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  • Is there any real advantage to use zend ce server over just referencing (include) the zend framework library?

    - by Marcos Roriz
    Hi, I'm new to PHP frameworks, and currently I'm trying Zend Framework (ZF). I'm old fashioned when it comes to installing software, I like to install apache/mysql/php all separetely since I find easier and it gives me more control of it. It seems that the "encouraged" way to develop with Zend Framework is using the Zend (CE) Server. I personally don't like this idea of a app install everything else (PHP/Apache and so on). From what I've seen if I include Zend Framework Library in php.ini path I'm ready to go. So is there any real advantage to use the Full Zend (CE) Server??

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  • Zend Optimizer not Functioning Correctly on Plesk 9.3.0 VPS

    - by dallasclark
    I have a new VPS running Plesk 9.3.0 without 'much' modifications to any settings. I've moved a site to this VPS and I'm receiving a page full of random 'gibbrish' characters like: Zend2003120702116268102798xù Ÿ2½}MŒ%ÇqæCwËg¸„ÖXXZ[ÆùÿCK¢FŠäš’(’¢-ÂÒèu¿zš6gºÇÝ=$Ec:-xá=èàƒÃ ôžL/`,¼'û$èdû$ð ›±OYïUUdfde½á›GâcWTfDdF|‘™‘QÕ_nN‡OÝ›Ÿ/ú9¾¢»"…çÎ =B³øo/=÷…?úúW?·/LX5¯ß½ ðtEÍ ãB„ð÷øìÞéåU®•òÊëZÈi^¿lN/NÎNoÞ›/šÅC׸”šÅLËÏåùÉ+Ü á¸a6Ê÷Ž..ϯrç…Õ–)Õþñòüvsz•{å mî!F³ã[çWsÖZ%k'-ÐÝ<¬þZ1B¡¼ "-ÏîH @/Ü´b.Ï›ù"ü tb¼Ò!”]œ¼ïŠ6–Ál \Ü;½hÎOößh®^“4#…s¡CÀ†æôUèP³Ð§3¦¬“; –j‡ìþb¤÷š»¶³Wçç7÷îÜ…w•bÞs«[ÆÎav,@ÿ´ÜéÖåÌfž¯þVÚlö‹½ÎÛØå#Èoòudñ^÷чW+ÕSsÐý¹w˜7Ÿò«{ò…?<Ìo1»èZÄN_ð³»·îqr÷Vs¾"ýµ¾§þˆ¡v Ù.j†Çï®#{îÞüÞú¿ºý²Q0âLõ$rv¥{»[à|sÝwxþðúy¯)þ • 7ÛŽ È^YËZá‘JV<|·g“l2£{µ«Ù›=é§eCÍîõÖ»ÓÖQtL´D?ε܃ÁªÇ3=ﯸ^=þAIÏjöÐÁ0¡ò¥ 2øÙŸÞçÝÊéqÔ€Lï÷*+Jo¬õLͺFøì x¨ÕìÛ'GH“æådD)ÿ:¨5¼q±¦rÖøLf“Ðj îÅõ¬éa÷[!_zöN?þ"™†á©›0Ý{ˆWóª‘ÁH4µx5+Ë^–Ž›·ÉöŠd1¹Õ¬ phpinfo() shows PHP is running on the Zend engine. This server is unmanaged so I cannot ask the hosting provider for assistance. Any help big or small will be appreciated. [root@vps ~]# php -v PHP 5.1.6 (cli) (built: Mar 31 2010 02:39:17) Copyright (c) 1997-2006 The PHP Group Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technologies

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  • Is DB2 Connect neccessary if I'm using Zend Server for i5/OS?

    - by tiraeth
    I have Zend Server for i5/OS and want to connect (in PHP) to local DB2 Instance. Do I need DB2 Connect product to call any program on i5/OS? If I can use ODBC Driver, can somebody - please - give me an url to some place where I can download it (OpenSource?) ? Another question: Is there any PDO_ODBC or ODBC adapter for Zend Framework's Zend_Db?

