Search Results

Search found 69545 results on 2782 pages for 'file manipulation'.

Page 115/2782 | < Previous Page | 111 112 113 114 115 116 117 118 119 120 121 122  | Next Page >

  • How can I transfer a file via XMPP using Python?

    - by Enchantner
    I'm using xmpppy library for my jabber remote administration bot, but I can't find how to send/receive a file and save it inside the directory specified. The documentation is poor and there isn't any examples, but I really want to make it. Can anyone show some examples or some links about it? Or maybe I should use an alternative xmpp bindings?

    Read the article

  • JavaScript String Replace with a tricky regular expression

    - by Juri
    Hi. I'm trying to work out what regular expression I would need to change this string html = '<img style="width: 311px; height: 376px;" alt="test" src="/img/1268749322.jpg" />'; to this html = '<img width="311" height="376" alt="test" src="/img/1268749322.jpg" />'; with the help of Javascript.replace. This is my start: html = html.replace(/ style="width:\?([0-9])px*"/g, "width=\"$1\""); Can anyone help me? THANKS

    Read the article

  • How to Split and strip into multiple variables?

    - by Khou
    How to Split and strip X string values into separate variables? X has string value of itemA=myvalue&itemB=anothervalue&itemC=andanother I have 3 strings (var1,var2,var3) to hold the values of the stripped values. Find in string X "itemA=" copy everything after "=" character until "&" character OR if no "&" character is found copy until end of string (store this value into var1) Find in string X "itemB=" copy everything after "=" character until "&" character OR if no "&" character is found copy until end of string (store this value into var2) Find in string X "itemB=" copy everything after "=" character until "&" character OR if no "&" character is found copy until end of string (store this value into var3)

    Read the article

  • How can I do batch image processing with ImageJ in Java or clojure?

    - by Robert McIntyre
    I want to use ImageJ to do some processing of several thousand images. Is there a way to take any general imageJ plugin and apply it to hundreds of images automatically? For example, say I want to take my thousand images and apply a polar transformation to each--- A polar transformation plugin for ImageJ can be found here: http://rsbweb.nih.gov/ij/plugins/polar-transformer.html Great! Let's use it. From: [http://albert.rierol.net/imagej_programming_tutorials.html#How%20to%20automate%20an%20ImageJ%20dialog] I find that I can apply a plugin using the following: (defn x-polar [imageP] (let [thread (Thread/currentThread) options ""] (.setName thread "Run$_polar-transform") (Macro/setOptions thread options) (IJ/runPlugIn imageP "Polar_Transformer" ""))) This is good because it suppresses the dialog which would otherwise pop up for every image. But running this always brings up a window containing the transformed image, when what I want is to simply return the transformed image. The stupidest way to do what I want is to just close the window that comes up and return the image which it was displaying. Does what I want but is absolutely retarded: (defn x-polar [imageP] (let [thread (Thread/currentThread) options ""] (.setName thread "Run$_polar-transform") (Macro/setOptions thread options) (IJ/runPlugIn imageP "Polar_Transformer" "") (let [return-image (IJ/getImage)] (.hide return-image) return-image))) I'm obviously missing something about how to use imageJ plugins in a programming context. Does anyone know the right way to do this? Thanks, --Robert McIntyre

    Read the article

  • What's a good way of building up a String where you specific start and end locations?

    - by Michael Campbell
    (java 1.5) I have a need to build up a String, in pieces. I'm given a set of (sub)strings, each with a start and end point of where they belong in the final string. Was wondering if there were some canonical way of doing this. This isn't homework, and I can use any licensable OSS, such as jakarta commons-lang StringUtils etc. My company has a solution using a CharBuffer, and I'm content to leave it as is (and add some unit tests, of which there are none (?!)) but the code is fairly hideous and I would like something easier to read. As I said this isn't homework, and I don't need a complete solution, just some pointers to libraries or java classes that might give me some insight. The String.Format didn't seem QUITE right... I would have to honor inputs too long and too short, etc. Substrings would be overlaid in the order they appear (in case of overlap). As an example of input, I might have something like: String:start:end FO:0:3 (string shorter than field) BAR:4:5 (String larger than field) BLEH:5:9 (String overlays previous field) I'd want to end up with FO BBLEH 01234567890

    Read the article

  • How do I flip a column in mysql that has data structured: 'last name, first name'?

    - by ggg
    I want to create a new column in a MYSQL table that has Fn Ln instead of Ln, Fn. Most of my data is printed Fn Ln. Another idea is to incorporate a string function each time there is an output (php based) but that seems to waste resources. Finally, I couldn't find the syntax (loop or foreach) for my php function anyway. Here is the working php function that I got from a previous post: $name = "Lastname, Firstname"; $names = explode(", ", $name); $name = $names[1] . " " . $names[0];

    Read the article

  • Can I use regular expressions with String.Replace in C#?

    - by Taz
    For example I have code below string txt="I have strings like West, and West; and west, and Western." I would like to replace the word west or West with some other word. But I would like not to replace West in Western. Can I use regular expression in string.replace? I used inputText.Replace("(\\sWest.\\s)",temp); It dos not work.

