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  • MouseListener fired without checking JCheckBox

    - by Morinar
    This one is pretty crazy: I've got an AppSight recording (for those not familiar, it's a recording of what they did including keyboard/mouse input + network traffic, etc) of a customer reproducing a bug. Basically, we've got a series of items listed on the screen with JCheckBox-es down the left side. We've got a MouseListener set for the JPanel that looks something like this: private MouseAdapter createMouseListener() { return new MouseAdapter(){ public void mousePressed( MouseEvent e ) { if( e.getComponent() instanceof JCheckBox ) { // Do stuff } } }; } Based on the recording, it appears very strongly that they click just above one of the checkboxes. After that, it's my belief that this listener fired and the "Do stuff" block happened. However, it did NOT check the box. The user then saw that the box was unchecked, so they clicked on it. This caused the "Do stuff" block to fire again, thus undoing what it had done the first time. This time, the box was checked. Therefore, the user thinks that the box is checked, and it looks like it is, but our client thinks that the box is unchecked as it was clicked twice. Is this possible at all? For the life of me, I can't reproduce it or see how it could be possible, but based on the recording and the data the client sent to the server, I can't see any other logical explanation. Any help, thoughts, and or ideas would be much appreciated.

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  • RMI client tracking

    - by 0000
    I'm building a Client / Server app that has some very specific needs. There are 2 kinds of servers: the first kind provide most of the remote procedures and clients connect to these directly, while the second kind is a single server that should keep track of what users are active (clients) and how many servers of the first kind are active when a method is called. The main thing is that the monitor should ONLY connect to the servers and not the clients directly. My first idea was to implement a simple login/logout rmi method when a client connects/ disconnects and keep track of those in a list but the main problem is when a client or server end abnormally. For example, if a client goes offline abruptly the server should somehow be notified and update the list accordingly, while if a server goes out all of the clients connected to it should be marked as not active in the control server. Any ideas of how to implement this functionality would be appreciated.

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  • Refactoring a long method that simply populates

    - by Jeune
    I am refactoring a method which is over 500 lines (don't ask me why) The method basically queries a list of maps from the database and for each map in the list does some computation and adds the value of that computation to the map. There are however too many computations and puts being done that the code has reached over 500 lines already! Here's a sample preview: public List<Hashmap> getProductData(...) { List<Hashmap> products = productsDao.getProductData(...); for (Product product: products) { product.put("Volume",new BigDecimanl(product.get("Height")* product.get("Width")*product.get("Length")); if (some condition here) { //20 lines worth of product.put(..,..) } else { //20 lines worth of product.put(..,..) } //3 more if-else statements like the one above try { product.put(..,..) } catch (Exception e) { product.put("",..) } //over 8 more try-catches of the form above } Any ideas on how to go about refactoring this?

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  • Problem formatting in Eclipse

    - by fastcodejava
    I have a method in Eclipse as below. public String toString() { return "HouseVo [ " + "Name : " + this.name == null ? "" : this.name + "Address : " + this.address == null ? "" : this.address; } When I format it becomes: return "HouseVo [ " + "Name : " + this.name == null ? "" : this.name + "Address : " + this.address == null ? "" : this.address; Any way to fix it so it correctly formats?

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  • What does assert do?

    - by peiska
    What does assert do? for example in the function? private static int charAt(String s, int d) { assert d >= 0 && d <= s.length(); if (d == s.length()) return -1; return s.charAt(d); }

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  • FileConnection Blackberry memory usage

    - by Dean
    Hello, I'm writing a blackberry application that reads ints and strings out of a database. This is my first time dealing with reading/writing on the blackberry, so forgive me if this is a dumb question. The database file I'm reading is only about 4kB I open the file with the following code fconn = (FileConnection) Connector.open("file_path_here", Connector.READ); if(fconn.exists()==false){fconn.close();return;} is = fconn.openDataInputStream(); while(!eof){ //etc... } is.close(); fconn.close(); The problem is, this code appears to be eating a LOT of memory. Using breakpoints and the "Memory Statistics" view, I determined the following: calling "Connector.open" creates 71 objects and changes "RAM Bytes in use" by 5376 calling "fconn.openDataInputStream();" increases RAM usage by a whopping 75920 Is this normal? Or am I doing something wrong? And how can I fix this? 75MB of RAM is a LOT of memory to waste on a handheld device, especially when the file I'm reading is only 4kB and I haven't even begun reading any data! How is this even possible?

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  • Filter Facebook Stream by Post privacy?