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  • How to know that a php project is using Zend framework?

    - by Wing C. Chen
    I am writing a piece of small software to go through the folders and files of all the php projects that are passed in and detect if any of them is actually also a Zend project. Is there any particular file that I can immediately read and tell that the current project is a Zend project? or is there any convenient way to tell?

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  • Static content not displayed with Zend FW

    - by shin
    I am trying to display a static content with Zend framework. When I go to http://square.localhost/content/services, I get an error message. Could anyone tell me how to fix this please? Thanks in advance. application.ini .... .... resources.layout.layoutPath = APPLICATION_PATH "/layouts" resources.layout.layout = "master" resources.router.routes.home.route = /home resources.router.routes.home.defaults.module = default resources.router.routes.home.defaults.controller = index resources.router.routes.home.defaults.action = index resources.router.routes.static-content.route = /content/:page resources.router.routes.static-content.defaults.module = default resources.router.routes.static-content.defaults.controller = static-content resources.router.routes.static-content.defaults.action = display application/modules/default/controllers/StaticContentController.php class StaticContentController extends Zend_Controller_Action { public function init() { } // display static views public function displayAction() { $page = $this->getRequest()->getParam('page'); if (file_exists($this->view->getScriptPath(null) . "/" . $this->getRequest()->getControllerName() . "/$page." . $this->viewSuffix)) { $this->render($page); } else { throw new Zend_Controller_Action_Exception('Page not found', 404); } } } application/modules/default/views/scripts/static-content/services.phtml some html ... ... Error message An error occurred Page not found Exception information: Message: Page not found Stack trace: #0 /var/www/square/library/Zend/Controller/Action.php(513): StaticContentController->displayAction() #1 /var/www/square/library/Zend/Controller/Dispatcher/Standard.php(295): Zend_Controller_Action->dispatch('displayAction') #2 /var/www/square/library/Zend/Controller/Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #3 /var/www/square/library/Zend/Application/Bootstrap/Bootstrap.php(97): Zend_Controller_Front->dispatch() #4 /var/www/square/library/Zend/Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #5 /var/www/square/public/index.php(26): Zend_Application->run() #6 {main} Request Parameters: array ( 'page' => 'services', 'module' => 'default', 'controller' => 'static-content', 'action' => 'display', )

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  • no volume in kubuntu 10.04

