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  • Replacing multiple patterns in a block of data

    - by VikrantY
    Hi All, I need to find the most efficient way of matching multiple regular expressions on a single block of text. To give an example of what I need, consider a block of text: "Hello World what a beautiful day" I want to replace Hello with "Bye" and "World" with Universe. I can always do this in a loop ofcourse, using something like String.replace functions availiable in various languages. However, I could have a huge block of text with multiple string patterns, that I need to match and replace. I was wondering if I can use Regular Expressions to do this efficiently or do I have to use a Parser like LALR. I need to do this in JavaScript, so if anyone knows tools that can get it done, it would be appreciated.

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  • Filter string in C

    - by Paul Tarjan
    How can I filter a string in c? I want to remove anything that isn't [a-z0-9_]. int main(int argc, char ** argv) { char* name = argv[1]; // remove anything that isn't [a-z0-9_] printf("%s", name); }

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  • Is it possible to use re2 from Python?

    - by flow
    i just discovered http://code.google.com/p/re2, a promising library that uses a long-neglected way (Thompson NFA) to implement a regular expression engine that can be orders of magnitudes faster than the available engines of awk, Perl, or Python. so i downloaded the code and did the usual sudo make install thing. however, that action had seemingly done little more than adding /usr/local/include/re2/re2.h to my system. there seemed to be some `*.a file in addition, but then what is it with this *.a extension? i would like to use re2 from Python (preferrably Python 3.1) and was excited to see files like make_unicode_groups.py in the distro (maybe just used during the build process?). those however were not deployed on my machine. how can i use re2 from Python?

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  • get city, state or zip from a string in python

    - by Joe
    I'd like to be able to parse out the city, state or zip from a string in python. So, if I entered Boulder, Co 80303 Boulder, Colorado Boulder, Co 80303 ... any variation of these it would return the city, state or zip. This is all going to be user inputted data and inputted in one text field.

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  • How to parse phpDoc style comment block with php?

    - by Reveller
    Please consider the following code with which I'm trying to parse only the first phpDoc style comment (noy using any other libraries) in a file (file contents put in $data variable for testing purposes): $data = " /** * @file A lot of info about this file * Could even continue on the next line * @author [email protected] * @version 2010-05-01 * @todo do stuff... */ /** * Comment bij functie bar() * @param Array met dingen */ function bar($baz) { echo $baz; } "; $data = trim(preg_replace('/\r?\n *\* */', ' ', $data)); preg_match_all('/@([a-z]+)\s+(.*?)\s*(?=$|@[a-z]+\s)/s', $data, $matches); $info = array_combine($matches[1], $matches[2]); print_r($info) This almose works, except for the fact that everything after @todo (including the bar() comment block and code) is considered the value of @todo: Array ( [file] => A lot of info about this file Could even continue on the next line [author] => [email protected] [version] => 2010-05-01 [todo] => do stuff... / /** Comment bij functie bar() [param] => Array met dingen / function bar() { echo ; } ) How does my code need to be altered so that only the first comment block is being parsed (in other words: parsing should stop after the first "*/" encountered?

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  • regular expression for string in c

    - by darkie15
    Hi All, I am working writing a regular expression used to validate string in C. Here is to what I have gone so far '^"[A-Za-z0-9]*[\t\n]*"$' for rules - A string should begin with double quotes - May not contain a newline character However, I am not able to capture the rule for allowing '\' or '"' in a string if preceded with '\'. Here is what I tried: '^"[A-Za-z0-9]*[\t\n]*[\\\|\\"]?"$' But this doesn't seem to work. What might be wrong with the regular expression here? Regards, darkie15

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  • Match string which doesn't start with

    - by Pinky
    I have a string that looks like this: var str = "Hello world, &nbsp;hello &gt;world, hello world!"; ... and I'd like to replace all the hellos with e.g. bye and world with earth, except the words that start with &nbsp or &gt. Those should be ignored. So the result should be: bye earth, &nbsp;hello &gt;world, bye earth! Tried to this with str.replace(/(?!\&nbsp;)hello/gi,'bye')); But it doesn't work.

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  • using regular expression in Java

    - by Mrityunjay
    Hi, i need to check a string that should contain only ABCDEFG characters, in any sequence and with only 7 characters. Please let me know the correct way of using regular expression. as corrently i am using String abs = "ABPID"; if(!Pattern.matches("[[ABCDEFG]", abs)) System.out.println("Error"); i am using the following code which works when i use the String abcdefg but for other cases it fails. please help me out.

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  • Issue with my regular expression?

