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  • I can't login to my Django app when debug is set to False

    - by Eric
    I have a very strange problem, and I don't know how to fix or debug it. Short Story: I get locked out of my Django app when Debug is set to False. Long story: Case 1 (the first time it happened): 1. I enter my login info, but It just redirects to the login page. 2. I restart the server, try to login, and it works fine, I get in. 3. a few hours later I come back, log out, try to log back in and I can't. It just redirects to the login page. Case 2 (I figure out how to provoke the login failure): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a server error. 4. I log out and try to log back in, and I can't, just get redirected back to the login page. Case 3 (I can't provoke the login failure with Debug set to True): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a traceback. 4. I log out and log back in, everything works. 5. I wait and play around with it and can't get the login to fail while in Debug mode. Please help!

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  • Securing Coredata objects

    - by Abraham Durairaj
    I am working on an application which has got some sensitive information. I am aware that it would be difficult for a layman to hack into iphone to get the information. If I use SQLite directly I have something called SQLite Cipher to encrypt / encode the database. Is there anyway where I can have the same way of encrypting the coredata so it makes it hard for hackers to get into the data. Can someone shed some light on this? Thanks in Advance

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  • Load images into separate movie clips from a XML, Flash, Actionscript 3.0

    - by James Dunay
    I have an xml image bank, pretty standard, and I have a loader, along with movie clips that I want the images loaded into, the problem that I am running into is I want the images to load into separate movie clips, so I’m using a case statement to specify where they go. However, I can only get them to load into a single movie clip, I assume they are loading ontop of each other and I don’t know how to get them to separate out. I’ll post my code. It doesn’t make any sense to me but if you have any suggestions that would be real great. I can make separate loaders and then just do 1 image per loader, but that just doesn’t sound right to me. var counterNumber:Number = 0; function callThumbs():void{ for (var i:Number = 0; i <3; i++){ thumbLoaded(); counterNumber++; } } function thumbLoaded(){ var photoLoader = new Loader(); switch (counterNumber){ case 1: photoLoader.load(new URLRequest(MovieClip(this.parent).xml.photos.imageOne.image.@url[0])); whole.boxOne.pictureLoader.addChild(photoLoader); trace("1Done"); break; case 2: photoLoader.load(new URLRequest(MovieClip(this.parent).xml.photos.imageTwo.image.@url[0])); whole.boxTwo.pictureLoader.addChild(photoLoader); trace("2Done"); break; } }

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  • iPhone code forUIImageViewControllerPickerSourceTypeCamera

    - by aman-gupta
    - (IBAction)pickAndDecode:(id) sender { UIImagePickerControllerSourceType sourceType; int i = [sender tag]; switch (i) { case 0: sourceType = UIImagePickerControllerSourceTypeCamera; break; case 1: sourceType = UIImagePickerControllerSourceTypeSavedPhotosAlbum; break; case 2: sourceType = UIImagePickerControllerSourceTypePhotoLibrary; break; default: sourceType = UIImagePickerControllerSourceTypeSavedPhotosAlbum; } [self pickAndDecodeFromSource:sourceType]; } - (void) updateToolbar { self.cameraBarItem.enabled = [UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypeCamera]; self.savedPhotosBarItem.enabled = [UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypeSavedPhotosAlbum]; self.libraryBarItem.enabled = [UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypePhotoLibrary]; self.archiveBarItem.enabled = true; self.actionBarItem.enabled = (self.result != nil) && ([self.result actions] != nil) && ([self.result actions].count > 0); } - (void)pickAndDecodeFromSource:(UIImagePickerControllerSourceType) sourceType { [self reset]; // Create the Image Picker if ([UIImagePickerController isSourceTypeAvailable:sourceType]) { UIImagePickerController* picker = [[UIImagePickerController alloc] init]; picker.sourceType = sourceType; picker.delegate = self; picker.allowsImageEditing = YES; // [[NSUserDefaults standardUserDefaults] boolForKey:@"allowEditing"]; // Picker is displayed asynchronously. [self presentModalViewController:picker animated:YES]; } else { NSLog(@"Attempted to pick an image with illegal source type '%d'", sourceType); } } Where I Put this line in my above codes; [picker setShowsCameraControls:FALSE]; please help me so that i can change the real view of iPhone camera according to my view which i have designed

