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  • Using a backwards relation (i.e FOO_set) for ModelChoiceField in Django

    - by Bwmat
    I have a model called Movie, which has a ManyToManyField called director to a model called Person, and I'm trying to create a form with ModelChoiceField like so: class MovieSearchForm(forms.Form): producer = forms.ModelChoiceField(label='Produced by', queryset=movies.models.Person.producer_set, required=False) but this seems to be failing to compile (I'm getting a ViewDoesNotExist exception for the view that uses the form, but it goes away if I just replace the queryset with all the person objects), I'm guessing because '.producer_set' is being evaluated too 'early'. How can I get this work? here are the relevant parts of the movie/person classes: class Person(models.Model): name = models.CharField(max_length=100) class Movie(models.Model): ... producer = models.ForeignKey(Person, related_name="producers") director = models.ForeignKey(Person, related_name="directors") What I'm trying to do is get ever Person who is used in the producer field of some Movie.

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  • How to disable translations during unit tests in django?

    - by Denilson Sá
    I'm using Django Internationalization tools to translate some strings from my application. The code looks like this: from django.utils.translation import ugettext as _ def my_view(request): output = _("Welcome to my site.") return HttpResponse(output) Then, I'm writing unit tests using the Django test client. These tests make a request to the view and compare the returned contents. How can I disable the translations while running the unit tests? I'm aiming to do this: class FoobarTestCase(unittest.TestCase): def setUp(self): # Do something here to disable the string translation. But what? # I've already tried this, but it didn't work: django.utils.translation.deactivate_all() def testFoobar(self): c = Client() response = c.get("/foobar") # I want to compare to the original string without translations. self.assertEquals(response.content.strip(), "Welcome to my site.")

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  • Django | capture sub domain as a string

    - by MMRUser
    How do I capture a part of sub-domain name and get that name as a string in my views through a request. ex: user.domain.com developer.domain.com I want to capture the user part of this domain name through a request (lets say when the first time user hits the page). Thanks.

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  • Is a many-to-many relationship with extra fields the right tool for my job?

    - by whichhand
    Previously had a go at asking a more specific version of this question, but had trouble articulating what my question was. On reflection that made me doubt if my chosen solution was correct for the problem, so this time I will explain the problem and ask if a) I am on the right track and b) if there is a way around my current brick wall. I am currently building a web interface to enable an existing database to be interrogated by (a small number of) users. Sticking with the analogy from the docs, I have models that look something like this: class Musician(models.Model): first_name = models.CharField(max_length=50) last_name = models.CharField(max_length=50) dob = models.DateField() class Album(models.Model): artist = models.ForeignKey(Musician) name = models.CharField(max_length=100) class Instrument(models.Model): artist = models.ForeignKey(Musician) name = models.CharField(max_length=100) Where I have one central table (Musician) and several tables of associated data that are related by either ForeignKey or OneToOneFields. Users interact with the database by creating filtering criteria to select a subset of Musicians based on data the data on the main or related tables. Likewise, the users can then select what piece of data is used to rank results that are presented to them. The results are then viewed initially as a 2 dimensional table with a single row per Musician with selected data fields (or aggregates) in each column. To give you some idea of scale, the database has ~5,000 Musicians with around 20 fields of related data. Up to here is fine and I have a working implementation. However, it is important that I have the ability for a given user to upload there own annotation data sets (more than one) and then filter and order on these in the same way they can with the existing data. The way I had tried to do this was to add the models: class UserDataSets(models.Model): user = models.ForeignKey(User) name = models.CharField(max_length=100) description = models.CharField(max_length=64) results = models.ManyToManyField(Musician, through='UserData') class UserData(models.Model): artist = models.ForeignKey(Musician) dataset = models.ForeignKey(UserDataSets) score = models.IntegerField() class Meta: unique_together = (("artist", "dataset"),) I have a simple upload mechanism enabling users to upload a data set file that consists of 1 to 1 relationship between a Musician and their "score". Within a given user dataset each artist will be unique, but different datasets are independent from each other and will often contain entries for the same musician. This worked fine for displaying the data, starting from a given artist I can do something like this: artist = Musician.objects.get(pk=1) dataset = UserDataSets.objects.get(pk=5) print artist.userdata_set.get(dataset=dataset.pk) However, this approach fell over when I came to implement the filtering and ordering of query set of musicians based on the data contained in a single user data set. For example, I could easily order the query set based on all of the data in the UserData table like this: artists = Musician.objects.all().order_by(userdata__score) But that does not help me order by the results of a given single user dataset. Likewise I need to be able to filter the query set based on the "scores" from different user data sets (eg find all musicians with a score 5 in dataset1 and < 2 in dataset2). Is there a way of doing this, or am I going about the whole thing wrong?

