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  • Regular Expression: back references

    - by sixtyfootersdude
    sed 's/^\(\h*\)\(.*\)$/\1<!-- \2 -->/' web.xml I think that this should take this xml: <a> <d> bla </d> </a> And turn it into: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> --> But what is doing is this: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> -->

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  • How to Redirect Subdomains to Other Domain

    - by Codex73
    What I'm trying to accomplish with htaccess mod-rewrite: Redirect all sub-domains to new domain name w rewrite rule. e.g. test1.olddomain.com === test1.newdomain.com test2.olddomain.com === test2.newdomain.com test3.olddomain.com === test3.newdomain.com This is what I have so far which of course is wrong: Options +FollowSymLinks RewriteEngine on RewriteCond %{HTTP_HOST} ^olddomain\.com$ [NC] RewriteRule ^(.*)$ http://www.newdomain.com/$1 [R=301,L] RewriteCond %{HTTP_HOST} ^www\.olddomain\.com$ [NC] RewriteRule ^(.*) http://www.newdomain.com/$1 [R=301,L] RewriteRule [a-zA-Z]+\.olddomain.com$ http://$1.newdomain.com/ [R=301,L] Since I'm not a Regular Expression junkie just yet, I need your help... Thanks for any help you can give here. I know also we can compile these first two conditions into one. Note: The reason I don't redirect all domain using DNS is that a lot of directories need special rewrite rules in order to maintain positions on SEO.

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  • Search for a String and replace it with a variable

    - by chrissygormley
    Hello, I am trying to use regular expression to search a document fo a UUID number and replace the end of it with a new number. The code I have so far is: read_file = open('test.txt', 'r+') write_file = open('test.txt', 'w') r = re.compile(r'(self.uid\s*=\s*5EFF837F-EFC2-4c32-A3D4\s*)(\S+)') for l in read_file: m1 = r.match(l) if m1: new=(str,m1.group(2)) new?????? This where I get stuck. The file test.txt has the below UUID stored in it: self.uid = '5EFF837F-EFC2-4c32-A3D4-D15C7F9E1F22' I want to replace the part D15C7F9E1F22. I have also tried this: r = re.compile(r'(self.uid\s*=\s*)(\S+)') for l in fp: m1 = r.match(l) new=map(int,m1.group(2).split("-") new[4]='RHUI5345JO' But I cannot seem to match the string. Thanks in advance for any help.

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  • What is the MM/DD/YYYY regular expression and how do I use it in php?

    - by zeckdude
    I found the regular expression for MM/DD/YYYY at http://www.regular-expressions.info/regexbuddy/datemmddyyyy.html but I don't think I am using it correctly. Here's my code: $date_regex = '(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d'; $test_date = '03/22/2010'; if(preg_match($date_regex, $test_date)) { echo 'this date is formatted correctly'; } else { echo 'this date is not formatted correctly'; } When I run this, it still echoes 'this date is not formatted correctly', when it should be saying the opposite. How do I set this regular expression up in php?

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  • Filter string in C

    - by Paul Tarjan
    How can I filter a string in c? I want to remove anything that isn't [a-z0-9_]. int main(int argc, char ** argv) { char* name = argv[1]; // remove anything that isn't [a-z0-9_] printf("%s", name); }

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  • replacing text within quotes until next quote

    - by Jordan Trainor
    String input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; This is my current code that works but iv added some code that has to run before this which makes some '"' split onto another line thus making the code below obsolute unless under certain cirumstances the '"' is not put onto the next line. firstQuote = input.IndexOf("\""); lastQuote = input.LastIndexOf("\""); input = input.Substring(0, firstQuote) + "<span>quote" + input.Substring(firstQuote + 1, lastQuote - (firstQuote + 1) + "quote</span>" + input.Substring(lastQuote + 1, lines.Length - (lastQuote + 1); How could I change the input string from input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; to input = "helloj(<span>quoteiojgeio\r\ngsk\\"jopriquote</span>gj\r\negjoijisgoe<span>quotejoijsofeijquote</span>quote<span>quote</span>ojgsoij<span>quote</span>";

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  • Simplest way to convert all html links in a string using PHP

    - by Gaz
    I am trying to convert a block of text that contains html text - i'd like to find all http links and convert them for link tracking purposes. So eg anything like this in a string would be converted to the latter <a href="http://www.google.com">Some Link</a> <a href="http://www.mysite.com/tracking.php?url=www.google.com">Some Link</a> Can anyone how to do this taking into account the original string will consists of all sorts of html, images etc..

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  • How do I best do balanced quoting with Perl's Regexp::Grammars?

    - by Evan Carroll
    Using Damian Conway's Regexp::Grammars, I'm trying to match different balanced quoting ('foo', "foo", but not 'foo") mechanisms -- such as parens, quotes, double quotes, and double dollars. This is the code I'm currently using. <token: pair> \'<literal>\'|\"<literal>\"|\$\$<literal>\$\$ <token: literal> [\S]+ This generally works fine and allows me to say something like: <rule: quote> QUOTE <.as>? <pair> My question is how do I reform the output, to exclude the needles notation for the pair token? { '' => 'QUOTE AS \',\'', 'quote' => { '' => 'QUOTE AS \',\'', 'pair' => { 'literal' => ',', '' => '\',\'' } } }, Here, there is obviously no desire to have pair in between, quote, and the literal value of it. Is there a better way to match 'foo', "foo", and $$foo$$, and maybe sometimes ( foo ) without each time creating a needless pair token? Can I preprocess-out that token or fold it into the above? Or, write a better construct entirely that eliminates the need for it?

