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  • SED whitespace removal within a string

    - by blazeprogrammer
    I'm trying to use sed to replace whitespace within a string. For example, given the line: var test = 'Some test text here.'; I want to get: var test = 'Sometesttexthere.'; I've tried using (\x27 matches the '): sed 's|\x27\([^x27[:space:]]*\)[[:space:]]|\x27\1|g but that just gives var test = 'Sometest text here.'; Any ideas?

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  • PHP preg_match Math Function

    - by Matt
    I'm writing a script that will allow a user to input a string that is a math statement, to then be evaluated. I however have hit a roadblock. I cannot figure out how, using preg_match, to dissallow statements that have variables in them. Using this, $calc = create_function("", "return (" . $string . ");" ); $calc();, allows users to input a string that will be evaluated, but it crashes whenever something like echo 'foo'; is put in place of the variable $string.

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  • negative look ahead to exclude html tags

    - by Remoh
    I'm trying to come up with a validation expression to prevent users from entering html or javascript tags into a comment box on a web page. The following works fine for a single line of text: ^(?!.(<|)).$ ..but it won't allow any newline characters because of the dot(.). If I go with something like this: ^(?!.(<|))(.|\s)$ it will allow multiple lines but the expression only matches '<' and '' on the first line. I need it to match any line. This works fine: ^[-_\s\d\w"'.,:;#/&\$\%\?!@+*\()]{0,4000}$ but it's ugly and I'm concerned that it's going to break for some users because it's a multi-lingual application. Any ideas? Thanks!

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  • Find all substrings between two strings

    - by Orsol
    I need to get all substrings from string. For ex: StringParser.GetSubstrings("[start]aaaaaa[end] wwwww [start]cccccc[end]", "[start]", "[end]"); that returns 2 string "aaaaaa" and "cccccc" Suppose we have only one level of nesting. Not sure about regexp, but I think it will be userful.

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  • Using regular expressions with Dojo data.fetch?

    - by Dfowj
    I'm trying to use the below code to fetch a regular expression like this /[computer]{3,8}/(what i think is any words containing the letters in computer ranging from 3 to 8 letters long) from a database (which i know is being loaded correctly). When i fetch, i get 10 results, all the same word... "Adenauer" var base = "computer"; var baseRE = '/[' + base + ']{' + this.minLength + ',' + base.length + '}/'; this.dict.fetch({query: {word:baseRE}, onComplete: onLoadWords, onError: function(err) { console.log(err); }}); Any ideas what im doing wrong?

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • Function of: if(/(file|http).*/.test(url)) { }

    - by WmasterJ
    I am wondering what this technique is called and what it does. It seems to be validating some regular expression on the variable url. I am customizing another persons code: var url = document.getElementById("editorURL").value; if(/(file|http).*/.test(url)) { } Maybe someone has a link to an article that explains this a bit more in-depth?

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  • MySql Not Like Regexp?

    - by KnockKnockWhosThere
    I'm trying to find rows where the first character is not a digit. I have this: SELECT DISTINCT(action) FROM actions WHERE qkey = 140 AND action NOT REGEXP '^[:digit:]$'; But, I'm not sure how to make sure it checks just the first character...

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  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

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  • I'm trying to match some numbers in a string using a regexpressions and am having difficulty with th

    - by Ryan
    here is the line i'm trying to parse [\\?\Volume{d3f7f470-526b-11df-92eb-001a647802d2}\] 85 90 NotFound I'm basically just trying to get the numbers that are outside of the brackets and ignore anything in between the brackets. My original syntax worked until I realized that sometimes there would be numbers in the brackets (I was just using "([0-99]{2})") any help would be greatly appreciated. Thanks

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  • Pulling international street addresses / phone numbers from free-form text

    - by spitzanator
    Hey, folks. I'm looking for some regular expressions to help grab street addresses and phone numbers from free-form text (a la Gmail). Given some text: "John, I went to the store today, and it was awesome! Did you hear that they moved to 500 Green St.? ... Give me a call at +14252425424 when you get a chance." I'd like to be able to pull out: 500 Green St. (recognized as a street address) +14252425424 (recognized as a phone number) What makes this problem easier is that I don't care about parsing text that gets pulled out. That is, I don't care that Green is the name of the road or that 425 is the area code. I just want to grab strings that "look like" addresses or telephone numbers. Unfortunately, this needs to work internationally, as best as possible. Anyone have any leads? Thanks!

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  • classic asp comparison of comma seperated lists

    - by Reiwoldt
    Hello, I have two comma seperated lists:- 36,189,47,183,65,50 65, 50, 189, 47 the question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. e.g. in the above example I would need the return value to be 36,183 Thanks

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  • Need to add specific characters to regular expression

    - by lordryan
    i'm using the following regular expression to form a basic email validation. var emailRegEx = /^([a-zA-Z0-9])(([a-zA-Z0-9])*([\._\+-])*([a-zA-Z0-9]))*@(([a-zA-Z0-9\-])+(\.))+([a-zA-Z]{2,4})+$/; this works pretty well for what i need but i also need to exclude these specific characters for reasons i won't go into. !,#,$,%,^,&,*,(,),-,+,|,{,},[,],:,>,<,?,/,\,= - (the characters between the "," if that isn't clear) could someone help me with adding the second group to the first? I know the pro's and cons of using javascript to validate email addresses - i have to do it this way. thanks.

