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  • cygwin g++ produces no output

    - by fred basset
    I just installed g++ from cygwin, when I try to compile a C++ file I am not getting any executable produced by the compiler, see example below. What's going wrong? Directory of C:\helloworld 01/02/2011 04:50 PM . 01/02/2011 04:50 PM .. 01/02/2011 04:48 PM 94 helloworld.cpp 1 File(s) 94 bytes 2 Dir(s) 24,658,272,256 bytes free C:\helloworldg++-4 helloworld.cpp C:\helloworlddir Volume in drive C is OS Volume Serial Number is C47B-942D Directory of C:\helloworld 01/02/2011 04:50 PM . 01/02/2011 04:50 PM .. 01/02/2011 04:48 PM 94 helloworld.cpp 1 File(s) 94 bytes 2 Dir(s) 24,657,747,968 bytes free C:\helloworld

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  • submit button on html to output result on same page

    - by amateur
    Hi, Although this seems like something very basic, but no matter what I tried I couldn't get my head around it. Basically I want a html form where a user types in their ID number in an input text box and when they hit the submit button it displays their email address which is their company ID number @ company.com, such as below <form action=""> ID Number: <input type="text" name="idnumber" /><br/> <input type="submit" value="Whats my email address" /> </form> <p>Your email address is 'idnumber'@email.com</p> Can this even be done using html or would I need to use Javascript or PHP for it? Thanks

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  • !gcroot output leads nowhere

    - by Jeff Costa
    I am troubleshooting memory fragmentation in an app pool, as evidenced by a small number of Free objects consuming the most space on the heap: 0x000007ff00256728 6,543 3,890,208 System.Collections.Hashtable+bucket[] 0x000007ff002649a8 7,297 22,979,560 System.Byte[] 0x000007ff001e0d90 251,347 30,374,304 System.String 0x0000000001d0c830 373 48,036,816 Free Running the !dumpgen 3 command reveals the fragmentation; There is a repeating pattern of Free and System.Object objects of the same size: 000000017feb7350 24 **** FREE **** 000000017feb7368 8192 System.Object[] 000000017feb9368 24 **** FREE **** 000000017feb9380 8192 System.Object[] 000000017febb380 24 **** FREE **** 000000017febb398 8192 System.Object[] 000000017febd398 24 **** FREE **** 000000017febd3b0 8192 System.Object[] 000000017febf3b0 24 **** FREE **** 000000017febf3c8 8192 System.Object[] 000000017fec13c8 24 **** FREE **** 000000017fec13e0 8192 System.Object[] 000000017fec33e0 24 **** FREE **** 000000017fec33f8 8192 System.Object[] 000000017fec53f8 24 **** FREE **** 000000017fec5410 14024 System.Object[] 000000017fec8ad8 24 **** FREE **** 000000017fec8af0 8192 System.Object[] 000000017fecaaf0 24 **** FREE **** 000000017fecab08 8192 System.Object[] 000000017feccb08 24 **** FREE **** 000000017feccb20 8192 System.Object[] 000000017feceb20 24 **** FREE **** 000000017feceb38 8192 System.Object[] 000000017fed0b38 24 **** FREE **** 000000017fed0b50 8192 System.Object[] 000000017fed2b50 24 **** FREE **** 000000017fed2b68 8192 System.Object[] When I try to obtain the root of one of the System.Objects with !gcroot, I get a pinned handle, but no additional stack data: Scan Thread 41 OSThread 1044 DOMAIN(0000000001D51330):HANDLE(Pinned):15217e8:Root: 000000017fe60fe8(System.Object[]) As you can see, there is no additional data to go on. Running a !handle command also yields nothing: 0:041> !handle 000000017fe7a068 ff Handle 000000017fe7a068 Type <Error retrieving type> unable to query object information unable to query object information No object specific information available How can I trace out this memory leak when I cannot find what is rooting System.Object?

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  • Using Entity Framework V4 - Mapping Stored Procedures with XML output

    - by ericwahner
    I have been attempting to implement the Entity framework into my project and unfortunately it seems like mapping an XML result set from SQL is not something that is supported. I also have issues with returning multiple result sets, though I understand that the EFExtensions was created to try to mitigate that issue. Is there a way to take a FOR XML EXPLICIT result from a SQL Stored Procedure and map it using the Entity Framework?

