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PHP post programmatically

- by Tural Teyyuboglu

After user registration, website send activation code to email. something like that. www.domain.com/?activate=<code> I'm creating 2 variants of activation: 1.manual 2.auto Lets say we have index.php. 1.Manual method. When someone wants to activate user manually all things are obvious: User opens page www.domain.com/?activate Index.php checks with following script and includes div file (which contains activation form) if (isset($_GET['activate'])) { $page='activate'; $divfile = 'path to div.php'; } include $divfile; Then page sends form data via ajax to activation.php file. 2.Auto method. Lets say user clicked directly to www.domain.com/?activate=<code>. What I wanna do is, to check if(!empty($_GET['activate'])), if all right ... I can't figure out how to act?! Programmatically send something like POST to activation.php or what? Please help. Thx in advance

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PHP & WP: Render Certain Markup Based on True False Condition

- by rob

So, I'm working on a site where on the top of certain pages I'd like to display a static graphic and on some pages I would like to display an scrolling banner. So far I set up the condition as follows: <?php $regBanner = true; $regBannerURL = get_bloginfo('stylesheet_directory'); //grabbing WP site URL ?> and in my markup: <div id="banner"> <?php if ($regBanner) { echo "<img src='" . $regBannerURL . "/style/images/main_site/home_page/mock_banner.jpg' />"; } else { echo 'Slider!'; } ?> </div> In my else statement, where I'm echoing 'Slider!' I would like to output the markup for my slider: <div id="slider"> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/1.jpg" alt="" /> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/2.jpg" alt="" /> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/3.jpg" alt="" /> ............. </div> My question is how can I throw the div and all those images into my else echo statement? I'm having trouble escaping the quotes and my slider markup isn't rendering.

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The youtube API sometimes throws error: Call to a member function children() on a non-object

- by Anna Lica

When i launch the php script, sometime works fine, but many other times it retrieve me this errror Fatal error: Call to a member function children() on a non-object in /membri/americanhorizon/ytvideo/rilevametadatadaurlyoutube.php on line 21 This is the first part of the code // set feed URL $feedURL = 'http://gdata.youtube.com/feeds/api/videos/dZec2Lbr_r8'; // read feed into SimpleXML object $entry = simplexml_load_file($feedURL); $video = parseVideoEntry($entry); function parseVideoEntry($entry) { $obj= new stdClass; // get nodes in media: namespace for media information $media = $entry->children('http://search.yahoo.com/mrss/'); //<----this is the doomed line 21 UPDATE: solution adopted for ($i=0 ; $i< count($fileArray); $i++) { // set feed URL $feedURL = 'http://gdata.youtube.com/feeds/api/videos/'.$fileArray[$i]; // read feed into SimpleXML object $entry = simplexml_load_file($feedURL); if ( is_object($entry)) { $video = parseVideoEntry($entry); echo ($video->description."|".$video->length); echo "<br>"; } else { $i--; } } In this mode i force the script to re-check the file that caused the error

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Will php code exit after echo for ajax?

- by Steve

I am running a typical php-engined ajax webpage. I use echo to return a html string from the php code. My question is, if I have some other code after the echo, will those code get executed? Or echo behaves similar to exit, which immediately return and stop running the php code? Thanks.

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Never getting a JSON response when running server-side PHP proxy script but I do with others

- by Dohk

I'm on PHP 5.3.4 and Apache 2.2 btw So I'm using (or trying to use) Simple PHP Proxy (Simple PHP Proxy) I enter a URL at his example page at SPP Example Page and it works fine, I see the JSON response and all the headers. However, when I copy the exact URL, only changing the URL to now have localhost, I get both empty headers and no JSON. Assuming that the script on his site is the same I downloaded, could this be due to a multitude of things or a setting in Apache and/or the PHP ini? So for example: benalman.com/code/projects/php-simple-proxy/ba-simple-proxy.php?url=http://github.com/&full_headers=1&full_status=1 That will get me a ton of info back Now changing to localhost http://localhost/ba-simple-proxy.php?url=http://github.com/&full_headers=1&full_status=1 {"headers":[],"status":{"url":"https:\/\/github.com\/","content_type":"text\/html","http_code":301,"header_size":194,"request_size":182,"filetime":-1,"ssl_verify_result":0,"redirect_count":1,"total_time":0.094,"namelookup_time":0,"connect_time":0.047,"pretransfer_time":0,"size_upload":0,"size_download":185,"speed_download":1968,"speed_upload":0,"download_content_length":185,"upload_content_length":0,"starttransfer_time":0,"redirect_time":0.047,"certinfo":[]},"contents":null} I even went basic and just used some curl and of course, empty objects being returned other than false for my content and the url I set in my JSON. Any help is deeply appreciated or any ideas.

