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  • (svn+ssh) getting bash to load my PATH over SSH

    - by Eli Bendersky
    This problem comes up with me trying to make svnserve (Subversion server) available on a server through SSH. I compiled SVN and installed it in $HOME/bin. Local access to it (not through SSH) works fine. Connections to svn+ssh fail due to: bash: svnserve: command not found Debugging this, I've found that: ssh user@server "which svnserve" says: which: no svnserve in (/usr/bin:/bin) This is strange, because I've updated the path to $HOME/bin in my .bashrc, and also added it in ~/.ssh/environment. However, it seems like the SSH doesn't read it. Although when I run: ssh user@server "echo $PATH" It does print my updated path! What's going on here? How can I make SSH find my svnserve? Thanks in advance

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  • Improper output in SSH session on OSX using FreeSSHd on Windows with cygwin bash/sh shell

    - by Tyler Clendenin
    I am testing out running an SSH server on a local Windows VM. I have installed FreeSSHd and set the command shell to "c:\cygwin\bin\sh --login -i" (bash as well) with "Use new console engine" unchecked. (When it was enabled no output would show through the ssh connection anyway) The shell seems to work, but when connecting from my OS-X terminal using ssh all of the shell results comes out ill formatted. $ ls -al total 17 drwxr-xr-x+ 1 SYSTEM Administrators 4096 Feb 2 01:00 . drwxrwxrwt+ 1 Administrator Administrators 0 Feb 2 01:01 .. -rw------- 1 SYSTEM Administrators 128 Feb 2 01:30 .bash_history -rwxr-xr-x 1 SYSTEM Administrators 1150 Feb 2 00:55 .bash_profile -rwxr-xr-x 1 SYSTEM Administrators 3754 Feb 2 00:55 .bashrc -rwxr-xr-x 1 SYSTEM Administrators 1461 Feb 2 00:55 .inputrc Any ideas on why this is happening, how I can fix this?

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  • Bash delete file when variable = x

    - by twigg
    I'm creating a bash script which reboots the system at each reboot it adds a new line to a text file, I then read the text file before each reboot. Once the variable holding the number of lines reaches say 10 I want the script to delete the text file (at which point on the next reboot it will see the file isn't there, brake the loop and promote the user to start again). I tried this: exec < text.txt nol=0 while read line do nol=`expr $nol + 1` done reboot_count=10 if ["$nol" == "$reboot_count"]; then rm text.txt fi but this doesn't seem to be working, all help is appreciated :)

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  • How to batch rename files using bash

    - by Alex Popov
    I know there are lots of such questions, but I couldn't find one (or a combination of several), which describes the things I want to do. I think I need to use regular expressions, but I am not very good with that. I use zsh. I have a folder with files, which I want to rename: I want the files challenge1.rb, challenge2.rb, challenge3.rb, etc. to be renamed to c1.rb, c2.rb etc. Similarly task1.rb and similar must be renamed to t1.rb etc. sample_spec_c1.rb, sample_spec_c2.rb etc. must be renamed to c1_spec.rb, c2_spec.rb etc. So I guess I need some combination of regular expressions and iteration, but I don't know how to write the bash script.

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  • How can I do `dir *.mp3` in bash?

    - by Andy
    Hi all, On Windows I used to quickly run a dir *.mp3 to find all files with an mp3 extension in the current directory. Is there a similarly quick way to do it with bash? The ls command seems to have a way to ignore a pattern, but not to show only the pattern. I can do find . -maxdepth 1 -iname '*.mp3' or ls|grep -i '\.mp3$' but neither of these flow out of my fingers in half a second or less;) Any quicker alternatives? TIA Andy

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  • About rw init=/bin/bash

    - by triedtoomuck
    I am a linux newbie so excuse me if I ask silly things. I recently find out that if I edit GRUB before booting and I add rw init=/bin/bash I end up with a root shell. Being in a condition that I want to understand everything I would like to know why this happens. I mean is it a bug? is it a feature? is it there to help admins to fix things as it only works if you have physical access to a computer? Which part are we exploiting? GRUB or the actual kernel? Sorry for asking a lot of things.

