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  • django forms overwrite data when saved

    - by dana
    If a have a form, with the data from a user, let's say a CV, and i save the data from the form into a database, but i don't want that a CV from the same user to be stored in the database more than once(when edited form instance) I want it to be overwritten every time it is saved by one same user. How can i do it? thanks a lot

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  • Django Aggregation Across Reverse Relationship

    - by Tom
    Given these two models: class Profile(models.Model): user = models.ForeignKey(User, unique=True, verbose_name=_('user')) about = models.TextField(_('about'), blank=True) zip = models.CharField(max_length=10, verbose_name='zip code', blank=True) website = models.URLField(_('website'), blank=True, verify_exists=False) class ProfileView(models.Model): profile = models.ForeignKey(Profile) viewer = models.ForeignKey(User, blank=True, null=True) created = models.DateTimeField(auto_now_add=True) I want to get all profiles sorted by total views. I can get a list of profile ids sorted by total views with: ProfileView.objects.values('profile').annotate(Count('profile')).order_by('-profile__count') But that's just a dictionary of profile ids, which means I then have to loop over it and put together a list of profile objects. Which is a number of additional queries and still doesn't result in a QuerySet. At that point, I might as well drop to raw SQL. Before I do, is there a way to do this from the Profile model? ProfileViews are related via a ForeignKey field, but it's not as though the Profile model knows that, so I'm not sure how to tie the two together. As an aside, I realize I could just store views as a property on the Profile model and that may turn out to be what I do here, but I'm still interested in learning how to better use the Aggregation functions.

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  • Putting links into text in Django

    - by Dane Larsen
    I have a notifications app that generates notifications for users. The notification class has to be really general, because notifications are generated by all sorts of different things. My question is this: How do I insert links into the text of the notifications? What I tried was this: note = Notification(..., notification="""%s %s has accepted the task: <a href="/tasks/%d/">%s</a>.""" % (request.user.first_name, request.user.last_name, task.id, task.name), ...) In retrospect, it's obvious this wouldn't work. How should I go about this? Thanks in advance!

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  • Structure for Django methods that span different models

    - by Duncan
    I have two models (say A and B) which are independent and have independent methods. I want to add some methods that operate on both models though. for example, addX() will create an object from both models A and B. What's the best way to structure code in this situation, since it doesnt make sense to have the method belong to either of the models methods. Is the standard to write a service for the kind of 'abstract' model?

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Downloading a csv file in django

    - by spyder
    I am trying to download a CSV file using HttpResponse to make sure that the browser treats it as an attachment. I follow the instructions provided here but my browser does not prompt a "Save As" dialog. I cannot figure out what is wrong with my function. All help is appreciated. dev savefile(request): try: myfile = request.GET['filename'] filepath = settings.MEDIA_ROOT + 'results/' destpath = os.path.join(filepath, myfile) response = HttpResponse(FileWrapper(file(destpath)), mimetype='text/csv' ) response['Content-Disposition'] = 'attachment; filename="%s"' %(myfile) return response except Exception, err: errmsg = "%s"%(err) return HttpResponse(errmsg) Happy Pat's day!

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  • Keeping filters in Django Admin

    - by Tomo
    What I would like to achive is: I go to admin site, apply some filters to the list of objects I click and object edit, edit, edit, hit 'Save' Site takes me to the list of objects... unfiltered. I'd like to have the filter from step 1 remembered and applied. Is there an easy way to do it?

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  • django modeling

    - by SledgehammerPL
    Concept: Drinks are made of components. E.g. 10ml of Vodka. In some receipt the component is very particular (10ml of Finlandia Vodka), some not (10 ml of ANY Vodka). I wonder how to model a component to solve this problem - on stock I have particular product, which can satisfy more requirements. The model for now is: class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Product, through='ReceiptComponent') def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) class Admin: pass def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive class Product(models.Model): name = models.CharField(max_length = 128) (...) class Admin: pass def __unicode__(self): return self.name class Stock(Store): products = models.ManyToManyField(Product) class Admin: pass def __unicode__(self): return self.name I think about making some table which joins real product (on stock) with abstract product (receiptcomponent). But maybe there's easy solution?

