Search Results

Search found 16688 results on 668 pages for 'expression language'.

Page 103/668 | < Previous Page | 99 100 101 102 103 104 105 106 107 108 109 110  | Next Page >

  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

    Read the article

  • How to design a database schema for storing text in multiple languages?

    - by stach
    We have a PostgreSQL database. And we have several tables which need to keep certain data in several languages (the list of possible languages is thankfully system-wide defined). For example lets start with: create table blah (id serial, foo text, bar text); Now, let's make it multilingual. How about: create table blah (id serial, foo_en text, foo_de text, foo_jp text, bar_en text, bar_de text, bar_jp text); That would be good for full-text search in Postgres. Just add a tsvector column for each language. But is it optimal? Maybe we should use another table to keep the translations? Like: create table texts (id serial, colspec text, obj_id int, language text, data text); Maybe, just maybe, we should use something else - something out of the SQL world? Any help is appreciated.

    Read the article

  • Matching Word with regular expression

    - by lbar
    I have the following text file: ... "somewords MYWORD";123123123123 "someother MYWORDOTHER";456456456456 "somedifferent MYWORDDIFFERENT";789789789 ... i need to match the word MYWORD, MYWORDOTHER, MYWORDDIFFERENT and then substitute the space before this word with ";". Someone can figure out a regex? I have done something like that: +[^ ][^ ][^ ][^ ][^ ][^ ][^ ]"; but this works only with a specific word lenght. I need to modify to get any word of any leght. Any help? Thank you.

    Read the article

  • what is the regular expression for this

    - by bn
    I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

    Read the article

  • Regular Expression Program

    - by david robers
    Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

    Read the article

  • Why is writeSTRef faster than if expression?

    - by wenlong
    writeSTRef twice for each iteration fib3 :: Int -> Integer fib3 n = runST $ do a <- newSTRef 1 b <- newSTRef 1 replicateM_ (n-1) $ do !a' <- readSTRef a !b' <- readSTRef b writeSTRef a b' writeSTRef b $! a'+b' readSTRef b writeSTRef once for each iteration fib4 :: Int -> Integer fib4 n = runST $ do a <- newSTRef 1 b <- newSTRef 1 replicateM_ (n-1) $ do !a' <- readSTRef a !b' <- readSTRef b if a' > b' then writeSTRef b $! a'+b' else writeSTRef a $! a'+b' a'' <- readSTRef a b'' <- readSTRef b if a'' > b'' then return a'' else return b'' Benchmark, given n = 20000: benchmarking 20000/fib3 mean: 5.073608 ms, lb 5.071842 ms, ub 5.075466 ms, ci 0.950 std dev: 9.284321 us, lb 8.119454 us, ub 10.78107 us, ci 0.950 benchmarking 20000/fib4 mean: 5.384010 ms, lb 5.381876 ms, ub 5.386099 ms, ci 0.950 std dev: 10.85245 us, lb 9.510215 us, ub 12.65554 us, ci 0.950 fib3 is a bit faster than fib4.

    Read the article

  • Java - Regular expression question

    - by Jacob
    I am new to regular expressions. I want to use java's replaceAll() function to replace any CSS comments in a string. Basically I want to use regex to search for anything that is surrounded by "/*" and "*/" and replace it with "".

    Read the article

  • Regular expression - skip string in quotes using sed

    - by milano
    I have string like this: "Some standard text CONST_INSIDE_QUOTES" blah blah CONST "There might be another quotes" The thing is, that i want to replace all constants in string with some text, but it mustn't be applied on constants inside text in quotes. I have this regex: sed "s/([A-Z][A-Z0-9_]*)([^a-z])/<span class=\"const\"\1<\/span\2/g" which of course works for all consts. Any ideas how to exclude its apply on quotes constants? Unfortunately sed only...

    Read the article

  • Expected Expression

    - by coffeeaddict
    I cannot figure out what I did or did not do here syntactically to cause this error. I don't see what's missing: function ShowWaitMessage(button) { var isValid; if (buttonSelected()) { showWaitMessage(button, "showMessage1"); isValid = true; } else { Page_ClientValidate(); if (Page_IsValid) { showWaitMessage(button, "showMessage2"); isValid = true; } } return isValid; }

    Read the article

  • Help to write regular expression

    - by Ockonal
    Hello, I have to get any text between: Final-Recipient: RFC822; !HERE! Action I need !HERE! from this example. There could be any string. I tried something like: $Pattern = '/Final-Recipient: RFC822; (.*) Action/'; But it doesn't work. upd Here is the string I'm trying to parse: http://dpaste.com/187638/

    Read the article

  • Sed: regular expression match lines without <!--

    - by sixtyfootersdude
    I have a sed command to comment out xml commands sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml Takes: <a> <!-- Comment --> <b> bla </b> </a> Produces: <!-- Security: <a> --> <!-- Security: <!-- Comment --> --> // NOTE: there are two end comments. <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> Ideally I would like to not use my sed script to comment things that are already commented. Ie: <!-- Security: <a> --> <!-- Comment --> <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> I could do something like this: sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml sed 's/^[ \t]*<!-- Security: \(<!--.*-->\) -->/\1/' web.xml but I think a one liner is cleaner (?) This is pretty similar: http://stackoverflow.com/questions/436850/matching-a-line-that-doesnt-contain-specific-text-with-regular-expressions

    Read the article

  • Multiline Regular Expression search and replace!

    - by Scott
    I've hit a wall. Does anybody know a good text editor that has search and replace like Notepad++ but can also do multi-line regex search and replace? Basically, I am trying to find something that can match a regex like: search oldlog\(.*\n\s+([\r\n.]*)\);replace newlog\(\1\) Any ideas?

    Read the article

  • boolean VB expression returning false for integer 1

    - by Bill
    This is probably a really basic (no pun intended) question, but I can't seem to find an answer anywhere. Why does the result of func1 return False and func2 returns True? On every other test I have done, integer 1 is converted to boolean true and 0 to false. Works ok if I just set rtnValue to 1 or 0. Public Function func1() As Boolean Dim rtnValue As Integer = 0 Return rtnValue = 1 End Function Public Function func2() As Boolean Dim rtnValue As Integer = 0 Return rtnValue = 0 End Function

    Read the article

< Previous Page | 99 100 101 102 103 104 105 106 107 108 109 110  | Next Page >