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  • this is my first time asking here, I wanted to create a linked list while sorting it thanks

    - by user2738718
    package practise; public class Node { // node contains data and next public int data; public Node next; //constructor public Node (int data, Node next){ this.data = data; this.next = next; } //list insert method public void insert(Node list, int s){ //case 1 if only one element in the list if(list.next == null && list.data > s) { Node T = new Node(s,list); } else if(list.next == null && list.data < s) { Node T = new Node(s,null); list.next = T; } //case 2 if more than 1 element in the list // 3 elements present I set prev to null and curr to list then performed while loop if(list.next.next != null) { Node curr = list; Node prev = null; while(curr != null) { prev = curr; curr = curr.next; if(curr.data > s && prev.data < s){ Node T = new Node(s,curr); prev.next = T; } } // case 3 at the end checks for the data if(prev.data < s){ Node T = new Node(s,null); prev.next = T; } } } } // this is a hw problem, i created the insert method so i can check and place it in the correct order so my list is sorted This is how far I got, please correct me if I am wrong, I keep inserting node in the main method, Node root = new Node(); and root.insert() to add.

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  • Security-Active Application in background-Does it store image of current screen

    - by user1509593
    Is this a probable security flaw. A user in public (lets say Starbucks) tries to log in to iOS application. He enters user id and password [Password is hidden using xxxxxxxx (not exposed)] and a call comes in or he presses home and the application goes to background. a) Does iOS store an image of current screen b) A malicious hacker with intent takes control of the device. Can he read the password ? Do we have to clear out sensitive information while going to background

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  • Finding What You Need in R: function arguments/parameters from outside the function's package

    - by doug
    Often in R, there are a dozen functions scattered across as many packages--all of which have the same purpose but of course differ in accuracy, performance, theoretical rigor, and so on. How do you gather all of these in one place before you start your task? So for instance: the generic plot function. Setting secondary ticks is much easier (IMHO) using a function outside of the base package, minor.tick(nx=n, ny=n, tick.ratio=n), found in Hmisc. Of course, that doesn't show up in plot's docstring. Likewise, the data-input arguments to 'plot' can be supplied by an object returned from the function 'hexbin', again, from a library outside of the base installation (where 'plot' resides). What would be great obviously is a programmatic way to gather these function arguments from the various libraries and put them in a single namespace. edit: (trying to re-state my example just above more clearly:) the arguments to plot supplied in the base package for, e.g., setting the axis tick frequency are xaxp/yaxp; however, one can also set a/t/f via a function outside of the base package, again, as in the minor.tick function from the Hmisc package--but you wouldn't know that just from looking at the plot method signature. Is there a meta function in R for this? So far, as i come across them, i've been manually gathering them in a TextMate 'snippet' (along with the attendant library imports). This isn't that difficult or time consuming, but i can only update my snippet as i find out about these additional arguments/parameters. Is there a canonical R way to do this, or at least an easier way? Just in case that wasn't clear, i am not talking about the case where multiple packages provide functions directed to the same statistic or view (e.g., 'boxplot' in the base package; 'boxplot.matrix' in gplots; and 'bplots' in Rlab). What i am talking is the case in which the function name is the same across two or more packages.

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  • JSF redirect doesn't work

    - by user319331
    I have a problem with redirecting a page in my JSF application. My navigation rule look like this : <navigation-rule> <from-view-id>/index.xhtml</from-view-id> <navigation-case> <from-action>#{registerBean.registerUser}</from-action> <from-outcome>success</from-outcome> <to-view-id>/confirmation.xhtml</to-view-id> <redirect/> </navigation-case> </navigation-rule> In my case the redirect tag doesn't work, the URL remains unchanged, and when I refresh the page the registerUser action is executed again. I just have no idea what I'm doing wrong; I'm not very experienced with JSF. Can anyone please tell why the redirect tag doesn't work? Thanks. (I'm using JSF 2.0 and NetBeans IDE)

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  • How to compress/decompress a long query string in PHP?

    - by jodeci
    I doubt if this is encryption but I can't find a better phrase. I need to pass a long query string like this: http://test.com/test.php?key=[some_very_loooooooooooooooooooooooong_query_string] The query string contains NO sensitive information so I'm not really concerned about security in this case. It's just...well, too long and ugly. Is there a library function that can let me encode/encrypt/compress the query string into something similar to the result of a md5() (similar as in, always a 32 character string), but decode/decrypt/decompress-able?

