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  • Zend Framework: Zend_DB Error

    - by Sergio E.
    I'm trying to learn ZF, but got strange error after 20 minutes :) Fatal error: Uncaught exception 'Zend_Db_Adapter_Exception' with message 'Configuration array must have a key for 'dbname' that names the database instance' What does this error mean? I got DB information in my config file: resources.db.adapter=pdo_mysql resources.db.host=localhost resources.db.username=name resources.db.password=pass resources.db.dbname=name Any suggestions? EDIT: This is my model file /app/models/DbTable/Bands.php: class Model_DbTable_Bands extends Zend_Db_Table_Abstract { protected $_name = 'zend_bands'; } Index controller action: public function indexAction() { $albums = new Model_DbTable_Bands(); $this->view->albums = $albums->fetchAll(); } EDIT All codes: bootstrap.php protected function _initAutoload() { $autoloader = new Zend_Application_Module_Autoloader(array( 'namespace' => '', 'basePath' => dirname(__FILE__), )); return $autoloader; } protected function _initDoctype() { $this->bootstrap('view'); $view = $this->getResource('view'); $view->doctype('XHTML1_STRICT'); } public static function setupDatabase() { $config = self::$registry->configuration; $db = Zend_Db::factory($config->db); $db->query("SET NAMES 'utf8'"); self::$registry->database = $db; Zend_Db_Table::setDefaultAdapter($db); Zend_Db_Table_Abstract::setDefaultAdapter($db); } IndexController.php class IndexController extends Zend_Controller_Action { public function init() { /* Initialize action controller here */ } public function indexAction() { $albums = new Model_DbTable_Bands(); $this->view->albums = $albums->fetchAll(); } } configs/application.ini, changed database and provided password: [development : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 db.adapter = PDO_MYSQL db.params.host = localhost db.params.username = root db.params.password = pedro db.params.dbname = test models/DbTable/Bands.php class Model_DbTable_Bands extends Zend_Db_Table_Abstract { protected $_name = 'cakephp_bands'; public function getAlbum($id) { $id = (int)$id; $row = $this->fetchRow('id = ' . $id); if (!$row) { throw new Exception("Count not find row $id"); } return $row->toArray(); } }

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  • Three20 TTSectionedDataSource row height

    - by Ward
    Hey there, I'm using Three20 to create a table with several textfields for user registration. I've found two possible methods using Three20. The first uses the TTSectionedDataSource's tableDidLoadModel method to manually add UI components and the second adds custom items that contains pre formatted UI components. The second option seems way more complex and I'm having a difficult time accessing the individual fields. So if one field is a textfield for the username, I need to access the field to submit the username and it doesn't seem like there's an easy answer. The first option gives me a lot of flexibility, but I can't figure out how to set the individual row heights. One row may have a label above a text field, another may have an image, etc. Is there a method that can be used in TTSectionedDataSource that will allow me to set the height for each row? Thus far, I'm using method one and creating UIViews to hold a label field and a text field. I've tried changing the frame of the uiview before it is added to the items array, but it has no affect. Any ideas?

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  • MySQL DDL error creating tables

