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  • Behavior of Struts2 and convention-plugin when there is Index(extends ActionSupport)

    - by hanishi
    We have an Action class named 'Index' immediately under com.example.common.action and is annotated @ParentPackage('default') which is declared in package directive in struts.xml and has "/" for its namespace and extends "struts-default". It also declares @Result so that it responses with jsp files corresponding the string values returned by its execute() method. In our struts.xml, the following struts setting is configured along with other necessary configurations that are needed for convention-plugin. <constant name="struts.action.extension" value=","/> When accessing /my_context/none_existing_path, the request apparently hits this Index class and the contents of the jsp declared in the Index's @Result section gets returned. However, if we provide /my_context/, we receive the following error: HTTP Status 404-There is no Action mapped for namespace[/] and action name [] associated with context path [/my_context]. We want to know the reason why accessing /my_context/none_existing_path, where none_existing_path has no matching action, can fallback to Index class, but error is returned when when the URL requested is just /my_context/. Currently, our convention-plugin settings are declared as follows: <constant name="struts.convention.package.locators.basePackage" value="com.example"/> <constant name="struts.convention.package.locators" value="action"/> Strangely, if we changed the value of the struts.convention.package.locators.basePackage to om.example.common, in which the aforementioned Index file can be immediately found by narrowing the search scope, requesting /my_context/ displays the content of the jsps declared in @Result section of the Index class. However, as our action classes are distributed throughout the com.example.[a-z].action packages, where [a-z] represents the large volume of directories we have in our package structure, we cannot use this trick as a workaround. We have also tried placing index.jsp at the top level of the class path, and have the index.jsp redirect to /my_context/index, which worked but not what we want. Could this be a bug? We appreciate your responses. Thank you in advance. EDIT: JIRA registered, problem solved (from Struts 2.3.12 up)

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  • How to use observer_field in RoR?

    - by Sindri Guðmundsson
    Hi, I have a single select_tag with categories gathered from array in controller. When the user selects a category I want the application to redirect to the selected category. I have the following code in my view which. (I've tried both using :method = :get and :post, only change is in development.log) <%=select_tag "cat_selected", options_for_select(@cats_for_mt)%><br> <%=observe_field 'cat_selected', :url => {:action => :viewflokkur}, :with => 'cat', :method => :get %> When I select one of the options the following gets logged to development.log. Processing CategoriesController#viewflokkur (for 127.0.0.1 at 2010-06-12 12:33:26) [GET] Parameters: {"cat"=>"Taugasjúkraþjálfun", "authenticity_token"=> "B2u5ULNr7IJ/ta0+hiAMBjmjEtTtc/yMAQQvSxFn2d0="} Rendering template within layouts/main Rendering categories/viewflokkur Completed in 20ms (View: 18, DB: 0) | 200 OK [http://localhost/categories/viewflokkur?cat=Taugasj%C3%BAkra%C3%BEj%C3%A1lfun&authenticity_token=B2u5ULNr7IJ%2Fta0%2BhiAMBjmjEtTtc%2FyMAQQvSxFn2d0%3D] According to this I should now be in "viewflokkur", but nothing changes in the browser window. Is there anything else I need to do, maybe in the controller? BR, Sindri

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  • Cleaning up PHP Code

    - by Michael
    Hi, I've noticed I am a very sloppy coder and do things out of the ordinary. Can you take a look at my code and give me some tips on how to code more efficiently? What can I do to improve? session_start(); /check if the token is correct/ if ($_SESSION['token'] == $_GET['custom1']){ /*connect to db*/ mysql_connect('localhost','x','x') or die(mysql_error()); mysql_select_db('x'); /*get data*/ $orderid = mysql_real_escape_string($_GET['order_id']); $amount = mysql_real_escape_string($_GET['amount']); $product = mysql_real_escape_string($_GET['product1Name']); $cc = mysql_real_escape_string($_GET['Credit_Card_Number']); $length = strlen($cc); $last = 4; $start = $length - $last; $last4 = substr($cc, $start, $last); $ipaddress = mysql_real_escape_string($_GET['ipAddress']); $accountid = $_SESSION['user_id']; $credits = mysql_real_escape_string($_GET['custom3']); /*insert history into db*/ mysql_query("INSERT into billinghistory (orderid, price, description, credits, last4, orderip, accountid) VALUES ('$orderid', '$amount', '$product', '$credits', '$last4', '$ipaddress', '$accountid')"); /*add the credits to the users account*/ mysql_query("UPDATE accounts SET credits = credits + $credits WHERE user_id = '$accountid'"); /*redirect is successful*/ header("location: index.php?x=1"); }else{ /*something messed up*/ header("location: error.php"); }

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  • jQuery preventing RedirectToAction from working?

