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  • Can I Move a MediaWiki site to a new virtual folder?

    - by Tyler
    I had MediaWiki installed in as the default site on my server using IIS 6 and I created a virtual directory and pointed it to the Wiki folder. The page loads, but all the links are pointing to the original location that is no longer pointing to the Wiki Folder. Info Server Name: tech Path to Wiki: http://tech/wiki/ Example Links Wrong Link - This is the current link displayed http://tech/index.php?title=Main_Page The link should look like this http://tech/wiki/index.php?title=Main_Page All of the links are not showing the /wiki Any ideas?

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  • Using javascript to call controller methond in mvc

    - by Christian Thoresson Dahl
    Im trying to make a table row work as a link to another view in my mvc website. Instead of using the standard "Details" link provided by the auto generated table list, I would like to use the table row as a link to the "Details" view instead. So somehow I need to make the row work as a link. Each rom has a unique id that I need to pass on to the controller method. I have tried different solutions but noting happens when I press on the table row... So far this is what I have: <script type="text/javascript"> $(document).ready(function(){ $('#customers tr').click(function () { var id = $(this).attr('id'); $.ajax({ url: "Customer/Details" + id, succes: function () { } }); }) }) </script> My controller method: public ActionResult Details(int id) { Customer model = new Customer(); model = this.dbEntities.Customers.Where(c => c.Customer_ID == id).Single(); return View(model); }

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  • deep linking in Excel sheets exported to html

    - by pomarc
    hello everybody, I am working on a project where I must export to html a lot of Excel files. This is pretty straightforward using automation and saving as html. The problem is that many of these sheets have links to worksheets of some other files. I must find a way to write a link to a single inner worksheet. When you export a multisheet excel file to html, excel creates a main htm file, a folder named filename_file, and inside this folder it writes down several files: a css, an xml list of files, a file that creates the tab bar and several html files named sheetxxx.htm, each one representing a worksheet. When you open the main file, you can click the menu bar at the bottom which lets you select the appropriate sheet. This is in fact a link, which replaces a frame content with the sheetxxx.htm file. When this file is loaded a javascript function that selects the right tab gets called. The exported files will be published on a web site. I will have to post process each file and replace every link to the other xls files to the matching htm file, finding a way to open the right worksheet. I think that I could add a parameter to the processed htm file link url, such as myfile.htm?sh=sheet002.htm if I want to link to the second worksheet of myfile.htm (ex myfile.xls). After I've exported them, I could inject a simple javascript into each of the main files which, when they are loaded, could retrieve the sh parameter with jQuery (this is easy) and use this to somehow replace the frSheet frame contents (where the sheets get loaded), opening the right inner sheet and not the default sheet (this is what I call deep linking) mimicking what happens when a user clicks on a tab. This last step is missing... :) I am considering different options, such as replacing the source of the $("frSheet") frame after document.ready. I'd like to hear from you any advice on what could be the best way to realize that in your opinion. any help is greately appreciated, many thanks.

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  • Disabling JavaScript Listener with Greasemonkey

    - by RHPT
    There is a Greasemonkey script that removes the tracking identifiers from Yahoo! News stories (http://userscripts.org/scripts/show/3642). However, Yahoo! implemented listeners that adds the tracking link back when you click on a news story link. How could I disable the onclick listener so that the link tracking is not added back?

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  • Just a small problem regarding javscript BOM question

    - by caramel1991
    The question is this: Create a page with a number of links. Then write code that fires on the window onload event, displaying the href of each of the links on the page. And this is my solution <html> <body language="Javascript" onload="displayLink()"> <a href="http://www.google.com/">First link</a> <a href="http://www.yahoo.com/">Second link</a> <a href="http://www.msn.com/">Third link</a> <script type="text/javascript" language="Javascript"> function displayLink() { for(var i = 0;document.links[i];i++) { alert(document.links[i].href); } } </script> </body> </html> This is the answer provided by the book <html> <head> <script language=”JavaScript” type=”text/javascript”> function displayLinks() { var linksCounter; for (linksCounter = 0; linksCounter < document.links.length; linksCounter++) { alert(document.links[linksCounter].href); } } </script> </head> <body onload=”displayLinks()”> <A href=”link0.htm” >Link 0</A> <A href=”link1.htm”>Link 2</A> <A href=”link2.htm”>Link 2</A> </body> </html> Before I get into the javascript tutorial on how to check user browser version or model,I was using the same method as the example,by acessing the length property of the links array for the loop,but after I read through the tutorial,I find out that I can also use this alternative ways,by using the method that the test condition will evalute to true only if the document.links[i] return a valid value,so does my code is written using the valid method??If it's not,any comment regarding how to write a better code??Correct me if I'm wrong,I heard some of the people say "a good code is not evaluate solely on whether it works or not,but in terms of speed,the ability to comprehend the code,and could posssibly let others to understand the code easily".Is is true??