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  • parse.json of authenticated play request

    - by niklassaers
    I've set up authentication in my application like this, always allow when a username is supplied and the API-key is 123: object Auth { def IsAuthenticated(block: => String => Request[AnyContent] => Result) = { Security.Authenticated(RetrieveUser, HandleUnauthorized) { user => Action { request => block(user)(request) } } } def RetrieveUser(request: RequestHeader) = { val auth = new String(base64Decode(request.headers.get("AUTHORIZATION").get.replaceFirst("Basic", ""))) val split = auth.split(":") val user = split(0) val pass = split(1) Option(user) } def HandleUnauthorized(request: RequestHeader) = { Results.Forbidden } def APIKey(apiKey: String)(f: => String => Request[AnyContent] => Result) = IsAuthenticated { user => request => if(apiKey == "123") f(user)(request) else Results.Forbidden } } I want then to define a method in my controller (testOut in this case) that uses the request as application/json only. Now, before I added authentication, I'd say "def testOut = Action(parse.json) {...}", but now that I'm using authentication, how can I add parse.json in to the mix and make this work? def testOut = Auth.APIKey("123") { username => implicit request => var props:Map[String, JsValue] = Map[String, JsValue]() request.body match { case JsObject(fields) => { props = fields.toMap } case _ => {} // Ok("received something else: " + request.body + '\n') } if(!props.contains("UUID")) props.+("UUID" -> UniqueIdGenerator.uuid) if (!props.contains("entity")) props.+("entity" -> "unset") props.+("username" -> username) Ok(props.toString) } As a bonus question, why is only UUID added to the props map, not entity and username? Sorry about the noob factor, I'm trying to learn Scala and Play at the same time. :-) Cheers Nik

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  • Is the C++ compiler optimizer allowed to break my destructor ability to be called multiple times?

    - by sharptooth
    We once had an interview with a very experienced C++ developer who couldn't answer the following question: is it necessary to call the base class destructor from the derived class destructor in C++? Obviously the answer is no, C++ will call the base class destructor automagically anyway. But what if we attempt to do the call? As I see it the result will depend on whether the base class destructor can be called twice without invoking erroneous behavior. For example in this case: class BaseSafe { public: ~BaseSafe() { } private: int data; }; class DerivedSafe { public: ~DerivedSafe() { BaseSafe::~BaseSafe(); } }; everything will be fine - the BaseSafe destructor can be called twice safely and the program will run allright. But in this case: class BaseUnsafe { public: BaseUnsafe() { buffer = new char[100]; } ~BaseUnsafe () { delete[] buffer; } private: char* buffer; }; class DerivedUnsafe { public: ~DerivedUnsafe () { BaseUnsafe::~BaseUnsafe(); } }; the explicic call will run fine, but then the implicit (automagic) call to the destructor will trigger double-delete and undefined behavior. Looks like it is easy to avoid the UB in the second case. Just set buffer to null pointer after delete[]. But will this help? I mean the destructor is expected to only be run once on a fully constructed object, so the optimizer could decide that setting buffer to null pointer makes no sense and eliminate that code exposing the program to double-delete. Is the compiler allowed to do that?

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  • Testing When Correctness is Poorly Defined?

    - by dsimcha
    I generally try to use unit tests for any code that has easily defined correct behavior given some reasonably small, well-defined set of inputs. This works quite well for catching bugs, and I do it all the time in my personal library of generic functions. However, a lot of the code I write is data mining code that basically looks for significant patterns in large datasets. Correct behavior in this case is often not well defined and depends on a lot of different inputs in ways that are not easy for a human to predict (i.e. the math can't reasonably be done by hand, which is why I'm using a computer to solve the problem in the first place). These inputs can be very complex, to the point where coming up with a reasonable test case is near impossible. Identifying the edge cases that are worth testing is extremely difficult. Sometimes the algorithm isn't even deterministic. Usually, I do the best I can by using asserts for sanity checks and creating a small toy test case with a known pattern and informally seeing if the answer at least "looks reasonable", without it necessarily being objectively correct. Is there any better way to test these kinds of cases?

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  • How do I structure my tests with Python unittest module?