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  • Trouble recording unique regex output to array in perl

    - by Structure
    The goal of the following code sample is to read the contents of $target and assign all unique regex search results to an array. I have confirmed my regex statement works so I am simplifying that so as not to focus on it. When I execute the script I get a list of all the regex results, however, the results are not unique which leads me to believe that my manipulation of the array or my if (grep{$_ eq $1} @array) { check is causing a problem(s). #!/usr/bin/env perl $target = "string to search"; $inc = 0; $once = 1; while ($target =~ m/(regex)/g) { #While a regex result is returned if ($once) { #If $once is not equal to zero @array[$inc] = $1; #Set the first regex result equal to @array[0] $once = 0; #Set $once equal to zero so this is not executed more than once } else { if (grep{$_ eq $1 } @array ) { #From the second regex result, check to see if the result is already in the array #If so, do nothing } else { @array[$inc] = $1; #If it is not, then assign the regex search result to the next unused position in the array in any position. $inc++; #Increment to next unused array position. } } } print @array; exit 0;

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  • Output of Iterable.sliding as Tuple

    - by ziggystar
    The method sliding on collections returns a sliding window of given size in the form of X[Iterable[A]] with X being the type of the collection and A the element type. Often I need two or three elements and I prefer to have them named. One ugly workaround for sliding(2) is the following: points.sliding(2).foreach{ twoPoints => val (p1,p2) = (twoPoints.head,twoPoints.last) //do something } This sucks and only works for two elements. Also note that (a,b) = (twoPoints(0),twoPoints(1)) doesn't work. Help me!

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  • Rails3 - will_paginate plugin strange output

    - by Sam
    I have the will_paginate plugin working in an application, but when I paginate a resource it just spits out the HTML as text, doesn't provide links to the next pages and such. And when I manually type in the URL the plugin is working it just doesn't make <%= will_paginate @products %> into links such as next 1 2 3 ... last Ideas?

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  • Perl parsing ps fwaux output

    - by Magic Hat
    I am trying to figure out children processes of a given parent from ps fwaux (there may very well be a better way to do this). Basically, I have daemons running that may or may not have a child process running at any given time. In another script I want to check if there are any child processes, and if so do something. If not, error out. ps fwaux|grep will show me the tree, but I'm not exactly sure what to do with it. Any suggestions would be great.

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  • formatting fgetcsv output

    - by Patrick
    Im trying to figure out how to take the data returned by fgetcsv, and format it into a readable/editable table, and then use fputcsv to save that table so far i have this <?php $row = 1; $handle = fopen("csv.csv", "r"); while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) { $num = count($data); $row++; for ($c=0; $c < $num; $c++) { echo $data[$c] . "\n"; } } fclose($handle); ?>

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  • Strange output produced by program

    - by Boom_mooB
    I think that my code works. However, it outputs 01111E5, or 17B879DD, or something like that. Can someone please tell me why. I am aware that I set the limit of P instead of 10,001. My code is like that because I start with 3, skipping the prime number 2. #include <iostream> bool prime (int i) { bool result = true; int isitprime = i; for(int j = 2; j < isitprime; j++) ///prime number tester { if(isitprime%j == 0) result = false; } return result; } int main (void) { using namespace std; int PrimeNumbers = 1; int x = 0; for (int i = 3 ; PrimeNumbers <=10000; i++) { if(prime(i)) { int prime = i; PrimeNumbers +=1; } } cout<<prime<<endl; system ("pause"); return 0; }

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  • What does this java output mean?!

    - by Phil
    public class Arrys { private int[] nums; //Step 3 public Arrys (int arrySize) { nums = new int[arrySize]; } public int [] getNums (){ return nums; } } Test class: public class TestArrys { public static void main(String args[]) { //Step 4 Arrys arry = new Arrys(10); System.out.println("\nStep4 "); for(int index = 0; index < arry.getNums().length; index++) { System.out.print(arry.getNums()); } } } It's incredibly simple, that is why I think I'm doing something fundamentally wrong. All I want is to display the value of the array. This is what I get back. I am totally lost, there is nothing in my book that explains this nor does googling it help. Step4 [I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440[I@1ac88440

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  • CVS Diff to output only modified files?

    - by Somebody still uses you MS-DOS
    Is it possible? Run a cvs diff in terminal at the project root that outputs only modified files (like local files that aren't in source control and local modified files). I'm running cvs diff --brief but I still have too many results since my project is large, and with a lot of subdirectories - it shows the whole hierarchy and I just want to know which files are different from HEAD revision. I'm using Linux.