    - by Alexandstein
    I am attempting to create tables for a MySQL database, but I am having some syntactical issues. It would seem that syntax checking is behaving differently between tables for some reason. While I've gotten all the other tables to go through, the table, 'stock' doesn't seem to be working, despite seeming to use the same syntax patterns. CREATE TABLE users ( user_id SMALLINT UNSIGNED NOT NULL AUTO_INCREMENT, username VARCHAR(30) NOT NULL, password CHAR(41) NOT NULL, date_joined DATETIME NOT NULL, funds DOUBLE UNSIGNED NOT NULL, PRIMARY KEY(user_id), UNIQUE KEY(username) ); CREATE TABLE owned_stocks ( id SMALLINT UNSIGNED NOT NULL AUTO_INCREMENT, user_id SMALLINT UNSIGNED NOT NULL, paid_price DOUBLE UNSIGNED NOT NULL, quantity MEDIUMINT UNSIGNED NOT NULL, purchase_date DATETIME NOT NULL, PRIMARY KEY(id) ); CREATE TABLE tracking_stocks ( ticker VARCHAR(5) NOT NULL, user_id SMALLINT UNSIGNED NOT NULL, PRIMARY KEY(ticker) ); CREATE TABLE stocks ( ticker VARCHAR(5) NOT NULL, last DOUBLE UNSIGNED NOT NULL, high DOUBLE UNSIGNED NOT NULL, low DOUBLE UNSIGNED NOT NULL, company_name VARCHAR(30) NOT NULL, last_updated INT UNSIGNED NOT NULL, change DOUBLE NOT NULL, percent_change DOUBLE NOT NULL, PRIMARY KEY(ticker) ); Am I just missing a really obvious syntactical issue? ERROR: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'change DOUBLE NOT NULL, percent_change DOUBLE NOT NULL, last DOUBLE' at line 4

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  • Password hashing, salt and storage of hashed values

    - by Jonathan Leffler
    Suppose you were at liberty to decide how hashed passwords were to be stored in a DBMS. Are there obvious weaknesses in a scheme like this one? To create the hash value stored in the DBMS, take: A value that is unique to the DBMS server instance as part of the salt, And the username as a second part of the salt, And create the concatenation of the salt with the actual password, And hash the whole string using the SHA-256 algorithm, And store the result in the DBMS. This would mean that anyone wanting to come up with a collision should have to do the work separately for each user name and each DBMS server instance separately. I'd plan to keep the actual hash mechanism somewhat flexible to allow for the use of the new NIST standard hash algorithm (SHA-3) that is still being worked on. The 'value that is unique to the DBMS server instance' need not be secret - though it wouldn't be divulged casually. The intention is to ensure that if someone uses the same password in different DBMS server instances, the recorded hashes would be different. Likewise, the user name would not be secret - just the password proper. Would there be any advantage to having the password first and the user name and 'unique value' second, or any other permutation of the three sources of data? Or what about interleaving the strings? Do I need to add (and record) a random salt value (per password) as well as the information above? (Advantage: the user can re-use a password and still, probably, get a different hash recorded in the database. Disadvantage: the salt has to be recorded. I suspect the advantage considerably outweighs the disadvantage.) There are quite a lot of related SO questions - this list is unlikely to be comprehensive: Encrypting/Hashing plain text passwords in database Secure hash and salt for PHP passwords The necessity of hiding the salt for a hash Clients-side MD5 hash with time salt Simple password encryption Salt generation and Open Source software I think that the answers to these questions support my algorithm (though if you simply use a random salt, then the 'unique value per server' and username components are less important).

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  • How to process AJAX requests more securely in PHP?

    - by animuson
    Ok, so I want to send AJAX requests to my website from my Flash games to process data, but I don't want people downloading them, decompiling them, then sending fake requests to be processed, so I'm trying to figure out the most secure way to process in the PHP files. My first idea was to use Apache's built in Authorization module to require a username and password to access the pages on a separate subdomain of my website, but then you'd have to include that username and password in the AJAX request anyway so that seems kind of pointless to even try. My current option looks pretty promising but I want to make sure it will work. Basically it just checks the IP address being sent using REMOTE_ADDR to make sure it's the IP address that my server runs on. <? $allowed = new Array("64.120.211.89", "64.120.211.90"); if (!in_array($_SERVER['REMOTE_ADDR'], $allowed)) header("HTTP/1.1 403 Forbidden"); ?> Both of those IP addresses point to my server. Things I'm worried about: 1) If I send a request from Flash/ActionScript, will that affect the IP address in any way? 2) Is it possible for malicious users to change the IP address that is being sent with REMOTE_ADDR to one of my IP addresses? Any other ways you would suggest that might be more secure?