    - by Rubans
    I'm trying to locate the number matches in a relative path for directory up references("..\"). So I have the following pattern : "(..\)" which works as expected for the path "....\a\b" where it will give me 2 successfull groups ("..\") but when I try the path "..\a\b" it will also return 2 when it should be 1. I tried this in a reg ex tool such Expresso and it seems to work as expected in there but not in in .net, any ideas?

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  • Python comparing string against several regular expressions

    - by maerics
    I'm pretty experienced with Perl and Ruby but new to Python so I'm hoping someone can show me the Pythonic way to accomplish the following task. I want to compare several lines against multiple regular expressions and retrieve the matching group. In Ruby it would be something like this: STDIN.each_line do |line| case line when /^A:(.*?)$/ then puts "FOO: #{$1}" when /^B:(.*?)$/ then puts "BAR: #{$1}" # when ... else puts "NO MATCH: #{line}" end end My attempts in Python are turning out pretty ugly because the matching group is returned from a call to match/search on a regular expression and Python has no assignment in conditionals or switch statements. What's the Pythonic way to do (or think!) about this problem?

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  • Extract a regular expression match in R version 2.10

    - by tovare
    Hi, I'm trying to extract a number from a string. And do something like this [0-9]+ on this string "aaaa12xxxx" and get "12". I thought it would be something like: > grep("[0-9]+","aaa12xxx", value=TRUE) [1] "aaa12xxx" And then I figured... > sub("[0-9]+", "\\1", "aaa12xxxx") [1] "aaa12xxx" But I got some form of response doing: > sub("[0-9]+", "ARGH!", "aaa12xxxx") [1] "aaaARGH!xxx" There's a small detail I'm missing Please advice :-) I'm using R version 2.10.1 (2009-12-14) Thanks ! Comments on the solution The best solution is to ignore the standard functions and install Hadley Wickham's stringr package to get something that actually makes sense. Kudos to Marek for figuring out how the standard library worked.

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  • Replacing text node of HTML input in PHP

    - by Aman Kumar Jain
    Hi, I want to replace all the text nodes in a html text. I'll explain with an example: $html = " <div> <p> text2 text2 word text2 <span>abcd</span> text2 text2 word text2 <p> this is a long, very long statement with punctuations. </div> I want to replace "text2 text2 word text2" with "<span>text2 text2 word text2</span>" and "this is a long, very long statement with punctuations." with "<span>this is a long, very long statement with punctuations.</span>" What should be the regular expression for the same?

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  • Extracting a string between specified characters in python

    - by Seth
    I'm a newbie to regular expressions and I have the following string: sequence = ["{\"First\":\"Belyuen,NT,0801\",\"Second\":\"Belyuen,NT,0801\"}","{\"First\":\"Larrakeyah,NT,0801\",\"Second\":\"Larrakeyah,NT,0801\"}"] I am trying to extract the text Belyuen,NT,0801 and Larrakeyah,NT,0801 in python. I have the following code which is not working: re.search('\:\\"...\\', ''.join(sequence)) I.e. I want to get the string between characters :\ and \.

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  • Modify a reference numbered group to match against

    - by StuperUser
    I want to match YYYY-YY for sequential years. I at moment I'm trying to match where all the second YY is the 3rd and 4th characters in YYYY with 1 added to it. So far I've got {19|20}(\d{2})-(\d{2}), but not sure how to use ? with reference to (1) or whether I'm going about this the right way and finding out the inevitable "unknown unknowns" (like YY99) with this approach? Edit: Matches: 2010-11,2011-12,2029-30 Not matches: 2010-12, 2010-09,2011-2,2011-2012

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  • Redirect visitor with .htaccess

    - by Aaron
    Hi all, I've got an e-shop on a virtual server that's been used as a subdirectory for the last few years, but now I'm finally giving the VS it's own domain name. What I really need is visitors to the old URL to be transparently (and 301) redirected to the new URL with everything after /eshop/ maintained and apended to the new host. I.e. http://www.example.com/eshop/page.php - http://www.newdomain.com/page.php Any help would be greatly appreciated.

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  • questions on nfa and dfa..

    - by Loop
    Hi Guys... Hope you help me with this one.... I have a main question which is ''how to judge whether a regular expression will be accepted by NFA and/or DFA? For eg. My question says that which of the regular expressions are equivalent? explain... 1.(a+b)*b(a+b)*b(a+b)* 2.a*ba*ba* 3.a*ba*b(a+b)* do we have to draw the NFA and DFA and then find through minimisation algorithm? if we do then how do we come to know that which regular expression is accepted by NFA/DFA so that we can begin with the answer? its so confusing.... Second is a very similar one, the question asks me to show that the language (a^nb^n|n1} is not accepted by DFA...grrrrr...how do i know this? (BTW this is a set of all strings of where a number of a's is followed by the same number of b's).... I hope I explained clearly well....

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