    - by neha
    hello,I am having both gnome and kde on my system.as my gnome is working perfectly but in KDE is there is no sound being generated. output of apley -l and lspci commands is as follows.. neha@neha-laptop:~$ aplay -l **** List of PLAYBACK Hardware Devices **** card 0: Intel [HDA Intel], device 0: STAC92xx Analog [STAC92xx Analog] Subdevices: 1/1 Subdevice #0: subdevice #0 card 0: Intel [HDA Intel], device 3: INTEL HDMI [INTEL HDMI] Subdevices: 1/1 Subdevice #0: subdevice #0 and output of lspci command is: neha@neha-laptop:~$ lspci 00:00.0 Host bridge: Intel Corporation Mobile PM965/GM965/GL960 Memory Controller Hub (rev 0c) 00:02.0 VGA compatible controller: Intel Corporation Mobile GM965/GL960 Integrated Graphics Controller (rev 0c) 00:02.1 Display controller: Intel Corporation Mobile GM965/GL960 Integrated Graphics Controller (rev 0c) 00:1a.0 USB Controller: Intel Corporation 82801H (ICH8 Family) USB UHCI Controller #4 (rev 02) 00:1a.1 USB Controller: Intel Corporation 82801H (ICH8 Family) USB UHCI Controller #5 (rev 02) 00:1a.7 USB Controller: Intel Corporation 82801H (ICH8 Family) USB2 EHCI Controller #2 (rev 02) 00:1b.0 Audio device: Intel Corporation 82801H (ICH8 Family) HD Audio Controller (rev 02) 00:1c.0 PCI bridge: Intel Corporation 82801H (ICH8 Family) PCI Express Port 1 (rev 02) 00:1c.1 PCI bridge: Intel Corporation 82801H (ICH8 Family) PCI Express Port 2 (rev 02) 00:1c.4 PCI bridge: Intel Corporation 82801H (ICH8 Family) PCI Express Port 5 (rev 02) 00:1d.0 USB Controller: Intel Corporation 82801H (ICH8 Family) USB UHCI Controller #1 (rev 02) 00:1d.1 USB Controller: Intel Corporation 82801H (ICH8 Family) USB UHCI Controller #2 (rev 02) 00:1d.2 USB Controller: Intel Corporation 82801H (ICH8 Family) USB UHCI Controller #3 (rev 02) 00:1d.7 USB Controller: Intel Corporation 82801H (ICH8 Family) USB2 EHCI Controller #1 (rev 02) 00:1e.0 PCI bridge: Intel Corporation 82801 Mobile PCI Bridge (rev f2) 00:1f.0 ISA bridge: Intel Corporation 82801HEM (ICH8M) LPC Interface Controller (rev 02) 00:1f.1 IDE interface: Intel Corporation 82801HBM/HEM (ICH8M/ICH8M-E) IDE Controller (rev 02) 00:1f.2 SATA controller: Intel Corporation 82801HBM/HEM (ICH8M/ICH8M-E) SATA AHCI Controller (rev 02) 00:1f.3 SMBus: Intel Corporation 82801H (ICH8 Family) SMBus Controller (rev 02) 02:09.0 FireWire (IEEE 1394): Ricoh Co Ltd R5C832 IEEE 1394 Controller (rev 05) 02:09.1 SD Host controller: Ricoh Co Ltd R5C822 SD/SDIO/MMC/MS/MSPro Host Adapter (rev 22) 02:09.2 System peripheral: Ricoh Co Ltd R5C843 MMC Host Controller (rev 12) 02:09.3 System peripheral: Ricoh Co Ltd R5C592 Memory Stick Bus Host Adapter (rev 12) 02:09.4 System peripheral: Ricoh Co Ltd xD-Picture Card Controller (rev ff) 09:00.0 Ethernet controller: Marvell Technology Group Ltd. 88E8040 PCI-E Fast Ethernet Controller (rev 12) 0b:00.0 Network controller: Broadcom Corporation BCM4312 802.11a/b/g (rev 01) can anyone help me??

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  • Zend framework controller action helper

    - by guptanikhilchandra
    I am getting fatal error after adding the action helper class. I am trying to load layout corresponding to called layout. Following is my code snippet: First of all i added a helper class under application/controller/helpers: class Zend_Controller_Action_Helper_Layout extends Zend_Controller_Action_Helper_Abstract { public $pluginLoader; public function __construct() { // TODO Auto-generated Constructor $this->pluginLoader = new Zend_Loader_PluginLoader (); } public function preDispatch() { $bootstrap = $this->getActionController()->getInvokeArg('bootstrap'); $config = $bootstrap->getOptions(); $module = $this->getRequest()->getModuleName(); if (isset($config[$module]['resources']['layout']['layout'])) { $layoutScript = $config[$module]['resources']['layout']['layout']; $this->getActionController()->getHelper('layout')->setLayout($layoutScript); } } } Then i added a loader in bootstrap.php: protected function _initLayoutHelper() { $this->bootstrap('frontController'); Zend_Controller_Action_HelperBroker::addPath(APPLICATION_PATH .'/controllers/helpers'); $layout = Zend_Controller_Action_HelperBroker::addHelper(new Zend_Controller_Action_Helper_Layout()); } Following is my application.ini: [production] autoloaderNamespaces.tree = "Tree_" phpSettings.display_startup_errors = 0 phpSettings.display_errors = 0 includePaths.library = APPLICATION_PATH "/../library" bootstrap.path = APPLICATION_PATH "/Bootstrap.php" bootstrap.class = "Bootstrap" resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" resources.frontController.helperDirectory = APPLICATION_PATH "/controllers/helpers" resources.modules[] = "" contact.resources.frontController.defaultControllerName = "index" resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.layout.layout = layout admin.resources.layout.layout = admin admin.resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.view[] = [staging : production] [testing : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 [development : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 While running this code i am getting following errors: Warning: include(Zend\Controller\Action\Helper\LayoutLoader.php) [function.include]: failed to open stream: No such file or directory in D:\personal\proj\renovate\library\Zend\Loader.php on line 83 Warning: include() [function.include]: Failed opening 'Zend\Controller\Action\Helper\LayoutLoader.php' for inclusion (include_path='D:\personal\proj\renovate\application/../library;D:\personal\proj\renovate\library;.;C:\php5\pear') in D:\personal\proj\renovate\library\Zend\Loader.php on line 83 Fatal error: Class 'Zend_Controller_Action_Helper_LayoutLoader' not found in D:\personal\proj\renovate\application\Bootstrap.php on line 33 Kindly let me know, how can i come out from this issue. I am beginner in Zend Framework. Thanks Nikhil