    - by fabian
    Hi there, i query some wall data within my facebook tab. I was wondering how to filter the data (query) to show only post which are visible to a certain country. $query = " SELECT post_id, created_time, attachment,action_links, privacy FROM stream WHERE source_id = ".$page_id." AND viewer_id = ".$user_id." AND actor_id = ".$actor_id." LIMIT 50"; The Output already show Australia: But how to filter for Australia-Only. Array ( [posts] => Array ( [0] => Array ( [post_id] => 123 [viewer_id] => 123 [source_id] => 123 [type] => 46 [app_id] => [attribution] => [actor_id] => 123 [target_id] => [message] => Only for Austria [attachment] => Array ( [description] => ) [app_data] => [action_links] => [comments] => Array ( [can_remove] => 1 [can_post] => 1 [count] => 0 [comment_list] => ) [likes] => Array ( [href] => http://www.facebook.com/social_graph.php?node_id=118229678189906&class=LikeManager [count] => 0 [sample] => [friends] => [user_likes] => 0 [can_like] => 1 ) [privacy] => Array ( [description] => Austria [value] => CUSTOM [friends] => [networks] => [allow] => [deny] => ) [updated_time] => 1271520716 [created_time] => 1271520716 [tagged_ids] => [is_hidden] => 0 [filter_key] => [permalink] => http://www.facebook.com/pages/ )

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  • back button is working on emulator but it is not working in device in android

    - by Rajeevgandhi
    Hi all, am new to this android development. I have index page and am displaying every links in the same page using div concept. Now i want to use the back button for my application i have developed code to handle the div and it is working in the AVD(Andriod Virtual Device 5556) but if i upload the apk into my device it is not working. Am waiting for your reply Please help me...... Thanks, Rajeevgandhi. S

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  • db2 jdbc driver does not release table locks

    - by as
    situation: We have a web service running on tomcat accessing DB2 database on AS400, we are using JTOPEN drivers for JNDI connections handled by tomcat. For handling transactions and access to database we are using Spring. For each select system takes JDBC connection from JNDI (i.e. from connection pool), does selection, and in the end it closes ResultSet, Statement and releases Connection in that order. That passes fine, shared lock on table dissappears. When we want to do update the same way as we did with select (exception on ResultSet object, we don't have one in such situation), after releasing Connection to JNDI lock on table stays. If we put maxIdle=0 for number of connections in JNDI configuration, this problem disappears, but this degrades performances, we have cca 100 users online on that service, we need few connections to be alive in pool. What do you suggest?

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  • How can I force the server socket to re-accept a request from a client?

    - by Roman
    For those who does not want to read a long question here is a short version: A server has an opened socket for a client. The server gets a request to open a socket from the same client-IP and client-port. I want to fore the server not to refuse such a request but to close the old socket and open a new one. How can I do ti? And here is a long (original) question: I have the following situation. There is an established connection between a server and client. Then an external software (Bonjour) says to my client the it does not see the server in the local network. Well, client does nothing about that because of the following reasons: If Bonjour does not see the server it does not necessarily means that client cannot see the server. Even if the client trusts the Bonjour and close the socket it does not improve the situation ("to have no open socket" is worser that "to have a potentially bad socket"). So, client do nothing if server becomes invisible to Bonjour. But than the server re-appears in the Bonjour and Bonjour notify the client about that. In this situation the following situations are possible: The server reappears on a new IP address. So, the client needs to open a new socket to be able to communicate with the server. The server reappears on the old IP address. In this case we have two subcases: 2.1. The server was restarted (switched off and then switched on). So, it does not remember the old socket (which is still used by the client). So, client needs to close the old socket and open a new one (on the same server-IP address and the same server-port). 2.2. We had a temporal network problem and the server was running the whole time. So, the old socket is still available for the use. In this case the client does not really need to close the old socket and reopen a new one. But to simplify my life I decide to close and reopen the socket on the client side in any case (in spite on the fact that it is not really needed in the last described situation). But I can have problems with that solution. If I close the socket on the client side and than try to reopen a socket from the same client-IP and client-port, server will not accept the call for a new socket. The server will think that such a socket already exists. Can I write the server in such a way, that it does not refuse such calls. For example, if it (the server) sees that a client send a request for a socket from the same client-IP and client-port, it (server) close the available socket, associated with this client-IP and client-port and than it reopens a new socket.

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  • [Android] XML Parser

    - by lemon
    I'm trying to extract n0Y7ezLlIYA8R0K54rEmHaTOraBQVSPDjQaGlQxlGso4jdVN1kRxtcfskEs= using w3c dom <html> <div id='token' style='display:none;'> n0Y7ezLlIYA8R0K54rEmHaTOraBQVSPDjQaGlQxlGso4jdVN1kRxtcfskEs= </div> </html> but I seem to be stuck DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document doc = builder.parse(con.getInputStream()); NodeList list = doc.getElementsByTagName("div"); Can someone please point me to some basic tutorials that would help me solve my dilemma. Thanks.

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  • playing two streams on android

    - by Yanush
    Hello, I'm looking for a way (or at least to be pointed in the right direction) to play two streams of audio on android simultaneously but each on a different channel (e.g one in the speaker and one through the headphones) I'm not even sure its possible hardware wise. Any thoughts, clues ? Y

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  • Calling and consuming a JBoss Web Service from JavaScript (AJAX)

    - by Andreas Grech
    I am fiddling around with JBOSS's Web Services, and I have created the following: http://127.0.0.1:8080/IM/TestService?wsdl Now I need to access Web Methods from that Web Service from JavaScript. Say I have a web method named foo in TestService, how do I make an ajax call to it? I tried accessing the method via http://127.0.0.1:8080/IM/TestService/foo, but I'm getting an HTTP Status 404.

