Search Results

Search found 46646 results on 1866 pages for 'operating system'.

Page 1110/1866 | < Previous Page | 1106 1107 1108 1109 1110 1111 1112 1113 1114 1115 1116 1117  | Next Page >

  • android low memory issue

    - by Faisal khan
    1.Start Andorid app in my app there are 10 screens i navigate b/w the screens after that i press home button my app goes on the background now i play with other applications which cause system to run GC press home button select my app come back to my app when i press back button it throws exception and crashes. any idea for quick fix ?

    Read the article

  • Question on using Informa RSS Library

    - by molleman
    hello guys I Just started looking at this technology , but i am finding it hard to understand, i want to just reed in a simple rss feed url, and display its contents how could i do this? this is what i lloked at so far URL inpFile = new URL("feed://images.apple.com/main/rss/hotnews/hotnews.rss"); ChannelIF channel = FeedParser.parse(new ChannelBuilder(), inpFile); System.out.println(channel.getDescription()); this creates a malformed url exeception, can anyone help me???

    Read the article

  • Image.createImage problem in J2ME

    - by Michael
    Hi All, I tried this on J2ME try { Image immutableThumb = Image.createImage( temp, 0, temp.length); } catch (Exception ex) { System.out.println(ex); } I hit this error: java.lang.IllegalArgumentException: How do I solve this?

    Read the article

  • Making a CMS extendable by plugins - examples

    - by Anant
    I'm working on an open source script. I would like to provide a feature to extend the script by use of plugins/modules. I need some recommendations on open source cms/scripts to study code from, to gather the best practices on making script extendable by plugins. I've used WordPress in the past, and was planning to implement a similar system, but I'm looking to dive into alternatives, which might be better. Language preferred is PHP 5

    Read the article

  • PHP app\console wont work trying to create bundle for Symfony2

    - by user3461632
    I have installed Symfony2 on a iis 7 server with PHP 5.3.21 and everything works ok ( the php, the symphony demo page ). I try to create my own helloWorld, as the tutorial says : php app/console generate:bundle I go Start-Run-CMD and put that line of code and it gives me back this : could not open input file : app/console and before anyone asks i am in the project directory when i perform this command I put the PHP directory to the System PATH but the problem persists.

    Read the article

  • can not run java program from command line which resides in package

    - by kshitij
    See following code with resides in fillowing directory mypack.pack1 package mypack.pack1; public class myclass { public static void main(String args[]) { System.out.println("KKKKKKKKKKKKKKKKKKKKKKKKKKKKKK"); } } See following screen shot. that is giving error. And i dont want to add anything in class path because i am in particular directory and it has to work. why it is not working.??????

    Read the article

  • asp.net ajax calls stop browsing of sites page

    - by Ashian
    Hi, I have an ajax web application(asp.net). some of users report the a problemt that when they work sometimes by system ( and pages who have ajax calls) their connection to server will intrupt and just a blank page they will see. they can't browse any other page on my site while they close all open browsers and reopen site. Is there any idea about this and how can I fix it? thanks Mehdi

    Read the article

  • Visualization in "VisIt"

    - by Naveen
    Hi, Did any one over here work in "VisIt" visualization software? I have a dataset where the x, y, z coordinates are stored in separate bin files, i don't know how to visualize these files in VisIt, which would be the best file format to use. Till now, we were using Advanced Visual System (AVS) .fld files to read the data in AVS, now we have to switch to VisIt, don't know how to do it. Would appreciate if anyone can give some pointers in this direction.

    Read the article

  • Replace method doesn't work properly

    - by John Smith
    Hello I have a string and when i try to use replace method in for loop it doesn't work String phrase="hello friend"; String[] wordds=phrase.split(" "); String newPhrase="sup friendhello weirdo"; for (int g=0;g<2;g++) { finalPhrase+=newPhrase.replace(wordds[g],"");} } System.out.println(finalPhrase) It prints out "sup hello weirdo" and i expect it to print "sup weirdo". What am i doing wrong?

    Read the article

  • bash script code help to make zip/tar of several folders .

    - by Arsheep
    I am very new in bash and never coded in before but this task is stuck so need to get rid of it . I need to make bash script to make a single compressed file with several dirs. Like - /home/code/bots/ /var/config/ . . . /var/system/ and all will be compressed to single file /var/file/bkup.[zip][tar.gz] Thanks in advance

    Read the article

  • throw exception

    - by Unknown
    Why can't you throw an InterruptedException in the following way: try { System.in.wait(5) //Just an example } catch (InterruptedException exception) { exception.printStackTrace(); //On this next line I am confused as to why it will not let me throw the exception throw exception; } I went to http://java24hours.com, but it didn't tell me why I couldn't throw an InterruptedException. If anyone knows why, PLEASE tell me! I'm desperate! :S

    Read the article

  • Reference Object calling function in Javascript

    - by Louis
    I have a makeshift events system in JS and the attacher looks like this: events.attach(events.NEW_TASK,this.update); Where this.update is a callback/handler/function. The problem is, when the dispatcher tries to call this handler, it loses it's original context. How can I bind the handler with the context of the object that calls the attach function without passing this as an argument and using that?

    Read the article

  • How to get "Data Type" value of Body of a Lotus Notes Item using .NET?

