & insensitive search

    - by zvikico
    I have a Lucene index which is currently case sensitive. I want to add the option of having a case insensitive search as a fall-back. This means that results that match the case will get more weight and will appear first. For example, if the number of results is limited to 10, and there are 10 matches which match my case, this is enough. If I only found 7 results, I can add 3 more results from the case-insensitive search. My case is actually more complex, since I have items with different weights. Ideally, having a match with "wrong" case will add some weight. Needless to say, I do not want duplicate results. One possible approach is to have 2 indexes. One with case and one without and search both. Naturally, there's some redundancy here, since I need to index twice. Is there a better solution? Ideas?

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  • question about Tetration

    - by davit-datuashvili
    i have question how write program which calculates following procedures http://en.wikipedia.org/wiki/Tetration i have exponential program which returns x^n here is code public class Exp{ public static long exp(long x,long n){ long t=0; if (n==0){ t= 1; } else{ if (n %2==0){ t= exp(x,n/2)* exp(x,n/2); } else{ t= x*exp(x,n-1); } } return t; } public static void main(String[]args){ long x=5L; long n=4L; System.out.println(exp(x,n)); } } but how use it in Tetration program?please help

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  • Print the page from mozswing

    - by uhsp
    Hi, I want to add a print option to the mozswing so I can print the page from it. I've used the MozillaAutomation.renderToImage() to get the image and then print it but it does not give me what I'm looking for. Can anyone please tell me how to do it. Thanks, uhs

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  • Printing the results in the original order

    - by Sam
    String[] numbers = new String[] {"3", "4", "s", "a", "c", "h", "i", "n", "t", "e", "n", "d", "u", "l", "k"}; Map<String, Integer> map = new HashMap<String, Integer>(); for (int i = 0; i < numbers.length; i++) { String key = numbers[i]; if (map.containsKey(key)) { int occurrence = map.get(key); occurrence++; map.put(key, occurrence); } else { map.put(key, 1); }// end of if else }// end of for loop Iterator<String> iterator = map.keySet().iterator(); while (iterator.hasNext()) { String key = iterator.next(); int occurrence = map.get(key); System.out.println(key + " occur " + occurrence + " time(s)."); } This program tries to count the number of occurrences of a string. When I execute it I am getting the answer, but the output is not in the original order, it is shuffled. How can I output the strings in the original order?

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  • Are Interfaces "Object"?

    - by PrashantGupta
    package inheritance; class A{ public String display(){ return "This is A!"; } } interface Workable{ public String work(); } class B extends A implements Workable{ public String work(){ return "B is working!"; } } public class TestInterfaceObject{ public static void main(String... args){ B obj=new B(); Workable w=obj; //System.out.println(w.work()); //invoking work method on Workable type reference System.out.println(w.display()); //invoking display method on Workable type reference //System.out.println(w.hashCode()); // invoking Object's hashCode method on Workable type reference } } As we know that methods which can be invoked depend upon the type of the reference variable on which we are going to invoke. Here, in the code, work() method was invoked on "w" reference (which is Workable type) so method invoking will compile successfully. Then, display() method is invoked on "w" which yields a compilation error which says display method was not found, quite obvious as Workable doesn't know about it. Then we try to invoke the Object class's method i.e. hashCode() which yields a successful compilation and execution. How is it possible? Any logical explanation?

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  • How is this function being made use of?

    - by Kay
    Hello all, I am just studying a few classes given to me by my lecturer and I can't understand how the function heapRebuild is being made used of! It doesn't change any global variables and it doesn't print out anything ad it doesn't return anything - so should this even work? It shouldn't, should it? If you were told to make use of heapRebuild to make a new function removeMac would you edit heapRebuild? public class MaxHeap<T extends Comparable<T>> implements Heap<T>{ private T[] heap; private int lastIndex; public T removeMax(){ T rootItem = heap[0]; heap[0] = heap[lastIndex-1]; lastIndex--; heapRebuild(heap, 0, lastIndex); return rootItem; } protected void heapRebuild(T[ ] items, int root, int size){ int child = 2*root+1; if( child < size){ int rightChild = child+1; if ((rightChild < size) && (items[rightChild].compareTo(items[child]) > 0)){ child = rightChild; } if (items[root].compareTo(items[child]) < 0){ T temp = items[root]; items[root] = items[child]; items[child] = temp; heapRebuild(items, child, size);} } } }

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  • Is there a Swing JPanel toolbar background that fits all OSs?