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  • Problem connecting to MySQL with zend

    - by wheresrhys
    I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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  • Problem connecting to MySQL with zend

    - by wheresrhys
    I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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  • phpmyadmin throws a blank page after installing Zend CE server

    - by infotoknowledge
    I installed LAMP on Ubuntu 12.0.4 LTE. Then I installed phpmyadmin. Everything was good. I used phpadmin to do lots of DB administration.... Then I installed Zend CE server. Now, phpmyadmin throws a blank page. No login screen. So, I reinstalled my VPS in the same sequence again. No luck. Same behavior. This time, I installed Apache, Mysql, PHP and Zend server in that order. Then I installed phpmyadmin....Unfortunately, still blank page on phpmyadmin. Any help?...Thanks in advance.

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  • Display subform after validate main form

    - by bahamut100
    Hi, I want to display a new form after the validation of a form. I use Zend_Form_SubForm to do it (I Try to Zend_Form too), but this new form is not displaying. Why ?? This is the code in question : if ($this->_request->isPost()) { $formData = $this->_request->getPost(); if ($form->isValid($formData)) { $subForm = new Zend_Form_SubForm(); $subForm ->setAction('') ->setMethod('post'); $nom=new Zend_Form_Element_Text('nom'); $submit = new Zend_Form_Element_Submit('submit'); $submit->setLabel('OK'); $subForm->addElements(array($nom,$submit)); } else { $form->populate($formData); } }

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  • Showing login view controller before main tab bar controller

