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  • free sql script to get a list of countries, provinces/states and their cities.

    - by reggie
    I am working on a registration page for a php website as mysql as the backend database. I need a sql script to insert the list of countries with their associated provinces and the provinces with their associated cities. I need all the countries, provinces and cities all over the world which are related to each other. I can get the individual list of countries, provinces and cities but there is no list that relates them together.. any help appreciated.. thanks in advance.

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  • PDO update with conditional?

    - by dmontain
    I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. But hopefully there is a way to accomplish this in 1 query?

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  • select random value from each type

    - by Joseph Mastey
    I have two tables, rating: +-----------+-----------+-------------+----------+ | rating_id | entity_id | rating_code | position | +-----------+-----------+-------------+----------+ | 1 | 1 | Quality | 0 | | 2 | 1 | Value | 0 | | 3 | 1 | Price | 0 | +-----------+-----------+-------------+----------+ And rating_option +-----------+-----------+------+-------+----------+ | option_id | rating_id | code | value | position | +-----------+-----------+------+-------+----------+ | 1 | 1 | 1 | 1 | 1 | | 2 | 1 | 2 | 2 | 2 | | 3 | 1 | 3 | 3 | 3 | | 4 | 1 | 4 | 4 | 4 | | 5 | 1 | 5 | 5 | 5 | | 6 | 2 | 1 | 1 | 1 | | 7 | 2 | 2 | 2 | 2 | | 8 | 2 | 3 | 3 | 3 | | 9 | 2 | 4 | 4 | 4 | | 10 | 2 | 5 | 5 | 5 | | 11 | 3 | 1 | 1 | 1 | | 12 | 3 | 2 | 2 | 2 | | 13 | 3 | 3 | 3 | 3 | | 14 | 3 | 4 | 4 | 4 | | 15 | 3 | 5 | 5 | 5 | +-----------+-----------+------+-------+----------+ I need a SQL query (not application level, must stay in the database) which will select a set of ratings randomly. A sample result would look like this, but would pick a random value for each rating_id on subsequent calls: +-----------+-----------+------+-------+----------+ | option_id | rating_id | code | value | position | +-----------+-----------+------+-------+----------+ | 1 | 1 | 1 | 1 | 1 | | 8 | 2 | 3 | 3 | 3 | | 15 | 3 | 5 | 5 | 5 | +-----------+-----------+------+-------+----------+ I'm totally stuck on the random part, and grouping by rating_id has been a crap shoot so far. Any MySQL ninjas want to take a stab? Thanks, Joe

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  • Is it possible to call a procedure within an SQL statement?

    - by darren
    Hi everyone I thought I would use a stored routine to clean up some of my more complex SQL statements. From what I've read, it seems impossible to use a stored procedure within an sql statement, and a stored function only returns a single value when what I need is a result set. I am using mySQL v5.0 SELECT p.`id`, gi.`id` FROM `sport`.`players` AS p JOIN `sport`.`gameinstances` AS gi ON p.`id` = gi.`playerid` WHERE (p.`playerid` IN (CALL findPlayers`("Canada", "2002"))) AND (gi.`instanceid` NOT IN (CALL findGameInstances`("Canada", "2002"))); For example, the procedures 'findPlayers' and 'findGameInstances' are are stored routines that execute some SQL and return a result set. I would prefer not to include their code directly within the statement above.

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  • Identifying which value of a multi-row inserts fails foreign key constraint

    - by Jonathan
    I have a multi-row insert that looks something like: insert into table VALUES (1, 2, 3), (4, 5, 6), (7, 8, 9); Assume the first attribute (1, 4, 7) is a foreign key to another table and assume that this referenced table does not have the value '4'. A MySQLExeption is thrown with error code 1452. EXCEPTION: Cannot add or update a child row: a foreign key constraint fails (dbName/tableName, CONSTRAINT id FOREIGN KEY (customer_id) REFERENCES referencedTable (customer_id)) Is there a way to identify which value caused the error? I would love to give my user an error message that said something like: Error: '4' does not exist in the referenced table. I am using the .NET mysql connector to execute the insert. Thanks- Jonathan

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  • PDO update query with conditional?

    - by dmontain
    I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; (meaning that the update of field3 is controlled by a conditional statement) Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. //run this query to update only fields 1 and 2 $update_part1 = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2 WHERE key=:key"); //if field3 should be update, run a separate query to update it separately if ($update3){ $update_part2 = $mypdo->prepare("UPDATE tablename SET field3=:field3 WHERE key=:key"); } But hopefully there is a way to accomplish this in 1 query?