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  • How do I create different Objects using Google Guice?

    - by kunjaan
    I have a Module which binds an Interface to a particular implementation. I use that module to create an object. How do I create a different kind of object with the the interface bound to a different implementation? Do I need to create a new module with the Interface bound to a different implementation?

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  • Android 2.1 How to get Phone Numbers of contacts.

    - by Brandon Delany
    Hi, I am new to Android and have been working on an app that needs to get all of the user's contact's phone numbers. Apparently the code I have does not work with the 2.1 SDK. So far here is the code I am using: String[] projection = new String[] { Phone.NUMBER }; Cursor c = managedQuery( Phone.CONTENT_URI, projection, null, null, null ); int colIndex = -1; try { colIndex = c.getColumnIndexOrThrow( Phone.NUMBER ); } catch( Exception e ) { print( e.getMessage() ); } print( "Column Index = " + colIndex ); //count is equal to 3 for( int i = 0; i < count; i++ ){ try { print( c.getString( 2 ) ); //the 2 used to be colIndex } catch ( Exception e ) { print( e.getMessage() ); } } It seems that no matter what I pass into c.getString() it keeps telling me that I passed in -1. But I even hardcoded the 2, and it says the same thing. Any help would be much appreciated.

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  • Prevent duplicate entries in arraylist

    - by timyh
    Say I create some object class like so public class thing { private String name; private Integer num; public oDetails (String a, Integer b) { name = a; num = b; } ...gets/ sets/ etc Now I want to create an arraylist to hold a number of this object class like so. ArrayList<thing> myList = new ArrayList<thing>; thing first = new thing("Star Wars", 3); thing second = new thing("Star Wars", 1); myList.add(first); myList.add(second); I would like to include some sort of logic so that in this case...when we try and add object "second" rather than add a new object to the arrayList, we add second.getNum() to first.getNum(). So if you were to iterate through the ArrayList it would be "Star Wars", 4 I am having trouble coming up with an elegant way of handling this. And as the arraylist grows, searching through it to determine if there are duplicate name items becomes cumbersome. Can anyone provide some guidance on this?

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  • Line by line image swing

    - by user1046017
    I want to show an image as it is downloading, I have the URL, and I am trying to get the image parts like this: InputStream openStream = url.openStream(); DataInputStream dis = new DataInputStream(new BufferedInputStream(openStream)); ByteArrayOutputStream os = new ByteArrayOutputStream(); while ((s = dis.read(b)) != -1) { os.write(b , 0, s); support.firePropertyChange("stream", null, os); } This way, any listener get the stream and creates an image, this way: if("stream".equals(evt.getPropertyName())){ try { ByteArrayOutputStream stream = (ByteArrayOutputStream) evt.getNewValue(); byte[] byteArray = stream.toByteArray(); stream.flush(); Image createImage = Toolkit.getDefaultToolkit().createImage(byteArray); this.getContentPane().add(new JLabel(new ImageIcon(createImage))); } catch (IOException ex) { Logger.getLogger(ImageTest.class.getName()).log(Level.SEVERE, null, ex); } } However, I am getting a "Premature end of JPEG file sun.awt.image.ImageFormatException: JPEG datastream contains no image" error, the image is a JPG image format, is there any library or method known to make something similar?

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  • Making a FTP connection in Android

    - by Elisha Khan
    i am working to make a Android application that can upload and download data from android phone to server using this link. As i am new to connection Android with server. is my local host works as a server to download and upload. i am using Uri ftpUri = Uri.parse("ftp://10.0.2.2"); But its not working help me to get out of this problem. I need your help just to sucessfullt connect to server, As i already said i aam new to connect Android Application to server. I am learning Programing myself and Internet is my teacher. Thank You Very Much

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  • Jquery autosuggest google maps - Load on selection

    - by user1738522
    At the moment, the Google map code works like this: When you start typing in the input box it loads a list of suggestions. Then when you click on one of these options from the list, it puts it into the input box. However, THEN you still have to click find to load up the result. I want to have it so when you click on an option from the autosuggest list, it automatically loads the result, without having to click "find" afterwards. This is the code I am working with. I hope I explained this question correctly. http://jsfiddle.net/BxG9H/

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  • Share Link - Perform action in background

    - by Justin
    I have an application that will accept URLs from the built in web browser via the "Share page" menu item. I'm using the send intent and it works just fine. However, I'd like to accept a URL and process it in the background without bringing my application to the front. I don't want the user to have to actually leave the web browser. It will notify the user it has finished processing the URL with a Toast message. I'm just not sure what type of activity should be used for this. A good example of this behavior is the "Read Later" instapaper application in the android market. Any help would be greatly appreciated.

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