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  • Discussion - Allowing / blocking user access to pages (Client Side Only!) - Javascript / Jquery

    - by Ozaki
    TLDR Using plain HTML / Javascript (Client Side) I want to prevent viewing of certain pages. The user will have to type a username and password and depending on that they get access to different pages. Answers can NOT include server side whatsoever It does not matter if they can break it easily. There is no sensitive information etc. Also the target audience will not have access to internet OR probably know what a cookie is... At some point the user will have to type username / password.(I can define the cookie here) Currently I thought of using cookies to set a cookie for each page to say "true" / "false" but that would get messy with so many cookies. Or setting an array within a cookie for each page? I have div field "#Content" which as it looks encompasses all of my content on the page so blocking out content will be as simple as replacing it with ("sorry you don't have access") etc. For Example: $.cookie("Access","page1, page2, page3"{ expires: 1 }); I am looking for anyway to do this does not have to be with cookies. Would be nice to get a discussion of different ways this can be done. So the question is: What do YOU think would be a good way to go about doing this with client side validation?

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  • Voting on Hacker News stories programmatically?

    - by igorgue
    I decided to write an app like: http://michaelgrinich.com/hackernews/ but for Android devices, my idea will use a web application backend (because I rather code in Python and for the web than completely in Java for Android devices). What I have right now implemented is something like this: $ curl -i http://localhost:8080/stories.json?page=1\&stories=1 HTTP/1.0 200 OK Date: Sun, 25 Apr 2010 07:59:37 GMT Server: WSGIServer/0.1 Python/2.6.5 Content-Length: 296 Content-Type: application/json [{"title": "Don\u2019t talk to aliens, warns Stephen Hawking", "url": "http://www.timesonline.co.uk/tol/news/science/space/article7107207.ece?", "unix_time": 1272175177, "comments": 15, "score": 38, "user": "chaostheory", "position": 1, "human_time": "Sun Apr 25 01:59:37 2010", "id": "1292241"}] The next step (and final I think) is voting, my design is doing something like this: $ curl -i http://localhost:8080/stories/1?vote=up -u username:password Will vote up and: $ curl -i http://localhost:8080/stories/1?vote=down -u username:password Down. I have no idea how to do it though... I was planning to use Twill but the login link is always different, e.g.: http://news.ycombinator.com/x?fnid=7u89ccHKln Later the Android app will consume this API. Any experience with programmatically browsing Hacker News?

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  • Finds in Rails 3 and ActiveRelation

    - by TheDelChop
    Guys, I'm trying to understand the new arel engine in Rails 3 and I've got a question. I've got two models, User and Task class User < ActiveRecord::Base has_many :tasks end class Task < ActiveRecord::Base belongs_to :user end here is my routes to imply the relation: resources :users do resources :tasks end and here is my Tasks controller: class TasksController < ApplicationController before_filter :load_user def new @task = @user.tasks.new end private def load_user @user = User.where(:id => params[:user_id]) end end Problem is, I get the following error when I try to invoke the new action: NoMethodError: undefined method `tasks' for #<ActiveRecord::Relation:0x3dc2488> I am sure my problem is with the new arel engine, does anybody understand what I'm doing wrong? Sorry guys, here is my schema.db file: ActiveRecord::Schema.define(:version => 20100525021007) do create_table "tasks", :force => true do |t| t.string "name" t.integer "estimated_time" t.datetime "created_at" t.datetime "updated_at" t.integer "user_id" end create_table "users", :force => true do |t| t.string "email", :default => "", :null => false t.string "encrypted_password", :limit => 128, :default => "", :null => false t.string "password_salt", :default => "", :null => false t.string "reset_password_token" t.string "remember_token" t.datetime "remember_created_at" t.integer "sign_in_count", :default => 0 t.datetime "current_sign_in_at" t.datetime "last_sign_in_at" t.string "current_sign_in_ip" t.string "last_sign_in_ip" t.datetime "created_at" t.datetime "updated_at" t.string "username" end add_index "users", ["email"], :name => "index_users_on_email", :unique => true add_index "users", ["reset_password_token"], :name => "index_users_on_reset_password_token", :unique => true add_index "users", ["username"], :name => "index_users_on_username", :unique => true end Thank you, Joe

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  • PHP / Zend Framework: Force prepend table name to column name in result array?