    - by DaveDev
    I'm trying to redirect the user if they login successfully but the code I have on my page seems to be preventing the redirection from working. If I remove the jQuery below the redirection works. Can somebody tell me tell me if there's something I'm doing wrong? Thanks I have the following Action: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Login(User user) { var myErrors = new Dictionary<string, string>(); try { if (ModelState.IsValid) { if (userRepository.ValidUser(user)) { return RedirectToAction("Index", "Group", new {page = (int?)null}); } else { return Json("Username or password seems to be incorrect"); } } else { foreach (KeyValuePair<string, ModelState> keyValuePair in ViewData.ModelState) { if (keyValuePair.Value.Errors.Count > 0) { List<string> errors = new List<string>(); myErrors.Add(keyValuePair.Key, keyValuePair.Value.Errors[0].ErrorMessage); } } return Json(myErrors); } } catch (Exception) { return Json("Invalid"); } } and the following code on my page: <script language="javascript" type="text/javascript"> $(document).ready(function() { $("#SaveSuccess").hide(); $("#btnLogin").click(function() { $("form").submit(function(event) { var formData = $(this).serialize(); $.post($(this).attr("action"), formData, function(res) { ShowErrors(res); if (res == true) { $("#SaveSuccess").text("Saved"); } else { $("#divError").html(res); } $("#SaveSuccess").fadeIn(100); }, "json"); return false; }); }); }); </script>

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  • Clearing Session in Global Application_Error

    - by Zarigani
    Whenever an unhandled exception occurs on our site, I want to: Send a notification email Clear the user's session Send the user to a error page ("Sorry, a problem occurred...") The first and last I've had working for a long time but the second is causing me some issues. My Global.asax.vb includes: Sub Application_Error(ByVal sender As Object, ByVal e As EventArgs) ' Send exception report Dim ex As System.Exception = Nothing If HttpContext.Current IsNot Nothing AndAlso HttpContext.Current.Server IsNot Nothing Then ex = HttpContext.Current.Server.GetLastError End If Dim eh As New ErrorHandling(ex) eh.SendError() ' Clear session If HttpContext.Current IsNot Nothing AndAlso HttpContext.Current.Session IsNot Nothing Then HttpContext.Current.Session.Clear() End If ' User will now be sent to the 500 error page (by the CustomError setting in web.config) End Sub When I run a debug, I can see the session being cleared, but then on the next page the session is back again! I eventually found a reference that suggests that changes to session will not be saved unless Server.ClearError is called. Unfortunately, if I add this (just below the line that sets "ex") then the CustomErrors redirect doesn't seem to kick in and I'm left with a blank page? Is there a way around this?

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  • Can redirection of screen output to file change the result of a C++ code?

    - by Biga
    I am having this very weird behaviour with a C++ code: It gives me different results when running with and without redirecting the screen output to a file (reproducible in cygwin and linux). I mean, if I get the same executable and run it like ./run or run it like ./run >out.log, I get different results! I use std::cout to output to screen, all lines ending with endl; I use ifstream for the input file; I use ofstream for output, all lines ending with endl. I am using g++ 4. Any idea what is going on? UPDATE: I have hard-coded the input data, so 'ifstream' is not used, and problem persists. UPDATE 2: That's getting interesting. I have probed three variables that are computed initially, and that's what I get when using with and without redirecting the output to file redirected to file: 0 -0.02 0 direct to screen: 0 -0.02 1.04083e-17 So there's a round-off difference in the code variables with and without redirecting the output! Now, why redirecting would interefere with an internal computation of the code? UPDATE 3: If I redirect to /dev/null, I get the sam behaviour as outputing direct to screen, instead of redirecting to file.