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Getting search results from Twitter in php

- by Mark Mayo

I'm attempting to put together a little mashup with some twitter APIs. However, the whole area is new to me (I'm more of an embedded developer dabbling). And frustratingly, every tutorial I am trying in Php is either out of date, not doing what it claims to do, it or is broken. Essentially, I just want a nice bit of example code - say, an HTML file, a connection.js for the JQuery magic, and a php file - 'getsearch' which contains the relevant Curl calls to the API to just return the results for a given search term. Followed the tutorial to the letter at http://www.reynoldsftw.com/2009/02/using-jquery-php-ajax-with-the-twitter-api/ and even downloaded the guy's code and chucked it on my webserver, but it just seems to sit there. I'm relatively competent at php and html, but it's the Curl and the JQuery side of things which is new to me, and would appreciate any thoughts, links, or code suggestions. I've attempted reading the API - but even that seems sparse - and several links are broken to their own tutorials, so that's put me off a bit for now.

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Druapl & Regular PHP Integration

- by user333128

I'm building a new website which has one core application and many content pages. Content pages are mostly dynamic and I require a way to manage this dynamic content on a regular basis. The core application's main functionality is a 3 step process or reading user data (input page), reading data from MySQL (product page) and submitting an application to an email address (application page). Ideally I would like to build the core application in regular PHP and leverage Drupal for its content management capabilities. Can Drupal and regular PHP be integrated as I suggest easily? My feeling is that coding the core application as a Drupal module(s) will add layers of complexity that could be difficult to code from the outset and maintain later on as the system matures - so I would really like to just use regular PHP. Let me explain where dynamic content (managed by the CMS) intersects with the core application: Dynamic content such as FAQ data is used both on the 'normal' help pages and also within a mini-feed displayed within core application pages down a right hand side column. In this column, 3 random questions are pulled from the database and displayed as a feed. When users click on FAQ question they are not taken away from the core application product page but are instead shown data in a pop-up window displaying the question and answer. In addition, users can browse other questions and answers through a simple navigation menu within this popup. There are 3 such like feeds as I describe above that I require on the core application product page. So, what is the ideal solution here in terms of 'keeping things simple' for both the management of dynamic content and the ease of coding the core application? Can 'regular PHP' and Drupal co-exist 'peacefully'? If so, how is this technically possible? Because there is some content managed by Drupal contained within core application pages, can the core application still be coded in regular PHP? Any advice / suggestions? Thank you! Jim.

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Dedicated podcast for PHP beginners

- by justjoe

I'm looking for any PHP/programming podcast episodes which specifically talk about PHP classes and objects. Maybe this is too specific but any reference is ok. BTW, are there any dedicated podcasts for PHP beginners?

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php database image show problem

- by Termedi

here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

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Enable GD support in PHP

- by Don

Hi, I'm trying to install pixelpost on an Apache server on windows. The installer is failing because: Pixelpost will not run if your PHP installation is not compiled with the GD graphics library. I've added the following line to php.ini extension=php_gd2.dll But I still get the same error message. When I run phpinfo() I don't see any reference to GD, so I guess it really isn't installed. I searched for php_gd2.dll and it's in the ext subfolder of my PHP root dir. I know nothing about PHP, so be gentle with me. Thanks, Don

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Multiple XML/XSLT files in PHP, transform one with XSLT and add others but process it first with PHP

- by ipalaus

I am processing XML files transformations with XSLT in PHP correctly. Actually I use this code: $xml = new DOMDocument; $xml->LoadXML($xml_contents); $xsl = new DOMDocument; $xsl->load($xsl_file); $proc = new XSLTProcesoor; $proc->importStyleSheet($xsl); echo $proc->transformToXml($xml); $xml_contents is the XML processed with PHP, this is done by including the XML file first and then assigning $xml_contents = ob_get_contents(); ob_end_clean();. This forces to process the PHP code on the XML, and it works perfectly. My problem is that I use more than one XML file and this XML files has PHP code on it that need to be processed AND have a XSLT file associated to process the data. Actually I'm including this files in XSLT with the next code:  <xsl:param name="menu" select="document('menu.xml')" />  <xsl:include href="menu.xsl" />  <xsl:apply-templates select="$menu/menu" /> My questiion is how I can handle this. I need to add mutiple XML(+XSLT) files to my first XML file that will containt PHP so it needs to be processed. Thank you in advance!