    - by Brian Lacy
    I am using Zend_Db_Select currently to retrieve hierarchical data from several joined tables. I need to be able to convert this easily into an array. Short of using a switch statement and listing out all the columns individually in order to sort the data, my thought was that if I could get the table names auto-prepended to the keys in the result array, that would solve my problem. So considering the following (assembled) SQL: SELECT user.*, contact.* FROM user INNER JOIN contact ON contact.user_id = user.user_id I would normally get a result array like this: [username] => 'bob', [contact_id] => 5, [user_id] => 2, [firstname] => 'bob', [lastname] => 'larsen' But instead I want this: [user.user_id] => 2, [user.username] => 'bob', [contact.contact_id] => 5, [contact.firstname] => 'bob', [contact.lastname] => 'larsen' Does anyone have an idea how to achieve this? Thanks!

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  • Fun with "The remote server returned an error: NotFound" - Silverlight4 Out of Browser

    - by Scott Silvi
    Hey all - I'm running SL4 on VS2010. I've got an app that authenticates via a web service to SPROC in my db. Unfortunately this is not WCF/WCF RIA, as I'm inheriting the DB/services from my client. This works perfectly inside of a browser. I'm attempting to move this OOB, and it's at this point that my authentication fails. Here's the steps I took... 1) SL App Properties Enable running app Out of Browser 2) SL App Properties Out of Browser Settings Require elevated trust when running OOB If i set a breakpoint on my logon button click, I see the service call is being made. However, if I step through it (or set a breakpoint on the actual logon web service), the code never gets that far. Here's the block it fails on: public LogonSVC.LogonResponse EndLogon(System.IAsyncResult result) { object[] _args = new object[0]; LogonSVC.LogonResponse _result = ((LogonSVC.LogonResponse)(base.EndInvoke("Logon", _args, result))); return _result; } I know using Elevated Trust means the crossdomain.xml isn't necessary. I dropped one in that allows everything, just to test, and that still fails. here's the code that calls the service: private void loginButton_Click(object sender, RoutedEventArgs e) { string Username = txtUserName.Text; string Password = txtPassword.Password; Uri iSilverlightServiceUriRelative = new Uri(App.Current.Host.Source, "../Services/Logon.asmx"); EndpointAddress iSilverlightServiceEndpoint = new EndpointAddress(iSilverlightServiceUriRelative); BasicHttpBinding iSilverlightServiceBinding = new BasicHttpBinding(BasicHttpSecurityMode.Transport);// Transport if it's HTTPS:// LogonService = new LogonSVC.LogonSoapClient(iSilverlightServiceBinding, iSilverlightServiceEndpoint); LogonService.LogonCompleted += new EventHandler<LogonSVC.LogonCompletedEventArgs>(LogonService_LogonCompleted); LogonService.LogonAsync(Username, Password); } My LogonService_LogonCompleted doesn't fire either (which makes sense, just a heads up). I don't know how to fiddler this, as this is running OOB with the site served via localhost/IIS. I know this works though in browser, so I'm curious what would break it OOB. Thank you, Scott

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  • Git repository gets corrupted when I do a large commit: "Possible repository corruption on the remot

    - by mindthief
    Hi All, A friend of mine and I have been trying to use git for a project. It is hosted on his server, and I git clone it as: git clone [email protected]:/path/to/git/repos.git Pretty standard stuff, and it works great for a while. But every time one of us has added a large commit (which git supposedly handles very well), of the order of 100MB or so, the git repository gets kind of broken. Basically, at this point I will be able to push new changes and pull other changes (I think), but when I try to clone the repository in a fresh location using that command above, I get an error message that says: $git clone [email protected]:/path/to/git/repos.git Initialized empty Git repository in /local/path/to/repos/.git/ remote: Counting objects: 1455, done. remote: Compressing objects: 100% (1235/1235), done. error: git upload-pack: git-pack-objects died with error.s fatal: git upload-pack: aborting due to possible repository corruption on the remote side. remote: aborting due to possible repository corruption on the remote side. fatal: early EOF fatal: index-pack failed This has happened 3 or 4 times now, and it's always when I add a large commit. Any idea why this is happening? How can we fix it? We're both using Mac OSX Snow Leopard. Thanks! -M