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  • Parsing XML wont display all items.

    - by Nauman A
    I have this code but the toast wont display any message what is wrong with my code.. I can get the value from link, linknext but title wont bring out any value. ( I am not very bright with writing code so please suggest anything you may feel like. final Button button = (Button) findViewById(R.id.Button01); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click try { URL url = new URL( "http://somelink.com=" + Link.setFirst_link); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(new InputSource(url.openStream())); doc.getDocumentElement().normalize(); NodeList nodeList = doc.getElementsByTagName("item"); /** Assign textview array lenght by arraylist size */ for (int i = 0; i < nodeList.getLength(); i++) { Node node = nodeList.item(i); Element fstElmnt = (Element) node; NodeList nameList = fstElmnt.getElementsByTagName("link"); Element nameElement = (Element) nameList.item(0); nameList = nameElement.getChildNodes(); String img = (((Node) nameList.item(0)).getNodeValue()); NodeList websiteList = fstElmnt.getElementsByTagName("linknext"); Element websiteElement = (Element) websiteList.item(0); websiteList = websiteElement.getChildNodes(); String nextlink = (((Node) websiteList.item(0)).getNodeValue()); Link.setFirst_link = nextlink; Drawable drawable = LoadImageFromWebOperations(img); imgView.setImageDrawable(drawable); NodeList titleList = fstElmnt.getElementsByTagName("title"); Element titleElement = (Element) titleList.item(0); websiteList = titleElement.getChildNodes(); String title = (((Node) titleList.item(0)).getNodeValue()); Context context = getApplicationContext(); CharSequence text = title; int duration = Toast.LENGTH_SHORT; Toast toast = Toast.makeText(context, text, duration); toast.show(); } } catch (Exception e) { System.out.println("XML Pasing Excpetion = " + e); } } }); /** Set the layout view to display */ } Here is the xml file <?xml version="1.0"?> <maintag> <item> <link>http://image.com/357769.jpg?40</link> <linknext>http://www.image.com</linknext> <title>imagename</title> </item> </maintag>

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  • Font Awesome Not Working In Chrome

    - by Connor Black
    So I'm trying to prototype a marketing page and I'm using bootstrap and the new font awesome file. The problem is when I try to use an icon all that gets rendered on the page in a big square. Here's how I include the files in the head: <head> <title> </title> <link rel="stylesheet" href="css/bootstrap.css"> <link rel="stylesheet" href="css/bootstrap-responsive.css"> <link rel="stylesheet" href="css/font-awesome.css"> <link rel="stylesheet" href="css/app.css"> <!--[if IE 7]> <link rel="stylesheet" href="css/font-awesome-ie7.min.css"> <![endif]--> </head> And here's an example of me trying to use an icon: <i class="icon-camera-retro"></i> But all that gets rendered in a big square. Does anyone know what could be going on?

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  • Linker warnings when using stdscr (ncurses)

    - by flarn2006
    Okay, so I'm getting these warnings whenever I try to use stdscr in pdcurses: LINK : warning LNK4098: defaultlib "LIBC" conflicts with use of other libs; use /NODEFAULTLIB:library LINK : warning LNK4049: locally defined symbol "_stdscr" imported LINK : warning LNK4049: locally defined symbol "_SP" imported How do I fix this? They're just warnings, but when I run my program, it crashes, so they probably have something to do with it. Especially considering the fact that the line it crashes at is the one that uses stdscr...

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  • Dynamic positioning inside relative div

    - by ian
    I'm trying to get a color picker javascript widget working in a page with a bunch of "stuff" in it that I can't change. Some of the "stuff" is causing the color picker to appear well below the link when clicked. I've reduced it to a simple example below. <html> <head> <script type="text/javascript"> function setPos(aname,dname) { var o=document.getElementById(aname); var ol=o.offsetLeft; while ((o=o.offsetParent) != null) { ol += o.offsetLeft; } o=document.getElementById(aname); var ot=o.offsetTop + 25; while((o=o.offsetParent) != null) { ot += o.offsetTop; } document.getElementById(dname).style.left = ol + "px"; document.getElementById(dname).style.top = ot + "px"; } </script> <style> h1 {height: 50px;} #divMain {position: relative;} </style> </head> <body> <h1></h1> <div id="divMain"> <a href="#" onClick="setPos('link1','div1');return false;" name="link1" id="link1">link 1</a> <div id="div1" style="position:absolute;border-style:solid;left:200px;top:200px;">div 1</div> </div> </body> </html> What's supposed to happen is when you click "link 1", "div1" should move directly below "link 1". What actually happens is that "div 1" appears well below "link 1". If you remove position: relative; from the CSS definition for divMain, "div 1" is positioned correctly. How can I position "div 1" directly beneath "link 1" without removing position: relative;?

