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  • How do I write a single-file Django application?

    - by obvio171
    I want to write a very small Django application in a single file, requiring all the appropriate modules and stuff, and then be able to run that as a normal Python script, like this: $ python myapp.py You can assume I won't render HTML, so I don't need templates (I'll return JSON or some other auto-generated string).

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  • How to test 500.html in (django) development env?

    - by lud0h
    I am using Django for a project and is already in production. In the production environment 500.html is rendered whenever a server error occurs. How do I test the rendering of 500.html in dev environment? Or how do I render 500.html in dev, if I turn-off debug I still get the errors and not 500.html background: I include some page elements based on a page and some are missing when 500.html is called and want to debug it in dev environment.

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  • How to configure multiple web site with django and tornado?

    - by mapcuk
    On my VDS I use nginx, django and tornado. I had just one project, Now i gonna deploy another one project with a different domain name. I want to use different databases and folders. I know how to configure nginx for serving static resourses , but what about tornado? Should i run separeted instance of tornado for each project or is there any better solution?

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  • Django: What's the correct way to get the requesting IP address?

    - by swisstony
    I'm trying to develop an app using Django 1.1 on Webfaction. I'd like to get the IP address of the incoming request, but when I use request.META['REMOTE_ADDR'] it returns 127.0.0.1. There seems to be a number of different ways of getting the address, such as using HTTP_X_FORWARDED_FOR or plugging in some middleware called SetRemoteAddrFromForwardedFor. Just wondering what the best approach was?

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  • How do I collect a bunch of Django abstract models in a QuerySet?

    - by Thierry Lam
    I have the following abstract Django models: class Food(models.Model): name = models.CharField(max_length=100) class Meta: abstract = True In one of my view, I created a bunch of Food model: panino = Food(name='Panino') poutine = Food(name='Poutine') food = [panino, poutine] From the above, I'm not saving the model and storing the Food model in a regular Python list. I want to store the above food models in a QuerySet object. How can I do that without storing any data to the database?

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  • Django/jquery: Address forms - dyamically adding state drop down list if country is United States?

    - by User
    I have a django html form for address information. There is standard street, city, state/province, postal code, country fields. The country field is a drop down list. How can I make the state/province field a drop down list if the selected country is united states and a free form text box if the country is anything else? I'd prefer not to have to do a round trip to the server so probably through jquery?

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  • Any reason not to use USE_ETAGS with CommonMiddleware in Django?

    - by allyourcode
    The only reason I can think of is that calculating ETag's might be expensive. If pages change very quickly, the browser's cache is likely to be invalidated by the ETag. In that case, calculating the ETag would be a waste of time. On the other hand, a giving a 304 response when possible minimizes the amount of time spent in transmission. What are some good guidelines for when ETag's are likely to be a net winner when implemented with Django's CommonMiddleware?

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  • I am currently serving my static files in Django. How do I use Apache2 to do this?

    - by alex
    (r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root': settings.MEDIA_ROOT}), As you can see, I have a directory called "media" under my Django project. I would like to delete this line in my urls.py and instead us Apache to serve my static files. What do I do to my Apache configs (which files do I change) in order to do this? By the way, I installed Apache2 like normal: sudo aptitude install apache2

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  • Magento - Add CMS Block to One Page

    - by a1anm
    I have this code in a xml layout file: <reference name="left"> <block type="blog/blog" name="left.blog.menu" before="-"> <action method="setTemplate" ifconfig="blog/menu/left"> <template>aw_blog/menu.phtml</template> </action> <block type="blog/tags" name="blog_tags" /> </block> </reference> I want to add a cms static block to the blog pages using this code: <block type="cms/block" name="brand_list"> <action method="setBlockId"><block_id>brand_list</block_id></action> </block> If I add it in directly after this line: <reference name="left"> It works but it is then displayed on every page. How can I get it to show only on the blog pages? Thanks. Edit: Here is the entire xml file: <layout version="0.1.0"> <default> <reference name="footer_links"> <block type="blog/blog" name="add.blog.footer"> <block type="blog/tags" name="blog_tags" /> <action method="addFooterLink" ifconfig="blog/menu/footer"></action> </block> </reference> <reference name="right"> <block type="blog/blog" name="right.blog.menu" before="-"> <action method="setTemplate" ifconfig="blog/menu/right" ifvalue="1"> <template>aw_blog/menu.phtml</template> </action> <block type="blog/tags" name="blog_tags" /> </block> </reference> <reference name="left"> <block type="blog/blog" name="left.blog.menu" before="-"> <action method="setTemplate" ifconfig="blog/menu/left"> <template>aw_blog/menu.phtml</template> </action> <block type="blog/tags" name="blog_tags" /> </block> </reference> <reference name="top.links"> <block type="blog/blog" name="add.blog.link"> <action method="addTopLink" ifconfig="blog/menu/top"></action> <block type="blog/tags" name="blog_tags" /> </block> </reference> <reference name="head"> <action method="addItem"><type>skin_css</type><name>aw_blog/css/style.css</name></action> </reference> </default> <blog_index_index> <reference name="content"> <block type="blog/blog" name="blog" template="aw_blog/blog.phtml"/> </reference> </blog_index_index> <blog_index_list> <reference name="content"> <block type="blog/blog" name="blog" template="aw_blog/blog.phtml"/> </reference> </blog_index_list> <blog_post_view> <reference name="content"> <block type="blog/post" name="post" template="aw_blog/post.phtml"> <block type="socialbookmarking/bookmarks" name="bookmarks" template="bookmarks/bookmarks.phtml"/> </block> </reference> </blog_post_view> <blog_cat_view> <reference name="content"> <block type="blog/cat" name="cat" template="aw_blog/cat.phtml" /> </reference> </blog_cat_view> <blog_rss_index> <block type="blog/rss" output="toHtml" name="rss.blog.new"/> </blog_rss_index> </layout>

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  • django on appengine

    - by aks
    I am impressed with django.Am am currenty a java developer.I want to make some cool websites for myself but i want to host it in some third pary environmet. Now the question is can i host the django application on appengine?If yes , how?? Are there any site built using django which are already hosted on appengine?

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  • How to access website CMS with only access to database

    - by user1741615
    I have a website that uses an "in-house" cms and I don't know the login details. The platform itself doesn't have the "reset your password" functionality. I do have access to ftp and phmyadmin and I found the SQL table containing the user details, but of course the password is MD5 encryption. I tried manually creating a user in php my admin and filling in a password encrypted in MD5 (used a md service online for that), but it still doesn't work. Does anybody know other tricks I can use? Thanks.

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  • Secure method for linking to image files uploaded via custom CMS

    - by letseatfood
    How does one provide a direct URL for an image file (JPEG) that is secure? For example, if a PHP script writes uploaded images to directory http://www.somehost.com/images, is it okay to provide http://www.somehost.com/images/someimage.jpg as the URL, or is there a more secure way to do this? Should I look into something like the permalink feature that is a part of Wordpress? I am not sure if that is related. The main reason I ask is that I have a custom PHP/MySQL CMS for managing images. I would like for the client to be able to copy a link to the image they want and then include it in a TinyMCE text editor for inserting the image in their website. Thanks!

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