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  • django many to many validation when add()

    - by Julien
    Hi i have a Category model with parent/child self relation For primary category and sub categories : class Place(models.Model): name = models.CharField(_("name"), max_length=100) categories = models.ManyToManyField("Category", verbose_name=_("categories")) class Category(models.Model): name = models.CharField(_("name"), max_length=100) parent = models.ForeignKey('self', blank=True, null=True, related_name='child_set') i need to prevent orphans, to prevent this kind of errors (in admin web interface) c_parent = Category(name='Restaurant') c_parent.save() c_child = Category(name="Japanese restaurant", parent=c_parent) c_child.save() place1 = Place (name="Planet sushi") place1.save() place1.categories.add(c_parent) place1.categories.add(c_child) So now we have a new Place called "Planet sushi", it's a Restaurant (root category), and a Japanese Restaurant (sub category) but i want to prevent this kind of things : place2 = Place (name="Tokyofood") place2.save() place2.categories.add(c_child) because parent is not set, or is not the correct parent category where can i do form validation for the admin ? and other forms (because any user can add a new place and will have to choose correct categories for)

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  • How to teach Django to non-web programmers? [closed]

    - by Greg
    I've been tasked with providing a workshop for my co-workers to teach them Django. They're all good programmers but they've never done any web programming. I was thinking to just go through the Django tutorial with them, but are there things in there that wouldn't make sense to non-web programmers? Do they need any kind of webdev background first? Any thoughts on a good way to provide the basics so that Django will make sense?

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  • django url from another template than the one associated with the view-function

    - by dana
    Heyy there, i have an application, and in my urls.py i have something like that: urlpatterns = patterns('', url(r'^profile_view/(?P<id>\d+)/$', profile_view, name='profile_view'),) meaning that the profile_view function has id as a parameter. Now, i want to call that function from another template than the one associated with the def-view that has this url. How should i do that? i have to put two render_to_response to one same function, in order to render the objects from both models? thank you!

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  • django ifequal naturalday

    - by Scott Willman
    I'm not sure why, but this condition will never evaluate True for me. I'm feeding it datetime.today() in the urls file. Am I missing something? Template: {% load humaize %} {{ entry.date|naturalday }} {# Evals to "today" #} {% ifequal entry.date|naturalday "today" %} True {{ entry.date|date:"fA"|lower }} {{ entry.date|naturalday|title }} {% else %} False {{ entry.date|naturalday|title }} {% endifequal %}

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  • How to make my view better to save Django

    - by user558251
    Hy guys sorry for this post but i need help with my application, i need optimize my view. I have 5 models, how i can do this? def save(request): # get the request.POST in content if request.POST: content = request.POST dicionario = {} # create a dict to get the values in content for key,value in content.items(): # get my fk Course.objects if key == 'curso' : busca_curso = Curso.objects.get(id=value) dicionario.update({key:busca_curso}) else: dicionario.update({key:value}) #create the new teacher Professor.objects.create(**dicionario) my questions are? 1 - How i can do this function in a generic way? Can I pass a variable in a %s to create and get? like this way ? foo = "Teacher" , bar = "Course" def save(request, bar, foo): if request post: ... if key == 'course' : get_course = (%s.objects.get=id=value) %bar ... (%s.objects.create(**dict)) %foo ??? i tried do this in my view but don't work =/, can somebody help me to make this work ? Thanks

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  • Can't iterate over nestled dict in django

    - by fredrik
    Hi, Im trying to iterate over a nestled dict list. The first level works fine. But the second level is treated like a string not dict. In my template I have this: {% for product in Products %} <li> <p>{{ product }}</p> {% for partType in product.parts %} <p>{{ partType }}</p> {% for part in partType %} <p>{{ part }}</p> {% endfor %} {% endfor %} </li> {% endfor %} It's the {{ part }} that just list 1 char at the time based on partType. And it seams that it's treated like a string. I can however via dot notation reach all dict but not with a for loop. The current output looks like this: Color C o l o r Style S ..... The Products object looks like this in the log: [{'product': <models.Products.Product object at 0x1076ac9d0>, 'parts': {u'Color': {'default': u'Red', 'optional': [u'Red', u'Blue']}, u'Style': {'default': u'Nice', 'optional': [u'Nice']}, u'Size': {'default': u'8', 'optional': [u'8', u'8.5']}}}] What I trying to do is to pair together a dict/list for a product from a number of different SQL queries. The web handler looks like this: typeData = Products.ProductPartTypes.all() productData = Products.Product.all() langCode = 'en' productList = [] for product in productData: typeDict = {} productDict = {} for type in typeData: typeDict[type.typeId] = { 'default' : '', 'optional' : [] } productDict['product'] = product productDict['parts'] = typeDict defaultPartsData = Products.ProductParts.gql('WHERE __key__ IN :key', key = product.defaultParts) optionalPartsData = Products.ProductParts.gql('WHERE __key__ IN :key', key = product.optionalParts) for defaultPart in defaultPartsData: label = Products.ProductPartLabels.gql('WHERE __key__ IN :key AND partLangCode = :langCode', key = defaultPart.partLabelList, langCode = langCode).get() productDict['parts'][defaultPart.type.typeId]['default'] = label.partLangLabel for optionalPart in optionalPartsData: label = Products.ProductPartLabels.gql('WHERE __key__ IN :key AND partLangCode = :langCode', key = optionalPart.partLabelList, langCode = langCode).get() productDict['parts'][optionalPart.type.typeId]['optional'].append(label.partLangLabel) productList.append(productDict) logging.info(productList) templateData = { 'Languages' : Settings.Languges.all().order('langCode'), 'ProductPartTypes' : typeData, 'Products' : productList } I've tried making the dict in a number of different ways. Like first making a list, then a dict, used tulpes anything I could think of. Any help is welcome! Bouns: If someone have an other approach to the SQL quires, that is more then welcome. I feel that it kinda stupid to run that amount of quires. What is happening that each product part has a different label base on langCode. ..fredrik