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  • asp file system object

    - by sushant
    i am using this code to access files and folders. <%@ Language=VBScript %<% option explicit dim sRoot, sDir, sParent, objFSO, objFolder, objFile, objSubFolder, sSize % <% sRoot = "D:Raghu" sDir = Request("Dir") sDir = sDir & "\" Response.Write "" & sDir & "" & vbCRLF Set objFSO = CreateObject("Scripting.FileSystemObject") on error resume next Set objFolder = objFSO.GetFolder(sRoot & sDir) if err.number < 0 then Response.Write "Could not open folder" Response.End end if on error goto 0 sParent = objFSO.GetParentFolderName(objFolder.Path) ' Remove the contents of sRoot from the front. This gives us the parent ' path relative to the root folder ' eg. if parent folder is "c:webfilessubfolder1subfolder2" then we just want "subfolder1subfolder2" sParent = mid(sParent, len(sRoot) + 1) Response.Write "" ' Give a link to the parent folder. This is just a link to this page only pssing in ' the new folder as a parameter Response.Write "Parent folder" & vbCRLF ' Now we want to loop through the subfolders in this folder For Each objSubFolder In objFolder.SubFolders ' And provide a link to them Response.Write "" & objSubFolder.Name & "" & vbCRLF Next ' Now we want to loop through the files in this folder For Each objFile In objFolder.Files if Clng(objFile.Size) < 1024 then sSize = objFile.Size & " bytes" else sSize = Clng(objFile.Size / 1024) & " KB" end if ' And provide a link to view them. This is a link to show.asp passing in the directory and the file ' as parameters Response.Write "" & objFile.Name & "" & sSize & "" & objFile.Type & "" & vbCRLF Next Response.Write "" % it works fine. but when i try to access something on shred path like: "\cvrdd0110:share" it gives error. how to access these files?

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  • Using regex and javascript to make links clickable but not overwrite pre-existing links?

    - by Lexsym
    I need to make links clickable using javascript and I thought regex would be the easiest not to mention fastest way. I want all links to be clickable, and to not rewrite the already clickable links that exist. Example: Here is a link to visit http://www.example.com/page Please take a look <a href="http://www.example.com/page">here</a>. Becomes: Here is a link to visit <a href="http://www.example.com/page">http://www.example.com/page</a> Please take a look <a href="http://www.example.com/page">here</a>. Another example: Here is a link to visit http://www.example.com/page Please take a look here: <a href="http://www.example.com/page">http://www.example.com/page</a> Becomes: Here is a link to visit <a href="http://www.example.com/page">http://www.example.com/page</a> Please take a look here: <a href="http://www.example.com/page">http://www.example.com/page</a>

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  • follow of curl for java

    - by zahir hussain
    i want how to follow the link... for example the link : http://example.com/hi.php this will redirect another page to http://example.com/vi.php then this will redirect another page to http://example.com/ji.html so i need to get the page link "http://example.com/ji.html" i think, i cant in java.. so have possible in java curl? thanks advance

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  • how to get app-store reivew url?

    - by beof
    In my application,I want to remind the user to write a reivew, however,when I copy the link write a review as shown below: http://itunes.apple.com/tw/app/id MyID?mt=8 It is the same as the product link. I follow this guide: http://blogs.oreilly.com/iphone/2008/08/scraping-appstore-reviews.html The US account can successfully link to the page,but the China-Twain Can not ,it pop an alertView saying:Cannot connect to iTunes Store The iTunes Store is not supported in this country. anyone has good suggestions?

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  • How can I provide links to intranet files through ASP.net?

    - by PhoenixWright
    Conditions: The files must be opened outside of the window that the link to them is in. I have tried href, but when I give it an intranet link it only opens correctly if I leave out target="_blank"; if I put that in, the new window that opens doesn't receive the full link if there is a pound sign in the filepath... a direct link to the intranet address \a\b\c#c.txt would be fine with me; there is no concern about security, but I can't seem to get that to happen in a new window. It seems like this is happening when I don't create a new window, but I can't utilize the same window to open the links. Any ideas?