    - by Pari
    I am trying to get Data Type (Body Format) of Mail,Calendar e.t.c. Body. Getting Body content as: String Body = (string)((object[])docInbox.GetItemValue("Body"))[0]; or String Body = docInbox.GetFirstItem("Body").Text; I tried it using: String bodyFormat = ((object[])docInbox.GetItemValue("Body"))[0].GetType().ToString(); But in this case i am getting "System.String" value.But actually it is : "Rich Text".

    Read the article

  • Start program on a second monitor?

    - by stukelly
    Is there a way to specify which monitor a application appears on in Delphi or C++Builder? I am developing a simple program for a customer, which displays kitchen orders on a secondary monitor, generated by a hospitality system. Currently they need to manually drag the window onto the second monitor after it starts.

    Read the article

  • Dreamweaver CS5 - Have Design Window as a Panel?

    - by Oliver Jones
    I've been looking around on the dreamweaver interface, and I'm trying to get my design window as an external panel. Reason is, I have a dual monitor system, and I would like to have the main window (where you can have both code/split/design) on my main screen, but with the code selected, and a design view on my secondary monitor. I'm assuming this can't be done, although I have noticed you can have your code as an external panel (Code Inspector). Would like to hear your input. Thanks

    Read the article

  • Java: Making concurrent MySQL queries from multiple clients synchronised

    - by Misha Gale
    I work at a gaming cybercafe, and we've got a system here (smartlaunch) which keeps track of game licenses. I've written a program which interfaces with this system (actually, with it's backend MySQL database). The program is meant to be run on a client PC and (1) query the database to select an unused license from the pool available, then (2) mark this license as in use by the client PC. The problem is, I've got a concurrency bug. The program is meant to be launched simultaneously on multiple machines, and when this happens, some machines often try and acquire the same license. I think that this is because steps (1) and (2) are not synchronised, i.e. one program determines that license #5 is available and selects it, but before it can mark #5 as in use another copy of the program on another PC tries to grab that same license. I've tried to solve this problem by using transactions and table locking, but it doesn't seem to make any difference - Am I doing this right? Here follows the code in question: public LicenseKey Acquire() throws SmartLaunchException, SQLException { Connection conn = SmartLaunchDB.getConnection(); int PCID = SmartLaunchDB.getCurrentPCID(); conn.createStatement().execute("LOCK TABLE `licensekeys` WRITE"); String sql = "SELECT * FROM `licensekeys` WHERE `InUseByPC` = 0 AND LicenseSetupID = ? ORDER BY `ID` DESC LIMIT 1"; PreparedStatement statement = conn.prepareStatement(sql); statement.setInt(1, this.id); ResultSet results = statement.executeQuery(); if (results.next()) { int licenseID = results.getInt("ID"); sql = "UPDATE `licensekeys` SET `InUseByPC` = ? WHERE `ID` = ?"; statement = conn.prepareStatement(sql); statement.setInt(1, PCID); statement.setInt(2, licenseID); statement.executeUpdate(); statement.close(); conn.commit(); conn.createStatement().execute("UNLOCK TABLES"); return new LicenseKey(results.getInt("ID"), this, results.getString("LicenseKey"), results.getInt("LicenseKeyType")); } else { throw new SmartLaunchException("All licenses of type " + this.name + "are in use"); } }

    Read the article

  • How do I detect server status in a port scanner java implementation

    - by akz
    I am writing a port scanner in Java and I want to be able to distinct the following 4 use cases: port is open port is open and server banner was read port is closed server is not live I have the following code: InetAddress address = InetAddress.getByName("google.com"); int[] ports = new int[]{21, 22, 23, 80, 443}; for (int i = 0; i < ports.length; i++) { int port = ports[i]; Socket socket = null; try { socket = new Socket(address, port); socket.setSoTimeout(500); System.out.println("port " + port + " open"); BufferedReader reader = new BufferedReader( new InputStreamReader(socket.getInputStream())); String line = reader.readLine(); if (line != null) { System.out.println(line); } socket.close(); } catch (SocketTimeoutException ex) { // port was open but nothing was read from input stream ex.printStackTrace(); } catch (ConnectException ex) { // port is closed ex.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { if (socket != null && !socket.isClosed()) { try { socket.close(); } catch (Exception e) { e.printStackTrace(); } } } } The problem is that I get a ConnectionException both when the port is closed and the server cannot be reached but with a different exception message: java.net.ConnectException: Connection timed out: connect when the connection was never established and java.net.ConnectException: Connection refused: connect when the port was closed so I cannot make the distinction between the two use cases without digging into the actual exception message. Same thing happens when I try a different approach for the socket creation. If I use: socket = new Socket(); socket.setSoTimeout(500); socket.connect(new InetSocketAddress(address, port), 1000); I have the same problem but with the SocketTimeoutException instead. I get a java.net.SocketTimeoutException: Read timed out if port was open but there was no banner to be read and java.net.SocketTimeoutException: connect timed out if server is not live or port is closed. Any ideas? Thanks in advance!

    Read the article

  • os.walk in python not running with cmd line parameter passed as path

    - by kartiku
    Hello, I needed to find the number of files in a folder on the system. This is what i used: file_count = sum((len(f) for _, _, f in os.walk('path'))) This works fine when we specify the path as a string in quotes, but when I enter a variable name that holds the path, type(file_count) is a generator object, and hence cannot be used as an integer. How to solve this and why does this happen?

    Read the article

< Previous Page | 1106 1107 1108 1109 1110 1111 1112 1113 1114 1115 1116 1117  | Next Page >