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  • Load page for validation but do not display it to user in ASP.NET

    - by Kevin
    We have a site requiring users pay $2 to view the details of a record. We occasionally get complaints because we send them to the payment page, and once they pay it turns out the record isn't valid, or it was lost, or the data couldn't be generated. So we want to add in a check to ensure the page constructs properly before the user is required to pay for it. However, we don't want the user to have access to the page until they pay for it. Is there anything in ASP.NET 3.5 or just general web design that would allow something like this? The data on the record is real time and computed on a backend server before sent to the client. Occasionally this computation fails for whatever reason. Our alternative is to call all of the loading methods and validate the data, then redirect them to the payment page. The problem is A) this will be a relatively involved process rewriting all of these methods to return validation information, and B) it still doesn't guarentee us the page will load properly. Any thoughts?

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  • A little confused about MVC and where to put a database query

    - by jax
    OK, so my Joomla app is in MVC format. I am still a little confused about where to put certain operations, in the Controller or in the Model. This function below is in the controller, it gets called when &task=remove. Should the database stuff be in the Model? It does not seem to fit there because I have two models editapp (display a single application) and allapps (display all the applications), now which one would I put the delete operation in? /** * Delete an application */ function remove() { global $mainframe; $cid = JRequest::getVar( 'cid', array(), '', 'array' ); $db =& JFactory::getDBO(); //if there are items to delete if(count($cid)){ $cids = implode( ',', $cid ); $query = "DELETE FROM #__myapp_apps WHERE id IN ( $cids )"; $db->setQuery( $query ); if (!$db->query()){ echo "<script> alert('".$db->getErrorMsg()."');window.history.go(-1); </script>\n"; } } $mainframe->redirect( 'index.php?option=' . $option . '&c=apps'); } I am also confused about how the flow works. For example, there is a display() function in the controller that gets called by default. If I pass a task, does the display() function still run or does it go directly to the function name passed by $task?

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  • grails question (sample 1 of Grails To Action book) problem with Controller and Service

    - by fegloff
    Hi, I'm doing Grails To Action sample for chapter one. Every was just fine until I started to work with Services. When I run the app I have the following error: groovy.lang.MissingPropertyException: No such property: quoteService for class: qotd.QuoteController at qotd.QuoteController$_closure3.doCall(QuoteController.groovy:14) at qotd.QuoteController$_closure3.doCall(QuoteController.groovy) at java.lang.Thread.run(Thread.java:619) Here is my groovie QuoteService class, which has an error within the definition of GetStaticQuote (ERROR: Groovy:unable to resolve class Quote) package qotd class QuoteService { boolean transactional = false def getRandomQuote() { def allQuotes = Quote.list() def randomQuote = null if (allQuotes.size() > 0) { def randomIdx = new Random().nextInt(allQuotes.size()) randomQuote = allQuotes[randomIdx] } else { randomQuote = getStaticQuote() } return randomQuote } def getStaticQuote() { return new Quote(author: "Anonymous",content: "Real Programmers Don't eat quiche") } } Controller groovie class package qotd class QuoteController { def index = { redirect(action: random) } def home = { render "<h1>Real Programmers do not each quiche!</h1>" } def random = { def randomQuote = quoteService.getRandomQuote() [ quote : randomQuote ] } def ajaxRandom = { def randomQuote = quoteService.getRandomQuote() render "<q>${randomQuote.content}</q>" + "<p>${randomQuote.author}</p>" } } Quote Class: package qotd class Quote { String content String author Date created = new Date() static constraints = { author(blank:false) content(maxSize:1000, blank:false) } } I'm doing the samples using Eclipse with grails addin. Any advice? Regards, Francisco

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  • Drupal 6 Validation for Form Callback Function

