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  • Elegant PostgreSQL Group by for Ruby on Rails / ActiveRecord

    - by digitalfrost
    Trying to retrieve an array of ActiveRecord Objects grouped by date with PostgreSQL. More specifically I'm trying to translate the following MySQL querry: @posts = Post.all(:group => "date(date)", :conditions => ["location_id = ? and published = ?", @location.id, true], :order => "created_at DESC") I am aware that PostgreSQL interpretation of the SQL standard is stricter than MySQL and that consequently this type of query won't work...and have read a number of posts on StackOverflow and elsewhere on the subject - but none of them seem to be the definitive answer on this subject I've tried various combinations of queries with group by and distinct clauses without much joy - and for the moment I have a rather inelegant hack which although works makes me blush when I look at it. What is the proper way to make such a querry with Rails and PostgreSQL ? (Ignoring the fact that surely this should be abstracted away at the ActiveRecord Level)

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  • Facebook profile search using email address of a user

    - by agdev
    Hello, If I have email address of a user, is there any way to find the profile of the user? I know it can be done using the uid and name of the user (GetInfo() or fql.query). The specific problem I am trying to address is when I search for a user using the name field, I end up getting multiple results (people with the same name). I have the email address of the user I want to search, so if I can search using email address, I will be able to reach to the specific user. Alternately, if there's a way to find uid for a given email address, I can get the user I am looking for. Any help is much appreciated. Thanks!

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  • Wpf user control button command is not firing in viewmodel

    - by mani1985
    hi, i have a user control in which there is a button. i wrote icommand in the viewmodel for the button to call some function. when i use this user control in some other page ,the user control button click is not working. my xaml Save my view model private ICommand _insertNewNote; public ICommand InsertNewNote { get { if (_insertNewNote == null) { _insertNewNote = new RelayCommand( param = this.InsertNewExceptionNote()); } return _insertNewNote; } } public void InsertNewExceptionNote() { //... } my problem is when i use this user control in some page like this the user control is getting displayed in the page. but the button in the user control is not firing when i click it. user control view model icommand is not at all initialized. please provide me a solution. Thanks in advance.

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  • group by with 3 diffrent

    - by NN
    I have 2 table and I wanna a query with 3 column result in on of them 2 column with view count and title name and in the other 1 column with type_ and i wanna to grouping type_ with max(view count) and show the them title but i didn't have any idea about grouping expression. i think we can solve in by using sub query but i don't know which column use in group by. 2 table join with this expression class pk=resource key i exam this query: SELECT t.title,j.type_ FROM tags asset t,journal article j where type_ in (select type_ from journal article,tags asset where class pk=resource key group by type_) but the answer was wrong

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  • MySQL LEFT JOIN, GROUP BY and ORDER BY not working as required

    - by Simon
    I have a table 'products' => ('product_id', 'name', 'description') and a table 'product_price' => ('product_price_id', 'product_id', 'price', 'date_updated') I want to perform a query something like SELECT `p`.*, `pp`.`price` FROM `products` `p` LEFT JOIN `product_price` `pp` ON `pp`.`product_id` = `p`.`product_id` GROUP BY `p`.`product_id` ORDER BY `pp`.`date_updated` DESC As you can probably guess the price changes often and I need to pull out the latest one. The trouble is I cannot work out how to order the LEFT JOINed table. I tried using some of the GROUP BY functions like MAX() but that would only pull out the column not the row. Thanks.