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  • How to use HTML markup tags inside Bash script

    - by CONtext
    I have crontab and a simple bash script that sends me emails every often containing PHP, NGINX, MYSQL errors from their log files. This is a simplified example. #/home/user/status.sh [email protected] PHP_ERROR=`tail -5 /var/log/php-fpm/error.log` NGINX_ERROR=`tail -5 /var/log/nginx/error.log` MYSQL_ERROR=`tail /var/log/mysqld.log` DISK_SPACE=`df -h` echo " Today's, server report:: ================================== DISK_SPACE: $DISK_SPACE --------------------------------- MEMORY_USAGE: $MEMORY_USAGE ----------------------------------- NGINX ERROR: $NGINX_ERROR ----------------------------------- PHP ERRORS: $PHP_ERROR ------------------------------------ MYSQL_ERRORS: $MYSQL_ERROR ------------------------------------- " | mail -s "Server reports" $EMAIL I know this is a very basic usage, but as you can see, I am trying to separate the errors, but not of the html tags including \n are working. So, my question is, is it possible to use HTML tags to format the text, if not .. then what are the alternatives.

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  • selective backup script in bash

    - by Sake
    Hi, I've been using this simple command (that's all I can do :) to backup the whole tree from my user data in NAS server for a year. cp -r /STORAGE /BACKUP-STORAGE/YYYY-MM-DD Unfortunately, after a year of service. My user start filling the spaces with lot of photo and cliparts (jpg, gif, bmp) And that start to make my backup process get much slower. The space is also a big issue. Now I no longer have enough space for a week-long daily backup set. I think I want to change from backup everything to backup only non-image data. How can I exclude jpg, gif, and bmp from the backup ? It's quite easy with DOS XCOPY command, but I really have no idea how to do that in bash. Thanks

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  • Mac OS X bash: uninstall all apache and PHP occurences

    - by fireeyedboy
    Hi all, How do I find all installed apache and PHP occurences on a Mac OS X system in bash and uninstall them? My motivation: I've managed to install multiple apache and PHP packages (I believe it's called packages in Unix terms, correct?) at some point, and I'ld like to start out fresh again, without completely re-installing Mac OS X again. Also, I'ld like to install suPHP along with apache this time, and I believe I need to compile apache with some additional stuff for that. But that is a challenge I'll deal with later, and probably ask a question about then. :) Thank you in advance for your info.

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  • Implementing dry-run in bash scripts

    - by Apikot
    How would one implement a dry-run option in a bash script? I can think of either wrapping every single command in an if and echoing out the command instead of running it if the script is running with dry-run. Another way would be to define a function and then passing each command call through that function. Something like: function _run () { if [[ "$DRY_RUN" ]]; then echo $@ else $@ fi } _run mv /tmp/file /tmp/file2 DRY_RUN=true _run mv /tmp/file /tmp/file2 Is this just wrong and there is a much better way of doing it?

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  • Displaying what `history` line is current in bash prompt

    - by warren
    What formatting character needs to be added to a bash prompt to indicate the most recent history item run (or the current command number if 1 could be added to the last history entry)? My prompt string is this: \[\033[33m\][\u@\[\033[1;31m\]\h]\]\033[0m {\W}\n\033[1;34m\]\w\]\033[0m > Gives me the following display: [user@host] {~} ~ > User is in yellow, and the host is in red. The entry in brackets is the current directory, and the entry before the greater-than sign is the full pwd. Can I append to the first line the current command number so I would have something like the following: [user@host] {~} (nnn) ~ > where (nnn) is the current (or just processed) command number, as shown when running history?

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  • How to interpret the bash command "usage" syntax?

    - by raoulsson
    How exactly do you have to interpret the output of a commands "usage" output, in bash for example. For example, on my OS X, cp gives me usage: cp [-R [-H | -L | -P]] [-fi | -n] [-apvX] source_file target_file cp [-R [-H | -L | -P]] [-fi | -n] [-apvX] source_file ... target_directory What does the nested options, like -H within -R, indicate? Does upper and lower case have any meaning? When is an argument optional, required? I need to implement a telnet command line against a program of mine and I would like to get this straight.