    - by Wade
    I have a simple form with a select menu on the node display page. Is there an easy way to validate the form in my callback function? By validation I don't mean anything advanced, just to check that the values actually existed in the form array. For example, without ajax, if my select menu has 3 items and I add a 4th item and try to submit the form, drupal will give an error saying something similar to "an illegal choice was made, please contact the admin." With ajax this 4th item you created would get saved into the database. So do I have to write validation like if ($select_item > 0 && $select_item <= 3) { //insert into db } Or is there an easier way that will check that the item actually existed in the form array? I'm hoping there is since without ajax, drupal will not submit the form if it was manipulated. Thanks. EDIT: So I basically need this in my callback function? $form_state = array('storage' => NULL, 'submitted' => FALSE); $form_build_id = $_POST['form_build_id']; $form = form_get_cache($form_build_id, $form_state); $args = $form['#parameters']; $form_id = array_shift($args); $form_state['post'] = $form['#post'] = $_POST; $form['#programmed'] = $form['#redirect'] = FALSE; drupal_process_form($form_id, $form, $form_state); To get $_POST['form_build_id'], I sent it as a data param, is that right? Where I use form_get_cache, looks like there is no data. Kind of lost now.

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  • Blocking HTML and Javascript from being displayed on my site

    - by Tim Powell
    I am working on this new social networking site. One of it's various functions is posting. You can post to Facebook and my site, or Twitter and my site. That being said, I couldn't help but try and post HTML as I was testing sql injection. When I did, I noticed that there where ways to manipulate the site to, for instance, using a element to completely screw up the CSS design, or redirect a user to another site using javascript. That being said, I want to make my site a safe environment for my users... not a site that is used to distribute computer viruses, porn, and other things that might make someone tend to stay off of my site. When I searched this topic, I found ways to "strip" the HTML out of the $post variable before submitting it to the database. However, I would just like to make it so you can post any text, including HTML and Javascript, without the browser interpreting it as "run this..." code: I want to display it as plane text. I've seen it on Facebook, and when I looked at it the source code of a post, it showed <, /, and as regular text. I tried "dissecting" Facebook's source code, but found nothing. I have tried using tags such as <pre> and <code>, but because of the lack of ability to style and control them, I gave up and went back to just allowing HTML. Please, anyone who knows how to do this, please help me out. Thanks in advance, TP

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  • php code works with mamp but not on ubuntu server

    - by user355510
    Hello, I have start looking at a twitter php library http://github.com/abraham/twitteroauth, but i can't get it to work on my ubuntu server, but on my mac, with mamp it works without any problems. This is the code that don't won't to work on my server, but in mamp. Yes i have edit config file <?php /* Start session and load library. */ session_start(); require_once('twitteroauth/twitteroauth.php'); require_once('config.php'); /* Build TwitterOAuth object with client credentials. */ $connection = new TwitterOAuth(CONSUMER_KEY, CONSUMER_SECRET); /* Get temporary credentials. */ $request_token = $connection->getRequestToken(OAUTH_CALLBACK); /* Save temporary credentials to session. */ $_SESSION['oauth_token'] = $token = $request_token['oauth_token']; $_SESSION['oauth_token_secret'] = $request_token['oauth_token_secret']; /* If last connection failed don't display authorization link. */ switch ($connection->http_code) { case 200: /* Build authorize URL and redirect user to Twitter. */ $url = $connection->getAuthorizeURL($token); header('Location: ' . $url); break; default: /* Show notification if something went wrong. */ echo 'Could not connect to Twitter. Refresh the page or try again later.'; } I have enable php session on my ubuntu server, because this code works <?php session_start(); $_SESSION["secretword"] = "hello there"; $secretword = $_SESSION["secretword"] ; ?> <html> <head> <title>A PHP Session Example</title> </head> <body> <?php echo $secretword; ?> </body> </html>

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  • Simple JPG/HTML Not Showing Up in iPhone

    - by Jascha
    I'm not familiar with iPhones wants and needs, nor do I have one, but a client wants a screen cap of his site to show up when an iPhone user comes around so I created an .htaccess redirect to an iPhone specific page with this bit of code... RewriteEngine on RewriteCond %{HTTP_USER_AGENT} iPhone RewriteCond %{REQUEST_URI} !^/iPhone/ RewriteRule .* /iPhone/ [R] And the html of the iPhone page... <html> <head> <title>Eatamadedia</title> </head> <body style="background-color:#858384;margin:0 auto;"> <img src="../images/iPhonePage.jpg"> </body> </html> The page redirects just fine, but the .jpg doesn't show up. I can't imagine a simpler page. Anyone know what could be preventing the image from displaying? Does the iPhone require headers? The site in question is http://eatamedida.com Thank you in advance for your input. -J

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  • is it possible to make one click fires two events or more by javascript?