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  • Persisting user control values afer postback in asp.net

    - by user557135
    Hi, I have a few user controls which I add to the aspx form depending on the user's choice from a combo box. I have a user control which has a textbox in it and a getValue() method that returns the value of the textbox. After user selects the related item I load the control and add to a panel using loadControl method. User enters some text. After a postback I want to keep the user control and the user input in the same state before . Hope i could be clear. Thanks in advanced

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  • check for several conditions when a user logs in

    - by paul
    I would like to accomplish the following: If a username or password field is null, notify the user. If user name already exists, do not insert into the database and notify user to create a different name. if the username is unique and password is not null, return the username to the user. As of now it always returns "Please enter a different user name." I believe the issue has to do with the database query but I am not sure. If anyone can have a look and see if I am making an error, I greatly appreciate it, thanks. if ($userName or $userPassword = null) { echo "Please enter a user name and password or return to the homepage."; } elseif (mysql_num_rows(mysql_query("SELECT count(userName) FROM logininfo WHERE userName = '$userName'")) ==1) { echo "Please enter a different user name."; } elseif ($userName and $userPassword != null) { echo "Your login name is: $userName"; }

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  • How do I use SPMemember.ID property to get User or Group

    - by Jason
    I have to write a utility to enumerate and manage the owners of groups within a SharePoint site. I know I can use the Groups property of the SPWeb object to retrieve a collection of groups. And I know I can use the Owner property of the group to get back the owner. My problem is that I do not know what to do next. The SPGroup.Owner property returns a SPMember object. The member object has one property called ID that returns the unique ID (an integer) of the member. What I cannot seem to find information on is how to use that integer value to determine if the member is a User or a Group and how to get back additional details (say the name). Any ideas? Thanks.

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  • GROUP BY and SUM distinct date across 2 tables

    - by kenitech
    I'm not sure if this is possible in one mysql query so I might just combine the results via php. I have 2 tables: 'users' and 'billing' I'm trying to group summed activity for every date that is available in these two tables. 'users' is not historical data but 'billing' contains a record for each transaction. In this example I am showing a user's status which I'd like to sum for created date and deposit amounts that I would also like to sum by created date. I realize there is a bit of a disconnect between the data but I'd like to some all of it together and display it as seen below. This will show me an overview of all of the users by when they were created and what the current statuses are next to total transactions. I've tried UNION as well as LEFT JOIN but I can't seem to get either to work. Union example is pretty close but doesn't combine the dates into one row. ( SELECT created, SUM(status) as totalActive, NULL as totalDeposit FROM users GROUP BY created ) UNION ( SELECT created, NULL as totalActive, SUM(transactionAmount) as totalDeposit FROM billing GROUP BY created ) I've also tried using a date lookup table and joining on the dates but the SUM values are being added multiple times. note: I don't care about the userIds at all but have it in here for the example. users table (where status of '1' denotes "active") (one record for each user) created | userId | status 2010-03-01 | 10 | 0 2010-03-01 | 11 | 1 2010-03-01 | 12 | 1 2010-03-10 | 13 | 0 2010-03-12 | 14 | 1 2010-03-12 | 15 | 1 2010-03-13 | 16 | 0 2010-03-15 | 17 | 1 billing table (record created for every instance of a billing "transaction" created | userId | transactionAmount 2010-03-01 | 10 | 50 2010-03-01 | 18 | 50 2010-03-01 | 19 | 100 2010-03-10 | 89 | 55 2010-03-15 | 16 | 50 2010-03-15 | 12 | 90 2010-03-22 | 99 | 150 desired result: created | sumStatusActive | sumStatusInactive | sumTransactions 2010-03-01 | 2 | 1 | 200 2010-03-10 | 0 | 1 | 55 2010-03-12 | 2 | 0 | 0 2010-03-13 | 0 | 0 | 0 2010-03-15 | 1 | 0 | 140 2010-03-22 | 0 | 0 | 150 Table dump: CREATE TABLE IF NOT EXISTS `users` ( `created` date NOT NULL, `userId` int(11) NOT NULL, `status` smallint(6) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `users` (`created`, `userId`, `status`) VALUES ('2010-03-01', 10, 0), ('2010-03-01', 11, 1), ('2010-03-01', 12, 1), ('2010-03-10', 13, 0), ('2010-03-12', 14, 1), ('2010-03-12', 15, 1), ('2010-03-13', 16, 0), ('2010-03-15', 17, 1); CREATE TABLE IF NOT EXISTS `billing` ( `created` date NOT NULL, `userId` int(11) NOT NULL, `transactionAmount` int(11) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `billing` (`created`, `userId`, `transactionAmount`) VALUES ('2010-03-01', 10, 50), ('2010-03-01', 18, 50), ('2010-03-01', 19, 100), ('2010-03-10', 89, 55), ('2010-03-15', 16, 50), ('2010-03-15', 12, 90), ('2010-03-22', 99, 150);