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  • Sending mail through PHP

    - by Angeline Aarthi
    I'm trying to sends mails in PHP. The code I used for sending a mail in CakePHP is given below. I get the message 'Simple Email Sent' in my web page but the mail is not delivered to my inbox. Am I missing something? The values in the to, subject and link fields are set with the values entered in the user interface. $this->set('to',$this->params['form']['to']); $this->set('subject',$this->params['form']['subject']); $this->set('link',$this->params['form']['link']); $this->Email->to = to; $this->Email->subject = subject; $this->Email->from = '[email protected]'; $this->Email->delivery= 'mail'; $this->Email->sendAs='text'; $this->Email->template = 'simple_message'; //$this->Email->send(link); if ( $this->Email->send(link) ) { $this->Session->setFlash('Simple email sent'); } else { $this->Session->setFlash('Simple email not sent'); }

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  • Regular expressions in python unicode

    - by Remy
    I need to remove all the html tags from a given webpage data. I tried this using regular expressions: import urllib2 import re page = urllib2.urlopen("http://www.frugalrules.com") from bs4 import BeautifulSoup, NavigableString, Comment soup = BeautifulSoup(page) link = soup.find('link', type='application/rss+xml') print link['href'] rss = urllib2.urlopen(link['href']).read() souprss = BeautifulSoup(rss) description_tag = souprss.find_all('description') content_tag = souprss.find_all('content:encoded') print re.sub('<[^>]*>', '', content_tag) But the syntax of the re.sub is: re.sub(pattern, repl, string, count=0) So, I modified the code as (instead of the print statement above): for row in content_tag: print re.sub(ur"<[^>]*>",'',row,re.UNICODE But it gives the following error: Traceback (most recent call last): File "C:\beautifulsoup4-4.3.2\collocation.py", line 20, in <module> print re.sub(ur"<[^>]*>",'',row,re.UNICODE) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer What am I doing wrong?

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  • whats wrong with this php mysql_real_escape_string

    - by skyhigh
    Hi Atomic Number Latin English Abbreviation * check the variables for content */ /*** a list of filters ***/ $filters = array( 'searchtext' => array( 'filter' => FILTER_CALLBACK, 'options' => 'mysql_real_escape_string'), 'fieldname' => array( 'filter' => FILTER_CALLBACK, 'options' => 'mysql_real_escape_string') ); /*** escape all POST variables ***/ $input = filter_input_array(INPUT_POST, $filters); /*** check the values are not empty ***/ if(empty($input['fieldname']) || empty($input['searchtext'])) { echo 'Invalid search'; } else { /*** mysql hostname ***/ $hostname = 'localhost'; /*** mysql username ***/ $username = 'username'; /*** mysql password ***/ $password = 'password'; /*** mysql database name ***/ $dbname = 'periodic_table'; /*** connect to the database ***/ $link = @mysql_connect($hostname, $username, $password); /*** check if the link is a valid resource ***/ if(is_resource($link)) { /*** select the database we wish to use ***/ if(mysql_select_db($dbname, $link) === TRUE) { /*** sql to SELECT information***/ $sql = sprintf("SELECT * FROM elements WHERE %s = '%s'", $input['fieldname'], $input['searchtext']); /*** echo the sql query ***/ echo '<h3>'.$sql.'</h3>'; /*** run the query ***/ $result = mysql_query($sql); /*** check if the result is a valid resource ***/ if(is_resource($result)) { /*** check if we have more than zero rows ***/ if(mysql_num_rows($result) !== 0) { echo '<table>'; while($row=mysql_fetch_array($result)) { echo '<tr> <td>'.$row['atomicnumber'].'</td> <td>'.$row['latin'].'</td> <td>'.$row['english'].'</td> <td>'.$row['abbr'].'</td> </tr>'; } echo '</table>'; } else { /*** if zero results are found.. ***/ echo 'Zero results found'; } } else { /*** if the resource is not valid ***/ 'No valid resource found'; } } /*** if we are unable to select the database show an error ****/ else { echo 'Unable to select database '.$dbname; } /*** close the connection ***/ mysql_close($link); } else { /*** if we fail to connect ***/ echo 'Unable to connect'; } } } else { echo 'Please Choose An Element'; } ? I got this code from phppro.org tutorials site and i tried to run it. It gives Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established. .... Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO).... I went to php.net and look it up "Note: A MySQL connection is required before using mysql_real_escape_string() otherwise an error of level E_WARNING is generated, and FALSE is returned. If link_identifier isn't defined, the last MySQL connection is used." My questions are: 1-why they put single quotation around mysql_real_escape_string ? 2-They should establish a connection first, then use the $filter array statement with mysql_real_escape_string ?