    - by NewInAlbert
    I am currently making a temporary download page for website visitor. The page includes a form, after the visitor fills the form up, the site will take them to the pdf download page. In the download page, there are some pdf files download links (I am just using a tag.). However, i wanna make a onclick event to those links, once they have been clicked, the page will refresh automatically or redirect to other pages. <a href="/file.pdf" onClick="window.location.reload()">The File</a> I have tried the jquery way as well. <a href="/file.pdf" id="FileDownload">The File</a> <script> $("#FileDownload").click(function(){ location.reload(); }); </script> But all the them are not working. Do you masters have any good ideas about this, many thanks. P.S. What if I wanna add a countdown after a file is being started download, and then do page reload when countdown finishes. Looks like have asked several questions... Thanks a ton in advance.

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  • CakePHP – 2 controllers, 1 form

    - by user1327
    I need to create a review form. I have 2 models and 2 controllers – Products and Reviews with 'Products' hasMany 'Reviews' relationship, the review form will be displayed on the current product page (Products controller, 'view' action), and this form will be use another controller (Reviews). Also I need validation with validation errors being displayed for this form. In my Products controller view.ctp I have: // product page stuff... echo $this->Form->create($model = 'Review', array('url' => '/reviews/add')); echo $this->Form->input('name', array('label' => 'Your name:')); echo $this->Form->input('email', array('label' => 'Your e-mail:')); echo $this->Form->input('message', array('rows' => '6', 'label' => 'Your message:')); echo $this->Form->end('Send'); echo $this->Session->flash(); ReviewsController - add: public function add() { if ($this->request->is('post')) { $this->Review->save($this->request->data); $this->redirect(array('controller' => 'products', 'action' => 'view', $this->request->data['Review']['product_id'], '#' => 'reviews')); } } Somehow this horrible code works.. in part. Review saves, but I don't get validation errors, and I can't add 'if ($this->Review->save($this->request->data);) { //... } because it will break this action (missed view error). My question is how to properly deal with this situation to achieve functionality that I need? Should I use elements with request action or I should move adding reviews to the ProductsController?

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  • Rails: Added new Action in Controller, but there is no path?

    - by Newbie
    Hello! I try to do following: A user is on his profile page. Now he edits his profile. He klicks on update and the data is saved. Now I want to redirect the user to another kind of profile-edit-page. I did the following in my users_controller.rb: def update @user = User.find(params[:id]) respond_to do |format| if @user.update_attributes(params[:user]) flash[:notice] = 'User was successfully updated.' if(@user.team_id != nil) format.html { redirect_to(@user) } else format.html { redirect_to choose_team_path } end format.xml { head :ok } else format.html { render :action => "edit" } format.xml { render :xml => @user.errors, :status => :unprocessable_entity } end end end def choose_team @user = User.find(params[:id]) end I created a view: /users/choose_team.html.erb Now I get the following error: undefined local variable or method `choose_team_path' for #<UsersController:0x1f56650> So I added choose_team to my routes.rb: map.choose_team 'choose-team', :controller => 'users', :action => 'choose_team' Now, after submitting my first edit form, it redirects me to http://localhost:3000/choose-team and I get following error: Couldn't find User without an ID What I want: If a user has no team_id, he should be redirected to my choose_team.html.erb for choosing a team, else he should be redirected to his profile/show. How to do this?

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  • Saving form values to database after a user logs in

    - by redfalcon
    Hi. We have a form with ratings to submit for a certain restaurant. After the user has entered some values and wants to submit them, we check whether the user is logged in or not. If not, we display a login form and let the user put in his account data and redirect him to the restaurant he wanted to submit a rating for. The problem is, that after he successfully logged in himself, the submitted values are not saved to the database (which works fine if the user is already logged in). So I wondered if it is possible, to somehow save the data although the user is not logged in. I thought of maybe saving the filled values in a variable and have then automatically re-entered after we redirected the user. But I guess this wont work because we use before_filter :login_required, :only => [ :create ] So we couldnt even access the filled in values, since we display the login-form before the method has processed the values in the form, right? Any idea how we can make rails to save the values or at least have them automatically re-entered to the form? Thanks!