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  • MySQL returns fewer rows with GROUP BY statement

    - by bschaeffer
    I've got a MySQL database that stores image information. Right now it only has three rows stored in the database, and each row is associated with something like, for instance, a unique blog post via a key column. As of right now, one "blog post key" has one image, and one has two images in the database. When I run this query, MySQL returns all three rows. SELECT `id`, `key`, `url` FROM (`images`) WHERE `key` = 'TpaS4G5h' OR `key` = '78855e44' However, when i add the GROUP BY statement I only get two rows... one for each key. SELECT `id`, `key`, `url` FROM (`images`) WHERE `key` = 'TpaS4G5h' OR `key` = '78855e44' GROUP BY `key` I'm sure there is a simple solution, but I don't know what it is... so any help would be really appreciated. Thanks in advance!

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  • Query returning an ascending group number

    - by Dougman
    I have a query like below that has groups (COL1) and that group's values (COL2). select col1, col2 from (select 'A' col1, 1 col2 from dual union all select 'A' col1, 2 col2 from dual union all select 'B' col1, 1 col2 from dual union all select 'B' col1, 2 col2 from dual union all select 'C' col1, 1 col2 from dual union all select 'C' col1, 2 col2 from dual ) order by col1, col2; The output of this query looks like: COL1 COL2 ---- ---- A 1 A 2 B 1 B 2 C 1 C 2 What I need is a query that will return an ordered number increasing for each different group (COL1). It seems like there would be a simple way to accomplish this (maybe with analytics) but for some reason it is escaping me. GRPNUM COL1 COL2 ------ ---- ---- 1 A 1 1 A 2 2 B 1 2 B 2 3 C 1 3 C 2 I am running Oracle 10gR2.

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  • Are sessions modifiable by the client/user?

    - by Sev
    In my PHP Web-App I use sessions to store the user's data. For exmaple, if a user logs in, then an instance of the User class is generated and stored in a Session. I have access levels associated with each user to determine their privileges. Store the user in a session by: $_SESSION['currentUser'] = new User($_POST['username']); For example: if($_SESSION['currentUser'] -> getAccessLevel() == 1) { //allow administration functions } where getAccessLevel() is simply a get method in the User class that returns the _accesslevel member variable. Is this secure? Or can the client somehow modify their access level through session manipulation of some sort?

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  • Need help with a sub query/group/order (get latest comment for each ordered topic)

    - by Scarface
    Hey guys I have a query that currently finds the latest comment for each of a user's topics and then orders topics by that comment's timestamp. What I want to do is expand on this query's use and print the latest comment for each topic. The problem with this query is that while it orders the topics correctly, it prints seemingly random comments for each topic. I am trying to implement a sub query but I am not quite sure how to approach it. I was thinking that I just had to somehow use this query to get the comments. If anyone has any ideas I would really appreciate it. Here is what I think I need to add SELECT * FROM comments where topic_id='$topic_id' ORDER BY timestamp DESC LIMIT 1 Here is the query I need to modify SELECT topic.topic_title, topic.content_type, topic.subject_id, topic.creator, topic.description, topic.topic_id,comments.message,comments.user FROM comments JOIN topic ON topic.topic_id = comments.topic_id WHERE topic.creator = '$user' AND comments.timestamp > $week GROUP BY topic_id ORDER BY MAX(comments.timestamp) DESC

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  • Rails: User specific sequential column