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  • Unexpected output on initializing array by using both `element-by-element` & `designated` technique

    - by haccks
    C99 provides a feature to initialize arrays by using both element-by-element & designated method together as: int a[] = {2,1,[3] = 5,[5] = 9,6,[8] = 4}; On running the code: #include <stdio.h> int main() { int a[] = {2,1,[3] = 5,[0] = 9,4,[6] = 25}; for(int i = 0; i < sizeof(a)/sizeof(a[0]); i++) printf("%d ",a[i]); return 0; } (Note that Element 0 is initialized to 2 and then again initialised by designator [0] to 9) I was expecting that element 0(which is 2) will be replaced by 9(as designator [0] = 9) and hence o/p will become 9 1 0 5 4 0 25 Unfortunately I was wrong as o/p came; 9 4 0 5 0 0 25 Any explanation for unexpected o/p?

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  • How to log SQL output to text file on client from C#

    - by Rob Packwood
    I have a large auditing stored procedure that prints values and runs some SELECT statements. When running within SQL Management Studio we have the use select to display "Results to Text" so all of the SQL results and print statement display in one place. Now I need to have some C# code also call this auditing procedure at the end of the process and basically store all data that would be in the "Results to Text" window into a .txt file. How can this be done?

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  • One input file to multiple output files

    - by user1265669
    I found some helpful stuff on this site but my input file is different from the examples already posted and I cannot make the leap in an efficient manner. My input file looks like this: sample_dude data1 data2 data3 data4 sample_lady data5 data6 data7 data8 sample_dude data9 data10 data11 data12 sample_child data13 data14 data15 data16 I want to create a separate file for each sample with all the data columns. For example, one file would be called sample_dude.txt and look like this: data1 data2 data3 data4 data9 data10 data11 data12 There is an unknown number of samples but always just four data columns. Any help greatly appreciated. Thank you. PS: I'm trying to do this in python.

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  • Weird output as the numbers get bigger in Fibonacci sequence

    - by Jon
    I noticed in my fibonacci sequence that I'm getting negative numbers after a certain point. Does this have to do with the limited range of "int"? or is there something wrong with my code? Here is the code: using std::cout; int main() { int n = 50, f1 = 0, f2 = 1, fn = 0, i = 0; cout << "0 "; for (i = 0; i < n; i++) { fn = f1 + f2; f2 = f1; f1 = fn; cout << fn << " "; }

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  • writing terminal output to file

    - by user1551817
    On my machine, I have some software which takes commands in the terminal and returns a list of values. To run it, I have to type something like: pdv -t filename I am trying to run it as part of a python programme. When I run the following: os.system('pdv -t %s' % (epoch_name)) then I get the values that I desire returned to my terminal (where epoch_name is the variable name for the filename). But when I try to write the result to a file: os.system('pdv -t %s % "(epoch_name)" > 123.txt') the file 123.txt is produced but it is empty. I know that I am misplacing the " and/or ' characters, but I can't figure out where they should go. Any help would be gratefully received!

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  • How to get jquery to append output immediately after each ajax call in a loop

    - by david_nash
    I'd like to append to an element and have it update immediately. console.log() shows the data as expected but append() does nothing until the for loop has finished and then writes it all at once. index.html: ... <body> <p>Page loaded.</p> <p>Data:</p> <div id="Data"></div> </body> test.js: $(document).ready(function() { for( var i=0; i<5; i++ ) { $.ajax({ async: false, url: 'server.php', success: function(r) { console.log(r); //this works $('#Data').append(r); //this happens all at once } }); } }); server.php: <?php sleep(1); echo time()."<br />"; ?> The page doesn't even render until after the for loop is complete. Shouldn't it at least render the HTML first before running the javascript?

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  • Do these methods have same output?