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  • How to call a method after asynchronous task is complete

    - by doctordoder
    I have a class called WikiWebView which is a subclass of UIWebView which loads Wikipedia subjects and is designed to fetch all the links of the webpage, in order to create a sort of site map for the subject. My problem is that I can only create the links once the web page has loaded, but the loading isn't done right after [self loadRequest:requestObj] is called. - (void)loadSubject:(NSString *)subject { // load the actual webpage NSString *wiki = @"http://www.wikipedia.org/wiki/"; NSString *fullURL = [wiki stringByAppendingString:subject]; NSURL *url = [NSURL URLWithString:fullURL]; NSURLRequest *requestObj = [NSURLRequest requestWithURL:url]; [self loadRequest:requestObj]; // [self createLinks]; // need this to be called after the view has loaded } - (void)createLinks { NSString *javascript = @"var string = \"\";" "var arr = document.getElementsByClassName(\"mw-redirect\");" "for (var i = 0; i < arr.length; ++i)" "{" "var redirectLink = arr[i].href;" "string = string + redirectLink + \" \";" "}" "string;"; NSString *links = [self stringByEvaluatingJavaScriptFromString:javascript]; self.links = [links componentsSeparatedByString:@" "]; } I tried the normal delegation technique, which lead to this code being added: - (id)init { if (self = [super init]) { self.delegate = self; // weird } return self; } #pragma mark - UIWebViewDelegate - (void)webViewDidStartLoad:(UIWebView *)webView { ++_numProcesses; } - (void)webView:(UIWebView *)webView didFailLoadWithError:(NSError *)error { --_numProcesses; } - (void)webViewDidFinishLoad:(UIWebView *)webView { --_numProcesses; if (_numProcesses == 0) { [self createLinks]; } } However, the delegate methods are never called.. I've seen similar questions where the answers are to use blocks, but how would I do that in this case?

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  • Multiple File upload doesnot work in CI

    - by sabuj
    Hi I have used Jquery Plugin to upload multiple file with CI. It works fine for one file but if i try to upload more than one file it doesnot work it gives the result like this"menu_back9.pngmenu_back9.png.jpg". function do_upload() { $config['upload_path'] = './uploads/'; // server directory $config['allowed_types'] = 'gif|jpg|png'; // by extension, will check for whether it is an image $config['max_size'] = '1000'; // in kb $config['max_width'] = '1024'; $config['max_height'] = '768'; $this-load-library('upload', $config); $this-load-library('Multi_upload'); $files = $this-multi_upload-go_upload(); if ( ! $files ) { $error = array('error' => $this->upload->display_errors()); $this->load->view('admin/add_digital_product', $error); } else { foreach($files as $file) { $pic_name = $file['name']; echo $pic_name; } exit; $data = array( 'dg_image_1'=$picture, 'dgproduct_name'=$this-input-post('dgproduct_name',TRUE), 'dgproduct_description'=$this-input-post('dgproduct_description',TRUE), 'url_additional'=$this-input-post('url_additional',TRUE), 'url_stored'=$this-input-post('url_stored',TRUE), 'delivery_format'=$this-input-post('delivery_format',TRUE), 'item_size'=$this-input-post('item_size',TRUE), 'price'=$this-input-post('price',TRUE), 'item_code'=$this-input-post('item_code',TRUE), 'payment_pro_code'=$this-input-post('payment_pro_code',TRUE), 'delivery_time'=$this-input-post('delivery_time',TRUE), 'thankyou_message'=$this-input-post('thankyou_message',TRUE), ); $this-db-insert('sm_digital_product',$data); redirect(site_url().'admin/admins'); } } I used avobe code If any body know please tell me. I am stack there.