    - by Nazgulled
    I'm using a JPanel to have a toolbar on my background, but I don't like the look of it. Actually, there's basically no look, no background and the buttons are flat when the mouse is not over them. This is on Windows. How can I have a better look for this? Something that would fit better on Windows? Maybe something like the ToolStrip in Visual Studio? Or maybe something better that would look much better depending on the OS version (Windows, Mac, Linux)? Suggestions?

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  • Just a small help about switch's use

    - by Laurent Fournier
    If an answer on this already exist, my apologies i've not found on this question... is this statement correct if i want presice actions on integers from -2 to 0, and for those between 1 and 6 apply the same methods with only my integer who'll change ? Like this: public void setCaseGUI(Point pt, int i, boolean b){ plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setSelected(b); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setIcon(null); switch(i) { case -2: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("F"); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red); break; case -1: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("B"); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red); break; case 0: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(""); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null); break; case 1: case 2: case 3: case 4: case 5: case 6: case 7: case 8: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(String.valueOf(i)); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null); break; default: System.out.println("Erreur de changement d'état/case !"); } } Please don't be too harsh on me i've started to learn dev only a few month ago

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  • How to invoke a Servlet (doGet) in a web application on startup?

    - by Dan
    I need to invoke a Servlet on application startup since it contains some application initialization logic. I know I can set load-on-startup configuration, but this will only invoke Servlet’s init method. I need to invoke a doGet method and pass some Url parameters to it. Servlet doGet method expects ServletRequest and ServletResponse objects. Also, since this is clustered application, I need to know exactly what node I am accessing (since one option is just to open a socket and invoke a Servlet). What is the best option to perform this?

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  • How to avoid wasting time during compilation during development?

    - by user259576
    Hello, I'm working with a small team of developers. My job is to convert a Make project (with Intellij Idea 9.0) into a Maven 2 project. The problem is : we spend a lot of time during the development. With Make, only one complete build was required and then any change did not consume a lot of time (almost instantaneously). On the other hand, with Maven 2, a little change takes a lot of time to run. Any solution ? Thanks.

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  • Spring @Transactional - Can I Override rollbackFor

    - by user475039
    Hi all, I am calling a service which has the following annotation: @Transactional(rollbackFor=ExceptionA.class) public void myMethodA(....) throws ExceptionA { . . } I am calling this method from an other method in another Spring Bean. @Transactional(rollbackFor=ExceptionB.class) public void mainEntryPointMethod(....) throws ExceptionB { . try { myMethodA() } catch (ExceptionA exp) { . } . } My problem is that if myMethodA throws an exception, my transaction (which is passed from mainEntryPointMethod - myMethodA by default propagation) will be marked for rollback. Is there a way in which the 'rollbackFor' for the inner method can be overriden? Thanks in advance Chris

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  • Some pro regular expressions help needed here

    - by Camran
    I need a special regular expression, have no experience in them whatsoever so I am turning to you guys on this one: I need to validate a classifieds title field so it doesn't have any special characters in it, almost. Only letters and numbers should be allowed, and also the swedish three letters å, ä, ö, and also not case sensitive. Besides the above, these should also be allowed: The "&" sign. Parenthesis sign "()" Mathematical signs "-", "+", "%", "/", "*" Dollar and Euro signs Accent sign or whatever it's called, for example in "coupé" the apostrophe above the "e". Double quote and singel quote signs. The comma "," and point "." signs Thanks

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  • Calculations coming out to 0.0?

    - by Nick Gibson
    A simple percentage calculation. It wont return a value except 0.0 and I think once or twice it returned 100.0%. Other than that it won't do a thing. I have tried playing with the code in several different ways and it just wont work. for (int loop = 1; loop < loopCount; loop++) { aa = r.nextInt(10+1); abc = (int) aa; String[] userAnswer = new String[x]; int totalQues = (correctAnswer + wrongAnswer), actualQues = (totalQues - 1); if(abc < x) { userAnswer[abc] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]+"\nCorrect Answers: "+correctAnswer+"\nWrong Answers: "+wrongAnswer+"\nTotal Questions: "+totalQues); if(userAnswer[abc].equals(answers[abc])) { correctAnswer++; } else { wrongAnswer++; }//else if(actualQues == x); { score = (correctAnswer / actualQues) * 100; JOptionPane.showMessageDialog(null,"The test is finished."); JOptionPane.showMessageDialog(null,"You scored "+score+"%"); }//if }//if }//for

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