Search Results

Search found 51843 results on 2074 pages for 'gdata java client'.

Page 1068/2074 | < Previous Page | 1064 1065 1066 1067 1068 1069 1070 1071 1072 1073 1074 1075  | Next Page >

  • Google App Engine + AWS S3 file protection!

    - by grep
    Hi all, I have an application running on GAE/J that streams video from AWS S3. I need a solution for protecting the video from being stolen and I found that pre-signed URLs might be it (??). How can I create pre-signed URLs from GAE/J or there's a better solution to secure the videos? thanks

    Read the article

  • removing comma from string array

    - by sarah
    Hi, I want to execute a query like select ID from "xyz_DB"."test" where user in ('a','b') so the corresponding code is like String s="("; for(String user:selUsers){ s+= " ' " + user + " ', "; } s+=")"; Select ID from test where userId in s; The following code is forming the value of s as ('a','b',) i want to remove the comma after the end of array how to do this ?

    Read the article

  • question about quicksort 3 way partition

    - by davit-datuashvili
    i want implement quicksort 3 way partition here is code public class quick3{ public static void quicksort3(int a[],int l,int r){ int k; int v=a[r]; if (r<=l) return; int i=l; int j=r; int p=l-1; int q=r; for (;;) { while (a[++i]<v); while (v<a[--j]) if (j==i) break; if (i>=j) break; swap( a,i, j); if (a[i]==v){ p++; swap(a,p,i);} if (v==a[j]){ q--; swap( a,q,j); } } swap(a,i,r); j=i-1; i=i+1; for (k=1;k<=p;k++,j--) swap(a,k,j); for (k=r-1;k>=q;k--,i++) swap(a,k,i); quicksort3(a,l,j); quicksort3(a,i,r); } public static void main(String[]args){ int a[]=new int[]{4,6,5,9,7,8,3}; quicksort3(a,0,a.length-1); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } } public static void swap(int a[],int i,int j){ int t=a[i]; a[i]=a[j]; a[j]=t; } } after change result is 4 8 7 6 3 5 9 any suggestion?please help

    Read the article

  • Which way of declaring a variable is fastest?

    - by ADB
    For a variable used in a function that is called very often and for implementation in J2ME on a blackberry (if that changed something, can you explain)? class X { int i; public void someFunc(int j) { i = 0; while( i < j ){ [...] i++; } } } or class X { static int i; public void someFunc(int j) { i = 0; while( i < j ){ [...] i++; } } } or class X { public void someFunc(int j) { int i = 0; while( i < j ){ [...] i++; } } } I know there is a difference how a static versus non-static class variable is accessed, but I don't know it would affect the speed. I also remember reading somewhere that in-function variables may be accessed faster, but I don't know why and where I read that. Background on the question: some painting function in games are called excessively often and even small difference in access time can affect the overall performance when a variable is used in a largish loop.

    Read the article

  • How to calculate the y-pixels of someones weight on a graph? (math+programming question)

    - by RexOnRoids
    I'm not that smart like some of you geniuses. I need some help from a math whiz. My app draws a graph of the users weight over time. I need a surefire way to always get the right pixel position to draw the weight point at for a given weight. For example, say I want to plot the weight 80.0(kg) on the graph when the range of weights is 80.0 to 40.0kg. I want to be able to plug in the weight (given I know the highest and lowest weights in the range also) and get the pixel result 400(y) (for the top of the graph). The graph is 300 pixels high (starts at 100 and ends at 400). The highest weight 80kg would be plot at 400 while the lowest weight 40kg would be plot at 100. And the intermediate weights should be plotted appropriately. I tried this but it does not work: -(float)weightToPixel:(float)theWeight { float graphMaxY = 400; //The TOP of the graph float graphMinY = 100; //The BOTTOM of the graph float yOffset = 100; //Graph itself is offset 100 pixels in the Y direction float coordDiff = graphMaxY-graphMinY; //The size in pixels of the graph float weightDiff = self.highestWeight-self.lowestWeight; //The weight gap float pixelIncrement = coordDiff/weightDiff; float weightY = (theWeight*pixelIncrement)-(coordDiff-yOffset); //The return value return weightYpixel; }

    Read the article

  • out-of-the-box way to get an idmap from hibernate for a given entity?

    - by Geert-Jan
    Over and over again I notive myself getting a list from hibernate, and the first thing next is put it in an idmap like: List<House> entities = s.createCriteria(House.class).list(); Map<String,House> entitymap = new HashMap<String,House>(); for(TA_entity e:entities){ entitymap.put(e.getId(), e); } Is there a way to get this directly out of hibenerate? afterall Hibernate is familiar with the id.