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  • Force 'Replace Into' to use a certain index

    - by Bobby
    I have a MySQL (5.0) table with 3 rows which are considered a combined Unique Index: CREATE TABLE `test`.`table_a` ( `Id` int(11) NOT NULL AUTO_INCREMENT, `field1` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', `field2` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', `field3` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', PRIMARY KEY (`Id`), INDEX `IdxUnqiue` (`field1`(5),`field2`(5),`field3`(5)) ) ENGINE=MyISAM; This table should be filled with a REPLACE INTO query: REPLACE INTO table_a ( Field1, Field2, Field3 ) VALUES ( "Test1", "Test2", "Test3" ) The behavior I'd like to see is that this query always overrides the previous inserted row, because IdxUnique is...ahm, triggered. But unfortunately, there's still the primary index which seems to kick in and always inserts a new row. What I get: Query was executed 3 times: +---Id---+---Field1---+---Field2---+---Field3---+ | 1 | Test1 | Test2 | Test2 | | 2 | Test1 | Test2 | Test2 | | 3 | Test1 | Test2 | Test2 | +--------+------------+------------+------------+ What I want: Query was executed 3 times: +---Id---+---Field1---+---Field2---+---Field3---+ | 3 | Test1 | Test2 | Test2 | +--------+------------+------------+------------+ So, can I tell REPLACE INTO to use just a certain Index or to consider one 'more inportant' then another?

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  • InnoDB Cascade Rule that looks at 2 columns?

    - by Travis
    I have the following mysql InnoDB tables... TABLE foldersA ( ID title ) TABLE foldersB ( ID title ) TABLE records ( ID folderID folderType title ) folderID in table "records" can point to ID in either "foldersA" or "foldersB" depending on the value of folderType. (0 or 1). I am wondering: Is there a way to create a CASCADE rule such that the appropriate rows in table records are automatically deleted when a row in either foldersA or folderB is deleted? Or in this situation, am I forced to have to delete the rows in table "records" programatically? Thanks for you help!

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  • How to order results based on number of search term matches?

    - by Travis
    I am using the following tables in mysql to describe records that can have multiple searchtags associated with them: TABLE records ID title desc TABLE searchTags ID name TABLE recordSearchTags recordID searchTagID To SELECT records based on arbitrary search input, I have a statement that looks sort of like this: SELECT recordID FROM recordSearchTags LEFT JOIN searchTags ON recordSearchTags.searchTagID = searchTags.ID WHERE searchTags.name LIKE CONCAT('%','$search1','%') OR searchTags.name LIKE CONCAT('%','$search2','%') OR searchTags.name LIKE CONCAT('%','$search3','%') OR searchTags.name LIKE CONCAT('%','$search4','%'); I'd like to ORDER this resultset, so that rows that match with more search terms are displayed in front of rows that match with fewer search terms. For example, if a row matches all 4 search terms, it will be top of the list. A row that matches only 2 search terms will be somewhere in the middle. And a row that matches just one search term will be at the end. Any suggestions on what is the best way to do this? Thanks!

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  • Update query with conditional?

    - by dmontain
    I'm not sure if this possible. If not, let me know. I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; (meaning that the update of field3 is controlled by a conditional statement) Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. //run this query to update only fields 1 and 2 $update_part1 = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2 WHERE key=:key"); //if field3 should be update, run a separate query to update it separately if ($update3){ $update_part2 = $mypdo->prepare("UPDATE tablename SET field3=:field3 WHERE key=:key"); } But hopefully there is a way to accomplish this in 1 query?

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  • SQL select all items of an owner from an item-to-owner table

    - by kdobrev
    I have a table bike_to_owner. I would like to select current items owned by a specific user. Table structure is CREATE TABLE IF NOT EXISTS `bike_to_owner` ( `bike_id` int(10) unsigned NOT NULL, `user_id` int(10) unsigned NOT NULL, `last_change_date` date NOT NULL, PRIMARY KEY (`bike_id`,`user_id`,`last_change_date`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; In the profile page of the user I would like to display all his/her current possessions. I wrote this statement: SELECT `bike_id`,`user_id`,max(last_change_date) FROM `bike_to_owner` WHERE `user_id` = 3 group by `last_change_date` but i'm not quite sure it works correctly in all cases. Can you please verify this is correct and if not suggest me something better. Using php/mysql. Thanks in advance!