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  • django forms from two tables referencial integrity

    - by dana
    i have a class named cv,and a class named university, and each user that completes his cv, should choose a University he studyes at. My problem is: one student can study at one or 2 or three universities, or may be a user that is not student. I need to take this data into a form, and i use ModelForm. The data from the Cv class, and from the University class in the same form, and the user can add one or more universities, or no university. (in the same form) How should i do it? Should i use ModelForm? if i have a foreign key in the CV class, and the user is not a student (so he is at zero universities), i may get an referencial integrity error. thanks a lot

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  • How to generate a line break in Django template

    - by Iamamac
    I want to give default value to a textarea. The code is something like this: <textarea>{{userSetting.list | join:"NEWLINE"}}</textarea> where userSetting.list is a string list, each item of whom is expected to show in one line. textarea takes the content between the tags as the default value, preserving its line breaks and not interpreting any HTML tags (which means <br>,\n won't work). I have found a solution: {{userSetting.list | join:" " | wordwrap:0}} (there is no whitespace in the list). But obviously it is NOT a good one. Any help would be appreciated.

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  • django sort by manytomany relationship

    - by Marconi
    I have the following model: class Service(models.Model): ratings = models.ManyToManyField(User) Now if I wanna get all the service with ratings sorted in descending order I did something: services_list = Service.objects.filter(ratings__gt=0).distinct() services_list = list(services_list) services_list.sort(key=lambda service: service.ratings.all().count(), reverse=True) As you can see its a three step process and I don't feel right about this. Anybody who knows a better way to do this?

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  • Putting links into text in Django

    - by Dane Larsen
    I have a notifications app that generates notifications for users. The notification class has to be really general, because notifications are generated by all sorts of different things. My question is this: How do I insert links into the text of the notifications? What I tried was this: note = Notification(..., notification="""%s %s has accepted the task: <a href="/tasks/%d/">%s</a>.""" % (request.user.first_name, request.user.last_name, task.id, task.name), ...) In retrospect, it's obvious this wouldn't work. How should I go about this? Thanks in advance!

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  • Django url rewrites and passing a parameter from Javascript

    - by William T Wild
    As a bit of a followup question to my previous , I need to pass a parameter to a view. This parameter is not known until the JS executes. In my URLConf: url(r'^person/device/program/oneday/(?P<meter_id>\d+)/(?P<day_of_the_week>\w+)/$', therm_control.Get_One_Day_Of_Current_Thermostat_Schedule.as_view(), name="one-day-url"), I can pass it this URL and it works great! ( thanks to you guys). http://127.0.0.1:8000/personview/person/device/program/oneday/149778/Monday/ In My template I have this: var one_day_url = "{% url personview:one-day-url meter_id=meter_id day_of_the_week='Monday' %}"; In my javascript: $.ajax({ type: 'GET', url: one_day_url , dataType: "json", timeout: 30000, beforeSend: beforeSendCallback, success: successCallback, error: errorCallback, complete: completeCallback }); When this triggers it works fine except I dont necessarily want Monday all the time. If I change the javascript to this: var one_day_url = "{% url personview:one-day-url meter_id=meter_id %}"; and then $.ajax({ type: 'GET', url: one_day_url + '/Monday/', dataType: "json", timeout: 30000, beforeSend: beforeSendCallback, success: successCallback, error: errorCallback, complete: completeCallback }); I get the Caught NoReverseMatch while rendering error. I assume because the URLconf still wants to rewrite to include the ?P\w+) . I seems like if I change the URL conf that breaks the abailty to find the view , and if I do what I do above it gives me the NoREverseMatch error. Any guidance would be appreciated.