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  • How can I handle validation of non-latin script input in PHP?

    - by Matt
    I am trying to adapt a php application to handle non-latin scripts (specifically: Japanese, simplified Chinese and Arabic). The app's data validation routines make frequent use of regular expressions to check input, but I am not sure how to adapt the \w character type to other languages without installing additional locales on the system (which I cannot rely on). Previous developers to have worked on the app have simply added needed characters to the regexes as the number of languages we supported grew (you frequently see "[\wÀÁÂÃÄÅÆÇÈÉ... etc" in the code), but I can't really do this for all the alphabets I need to support now. Does anybody out there have some advice on how to tackle this?

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  • Apply a class to a <h1> based on the site url

    - by user1870639
    I'm new to PHP and want to apply a specific class to the title of my page depending on what part of the site the viewer is browsing. For instance, I want to apply the class "blog" to the if the viewer is at domain.com/blog OR domain.com/blog/post-1 so on and so forth BUT apply the class "pics" if they're viewing domain.com/pics or domain.com/pics/gallery-1 etc etc. I found something that could be modified to serve my needs using javascript here but I figured seeing as I'm using PHP already, it'd make more sense to keep this sort of thing server side. As I say, I'm new to PHP. I've experimented with some regular expressions, but to no avail.

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  • A regular expression question

    - by Hellnar
    Hello, I am in dire need of a such regular expression where my alphabet is made up of 0s and 1s. Now I need a language that accepts all words as long as it has three 0s. IE: 000 10001 0001 1000 10000101

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  • actionscript find and convert text to url

    - by gravesit
    I have this script that grabs a twitter feed and displays in a little widget. What I want to do is look at the text for a url and convert that url to a link. public class Main extends MovieClip { private var twitterXML:XML; // This holds the xml data public function Main() { // This is Untold Entertainment's Twitter id. Did you grab yours? var myTwitterID= "username"; // Fire the loadTwitterXML method, passing it the url to your Twitter info: loadTwitterXML("http://twitter.com/statuses/user_timeline/" + myTwitterID + ".xml"); } private function loadTwitterXML(URL:String):void { var urlLoader:URLLoader = new URLLoader(); // When all the junk has been pulled in from the url, we'll fire finishedLoadingXML: urlLoader.addEventListener(Event.COMPLETE, finishLoadingXML); urlLoader.load(new URLRequest(URL)); } private function finishLoadingXML(e:Event = null):void { // All the junk has been pulled in from the xml! Hooray! // Remove the eventListener as a bit of housecleaning: e.target.removeEventListener(Event.COMPLETE, finishLoadingXML); // Populate the xml object with the xml data: twitterXML = new XML(e.target.data); showTwitterStatus(); } private function addTextToField(text:String,field:TextField):void{ /*Regular expressions for replacement, g: replace all, i: no lower/upper case difference Finds all strings starting with "http://", followed by any number of characters niether space nor new line.*/ var reg:RegExp=/(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/ig; //Replaces Note: "$&" stands for the replaced string. text.replace(reg,"<a href=\"$&\">$&</a>"); field.htmlText=text; } private function showTwitterStatus():void { // Uncomment this line if you want to see all the fun stuff Twitter sends you: //trace(twitterXML); // Prep the text field to hold our latest Twitter update: twitter_txt.wordWrap = true; twitter_txt.autoSize = TextFieldAutoSize.LEFT; // Populate the text field with the first element in the status.text nodes: addTextToField(twitterXML.status.text[0], twitter_txt); }

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  • Is it possible to use a back reference to specify the number of replications in a regular expression

    - by user307894
    Is it possible to use a back reference to specify the number of replications in a regular expression? foo= 'ADCKAL+2AG.+2AG.+2AG.+2AGGG+.+G+3AGGa4.' The substrings that start with '+[0-9]' followed by '[A-z]{n}.' need to be replaced with simply '+' where the variable n is the digit from earlier in the substring. Can that n be back referenced? For example (doesn't work) '+([0-9])[A-z]{/1}.' is the pattern I want replaced with "+" (that last dot can be any character and represents a quality score) so that foo should come out to ADCKAL++++G.G+. foo = 'ADCKAL+2AG.+2AG.+2AG.+2AGGG^+.+G+3AGGa4.' indelpatt = re.compile('\+([0-9])') while indelpatt.search(foo): indelsize=int(indelpatt.search(foo).group(1)) new_regex = '\+%s[ACGTNacgtn]{%s}.' % (indelsize,indelsize) newpatt=re.compile(new_regex) foo = newpatt.sub("+", foo) I'm probably missing an easier way to parse the string.

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