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  • Mysql_insert_id with Doctrine

    - by Industrial
    Hi! I have a couple of tables (mySQL) that i would like to update with the help of Doctrine. The products table id is auto-incrementing, and here's a brief description on what I would like to do: $prod = new Products(); $prod->type = '0'; $categ = new CategoriesToProducts(); $categ->cat = '111'; $categ->product = $prod->id; $conn = Doctrine_Manager::connection(); $conn->flush(); How can I do this while using flush? Using a regular save is an alternative, but there will be multiple transactions while doing such. I have tried to find a Mysql_insert_id version for doctrine, but without any luck. Thanks!

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  • Insert new row with data computed from other rows

    - by Tyler McHenry
    Suppose I have a MySQL table called MyTable, that looks like this: +----+------+-------+ | Id | Type | Value | +----+------+-------+ | 0 | A | 1 | | 0 | B | 1 | | 1 | A | 2 | | 1 | B | 3 | | 2 | A | 5 | | 2 | B | 8 | +----+------+-------+ And, for each Id, I want to insert a new row with type C whose Value is the sum of the type A and B values for the rows of the same Id. The primary key on this table is (Id, Type), so there's no question of duplication of Id,Type pairs. I can create the rows I want with this query: SELECT MyTable_A.Id AS Id, 'C' AS Type, (A_Val + B_Val) AS Value FROM (SELECT Id, Value AS A_Val FROM MyTable WHERE Type='A') AS MyTable_A JOIN (SELECT Id, Value AS B_Val FROM MyTable WHERE Type='B') AS MyTable_B ON MyTable_A.Id = MyTable_B.Id Giving: +----+------+-------+ | Id | Type | Value | +----+------+-------+ | 0 | C | 2 | | 1 | C | 5 | | 2 | C | 13 | +----+------+-------+ But the question is: How do I use this result to insert the generated type-C rows into MyTable? Is there a relatively simple way to do this with a query, or do I need to write a stored procedure? And if the latter, guidance would be helpful, as I'm not too well versed in them.

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  • How to do this query?

    - by Damiano
    Hello everybody! I have a mysql table with these columns: ID (auto-increment) ID_BOOK (int) PRICE (double) DATA (date) I know two ID_BOOK values, example, 1 and 2. QUERY: I have to extract all the PRICE (of the ID_BOOK=1 and ID_BOOK=2) where DATA is the same! Table example: 1 1 10.00 2010-05-16 2 1 11.00 2010-05-15 3 1 12.00 2010-05-14 4 2 18.00 2010-05-16 5 2 11.50 2010-05-15 Result example: 1 1 10.00 2010-05-16 4 2 18.00 2010-05-16 2 1 11.00 2010-05-15 5 2 11.50 2010-05-15 ID_BOOK=2 hasn't 2010-05-14 so i jump it. Thank you so much!

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  • How can I select all records between two dates without using date fields?

    - by Hayden Bech
    Hi, I have a MySQL DB and I need to be able to store dates earlier then 1970 - in my case, as early as 0 AD and earlier too, so I need a custom way to store dates. I have thought to use this format: Year - int(6) | Month -int(2) | day - int (2) | time - time | AD tinyint (1) | mya - int (11) But when it comes to actually using data in this format it becomes difficult. For example, if I want to get all records between two dates it would be like (pseudocode not SQL): get all where year between minYear and maxYear if year == minYear, month = minMonth if year == maxYear, month <= maxMonth if month == minMonth, day = minDay if month == maxMonth, day <= maxDay if day == minDay, time = minTime if day == maxDay, time <= maxTime or something, which seems like a right pain. I could store seconds before/after 0 AD, but that would take up way too much data! 2010 (EDIT: 2011) = 6.4 billion seconds since 0 AD. Does anybody have any ideas for this problem?

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  • Accessing global variables within functions in PHP

    - by st3
    There are multiple times in one page where I need to connect and subsequently query a MySQL database, yet my code won't let me. I think it might be something to do with how my files are nested but it makes no sense. I am opening the SQL connection in the header file. The top of the offending page looks like the following: <?php $page_title = 'Dashboard'; include('templates/header.inc'); // includes a 'require_once('mysqli_connect.php') and a small query to the database; require_once('includes/functions.php'); require_once('includes/dashboard_sql.php'); // Contains functions which connect to database (which are failing.) ?> I get the PHP error Notice: Undefined variable: dbc in /Library/WebServer/Documents/pediatory_site/includes/dashboard_sql.php Where $dbc is the database connection defined in mysqli_connect.php. If anyone could help me out that would be great.