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one php processing file vs many form

- by klox

how to manage a process php file?? i want every form which connected to database just use one php file..how to separate every command inside that php file??can i do that?

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PHP: Object Oriented Programming -> Operator

- by oman9589

So I've been reading through the book PHP Solutions, Dynamic Web Design Made Easy by David Powers. I read through the short section on Object Oriented PHP, and I am having a hard time grasping the idea of the - operator. Can anyone try to give me a solid explanation on the - operator in OOP PHP? Example: $westcost = new DateTimeZone('America/Los_Angeles'); $now->setTimezone($westcoast); Also,a more general example: $someObject->propertyName Thanks

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Socket php server not showing messages sent from android client

- by Mj1992

Hi I am a newbie in these kind of stuff but here's what i want to do. I am trying to implement a chat application in which users will send their queries from the website and as soon as the messages are sent by the website users.It will appear in the android mobile application of the site owner who will answer their queries .In short I wanna implement a live chat. Now right now I am just simply trying to send messages from android app to php server. But when I run my php script from dreamweaver in chrome the browser keeps on loading and doesn't shows any output when I send message from the client. Sometimes it happened that the php script showed some outputs which I have sent from the android(client).But i don't know when it works and when it does not. So I want to show those messages in the php script as soon as I send those messages from client and vice versa(did not implemented the vice versa for client but help will be appreciated). Here's what I've done till now. php script: <?php set_time_limit (0); $address = '127.0.0.1'; $port = 1234; $sock = socket_create(AF_INET, SOCK_STREAM, 0); socket_bind($sock, $address, $port) or die('Could not bind to address'); socket_listen($sock); $client = socket_accept($sock); $welcome = "Roll up, roll up, to the greatest show on earth!\n? "; socket_write($client, $welcome,strlen($welcome)) or die("Could not send connect string\n"); do{ $input=socket_read($client,1024,1) or die("Could not read input\n"); echo "User Says: \n\t\t\t".$input; if (trim($input) != "") { echo "Received input: $input\n"; if(trim($input)=="END") { socket_close($spawn); break; } } else{ $output = strrev($input) . "\n"; socket_write($spawn, $output . "? ", strlen (($output)+2)) or die("Could not write output\n"); echo "Sent output: " . trim($output) . "\n"; } } while(true); socket_close($sock); echo "Socket Terminated"; ?> Android Code: public class ServerClientActivity extends Activity { private Button bt; private TextView tv; private Socket socket; private String serverIpAddress = "127.0.0.1"; private static final int REDIRECTED_SERVERPORT = 1234; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); bt = (Button) findViewById(R.id.myButton); tv = (TextView) findViewById(R.id.myTextView); try { InetAddress serverAddr = InetAddress.getByName(serverIpAddress); socket = new Socket(serverAddr, REDIRECTED_SERVERPORT); } catch (UnknownHostException e1) { e1.printStackTrace(); } catch (IOException e1) { e1.printStackTrace(); } bt.setOnClickListener(new OnClickListener() { public void onClick(View v) { try { EditText et = (EditText) findViewById(R.id.EditText01); String str = et.getText().toString(); PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(socket.getOutputStream())),true); out.println(str); Log.d("Client", "Client sent message"); } catch (UnknownHostException e) { tv.setText(e.getMessage()); e.printStackTrace(); } catch (IOException e) { tv.setText(e.getMessage()); e.printStackTrace(); } catch (Exception e) { tv.setText(e.getMessage()); e.printStackTrace(); } } }); } } I've just pasted the onclick button event code for Android.Edit text is the textbox where I am going to enter my text. The ip address and port are same as in php script.

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Learning PHP - start out using a framework or no?

- by Kevin Torrent

I've noticed a lot of jobs in my area for PHP. I've never used PHP before, and figure if I can get more opportunities if I pick it up then it might be a good idea. The problem is that PHP without any framework is ugly and 99% of the time really bad code. All the tutorials and books I've seen are really lousy - it never shows any kind of good programming practice but always the quick and dirty kind of way of doing things. I'm afraid that trying to learn PHP this way will just imprint these bad practices in my head and make me waste time later trying to unlearn them. I've used C# in the past so I'm familiar with OOP and software design patterns and similar. Should I be trying to learn PHP by using one of the better known frameworks for it? I've looked at CakePHP, Symfony and the Zend Framework so far; Zend seems to be the most flexible without being too constraining like Cake and Symfony (although Symfony seemed less constraining than CakePHP which is trying too hard to be Ruby on Rails), but many tutorials for Zend I've seen assume you already know PHP and want to learn to use the framework. What would be my best opportunity for learning PHP, but learning GOOD PHP that uses real software engineering techniques instead of spaghetti code? It seems all the PHP books and resources either assume you are just using raw PHP and therefore showcase bade practices, or that you already know PHP and therefore don't even touch on parts of the language.