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  • Make datalist into 3 x 3

    - by unknown
    This is my code behind for products page. The prodblem is that my datalist will fill in new items whenever I add a new object in the website. So may I know how to add the codes in so that I can make the datalist into 3x3. Thanks. Code behind Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Dim Product As New Product Dim DataSet As New DataSet Dim pds As New PagedDataSource DataSet = Product.GetProduct Session("Dataset") = DataSet pds.PageSize = 4 pds.AllowPaging = True pds.CurrentPageIndex = 1 Session("Page") = pds If Not Page.IsPostBack Then UpdateDatabind() End If End Sub Sub UpdateDatabind() Dim DataSet As DataSet = Session("DataSet") If DataSet.Tables(0).Rows.Count > 0 Then pds.DataSource = DataSet.Tables(0).DefaultView Session("Page") = pds dlProducts.DataSource = DataSet.Tables(0).DefaultView dlProducts.DataBind() lblCount.Text = DataSet.Tables(0).Rows.Count End If End Sub Private Sub dlProducts_UpdateCommand(source As Object, e As System.Web.UI.WebControls.DataListCommandEventArgs) Handles dlProducts.UpdateCommand dlProducts.DataBind() End Sub Public Sub PrevNext_Command(source As Object, e As CommandEventArgs) Dim pds As PagedDataSource = Session("Page") Dim CurrentPage = pds.CurrentPageIndex If e.CommandName = "Previous" Then If CurrentPage < 1 Or CurrentPage = pds.IsFirstPage Then CurrentPage = 1 Else CurrentPage -= 1 End If UpdateDatabind() ElseIf e.CommandName = "Next" Then If CurrentPage > pds.PageCount Or CurrentPage = pds.IsLastPage Then CurrentPage = CurrentPage Else CurrentPage += 1 End If UpdateDatabind() End If Response.Redirect("Products.aspx?PageIndex=" & CurrentPage) End Sub this is my code for product.vb Public Function GetProduct() As DataSet Dim strConn As String strConn = ConfigurationManager.ConnectionStrings("HomeFurnitureConnectionString").ToString Dim conn As New SqlConnection(strConn) Dim strSql As String 'strSql = "SELECT * FROM Product p INNER JOIN ProductDetail pd ON p.ProdID = pd.ProdID " & _ ' "WHERE pd.PdColor = (SELECT min(PdColor) FROM ProductDetail as pd1 WHERE pd1.ProdID = p.ProdID)" Dim cmd As New SqlCommand(strSql, conn) Dim ds As New DataSet Dim da As New SqlDataAdapter(cmd) conn.Open() da.Fill(ds) conn.Close() Return ds End Function

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  • Is there a better way to keep track of session variable creation/access throughout different pages?

    - by Brandon
    Here's what I am working on. At my website I have multiple processes with each one containing multiple steps. Now in one of the processes, there is an error checking routine executed before proceeding to the next step of that process. A session var is set indicating the error status and it will either redirect back to the referrer or display the next page's contents. Now this kind of functionality, I believe, is common throughout web development. The issue that is occurring is that session vars are left around and are not being cleaned up properly. At times this introduces undesired behavior. My website is growing and I find that I am requiring more and more session vars to keep track of different system and error states. So I was thinking about creating a kind of "session variable keeper" to keep track of session var usage. The idea is fairly simple. It will have the notion of a context (e.g. registration process) and allow access to a predefined set of session vars within that context. In addition, the var and context will be paired with an action to proceed to some form of event handling. So if you haven't noticed I'm new to web development. Any thoughts or comments on the idea that I am proposing would be greatly appreciated. The back-end is written in PHP/MySQL.

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  • Switch front-end's of a website after X amount of hits

    - by Derek Adair
    Sorry about the title - not sure what to call this one. A client of mine would like to redirect users to different front-ends of his eCommerce site based on a hit-counter (possibly a timer?). important: -The content is moderately different in the two sites, enough to consider them two different websites. Knowing this client he will likely add more drastic content changes and other front-ends. So for this question consider the content to be -This site has a rather large back-end. With affiliate networking, multiple payment gateways, order-tracking, and several other features in the works. It is essential that these two front-ends have identical back-end functionality I know that if it was just a simple CSS swap this would be as simple as an if statement that ran off some kind of counter stored in a DB... but the different HTML markup is throwing me for a loop. Q: How can I serve two different front-ends (HTML/CSS) based on a hit counter? Also, I don't have any clue what to tag this one as...

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  • How can i get my delete messages function just appear for the user's own messages left on their friends page?