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  • Error setting env thru subprocess.call to run a python script on a remote linux machine

    - by John Smith
    I am running a python script on a windows machine to invoke another python script on a remote linux machine. I am using subprocess.call with ssh to do this, like below: subprocess.call('ssh -i <identify file> username@hostname python <script_on_linux_machine>') and this works fine. However, if I want to set some environment variables, like below: subprocess.call('ssh -i <identify file> username@hostname python <script_on_linux_machine>', env={key1:value1}) it fails. I get the following error: ssh_connect: getnameinfo failed ssh: connect to host <hostname> port 22: Operation not permitted 255 I've tried splitting the ssh commands into list and passing. Didn't help. I've tried to run other 'local'(windows) commands thru subprocess.call() and tried setting the env. It works fine. I've tried to run other commands(such as ls) on the remote linux machine. Again, subprocess.call() works fine, as long as I don't try to set the environment. What am I doing wrong? Would I be able to set the environment for a python script on a remote machine? Any help will be appreciated.

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  • Entity Framework Duplicate type name within an assembly (6.1.0)

    - by CodeMilian
    I am not sure what is going on but I keep getting the following exception when doing a query. "Duplicate type name within an assembly." I have not been able to find a solution on the web. I had resolved the issue by removing entity framework from all the projects in the solutions and re-installing using nugget. Then all of the sudden the exception is back. I have verified my table schema over and over and find nothing wrong with. This is the query causing the exception. var BaseQuery = from Users in db.Users join UserInstalls in db.UserTenantInstalls on Users.ID equals UserInstalls.UserID join Installs in db.TenantInstalls on UserInstalls.TenantInstallID equals Installs.ID where Users.Username == Username && Users.Password == Password && Installs.Name == Install select Users; var Query = BaseQuery.Include("UserTenantInstalls.TenantInstall"); return Query.FirstOrDefault(); As I mentioned previously the same query was working before. The data has not changed and the code has not changed.

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  • Populate table with JQuery

    - by Talkar
    I need to populate some data into a table. The data i have is something i get in response from my ASP.NET MVC site, when i make a json post call there. Yet i can't seem to find a way to actually display the data i get back in response. Here is my code so far. Any help would be much appreciated: $(document).ready(function () { var uName = '<%= Session["UserName"].ToString()%>'; var pWord = '<%= Session["Password"].ToString()%>'; var data = { UserName:uName,Password:pWord}; $.ajax( { type: 'POST', url: "http://someurl.goes.here/", crossDomain: true, data: data, dataType: 'jsonp', success: function(myData) { $.each(myData, function (index, element) { $("#ClassTable").append('<tr><td> ' + element[0] + ' </td> <td> ' + element[1] + '</td></tr>'); }) } }); }); myData looks like this: [Object { IsActive = True, ObjectId=1, ObjectString="someString", etc... etc... } ]

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  • rails Rake and mysql ssh port forwarding.

    - by rube_noob
    Hello, I need to create a rake task to do some active record operations via a ssh tunnel. The rake task is run on a remote windows machine so I would like to keep things in ruby. This is my latest attempt. desc "Syncronizes the tablets DB with the Server" task(:sync => :environment) do require 'rubygems' require 'net/ssh' begin Thread.abort_on_exception = true tunnel_thread = Thread.new do Thread.current[:ready] = false hostname = 'host' username = 'tunneluser' Net::SSH.start(hostname, username) do|ssh| ssh.forward.local(3333, "mysqlhost.com", 3306) Thread.current[:ready] = true puts "ready thread" ssh.loop(0) { true } end end until tunnel_thread[:ready] == true do end puts "tunnel ready" Importer.sync rescue StandardError => e puts "The Database Sync Failed." end end The task seems to hang at "tunnel ready" and never attempts the sync. I have had success when running first a rake task to create the tunnel and then running the rake sync in a different terminal. I want to combine these however so that if there is an error with the tunnel it will not attempt the sync. This is my first time using ruby Threads and Net::SSH forwarding so I am not sure what is the issue here. Any Ideas!? Thanks

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  • How to get database table header information into an CSV File.