    Read the article

  • rotating bitmaps. In code.

    - by Marco van de Voort
    Is there a faster way to rotate a large bitmap by 90 or 270 degrees than simply doing a nested loop with inverted coordinates? The bitmaps are 8bpp and typically 2048*2400*8bpp Currently I do this by simply copying with argument inversion, roughly (pseudo code: for x = 0 to 2048-1 for y = 0 to 2048-1 dest[x][y]=src[y][x]; (In reality I do it with pointers, for a bit more speed, but that is roughly the same magnitude) GDI is quite slow with large images, and GPU load/store times for textures (GF7 cards) are in the same magnitude as the current CPU time. Any tips, pointers? An in-place algorithm would even be better, but speed is more important than being in-place. Target is Delphi, but it is more an algorithmic question. SSE(2) vectorization no problem, it is a big enough problem for me to code it in assembler Duplicates How do you rotate a two dimensional array?. Follow up to Nils' answer Image 2048x2700 - 2700x2048 Compiler Turbo Explorer 2006 with optimization on. Windows: Power scheme set to "Always on". (important!!!!) Machine: Core2 6600 (2.4 GHz) time with old routine: 32ms (step 1) time with stepsize 8 : 12ms time with stepsize 16 : 10ms time with stepsize 32+ : 9ms Meanwhile I also tested on a Athlon 64 X2 (5200+ iirc), and the speed up there was slightly more than a factor four (80 to 19 ms). The speed up is well worth it, thanks. Maybe that during the summer months I'll torture myself with a SSE(2) version. However I already thought about how to tackle that, and I think I'll run out of SSE2 registers for an straight implementation: for n:=0 to 7 do begin load r0, <source+n*rowsize> shift byte from r0 into r1 shift byte from r0 into r2 .. shift byte from r0 into r8 end; store r1, <target> store r2, <target+1*<rowsize> .. store r8, <target+7*<rowsize> So 8x8 needs 9 registers, but 32-bits SSE only has 8. Anyway that is something for the summer months :-) Note that the pointer thing is something that I do out of instinct, but it could be there is actually something to it, if your dimensions are not hardcoded, the compiler can't turn the mul into a shift. While muls an sich are cheap nowadays, they also generate more register pressure afaik. The code (validated by subtracting result from the "naieve" rotate1 implementation): const stepsize = 32; procedure rotatealign(Source: tbw8image; Target:tbw8image); var stepsx,stepsy,restx,resty : Integer; RowPitchSource, RowPitchTarget : Integer; pSource, pTarget,ps1,ps2 : pchar; x,y,i,j: integer; rpstep : integer; begin RowPitchSource := source.RowPitch; // bytes to jump to next line. Can be negative (includes alignment) RowPitchTarget := target.RowPitch; rpstep:=RowPitchTarget*stepsize; stepsx:=source.ImageWidth div stepsize; stepsy:=source.ImageHeight div stepsize; // check if mod 16=0 here for both dimensions, if so -> SSE2. for y := 0 to stepsy - 1 do begin psource:=source.GetImagePointer(0,y*stepsize); // gets pointer to pixel x,y ptarget:=Target.GetImagePointer(target.imagewidth-(y+1)*stepsize,0); for x := 0 to stepsx - 1 do begin for i := 0 to stepsize - 1 do begin ps1:=@psource[rowpitchsource*i]; // ( 0,i) ps2:=@ptarget[stepsize-1-i]; // (maxx-i,0); for j := 0 to stepsize - 1 do begin ps2[0]:=ps1[j]; inc(ps2,RowPitchTarget); end; end; inc(psource,stepsize); inc(ptarget,rpstep); end; end; // 3 more areas to do, with dimensions // - stepsy*stepsize * restx // right most column of restx width // - stepsx*stepsize * resty // bottom row with resty height // - restx*resty // bottom-right rectangle. restx:=source.ImageWidth mod stepsize; // typically zero because width is // typically 1024 or 2048 resty:=source.Imageheight mod stepsize; if restx>0 then begin // one loop less, since we know this fits in one line of "blocks" psource:=source.GetImagePointer(source.ImageWidth-restx,0); // gets pointer to pixel x,y ptarget:=Target.GetImagePointer(Target.imagewidth-stepsize,Target.imageheight-restx); for y := 0 to stepsy - 1 do begin for i := 0 to stepsize - 1 do begin ps1:=@psource[rowpitchsource*i]; // ( 0,i) ps2:=@ptarget[stepsize-1-i]; // (maxx-i,0); for j := 0 to restx - 1 do begin ps2[0]:=ps1[j]; inc(ps2,RowPitchTarget); end; end; inc(psource,stepsize*RowPitchSource); dec(ptarget,stepsize); end; end; if resty>0 then begin // one loop less, since we know this fits in one line of "blocks" psource:=source.GetImagePointer(0,source.ImageHeight-resty); // gets pointer to pixel x,y ptarget:=Target.GetImagePointer(0,0); for x := 0 to stepsx - 1 do begin for i := 0 to resty- 1 do begin ps1:=@psource[rowpitchsource*i]; // ( 0,i) ps2:=@ptarget[resty-1-i]; // (maxx-i,0); for j := 0 to stepsize - 1 do begin ps2[0]:=ps1[j]; inc(ps2,RowPitchTarget); end; end; inc(psource,stepsize); inc(ptarget,rpstep); end; end; if (resty>0) and (restx>0) then begin // another loop less, since only one block psource:=source.GetImagePointer(source.ImageWidth-restx,source.ImageHeight-resty); // gets pointer to pixel x,y ptarget:=Target.GetImagePointer(0,target.ImageHeight-restx); for i := 0 to resty- 1 do begin ps1:=@psource[rowpitchsource*i]; // ( 0,i) ps2:=@ptarget[resty-1-i]; // (maxx-i,0); for j := 0 to restx - 1 do begin ps2[0]:=ps1[j]; inc(ps2,RowPitchTarget); end; end; end; end;