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  • execute a command in all subdirectories bash

    - by Luigi R. Viggiano
    I have a directory structure composed by: iTunes/Music/${author}/${album}/${song.mp3} I implemented a script to strip my mp3 bitrate to 128 kbps using lame (which works on a single file at time). My script looks like this 'normalize_mp3.sh': #!/bin/bash SAVEIFS=$IFS IFS=$(echo -en "\n\b") for f in *.mp3 do lame --cbr $f __out.mp3 mv __out.mp3 $f done IFS=$SAVEIFS This works fine, if I go folder by folder and execute this command. But I'd like to have a "global" command, like in 4DOS so I can run: $ cd iTunes/Music $ global normalize_mp3.sh and the global command would traverse all subdirs and execute the normalize_mp3.sh to strip all my mp3 in all subfolders. Anyone knows if there is a unix equivalent to the 4dos global command? I tried to play with find -exec but I just managed to get an headache.

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  • Implementing dry-run in bash scripts

    - by Andrei Serdeliuc
    How would one implement a dry-run option in a bash script? I can think of either wrapping every single command in an if and echoing out the command instead of running it if the script is running with dry-run. Another way would be to define a function and then passing each command call through that function. Something like: function _run () { if [[ "$DRY_RUN" ]]; then echo $@ else $@ fi } `_run mv /tmp/file /tmp/file2` `DRY_RUN=true _run mv /tmp/file /tmp/file2` Is this just wrong and there is a much better way of doing it?

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  • Files listed by bash but unaccessible

    - by Cerin
    What would cause the following behavior on an Ubuntu 12.04 system? I've SSHed into a machine as the "ubuntu" user. Running ls -lah /data/* shows dozens of non-empty files (e.g. file1.txt, file2.txt, etc), all owned by the "ubuntu" user/group, and with full read/write access. If I try to cat /data/file1.txt, bash gives me the error "cat: /data/file1.txt: No such file or directory" In short, ls is listing files, but in every other way, the files essentially don't exist. I can't cat them or read them in any way. Even giving all the files 777 permission doesn't change anything. This is really bizarre. What's going on here?

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  • VIM zsh, bash and colors in command line on Ubuntu

    - by Jacek Wysocki
    I have problem with VIM command line when calling system commands. e.g. !ls, all command output colors aren't parsed by VIM. My system is Ubuntu 12.04 LTS with VIM 7.3.429 from Ubuntu repositories. Is there any workaround for this problem? EDIT: My vimrc file :!echo $TERM in VIM returns : dumb EDIT2: I found a simple workaround but it's not perfect if [ "$VIM" ] && [ "$TERM" = "dumb" ] then # For gvim's monochromatic :shell PS1='\n\u@\h \w\n\$ ' unalias ls unalias grep fi (It's working on bash)

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  • How to avoid tilde ~ in Bash prompt?

    - by Jirka
    Hello! I have set my prompt in bash in a such way that I can use it directly in scp command: My current PS1 string: PS1="\h:\w\n$" And the prompt looks like this: lnx-hladky:/tmp/plugtmp $ What I don't like at all is the fact that $HOME directory is displayed as tilde. Can this be avoided? It's causing problems when switching between different users. Example: lnx-hladky:~/DOC $ Documentation says: \w : the current working directory, with $HOME abbreviated with a tilde \W: the basename of the current working directory, with $HOME abbreviated with a tilde Is there any possibility to avoid $HOME being abbreviated with a tilde? I have found one way around but I feel like it's overcomplicated: PROMPT_COMMAND='echo -ne "\e[4;35m$(date +%T)\e[24m$(whoami)@$(hostname):$(pwd)\e[m\n"' PS1=$ Can anyone propose a better solution? I have a feeling it's not quite OK to run so many commands just to get prompt. (date,whoami,hostname,pwd). Thanks a lot! Jirka

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  • sudo displays typed password in bash script

    - by Andy
    Hullo, I have a bash script that uses sudo a few times. There's a couple of strange points about it though. It asks me for my password a few seconds after I've already entered it for a previous command. The second time I enter my password, it's echoed to the display. Here's the relevant bits of the script. sudo service apache2 stop drush sql-dump --root="$SITE_DIR" --structure-tables-key=svn --ordered-dump | grep -iv 'dump completed on' | sudo tee "$DB_DIR/${SITE_NAME}.sql" > /dev/null sudo svn diff "$DB_DIR" | less sudo svn commit -m "$MESSAGE" "$DB_DIR" sudo service apache2 start The first password is to stop apache, and it works as expected. As mentioned, the sudo tee doesn't 'remember' that I have elevated privileges, asks for the password again, and echoes it to the screen. Given that tee is all about echoing to screen, I've played around a little with simple scripts which have | sudo tee, and they all work as expected. Ideas?! TIA Andy