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how to run imagemagik commands in PHP ?

- by user345804

Hi, i am trying to bend text using imagemagik in PHP. but the commands shown in the website are not working. http://www.fmwconcepts.com/imagemagick/texteffect/index.php how can i run these scripts in PHP ? somebody please help me.. NB :-t \'SOME ARCHBOTTOM TEXT\' -s outline -e arch-bottom -d 1.0 -f Arial -p 48 -c skyblue -b white -o black -l 1 -u lightpink

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PHP Not Automatically Updating With ?reload=1

- by user32007

A friend built a ranking system on his site and I am trying to host in on mine via wordpress and godaddy. It updates for him but when I load it to my site, it works for 6 hours, but as soon as the reload is supposed to occur, it errors and I get a 500 timeout error. His page is at: jeremynoeljohnson .com/yakezieclub My page is currently at http://sweatingthebigstuff.com/yakezieclub but when you ?reload=1 it will give the error. Any idea why this might be happening? Any settings that I might need to change? Here is the top of the index.php file. I'm not sure which part of any of it is messing up. I literally uploaded the same code as him. Here's the reload part: $cachefile = "rankings.html"; $daycachefile = "rankings_history.xml"; $cachetime = (60 * 60) * 6; // every 6 hours, the cache refreshes $daycachetime = (60 * 60) * 24; // every 24 hours, the history will be written to - or whenever the page is requested after 24 hours has passed $writenewdata = false; if (!empty($_GET['reload'])) { if ($_GET['reload']== 1) { $cachetime = 1; } } if (!empty($_GET['reloadhistory'])) { if ($_GET['reloadhistory'] == 1) { $daycachetime = 1; $cachetime = 1; } } if (file_exists($daycachefile) && (time() - $daycachetime < filemtime($daycachefile))) { // Do nothing } else { $writenewdata = true; $cachetime = 1; } // Serve from the cache if it is younger than $cachetime if (file_exists($cachefile) && (time() - $cachetime < filemtime($cachefile))) { include($cachefile); echo ""; exit; } ob_start(); // start the output buffer ?

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PHP socket UDP communication

- by Ghedeon

Server works fine, but the problem is the client doesn't receive anything. server.php <?php $buf_size = 1024; $socket = stream_socket_server("udp://127.0.0.1:3127", $errno, $errstr, STREAM_SERVER_BIND); do { $str = stream_socket_recvfrom($socket, $buf_size, 0, $peer); $str = "abc"; stream_socket_sendto($socket, $str, strlen($str), 0, $peer); } while (true); ?> client.php <?php $fp = stream_socket_client("udp://127.0.0.1:3127", $errno, $errstr); if (!$fp) { echo "$errno - $errstr<br />\n"; } else { fwrite($fp, "1 2 3"); echo fread($fp, 15); fclose($fp); } ?>

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PHP OAuth Twitter

- by Sandhurst

I have created a twitter app which I am using to post tweets. The problem that I am not able to resolve is everytime I have to allow access to my application. so lets say I need to tweet three messages, so all the three times I have to allow access to my app. I just need that once user has allowed access to my app, next time he should only be asked to allow acces is that when he/she relogins. Here's my code that I am using Share content on twitter"; include 'lib/EpiCurl.php'; include 'lib/EpiOAuth.php'; include 'lib/EpiTwitter.php'; include 'lib/secret.php'; $twitterObj = new EpiTwitter($consumer_key, $consumer_secret); $oauth_token = $_GET['oauth_token']; if($oauth_token == '') { $url = $twitterObj-getAuthorizationUrl(); echo ""; echo "Sign In with Twitter"; echo ""; } else { $twitterObj-setToken($_GET['oauth_token']); $token = $twitterObj-getAccessToken(); $twitterObj-setToken($token-oauth_token, $token-oauth_token_secret); $_SESSION['ot'] = $token-oauth_token; $_SESSION['ots'] = $token-oauth_token_secret; $twitterInfo= $twitterObj-get_accountVerify_credentials(); $twitterInfo-response; $username = $twitterInfo-screen_name; $profilepic = $twitterInfo-profile_image_url; include 'update.php'; } if(isset($_POST['submit'])) { $msg = $_REQUEST['tweet']; $twitterObj-setToken($_SESSION['ot'], $_SESSION['ots']); $update_status = $twitterObj-post_statusesUpdate(array('status' = $msg)); $temp = $update_status-response; header("Location: MessageStatus.html"); exit(); } ?