    - by Padawan
    I'm creating an iPad app with a tab bar controller that requires login. So on launch, I want to show a LoginViewController and if login is successful, then show the tab bar controller. This is how I implemented an initial test version (left out some typical header stuff, etc)... AppDelegate.h: @interface AppDelegate_Pad : NSObject <UIApplicationDelegate, LoginViewControllerDelegate> { UIWindow *window; UITabBarController *tabBarController; } @property (nonatomic, retain) IBOutlet UIWindow *window; @property (nonatomic, retain) IBOutlet UITabBarController *tabBarController; @end AppDelegate.m: @implementation AppDelegate_Pad @synthesize window; @synthesize tabBarController; - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { LoginViewController_Pad *lvc = [[LoginViewController_Pad alloc] initWithNibName:@"LoginViewController_Pad" bundle:nil]; lvc.delegate = self; [window addSubview:lvc.view]; //[lvc release]; [window makeKeyAndVisible]; return YES; } - (void)loginViewControllerDidFinish:(LoginViewController_Pad *)loginViewController { [window addSubview:tabBarController.view]; } - (void)dealloc {...} @end LoginViewController_Pad.h: @protocol LoginViewControllerDelegate; @interface LoginViewController_Pad : UIViewController { id<LoginViewControllerDelegate> delegate; } @property (nonatomic, assign) id <LoginViewControllerDelegate> delegate; - (IBAction)buttonPressed; @end @protocol LoginViewControllerDelegate -(void)loginViewControllerDidFinish:(LoginViewController_Pad *)loginViewController; @end LoginViewController_Pad.m: @implementation LoginViewController_Pad @synthesize delegate; ... - (IBAction)buttonPressed { [self.view removeFromSuperview]; [self.delegate loginViewControllerDidFinish:self]; } ... @end So the app delegate adds the login view controller's view on launch and waits for login to call "did finish" using a delegate. The login view controller calls removeFromSuperView before it calls didFinish. The app delegate then calls addSubView on the tab bar controller's view. If you made it up to this point, thanks, and I have three questions: MAIN QUESTION: Is this the right way to show a view controller before the app's main tab bar controller is displayed? Even though it seems to work, is it a proper way to do it? If I comment out the "lvc release" in the app delegate then the app crashes with EXC_BAD_ACCESS when the button on the login view controller is pressed. Why? With the "lvc release" commented out everything seems to work but on the debugger console it writes this message when the app delegate calls addSubView for the tab bar controller: Using two-stage rotation animation. To use the smoother single-stage animation, this application must remove two-stage method implementations. What does that mean and do I need to worry about it?

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  • MVC - Calling Controller Methods

    - by JT703
    Hello, My application is following the MVC design pattern. The problem I keep running into is needing to call methods inside a Controller class from outside that Controller class (ex. A View class wants to call a Controller method, or a Manager class wants to call a Controller method). Is calling Controller methods in this way allowed in MVC? If it's allowed, what's the proper way to do it? According to the version of MVC that I am following (there seems to be so many different versions out there), the View knows of the Model, and the Controller knows of the View. Doing it this way, I can't access the controller. Here's the best site I've found and the one describing the version of MVC I'm following: http://leepoint.net/notes-java/GUI/structure/40mvc.html. The Main Program code block really shows how this works. Thanks for any answers.

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  • zend_form ViewScript decorator / passing arguments

    - by timpone
    I have a form that is extend from Zend_Form. I am placing the form into a ViewScript decorator like this: $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml')))); I'd like to pass in a variable to this ViewScript but am not sure how this could be done. Since the partial renders out as a Zend_View (allowing $this-app_store_icon for rendering), it seems like there should be a way to pass variables to be rendered. I tried the following but to no avail. $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml'),array('app_store_picon'=>$current_app_store_picon)))); Any help on how to get this done would be appreciated. thanks

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  • How to add CSS classes to Zend_Form_Element_Select option

    - by Jah Selassie
    Hi, I'm trying to add a CSS class to a Zend_Form_Element_Select option, but I just can't find a way to do it. The desired output would be something like this: <select name="hey" id="hey"> <option value="value1" style="parent">label1</option> <option value="value2" style="sibling">sublabel1</option> <option value="value3" style="sibling">sublabel2</option> <option value="value4" style="parent">label2</option> <option value="value5" style="sibling">sublabel3</option> <option value="value6" style="sibling">sublabel4</option> </select> But I'm getting this: <select name="hey" id="hey"> <option value="value1">label1</option> <option value="value2">sublabel1</option> <option value="value3">sublabel2</option> <option value="value4">label2</option> <option value="value5">sublabel3</option> <option value="value6">sublabel4</option> </select> I can't seem to pass a CSS class attribute to any of the options in the select element although I can style the select element itselft. My code: $sel = new Zend_Form_Element_Select('hey'); $sel->setRequired(true)->setLabel('Select an Option:'); $sel->addMultiOption('value1', 'label1', array('class' => 'parent')) ->addMultiOption('value2', 'sublabel1', array('class' => 'sibling')) (etc...); After researching a bit I found out that Element_Select doesn't have a method for adding CSS styles to the options in the select box, only for the select itself. So, how can I add them? Should I extend the form_element_select? Or would a custom decorator suffice? Can anyone give me a hint? I'm baffled with this. Thanks in advance!