    - by Rachel
    I am trying to connect to the database and get current state of a table and update that information into csv file, with below mentioned piece of code, am able to get data information into csv file but am not able to get header information from database table into csv file. So my questions is How can I get Database Table Header information into an CSV File ? $config['database'] = 'sakila'; $config['host'] = 'localhost'; $config['username'] = 'root'; $config['password'] = ''; $d = new PDO('mysql:dbname='.$config['database'].';host='.$config['host'], $config['username'], $config['password']); $query = "SELECT * FROM actor"; $stmt = $d->prepare($query); // Execute the statement $stmt->execute(); var_dump($stmt->fetch(PDO::FETCH_ASSOC)); $data = fopen('file.csv', 'w'); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo "Hi"; // Export every row to a file fputcsv($data, $row); } Header information meaning: Vehicle Build Model car 2009 Toyota jeep 2007 Mahindra So header information for this would be Vehicle Build Model Any guidance would be highly appreciated.

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  • Google Spreadsheet API problem: memory exceeded

    - by Robbert
    Hi guys, Don't know if anyone has experience with the Google Spreadsheets API or the Zend_GData classes but it's worth a go: When I try to insert a value in a 750 row spreadsheet, it takes ages and then throws an error that my memory limit (which is 128 MB!) was exceeded. I also got this when querying all records of this spreadsheet but this I can imaging because it's quite a lot of data. But why does this happen when inserting a row? That's not too complex, is it? Here's the code I used: public function insertIntoSpreadsheet($username, $password, $spreadSheetId, $data = array()) { $service = Zend_Gdata_Spreadsheets::AUTH_SERVICE_NAME; $client = Zend_Gdata_ClientLogin::getHttpClient($username, $password, $service); $client->setConfig(array( 'timeout' => 240 )); $service = new Zend_Gdata_Spreadsheets($client); if (count($data) == 0) { die("No valid data"); } try { $newEntry = $service->insertRow($data, $spreadSheetId); return true; } catch (Exception $e) { return false; } }

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  • How to write custom (odd) authentication plugins for Wordpress, Joomla and MediaWiki?

    - by Bart van Heukelom
    On our network (a group of related websites - not a LAN) we have a common authentication system which works like this: On a network site ("consumer") the user clicks on a login link This redirects the user to a login page on our auth system ("RAS"). Upon successful login the user is directed back to the consumer site. Extra data is passed in the query string. This extra data does not include any information about the user yet. The consumer site's backend contacts RAS, with this extra data, to get the information about the logged in user (id, name, email, preferences, etc.). So as you can see, the consumer site knows nothing about the authentication method. It doesn't know if it's by username/password, fingerprint, smartcard, or winning a game of poker. This is the main problem I'm encountering when trying to find out how I could write custom authentication plugins for these packages, acting as consumer sites: Wordpress Joomla MediaWiki For example Joomla offers a pretty simple auth plugin system, but it depends on a username/password entered on the Joomla site. Any hints on where to start?