    Read the article

  • how to retrieve part of a string in java?

    - by mithun1538
    Hello everyone, I am designing a chat applet. In this, a user will append his name to the beginning of the message that he sends to the other user. In the window of other user, I want to retrieve the appended user name from that string. How do I do that? The message sent by the user is as follows : final_msg = user_name + ": " + user_message Hence I want to know how to retrieve the user_name string only. Is there a function that can retrieve a substring upto the first ":"? I dont want to use final_msg.split(":"), because there is a possiblity that the user_message contains ":", which will then give me an array of strings.

    Read the article

  • C# string parsing question

    - by rsteckly
    I'm trying to split a string: string f = r.ReadToEnd(); string[] seperators = new string[] {"[==========]"}; string[] result; result = f.Split(seperators, StringSplitOptions.None); There's this ========== thing that separates entries. For the life of me, I can't get this to work. I've got a ruby version working...BUT using the string splitter classes I thought I knew for .NET doesn't seem to be working so well. Any ideas what I'm doing wrong?

    Read the article

  • Java add leading zeros to a number....

    - by user69514
    I need to return a string in the form xxx-xxxx where xxx is a number and xxxx is another number, however when i have leading zeros they disappear. I'm trying number formatter, but it's not working. public String toString(){ NumberFormat nf3 = new DecimalFormat("#000"); NumberFormat nf4 = new DecimalFormat("#0000"); if( areaCode != 0) return nf3.format(areaCode) + "-" + nf3.format(exchangeCode) + "-" + nf4.format(number); else return exchangeCode + "-" + number; } } I figured it out: public String toString(){ NumberFormat nf3 = new DecimalFormat("000"); NumberFormat nf4 = new DecimalFormat("0000"); if( areaCode != 0) //myFormat.format(new Integer(someValue)); return nf3.format(new Integer(areaCode)) + "-" + nf3.format(new Integer(exchangeCode)) + "-" + nf4.format(new Integer(number)); else return nf3.format(new Integer(exchangeCode)) + "-" + nf4.format(new Integer(number)); }

    Read the article

  • Tricky string transformation (hopefully) in LINQ

    - by Larsenal
    I'm hoping for a concise way to perform the following transformation. I want to transform song lyrics. The input will look something like this: Verse 1 lyrics line 1 Verse 1 lyrics line 2 Verse 1 lyrics line 3 Verse 1 lyrics line 4 Verse 2 lyrics line 1 Verse 2 lyrics line 2 Verse 2 lyrics line 3 Verse 2 lyrics line 4 And I want to transform them so the first line of each verse is grouped together as in: Verse 1 lyrics line 1 Verse 2 lyrics line 1 Verse 1 lyrics line 2 Verse 2 lyrics line 2 Verse 1 lyrics line 3 Verse 2 lyrics line 3 Verse 1 lyrics line 4 Verse 2 lyrics line 4 Lyrics will obviously be unknown, but the blank line marks a division between verses in the input.

    Read the article

  • Counting longest occurence of repeated sequence in Python

    - by user248237
    What's the easiest way to count the longest consecutive repeat of a certain character in a string? For example, the longest consecutive repeat of "b" in the following string: my_str = "abcdefgfaabbbffbbbbbbfgbb" would be 6, since other consecutive repeats are shorter (3 and 2, respectively.) How can I do this in Python? thanks.

    Read the article

  • Regex to check that a character in range doesn't repeat

    - by Aly
    Hi, I want to match against Strings such as AhKs & AdKs (i.e. two cards Ah = Ace of Hearts). I want to match two off-suit cards with a regex, what I currently have is "^[AKQJT2-9][hscd]{2}$", but this could match hands such as AhKh (suited) and AhAh. Is there a way to possibly use backreferences to say the second [hscd] cannot be the same as the firs (similarly for [AKQJT2-9])

    Read the article

  • Obj-C combining strings

    - by Brodie4598
    this must be such a simple problem but can someone tell me why this doesnt work: visibilityString1 = @"the"; visibilityString2 = @"end"; visibilityString = (@"This is %@ %@", visibilityString1, visibilityString2); Every time I try to combine strings this way, it will only return the second string so what I get is: end

    Read the article

< Previous Page | 111 112 113 114 115 116 117 118 119 120 121 122  | Next Page >