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  • management users with Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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  • Setting the inner html text of a < span > element using Zend_Form_Decorators

    - by Mallika Iyer
    I'm trying to set the inner html of the < span tag here , so it looks like: Group this is what i have so far: $form->addDisplayGroup( array( ................ ), 'maingroup1', array( 'legend'=>'', 'disableDefaultDecorators'=> true, 'decorators'=> array('FormElements', array('FieldSet',array('class'=>'dashed-outline2')), array(array('SpanTag' => 'HtmlTag'), array('tag'=>'span','class' => 'group',)), array('HtmlTag',array('tag'=>'div','id'=>'group1','class'=>'group','openOnly'=> true)) ) ) ); Is there a setter / property that I can use to set the inner text of the < span element using Zend_form_decorators? Thanks.

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  • How can I append a description to a Zend_Form_Element?

    - by Mallika Iyer
    I have the following Zend_Form_Element: $imginstructions = "Some description"; $img = $this->createElement('select','img'); $img->setAttrib('class', 'image-select'); $imgdecorator = $img->getDecorator('Description'); $imgdecorator->setOption('escape', false); $img->setLabel('Image:') ->setRequired(true) ->addMultiOptions($images) ->setValue('') ->setDescription($imginstructions) ->addErrorMessage('You must select an image'); $img->size = 5; $this->addElement($img); The description should appear next to the select box. The problem is : When an error is thrown, the html rendered changes so the description shows up below the select box, instead of beside it. HTML rendered before error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p></dd> HTML rendered after error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <ul class="errors"><li>You must select an image</li></ul> <p class="description">Some Description</p></dd> Is there a way to force the error message to be appended as the last element in the DOM tree for the dd element? Something like: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p> <ul class="errors"><li>You must select an image</li></ul></dd> so the 'ul' is at the end of the dd DOM tree. Thanks, I appreciate your taking the time to respond to this question!

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  • Some question about Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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  • What's the simplest way to create a Zend_Form tabular display with each row having a radio button?

    - by RenderIn
    I've seen simple examples of rendering a Zend_Form using decorators, but I'm not sure they are able to handle the issue I'm facing very well. I query the database and get an array of user objects. I want to display these users as a form, with a radio button next to each of them and a submit button at the bottom of the page. Here's roughly what the form will look like: [user id] [email] [full name] ( ) 1 [email protected] Test user 1 (*) 2 [email protected] Test user 2 [SUBMIT] Is this something achievable in a reasonably straightforward way or do I need to use the ViewScript partial?

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  • row specific class

    - by stimpie
    How do I create a Zend_Db_Table which returns a different class for each row.? Example UserTable has id,name and type Type contains class names (admin,client,etc...) The classes admin, client are all subclasses of user If I call fetch I need to get a admin or client object depending on the corresponding value in the db.

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  • Inject filter into Zend_View

    - by chelmertz
    Hi! I wish to set some properties in MyFilter with constructor injection but it seems impossible with Zend_View::addFilter(string $filter_class_name) since it loads a new instance upon usage. MyFilter implements Zend_Filter_Interface. Can I somehow inject an instance of a filter to an instance of Zend_View?

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  • how to decorate the error message

    - by ulduz114
    this is the decorator code $mydecorate = array( 'ViewHelper', array('Errors', array('placement' => 'append','class' => 'error')), array('Label', array('separator' => '')), array('HtmlTag', array('tag' => 'p', 'class' => 'element-form')) ); html result of two input elements with the above decorator: <p class="element-form"> <label for="firstname" class="required">First Name:</label> <input name="firstname" id="firstname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> <p class="element-form"> <label for="lastname" class="required">Last Name:</label> <input name="lastname" id="lastname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> I'd like the error message to be placed inside the p.element-form tag, any idea pleas? thanks

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