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  • bash process uses 90% CPU, comes back on computer restart

    - by Sano
    I’ve replaced the old HDD of my late 2008 unibody MacBook (8 GB of RAM, running OS X 10.7.4) with an OCZ Vertex 3 SSD. After doing this, I've installed Lion and restored my data from a Time Machine backup. Everything is fine, except for a process named “bash” that permanently uses about 90 % CPU. If I kill it via Activity Monitor, everything goes back to normal, but unfortunately the process comes back every time I restart the computer. I've tried do zap the PRAM, reinstall 10.7.4 from the combo package, and even simply wait for more than 2 hours, but the problem is still here.

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  • Unexpected behavior in Bash

    - by cYrus
    From man bash: A simple command is a sequence of optional variable assignments followed by blank-separated words and redirections, and terminated by a control operator. The first word specifies the command to be executed, and is passed as argument zero. The remaining words are passed as arguments to the invoked command. So it's perfectly legal to write: foo=bar echo $foo but it doesn't work as I expect (it prints just a newline). It's quite strange to me since: $ foo=bar printenv foo=bar TERM=rxvt-unicode [...] Could someone please explain me where I'm doing wrong?

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  • Mac OS X bash prompt bug?

    - by Memo
    I am trying to set my bash prompt to display the time and current directory in bold: export PS1="\[\e[1m\][\A] \w \$ \[\e[0m\]" This does apparently work, but when I use the command history (ctrl-r), after finding the command I was searching for and pressing enter, this line is not displayed correctly. Here is an example: [21:58] ~/Wyona/svn-repos/zwischengas $ (reverse-i-search)`ta': tail -F logs/log4j-cnode1.log becomes, after pressing enter: [21:58] ~/Wyona/svn-repos/zwischengas $ -F logs/log4j-cnode1.log Of course, this is not "really" a problem, since the command does work correctly, but it is still annoying. Does anybody know why this happens? And, more importantly, how to prevent/fix it? Thanks, Memo

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  • bash and arithmetic comparison: double quotes or not?

    - by Martin
    when comparing two integers in bash, do we have to put double quotes ? In the official document http://tldp.org/LDP/abs/html/comparison-ops.html I can read that double quotes should appear every time... But what is the differences in the following examples: [ "$VAR" -eq "1" ] [ $VAR -eq "1" ] [ "$VAR" -eq 1 ] [ $VAR -eq 1 ] As I am curious, a took a look at Ubuntu init scripts in /etc/init.d and there are many usage of arithmetic comparison in it, at least [ "$VAR" -eq "1" ] and [ $VAR -eq 1 ] are used... but it seems no one really "knows" what is the official way to do it. Thanks !

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  • bash : "set -e" and check if a user exists make script exit

    - by Dahmad Boutfounast
    i am writing a script to install a program with bash, i want to exit on error so i added "set -e" in the beginning of my script. the problem is that i have to check if a user exists inside of my script, to do this i am using "grep "^${USER}:" /etc/passwd", if the user exists, the script runs normally, but if the user doesn't exist, this command exists, and i don't want to exit on this case (i have to create the user and continue my installation). so what's the solution to make my script continue running ?? i tried to redirect the output of "grep" to a variable, but i still have the same problem :( thanks.

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  • Bash - Program is writing directly to terminal

    - by Salis
    Valve's dedicated server for the Source Engine (srcds_run) on Linux writes directly to the terminal, not stdout. I want to run it as an /etc/init.d daemon on Debian 6, and I'd like to redirect/capture the output to a file. How can I do that? And better yet, why would they output directly to the terminal, is there any benefit in doing that? I suppose I could start another bash instance just for srcds_run, but that seems like a dirty solution, and I still don't know how to redirect the output.

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  • How to stop Bash appending history

    - by Craig
    I am having a lot of trouble setting up the terminal history of Bash the way I want. I would like to have no duplicate entries and if I enter a command I want it saved and the duplicates above removed. The problem is the history command shows me it is functioning the way I want however once I log out the duplicates come back again. I believe it is just appending the history to the existing one. I have these lines in my .bashrc file (~/.bashrc) HISTCONTROL=ignoreboth:erasedups shopt -u histappend I have even tried uncommenting shopt but it still appends the history on logout. How can I have the history be exactly how it is before I logout?

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