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  • Was: Not unique table :: Now: #1054 - Unknown column - can't understand why!?

    - by Andy Barlow
    Hi! I'm trying to join some tables together in MySQL, but I seem to get an error saying: #1066 - Not unique table/alias: 'calendar_jobs' I really want it to select everything from the cal_events, the 2 user bits and just the destination col from the jobs table, but become "null" if there arn't any job. A right join seemed to fit the bill but doesn't work! Can anyone help!? UPDATE: Thanks for the help on the previous query, I'm now up to this: SELECT calendar_events.* , calendar_users.doctorOrNurse, calendar_users.passportName, calendar_jobs.destination FROM `calendar_events` , `calendar_users` RIGHT JOIN calendar_jobs ON calendar_events.jobID = calendar_jobs.jobID WHERE `start` >= 0 AND calendar_users.userID = calendar_events.userID; But am now getting an error saying: #1054 - Unknown column 'calendar_events.jobID' in 'on clause' What is it this time!? Thanks again!

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  • Not unique table/alias - can't understand why!?

    - by Andy Barlow
    Hi! I'm trying to join some tables together in MySQL, but I seem to get an error saying: #1066 - Not unique table/alias: 'calendar_jobs' I really want it to select everything from the cal_events, the 2 user bits and just the destination col from the jobs table, but become "null" if there arn't any job. A right join seemed to fit the bill but doesn't work! Can anyone help!? SELECT calendar_events.* , calendar_users.doctorOrNurse, calendar_users.passportName, calendar_jobs.destination FROM `calendar_events` , `calendar_users` , `calendar_jobs` RIGHT JOIN calendar_jobs ON calendar_events.jobID = calendar_jobs.jobID WHERE `start` >=0 AND calendar_users.userID = calendar_events.userID Cheers!

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  • Update ancestors in a nested set?

    - by Travis
    I am using nested sets to represent a tree in mysql, like so: Tree ID title lft rgt Given the ID of a node in the tree, what is the easiest / best way to UPDATE that node as well as all of it's ancestors? For example, let's say that the node ID (36) is 4 levels deep in the tree. I would like to update its title, as well as every parent node's title, all the way to the root, to the word "fish". (Should be four updates in all.) Thanks for your help!

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  • MYSQL -Incorrect Syntax

    - by user1854392
    WHILE x > 1 DO SET x = x - 1; SET totalTime = SELECT CONCAT(FLOOR(HOUR(TIMEDIFF(end_time,start_time)) / 24), ' days ', MOD(HOUR(TIMEDIFF(end_time,start_time)), 24), ' hrs ', MINUTE(TIMEDIFF(end_time,start_time)), ' minutes ') AS total_Time I don't see why I am having a syntax error? It is part of a bigger procedure but is pointing to this aas being incorrect Error message: SQL Error (1064): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT CONCAT(FLOOR(HOUR(TIMEDIFF(end_time,start_time)) / 24,' days',' at line 11 and totalTime is declared as a VARCHAR(50)

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  • mysql_real_escape_string & slashes (again, oh yes)

    - by Fizzadar
    Righto, firstly magic quotes & runtime are disabled correctly in php.ini, and confirmed by phpinfo(). PHP version: 5.3.4 MySQL version: 5.1.52 I'm only use mysql_real_escape_string on the data, after htmlspecialchars and a trim, that's all the data cleaning on the variable. Yet, when I submit a single quote, the slash remains in the database. When running mysql_query I'm using "' . $var . '", although in the past this hasn't changed anything (could be due to the double quotes?). Any ideas? and please don't tell me about PDO/prepared statements, I'm aware of them and I have my reasons for doing it this way. Thanks!

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  • PHP - Get value of imput box, without a form?

    - by Dodi300
    Hello. Does anyone know how I can get the value of an imput box, without having a form? I want a sumbit button, but instead of submiting a form, I want it to change data in a MySQL database. Something like this maybe? $img1="WHAT DO I PUT HERE?" $idx=1 $sql="INSERT INTO games SET img1='$img1' WHERE id=$idx"; $result=mysql_query($sql); Could I use that code on a "onclick" event? The imput box is named "img1". Thanks for the help!

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  • Why do apache2 upgrades remove and not re-install libapache2-mod-php5?