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  • Help with psudo classes in CSS

    - by Anil Namde
    <a class="success" href="javascript:void(0)"></a> //CSS for setting background for above link a.success:hover{ //set background image } What my intent is to change the class of link on server side based on success/fail and set icon for the link accordingly. But above CSS is not working as expected. Can someone plz help with this.

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  • JQuery Bind click event to appended element with an argument

    - by Gabor Szauer
    Hi guys, I'm trying to populate a ul list with some li elements and give each li element a link that calls the same function with a different argument. However it doesn't seem to work, i've attached the code below, CheckForNewMail is called on document load. Can anyone please help me out? function CheckForNewMail() { ////////////////////////////////////////////////////////////////// // This will be dynamic MailInInbox[0] = new Array("0", "Mail One"); MailInInbox[1] = new Array("12", "Mail Two"); MailInInbox[2] = new Array("32", "Mail Three"); MailInInbox[3] = new Array("5", "Mail Four"); ////////////////////////////////////////////////////////////////////// $('#mail-in-inbox').children().remove(); size = 4; element = $('#mail-in-inbox'); for(i = 0; i < size; ++i) { var link = $('<a href="#" class="inbox-link">'+ MailInInbox[i][1] +'</a>'); link.live('click', function() { LoadMailById(i); }); li = $('<li></li>'); li.append(link); element.append(li); } } function LoadMailById(id) { alert("Button "+ id +" clicked!"); }

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  • Javascript and jQuery (Fancybox) question

    - by songdogtech
    Javascript and jQuery (Fancybox) question I'm using the Javascript function below for Twitter sharing (as well as other services; the function code is simplified to just Twitter for this question) that grabs the to-be-shared page URL and title and it is invoked in the link with onclick. That results in the Twitter share page loading in a pop up browser window, i.e.<img src="/images/twitter_16.png" onclick="share.tw()" /> In order to be consistent with other design aspects of the site, what I'd like to be able to do is have the Twitter share page open not in a standard browser window but in a Fancybox (jQuery) window. Fancybox can load an external page in an iFrame when the img or href link contains a class (in this case class="iframe" ) in the link and in the document ready function in the header. Right now, of course, when I give the iframe class to the link that also has the onclick share.tw(), I get two popups: one browser window popup with the correct Twitter share page loaded, and a Fancybox jQuery popup that shows a site 404. How can I change the function to use Fancybox to present the Twitter share page? Is that a correct way to approach it? Or is there a better way, such as implementing the share function in jQuery, too? Thanks... Javascript share function: var share = { tw:function(title,url) { this.share('http://twitter.com/home?status=##URL##+##TITLE##',title,url); }, share:function(tpl,title,url) { if(!url) url = encodeURIComponent(window.location); if(!title) title = encodeURIComponent(document.title); tpl = tpl.replace("##URL##",url); tpl = tpl.replace("##TITLE##",title); window.open(tpl,"sharewindow"+tpl.substr(6,15),"width=640,height=480"); } }; It is invoked, i.e.: <img src="/images/twitter_16.png" onclick="share.tw()" /> Fancybox function, invoked by adding class="iframe" in the img or href link $(".iframe").fancybox({ 'width' : '100%', 'height' : '100%', 'autoScale' : false, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'iframe' });

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  • Learning rails and AJAX. How do I load a div via ajax and then toggle hiding/showing it?

    - by Kevin L.
    I'm doing my first Ruby on Rails project. I am working on a project where the user can add a new message. Then they can add updates to this message like a thread. I've got it all written and now I'm going back and applying some AJAX. I want to show just the main message when the page first loads. Then when I click a link I want an AJAX event to fire that populates a div with all the updates to the message. Then I want this same link to toggle hiding and showing the div. I've made a submit button to fire the ajax and get back the updates using form_remote_tag. I've also created a separate link to toggle the hiding using $(div_id).toggle();. But now I'm stuck on how to combine these two things into one all purpose link. Thanks.

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  • Rewriting URL in AJAX application

    - by Artem Moskalev
    I am making a simple online application. I have a navigation bar with a few buttons and one "div" into which all the new contents will be loaded dynamically i.e. when I click "About", it will load the page parts into the "div" without reloading the whole page with .load() function. The problem is: what if I need to give a link to the Documents section of my web site, or the user wants to store this kind of link, the url is not rewritten when browsing my site. when the user stores the default link it will always link him to the default "Home" part. How can I rewrite the URL and what is the most correct way to do this?

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