    - by persepolis
    I'm trying to build a test framework for automated webtesting in selenium and unittest, and I want to structure my tests into distinct scripts. So I've organised it as following: base.py - This will contain, for now, the base selenium test case class for setting up a session. import unittest from selenium import webdriver # Base Selenium Test class from which all test cases inherit. class BaseSeleniumTest(unittest.TestCase): def setUp(self): self.browser = webdriver.Firefox() def tearDown(self): self.browser.close() main.py - I want this to be the overall test suite from which all the individual tests are run. import unittest import test_example if __name__ == "__main__": SeTestSuite = test_example.TitleSpelling() unittest.TextTestRunner(verbosity=2).run(SeTestSuite) test_example.py - An example test case, it might be nice to make these run on their own too. from base import BaseSeleniumTest # Test the spelling of the title class TitleSpelling(BaseSeleniumTest): def test_a(self): self.assertTrue(False) def test_b(self): self.assertTrue(True) The problem is that when I run main.py I get the following error: Traceback (most recent call last): File "H:\Python\testframework\main.py", line 5, in <module> SeTestSuite = test_example.TitleSpelling() File "C:\Python27\lib\unittest\case.py", line 191, in __init__ (self.__class__, methodName)) ValueError: no such test method in <class 'test_example.TitleSpelling'>: runTest I suspect this is due to the very special way in which unittest runs and I must have missed a trick on how the docs expect me to structure my tests. Any pointers?

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  • "No keyboard for id 0"?

    - by Mellon
    I am new in Android app. development, now I have encountered a strange problem with the Menu button. Here is the thing: I have two activities, "ActivityOne" and "ActivityTwo", where "ActivityTwo" is the child Activity of "ActivityOne". In both activity, I have defined the menu button options like following: @Override public boolean onCreateOptionsMenu(Menu menu) { super.onCreateOptionsMenu(menu); MenuItem insertMenuItem = menu.add(0, INSERT_ID, 0, R.string.menu_insert); insertMenuItem.setIcon(R.drawable.ic_menu_add); MenuItem settingMenuItem = menu.add(0, SETTING_ID, 0, R.string.menu_setting); settingMenuItem.setIcon(R.drawable.ic_menu_settings); MenuItem aboutMenuItem = menu.add(0, ABOUT_ID, 0, R.string.menu_about); aboutMenuItem.setIcon(R.drawable.ic_menu_about); logPrinter.println("creating menu options..."); return true; } @Override public boolean onMenuItemSelected(int featureId, MenuItem item) { switch(item.getItemId()) { case INSERT_ID: doInsert(); return true; case SETTING_ID: return true; case ABOUT_ID: showAbout(); return true; } return super.onMenuItemSelected(featureId, item); } In "ActivityOne", when I click the physical Menu button, there is no menu options pop up from screen bottom, when I checked the LogCat console, there are two warning messages, which are "No keyboard for id 0" and "Using default keyMap:/system/usr/keychars/qwerty.kcm.bin" . BUT, in "ActivityTwo", the menu button works fine, it shows me those menu options I defined. Why the menu button does not work in "ActivityOne" ?? What does the warning msg mean???

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  • Mixing menuItem.setIntent with onOptionsItemSelected doesn't work

    - by superjos
    While extending a sample Android activity that fires some other activities from its menu, I came to have some menu items handled within onOptionsItemSelected, and some menu items (that just fired intents) handled by calling setIntent within onCreateOptionsMenu. Basically something like: @Override public boolean onCreateOptionsMenu(Menu menu) { super.onCreateOptionsMenu(menu); menu.add(0, MENU_ID_1, Menu.NONE, R.string.menu_text_1); menu.add(0, MENU_ID_2, Menu.NONE, R.string.menu_text_2); menu.add(0, MENU_ID_3, Menu.NONE, R.string.menu_text_3). setIntent(new Intent(this, MyActivity_3.class)); return true; } @Override public boolean onOptionsItemSelected(MenuItem item) { super.onOptionsItemSelected(item); switch (item.getItemId()) { case (MENU_ID_1): // Process menu command 1 ... return true; case (MENU_ID_2): // Process menu command 2 ... // E.g. also fire Intent for MyActivity_2 return true; default: return false; } } Apparently, in this situation the Intent set on MENU_ID_3 is never fired, or anyway the related activity is never started. Android javadoc at some point goes like <<[if you set an intent on a menu item] and nothing else handles the item, then the default behavior will be to [start the activity with the intent]. What does it actually mean "and nothing else handles the item"? Is it enough to return false from onOptionsItemSelected? I also tried not to call super.onOptionsItemSelected(item) at the beginning and only invoke it in the default switch case, but I had same results. Does anyone have any suggestion? Does Android allow to mix the two type of handling? Thanks for your time everyone.