    - by nutznboltz
    We repeatedly see that when an apache2 update arrives and is installed it causes the libapache2-mod-php5 package to be removed and does not subsequently re-install it automatically. We must subsequently re-install the libapache2-mod-php5 manually in order to restore functionality to our web server. Please see the following github gist, it is a contiguous section of our server's dpkg.log showing the November 14, 2011 update to apache2: https://gist.github.com/1368361 it includes 2011-11-14 11:22:18 remove libapache2-mod-php5 5.3.2-1ubuntu4.10 5.3.2-1ubuntu4.10 Is this a known issue? Do other people see this too? I could not find any launchpad bug reports about it. Platform details: $ lsb_release -ds Ubuntu 10.04.3 LTS $ uname -srvm Linux 2.6.38-12-virtual #51~lucid1-Ubuntu SMP Thu Sep 29 20:27:50 UTC 2011 x86_64 $ dpkg -l | awk '/ii.*apache/ {print $2 " " $3 }' apache2 2.2.14-5ubuntu8.7 apache2-mpm-prefork 2.2.14-5ubuntu8.7 apache2-utils 2.2.14-5ubuntu8.7 apache2.2-bin 2.2.14-5ubuntu8.7 apache2.2-common 2.2.14-5ubuntu8.7 libapache2-mod-authnz-external 3.2.4-2+squeeze1build0.10.04.1 libapache2-mod-php5 5.3.2-1ubuntu4.10 Thanks At a high-level the update process looks like: package package_name do action :upgrade case node[:platform] when 'centos', 'redhat', 'scientific' options '--disableplugin=fastestmirror' when 'ubuntu' options '-o Dpkg::Options::="--force-confdef" -o Dpkg::Options::="--force-confold"' end end But at a lower level def install_package(name, version) run_command_with_systems_locale( :command = "apt-get -q -y#{expand_options(@new_resource.options)} install #{name}=#{version}", :environment = { "DEBIAN_FRONTEND" = "noninteractive" } ) end def upgrade_package(name, version) install_package(name, version) end So Chef is using "install" to do "update". This sort of moves the question around to "how does apt-get safe-upgrade" remember to re-install libapache-mod-php5? The exact sequence of packages that triggered this was: apache2 apache2-mpm-prefork apache2-mpm-worker apache2-utils apache2.2-bin apache2.2-common But the code is attempting to run checks to make sure the packages in that list are installed already before attempting to "upgrade" them. case node[:platform] when 'debian', 'centos', 'fedora', 'redhat', 'scientific', 'ubuntu' # first primitive way is to define the updates in the recipe # data bags will be used later %w/ apache2 apache2-mpm-prefork apache2-mpm-worker apache2-utils apache2.2-bin apache2.2-common /.each{ |package_name| Chef::Log.debug("is #{package_name} among local packages available for changes?") next unless node[:packages][:changes].keys.include?(package_name) Chef::Log.debug("is #{package_name} available for upgrade?") next unless node[:packages][:changes][package_name][:action] == 'upgrade' package package_name do action :upgrade case node[:platform] when 'centos', 'redhat', 'scientific' options '--disableplugin=fastestmirror' when 'ubuntu' options '-o Dpkg::Options::="--force-confdef" -o Dpkg::Options::="--force-confold"' end end tag('upgraded') } # after upgrading everything, run yum cache updater if tagged?('upgraded') # Remove old orphaned dependencies and kernel images and kernel headers etc. # Remove cached deb files. case node[:platform] when 'ubuntu' execute 'apt-get -y autoremove' execute 'apt-get clean' # Re-check what updates are available soon. when 'centos', 'fedora', 'redhat', 'scientific' node[:packages][:last_time_we_looked_at_yum] = 0 end untag('upgraded') end end But it's clear that it fails since the dpkg.log has 2011-11-14 11:22:25 install apache2-mpm-worker 2.2.14-5ubuntu8.7 on a system which does not currently have apache2-mpm-worker. I will have to discuss this with the author, thanks again.

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  • Enable Claims based Auth on a SP2010 website, after it has been provisioned

    Ad:: SharePoint 2007 Training in .NET 3.5 technologies (more information). This feed URL has been discontinued. Please update your reader's URL to : http://feeds.feedburner.com/winsmarts Read full article .... ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Online Accounts auth over and over again without success

    - by Mike Pretzlaw
    I just added my Google account to the "Online Accounts" in Gnome. Before my last restart the account couldn't be added for unknown reason. I authorized Gnome access to my Google Account, the window closed and nothing happened. Now I authorized Ubuntu access to my Google Account which worked well: But I can not open the Gnome Online Accounts even when I delete every online account: It's icon show up that it is loading in the dash but then suddenly disappears without any message. How to debug that? What can I do?

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