    - by Alex Marchant
    I have an inventory system, where a User has many inventory. We have a barcode column which needs to be sequential for each user. I run into a problem however when doing bulk association building. I end up getting several inventories for a user with the same barcode. For example: Inventory Table: id | user_id | barcode 1 | 1 | 1 2 | 1 | 2 3 | 2 | 1 4 | 2 | 2 5 | 1 | 3 In the Inventory model I have before_validation :assign_barcode, on: :create def assign_barcode self.barcode = (user.inventories.order(barcode: :desc).first.try(:barcode) || 0) + 1 end It generally works, but ran into a problem when seeding my db: (1..5).each do user.inventories.build(...) end user.save I end up with a bunch of inventories for user that have the same barcode. How can I ensure that inventories have unique barcodes even when adding inventories in bulk?

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  • MySQL, PHP, How Many in GROUP

    - by 0Neji
    I'm trying to create a table which outputs a list of users and how many times they've logged in. A new row in the table is created every time that someone logs in so there is multiple rows for one user. Now, I'm trying using the following statement to pull the data out: SELECT * FROM logins GROUP BY user ORDER BY timestamp DESC Which is working fine but now there is a column in my HTML table which should show how many times the user has logged in. How do I go about counting the amount of rows in each group?

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  • Drop and Give Me 20 Questions

    - by [email protected]
    IOUG Sponsors Boot Camp at Collaborate 10 Feeling flabby and out of shape on topics such as virtualization, SQL development, and security? Want to beef up your skills on Oracle Database 11g Release 2, Oracle on Linux for IBM System z, and Oracle's maximum availability architecture on Linux for IBM System z? If so, it's time for boot camp. The Independent Oracle Users Group (IOUG) is sponsoring its first-ever boot camp for Oracle technology and database professionals at Collaborate 10, April 19 to 21. And yes, as with many boot camps, the IOUG programs will be in a harsh, desert environment--at the Mandalay Bay Convention Center in Las Vegas, Nevada. The one- and two-day programs will cover Oracle technology and a variety of database topics, and they'll be taught by drill instructors, including industry experts as well as Oracle users and staff. You'll get in-depth training. But don't worry. You won't have to suffer through a bad haircut and 20-mile hikes. Are you ready? Was that a "yes, sir"? I can't hear you.

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  • OS X multiple use of same machine via VNC

    - by Hassan Syed
    I'm wondering if I can connect to my wife's mac via VNC while she is logged in herself. I wouldn't be surprised if this isn't possible, although the machinery should be there with "fast-user-switching" support. So, if I create a profile for myself and I log in (and enable the VNC server/sharing for my profile), and then my wife switches to her own account which she uses on the physical console. Will I be able to use the mac ?

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  • Reading line for Ubuntu users

    - by Willy Levine
    Normally when I read a book I use a bookmark held horizontally under the current line I'm reading to help me keep my eyes on the right spot. When I read a PDF or other document on my computer I would like to be able to do the same thing, only with a line on the screen controlled by the up and down arrow keys. Any suggestions for an application which would do this? I'm a Ubuntu Linux user.

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  • Chrome Open in New Tab/Window Menu Items

    - by Aequitarum Custos
    The problem is, both Firefox and Internet Explorer have "Open in New Tab" as the second option. This has become muscle memory for me by now, to the point that I don't use as often as I want to, solely because I can't open a page in a new tab without thinking about it. Is there a way to switch the position of "Open Link in new tab" and "Open link in new window", so that I can resume browsing as normal, or am I cursed by this user interface design nightmare by Google?

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  • My Window's 7 is exposing me and my files I am the only administrator.

    - by Connie
    I am the only administrator on my Window's 7 Asus x53E series laptop. Why is a standard user able to access my files by just searching my name in the start menu? If I log into guest account and search my name it shows an error that i don't have permission. When i log into my roommate's standard account and go to the start menu I put my name in search and everything I have done or searched is open to them . How can i make my administrator account private

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