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  • Django: request object to template context transparancy

    - by anars
    Hi! I want to include an initialized data structure in my request object, making it accessible in the context object from my templates. What I'm doing right now is passing it manually and tiresome within all my views: render_to_response(...., ( {'menu': RequestContext(request)})) The request object contains the key,value pair which is injected using a custom context processor. While this works, I had hoped there was a more generic way of passing selected parts of the request object to the template context. I've tried passing it by generic views, but as it turns out the request object isn't instantiated when parsing the urlpatterns list.

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  • Keeping filters in Django Admin

    - by Tomo
    What I would like to achive is: I go to admin site, apply some filters to the list of objects I click and object edit, edit, edit, hit 'Save' Site takes me to the list of objects... unfiltered. I'd like to have the filter from step 1 remembered and applied. Is there an easy way to do it?

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  • django forms overwrite data when saved

    - by dana
    If a have a form, with the data from a user, let's say a CV, and i save the data from the form into a database, but i don't want that a CV from the same user to be stored in the database more than once(when edited form instance) I want it to be overwritten every time it is saved by one same user. How can i do it? thanks a lot

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Structure for Django methods that span different models

    - by Duncan
    I have two models (say A and B) which are independent and have independent methods. I want to add some methods that operate on both models though. for example, addX() will create an object from both models A and B. What's the best way to structure code in this situation, since it doesnt make sense to have the method belong to either of the models methods. Is the standard to write a service for the kind of 'abstract' model?

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  • Downloading a csv file in django

    - by spyder
    I am trying to download a CSV file using HttpResponse to make sure that the browser treats it as an attachment. I follow the instructions provided here but my browser does not prompt a "Save As" dialog. I cannot figure out what is wrong with my function. All help is appreciated. dev savefile(request): try: myfile = request.GET['filename'] filepath = settings.MEDIA_ROOT + 'results/' destpath = os.path.join(filepath, myfile) response = HttpResponse(FileWrapper(file(destpath)), mimetype='text/csv' ) response['Content-Disposition'] = 'attachment; filename="%s"' %(myfile) return response except Exception, err: errmsg = "%s"%(err) return HttpResponse(errmsg) Happy Pat's day!

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  • django many to many validation when add()

    - by Julien
    Hi i have a Category model with parent/child self relation For primary category and sub categories : class Place(models.Model): name = models.CharField(_("name"), max_length=100) categories = models.ManyToManyField("Category", verbose_name=_("categories")) class Category(models.Model): name = models.CharField(_("name"), max_length=100) parent = models.ForeignKey('self', blank=True, null=True, related_name='child_set') i need to prevent orphans, to prevent this kind of errors (in admin web interface) c_parent = Category(name='Restaurant') c_parent.save() c_child = Category(name="Japanese restaurant", parent=c_parent) c_child.save() place1 = Place (name="Planet sushi") place1.save() place1.categories.add(c_parent) place1.categories.add(c_child) So now we have a new Place called "Planet sushi", it's a Restaurant (root category), and a Japanese Restaurant (sub category) but i want to prevent this kind of things : place2 = Place (name="Tokyofood") place2.save() place2.categories.add(c_child) because parent is not set, or is not the correct parent category where can i do form validation for the admin ? and other forms (because any user can add a new place and will have to choose correct categories for)

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  • Django - Check users messages every request

    - by Hanpan
    Hi, I want to check if a user has any new messages each time they load the page. Up until now, I have been doing this inside of my views but it's getting fairly hard to maintain since I have a fair number of views now. I assume this is the kind of thing middleware is good for, a check that will happen every single page load. What I need it to do is so: Check if the user is logged in If they are, check if they have any messages Store the result so I can reference the information in my templates Has anyone ever had to write any middleware like this? I've never used middleware before so any help would be greatly appreciated.

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  • Creating a db driven primary navigation in django?

    - by Fedor
    I find that it's pretty common most people hardcode the navigation into their templates, but I'm dealing with a pretty dynamic news site which might be better off if the primary nav was db driven. So I was thinking of having a Navigation model where each row would be a link. link_id INT primary key link_name varchar(255) url varchar(255) order INT active boolean If anyone's done something similar in the past, would you say this sort of schema is good enough? I also wanted for there to be an optional dropdown in the admin near the url field so that a user could choose a Category model's slug since category links would be common, but I'm not quite sure how that would be possible.

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