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As3 & PHP URLEncoding problem!

- by Jk_

Hi everyone, I'm stuck with a stupid problem of encoding. My problem is that all my accentuated characters are displayed as weird iso characters. Example : é is displayed %E9 I send a string to my php file : XMLLoader.load(new URLRequest(online+"/query.php?Query=" + q)); XMLLoader.addEventListener(Event.COMPLETE,XMLLoaded); When I trace q, I get : "INSERT INTO hello_world (message) values('éàaà');" The GOOD query My php file look like this : <?php include("conection.php");//Conectiong to database $Q = $_GET['Query']; $query = $Q; $resultID = mysql_query($query) or die("Could not execute or probably SQL statement malformed (error): ". mysql_error()); $xml_output = "<?xml version=\"1.0\"?>\n"; // XML header $xml_output .= "<answers>\n"; $xml_output .= "<lastID id=".'"'.mysql_insert_id().'"'." />\n"; $xml_output .= "<query string=".'"'.$query.'"'." />\n"; $xml_output .= "</answers>"; echo $xml_output;//Output the XML ?> When I get back my XML into flash the $query looks like this : "INSERT INTO hello_world (message) values('%E9%E0a%E0');" And these values are then displayed into my DB which is annoying. Any help would be appreciated! Cheers. Jk_

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PHP app.yaml, new to GAE, not sure of how to setup

- by chetweewax

I have a single page website built on bootstrap 3, that I am trying to move to Google Apps Engine. I Scaffold my sites using php, and all the content is showing but not the styles and javascript. My site is basically set up as follows _/js/bootstrap.js _/js/custom.js _/fonts/glypicon ...etc _/css/bootstrap.css _/css/custom.css _/php/ .. all my php files go here ... index.php can someone help me setup my app.yaml for this? I am new to GAE, and am a little confused by this.

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PHP Download File with Include

- by arik-so

How can I use PHP's include function to include a file and then modify the headers so it forces - at least that's how it's called - browsers to download ITSELF (the PHP file). Is it possible to also modify the preset save name, in order to change the extension from *.php to something else? Thanks in advance!

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how to access remote cgi from PHP script?

- by solotim

I'm totally rookie as to PHP. I want to write a PHP script in which it can access a remote cgi via http to get some data. I know that PHP is able to fopen any remote URL and fetch file content, but I concern about the result returned by cgi script, not the script itself.

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How to run perl script with a few arguments from php

- by Cristalla

My html webpage calls php script to upload files to the server from a local computer as follows. <form enctype="multipart/form-data" action="upload.php" method="POST"> <p><b><h3> <font color="#003366"> (1) Upload your reading text file. </font> </h3> </b> </p> <INPUT type="file" name="uploaded" size="50" > <br/> <input type="submit" name="files" value="upload"> </form> In order to process with an uploaded file, my php script calls shell script $output=system('/bin/sh connector_0.sh'); and my shell script is composed of a series of python/perl scripts. #!/bin/sh python main_senselearner_final_0.py senseLearner.pl -i Uploaded_Files/slinput_0.txt -o Uploaded_Files/presloutput_0 .txt -model modelNNCollocations -model modelJJCollocations -model modelVBColloc ations -pos python smutngslout_0.py python genhtml_0.py Now, the problem is the following: all python scripts in shell script worked fine through php. But perl script didn't work. When I run shell script by myself in my server, all four scripts in shell worked perfectly. However, when I run shell script from php, only perl script doesn't work. Would you please give me any tips to solve this problem? Many thanks!!!

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Creating a session user login php

- by user2419393

I'm stuck on how to create a session for a user who logs in. I got the part of checking to make sure the log in information corresponds with the database information, but is stuck on how to take the email address and store into a session. Here is my php code below. <?php include '../View/header.php'; session_start(); require('../model/database.php'); $email = $_POST['username']; $password = $_POST['password']; $sql = "SELECT emailAddress FROM customers WHERE emailAddress ='$email' AND password = '$password'"; $result = mysql_query($sql, $db); if (!$result) { echo "DB Error, could not query the database\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_assoc($result)) { echo $row['emailAddress']; } mysql_free_result($result); ?>

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