    Read the article

  • Junit | How to test parameters in a method

    - by MMRUser
    How do I test parameters inside a method itself. For example class TestClass { public void paraMethod(String para1, String para2) { String testPara1 = para1; String testPara2 = para2; } } class TestingClass { @Test public void testParaMethod () throws Exception { String myPara1 = "MyPara1"; String myPara2 = "MyPara2"; new TestClass().paraMethod(myPara1, myPara2); } } Ok, so is it possible to test if the testPara1 and testPara2 are properly set to the values that I have passed? Thanks.

    Read the article

  • String.valueOf(int value) gives error [closed]

    - by Davidrd91
    I am trying to convert an int into a String so that I can put the String values into an SQLite Cursor. I've tried multiple syntax and methods but none seem to work for me. The Error occurs in MangaItemDB() while trying to convert any Int types aswell as the boolean. I've looked through several articles like this one but none works for me. Here's my code: public class MangaItem { private int _id; private String mangaName; private String mangaLink; private static String mangaAlpha; private static int mangaCount; private static int alphaCount; private boolean mangaComplete = false; public MangaItem MangaItemDB(int id, String mangaName, String mangaLink, String mangaAlpha, String mangaCount, String alphaCount, String mangaComplete) { MangaItem MangaItemDB = new MangaItem(); MangaItemDB._id = id; MangaItemDB.mangaName = mangaName; MangaItemDB.mangaLink = mangaLink; MangaItemDB.mangaAlpha = mangaAlpha; MangaItemDB.mangaCount = String.valueOf(int mangaCount); MangaItemDB.alphaCount = Integer.toString(getAlphaCount()); MangaItemDB.mangaComplete = String.valueOf(getMangaComplete()); return MangaItemDB; } public void incrementMangaCount() { mangaCount++; } public int getMangaCount() { return mangaCount; } public void incrementAlphaCount() { alphaCount++; } public int getAlphaCount() { return alphaCount; } public boolean setMangaComplete(boolean mangaComplete) { return true; } public boolean getMangaComplete() { return mangaComplete; } /** * @return the mangaName */ public String getMangaName() { return mangaName; } /** * @param mangaName the mangaName to set */ public void setMangaName(String mangaName) { this.mangaName = mangaName; } /** * @return the mangaLink */ public String getMangaLink() { return mangaLink; } /** * @param mangaLink the mangaLink to set */ public void setMangaLink(String mangaLink) { this.mangaLink = mangaLink; } /** * @return the mangaAlpha */ public String getMangaAlpha() { return mangaAlpha; } /** * @param mangaAlpha the mangaAlpha to set */ public void setMangaAlpha(String mangaAlpha) { this.mangaAlpha = mangaAlpha; } /** * @return the _id */ public int get_id() { return _id; } /** * @param _id the _id to set */ public void set_id(int _id) { this._id = _id; } } The lines : MangaItemDB.mangaCount = String.valueOf(mangaCount); MangaItemDB.alphaCount = Integer.toString(getAlphaCount()); MangaItemDB.mangaComplete = String.valueOf(getMangaComplete()); all give "Type mismatch: cannot convert from String to Int"

    Read the article

  • How to find selected node in Tree?

    - by badgirl
    Hello. I have dynamic tree (moreover nodes can have children). Every node has some action. When I right click on some node, it offers me some actions. One action, for example createChildNode creates child node, which in turn creates MyObject2. MyObject2 must be created with assistance of MyOject1, which was created in parent node(that one where I right click for actions ). How to get that object from selected node? That objects in nodes are putted to lookups.singleton(MyObjectX)

    Read the article

  • Group Objects by Common Key

    - by Marshmellow1328
    I have a list of Customers. Each customer has an address and some customers may actually have the same address. My ultimate goal is to group customers based on their address. I figure I could either put the customers in some sort of list-based structure and sort on the addresses, or I could drop the objects into some sort of map that allows multiple values per key. I will now make a pretty picture: List: A1 - C1, A1 - C2, A2 - C3, A3 - C4, A3 - C5 Map: A1 A2 A3 C1 C3 C4 C2 C5 Which option (or any others) do you see as the best solution? Are there any existing classes that will make development easier?

    Read the article

  • Maven: Re-use a POM file in every project.