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  • How should I return different types in a method based on the value of a string in Java?

    - by Siracuse
    I'm new to Java and I have come to having the following problem: I have created several classes which all implement the interface "Parser". I have a JavaParser, PythonParser, CParser and finally a TextParser. I'm trying to write a method so it will take either a File or a String (representing a filename) and return the appropriate parser given the extension of the file. Here is some psuedo-code of what I'm basically attempting to do: public Parser getParser(String filename) { String extension = filename.substring(filename.lastIndexOf(".")); switch(extension) { case "py": return new PythonParser(); case "java": return new JavaParser(); case "c": return new CParser(); default: return new TextParser(); } } In general, is this the right way to handle this situation? Also, how should I handle the fact that Java doesn't allow switching on strings? Should I use the .hashcode() value of the strings? I feel like there is some design pattern or something for handling this but it eludes me. Is this how you would do it?

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  • jQuery ajax returns

    - by Tom
    I think this will be some obvious problem, but I cannot figure it out. I hope someone can help me. So I have a slider with 3 slides - Intro, Question, Submit Now I want to make sure that if the question is answered wrong people cannot slide to Submit. The function to move slide is like this: function changeSlide(slide){ // In case current slide is question check the answer if (jQuery('.modalSteps li.current',base).hasClass('questionStep')){ checkAnswer(jQuery('input[name="question_id"]',base).val(), jQuery('input[name="answer"]:checked',base).val()); } jQuery('.modalSteps li.current',base).fadeOut('fast',function(){ jQuery(this).removeClass('current'); jQuery(slide).fadeIn('fast',function(){ jQuery(slide).addClass('current'); }); }); // In case the new slide is question, load the question if (jQuery(slide).hasClass('questionStep')){ var country = jQuery('input[name="country"]:checked',base).val(); loadQuestion(country); } } Now as you can see on first lines, I am calling function checkAnswer, which takes id of question and id of answer and pass it to the AJAX call. function checkAnswer(question, answer){ jQuery.ajax({ url: window.base_url+'ajax/check_answer/'+question+'/'+answer+'/', success: function(data){ if (!data.success){ jQuery('.question',base).html(data.message); } } }); } The problem i am having is that I cannot say if(checkAnswer(...)){} Because of Ajax it always returns false or undefined. What I need is something like this: function changeSlide(slide){ // In case current slide is question check the answer if (jQuery('.modalSteps li.current',base).hasClass('questionStep')){ if (!checkAnswer(jQuery('input[name="question_id"]',base).val(), jQuery('input[name="answer"]:checked',base).val())){ return false; } } ... So it will prevent the slide from moving on. Now when Im thinking about it, I will probably have slide like "Wrong answer" so I could just move the slide there, but I would like to see the first solution anyway. Thank you for tips

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  • Need Help with .NET OpenId HttpHandler

    - by Mark E
    I'm trying to use a single HTTPHandler to authenticate a user's open id and receive a claimresponse. The initial authentication works, but the claimresponse does not. The error I receive is "This webpage has a redirect loop." What am I doing wrong? public class OpenIdLogin : IHttpHandler { private HttpContext _context = null; public void ProcessRequest(HttpContext context) { _context = context; var openid = new OpenIdRelyingParty(); var response = openid.GetResponse(); if (response == null) { // Stage 2: user submitting Identifier openid.CreateRequest(context.Request.Form["openid_identifier"]).RedirectToProvider(); } else { // Stage 3: OpenID Provider sending assertion response switch (response.Status) { case AuthenticationStatus.Authenticated: //FormsAuthentication.RedirectFromLoginPage(response.ClaimedIdentifier, false); string identifier = response.ClaimedIdentifier; //****** TODO only proceed if we don't have the user's extended info in the database ************** ClaimsResponse claim = response.GetExtension<ClaimsResponse>(); if (claim == null) { //IAuthenticationRequest req = openid.CreateRequest(identifier); IAuthenticationRequest req = openid.CreateRequest(Identifier.Parse(identifier)); var fields = new ClaimsRequest(); fields.Email = DemandLevel.Request; req.AddExtension(fields); req.RedirectingResponse.Send(); //Is this correct? } else { context.Response.ContentType = "text/plain"; context.Response.Write(claim.Email); //claim.FullName; } break; case AuthenticationStatus.Canceled: //TODO break; case AuthenticationStatus.Failed: //TODO break; } } }