    - by devrimbaris
    protected synchronized boolean isTimeoutOccured(Duration timeoutDuration) { DateTime now = new DateTime(); if (timeoutOccured == false) { if (new Duration(requestTime.getMillis(), now.getMillis()).compareTo(timeoutDuration) > 0) { timeoutOccured = true; } } return timeoutOccured; } protected boolean isTimeoutOccured2(Duration timeoutDuration) { return atomicTimeOut.compareAndSet(false, new Duration(requestTime.getMillis(), new DateTime().getMillis()).compareTo(timeoutDuration) > 0); }

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  • delay loop output in C++

    - by itachisxeyes
    I have a while loop that runs in a do while loop. I need the while loop to run exactly every second no faster no slower. but i'm not sure how i would do that. this is the loop, off in its own function. I have heard of the sleep() function but I also have heard that it is not very accurate. int min5() { int second = 00; int minute = 0; const int ZERO = 00; do{ while (second <= 59){ if(minute == 5) break; second += 1; if(second == 60) minute += 1; if(second == 60) second = ZERO; if(second < 60) cout << "Current Time> "<< minute <<" : "<< second <<" \n"; } } while (minute <= 5); }

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  • How can I get the output of a command terminated by a alarm() call in Perl?

    - by rockyurock
    Case 1 If I run below command i.e iperf in UL only, then i am able to capture the o/p in txt file @output = readpipe("iperf.exe -u -c 127.0.0.1 -p 5001 -b 3600k -t 10 -i 1"); open FILE, ">Misplay_DL.txt" or die $!; print FILE @output; close FILE; Case 2 When I run iperf in DL mode , as we know server will start listening in cont. mode like below even after getting data from client (Here i am using server and client on LAN) @output = system("iperf.exe -u -s -p 5001 -i 1"); on server side: D:\_IOT_SESSION_RELATED\SEEM_ELEMESNTS_AT_COMM_PORT_CONF\Tput_Related_Tools\AUTO MATION_APP_\AUTOMATION_UTILITYiperf.exe -u -s -p 5001 ------------------------------------------------------------ Server listening on UDP port 5001 Receiving 1470 byte datagrams UDP buffer size: 8.00 KByte (default) ------------------------------------------------------------ [1896] local 192.168.5.101 port 5001 connected with 192.168.5.101 port 4878 [ ID] Interval Transfer Bandwidth Jitter Lost/Total Datagrams [1896] 0.0- 2.0 sec 881 KBytes 3.58 Mbits/sec 0.000 ms 0/ 614 (0%) command prompt does not appear , process is contd... on client side: D:\_IOT_SESSION_RELATED\SEEM_ELEMESNTS_AT_COMM_PORT_CONF\Tput_Related_Tools\AUTO MATION_APP_\AUTOMATION_UTILITYiperf.exe -u -c 192.168.5.101 -p 5001 -b 3600k -t 2 -i 1 ------------------------------------------------------------ Client connecting to 192.168.5.101, UDP port 5001 Sending 1470 byte datagrams UDP buffer size: 8.00 KByte (default) ------------------------------------------------------------ [1880] local 192.168.5.101 port 4878 connected with 192.168.5.101 port 5001 [ ID] Interval Transfer Bandwidth [1880] 0.0- 1.0 sec 441 KBytes 3.61 Mbits/sec [1880] 1.0- 2.0 sec 439 KBytes 3.60 Mbits/sec [1880] 0.0- 2.0 sec 881 KBytes 3.58 Mbits/sec [1880] Server Report: [1880] 0.0- 2.0 sec 881 KBytes 3.58 Mbits/sec 0.000 ms 0/ 614 (0%) [1880] Sent 614 datagrams D:\_IOT_SESSION_RELATED\SEEM_ELEMESNTS_AT_COMM_PORT_CONF\Tput_Related_Tools\AUTO MATION_APP_\AUTOMATION_UTILITY so with this as server is cont. listening and never terminates so can't take output of server side to a txt file as it is going to the next command itself to create a txt file so i adopted the alarm() function to terminate the server side (iperf.exe -u -s -p 5001) commands after it received all data from the client. could anybody suggest me the way.. Here is my code: #! /usr/bin/perl -w my $command = "iperf.exe -u -s -p 5001"; my @output; eval { local $SIG{ALRM} = sub { die "Timeout\n" }; alarm 20; #@output = `$command`; #my @output = readpipe("iperf.exe -u -s -p 5001"); #my @output = exec("iperf.exe -u -s -p 5001"); my @output = system("iperf.exe -u -s -p 5001"); alarm 0; }; if ($@) { warn "$command timed out.\n"; } else { print "$command successful. Output was:\n", @output; } open FILE, ">display.txt" or die $!; print FILE @output_1; close FILE; i know that with system command i cannot capture the o/p to a txt file but i tried with readpipe() and exec() calls also but in vain... could some one please take a look and let me know why the iperf.exe -u -s -p 5001 is not terminating even after the alarm call and to take the out put to a txt file

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