    - by Hannah_B
    I had been working on this trying the delete message button to work on my own profile page of my site. When I delete a message left by a friend it not only deletes it from the screen but deletes it from the database. The messages in the database have 4 fields: message_id, from, to and message. Here is my profile view that shows how Im deleting messages from my friends: if(!empty($messages)){ foreach($messages as $message): $delete = $message['message_id']; //var_dump($message); ?> <li><?=$message['from']?> says...: "<?=$message['message']?>"(<?=anchor("home/deleteMsg/$delete", 'delete')?>)</li> //this is where the delete button appears beside messages left <?php endforeach?> <?php }else{ ?> <?php echo 'No messages left yet !!!'; }?> Here is my controller showing the deleteMsg function called: function deleteMsg($messageid) { $this->messages->deleteMsg($messageid); redirect('home'); } Here is the messages model showing the deleteMsg model itself: function deleteMsg($message_id) { $this->db->where(array('message_id' => $message_id)); $this->db->delete('messages'); } Here is my friendprofile view where I want to implement the delete message command just so the button appears for messages Ive left and I can delete them. The delete button will not appear beside other friends comments on this page: <li><?=$message['from']?> says...: "<?=$message['message']?>"</li> Now I've tried creating a new delete Message function to no success so far, am I better off doing this than calling the same function? As this didnt work either.

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  • cakephp - form for belongsTo Model

    - by user1511579
    I createt the following model to link 2 relational tables: class Ficha extends AppModel { //public $useTable = 'ficha_seg'; var $primaryKey = 'id_ficha'; var $name = 'Ficha'; var $belongsTo = array( 'Perigo' => array( 'className' => 'Perigo', 'foreignKey' => false, 'conditions' => 'Perigo.id_fichas = Ficha.id_ficha' ) ); } Now, i have a form that requires data from the class Ficha, and then is redirected to another ctp page where i will input the data for the table "Perigos". However, since i'm still a newbie in cakephp i'm having difficult building that second form to insert the data on the table "Perigos". Here goes the code i built at the moment related to the second form: FichasController.php (the method where is it supposed to save the data on the table "Perigos": public function preencher_ficha(){ if ($this->request->is('ficha')) { $this->Ficha->create(); if ($this->Ficha->Perigo->save($this->request->data)) { $last_id=$this->Ficha->getLastInsertID(); $this->Session->setFlash('Your post has been updated '.$last_id.'.'); //$this->redirect(array('action' => 'preencher_ficha')); } else { $this->Session->setFlash('Unable to qualquer coisa your post.'); } } } The preencher_ficha.ctp file with the form: echo $this->Form->create('Ficha->Perigo', array('action' => 'index')); echo $this->Form->input('class_subst', array('label' => 'Classificação:')); echo $this->Form->input('simbolos_perigo', array('label' => 'Símbolos:')); echo $this->Form->input('frases_r', array('label' => 'Frases:')); echo $this->Form->end('Finalizar Ficha'); Here i guess the create part is wrong, but i think i have errors too in the controller part.

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  • Is it theoretically possible to emulate a human brain on a computer?

    - by JoelK
    Our brain consists of billions of neurons which basically work with all the incoming data from our senses, handle our consciousness, emotions and creativity as well as our hormone system, etc. So I'm completely new to this topic but doesn't each neuron have a fixed function? E.g.: If a signal of strength x enters, if the last signal was x ms ago, redirect it. From what I've learned in biology about our nerves system which includes our brain because both consist of simple neurons, it seems to me as our brain is one big, complicated computer. Maybe so complicated that things such as intelligence and cognition become possible? As the most complicated things about a neuron pretty much are the chemical aspects on generating an electric singal, keeping itself alive, and eventually segmenting itself, it should be pretty easy emulating some on a computer, or? You won't have to worry about keeping your virtual neuron alive, or? If you can emulate a single neuron on a computer, which shouldn't be too hard, could you theoretically emulate more than 1000 billions of them, recreating intelligence, cognition and maybe even creativity? In my question I'm leaving out the following aspects: Speed of our current (super) computers Actually writing a program for emulating neurons I don't know much about this topic, please tell me if I got anything wrong :) (My secret goal: Make a copy of my brain and store it on some 10 million TB HDD and make someone start it up in the future)

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