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  • Give the mount point of a path

    - by Charles Stewart
    The following, very non-robust shell code will give the mount point of $path: (for i in $(df|cut -c 63-99); do case $path in $i*) echo $i;; esac; done) | tail -n 1 Is there a better way to do this? Postscript This script is really awful, but has the redeeming quality that it Works On My Systems. Note that several mount points may be prefixes of $path. Examples On a Linux system: cas@txtproof:~$ path=/sys/block/hda1 cas@txtproof:~$ for i in $(df -a|cut -c 57-99); do case $path in $i*) echo $i;; esac; done| tail -1 /sys On a Mac osx system cas local$ path=/dev/fd/0 cas local$ for i in $(df -a|cut -c 63-99); do case $path in $i*) echo $i;; esac; done| tail -1 /dev Note the need to vary cut's parameters, because of the way df's output differs: indeed, awk is better. Answer It looks like munging tabular output is the only way within the shell, but df /dev/fd/impossible | tail -1 | awk '{ print $NF}' is a big improvement on what I had. Note two differences in semantics: firstly, df $path insists that $path names an existing file, the script I had above doesn't care; secondly, there are no worries about dereferncing symlinks. It's not difficult to write Python code to do the job.

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  • ListView setOnItemClickListener in ListFragment not working

    - by Siddarth Kaki
    I am developing an app that uses ActionBar tabs to display a list of options through ListFragment. The list (and ListFragment) display without a problem, but the ListView's setOnItemClickListener doesn't seems to work, as nothing happens when an item in the list is clicked. Here's the code for the ListFragment class: package XXX.XXX; public class AboutFrag extends SherlockListFragment { @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { View view = inflater.inflate(R.layout.aboutfrag, container, false); ListView lv = (ListView) view.findViewById(android.R.id.list); String[] items = new String[] {"About 1", "About 2", "About 3"}; lv.setAdapter(new ArrayAdapter<String>(getActivity(), R.layout.list_item, items)); lv.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { switch (position) { case 0: Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://google.com")); startActivityForResult(browserIntent, 0); break; case 1: Intent browserIntent2 = new Intent(Intent.ACTION_VIEW, Uri.parse("http://wikipedia.org")); startActivityForResult(browserIntent2, 0); break; case 2: Intent browserIntent3 = new Intent(Intent.ACTION_VIEW, Uri.parse("http:/android.com"); startActivityForResult(browserIntent3, 0); break; } } }); return view; } } I'm assuming it does not work because the class returns the view object, so the FragmentActivity can't run the listener code, so does anyone know how to make this work? By the way, I am using ActionBarSherlock. Thanks in advance!!!

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  • Prob comparing pointers and integer in C

    - by Dimitri
    Hi I have a problem with this code. When i am using this function I have no warnings. : void handler(int sig){ switch(sig) { case SIGINT : { click++; fprintf(stdout,"SIGINT recu\n"); if( click == N){ exit(0); } } case SIGALRM : fprintf(stdout,"SIGALRM received\n"); exit(0); case SIGTERM: fprintf(stdout,"SIGTERM received\n"); exit(0); } } But when i rewrite the function with this new version, I have a " comparison between pointer and integer" warning on the if statement: void handler( int sig){ printf("Signal recu\n"); if( signal == SIGINT){ click++; fprintf(stdout,"SIGINT received; Click = %d\n",click); if(click == N){ fprintf(stdout,"Exiting with SIGINT\n"); exit(0); } } else if(signal == SIGALRM){ fprintf(stdout,"SIGALRM received\n"); exit(0); } else if(signal == SIGTERM){ fprintf(stdout,"SIGTERM received\n"); exit(0); } Can someone tell me where is the prob?