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  • Django model help

    - by dotty
    Does anyone have any clue why this doesn't work as expected. If i use the python shell and do team.game_set or team.games It returns an error AttributeError: 'Team' object has no attribute 'game' If i create a Game object and call game.home_team it returns the correct team object Heres my model class Team(models.Model): name = models.CharField(blank=True, max_length=100) class Game(models.Model): home_team = models.ForeignKey(Team, related_name="home_team")

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  • Django 1.2 - Pb with a form in a template (WSGIRequest)

    - by Tom
    Hi, I'm trying to display a form on a template, but I get a fantastic error : Caught AttributeError while rendering: 'WSGIRequest' object has no attribute 'get' The error is in this line : {% for field in form.visible_fields %} My view : def view_discussion(request, discussion_id): discussion = get_object_or_404(Discussion, id=discussion_id) form = BaseMessageForm(request) return render(request,'ulule/discussions/view_discussion.html', { 'discussion':discussion, 'form':form, }) My form : class BaseMessageForm(forms.Form): message_content = forms.CharField(widget=forms.HiddenInput()) My template : <form action="" method="post"> {% csrf_token %} {% for field in form.visible_fields %} <div class="fieldWrapper"> {% if forloop.first %} {% for hidden in form.hidden_fields %} {{ hidden }} {% endfor %} {% endif %} {{ field.errors }} {{ field.label_tag }}: {{ field }} </div> {% endfor %} <p><input type="submit" value="Send message" /></p> </form> Thanks a lot for your help !

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  • Django i18n and SEO

    - by etam
    Hi, how do you prepare i18n in your websites? I mean what do you do avoid the situation when you search for i18ned websites in Polish you get English description cause English is the default one. Thanks in advance, Etam.

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  • django join querysets from multiple tables

    - by dana
    if i have queries on multiple tables like: d = Relations.objects.filter(follow = request.user).filter(date_follow__lt = last_checked) r = Reply.objects.filter(reply_to = request.user).filter(date_reply__lt = last_checked) article = New.objects.filter(created_by = request.user) vote = Vote.objects.filter(voted = article).filter(date__lt = last_checked) and i want to display the results from all of them ordered by date (i mean not listing all the replies, then all the votes, etc ). Somehow, i want to 'join all these results', in a single queryset. Is there possible?

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  • django display m2m elements in a template

    - by dana
    if a have a declaration like theclass = Classroom.objects.get(classname = classname) members = theclass.members.all() and i want to display all the members(of a class) in a template, how should i do it?? if i write: {{theclass.members.all}} the output is an empty list(though the class has some members) How should the elements of a m2m table be displayed in a template? thanks!

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  • Is there a way to ignore Cache errors in Django?

    - by Josh Smeaton
    I've just set our development Django site to use redis for a cache backend and it was all working fine. I brought down redis to see what would happen, and sure enough Django 404's due to cache backend behaviour. Either the Connection was refused, or various other errors. Is there any way to instruct Django to ignore Cache errors, and continue processing the normal way? It seems weird that caching is a performance optimization, but can bring down an entire site if it fails. I tried to write a wrapper around the backend like so: class CacheClass(redis_backend.CacheClass): """ Wraps the desired Cache, and falls back to global_settings default on init failure """ def __init__(self, server, params): try: super(CacheClass, self).__init__(server, params) except Exception: from django.core import cache as _ _.cache = _.get_cache('locmem://') But that won't work, since I'm trying to set the cache type in the call that sets the cache type. It's all a very big mess. So, is there any easy way to swallow cache errors? Or to set the default cache backend on failure?

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