    - by Zombies
    My goal is pretty simple actually but since there are multiple (and seemingly complex ways to do this) I wonder what I need to do... So I have certain runtime libraries (ADF libraries in particular) that are needed to be added to every project. This parent pom file will just have JAR dependencies in it. How can I use this pom file from a child pom file?

    Read the article

  • Sort a list with element still in first position

    - by Mercer
    I have a String list: List<String> listString = new ArrayList<String>(); listString.add("faq"); listString.add("general"); listString.add("contact"); I do some processing on the list and I want to sort this list but I want "general" still to be in first position. Thx ;)

    Read the article

  • How to get the next element of a SortedSet?

    - by Pentium10
    I have a SortedSet holding my ordered data. I use the .first() method to return the first record, and pass it to another window. When the other window finishes I get an event called, and I want to pass the next from the SortedSet to the window, so how to move to the next element? launchWindow(this.set.first()); Then I have this: onActivityResult(...) { if (this.set.hasNext()) launchWindow(this.set.next());//hasNext/next doesn't exists in the current context for SortedSet } What options I have?

    Read the article

  • One log4j.xml - many scripts

    - by psed
    One of my utility jar files is used by different nix scripts, located in different categories. Problem: unable to initialize log4j framework (unable to find log4j.xml). Solution, that allows to configure logger correctly while launching jar classes by different scripts - usage of env vars and force configuring using DOMConfigurtor.configure(pathToConfXml) method. is it possible to avoid path hardcoding and configure logger inside of a script? Appreciate all your help. Thanks.

    Read the article

  • Need help to solve sharedPreference probem

    - by HFherasen
    I am working on this app where I have one EditText field where you can write somthing and then it get saved and added to a list(TextView). I save the content of the EditText in this way : saved += "*" + editTextFelt.getText().toString() + ". \n"; saved is a String. Everything works fine, I can even reload the app and it's still displayed in the TextView, but if i try to write somthing and save it everything that was there, now dissapear. anyone know why ? It's kind of confusing, and I have to get it to work! Thank's!! CODE: init Mehtod() sp = getSharedPreferences(fileName, 0); betaView = (TextView)findViewById(R.id.betaTextView); Ive got a button to send the text, and this is like: p ublic void onClick(View v) { switch(v.getId()){ case R.id.btnSend: saved += "*" + editTextFelt.getText().toString() + ". \n"; SharedPreferences.Editor editor = sp.edit(); editor.putString("SAVED", saved); editor.commit(); betaView.setText(sp.getString("SAVED", "Empty"));

    Read the article

  • Magic squares, recursive

    - by user310827
    Hi, my problem is, I'm trying to permute all posibilities for a 3x3 square and check if the combination is magic. I've added a tweak with (n%3==0) if statement that if the sum of numbers in row differs from 15 it breaks the creation of other two lines... but it doesn't work. Any suggestions? I call the function with Permute(1). public static class Global { //int[] j = new int[6]; public static int[] a= {0,0,0,0,0,0,0,0,0}; public static int[] b= {0,0,0,0,0,0,0,0,0}; public static int count = 0; } public static void Permute(int n) { int tmp=n-1; for (int i=0;i<9;i++){ if (Global.b[i]==0 ) { Global.b[i]=1; Global.a[n-1]=i+1; if ((n % 3) == 0) { if (Global.a[0+tmp]+Global.a[1+tmp]+Global.a[2+tmp] == 15) { if (n<9) { Permute(n+1); } else { isMagic(Global.a); } } else break; } else { Permute(n+1); } Global.b[i]=0; } } }

    Read the article

  • How do I make dynamic windows in Swing?

    - by Roman
    I have a general question. I would like to have a window containing some buttons, radio buttons, text fields and so on. So, user can do something (write text, select options and press buttons). As the result of the user activity window should change it structure/appearance some element should disappear and some appear. How do I program such "updates"? Should I close an old window and open a new one or I can modify content of window without closing it?

    Read the article

  • A typical lifecycle of a Hibernate object in a web app - ?

    - by EugeneP
    Describe please a typical lifecycle of a Hibernate object (that maps to a db table) in a web app. Suppose, you create a new instance of an object and persist in the db. But during the app lifetime you'll be working on a detached object and finally you need to update it in the database, for example on exit. How does it look like with hibernate and spring? p.s. Can transactions and sessions live between servlet transitions? So that we opened 1 session and use it in all servlets without a need to reopen it?

    Read the article

< Previous Page | 1064 1065 1066 1067 1068 1069 1070 1071 1072 1073 1074 1075  | Next Page >