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  • Android game logic problem

    - by semajhan
    I'm currently creating a game and have a problem which I think I know why it is occurring but not entirely sure and even if I knew, don't know how to solve. I have a 2D array 10 x 10 and have a "player" class that takes up a tile. Now, I have created 2 instances of the player and move them around via swiping. Around the edges I have put "walls" that the player cannot walk through and everything works fine, until I remove a wall. Once I remove a wall and move the character/player to the edge of the screen, the player cannot go any further. The problem occurs here, where the second instance of the player is not at the edge of the screen but say 2 tiles from the first instance of "player" who is at the edge. If I try moving them further into the direction of the edge, I understand that the first instance of player wouldn't move or do anything but the second instance of player should still move, but it won't. This is the code that executed when the user swipes: if (player.getArrayX() - 1 != player2.getArrayX()) { player.moveLeft(); } else if (player.getArrayX() - 1 == player2.getArrayX() && player.getArrayY() != player2.getArrayY()) { player.moveLeft(); } if (player2.getArrayX() - 1 != player.getArrayX()) { player2.moveLeft(); } else if (player2.getArrayX() - 1 == player.getArrayX() && player2.getArrayY() != player.getArrayY()) { player2.moveLeft(); } In the player class I have: public void moveLeft() { if (alive) { switch (levelMaster.getLevel1(getArrayX() - 1, getArrayY())) { case 0: break; case 1: subX(); // basically moves player left setArrayX(getArrayX() - 1); // shifts x coord of player 1 within tilemap Log.d("semajhan", "x: " + getArrayX()); break; case 9: subX(); setArrayX(getArrayX() - 1); setAlive(false); break; } } } Any help on the matter or further insight would be greatly appreciated, thanks.

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  • http post request with cross-origin in javascript

    - by Calamarico
    i have a problem with a http post call in firefox. I know that when there are a cross origin, firefox first do a OPTIONS before the POST to know the access-control-allow headers. With this code i dont have any problem: Net.requestSpeech.prototype.post = function(url, data) { if(this.xhr != null) { this.xhr.open("POST", url); this.xhr.onreadystatechange = Net.requestSpeech.eventFunction; this.xhr.setRequestHeader("Content-Type", "application/json; charset=utf-8"); this.xhr.send(data); } } I test this code with a simple html that invokes this function. Everything is ok and i have the response of the OPTIONS and POST, and i process the response. But, i'm trying to integrate this code with an existen application with uses jquery (i dont know if this is a problem), when the send(data) executes in this case, the browser (firefox) do the same, first do a OPTION request, but in this case dont receive the response of the server and puts this message in console: [18:48:13.529] OPTIONS http://localhost:8111/ [undefined 31ms] Undefined... the undefined is because dont receive the response, but the code is the same, i dont know why in this case the option dont receive the response, someone have an idea? i debug my server app and the OPTIONS arrive ok to the server, but it seems like the browser dont wait to the response. edit more later: ok i think that the problem is when i run with a simple html with a SCRIPT tag that invokes the method who do the request run ok, but in this app that dont receive the response, i have a form that do a onsubmit event, i think that the submit event returns very fast and the browser dont have time to get the OPTIONS request. edit more later later: WTF, i resolve the problem make the POST request to sync: this.xhr.open("POST", url, false); The submit reponse very quickly and can't wait to the OPTION response of the browser, any idea to this?

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  • Writing functions of tuples conveniently in Scala

    - by Alexey Romanov
    Quite a few functions on Map take a function on a key-value tuple as the argument. E.g. def foreach(f: ((A, B)) ? Unit): Unit. So I looked for a short way to write an argument to foreach: > val map = Map(1 -> 2, 3 -> 4) map: scala.collection.immutable.Map[Int,Int] = Map(1 -> 2, 3 -> 4) > map.foreach((k, v) => println(k)) error: wrong number of parameters; expected = 1 map.foreach((k, v) => println(k)) ^ > map.foreach({(k, v) => println(k)}) error: wrong number of parameters; expected = 1 map.foreach({(k, v) => println(k)}) ^ > map.foreach(case (k, v) => println(k)) error: illegal start of simple expression map.foreach(case (k, v) => println(k)) ^ I can do > map.foreach(_ match {case (k, v) => println(k)}) 1 3 Any better alternatives?

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