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  • Handling responses in libcurl

    - by sfactor
    i have a code to send a Form Post with login credentials to a webpage. it looks like this CURL *curl; CURLcode res; struct curl_httppost *formpost=NULL; struct curl_httppost *lastptr=NULL; struct curl_slist *headerlist=NULL; static const char buf[] = "Expect:"; curl_global_init(CURL_GLOBAL_ALL); /* Fill in the username */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "user", CURLFORM_COPYCONTENTS, "username", CURLFORM_END); /* Fill in the password */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "pass", CURLFORM_COPYCONTENTS, "password", CURLFORM_END); /* Fill in the submit field too, even if this is rarely needed */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "submit", CURLFORM_COPYCONTENTS, "send", CURLFORM_END); curl = curl_easy_init(); /* initalize custom header list (stating that Expect: 100-continue is not wanted */ headerlist = curl_slist_append(headerlist, buf); if(curl) { /* what URL that receives this POST */ curl_easy_setopt(curl, CURLOPT_URL, "http://127.0.0.1:8000/index.html"); /* only disable 100-continue header if explicitly requested */ curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist); curl_easy_setopt(curl, CURLOPT_HTTPPOST, formpost); res = curl_easy_perform(curl); /* always cleanup */ curl_easy_cleanup(curl); /* then cleanup the formpost chain */ curl_formfree(formpost); /* free slist */ curl_slist_free_all (headerlist); } now i need to know is how do i handle the responses i get back from the server? i need to store the response into a string and then work on it.

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  • Simple continuously running XMPP client in python

    - by tom
    I'm using python-xmpp to send jabber messages. Everything works fine except that every time I want to send messages (every 15 minutes) I need to reconnect to the jabber server, and in the meantime the sending client is offline and cannot receive messages. So I want to write a really simple, indefinitely running xmpp client, that is online the whole time and can send (and receive) messages when required. My trivial (non-working) approach: import time import xmpp class Jabber(object): def __init__(self): server = 'example.com' username = 'bot' passwd = 'password' self.client = xmpp.Client(server) self.client.connect(server=(server, 5222)) self.client.auth(username, passwd, 'bot') self.client.sendInitPresence() self.sleep() def sleep(self): self.awake = False delay = 1 while not self.awake: time.sleep(delay) def wake(self): self.awake = True def auth(self, jid): self.client.getRoster().Authorize(jid) self.sleep() def send(self, jid, msg): message = xmpp.Message(jid, msg) message.setAttr('type', 'chat') self.client.send(message) self.sleep() if __name__ == '__main__': j = Jabber() time.sleep(3) j.wake() j.send('[email protected]', 'hello world') time.sleep(30) The problem here seems to be that I cannot wake it up. My best guess is that I need some kind of concurrency. Is that true, and if so how would I best go about that? EDIT: After looking into all the options concerning concurrency, I decided to go with twisted and wokkel. If I could, I would delete this post.

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  • Unity Framework constructor parameters in MVC

    - by ubersteve
    I have an ASP.NET MVC3 site that I want to be able to use different types of email service, depending on how busy the site is. Consider the following: public interface IEmailService { void SendEmail(MailMessage mailMessage); } public class LocalEmailService : IEmailService { public LocalEmailService() { // no setup required } public void SendEmail(MailMessage mailMessage) { // send email via local smtp server, write it to a text file, whatever } } public class BetterEmailService : IEmailService { public BetterEmailService (string smtpServer, string portNumber, string username, string password) { // initialize the object with the parameters } public void SendEmail(MailMessage mailMessage) { //actually send the email } } Whilst the site is in development, all of my controllers will send emails via the LocalEmailService; when the site is in production, they will use the BetterEmailService. My question is twofold: 1) How exactly do I pass the BetterEmailService constructor parameters? Is it something like this (from ~/Bootstrapper.cs): private static IUnityContainer BuildUnityContainer() { var container = new UnityContainer(); container.RegisterType<IEmailService, BetterEmailService>("server name", "port", "username", "password"); return container; } 2) Is there a better way of doing that - i.e. putting those keys in the web.config or another configuration file so that the site would not need to be recompiled to switch which email service it was using? Many thanks!