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  • Removing text within parentheses (parentheses within parentheses prob)

    - by TenJack
    Hi, I am trying to remove text that is within parentheses (along with the parentheses themselves) but am having trouble with the scenario where there are parentheses within parentheses. This is the method I am using (in Ruby): sentence.gsub(/\(.*?\)/, "") and that works fine until I have a sentence such as: "This is (a test (string))" Then the above chokes. Anyone have any idea how to do this? I am completely stumped.

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  • Is it possible to use re2 from Python?

    - by flow
    i just discovered http://code.google.com/p/re2, a promising library that uses a long-neglected way (Thompson NFA) to implement a regular expression engine that can be orders of magnitudes faster than the available engines of awk, Perl, or Python. so i downloaded the code and did the usual sudo make install thing. however, that action had seemingly done little more than adding /usr/local/include/re2/re2.h to my system. there seemed to be some `*.a file in addition, but then what is it with this *.a extension? i would like to use re2 from Python (preferrably Python 3.1) and was excited to see files like make_unicode_groups.py in the distro (maybe just used during the build process?). those however were not deployed on my machine. how can i use re2 from Python?

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  • Limiting input to specified regexp with uppercase chars in IE

    - by pixelboy
    I'm trying to limit what our users will be able to type in inputs, using javascript/jquery. Problem is, I have to limit this to Uppercase chars only, and numbers. Here's what I coded previously : $(input).keydown(function(e){ if ($(input).attr("class")=="populationReference"){ var ValidPattern = /^[A-Z_0-9]*$/; var char = String.fromCharCode(e.charCode); if (!ValidPattern.test(char) && e.charCode!=0){ return false; e.preventDefault(); } } }); If Firefox supports charCode, IE doesn't. How then, could I test if the user is typing uppercase or lowercase characters ? Thanks for any help !

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  • get city, state or zip from a string in python

    - by Joe
    I'd like to be able to parse out the city, state or zip from a string in python. So, if I entered Boulder, Co 80303 Boulder, Colorado Boulder, Co 80303 ... any variation of these it would return the city, state or zip. This is all going to be user inputted data and inputted in one text field.

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  • questions on nfa and dfa..

    - by Loop
    Hi Guys... Hope you help me with this one.... I have a main question which is ''how to judge whether a regular expression will be accepted by NFA and/or DFA? For eg. My question says that which of the regular expressions are equivalent? explain... 1.(a+b)*b(a+b)*b(a+b)* 2.a*ba*ba* 3.a*ba*b(a+b)* do we have to draw the NFA and DFA and then find through minimisation algorithm? if we do then how do we come to know that which regular expression is accepted by NFA/DFA so that we can begin with the answer? its so confusing.... Second is a very similar one, the question asks me to show that the language (a^nb^n|n1} is not accepted by DFA...grrrrr...how do i know this? (BTW this is a set of all strings of where a number of a's is followed by the same number of b's).... I hope I explained clearly well....

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  • Ruby: backslash all non-alphanumeric characters in a string

    - by HBlend
    I have a script where I need to take a user's password and then run a command line using it. I need to backslash all (could be more then one) non-alphanumeric characters in the password. I have tried several things at this point including the below but getting no where. This has to be easy, just missing it. Tried these and several others: password = password.gsub(/(\W)/, '\\1') password = password.gsub(/(\W)/, '\\\1') password = password.gsub(/(\W)/, '\\\\1')

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  • Issue with my regular expression?

    - by Rubans
    I'm trying to locate the number matches in a relative path for directory up references("..\"). So I have the following pattern : "(..\)" which works as expected for the path "....\a\b" where it will give me 2 successfull groups ("..\") but when I try the path "..\a\b" it will also return 2 when it should be 1. I tried this in a reg ex tool such Expresso and it seems to work as expected in there but not in in .net, any ideas?

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  • Algorithm to match natural text in mail

    - by snøreven
    I need to separate natural, coherent text/sentences in emails from lists, signatures, greetings and so on before further processing. example: Hi tom, last monday we did bla bla, lore Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. list item 2 list item 3 list item 3 Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid x ea commodi consequat. Quis aute iure reprehenderit in voluptate velit regards, K. ---line-of-funny-characters-####### example inc. 33 evil street, london mobile: 00 234534/234345 Ideally the algorithm would match only the bold parts. Is there any recommended approach - or are there even existing algorithms for that problem? Should I try approximate regular expressions or more statistical stuff based on number of punctation marks, length and so on?

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  • Match subpatterns in any order

    - by Yaroslav
    I have long regexp with two complicated subpatters inside. How i can match that subpatterns in any order? Simplified example: /(apple)?\s?(banana)?\s?(orange)?\s?(kiwi)?/ and i want to match both of apple banana orange kiwi apple orange banana kiwi It is very simplified example. In my case banana and orange is long complicated subpatterns and i don't want to do something like /(apple)?\s?((banana)?\s?(orange)?|(orange)?\s?(banana)?)\s?(kiwi)?/ Is it possible to group subpatterns like chars in character class? UPD Real data as requested: 14:24 26,37 Mb 108.53 01:19:02 06.07 24.39 19:39 46:00 my strings much longer, but it is significant part. Here you can see two lines what i need to match. First has two values: length (14 min 24 sec) and size 26.37 Mb. Second one has three values but in different order: size 108.53 Mb, length 01 h 19 m 02 s and date June, 07 Third one has two size and length Fourth has only length There are couple more variations and i need to parse all values. I have a regexp that pretty close except i can't figure out how to match patterns in different order without writing it twice. (?<size>\d{1,3}\[.,]\d{1,2}\s+(?:Mb)?)?\s? (?<length>(?:(?:01:)?\d{1,2}:\d{2}))?\s* (?<date>\d{2}\.\d{2}))? NOTE: that is only part of big regexp that forks fine already.

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  • [PHP] preg_replace: replacing using %

    - by Juan
    Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks Juan

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