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  • How to tell what account my webservice is running under in Visual Studio 2005

    - by John Galt
    I'm going a little nuts trying to understand the doc on impersonation and delegation and the question has come up what account my webservice is running under. I am logged as myDomainName\johna on my development workstation called JOHNXP. From Vstudio2005 I start my webservice via Debug and the wsdl page comes up in my browser. From Task Manager, I see the following while sitting at a breakpoint in my .asmx code: aspnet_wp.exe pid=1316 UserName=ASPNET devenv.exe pid=3304 UserName=johna The IIS Directory Security tab for the Virtual Directory that hosts my ws.asmx code has "Enable Anonymous access" UNCHECKED and has "Integrated Windows Authentication" CHECKED. So when the MSDN people state "you must configure the user account under which the server process runs", what would they be refering to in the case of my little webservice described above? I am quoting from: http://msdn.microsoft.com/en-us/library/aa302400.aspx Ultimately, I want this webservice of mine to impersonate whatever authenticated domain user browses through to an invoke of my webservice. My webservice in turn consumes another ASMX webservice on a different server (but same domain). I need this remote webservice to use the impersonated domain user credentials (not those of my webservice on JOHNXP). So its getting a little snarly for me to understand this and I see I am unclear about the account my web service uses. I think it is ASPNET in IIS 5.1 on WinXP but not sure.

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  • iPad keyboard will not dismiss if navigation controller presentation style is "form sheet".

    - by Kalle
    UPDATE: This is apparently "works as intended" classed by Apple. See accepted answer below for details. Update: this question is about a behavior discovered in the iPad keyboard, where it refuses to be dismissed if shown in a modal dialog with a navigation controller. Basically, if I present the navigation controller with the following line: navigationController.modalPresentationStyle = UIModalPresentationFormSheet; The keyboard refuses to be dismissed. If I comment out this line, the keyboard goes away fine. ... I've got two textFields, username and password; username has a Next button and password has a Done button. The keyboard won't go away if I present this in a modal navigation controller. WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; [self.view addSubview:b.view]; DOES NOT WORK broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:b]; navigationController.modalPresentationStyle = UIModalPresentationFormSheet; navigationController.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal; [self presentModalViewController:navigationController animated:YES]; [navigationController release]; [b release]; If I remove the navigation controller part and present 'b' as a modal view controller by itself, it works. Is the navigation controller the problem? WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; b.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal; [self presentModalViewController:b animated:YES]; [b release]; WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:b]; [self presentModalViewController:navigationController animated:YES]; [navigationController release]; [b release];

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  • NHibernate mapping for subclasses and joined-subclasses

    - by Husain
    In a project that I am working on, I have the following entities: Analyst, Client and Contractor. Each inherit from a base class User. public abstract class User { public virtual int Id { get; set; } public virtual string Username { get; set; } public virtual string FullName { get; set; } } I then have the other classes inheriting from the base class as: public class Analyst : User { // Empty class. There are no additional properties for an analyst. } public class Client : User { // Empty class. There are no additional properties for a client. } public class Contractor : User { public int TotalJobs { get; set; } public int JobsInProgress { get; set; } } For the above classes, I have the following table structure: USER ---- UserId Username FullName UserType (1 = Analyst, 2 = Client, 3 = Contractor) CONTRACTOR ---------- UserId TotalJobs JobsInProgress There are no tables for Analyst and Client classes. I would like to know how I can write the NHibernate mapping file for the Contractor class. For the other classes, I have created a User mapping file and added Client and Analyst as sub-classes. How can I map the Contractor class?

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  • Update database settings in properties file in Spring

    - by mvg
    Hi all, I am trying to create a Database Manager page which shows the database details on page load and updates the database settings when the user press submit I followed this tutorial and set the database settings in properties file. I managed to update the database settings in properties file programmatically. When I retrieved the database settings using the following code DriverManagerDataSource databaseSource = (DriverManagerDataSource)context.getBean("dataSource"); databaseSource.getUsername(); I managed to get the old value and unable to get the new value This is the mapping in applicationContext.xml file <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>classpath:/bundle/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> I checked the properties file and found it to be updated with the latest input. What am I missing? Thanks in advance P.S I am using JSF1.2 with Spring 3 Update Just making my requirement simple. I am creating a setparate dbsettings page, so that when user wishes to connect to different database he/she can just enter the details in dbsettings page and connect

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